The mean of ^p can be calculated using the formula: ^p = x/n, where x is the number of minority applicants in the sample and n is the sample size. Since we do not know the sample size, we cannot calculate the exact value of ^p.
However, we can assume that the sample size is large enough for the Central Limit Theorem to apply, which means that the mean of ^p is equal to the proportion of minority applicants in the population, which is 0.1 (10%).
The standard deviation of ^p can be calculated using the formula: σ(^p) = sqrt((p(1-p))/n), where p is the proportion of minority applicants in the population and n is the sample size. Substituting p = 0.1 and using the information that the bank filled 9% of open positions with minority candidates, we can estimate the sample size as
[tex]n = 0.09/0.1 = 0.9. Therefore, σ(^p) = sqrt((0.1*0.9)/0.9) = sqrt(0.1) = 0.316.[/tex]
To compute an approximation for p(^p < or is equal to 0.09), we need to standardize the variable ^p using the formula:
[tex]z = (^p - p)/σ(^p).[/tex]
Substituting the values of ^p, p, and σ(^p), we get: z = (0.09 - 0.1)/0.316 = -0.316.
The probability of ^p being less than or equal to 0.09 can be found by looking up the area under the standard normal distribution curve to the left of z = -0.316. Using a standard normal table or a calculator, we find that this probability is approximately 0.376.
Therefore, there is a 37.6% chance that the sample will have fewer minority applicants than were hired by the bank.
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It is known that the population variance equals 484. With a 0.95 probability, the sample size that needs to be taken to estimate the population mean if the desired margin of error is 5 or less is a. 25 b. 74 c. 189 d. 75
The answer is d. 75. The sample size needed is approximately 189, which corresponds to option c.
To estimate the required sample size, we can use the formula:
n = (Z^2 * σ^2) / E^2
where:
Z = the Z-score associated with the desired level of confidence (0.95 = 1.96)
σ^2 = the population variance (484)
E = the desired margin of error (5)
Substituting these values, we get:
n = (1.96^2 * 484) / 5^2
n = 74.4096
Rounding up to the nearest integer, the required sample size is 75.
Therefore, the answer is d. 75.
To find the required sample size for estimating the population mean with a desired margin of error of 5 or less and a 0.95 probability, you can use the following formula:
n = (Z^2 * σ^2) / E^2
where n is the sample size, Z is the Z-score corresponding to the desired level of confidence (in this case, 0.95), σ^2 is the population variance, and E is the margin of error.
Given the population variance (σ^2) of 484 and a desired margin of error (E) of 5, we can use the Z-score for a 95% confidence level, which is 1.96. Plug these values into the formula:
n = (1.96^2 * 484) / 5^2
n ≈ 189
Therefore, the sample size needed is approximately 189, which corresponds to option c.
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If x is a nontrivial solution of Ax=0, then every entry in x is nonzero. T/F?
The statement "If x is a nontrivial solution of Ax=0, then every entry in x is nonzero" is False.
A nontrivial solution means that there is at least one nonzero entry in x. However, it doesn't imply that every entry in x must be nonzero. It's possible to have a mixture of nonzero and zero entries in a nontrivial solution.
If x is a nontrivial solution of Ax=0, it means that x is a nonzero vector in the null space of A. This implies that A x = 0, which means that the linear combination of the columns of A given by x results in the zero vector.
However, this does not necessarily mean that every entry in x is nonzero. For example, consider the matrix A given by:
A = [1 0 1;
0 1 1;
1 1 2]
The null space of A contains the vector x = [-1; 1; 1], which is a nontrivial solution of Ax = 0. However, this vector has one entry that is zero and two entries that are nonzero.
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(Chapter 12) For any vectors u and v in V3, (u + v) X v= (u X v)
After substitution, we get (u + v) X v = u X v + 0, which simplifies to (u + v) X v = u X v thus proving that (u + v) X v = u X v for any vectors u and v in V3.
