The equation 2x² + 2y2 – 8x - 12y + 16 = 0 defines a circle.
which of these shows a correct step for determining the center and radius of this circle? choose all that are correct.
(2x2 – 8x + 16) + (2y2 – 12y + 36) = -16 + 36
(x - 4)2 + (y - 9)2 = 5
(x2 - 4x + 4) + (y2 – 6y + 9) = -8 +13
ox? + y2 - 4x - 6y = -16
(x - 2)2 + (y - 3)2 = 5

Answers

Answer 1

Answer:

  C, E

Step-by-step explanation:

Here, we want to change the equation of a circle from general form to standard form. This is done by making the leading coefficients 1, completing the squares, and then rewriting the equation in standard form.

The leading coefficients of the given equation are 2, so we first want to divide by 2. This gives ...

  x² +y² -4x -6y +8 = 0

Subtracting 8 puts us in better position to complete the squares.

  x² +y² -4x -6y = -8

Now, we can add the squares of half the coefficients of the linear terms.

  (x² -4x +4) +(y² -6x +9) = -8 +13 . . . . . . matches C

And we can simplify this to the standard form equation:

  (x -2)² +(y -3)² = 5 . . . . . matches E


Related Questions

I hate these types of problems
I was never taught this stuff

Answers

I’m not in geometry but i think that the answer might be 36. Because you’re finding perimeter and perimeter is adding up all the sides. So, it would be 10+10+8+8=36

Donald said that the median is 2. What did he do wrong?
8,13,2,4,48

Answers

Answer:

He did not put the numbers in order.

Explanation:

The numbers need to be in order from smallest to largest before you find the median.

Please help! I don't know what answer b is, but i know a, thank you.

Answers

They are corresponding angles

Step-by-step explanation:

We know that x=75 because

[tex]180 - 105 = 75[/tex]

75⁰ is angle EFB

Since we know this, and because we know that AD//EH,

We can conclude that x=75(AD is parallel to EH and angle CBA or x and angle EFB are corresponding angles)

NO LINKS PLEASE
I NEED THEM TODAY
NO LINKS!!!

Answers

Answer:

13. True, False, True

14. False, True, True

15. All true

What is the diameter of a hemisphere with the volume of 74466

Answers

[tex]\textit{volume of a hemisphere}\\\\ V=\cfrac{1}{2}\cdot \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=74466 \end{cases}\implies 74466=\cfrac{1}{2}\cdot \cfrac{4\pi r^3}{3} \\\\\\ 74466=\cfrac{2\pi r^3}{3}\implies 223398=2\pi r^3\implies \cfrac{22398}{2\pi }=r^3\implies \cfrac{111699}{\pi }=r^3 \\\\\\ \sqrt[3]{\cfrac{111699}{\pi }}=r~\hfill \stackrel{\textit{diameter = 2r}}{2\sqrt[3]{\cfrac{111699}{\pi }}\implies \sqrt[3]{\cfrac{893592}{\pi }}}~~ \boxed{\approx~~65.77}[/tex]

Given the function h of x equals 2 times the cube root of x minus 10 end root plus 4, what is the x-intercept of the function?

–10
–4
2
8

Answers

Step-by-step explanation:

if I understand correctly, then we have

h(x) = 2 × cubic root(x - 10) + 4

the x-intercept is the x value where y or h(x) = 0.

0 = 2 × cubic root(x - 10) + 4

0 = cubic root(x - 10) + 2

-2 = cubic root(x - 10)

-8 = x - 10

x = 2

The intercept is the point where a line or curve crosses the axis. The x-intercept of the function is (2,0)

Intercept of a function

The intercept is the point where a line or curve crosses the axis. Given the function below:

h(x) = 2(∛x-10) + 4

For the x-intercept, it is the point where h(x) = 0.

Substitute

2(∛x-10) + 4 = 0

2(∛x-10)  = -4

(∛x-10)  = -2

Take the cube of both sides

x-10 = (-2)^3
x -10 = -8

x = -8 + 10

x = 2

Hence the x-intercept of the function is (2,0)

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A cyclist travels a distance of 837 1/2 feet in 25 seconds. The cyclist travels at a constant rate. What is the unit rate, in feet per second, at which the cyclist travels?


PLEASE

Answers

Answer:

[tex]\boxed{33.5 \ \text{feet/second}}[/tex]

Step-by-step explanation:

To find the unit rate, we need to find out how much distance does the cyclist travel in 1 second. For that, we need to use the unitary method. A unitary method is a method that determines the unit rate of an object.

Note: Since the cyclist travels at a constant rate, unitary method can be used.

