The following diene does not undergo Diels Alder reaction because _____. Click on text below: A. it does not have an electron donating group B. it does not have an electron withdrawing group C. the bicyclic ring does not function as a diene D. it cannot adopt the s-cis conformation E. the double bonds are not in the same cyclic ring

Answers

Answer 1
28 because of how the penny flips and the Group A is blue so , The book would be 82 So dicvide 7 to 92 And u get 6

Related Questions

bromine pentachloride formula

Answers

Answer:

Bromine pentafluoride, BrF5

bromine pentafluoride is an interhalogen compound and a fluoride of bromine. It is a strong fluorination reagent. BrF5 finds use in oxygen isotope analysis.

The chemical formula of a compound is obtained from the symbols of the elements that compose the compound. The formula of bromine pentachloride is BrCl5.

In chemistry, compounds are represented using shorthand symbols called chemical formula.

The chemical formula is composed of the symbols of the respective elements that compose the compound as well as the number of atoms of each element that compose the compound.

For the compound bromine pentachloride, there is one bromine atom and five chlorine atoms giving the formula BrCl5.

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A stock solution was created by adding 0.1042 g of lead (II) nitrate to a 100.00 mL volumetric flask and diluting to volume with deionized water. A diluted solution was then created by removing 5.00 mL of the stock solution and placing into into a 50.00 mL volumetric flask and then diluting to volume with deionized water. What is the concentration (in molarity, M) of the diluted solution

Answers

Answer: The molarity of diluted solution is 0.00031 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

moles of [tex]Pb(NO_3)_2[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.1042g}{331.2g/mol}=0.00031mol[/tex]

Now put all the given values in the formula of molality, we get

[tex]Molarity=\frac{0.00031mol\times 1000}{100ml}=0.0031M[/tex]

According to the dilution law,

[tex](stock)M_1V_1=M_2V_2(dilute)[/tex]

Putting in the values we get:

[tex]0.0031\times 5.00=M_2\times 50.00[/tex]

[tex]M_2=0.00031M[/tex]

Therefore, the molarity of diluted solution is 0.00031 M

What force is required to accelerate a car at a rate of 4 m/s2 if the car has a mass of 37.5 kg?

Answers

Answer:150

Explanation:I think because f=MxA and the mass is 37.5 kg while acceleation is 4 m/s^2  and when you multiply that is gets 150 so F=150 N

If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?

Answers

Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles[/tex]  

[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]  

According to stoichiometry :

2 moles of [tex]K[/tex] produce = 2 moles of [tex]KOH[/tex]

Thus 0.57 moles of [tex]K[/tex] will produce=[tex]\frac{2}{2}\times 0.57=0.57moles[/tex]  of [tex]KOH[/tex]

Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g[/tex]

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

Ammonia is produced by the chemical reaction of hydrogen and nitrogen

N2 + 2H2 → 2NH3

How many moles of H2 are needed to react with 1.8 moles of N2

Answers

Answer:

3.6 mol H₂

Explanation:

N₂ + 2H₂ → 2NH₃

In order to convert from N₂ moles to H₂ moles we need to use a conversion factor. This conversion factor has to have N₂ moles in the denominator and H₂ moles in the numerator, using the stoichiometric coefficients of the reaction, as follows:

1.8 mol N₂ * [tex]\frac{2molH_2}{1molN_2}[/tex] = 3.6 mol H₂

Is anyone good at chemistry if so can someone help me please ?

(NO LINKS)

Answers

In general, salts (formed during a neutralization reaction) are ionic compounds that are soluble in water and dissociate in solution into ions that conduct electricity. Out of the six statements given, there are three related statements that rehash the foregoing, and there are three related statements that are collectively incorrect.

Statements A, B, and D are (generally) true regarding salts formed during a neutralization reaction. When you consider that the net ionic equation of many acid-base neutralization reactions is H⁺(aq) + OH⁻(aq) → H₂O(l), the counterions of the H⁺(aq) and OH⁻(aq) are the aqueous spectator ions that comprise the salt. These ions are electrolytes, as they are charged species that can carry a current in solution; they are ionic compounds by definition since they're composed of cations and anions; and, as aqueous species, they're clearly dissolved in water.

Statements C, E, and F, as a whole, generally aren't true of such salts.

If you were to describe America, what would you describe? In one word​

Answers

Answer:

Happy..

grateful

freedom

Explanation:

Answer:

huge

Explanation:

How many grams are in 2.4 moles of sulfur?

Answers

Answer:

76.96

Explanation:

A mole is Avagadro’s number of atoms of a substance. My periodic table of the elements gives the Gram Atomic Mass of natural sulphur is 32.066 grams/mole. Therefore, 2.4 moles would have a mass of 76.96 grams.

