The number of candies in the machine = 2700 candies
Number of customers required to empty the machine = 386
The amount of money in the machine = $96.43
Explanations:The price of candy in the machine = 15 pounds
Each pound of candy contains about 180 individual candies.
A child can buy 7 candies with a quarter
1 pound = 180 candies
15 pounds = 180 * 15 = 2700 candies
The number of candies in the machine = 2700 candies
2) 7 candies cost 1 quarter
2700 candies will cost 2700 / 7 quarters
2700 candies will cost 385.7 quarters
Since each child inserts a quarter, there will be 386 customers to empty the machine
1 quarter = $0.25
385.7 quarters = $96.43
The amount of money in the machine = $96.43
brainly got this wrrong i asked and posted it can you guys help please
Explanation:
[tex]\begin{gathered} h=\frac{3}{8}d \\ d=2r \\ h=\frac{3}{8}\times2r=\frac{3}{4}r \\ \frac{dh}{dt}=\frac{3}{4}\frac{dr}{dt} \\ r=\frac{4h}{3}=\frac{4\times5}{3}=\frac{20}{3}m=\frac{2000}{3}cm \\ \end{gathered}[/tex]The volume of a cone is given below as
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ V=\frac{1}{3}\pi r^2(\frac{3}{4}r) \\ V=\frac{1}{4}\pi r^3 \\ \frac{dV}{dr}=\frac{3}{4}\pi r^2 \end{gathered}[/tex]Given from the question,
[tex]\begin{gathered} \frac{dV}{dt}=15m^3\text{ /min} \\ \frac{dV}{dt}=15000000cm^3\text{ /min} \end{gathered}[/tex][tex]\begin{gathered} \frac{dV}{dt}=\frac{dV}{dr}\times\frac{dr}{dt} \\ 15000000=\frac{3}{4}\pi r^2\times\frac{dr}{dt} \\ \frac{15000000}{0.75\times\pi\times(\frac{2000}{3})^2}=\frac{dr}{dt} \\ \frac{dr}{dt}=\frac{15,000,000}{0.75\pi(\frac{2,000}{3})^{2}} \\ \frac{dr}{dt}=14.32cm\text{ /min} \end{gathered}[/tex]Hence,
The height is changing at a rate of
[tex]\begin{gathered} \frac{dh}{dt}=\frac{3}{4}\times14.32 \\ \frac{dh}{dt}=10.74cm\text{ /min} \end{gathered}[/tex]Hence,
The radius is changing at a rate of
[tex]14.32\text{ cm/min}[/tex]A bottle of ant killer holds 1 L of concentrate. To make up a solution, 5 capfuls are added to 1, 5 L of water. Each capful is 25 mL. How many litres of solutions can be made if you use the entire bottle of concentrate?
So first we have 1.5L of water and we add 5 25mL capfuls of ant killer. First we should work with the same unit so we transform liters into mililiters using the rule of three:
[tex]\begin{gathered} 1L\rightarrow1000mL \\ 1.5L\rightarrow x \end{gathered}[/tex]Where:
[tex]x=\frac{1.5L\cdot1000mL}{1L}=1500mL[/tex]So we know that we have 1500mL of water. The total amount of ant killer that was added to this water is:
[tex]5\cdot25mL=125mL[/tex]Then the solution has 1500mL of water and 125mL of ant killer which means that the total volume of solution is:
[tex]1500mL+125mL=1625mL[/tex]Knowing this, we need to find how many liters of solution we can make if we use the entire liter of ant killer. The information we have is that with 125 mL of ant killer you can make 1625 mL of solution. If we use the rule of three:
[tex]\begin{gathered} 125mL\text{ of ant killer}\rightarrow1625mL\text{ of solution} \\ 1000mL\text{ of ant killer}\rightarrow x\text{ of solution} \end{gathered}[/tex]Where x is the amount of mililiters that we are looking for and is given by:
[tex]x=\frac{1000mL\cdot1625mL}{125mL}=13000mL[/tex]So we can make 13000 mL of solution but we must express it in litres:
[tex]\begin{gathered} 1000mL\rightarrow1L \\ 13000mL\rightarrow x \end{gathered}[/tex]With:
[tex]x=\frac{13000mL\cdot1L}{1000L}=13L[/tex]Then the answer is that you can make 13 L of solution with the entire bottle of concentrate.