To prove the statement (u + v) X v = u X v for any vectors u and v in V3, we will use the properties of the cross product. First, we know that the cross product is distributive over addition, meaning that (u + v) X v = u X v + v X v.
However, we also know that the cross product of a vector with itself is zero, since the angle between the two vectors is zero degrees. Therefore, v X v = 0.
Substituting this into the previous equation gives us (u + v) X v = u X v + 0, which simplifies to (u + v) X v = u X v.
Therefore, we have proven that (u + v) X v = u X v for any vectors u and v in V3.
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problem 2. (1 point) you are hosting a party with 80 fellow students from uci (including yourself the number of students is 81). as the party organizer, you shake hands with every guest to welcome them. moreover, there are a lot handshakes among the guests as well (e.g., to say hello or introduce themselves). if you do not know the total number of handshakes, can you be certain that there are at least two guests who had the same number of handshakes?
Yes, you can be certain that there are at least two guests who had the same number of handshakes. This is due to the Pigeonhole Principle.
As the party organizer, you shake hands with all 80 guests, which means you have 80 handshakes. The guests can have a minimum of 0 handshakes (if they don't shake hands with anyone except you) and a maximum of 79 handshakes (if they shake hands with everyone except themselves). There are 80 guests (excluding yourself), so there are 80 "pigeonholes" for the number of handshakes. The range of possible handshakes among the guests is from 0 to 79, which creates 80 possible outcomes or "pigeons."
According to the Pigeonhole Principle, if there are n pigeonholes and n+1 pigeons, at least one pigeonhole must contain at least two pigeons. In this case, there are 80 pigeonholes (guests) and 80 pigeons (possible handshakes). Therefore, at least two guests must have had the same number of handshakes.
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Sir Ronald Fisher's F-distribution is used in many statistical tests. Pick two from the following list that use the F-distribution for their test statistic. Test of two samples to see if they are from populations with the same variance.
Variance Ratio test and ANOVA have same variance when F-distribution is performed.
Sir Ronald Fisher's F-distribution is indeed used in various statistical tests. From the list provided, two tests that use the F-distribution for their test statistic and involve testing if two samples are from populations with the same variance:
1. F-test (Variance Ratio Test): This test is used to compare the variances of two independent samples. The F-test statistic is calculated as the ratio of the larger sample variance to the smaller sample variance. If the test statistic follows the F-distribution, we can then determine whether the samples come from populations with the same variance.
2. Two-Way Analysis of Variance (ANOVA): ANOVA is used to compare the means of multiple groups while considering multiple factors. In the two-way ANOVA, the F-distribution is used to calculate the test statistic for both main effects (rows and columns) and interaction effects. This test helps in determining whether the samples come from populations with the same variance, among other factors.
In both of these tests, the F-distribution plays a key role in the calculation of the test statistic, which is then used to draw conclusions about the population variances.
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(b) -0.99 As in part (a), we are given a z test statistic and we will calculate the corresponding P-value. Here the value of the z test statistic is -0.99. We previously determined that since the alternative hypothesis is of the form p < Po, the P-value is the area under the z curve to the left of the calculated value of the test statistic. Using SALT, we find that the cumulative probability associated with a z test statistic of -0.99, rounded to four decimal places, is -1.6449 x The cumulative probability is exactly the area under the z curve to the left, so we can use the cumulative probability to find the P-value, rounding the answers to four decimal places. P-value = (z curve area to the left of -0.99) = ____
The P-value is 0.1611.
P-value = 0.1602
You are given a z-test statistic of -0.99, and you want to find the corresponding P-value. The P-value represents the probability of observing a test statistic as extreme as, or more extreme than, the one calculated, given that the null hypothesis is true.
Step 1: Identify the z-test statistic
The z-test statistic is given as -0.99.
Step 2: Find the cumulative probability associated with the z-test statistic
Using a z-table or a statistical software, you can find the cumulative probability associated with a z-test statistic of -0.99.
