The energy conversation in an electrolytic cell is
(a)electrical to chemical
(b)electrical to mechanical
(c)chemical to electrical
(d)chemical to mechanical ​

Answers

Answer 1

Answer:

Your answer is electrical to chemical.


Related Questions

The phase diagram of ammonia.

Answers

Explanation:

Ammonia is a gas,

however at low temperature or high pressure the gas become liquid and at extreme conditions,a solid

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Hi, I need help with this please.

Answers

The final temperature of the water when thermal equilibrium is reached is approximately 24.36°C.

What is the final temperature of the water?

The principle of conservation of energy which states that the heat lost by the metal cubes must be equal to the heat gained by the water is used to determine the final temperature of the water.

The formula to calculate the heat lost by a metal cube is:

Q = m × c × ΔT

where;

Q is the heat lost,m is the mass of the cube,c is the specific heat capacity of the metal, and ΔT is the change in temperature of the metal.

For the silver cube:

m = density × volume

m = 10.49 g/cm³ × (2.31 cm)³

m = 58.48 g

c = 0.235 J/g°C (specific heat capacity of silver)

ΔT = (82.2°C - 19.6°C)

ΔT = 62.6°C

Q = 58.48 g × 0.235 J/g°C × 62.6°C

Q = 877.4 J

For the gold cube:

m = density × volume

m = 19.32 g/cm³ × (2.78 cm)³

m = 170.5 g

c = 0.129 J/g°C (specific heat capacity of gold)

ΔT = (82.2°C - 19.6°C)

ΔT  = 62.6°C

Q = 170.5 g × 0.129 J/g°C × 62.6°C = 1354.4 J

The total heat lost by both cubes is:

Qtotal = 877.4 J + 1354.4 J

Qtotal= 2231.8 J

To calculate the final temperature of the water, we can use the formula:

Q = mwater × cwater × ΔT

where;

mwater is the mass of water,cwater is the specific heat capacity of water, and ΔT is the change in temperature of the water.

Solving for ΔT:

ΔT = Qtotal / (mwater × cwater)

ΔT = 2231.8 J / (113.0 g × 4.184 J/g°C)

ΔT = 4.76°C

Final temperature = 19.6°C + 4.76°C

Final temperature= 24.36°C

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Which of the following elements is NOT involved in the cycling of energy and matter on Earth? O Phosphorus O Gold O Nitrogen O Carbon ​

Answers

Gold is not involved in the cycling of energy and matter on Earth.

option B.

What is Biogeochemical cycles?

Biogeochemical cycles refer to the pathways by which essential elements such as carbon, nitrogen, and phosphorus move through the Earth's biosphere, atmosphere, geosphere, and hydrosphere. These cycles are crucial for maintaining the balance of elements required for life on Earth, and they involve both biotic and abiotic processes.

The carbon cycle involves the movement of carbon through the atmosphere, the biosphere, and the oceans, with processes such as photosynthesis, respiration, and decomposition contributing to carbon uptake and release. Carbon is also stored in rocks and sediments as fossil fuels.

The other three elements listed - phosphorus, nitrogen, and carbon - are all essential elements involved in biogeochemical cycles on Earth, including the phosphorus cycle, nitrogen cycle, and carbon cycle. Gold, on the other hand, is a relatively inert element and does not play a significant role in the cycling of energy and matter on Earth.

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Sodium and Lithium have similar chemical properties. What characteristic of these elements explains why they are chemically similar?

F. Their atoms both have 1 valence electron

G. Their atoms both have more neutrons than protons

H. Their atoms have the same number of energy levels

J. Their atoms contain equal numbers of protons and electrons


I am not in college...

Answers

These elements' shared possession of a single valence electron in their atoms explains why they are chemically related. As a result, F is the right response.

An atom's valence shell electrons control how it interacts with its neighbours and, consequently, its chemical characteristics. Lithium and sodium both contain one valence electron, hence they have comparable chemical characteristics. Elements from this family include lithium, sodium, potassium, rubidium, cesium, and francium (Li, Na, K, Rb, Cs, and Fr, respectively). The components of Group 1 have similar traits. Each of them is a delicate silver metal. These metals have low melting temperatures and are extremely reactive because of their low ionisation energy.

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