The probability that a randomly selected bolt will have a diameter greater than 0.60 cm is approximately 0.6915.
We know that the diameters of bolts produced on a certain machine are normally distributed with a mean (μ) of 0.62 cm and a standard deviation (σ) of 0.04 cm.
Let X be the diameter of a bolt. Then, X ~ N(μ, σ) = N(0.62, 0.04).
We need to find the probability that a randomly selected bolt will have a diameter greater than 0.60 cm.
P(X > 0.60) = P((X - μ)/σ > (0.60 - 0.62)/0.04) (standardizing X)
= P(Z > -0.5) (where Z ~ N(0,1) is the standard normal distribution)
Using the standard normal distribution table or calculator, we can find that P(Z > -0.5) is approximately 0.6915.
Therefore, the probability that a randomly selected bolt will have a diameter greater than 0.60 cm is approximately 0.6915.
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The functions f(x)=−34x+214 and g(x)=(12)x+1 are shown in the graph. What are the solutions to −34x+214=(12)x+1? Select each correct answer.
The graphs cross at x=-1 and x=1. Those are the solutions to to the equation
How to explain the graphWe know that, If two functions are equal then there solution is the intersection point of the curves.
When we determine the graph the intersection points are (0,2) and (1,1.25).
The values of x of the intersection points are the solutions of the system
Using a graphing tool, there are two intersection points and therefore the solutions are x = -1 and x [ 1.
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Which one of the following is true regarding the use of the mode, mean, and median for different levels of measurement?
The mode, mean, and median are all valid measures of central tendency for interval and ratio level data. For nominal level data, only the mode is appropriate, while for ordinal level data, both the mode and median can be used, but the mean is not recommended as it assumes equal intervals between categories.
The correct statement regarding the use of the mode, mean, and median for different levels of measurement is:
The mode can be used for nominal and ordinal levels of measurement, the median is used for ordinal, interval, and ratio levels, while the mean is used for interval and ratio levels of measurement.
Let's break it down:
1. Mode: applicable to nominal and ordinal levels as it represents the most frequently occurring value in the data.
2. Median: applicable to ordinal, interval, and ratio levels as it represents the middle value when data is arranged in order.
3. Mean: applicable to interval and ratio levels as it represents the average value by summing all data points and dividing by the number of data points.
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PLEASE HELP ME!!! + points
the gas station and hotel are both on a highway, and the distance between them is about 100 miles. john has to drive to the gas station or hotel, which are both 60 miles away from his farmhouse, to get on the highway. he wants to build a road to the highway using the shortest distance possible from his farmhouse. enter the shortest distance possible from his farmhouse. enter the shortest distance, in miles, from the farmhouse, to the highway
The shortest distance from John's Farm house to the high way is 116.6miles. This is solved using Pythagorean theorem.
What is the explanation?When triangulated, we find three possible distances:
D - the Gas Station to the Hotel = 100miles
P - The gas station to the farm house = 60 miles
x - shortest distance between farm ouse to the highway
In Pythagorean format:
x² = 60² + 100²
x² = 3600 +10000
x = √13600
x [tex]\approx[/tex] 116.6 Miles.
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Determine whether the integral is convergent or divergent. If it is convergent, evaluate it. (if the quantity diverges, enter diverges. ) [infinity] 0 1 6 1 x dx
a. Convergent
b. Divergent
The integral ∫[0,6] 1/x dx is divergent, An integral is said to be divergent if it does not have a finite value.
The given integral is:
[tex]∫[0,6] 1/x dx[/tex]
We know that the integral of 1/x is ln(x), and the antiderivative of ln(x) is xln(x) - x.
So, applying the limits of integration, we get:
[tex]∫[0,6] 1/x dx = ln(x)|[0,6] = ln(6) - ln(0)[/tex]
The natural logarithm of zero is unclear, so the indispensably isn't characterized at x = 0. In this manner, the indispensability is unique.
An integral is said to be divergent in the event that it does not have limited esteem. In other words, on the off chance that the fundamentally does not meet a genuine number, it is said to be unique.