Step 3: Determine the P-value
The cumulative probability you find in Step 2 is equivalent to the P-value since the alternative hypothesis is of the form p < p₀, and the P-value is the area under the z curve to the left of the calculated value of the test statistic.
P-value = (z curve area to the left of -0.99)
After finding the cumulative probability in a z-table or using a statistical software for a z-score of -0.99, you get:
P-value = 0.1611 (rounded to four decimal places)
So, the P-value is 0.1611.
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Consider the following graph:
a) The slope of the graph from ( 0 , 1 ) and ( 2 , 4 ) = 3/2
b) The slope of the graph from ( -2 , 1/4 ) and ( -1 , 1/2 ) = 1/4
c) No , the slope is not a constant
d) No , the graph is not linear
Given data ,
Let the exponential equation be represented as A
Now , the slope of the graph from ( 0 , 1 ) and ( 2 , 4 ) is given by
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
m = ( 4 - 1 ) / ( 2 - 0 )
m = 3/2
And , slope of the graph from ( -2 , 1/4 ) and ( -1 , 1/2 ) is given by
m = ( 1/2 - 1/4 ) / ( -1 - ( -2 ) )
m = ( 1/4 )
And , the slopes are not same for the line , so it is not constant and line is not a linear equation
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DL is a perpendicular bisector of chord GA. Identify the diameter.
Since DL is a perpendicular bisector of chord GA, the diameter is equal to 52 feet.
What is a perpendicular bisector?In Mathematics and Geometry, a perpendicular bisector is a line that bisects or divides a line segment exactly into two (2) equal halves and forms an angle that has a magnitude of 90 degrees at the point of intersection.
Generally speaking, the product of the segment lengths for each chord is a constant. Therefore, we can determine this constant as a product of the segment lengths with respect to the bisected chord as follows:
24 × 24 = 576 ft²
For the missing segment length of the diameter's chord (DO), we have:
DO × 36 = 576 ft²
DO = 576/36
DO = 16 ft.
Therefore, the total length of the diameter is given by;
DL = DO + OL
DL = 16 + 36
DL = 52 ft.
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can someone help with question 19
Answer:
48. 192
Step-by-step explanation:
In order to get from 3/4 to 3/16, one way would be to divide by 4. Another way is to multiply 3/4 by 1/4.
You can test whether multiplying by 4 works by multiplying 3/4 by 4 and 3 by 4.
When 3/4 is multiplied by 4, it would equal 12/3 which will simplify to 3. This can be done again with 3*4=12.
So the answer would be 12*4 = 48 and 48*4 = 192.
13 describe a situation in which you believe it would be appropriate to perform a regression analysis in a social service agency with which you are familiar? how would the results13 describe a situation in which you believe it would be appropriate to perform a regression analysis in a social service agency with which you are familiar? how would the results help the agency? help the agency?
One situation in which a social service agency may want to perform a regression analysis is when they are trying to determine the factors that contribute to the success or failure of their programs.
For example, let's say the agency runs a job training program and they want to know which factors (such as age, education level, or prior work experience) are most strongly correlated with program completion and employment outcomes for participants.
Performing a regression analysis can help the agency identify these key factors and assess their relative importance. This information can then be used to make targeted improvements to the program, such as adjusting the curriculum or offering additional support services to address specific barriers to success.
Additionally, the results of the regression analysis can be used to make a stronger case for the effectiveness of the program to funders and stakeholders. By being able to demonstrate a clear link between program participation and positive outcomes, the agency may be more likely to receive continued support and funding for their services.
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pls solve with solution pls.
