the drop down box numbers are 39, 90, 120, and 180

Answer:

C. 189 square centimeters

Step-by-step explanation:

Area of a Square/Rectangle is base x height

= 7 X 7 = 49

Area of a triangle = 1/2 Base X Height

= 1/2 X 7 X 10

= 35

There are 4 triangles

35 X 4 = 140

140 + 49 = 189

= 189cm^2

Answer: C. 189 cm²

Step-by-step explanation:

      A rectangle/square is solved for with A = L * W.

The middle square has a (surface) area of:

7 * 7 = 49 cm²

     We then have four triangles. These are solved for with [tex]\frac{B*H}{2}[/tex]. Since all four are congruent, I will multiply one of them by 4.

The triangles have a total (surface) area of:

10 * 7 = 70

70 / 2 = 35

35 * 4 = 140 cm²

     Lastly, we will add the two totals together.

140 cm² + 49 cm² = 189 cm²

         The object has a surface area of C. 189 cm².

The length of all the strings combined is 84 inches, while the length of the smallest string is 6 inches.

A line plot is a graph that shows the frequency of each value by displaying data as points or checkmarks above a number line.

In the given line plot, if we consider each of the options with the plot given to us, we will get to know which of the options are true or not.

A.) A. The difference between the longest length and shortest length is 14 inches.

As given in the plot, the longest string is 14 units while the smallest is 6 units, therefore, the first option is incorrect.

B.) I have twice as many 12-inch strings as I do 8-inch strings.

In the plot since the number of dots represents the number of strings of a particular length, therefore, the number of strings of length 12-inches is 4 and the number of strings of length 8-inches is 2. Thus, the given options are correct.

C.)  The total length of string that I have is 84 inches.

As per the plot, the number of strings of length 6 inches is 1, the number of strings of length 8 inches is 2, the strings of length 12inches is 4, and the number of strings of length 14 inches is 1. Thus, the sum of the length of all the strings is 84 inches.

Hence, the statement is correct.

D.) I cannot determine what the shortest string is by looking at my line plot.

As given in the plot, the length of the smallest string is 6 inches, thus, the statement is incorrect.

E.) Since I need 100 total inches of string for my project, I have enough string.

As the length of all the strings combined is just 84 inches, thus, the statement is incorrect.

Hence, the only option that is correct is 'B' and 'C'.

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Answer:

f(1) = 12

Step-by-step explanation:

We know that f(x)=f(x-1)+2x+1

We are told that f(2) = 17

Use the first equation to calculate f(1).  Since f(2) is known and f(x-1) will become f(1) after f(2-1) is simplified to f(1).

17 = f(2-1)+2*2+1

f(2-1) = 17 - 5

f(1) = 12

Answer:

1.53x−14.23

Step-by-step explanation:

simplify:

5.03x−8.03−(3.5x+6.2)

Distribute the Negative Sign:

=5.03x−8.03−1(3.5x+6.2)

=5.03x−8.03−1(3.5x)+(−1)(6.2)

=5.03x−8.03−3.5x−6.2

Combine Like Terms:

=5.03x−8.03+−3.5x−6.2

=(5.03x−3.5x)+(−8.03−6.2)

=1.53x−14.23

(5.03x -8.03) - (3.5x +6.2)=

Answer:

The Formula for Percent Proportion is Parts /whole = percent/100. This formula can be used to find the percent of a given ratio and to find the missing value of a part or a whole.

Answer:

a = 9

Step-by-step explanation:

[tex]\frac{4}{12}[/tex] = [tex]\frac{a}{27}[/tex] ( cross- multiply )

12a = 108 ( divide both sides by 12 )

a = 9

Answer:

C. (25,20)

Step-by-step explanation:

Edge2022 <3

Good luck and remember (yall that take edge) , you can get through the day no matter how hard it may seem. I have faith In you guys :).

If number of hours worked is less than 20, 500 flat rate is preferable

and, If number of hours is more than 20, hourly rate i.e. 20 per hour is better.

An inequality is a mathematical statement that compares two values or expressions using inequality symbols such as "<" (less than), ">" (greater than), "<=" (less than or equal to), ">=" (greater than or equal to), or "≠" (not equal to).

In the first scenario, where there is a $500 flat rate regardless of the number of hours worked, the pay per hour remains constant at $500 divided by the number of hours worked.

So, the graph for this scenario would be a horizontal line at a height of $500.

In the second scenario, where the contractor is paid $20 per hour worked, the pay per hour is fixed at $20.

let the number of hours be worked be x.

Then, 20x < 500

x< 25

So, if number of hours worked is less than 20, 500 flat rate is preferable

and, If number of hours is more than 20, hourly rate i.e. 20 per hour is better.

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#SPJ7

Hello!

Let's solve this equation:

84=h-8

This is the same as

h-8=84

Add 8 to both sides:

h=84+8

h=92

Hope everything is clear.