of the following sets, which numbers in {1, 2, 3, 4, 5) make the inequality 3x + 1 > 4 true?A. {1,2)B. {1, 2, 3)C. {1, 2, 3, 4, 5)D. {2,3,4,5)
Answer:
[tex]D;\text{ \textbraceleft2,3,4,5\textbraceright}[/tex]Explanation:
Here, we want to select the member of the set that makes the inequality true
We simply substitute the values in the set
When x is 1
3(1) + 1 = 4
This is not greater then 4 and as such, it cannot be a soution
However, as x is greater than 1, the values hold
Thus, we have the correct options as:
{2,3,4,5}
suppose U={1, 2, 3, 4, 5} is the universal set and A={1, 5}. What is A’?
U defines the whole sample space for a determined set of numbers (all possible outcomes), A represents an event defined in said space, is a subset that involves one or more possible outcomes of the sample space.
I need to know which answer this is. It’s a multiple choice and I don’t understand this question. Please help
GIVEN:
We are told that a motorcycle purchased for $20,200 depreciates at a constant rate of 15% per year.
Required;
Write the function that models the value of the motorcycle after t years.
What will the motorcycle be worth after 5 years?
Step-by-step solution;
For a value that depreciates at a given percentage, we use the exponential function. For an exponential decay (decrease in value), we use the following formula;
[tex]y=a(1-r)[/tex]This represents the value as at the first year after purchase. Therefore, for the value after any number of years given the exponential part of the equation is raised to the power of the year in review.
Therefore, for t number of years, we now have;
[tex]\begin{gathered} y=a(1-r)^t \\ \\ Where; \\ \\ y=amount\text{ }at\text{ }the\text{ }end\text{ }the\text{ }period \\ \\ a=initial\text{ }amount \\ \\ r=rate\text{ }of\text{ }decrease\text{ }(given\text{ }in\text{ }decimals) \\ \\ t=period\text{ }(in\text{ }years) \end{gathered}[/tex]For the value of the motorcycle after t number of years, we now have the following;
[tex]\begin{gathered} y=20200(1-0.15)^t \\ \\ y=20200(0.85)^t \end{gathered}[/tex]Therefore, for the value after 5 years we simply substitute t equals 5 in the equation.
[tex]\begin{gathered} y=20200(0.85)^5 \\ \\ y=8962.8473125 \end{gathered}[/tex]We can now approximate this value and we'll have;
[tex]y\approx8963[/tex]Therefore,
ANSWER;
The 4th option is the correct answer. The motorcycle will be worth $8,963 in the next 5 years.
Find the probability that the last two tosses come up tails
Part b
the probability is equal to
P=(1/2)*(1/2)
P=1/4
the answer is 1/4Solve each equation Show steps for credit 10.4+a=13
The given equation is,
[tex]4+a=13[/tex]Subtract 4 from both sides of the equation.
[tex]\begin{gathered} 4+a-4=13-4 \\ a=9 \end{gathered}[/tex]Therefore, the value of a is 9.
Sketch the graph of the function using a window that gives a complete graph.
Answer:
Explanation:
Given:
Based on the given function, when x is greater than or equal to 4, the value of y is 1. While, y= -1 if the value of x is less than 4.
The graph of the function is shown below:
Therefore, the answer is graph c.
If I move the points what are 5 things I would be able to observe about AVB, AVC and BVC
Point V is the focus for AV
The mean is: Find the mean and standard deviation for the number of sleepwalkers in group five.
As given by the question
There are given that the probability distribution and the value of x
Now,
First find the value of mean:
So,
The value of mean will be:
[tex]\operatorname{mean}=0\times0.193+1\times0.354+2\times0.304+3\times0.112+4\times0.034+5\times0.003[/tex]Then,
Solve the above expression:
[tex]\begin{gathered} \operatorname{mean}=0\times0.193+1\times0.354+2\times0.304+3\times0.112+4\times0.034+5\times0.003 \\ \operatorname{mean}=0+0.354+0.608+0.336+0.136+0.015 \\ \operatorname{mean}=1.449 \end{gathered}[/tex]Hence, the value of the mean is 1.449.