The first quartile for 1 - 3 is Q₁ = 756660.5 (b) The 5th decile for 5 - 6 is D5 = 2724770.5and (c) The 80th percentile for 7 - 9 is 775346.4
What is Quartile?Recall that a quartile is a statistical term used to measure the spread of values above and below the mean
the first quartile is represented by Q1
Q₁ = 1/4 (n+1)th term
Q₁ = 1/4 (3026641+1)
Q₁ = 3026642/4
Q₁ = 756660.5
b) The 5th decile can be calculated using the formula 5 (n+1) / 10, where 5 is the middle data point of any given set of numbers. This means that half of the scores lie above and below the distribution
This implies that D5 = 5 (n+1) / 10
D5 = 5(5449540 + 1) / 10
D5 = 5*5449541 /10
D5 = 27247705/10
D5 = 2724770.5
c) The 80th percentile is a measure of how well you are performing compared to other test takers.
It is calculated by dividing the number of points you scored by 100 and then multiplying that number by 50 to get an ordinal rank
the 80th % = n/100 * 80
80th percentile = 969183/100 * 80
80th Percentile = 969183 *80 = 775346.4
From the calculation, it means that Saudi Arabia has less cases of
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First grade level equation 5x+2x=-8-6
Answer:
x = -2
Step-by-step explanation:
5x + 2x = -8 - 6
7x = -14
x = -2
g in a simple undirected graph with 8 vertices and 27 edges, how many vertices can have degree 7?
In a simple undirected graph with 8 vertices and 27 edges, the maximum degree for a vertex is 7, since a vertex can connect to all other vertices. To determine the number of vertices that can have degree 7, we will consider the properties of simple graphs and the relationship between vertices, edges, and degrees.
In a simple graph, there are no self-loops or multiple edges between the same pair of vertices. Therefore, the maximum number of edges in a simple graph with n vertices can be calculated using the formula:
[tex]Max edges = n(n-1)/2\\[/tex]
For our graph with 8 vertices, the maximum number of edges is:
Max edges = 8(8-1)/2 = 8(7)/2 = 28
Since our graph has 27 edges, it is almost a complete graph (which would have 28 edges). To figure out how many vertices can have a degree of 7, we can examine the degrees of other vertices.
If we have one vertex with degree 7, the remaining 7 vertices will be fully connected to each other, forming a complete subgraph with 7 vertices. The number of edges in this subgraph is:
Edges = 7(7-1)/2 = 7(6)/2 = 21
The total number of edges in the graph, including the vertex with degree 7, is 21 + 7 = 28. Since our graph has 27 edges, we need to remove one edge from this configuration. We can remove one edge between two of the vertices that are not the vertex with degree 7. By doing this, we maintain the degree 7 for the first vertex while reducing the degrees of two other vertices to 6.
Therefore, in a simple undirected graph with 8 vertices and 27 edges, 1 vertex can have a degree of 7.
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Write an equivalent expression to x-4y+9
Answer:
Step-by-step explanation:
you could break up a term, like the y term.
x+2y+2y+9 this is equivalent
Shivani runs a day care center. Of the 8 children at the day care center, 4 of them are six-year-olds. What is the probability that a randomly selected child will be a six-year-old? Write your answer as a fraction or whole number.
The probability that a randomly selected child will be a six-year-old is given by P ( A ) = 1/2
Given data ,
Let the probability that a randomly selected child will be a six-year-old be represented as P ( A )
Now , the total number of children in the day care = 8
The number of 6 year olds in the day care = 4
So , P ( A ) = number of 6 year olds in the day care / total number of children in the day care
On simplifying , we get
P ( A ) = 4/8
P ( A ) = 1/2
P ( A ) = 0.5
Hence , the probability is 1/2
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A line has a slope of
2/7 and passes through the point (7,0). Write its equation in slope-intercept form.
Answer: The slope-intercept form of the equation of a line is y = mx + b, where "m" is the slope and "b" is the y-intercept.
We know that the slope of the line is 2/7. We can also find the y-intercept by plugging in the coordinates of the given point (7,0) and solving for "b".