There are a few reasons why a fundamentally may be unique. A few common reasons incorporate:
The integrand gets to be unbounded at a few points inside the limits of integration.
The integrand does not approach zero as the constraint of integration approaches boundlessness.
The limits of integration are interminable, and the integrand does not merge to a limited esteem as the limits approach interminability.
When an indispensably is disparate, it implies that the zone beneath the bend is interminable or does not exist.
This could have imperative suggestions in ranges such as material science and designing, where integrands are utilized to calculate amounts such as work, energy, and a liquid stream.
Thus, the answer is (b) Divergent.
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The Fourier transform of the function: f(t) = sin 3t,k≤|t|≤2k 0, |t|
a.-i[(sin2k(w-3)-sink(w-3)/w-3 )-(sin2k(w+3)-sink(w+3)/w-3)]
b.-1/2[(sin2k(w-3)-sink(w-3)/w-3 )-(sin2k(w+3)-sink(w+3)/w-3)]
c.i[(sin2k(w-3)-sink(w-3)/w-3 )-(sin2k(w+3)-sink(w+3)/w-3)]
d.none of the above
Its Fourier transform is also 0.
The Fourier transform of a function f(t) is defined as:
F(w) = (1/√(2π)) ∫[from -∞ to +∞] f(t) e^(-iwt) dt
Let's find the Fourier transform of the given function f(t) = sin 3t, k≤|t|≤2k and 0, |t|>2k.
For k≤|t|≤2k, we can write:
f(t) = sin 3t
= (1/2i) (e^(i3t) - e^(-i3t))
Using the Fourier transform properties, we can write:
F(w) = (1/2i) [∫[from -2k to -k] e^(i3t) e^(-iwt) dt + ∫[from k to 2k] e^(i3t) e^(-iwt) dt]
Applying the integral formula ∫ e^(ax) dx = (1/a) e^(ax) + C, we get:
F(w) = (1/2i) [(1/i(3-w))(e^(i(3-w)2k) - e^(i(3-w)k)) + (1/i(3+w))(e^(i(3+w)k) - e^(i(3+w)2k))]
Simplifying the above expression, we get:
F(w) = (1/2) [(sin(2kw-3) - sin(kw-3))/(kw-3) + (sin(kw+3) - sin(2kw+3))/(kw+3)]
For |t|>2k, f(t) = 0. Thus, its Fourier transform is also 0.
Therefore, the correct option is d. none of the above.
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What is the equation of a line that is perpendicular to the line y = –23 x – 7 and passes through the point (–4, 2)?
The equation of a line that is perpendicular to the line y = –23x – 7 and passes through the point (–4, 2) is y = x/23 + 50/23.
How to determine an equation of this line?In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):
y - y₁ = m(x - x₁)
Where:
x and y represent the data points.m represent the slope.Since the equation of this line is perpendicular to the line y = –23x – 7, the slope is given by;
Slope, m = -23
m₁ × m₂ = -1
-23 × m₂ = -1
m₂ = -1/-23
Slope, m₂ = 1/23
At data point (-4, 2) and a slope of 1/23, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 2 = 1/23(x - (-4))
y - 2 = 1/23(x + 4)
y = x/23 + 4/23 + 2
y = x/23 + 50/23
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What is the quotient of 13,756 divided 5
The quotient of 13,756 divided 5 is 2, 753.
We have to divide 13756 by 5.
So, the division is
5 | 13765 | 2 7 5 3
10
____
37
35
____
26
25
___
15
15
___
0
Thus, the quotient is 2,753.
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Find the area of each triangle. Round answers to the nearest tenth.
7)
8)
9)
3.2 mi
8.7 yd
12 yd
square yards
6 mi
square miles
10)
4.1 ft
9.4 in
8.3 ft
square feet
6.8 in
square inches
7. The area of the triangle is 52.2 yd².
8. The area of the triangle is 17.02 ft².
9. The area of the triangle is 9.6 mi².
10. The area of the triangle is 31.96 in².
What is the area of each of the triangle?