Let me know if you have any questions!

#KeepLearning

:-)

The cost of painting the rectangular board with a semicircular top is $31.065 to the nearest hundredth.

To find area of the composite figures,

The dimentions of the rectangle is 3 by 4 foot. The area of the rectangle is,

[tex]A_r=3\times4\\A_r=12\rm \;ft^2[/tex]

The radius of the semicircle is 1.5 m. The area of the semicircle is,

[tex]A_{sc}=\dfrac{1}{2}\pi\times(1.5)^2\\A_{sc}=\dfrac{1}{2}(3.14)\times(1.5)^2\\A_{sc}=3.5325\rm\; ft^2[/tex]

The area of the composite figure is,

[tex]A=12+3.5325\\A=15.5325\rm\;ft^2\\[/tex]

The rate of  painting is $2.00 per square foot. Thus the cost to paint the figure is,

[tex]A=15.5325\times2\\A=31.065[/tex]

Hence, the cost of painting the rectangular board with a semicircular top is $31.065 to the nearest hundredth.

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Answer:31

Step-by-step explanation:

Answer:

x=21/5

Step-by-step explanation:

5x:9 = 7:3

Turn the ratios into fractions:

5x/9 = 7/3

Then cross mutiply

15x=63

x=21/5

Answer:

  3 tents hold 2 campers

Step-by-step explanation:

The given relations can be expressed as a single equation in the number of 2-camper tents.

__

Let x represent the number of 2-camper tents. Then the number of 4-camper tents is 6-x, and the total number of campers in tents is ...

  2x +4(6 -x) = 18

  -2x +24 = 18

  -2x = -6 . . . . . . subtract 24

  x = 3 . . . . . . . divide by -2

Exactly 3 tents hold 2 campers.

_____

Additional comment

The other 3 tents hold 4 campers.

Another way to consider this is to assume that all tents hold 2 campers, and then realize there are 18 -6×2 = 6 campers left over. If these are placed 2 per tent, then there will be 6/2 = 3 tents with 4 campers. The remaining 3 tents will have 2 campers.

w = won game

l = lost game

w + l = 15

and

w = I + 3

so

l + 3 + l = 15

2l = 12

l = 6

lost = 6

won = 9

Answer:

The ratio of wins to losses is 3 to 1, out of 32 total games. 3:1 has a total of 4 parts (3+1).

Total games divided by total parts is 32/4 = 8.

Now multiplying number of parts to divisor gives us 3x8 : 1x8 or 24:8. Therefore they won 24 games, lost 8.

Step-by-step explanation:

Answer:

9. (a) 1/4

   (b) remove 3 alphabet cards

   (c)  add 4 number cards

10.  1/8

Step-by-step explanation:

Question 9

Given:

⇒ total number of cards = 8 + 10 + 6 = 24 cards

[tex]\mathsf{Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ outcomes}}[/tex]

(a) P(picture card) = 6/24 = 1/4

(b) P(alphabet card) = 10/24 = 5/12

If we remove 3 alphabet cards from the box

⇒ number of alphabet cards = 10 - 3 = 7

⇒ total number of cards = 24 - 3 = 21

Therefore, P(alphabet card) = 7/21 = 1/3

(c)  P(number card) = 8/24 = 1/3

If we add 4 number cards to the box:

⇒ number of number cards = 8 + 4 = 12

⇒ total number of cards = 24 + 4 = 28

Therefore, P(number card) = 12/28 = 3/7

--------------------------------------------------------------------

Question 10

Given:

⇒ area of ΔSDR = area of ΔPRQ = 1/2 × 4 × 4 = 8 cm²

As PR = SD = 4cm

Area of rectangle = (4 + 4) × (12 + 4) = 128 cm²

P(point lies in ΔSDR) = 8/128 = 1/16

P(point lies in ΔPRQ) = 8/128 = 1/16

P(point lies in ΔSDR) OR P(point lies in ΔPRQ) = 1/16 + 1/16 = 2/16 = 1/8

Answer:

[tex]-3m-2k[/tex]

Step-by-step explanation:

Given to simplify : 3k - (2m + 5K) - m

Solution :

[tex]\mathrm{Apply\:the\:distributive\:law}:\quad \:-\left(a+b\right)=-a-b[/tex]

[tex]-\left(2m+5k\right)=-2m-5k[/tex]

[tex]=3k-2m-5k-m[/tex]

[tex]\mathrm{Group\;like\;terms}[/tex]

[tex]=-2m-m+3k-5k[/tex]

[tex]\mathrm{Group\;like\;terms}[/tex]

[tex]=-3m+3k-5k[/tex]

[tex]\mathrm{Group\;like\;terms}[/tex]

[tex]=-3m-2k[/tex]

[RevyBreeze]

Use the distributive property:-

-(2m+5k) = -2m-5k [tex]\checkmark[/tex]

[tex]\rule{270}{1}[/tex]