0 = (2/7) * 7 + b
0 = 2 + b
b = -2
So the equation of the line in slope-intercept form is:
y = (2/7)x - 2
Step-by-step explanation:
Answer: [tex]y=\frac{2}{7}x-7[/tex]
Step-by-step explanation:
m=slope=2/7
point(7,0)
put into point-slope formula
[tex](y-y_{1})=m(x-x_{1)}[/tex] where [tex](x_{1} ,y_{1)} =(0,7)[/tex]
[tex]y-7=\frac{2}{7}(x-0)[/tex] now put into slope- intercept(y=mx+b) form by simplifying, 0 goes away, and add 7 to both sides
[tex]y=\frac{2}{7}x-7[/tex] b is your y-intercept, where it hits y-axis
while cleaning data, a data analyst can use a changelog to keep a chronological list of changes they make. they can refer to it during the___period if there are errors or questions.
While cleaning data, a data analyst can use a changelog to keep a chronological list of changes they make. They can refer to it during the cleaning period if there are errors or questions that arise.
This can be a valuable tool in ensuring that the data is accurate and reliable, as it allows the analyst to track any changes that have been made and easily identify any issues that may need to be addressed. By keeping a detailed log of their actions, the analyst can also demonstrate the steps they took to clean the data, which can be useful for auditing purposes or for sharing their work with others on the team.
Ultimately, the use of a changelog can help to streamline the data cleaning process and make it more efficient, while also improving the overall quality of the data.
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9. Name the four basic logic gates.
The four basic logic gates are AND, OR, NOT, and XOR.
1. AND Gate: This gate takes two or more inputs and produces an output of 1 (true) only if all the inputs are 1 (true).
2. OR Gate: This gate takes two or more inputs and produces an output of 1 (true) if at least one of the inputs is 1 (true).
3. NOT Gate (Inverter): This gate has only one input and inverts it, producing an output of 1 (true) if the input is 0 (false) and vice versa.
4. XOR Gate (Exclusive OR): This gate takes two inputs and produces an output of 1 (true) if either, but not both, of the inputs are 1 (true).
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1. Which function is graphed to the right?
□ A. f(x) = -¹₂ +3x-2
□ B. f(x) =12(x+2)
+3
C. f(x) = ¹ + 2
x+3
Note tha the function that is graphed is f(x) = 1/(x+3) + 2. See same attached.
What is nature of the above function?The function f(x) = 1/(x+3) + 2 is a rational function with a vertical asymptote at x = -3. The graph of the function is a hyperbola that is shifted 2 units up from the standard hyperbola.
As x approaches positive or negative infinity, the function approaches the horizontal line y = 2.
Thus, it is correct to state that it is the function that is graphed.
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Find the area of the shaded region.
80⁰
5 cm
A≈ [?] cm²
Enter a decimal rounded to the nearest tenth.
The area of the shaded region for the circle is derived to be equal to 73.4 square centimeters.
How to evaluate for the area of shaded regionThe shaded region is the segment area in the circle, so it is derived by subtracting the area of the segment from the area of the circle as follows:
area of the circle = 22/7 × 5 cm × 5 cm
area of the circle = 78.57 cm²
area of sector = 80/360 × 22/7 × 5 cm × 5 cm
area of sector = 17.46 cm²
area of triangle = 5 cm × sin40° × 5 cm × cos40°
area of triangle = 12.31 cm²
area of the segment = 17.46 cm² - 12.31 cm²
area of the segment = 5.15 cm²
area of the shaded region = 78.57 cm² - 5.15 cm²
area of the shaded region = 73.42 cm²
Therefore, the area of the shaded region for the circle is derived to be equal to 73.4 square centimeters.
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which of follwing points is located at (-3,0)
Answer: B
Step-by-step explanation:
(x,y) (-3,0) look for the point located at -3 on the x-axis and 0 on the y-axis
Answer this question please!
a) There is no enough evidence of an increase in life expectancy.
b) P-value=0.07.
The P-value indicates that this sample result is not rare to happen (is greater than the significance level) even if the mean of the population is still 87 hours.
We have to perform a hypothesis test on the mean, with known standard deviation of the population.
The null hypothesis, which we will reject or not, states that the life expectancy has not increase (it stays equal or less than 87 hours).