The area of each triangle is calculated by applying the following formula as shown below;
Area = ¹/₂bh
where;
b is the base of the triangleh is the height of the triangle7. The area of the triangle is calculated as
A = ¹/₂ x 12 yd x 8.7 yd
A = 52.2 yd²
8. The area of the triangle is calculated as
A = ¹/₂ x 8.3 ft x 4.1 ft
A = 17.02 ft²
9. The area of the triangle is calculated as
A = ¹/₂ x 6 mi x 3.2 mi
A = 9.6 mi²
10. The area of the triangle is calculated as
A = ¹/₂ x 9.4 in x 6.8 in
A = 31.96 in²
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the is the proportion of the total variation in the dependent variable explained by the regression model (or independent variable). A) coefficient of determination B) correlation coefficient C) slope D) standard error
The term you are looking for is the proportion of the total variation in the dependent variable explained by the regression model (or independent variable), which is known as the A) coefficient of determination.
The coefficient of determination, also known as R-squared, is a statistical measure that indicates the proportion of the total variation in the dependent variable that is explained by the regression model or independent variable. It ranges from 0 to 1, with higher values indicating a better fit of the model to the data. The other terms mentioned - variable, proportion, and independent - are all related to the concept of regression analysis, which is used to identify the relationship between a dependent variable and one or more independent variables, and to quantify the extent to which changes in the independent variables affect the dependent variable.
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[1] Find the probabilities of the followings. (a) toss five coins and find three heads and two tails. (b) the face ‘6’ turns up 2 times in 3 rolls of a die as (6 + other + 6). (c) 46% of the population approve of the president’s performance. What is the probability that all four individuals in a telephone toll disapprove of his performance? (d) take five cards from a card deck and find ‘full house.’
The total number of ways to choose five cards from a deck of 52 cards is (52 choose 5) = 2,598,960. Therefore, the probability of getting a full house is 3,744/2,598,960 = 0.00144.
(a) The total number of possible outcomes when tossing five coins is 2^5 = 32. The number of ways to get three heads and two tails is the number of ways to choose three heads out of five times the number of ways to choose two tails out of five, which is (5 choose 3) x (5 choose 2) = 10 x 10 = 100. Therefore, the probability of getting three heads and two tails is 100/32 = 0.3125.
(b) The probability of getting a '6' on a single roll of a die is 1/6. The probability of not getting a '6' on a single roll of a die is 5/6. The probability of getting '6 + other + 6' in three rolls of a die is (1/6) x (5/6) x (1/6) x 3 = 5/216. Therefore, the probability of getting '6 + other + 6' two times in three rolls of a die is (5/216)^2 x (211/216)^1 x (3 choose 2) = 0.0029.
(c) The probability of an individual disapproving of the president's performance is 1 - 0.46 = 0.54. The probability that all four individuals in a telephone poll disapprove of his performance is 0.54^4 = 0.054.
(d) A full house consists of three cards of one rank and two cards of another rank. The number of ways to choose the rank for the three cards is 13, and the number of ways to choose the three cards of that rank is (4 choose 3) = 4. The number of ways to choose the rank for the two cards is 12 (since one rank has already been chosen), and the number of ways to choose the two cards of that rank is (4 choose 2) = 6. Therefore, the number of ways to get a full house is 13 x 4 x 12 x 6 = 3,744. The total number of ways to choose five cards from a deck of 52 cards is (52 choose 5) = 2,598,960. Therefore, the probability of getting a full house is 3,744/2,598,960 = 0.00144.
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A square with sides measuring 5 millimeters each is drawn within the figure shown. A point within the figure is randomly selected.
What is the approximate probability that the randomly selected point will lie inside the square?
5.3%
8.4%
13.3%
18.1%
Answer:
C) 13.3%-------------------------
Area of square with side of 5 mm is:
A = a² = (5 mm)² = 25 mm²Find total area of the figure:
A(total) = A(trapezoid) + A(triangle)A(total) = (b₁ + b₂)h/2 + bh/2A(total) = (14 + 18)(17 - 12)/2 + 18*12/2 = 80 + 108 = 188Find the percent value of the ratio of areas of the square and full figure, which determines the probability we are looking for:
25/188*100% = 13.2978723404 % ≈ 13.3%This is matching the choice C.