H3O+ is called the

A. Hydroxide ion.
B. Hydrogen ion.
C. Hydrate ion.
D. Hydronium ion

Answers

A.hydroxide ion

Explanation:

because it consists 3 hydrogen and 1 oxygen with + ion

Given the balanced equation:
2H2 + 02 --> 2H20

How many grams of H20 is produced if you have 7g of O2

Answers

Answer: 7.88375g

Explanation:

Here is the dimensional analysis table

7g O2 | 1 mol O2 | 2 mol H2O | 18.02 g H2O

| 32 g O2 | 1 mol O2 | 1 mol H2O

You use grams to convert to moles of O2, then use that to find grams of H20

help please really need help

Answers

Answer:

2.14 × 10⁻³ molecules/RSP

3.31 × 10⁻³ molecules/ESP

Explanation:

Step 1: Calculate the number of moles of Acetaminophen per Regular Strength Pill (RSP)

A Regular Strength Pill has 1.29 × 10²¹ molecules of Acetaminophen per pill. To convert molecules to moles we will use Avogadro's number: there are 6.02 × 10²³ molecules in  1 mole of molecules.

1.29 × 10²¹ molecules/RSP × 1 mol/6.02 × 10²³ molecules = 2.14 × 10⁻³ molecules/RSP

Step 2: Calculate the number of moles of Acetaminophen per Extra Strength Pill (ESP)

An Extra Strength Pill has 1.99 × 10²¹ molecules of Acetaminophen per pill. To convert molecules to moles we will use Avogadro's number: there are 6.02 × 10²³ molecules in  1 mole of molecules.

1.99 × 10²¹ molecules/ESP × 1 mol/6.02 × 10²³ molecules = 3.31 × 10⁻³ molecules/ESP

You want to produce a casting of sterling silver that is silver plus 13 atomic% copper. Pure silver is too soft for many applications and adding 13 atomic% copper strengthens the silver without significantly changing the color. To produce the sterling silver casting, you are going to melt commercially available pure silver and copper in a furnace, and then you will pour the liquid metal mixture into a mold. The following questions relate to this alloy. (a) In selecting a furnace, what must be the minimum value of the high-temperature capability of your selected furnace

Answers

Answer:

1085° C

Explanation:

From the phase diagram of Ag-Cu shown below:

The minimum value of the high-temp required to be selected for the furnace is: 1085° C

This is on the grounds that the furnace should be chosen to such an extent that it should melt any sort of possible material including pure Cu that melts and liquefies at the temperature of 1085° C.

if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be added to reach the equivalence point

Answers

Answer:

14.91 mL

Explanation:

Assuming the weak acid is monoprotic, we can solve this problem using the equation:

C₁V₁=C₂V₂

Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.

We input the data:

25.00 mL * 0.1084 M = 0.1817 M * V₂

And solve for V₂:

V₂ = 14.91 mL

The volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.

How we calculate the volume?

Volume for the given solution will be calculated from the below equation:

M₁V₁ = M₂V₂, where

M₁ = Molarity of weak acid = 0.1084 M

V₁ = volume of weak acid = 25 mL

M₂ = molarity of NaOH = 0.1817 M

V₂ = volume of NaOH = to find?

On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL

Hence required volume is 14.91 mL.

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KNO3 ______ ions in an aqueous solution. A. Forms B. Does not form ​

Answers

Answer:

A

Explanation:

b) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
constant pressure?
C2H5OH burning in a simple alcohol lamp is -1277.3kJ/mol​

Answers

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

All of the following are strong acids except

A. Nitric acid
B. Hydrochloric acid
C. Sulfuric acid
D. Acetic acid

Answers

Answer:

acetic acid

Explanation:

Acetic acid because it presents in solution primarily as whole.

The body system responsible for breaking down food and absorbing nutrients is the ____

a
circulatory system
b
respiratory system
c
excretory system
d
digestive system

Answers

Answer:

d

digestive system

Explanation

It’s the digestive system

2. A plant growing in response to the sunlight.
Gravitropism

Phototropism

Thigmotropism

Hydrotropism

Answers

Answer:

Phototropism.

Explanation:

Phototropism is the phenomenon of plants growing in response to light. This is a response to the plants to align or steer towards the source of sunlight, thereby becoming the 'path' to their growth.

The term "photo" means light and "tropism" means "growth" or movement towards". So, we can safely say that phototropism is the scientific and natural phenomenon of plants growing towards or in response to the sunlight.