The null and alternative hypothesis are
H₀: μ ≤ 87
H₁ : μ > 87
The significance level is α=0.01.
The z-value is
z = 1.5
The P-value for z is = 0.06681
The P-value (0.07) is greater than the significance level (0.01), so the effect is not significant. We fail to reject the null hypothesis.
There is no enough evidence of an increase in life expectancy.
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complete question:
D" size batteries produced by MNM Corporation have had a life expectancy of 87 hours. Because of an improved production process, the company believes that there has been an increase in the life expectancy of its "D" size batteries. A sample of 36 batteries showed an average life of 88.5 hours. Assume from past information that it is known that the standard deviation of the population is 9 hours.
(a) Use a 0.01 level of significance, and test to determine if there has been an increase in the life expectancy of the "D" size batteries.
(b) What is the p-value associated with the sample results? What is your conclusion, based on the p-value?
The radius of a circle is 3 feet. What is the length of a 180° arc? 180° 77 Give the exact answer in simplest form. 00 r=3 ft feet
Step-by-step explanation:
TOTAL ( 360 degree) circumference is pi * d d = 2r = 6ft
you want 180 degrees of this
180 / 360 * pi* 6 = 1/2 * 6 pi = 3 pi ft
What is the yield on a corporate bond with a $1000
face value purchased at a discount price of $850, if
it pays 8% fixed interest for the duration of the
bond?
yield = [?] %
Give your answer as a percent rounded to the nearest
hundredth.
The yield on a corporate bond is A = 9.14 %
Given data ,
Face value of the bond (FV) = $1000
Purchase price of the bond = $850
Fixed interest rate = 8%
The annual interest payment (I) can be calculated as a percentage of the face value:
I = (Fixed interest rate / 100) * FV
Substituting the given values:
I = (8 / 100) x 1000 = $80
The yield (Y) can be calculated as:
Y = (Annual interest payment / Purchase price) * 100
Substituting the calculated values:
Y = (80 / 850) x 100 = 9.41%
Hence , the yield on the corporate bond is 9.41%
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question # 1
How many people were in the survey shown in the frequency table?
A. 42
B. 27
C. 30
D. 10
question # 2
What is wrong with the frequency table?
A. There is nothing wrong with the table.
B. The tallies are not totaled correctly.
C. There is not enough data.
D. There should be a row for 58.
question # 3
Which example would be likely to give a valid conclusion?
A. People leaving the library are asked if they like to read.
B. Five students are asked how tall they are.
C. The teacher displays the class's test scores in stem-and-leaf plot.
D. Eight tall people are measured to find the height of a 5th grade student.
question # 4
How many people were in the survey shown in the frequency table?
A. 34
B. 32
C. 13
D. 30
question # 5
What is wrong with the frequency table?
A. The tallies are not totaled correctly.
B. There should not be a row for 57.
C. There is nothing wrong with the table.
D. There is not enough data.
Answer:
Question 1: 27
Question 2: nothing wrong with the table
Question 3: Not sure which one to pick
Question 4: 15
Question 5: There is not enough data
Step-by-step explanation:
[tex]Question[/tex] #1
In the first picture we can see that if we add up all the frequencies we can conclude to: 2+15+8+2
= 27.
Thus the answer to question 1 is, 27
[tex]Question[/tex] #2
By looking at the FIRST picture what I can conclude is that there should be nothing wrong with the table. ( Not 100% sure )
Thus the answer to question 2 is, nothing wrong with the table
[tex]Question[/tex] #3
For this one I am not sure.
[tex]Question[/tex] #4
Well by looking at the SECOND picture I can conclude by adding:
1+8+4+2 = 15
Thus the answer to question 4 is, 15
[tex]Question[/tex] #5
Well looking at it judging by the picture given what I can conclude is that there is not enough data for the frequency.