Classifiy the triangle by using its side lengths
Answer: Where is the triangle?
Step-by-step explanation: Brainliest pls:)
A circular region has a population of about 175,000 people and a population density of about 1318 people per square mile. Find the radius of the region. Round your answer to the nearest tenth.
The radius of the region is 11.55 mile.
We have,
Population = 175,000
So, population density
= 175,000 / 1318
= 132.77
and, the radius using from the population density
Radius = √area / (22/7)
= √1318 x 7/22
= 11.55 mile
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There are 640 acres in 1 square mile. The area of a forest is increasing at a rate of 1 acre per decade. Which of the following is closest to the rate at which the area of the forest is increasing, in square kilometers per decade? (Use 1 kilometer =0.62 mile.) A) 0.00061mi=1.61 km B) 0.0010 C) 0.0025 D) 0.0041
There are 640 acres in 1 square mile. The area of a forest is increasing at a rate of 1 acre per decade. The rate at which the area of the forest is increasing, in square kilometers per decade is C) 0.0025 square kilometers per decade.
The area of the forest is increasing at a rate of 1 acre per decade. To find the rate in square kilometers per decade, we first need to convert acres to square miles, and then square miles to square kilometers.
1 acre = 1/640 square miles (since there are 640 acres in 1 square mile)
Now, we'll convert square miles to square kilometers using the given conversion factor (1 kilometer = 0.62 mile):
1/640 square miles * (1 km / 0.62 mile)^2 = 1/640 * (1 / 0.3844) square kilometers ≈ 0.00256 square kilometers
So, the closest answer to the rate at which the area of the forest is increasing is:
C) 0.0025 square kilometers per decade
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The relationship between marketing expenditures (x) and sales (y) is given by the following formula, y = 9x − 0.20x2 + 8. (Hint: Use the Nonlinear Solver tool). What level of marketing expenditure will maximize sales? (Round your answer to 2 decimal places.) What is the maximum sales value? (Round your answer to 2 decimal places.)
Hi! To find the level of marketing expenditure that will maximize sales and the maximum sales value, we can follow these steps:
1. The relationship between marketing expenditure (x) and sales (y) is given by the formula: y = 9x - 0.20x^2 + 8.
2. To maximize sales, we need to find the maximum point of this quadratic function, which can be done by finding the vertex.
3. The vertex formula for a quadratic function is: x = -b / (2a), where a and b are coefficients in the equation (in this case, a = -0.20 and b = 9).
4. Calculate x (marketing expenditure) for the vertex: x = -9 / (2 * -0.20) = -9 / -0.40 = 22.50.
5. Round the marketing expenditure to 2 decimal places: 22.50.
6. Plug the marketing expenditure value (x) back into the sales formula to find the maximum sales value (y): y = 9(22.50) - 0.20(22.50)^2 + 8.
7. Calculate y: y = 202.50 - 0.20(506.25) + 8 = 202.50 - 101.25 + 8 = 109.25.
8. Round the maximum sales value to 2 decimal places: 109.25.
So, the level of marketing expenditure that will maximize sales is $22.50, and the maximum sales value is $109.25.
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whats the answer to 12ab x 3cd
3(n + 5) is equivalent to (n + p)3.
Answer:
[tex]3(n + 5) = (n + 5)3[/tex]
So p = 5.
Sales associates at an electronics store earn different commission
percentages based on the items they sell. The table shows the total
sales and commission earnings for four sales associates at the
electronics store last month.
GIFTING EXTRA POINTS
The required model is c = 0.03d+1.81.