Thus, the correct answer is phototropism.

ection
9)
A compound consists of 25.9% nitrogen and 74.1% oxygen by mass. What is the empirical
formula of the compound?
A)
NOZ
B)
NO
C)
N₂Os
D)
0
1
N20
2
3
4
5
6
7
8
9
0
21
2

Answers

Answer:

69

Explanation:

When an acid is added to a base, which if the following changes in pH might be observed?
A. An increase from 7 to 8
B. An increase from 3 to 8
C, A decrease from 7 to 6
D. A decrease from 9 to 5

Answers

Im just guessing, so i think is A

According to 2011/Chemistry Reference Tables
A. The electronegativity value of Cobalt is higher than the electronegativity value of Nickel
B. The electronegativity value of nitrogen is higher than the electronegativity value of fluorine
C. The electronegativity value of calcium is lower than the electronegativity value of silicon
D. The electronegativity value of boron is lower than the electronegativity value of beryllium​

Answers

Answer:

C

Explanation:

C. The electronegativity value of calcium is lower than the electronegativity value of silicon

is the only correct statement.

When 4.088 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.82 grams of CO2 and 2.829 grams of H2O were produced.

In a separate experiment, the molecular weight of the compound was found to be 78.11 amu. Determine the empirical formula and the molecular formula of the hydrocarbon.

Answers

Answer:

Empirical formula: CH

Molecular formula: C₆H₆

Explanation:

Based on the combustion of a hydrocarbon, the moles of CO₂ = Moles of Carbon in the hydrocarbon and the moles of H₂O = 1/2 moles of hydrogen in the hydrocarbon.

The empirical formula is the simplest whole number of atoms present in a molecule. With the moles of C and H we can find empirical formula:

Moles C -Molar mass CO₂ = 44.01g/mol-:

13.82g * (1mol / 44.01g) = 0.314 moles C

Moles H -Molar mass H₂O = 18.01g/mol-:

2.829g H₂O * (1mol / 18.01g) = 0.157 moles H₂O * (2mol H / 1mol H₂O) = 0.314 moles of H

The ratio of moles H: moles C:

0.314 moles / 0.314 moles = 1

That means empirical formula is:

CH

With the molecular weight and empirical formula we can find the molecular formula:

Molar mass CH = 12.01g/mol+1.01g/mol = 13.02g/mol

As the molecular weight of the molecule is 78.11amu = 78.11g/mol, there are:

78.11g/mol / 13.02g/mol = 6 times the empirical formula in the molecular formula

That means molecular formula is:

C₆H₆

What is the empirical formula for a compound that is 7.70 % carbon and 92.3 % chlorine?

Answers

Answer:

Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.

Explanation:

What is the main difference between rain and hail?

Answers

Answer:

Rain is a liquid and hail is a solid.

A ___________ ion is made of 2 or more atoms of different elements
O nuclear
O polyatomic
O magnetic
O mono-atomic

Answers

Answer: polyatomic

Explanation:hope you find helpful

A polyatomic is made of 2 or more atoms of different elements.

Our most recent mass extension happened about 65million years ago. Describe the effects of this event.

Answers

Answer:

To explain what caused this mass extinction, scientists have focused on events that would have altered our planet's climate in dramatic, powerful ways. The leading theory is that a huge asteroid or comet slammed into Earth 65 million years ago, blocking sunlight, changing the climate and setting off global wildfires.

Determine the concentration of a solution of sodium hydroxide (NaOH) using a 0.500M Potassium Hydrogen Phthalate (KHP) standard solution. Acid-base indicator phenolphthalein is added in its (colorless) acidic form to a precise volume sample of KHP. The base NaOH is slowly added to the same of KHP. Once all the KHP has reacted with the base, the first excess drop of NaOH will cause the indicator to convert to its basic (pink) form.

Answers

Answer:

0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL

Explanation:

The KHP reacts with NaOH as follows:

KHP + NaOH → KNaP + H₂O

Where 1 mole of KHP reacts per mole of KNaP

That means, the moles of KHP added to the NaOH solution = Moles NaOH at equivalence point. With the moles of NaOH and the volume in liters we can find the molar concentration of NaOH.

Assuming the volume added of KHP was 25.50mL and the solution of NaOH contains 30.0mL (0.0300L), the concentration of the NaOH is:

Moles KHP = Moles NaOH:

25.50mL = 0.02550L * (0.500mol / L) = 0.01275 moles KHP = Moles NaOH

Molarity NaOH:

0.01275 moles NaOH / 0.0300L =

0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL

How many grams of iron contain 4.06X10^24 atoms of iron?