Thus the answer to question 5 is, there is not enough data
Answer:
#1 A- 42
#2 D- Should be a row for 58
#3 A- Asking people leaving the library if they like to read
#4 C- 13
#5- Nothing wrong with the table
A new truck costing 50,000 with a residual value of 4,000 has an estimated useful life of five years. Using the declining- balance method at twice the straight-like rate, the depreciation expense in year 2 is:
1. 20,000
2. 12,000
3. 18,000
4. 7,200
The depreciation expense in year 2 using the declining-balance method at twice the straight-line rate is $10,400, not one of the options provided.
To calculate the depreciation expense for year 2 using the declining-balance technique at double the straight-line rate, we must first estimate the straight-line rate and the double-declining rate.
The straight-line rate of depreciation is calculated as follows:
Straight-line rate = 1 / Estimated useful life
Straight-line rate = 1 / 5 = 0.2 or 20%
The double-declining rate of depreciation is calculated as follows:
Double-declining rate = Straight-line rate x 2
Double-declining rate = 20% x 2 = 40%
Using the double-declining rate of depreciation, the depreciation expense for year 1 can be calculated as follows:
Depreciation expense year 1 = Beginning book value x Double-declining rate
Depreciation expense year 1 = $50,000 x 0.4 = $20000
The beginning book value for year 2 is calculated as follows:
Beginning book value year 2 = Cost - Accumulated depreciation year 1 - Residual value
Beginning book value year 2 = $50,000 - $20,000 - $4,000 = $26,000
Using the double-declining rate of depreciation, the depreciation expense for year 2 can be calculated as follows:
Depreciation expense year 2 = Beginning book value year 2 x Double-declining rate
Depreciation expense year 2 = $26,000 x 40% = $10,400
Therefore, the correct answer is not among the options provided.
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8 The graph of a linear function is shown on the coordinate grid.
A m=
13
10
8
6
+
10-8-6-4-2
4 6 8 10
-2
-5
--8
10
What is the slope of the line represented by the graph?
8 m = -²
N
N
HIS
The slope of the line represented by the graph include the following: C. m = 3.
How to calculate or determine the slope of a line?In Mathematics and Geometry, the slope of any straight line can be determined by using the following mathematical equation;
Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)
Slope (m) = rise/run
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
By substituting the given data points into the formula for the slope of a line, we have the following;
Slope (m) = (9 - (-3))/(2 - 0)
Slope (m) = (9 + 3)/(2)
Slope (m) = 12/4
Slope (m) = 3.
Based on the graph, the slope is the change in y-axis with respect to the x-axis and it is equal to 3.
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What two numbers multiply to -6 and add to -5
We can see here that the two numbers that multiply to -6 and add to -5 are -6 and 1.
What is multiplication?A basic mathematical operation known as multiplication combines two or more numbers to produce a brand-new number known as their product. It involves adding the same number repeatedly.
Calculating areas and volumes, figuring out rates and proportions, and solving equations are just a few examples of the various applications of multiplication in mathematics, science, and daily life.
Multiplying to get -6:
-6 × 1 = -6
Adding to get -5:
-6 + 1 = -5
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pls hlp thx your the best
The total cost for 13 rides is 46 $.
Amount to be paid as entry fee = 20 $
Amount to be paid in each ride = 2 $
Therefore, total cost for 13 rides, P = 20 + (2 x 13)
P = 46 $
Total cost for r rides, P' = (20 + 2r) $
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used in case-control studies, a type of indirect measure of the association between frequency of exposure and frequency of outcome is known as the: group of answer choices odds ratio population risk difference attributable risk all of these are correct.
In case-control studies, the indirect measure of association between frequency of exposure and frequency of outcome is known as the odds ratio.'
The answer to your question is odds ratio. In case-control studies, odds ratio is used as an indirect measure of the association between frequency of exposure and frequency of outcome. It compares the odds of exposure in cases to the odds of exposure in controls, and provides an estimate of the strength of the association between exposure and outcome. While other measures such as population risk difference and attributable risk may also be calculated in case-control studies, odds ratio is the most commonly used measure of association.
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