Given are 4 entries, but we just need 2 to plot the relation lets pick the first two, we would be using the equation of a line in the two-point form,
c - c₁ / d - d₁ = c₂ - c₁ / d₂ - d₁
We, put in the points, (673,22) and (3277,101), we get,
c - 22 / d-673 = 0.03
c-22 = 0.03 (d-673)
c-22 = 0.03d-20.19
c-22 / d-673 = 101-22 / 3277-673 = 79 / 2604 = 0.03
c = 0.03d+1.81
Hence, the required model is c = 0.03d+1.81.
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Please help for question 9
a) The linear function giving the cost after x months is given as follows: C(x) = 88 - 8x.
b) The cost of the shoes after 8 months is given as follows: $24.
How to define a linear function?The slope-intercept representation of a linear function is given by the equation presented as follows:
y = mx + b
The coefficients of the function and their meaning are described as follows:
m is the slope of the function, representing the change in the output variable y when the input variable x is increased by one.b is the y-intercept of the function, which is the initial value of the function, i.e., the numeric value of the function when the input variable x assumes a value of 0. On a graph, it is the value of y when the graph of the function crosses the y-axis.Each month, the balance decays by $8.00, hence the slope m is given as follows:
m = -8.
Hence:
y = -8x + b.
When x = 1, y = 80, hence the intercept b is given as follows:
80 = -8 + b
b = 88.
Hence the function is:
C(x) = 88 - 8x.
The cost after 8 months is given as follows:
C(8) = 88 - 8(8) = 88 - 64 = $24.
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1Find 58% of 5.26
2 find 35% of 4.19
3 find 22% of 3.27
4 find 2% of 5.83
5 find 38% of 8.92
1:. 3.0508
2:. 1.4665
3:. 0.7194
4:. 0.1166
5:. 3.3896
the table shows information about masses of some dogs work at the minimum and maximum auto dogs that have a more 27kg
The minimum number of dogs that have more than 27 kg is 4, and the maximum number of dogs that have more than 27 kg is 26.
We have,
To determine the minimum and maximum number of dogs that have more than 27 kg, we need to first find the cumulative frequency for the mass data.
Mass(x) frequency Cumulative frequency
0 ≤ x ≤10 3 3
10 ≤ x ≤20 9 12
20 ≤ x ≤ 30 13 25
30 ≤ x ≤ 40 4 29
Now, we can see that there are a total of 29 dogs.
To find the minimum and maximum number of dogs that have more than 27 kg, we can use the cumulative frequency table as follows:
The minimum number of dogs that have more than 27 kg is the frequency of dogs in the 30 ≤ x ≤ 40 category, which is 4.
The maximum number of dogs that have more than 27 kg is the total number of dogs minus the cumulative frequency for the 0 ≤ x ≤ 27 category, which is 3.
Now,
The maximum number of dogs that have more than 27 kg is:
29 - 3 = 26.
Thus,
The minimum number of dogs that have more than 27 kg is 4, and the maximum number of dogs that have more than 27 kg is 26.
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in 2020, the population of a city was 1,596,000 . this was a 3.5% increase from 2019. the population is expected to continue to increase at the same rate per year. write a function, f(x) , to model the population, where x is the number of years since 2020.
To model the population of a city, we can use the formula:
f(x) = 1,596,000 * (1 + 0.035)^x
Where x is the number of years since 2020 and 0.035 represents the annual increase rate of 3.5%.
To model the population of a city, we need to take into account the initial population in 2020 and the annual increase rate of 3.5%. The annual increase rate of 3.5% means that the population is expected to grow by 3.5% every year from the previous year's population. To incorporate this growth rate into our model, we can use the formula for compound interest:
A = P * (1 + r)^t
Where A is the final amount, P is the initial amount, r is the annual interest rate, and t is the number of years. In our case, the final amount is the population after x years since 2020, the initial amount is the population in 2020 (1,596,000), the annual interest rate is 3.5%, and the number of years is x.
By substituting the values into the formula, we get:
f(x) = 1,596,000 * (1 + 0.035)^x
This formula can be used to calculate the expected population of the city for any year in the future. For example, if we want to know the population in 2025, we can substitute x = 5 into the formula:
f(5) = 1,596,000 * (1 + 0.035)^5
= 1,825,854
Therefore, we can expect the population of the city to be around 1,825,854 in 2025, assuming the same annual increase rate of 3.5%.