Now,
Find the standard deviation:
So, from the formula of standard deviation
[tex]\text{Standard deviation=}\sqrt[]{\sum^{\infty}_{n\mathop=0}(x-mean})^2\times P(x)[/tex]Then,
[tex]\begin{gathered} \text{Standard deviation=}\sqrt[]{\sum^{\infty}_{n\mathop{=}0}(x-mean})^2\times P(x) \\ =\sqrt[]{(0-1.449)^2\times0.193+(1-1.449)^2\times0.354+(2-1.449)^2\times0.304+(3-1.449)^2\times0.112+(4-1.449)^2\times0.034+(5-1.449)^2\times0.003} \end{gathered}[/tex]Then,
[tex]\begin{gathered} =\sqrt[]{(0-1.449)^2\times0.193+(1-1.449)^2\times0.354+(2-1.449)^2\times0.304+(3-1.449)^2\times0.112+(4-1.449)^2\times0.034+(5-1.449)^2\times0.003} \\ =0.405+2.123+0.092+0.27+0.221+0.0378 \\ =3.1488 \end{gathered}[/tex]Hence, the value of the standard deviation is 3.1488.
In circle C, MGK = 38°, mKL = 56°, and mLH = 86°.KFigure not drawn to scaleWhat is the measure of angle LJH?m. All rights reserved.H
Answer: c
Step-by-step explanation: im smart
I need help with my algebra
which of the following lograthmic equations is equivalent to the exponential equation below?[tex] {8}^{x} = 512[/tex]no explanation needed
By definition, the logarithm can be used equivalently in these expressions:
[tex]\begin{gathered} b^a=c^{} \\ \log _bc=a \end{gathered}[/tex]So, if we want an equivalent to:
[tex]8^x=512[/tex]We can write:
[tex]\log _8512=x[/tex]In a game using a spinner with four equal parts numbered 1 to 4, a contestant wins when the spinner lands on an odd number. Is this game fair?A.yesB.noC.not enough information
If the parts of the spinner are equal then the chance of the spinner landing on a certain number is the same for all the numbers. There are 2 odd numbers between 1 and 4 which are 1 and 3. Then the probability of the spinner landing on an odd number is:
[tex]\frac{2}{4}=\frac{1}{2}[/tex]And that's the probability of winning. On the other hand, the probability of losing is the probability of the spinner landing on an even number. There are two even numbers which means that the probability of losing is:
[tex]\frac{2}{4}=\frac{1}{2}[/tex]AnswerThe probability of losing is equal to the probability of winning. Therefore the game is fair and the answer is option A.
The Agency for Healthcare Research and Quality reported that 53% of people who had coronary bypass surgery in 2008 were over the age of 65. Suppose 15 coronary bypass surgery patients from the year 2008 are chosen. What is the probability that: (Express answers to 4 decimal places) a) exactly 8 of the patients were over the age of 65 when they had their surgery? b) fewer than 10 of the patients were over the age of 65 when they had their surgery? c) between 6 and 11 of the patients were over the age of 65 when they had their surgery? d) more than 12 of the patients were over the age of 65 when they had their surgery? e) would it be unusual that all 15 of the patients were over the age of 65 when they had their surgery?(Remember: "between" does not include the endpoints of an interval of discrete numbers.)
Given:
Percentage of people over 65 = 53%
Sample = 15
Let's solve for the following:
• (a). Exactly 8 of the patients were over the age of 65 when they had their surgery?
Here, we are to apply binomial probability.
We have:
[tex]\begin{gathered} P(x=8)=(^{15}_8)(0.53)^8(1-0.53)^{15-8} \\ \\ P(x=8)=(^{15}_8)(0.53)^8(0.47)^7 \\ \\ p(x=8)=0.2030 \end{gathered}[/tex]The probability is 0.2030
• (b). Fewer than 10 of the patients were over the age of 65 when they had their surgery?
Here, we are to find P(x < 10).