[tex]\rightarrow 837 \dfrac{1}{2} \ \text{feet in 25 seconds}[/tex]

[tex]\rightarrow 837.5 \ \text{feet} = 25 \ \text{seconds}[/tex]

Divide both sides by 25:

[tex]\rightarrow \dfrac{837.5}{25} \ \text{feet} = \dfrac{25}{25} \ \text{seconds}[/tex]

[tex]\rightarrow 33.5 \ \text{feet} = 1 \ \text{seconds}[/tex]

[tex]\rightarrow \boxed{33.5 \ \text{feet/second}}[/tex]

Learn more about unitary method: https://brainly.com/question/19423643

Evaluate the triple integral. X dv, where e is bounded by the paraboloid x = 4y2 4z2 and the plane x = 4. E

Answers

The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762

Parabloid, x = 4y² + 4z²

plane x = 4

x = 4y² + 4z²

x = 4

4 = 4y² + 4z²

4 = 4 (y² + z² )

1 = y² + z²

from polar coordinates

y = r cos θ

z = r sin θ

r² = y² + z²

The limits of the integral

0 ≤ θ ≤ 2π

4r² ≤ x ≤ 4

0 ≤ r ≤ 1

[tex]\int\limits\int\limits\int\limits {x} \, dV = \int\limits^1_0\int\limits^a_b\int\limits^c_d {x} \, dx ( rdrdz)[/tex]

where

a = 4

b = 4r²

c = 2r

d = 0

The first integral using limits c and d gives:

[tex]2pi\int\limits^1_0\int\limits^a_b {xr} \, dx[/tex]

The second integral using limits a and b

[tex]pi\int\limits^1_0 {16 } } \, rdr - pi\int\limits^1_0 {16r^{5} \, dx[/tex]

[tex]16pi\int\limits^1_0 { } } \, rdr - 16pi\int\limits^1_0 {r^{5} \, dx[/tex]

[tex]16pi\int\limits^1_0 { } } \, [r-r^{5}]dr[/tex]

The third integral using limits 1 and 0 gives: 16.762

Read more on Triple integral here: https://brainly.com/question/27171802

The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762

What is integration?

Integration is defined as adding small parts to form a new significant part.

Parabloid, x = 4y² + 4z²

plane x = 4

x = 4y² + 4z²

x = 4

4 = 4y² + 4z²

4 = 4 (y² + z² )

1 = y² + z²

from polar coordinates

y = r cos θ

z = r sin θ

r² = y² + z²

The limits of the integral

0 ≤ θ ≤ 2π

4r² ≤ x ≤ 4

0 ≤ r ≤ 1

[tex]\int\int\intxdV = \int_0_1\int_b_a\int_d_cxdx(rdrdz)[/tex]

where

a = 4

b = 4r²

c = 2r

d = 0

The first integral using limits c and d gives:

[tex]2\pi\int_0^1\int_b^axydx[/tex]

The second integral using limits a and b

[tex]\pi \int_0^116rdr-\pi\int_0^116r^5dx[/tex]

[tex]16\pi \int_0^1rdr-16\pi\int_0^1 r^5dx[/tex]

[tex]16\pi\int_0^1[r-r^5]dr[/tex]

The third integral using limits 1 and 0 gives: 16.762

Read more on Triple integral here:

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The value of stock changes from $22 on Monday to $30 on Tuesday. Calculate the percent increase.

Answers

22 + 22 x r = 30

22 x r = 30 - 22

r = 8 : 22

r = +36,36%

r = increase rate

Maryan harvested a total of 22.69 t of rice and sold it in 100 kg bags. how many full bags did she sell​

Answers

Answer:

1t = 1000kg

22.69 x 1000= 22690 kg

22690 kg ÷ 100 = 226.9

I would usually round it to 227 but I would say 226, since they are asking how many full bags she sold.

4x+y=2 solve for y algebra 2

Answers

4x+y=2
-4x. -4x

y=2-4x

Answer:

Step-by-step explanation:

4x + y = 2

y = -4x + 2

please help asap



For each relation, decide whether or not it is a function. ​

Answers

Answer:

Step-by-step explanation:

Refer to the definition of a function. I'll just give you a layman's definition to be concise.

For something to be a function, there needs to be exactly 1 output for every input. You cannot have a case where you input 1 value, and get 2 or more values as an output.

In math we call all the possible input values the domain, and we call all the possible output values the range.

Let's take a look at each situation on your worksheet.

1. Is a function. This is because only one arrow stems from each input value. There are cases where the different input values give the same output, sure, but each input returns 1 discrete thing, not an array of things.

(Think of it this way, if i had a machine that could answer any question I had with yes, no or maybe. I wouldn't want the machine to give me "yes and maybe" or "yes and no" as the result when I ask it a question. That doesn't make sense and I would think the machine is broken. What could happen, is that I ask the machine different questions, and for those different questions, it gave me the same answer, like "yes" and "yes" respectively. in that case, it would be acceptable, because it isn't contradicting itself for any individual question.)