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One way to measure a person’s fitness is to measure their body fat percentage. Average body fat percentages vary by age, but according to some guidelines, the normal range for men is 15-20% body fat, and the normal range for women is 20-25% body fat.
The body fat of 25 gym goers was measured by a trainer and the Mean and standard deviation for each group is summarized in table below.
Group Sample Size (n) Average (X-bar) Standard deviation (s)
Women 10 22.29 5.32
Men 15 14.95 6.84
A) What should the Null hypothesis say about the mean body fat percentage of women compared to the mean body fat percentage of males? B) What should the Alternative hypothesis say about the mean body fat percentage of women compared to the mean body fat percentage of males? C) Is the p-value for your test less than 0.05? "yes" or "no" D) At the 0.05 significance level, is there enough evidence to conclude that the mean body fat percentage for women is more than 3% greater than men? "yes" or "no" E) At the 0.01 significance level, is there enough evidence to conclude that the mean body fat percentage for women is more than 3% greater than men? "yes" or "no" F) Does the 95% confidence interval support the alternative hypothesis? "yes" or "no" G) Why or Why not does the 95% confidence interval support the alternative hypothesis?
A) The null hypothesis should say that the mean body fat percentage of women is equal to the mean body fat percentage of men.
B) The alternative hypothesis should say that the mean body fat percentage of women is greater than the mean body fat percentage of men.
C) The p-value for the test cannot be determined without knowing the results of the actual test.
D) Yes, there is enough evidence to conclude that the mean body fat percentage for women is more than 3% greater than men at the 0.05 significance level, because the difference between the means is 7.34% (22.29% - 14.95%) which is greater than 3%.
E) No, there is not enough evidence to conclude that the mean body fat percentage for women is more than 3% greater than men at the 0.01 significance level, because the difference between the means is not significant enough to reject the null hypothesis.
F) Yes, the 95% confidence interval supports the alternative hypothesis because it does not include the null value of 0. The confidence interval for the difference between the means is (1.63%, 12.05%).
G) The 95% confidence interval supports the alternative hypothesis because it provides a range of plausible values for the difference between the means that do not include 0. This means that we can be 95% confident that the true difference between the means is somewhere within the interval, and that the mean body fat percentage for women is likely to be higher than men.
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You invest $2,000 for 3 years at interest rate 6%, compounded every 6 months. What is the value of your investment at the end of the period?
If you invest $2,000 for 3 years at an interest rate of 6%, compounded every 6 months. The value of your investment at the end of the period is $2,397.39.
The interest rate is 6% and it is compounded every 6 months, so the period is 6 months. To calculate the value of the investment at the end of the period, we need to use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the final amount.
P = the principal amount (initial investment)
r = the annual interest rate (6%).
n = the number of times the interest is compounded per year (2, since it's compounded every 6 months).
t = the time period in years (3)
Plugging in the numbers, we get:
A = 2,000(1 + 0.06/2)^(2*3)
A = 2,000(1 + 0.03)^6
A = 2,000(1.03)^6
A = $2,397.39
Therefore, the value of your investment at the end of the period is $2,397.39.
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Help me with the question please. (10 points)
a rhombus is a parallelogram with a pair of opposite equal acute angles, a pair of opposite equal obtuse angles, and four equal sides.
in other words, it is a parallelogram with 4 equal sides, including a square as a special case.
the diagonal intersection point is the midpoint of both diagonals.
the diagonals intersect each other at a right angle (90°).
and they split each vertex angle in half.
so, they split the whole rhombus into 4 equal right-angled triangles.
and remember, the sum of all angles in a triangle is always 180°.
an "obtuse" angle means an angle larger than 90°.
an "acute" angle means an angle smaller than 90°.
because of all that, in the triangle PKE the angle K must be greater than 45° (90/2 = 45), so that the rhombus angle K can be "obtuse", as it must be twice the triangle angle K.
the triangle angle E is 90°.
so, the 16° must be triangle angle P.
and the triangle angle K is then
triangle angle K = 180 - 90 - 16 = 74°.
so, rhombus angle K = rhombus angle N = 2×74 = 148°
and triangle PMN angle N = 74°.
triangle PMN angle M = triangle PMN angle P = 16°.
calculate the moment of inertia when an object's mass is 12 kg and the mass is distributed 4 meters from the axis of rotation.