Using binomial probability, we have:
[tex]\begin{gathered} P(x<10)=P(x=0)+P(x=1)+P(x=2)+P(x=3)......P(x=9) \\ \\ P(x<10)=\sum_{x\mathop{=}0}^9(^{15}_x)(0.53)^x(1-0.53)^{15-x} \\ \\ Using\text{ the calculator, we have:} \\ P(x<10)=0.7875 \end{gathered}[/tex]The probability is 0.7875
• (c). Between 6 and 11 of the patients were over the age of 65 when they had their surgery?
Since between does not include the endpoints of the interval, we are to find:
P(6 < x < 11) = P(x = 7) + P(x = 8) + P(x = 9) + P(x = 10)
Hence, we have:
[tex]\begin{gathered} P(6The probability is 0.6814• (d). More than 12 of the patients were over the age of 65 when they had their surgery?
We are to find P(x > 12) = P(x = 13) + P(x = 14) + p(x = 15)
[tex]\begin{gathered} P(x>12)=\sum_{x\mathop{=}13}^{12}(_x^{15})(0.53)^x(1-0.53)^{15-x} \\ \\ P(x>12)=0.0071 \end{gathered}[/tex]• (e). Would it be unusual that all 15 of the patients were over the age of 65 when they had their surgery?
We are to find P(x = 15):
[tex]\begin{gathered} P(x=15)=(^{15}_{15})(0.53)^{15}(1-0.53)^{15} \\ \\ P(x=15)=(_{15}^{15})(0.53)^{15}(0.47)^{15} \\ \\ P(x=15)=0.0001 \end{gathered}[/tex]ANSWER:
• (a). 0.2030
,• (b). 0.7875
,• (c). 0.6814
,• (d). 0.0071
,• (e). 0.0001
Lesson 4 Extra Practice Mean Absolute Deviation Determine the mean absolute deviation for e the nearest hundredth if necessary. Then des absolute deviation represents. 1. Number of Sibmas 2 5 8 9 7 6 3 5 1 &
Data set: 2 5 8 9 7 6 3 5 1
Number of data values: 9
Average: (2 + 5 + 8 + 9 + 7 + 6 + 3 + 5 + 1)/9 = 5.11
|2 - 5.11| = 3.11
|5 - 5.11| = 0.11
|8 - 5.11| = 2.89
|9 - 5.11| = 3.89
|7 - 5.11| = 1.89
|6 - 5.11| = 0.89
|3 - 5.11| = 2.11
|5 - 5.11| = 0.11
|1 - 5.11| = 4.11
Mean Absolute Deviation =
(3.11 + 0.11 + 2.89 + 3.89 + 1.89 + 0.89 + 2.11 + 0.11 + 4.11)/9 = 2.12
In the figure below, k || 1 and m || n. Find the values of x and z.
As shown in the figure m // n
the angles x and 63 are exterior supplementary angles
So, x + 63 = 180
so, x = 180 - 63 = 117
and the angles 63 and ( 4z - 29 ) are congruent
so,
[tex]\begin{gathered} 4z-29=63 \\ 4z=63+29 \\ 4z=92 \\ \\ z=\frac{92}{4}=23 \end{gathered}[/tex]So, the answer is :
[tex]\begin{gathered} x=117 \\ \\ z=23 \end{gathered}[/tex]the graphing troubles me
The vertices are given as D(-8,4), E(-2,2), and F(-5,9).
Consider that area of the traingle is given by,
[tex]\text{Area}=\frac{1}{2}\lbrack x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\rbrack[/tex]Then the area of triangle DEF is given by,
[tex]\text{Area}=\frac{1}{2}\lbrack-8(2-9)-2(9-4)-5_{}(4-2)\rbrack=\frac{1}{2}\lbrack-8(-7)-2(5)-5(2)\rbrack[/tex]Simplify the terms further as,
[tex]\text{Area}=\frac{1}{2}\lbrack56-10-10\rbrack=\frac{1}{2}(36)=18[/tex]Thus, the area of the triangle is 18 square units.
In ∆HIJ, i=99 inches and < H=9°. Find the length of h, to the nearest inch.
