The following is a set of hypotheses, some information from one or more samples, and a standard error from a randomization distribution. Test H0 : p=0.28 vs Ha : p<0.28 when the sample has n=800, and p^=0.217 with SE=0.01.

Required:
Find the value of the standardized z-test statistic.

Answers

Answer 1

Answer:

Z = -6.3

Step-by-step explanation:

Given that:

[tex]\mathbf{H_o :p= 0.28}[/tex]

[tex]\mathbf{H_o :p < 0.28}[/tex]

Since the alternative hypothesis is less than 0.28, then this is a left-tailed hypothesis.

Sample sixe n = 800

[tex]\hat p[/tex] = 0.217

The standard error [tex]S.E(p) = \sqrt{\dfrac{p(1-p)}{n}}[/tex]

[tex]S.E(p) = \sqrt{\dfrac{0.28(1-0.28)}{800}}[/tex]

[tex]S.E(p) \simeq0.015[/tex]

Since this is a single proportional test, the test statistics can be computed as:

[tex]Z = \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}}[/tex]

[tex]Z = \dfrac{0.217- 0.28}{0.01}[/tex]

Z = -6.3


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10 tshirts or 5 sweatshirts

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Answers

Answer:

[tex]\sqrt{13}[/tex]

Step-by-step explanation:

we can solve this using the distance formula: [tex]\sqrt{(x_{2}-x_1)^{2} + (y_{2}-y_1)^{2}}[/tex]

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[tex]x_2, y_2[/tex] is (-1, -2)

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Answers

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