To calculate the moment of inertia of an object, you need to know its mass and the distance it is from the axis of rotation. In this case, the object has a mass of 12 kg and is distributed 4 meters from the axis of rotation. The formula to calculate the moment of inertia is I = mr^2, where the moment of inertia, m is the mass, and r is the distance from the axis of rotation.
Using this formula, we can calculate the moment of inertia of the object:
I = 12 kg x (4 m)^2
I = 192 kgm^2
Therefore, the moment of inertia of the object is 192 kgm^2.
To calculate the moment of inertia for an object, you can use the following formula:
Moment of Inertia (I) = Mass (m) × Distance² (r²)
Given the object's mass is 12 kg and the mass is distributed 4 meters from the axis of rotation, we can plug these values into the formula:
I = 12 kg × (4 m)²
Now, we'll square the distance:
I = 12 kg × 16 m²
Finally, multiply the mass and the squared distance:
I = 192 kg·m²
So, the moment of inertia of the object is 192 kg·m².
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Solve for x.
.
.
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Question content area top right
Part 1
35°
C
B
45
x
Question content area bottom
Part 1
x= enter your response here (Round to the nearest hundredth.)
The measure of the side x is 31. 509
How to determine the valueFirst, we need to know the different trigonometric identities. These identities are;
sinetangentcosinesecantcosecantcotangentFrom the information given, we have that;
The opposite side = x
The adjacent side = 45
The angle, theta = 35 degrees
Using the tangent identity, we have the ratio
tan 35 = x/45
cross multiply the values, we have;
x = 45tan (35)
find the value
x = 45(0. 7002)
multiply the values
x = 31. 509
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The probability distribution for a game is shown in the table below.
What is the probability of getting more than 1 point if the game is played one time?
Answer:
3/8
Step-by-step explanatio
the person shows the answer and explanation nice!
"needed in 20 mins i will rateyour answerQuestion 1 dy Find for the following functions, simp dx 9 (i) y = 2x5 – 4x3 + 9/4x^(3)
The derivative of the given function is:
y' = 10x^4 - 12x^2 + (27/4)x^2
To find the derivative of the given function, y = 2x^5 - 4x^3 + (9/4)x^3, we can use the power rule and the sum rule of differentiation.
The power rule states that the derivative of x^n is nx^(n-1), where n is any real number.
Using the power rule, we can find the derivative of each term in the function:
dy/dx (2x^5) = 10x^4
dy/dx (-4x^3) = -12x^2
dy/dx ((9/4)x^3) = (27/4)x^2
Using the sum rule, we can add the derivatives of each term to find the derivative of the function:
dy/dx (y) = dy/dx (2x^5) + dy/dx (-4x^3) + dy/dx ((9/4)x^3)
dy/dx (y) = 10x^4 - 12x^2 + (27/4)x^2
Therefore, the derivative of the given function is y' = 10x^4 - 12x^2 + (27/4)x^2.
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4 x 25 = ? Use the distributive property. 4 × (20+5)
4 multiplied by 25 using the distributive property is equal to 100.
The distributive property is a fundamental property in mathematics that states that multiplying a number by a sum is the same as multiplying the number by each addend in the sum and then adding the products.
In this case, we have 4 multiplied by the sum of 20 and 5, which can be rewritten as 4 multiplied by 20 plus 4 multiplied by 5. Thus:
4 × (20+5) = 4 × 20 + 4 × 5
= 80 + 20
= 100
Therefore, 4 multiplied by 25 using the distributive property is equal to 100.
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