ANSWER
h = 16 in
EXPLANATION
We can solve this using the law of sines:
In this case, the relation is:
[tex]\frac{i}{\sin I}=\frac{j}{\sin J}=\frac{h}{\sin H}[/tex]WIth the first two ratios we have:
[tex]\frac{99}{\sin I}=\frac{99}{\sin J}[/tex]We can find that angles I and J are equal:
[tex]\begin{gathered} \frac{\sin J}{\sin I}=\frac{99}{99} \\ \frac{\sin J}{\sin I}=1 \\ \sin J=\sin I \\ J=I \end{gathered}[/tex]Therefore, they measures - because the interior angles of a triangle add up 180º- are:
[tex]\begin{gathered} m\angle H+m\angle J+m\angle I=180º \\ 9º+2m\angle J=180º \\ m\angle J=\frac{180º-9º}{2} \\ m\angle J=m\angle I=85.5º \end{gathered}[/tex]Now, using the law of sines, we can find h:
[tex]\begin{gathered} \frac{i}{\sin I}=\frac{h}{\sin H} \\ \frac{99}{\sin85.5º}=\frac{h}{\sin 9º} \\ h=99\cdot\frac{\sin 9º}{\sin 85.5º} \\ h=15.535in \end{gathered}[/tex]Rounded to the nearest inch, h = 16 in
You have a bag of gummy worms. 12 are green, 3 are blue, 6 are red and 2 are orange. What is the probability that you will reach into the bag and pull a red worm, eat it, and then pull a green worm?answer choices:18/23 36/253 1/529. 72/529
To answer this question, we can proceed as follows:
1. Count the total of gummy worms into the bag:
12 green + 3 blue + 6 red + 2 orange = 23 gummy worms.
2. In the first event (pull a red worm), we have that the probability of it is:
[tex]P(R)=\frac{6}{23}[/tex]Since we have 6 red gummy worms from a total of 23.
3. Now, the probability of the second event is a little different. You have eaten one of the red gummy worms. Then, we have a total of 23 - 1 = 22 gummy worms.
The probability, now, of getting a green worm is (there are 12 green gummy worms):
[tex]P(G)=\frac{12}{22}\Rightarrow P(G)=\frac{6}{11}[/tex]4. Finally, the probability of these two events is, applying the multiplication rule:
[tex]P(R\cap G)=\frac{6}{23}\cdot\frac{6}{11}\Rightarrow P(R\cap G)=\frac{36}{253}[/tex]Then, the answer is 36/253 (second option.)
This is a case of conditional probability. We see that the probability of the second event was influenced by the first event.
Find the distance between the points. (6,-3) and (0,5) 40) draw the triangle
The formula to find the distance between two points (a,b) and (c,d) is:
[tex]\sqrt[]{(a-c)^2+(b-d)^2}[/tex]Substitute (a,b)=(6,-3) and (c,d)=(0,5):
[tex]\begin{gathered} \sqrt[]{(6-0)^2+(-3-5)^2} \\ =\sqrt[]{(6)^2+(-8)^2} \\ =\sqrt[]{36+64} \\ =\sqrt[]{100} \\ =10 \end{gathered}[/tex]Therefore, the distance between (6,-3) and (0,5) is 10.
Plot the points on the coordinate plane to draw the triangle:
Solve the system of equations algebraically.5x + y = 93x + 2y = 4
The solution is (2, -1)
Explanation:5x + y = 9 ....(1)
3x + 2y = 4 ....(2)
Using susbtitution method:
from equation 1, we will make y the subject of formula
y = 9 - 5x
substitute for y in equation 2:
3x + 2(9 - 5x) = 4
3x + 2(9) -2(5x) = 4
3x + 18 - 10x = 4
-7x + 18 = 4
-7x = 4 - 18
-7x = -14
Divide both sides by -7:
-7x/-7 = -14/-7
x = 2
substitute for x in equation (1):
5(2) + y = 9
10 + y = 9
y = 9 - 10
y = -1
The solution (x, y) is (2, -1)
anthony had a 0.250 batting average at the end of his. last base ball season wich means that he got a hit 25 percent of the times he was up to bat if anthony had 47 hits his last season how many times did he bat
average = 0.250
Total* 25% = 47
Total *0.25 = 47
Total = 47/ 0.25
Total = 188
_________________
Answer
He batted 188 times.
What do you think? How could I find a point that is 1/4 of the way between A and B instead of 1/2 way?