Let's simplify this expression by combining like terms:-

[tex]\bigstar[/tex] The like terms are:-

3k, -5k

and

-2m, -m

[tex]\bigstar{[/tex] Combine Like terms:-

3k-5k=-2k

-2m-m=-3m

Hence, we have:-

[tex]\bigstar{\boxed{\pmb{-2k-3m}}[/tex]

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

Answer:

V≈2144.66cm³

Step-by-step explanation:

Answer:

He has 4 full boxes

6 Apple pies are leftover

Step-by-step explanation:

42/9 = 4.67 How many full boxes can he fill

9 X 4 = 36 He filled out 4 full boxes

42-36=6 Total - Filled = Remainder

Answer:

she has 4 full boxes of applepies and she has 6 leftover apple pies

Step-by-step explanation:

Answer:

15/28, 15/28, 15/28

Step-by-step explanation:

1. Is simplified

2. Divided

3. Evaluated

(Yes I know there the same but its just in case.)

Answer:

1/18 x 9 x 1 = .5 cubic yards. Why would you ever waste time asking this....

Step-by-step explanation:

Answer:

Step-by-step explanation:

We have to find the volume. we can use volume of the cuboid formula

l = 1/18 yard

w = 9 yard

h = 1 yard

Volume = l*w*h

             [tex]= \dfrac{1}{18}*9*1\\\\\\= \dfrac{1}{2}\\\\\\= 0.5 \ \sf cubic yard[/tex]

0.5 cubic yards of cement is needed

Answer:

5

Step-by-step explanation:

Determina el grado de y =3r⁵ + 8r³

5

The volume of a cone with the same radius and height as the cylinder is 40cm³.

A cylinder is a three-dimensional object. It is a prism with a circular base.

Volume of a cylinder = nr^2h

Volume of a cone = 1/3(nr^2h)

The volume of a cone, is 1/3 that of a cylinder.

Volume of the cone = 1/3 x 120 = 40

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Answer:cool

Step-by-step explanation:

iono

Answer: The answer is ASA I got it right

Step-by-step explanation:

brainliest pls <3

Answer:

31.8  cm^2

Step-by-step explanation:

Area of WHOLE circle  = pi r^2

semicircle is 1/2 of this    ( r = 1/2 of the diameter)

  1/2 pi r^2

  1/2 pi  (9/2)^2 =

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Area of a Parallelogram is ~

[tex]\qquad \sf  \dashrightarrow \:base \times height[/tex]

[tex]\qquad \sf  \dashrightarrow \:7 \times 5[/tex]

[tex]\qquad \sf  \dashrightarrow \:35 \: {cm}^{2} [/tex]

Answer

102.1

Step-by-step explanation:

area of the shaded region is the area of the the whole circle subtract area area of the unshaded minor segment.

Answer:

[tex]\frac{1}{36}[/tex]

Step-by-step explanation:

The probability of having 1 is 1/6.

The probability of it happening twice in a row is 1/6 * 1/6 = 1/(6*6)=1/36

Answer:

the answer is B 0.760

Step-by-step explanation:

i did the test.

‎[tex] \qquad\quad\hookrightarrow{\sf { 1000(e-1)}}[/tex]

[tex] \begin{aligned}&\longrightarrow \int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999} \int_{k}^{k + 1}e ^{x - |x| }dx \\ \\ &\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999} \int_{k}^{k + 1}e^{x - k}dx \\\\&\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^{999}e^{x - k \big |_{k}^ {k + 1}} \\ \\& \longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = \sum_{k = 0}^ {999}(e - 1)\\\\&\longrightarrow\int_{0} ^{1000} {e}^{ - |x| }dx = 1000(e - 1)\end{aligned}[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Derivative of tan(x) is sec²x

[tex]\qquad \sf  \dashrightarrow \: \therefore \dfrac{d}{dx} ( \tan(x)) = { \sec}^{2} (x)[/tex]

You can check the first principle method of derivation in attachment

[tex]\rightarrow \sf \dfrac{d}{dx} (tan(x))[/tex]

[tex]\rightarrow \sf \dfrac{d}{dx} ( \ \dfrac{sin(x)}{cos(x)} \ )[/tex]

use the quotient rule

[tex]\rightarrow \sf \dfrac{cos(x) * \dfrac{d}{dx} (sin(x)-sin(x)*\dfrac{d}{dx}(cos(x) }{cos(x)^2}[/tex]

[tex]\rightarrow \sf \dfrac{cos(x) * cos(x)-sin(x)*(-sin(x) )}{cos(x)^2}[/tex]

[tex]\rightarrow \sf \dfrac{cos(x)^2+sin(x)^2}{cos(x)^2}[/tex]

[tex]\rightarrow \sf \dfrac{1}{cos(x)^2}[/tex]

[tex]\rightarrow \sf sec(x)^2[/tex]

used formula's :