2. Not a function. There are 2 different output values for b.

(Refer back to my machine analogy. The "machine" in this question is contradicting itself. I gave the machine one input, and the machine is telling me, "it's this and actually it's this other thing too")

3. Is a function for the same reasons as 1.

4. Isn't a function.

(It's basically telling you, the machine reads -6 as -4, but it also reads -6 as 0, and also 2. And it also tells you the machine reads -4 as -3, but it also reads it as 8. Again, the machine should only read 1 input in 1 way and not contradict itself. )


[tex] \sf \large \: find \: \frac{dy}{dx} \: if \: x=a ( \Theta + sin \Theta ) , y= a (1- Cos \Theta ) \: at \: \Theta = \frac{π}{2} \\ \\ \\ \\ \\ [/tex]

Kindly Don't Spàm!
Thanks!!!!​

Answers

Given :

[tex] \: \: \: [/tex]

[tex] \rm \large \: x = a ( \Theta + Sin \Theta )[/tex]

[tex] \: \: \: [/tex]

[tex] \rm \large y = a ( 1 - cos \: \Theta )[/tex]

[tex] \: \: [/tex]

Now , x = a ( θ + sin θ )

[tex] \: \: [/tex]

Diff w.r.t " θ "

[tex] \: \: \: [/tex]

[tex] \rm \large\frac{dx}{dθ } = a \: \frac{d}{dθ} (θ + \sin\theta )[/tex]

[tex] \: \: [/tex]

[tex] \boxed{ \rm \large\underline{ \frac{dx}{d \theta} = a(1 + \cos \theta ) }}[/tex]

[tex] \: \: [/tex]

Now y = a ( 1-cosθ)

[tex] \: \: [/tex]

Diff w.r.t " θ " we get .

[tex] \: \: [/tex]

[tex] \rm \large \frac{dy}{d \theta} = a \frac{d}{d \theta} (1 - cos \theta) [/tex]

[tex] \: \: \: [/tex]

[tex] \boxed{ \rm \large \underline{ \frac{dy}{d \theta} = a \sin \theta}}[/tex]

[tex] \: \: \: [/tex]

From eqn ( 1 ) & ( 2 )

[tex] \: \: [/tex]

[tex] \rm \large \frac{dy}{dx} = \frac{ \frac{dy}{d \theta} }{\frac{dx}{d \theta}} [/tex]

[tex] \: \: \: [/tex]

[tex] \: \: \: \rm \large = \frac{ \cancel{a} \: sin \theta}{ \cancel a \: (1 + cos \theta)} [/tex]

[tex] \: \: [/tex]

[tex] \rm \large \: = \frac{sin \theta}{1 + \cos \theta } [/tex]

[tex] \: \: \: [/tex]

[tex] \rm \large \: \frac{2 \sin( \frac{\theta }{2} ) cos\frac{\theta }{2} }{2 \: cos ^{2} \frac{\theta }{2}} \: \: ......(sin \: a \: = 2 \: sin \frac{a}{2} \: cos \frac{a}{2} 1 + \: cos \: a \: = 2cos ^{2} \frac{a}{2} )[/tex]

[tex] \: \: [/tex]

[tex] \rm \large \: \frac{dy}{dx} = \frac{sin \frac{ \theta}{2} }{cos \frac{ \theta}{2} } [/tex]

[tex] \: \: [/tex]

[tex] \rm \large \: \frac{dy}{dx} = tan \frac{ \theta}{2} [/tex]

[tex] \: \: [/tex]

[tex] \rm \large \: ( \frac{dy}{dx} ) = tan \frac{ \frac{ \theta}{2} }{2} [/tex]

[tex] \: \: [/tex]

[tex] \rm \large \: = tan( \frac{ \theta}{4} )[/tex]

[tex] \: \: [/tex]

[tex] \boxed{ \rm \large \underline{ ( \frac{dy}{dx} ) = \frac{\pi}{2} = 1}}[/tex]

[tex] \: \: [/tex]

Hope Helps!:)

Solve for b
SOLVE ASAP!!

Answers

Answer:

Step-by-step explanation:

<A and <B are alternate interior angles. That means they are in the interior of the parallel lines and they are on opposite sides of the transversal.

When that happens <A = <B

8x + 78 = 2x + 114                      Subtract 2x from both sides.

8x - 2x + 78 = 2x - 2x + 114       Combine

6x + 78 = 114                              Subtract 78 from both sides

6x + 78 - 78 = 114 - 78

6x = 36                                       Divide by 6

6x/6 = 36/6

x = 6

I think you are asked for B

<B = 2x + 114

<B = 2*6 + 114

<B = 12 + 114

<B = 126

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