Answers

4.06x20^24/6.02x10^23 = 6.744 moles x 55.845 g/mole = 376.61868grams

We have that the grams of iron contained 4.06X10^24 atoms of iron is

g= 376.6g

From the question we are told

How many grams of iron contain 4.06X10^24 atoms of iron?

Generally the equation for the Moles of Iron   is mathematically given as

[tex]M=\frac{4.06x10^24}{6.02x10^23} \\\\M=6.744moles[/tex]

Therefore

Where Molar mass of Iron =55.845

Generally the equation for the mass   is mathematically given as

g= 6.744  x 55.85

g= 376.6g

Therefore

the grams of iron contained 4.06X10^24 atoms of iron is

g= 376.6g

 

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Which of the following combinations would form a buffer solution?
a. HF and Lif
b. NH3 and NH4Br
c. HNO2 and NaNO2
d. all of the above
e. none of the above

Answers

Answer:

d . all of the above

Explanation:

A buffer system can be formed in one of two ways:

A weak acid and its conjugate baseA weak base and its conjugate acid

Which of the following combinations would form a buffer solution?

a. HF and LiF. YES. HF is a weak acid and F⁻ (from LiF) is its conjugate base.

b. NH₃ and NH₄Br. YES. NH₃ is a weak base and NH₄⁺ (from NH₄Br) is its conjugate acid.

c. HNO₂ and NaNO₂. YES. HNO₂ is a weak acid and NO₂⁻ (from NaNO₂) is its conjugate base.

Calculate the pH of a solution prepared by dissolving 1.60 g of sodium acetate, CH3COONa, in 50.0 mL of a 0.10 M acetic acid, CH3COOH (aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1.75 × 10^-5.​

Answers

Answer:

pH = 5.35

Explanation:

Given 1.60 grams sodium acetate (NaOAc(aq))*** added to 50ml of 0.10M acetic acid (HOAc(aq)) solution.

Applying common ion effect keeping in mind that the addition of NaOAc provides the common-ion (OAc⁻).

     HOAc(aq) ⇄          H⁺(aq)            +                 OAc⁻(aq)

I      0.10m          1.32 x 10⁻³M ≈ ∅M*     (1.6g/82.03g/mol) / 0.050L = 0.39M

C       -x                         +x                                0.39M + x ≈ 0.39M**

E    0.10M - x                  x                                    0.39M

      ≈ 0.10M

Ka = [H⁺][OAC⁻]/[HOAC] => [H⁺] = Ka·[HOAc] / [OAc⁻]

[H⁺] = (1.75 X 10⁻⁵)(0.10) / (0.39) = 4.5 x 10⁻⁶M

∴ pH = -log[H⁺] = -log(4.5 x 10⁻⁶) = -(-5.35) = 5.35

_______________________________________________

* [H⁺] before adding NaOAc = SqrRt(Ka · [HOAc]) = SqrRt(1.75 x 10⁻⁵· 0.10) = 1.32 x 10⁻³M. Since this concentration value is so small, the initial [H⁺] is assumed to be zero molar (∅M).

** The added [H⁺] is negligible and dropped in the ICE table. That is, adding ~[H⁺] in the order of 10⁻³M does not change the H⁺ ion concentration sufficiently to affect problem outcome and is therefore dropped in the ICE table.

*** Acetic Acid and Sodium Acetate are frequently written HOAc and NaOAc where the OAc⁻ anion is the acetate ion (CH₃COO⁻) for brevity.

We have that the  pH of the solution  derived to be

[tex]pH=5.0969[/tex]

From the Question we are told that

Mass of CH3COONa=1.60g

Volume of CH3COONa v=40ml

0.10 M acetic acid

Ka of CH3COOH is 1.75 × 10^-5.​

Generally the equation for the  pH  is mathematically given as

[tex]pH = pKa + log\frac{ base}{acid}[/tex]

Where

[tex]pka = -logKa\\\\pKa = -log(1.75*10^{-5})[/tex]

Generally

[tex]Moles\ of\ CH3COONa = \frac{Mass of CH3COONa}{Molar mass of CH3COONa}[/tex]

[tex]Moles of CH3COONa=\frac{1.15}{82.03}[/tex]

[tex]Moles of CH3COONa=0.0140moles[/tex]

And

[tex]base=\frac{ 0.0140moles}{(64.0/1000)}\\\\base=0.21875moles[/tex]

Therefore returning to the initial pH equation

[tex]pH = pKa + log\frac{ base}{acid}\\\\pH = -log(1.75*10^{-5}) + log\frac{ 0.21875}{0.10}[/tex]

[tex]pH=5.0969[/tex]

In conclusion

The  pH of the solution  derived to be

[tex]pH=5.0969[/tex]

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