5. Identify the transformation graphed below. (Remember to include the required information): 6. Answer A 5 2 1 -6 -5 -4 -3 -2 -1 X (-1,-2) -5
From the graph, we have:
Write in number form:nine million one hundred eight thousand one hundred seventy-six
In order to write this expression in number form, let's first separate it and write each corresponding value in number form:
"nine million" = 9,000,000
"one hundred eight thousand" = 108,000
"one hundred seventy-six" = 176
So, adding each piece, we have:
"nine million one hundred eight thousand one hundred seventy-six"
=
9,108,176.
From 2010 to 2012, the average selling price of tablets decreased by 20%. This percent reduction amounted in a decrease of $122. Find the average selling price of tablets in 2010 and in 2012.
Let the original price of tablets be represented by x.
The average selling price decreased by 20% (or 0.2).
The decrease now was calculated as $122. That means the figure 122 is 20% of x. Therefore, what we have is;
[tex]\begin{gathered} \text{Original price=x} \\ \text{Decrease}=122 \\ \text{New price=x-122} \\ \text{Note that 20\% (0.2) is also 122, hence} \\ \frac{20}{100}=\frac{122}{x} \\ \text{Cross multiply and we'll have} \\ x=\frac{122\times100}{20} \\ x=610 \\ \text{The original price in 2010 is \$610} \\ \text{If the price reduced by \$122 in 2012, then } \\ \text{The price in 2012 would be }610-122=488 \\ \end{gathered}[/tex]The price in 2010 would be $610
The price in 2012 would be $488
You spin the spinner twice.6789What is the probability of landing on a 6 and then landing on a prime number?Simplify your answer and write it as a fraction or whole number.
Given,
The number of section in the spinner is 4.
Required
The probability of landing on a 6 and then landing on a prime number.
The probability of spinner lands on 6 is,
[tex]\begin{gathered} P(6)=\frac{n(6)}{total\text{ section}} \\ =\frac{1}{4} \end{gathered}[/tex]The probability of spinner lands on prime is,
[tex]\begin{gathered} P(prime)=\frac{n(prime)}{total\text{ section}} \\ =\frac{1}{4} \end{gathered}[/tex]The probability of landing on a 6 and then landing on a prime number.
[tex][/tex]Tell whether each equation represents a direct variation. If so, identify the constant of variation.
The variation of the equation is ; y/x
if y/x = k , where k is constant then the variation is Constant
1) 3y = 4x+1
[tex]\begin{gathered} \text{Simplify it in }\frac{y}{x} \\ \text{Divide equation by x} \\ \frac{3y}{x}=\frac{4x}{x}+\frac{1}{x} \\ \frac{y}{x}=\frac{4}{3}+\frac{1}{3x} \\ \frac{y}{x}\ne\text{ any constant term} \end{gathered}[/tex]So, it does not represent direct variation.
2) 3x = -4y
[tex]\begin{gathered} \text{Simplify it in }\frac{y}{x} \\ 3x=-4y \\ \text{Divide by 3y} \\ \frac{3x}{3y}=\frac{-4y}{3y} \\ \frac{x}{y}=-\frac{4}{3} \\ \frac{y}{x}=-\frac{3}{4} \\ \frac{y}{x}=Cons\tan t\text{ term} \end{gathered}[/tex]It represent direct variation.
3) y + 3x =0
[tex]\begin{gathered} \text{Simplify it in }\frac{y}{x} \\ \text{Divide by x} \\ \frac{y}{x}+\frac{3x}{x}=0 \\ \frac{y}{x}=-3 \\ \frac{y}{x}=\text{ Constant term} \end{gathered}[/tex]It represnt the direct variation.
Answer: 2) 3x = -4y
3) y + 3x = 0
Can somebody help me fix my 4 and 5 problem of this exercise?
Hello
To solve this question, we were given a particular function and asked to evalute when the function is defined with a particular variable
[tex]\begin{gathered} f(x)=3-4x \\ g(x)=3x+4x^2 \end{gathered}[/tex]For f(-6)
[tex]\begin{gathered} f(x)=3-4x^{} \\ f(-6)=3-4(-6) \\ f(-6)=3-4(-6) \\ f(-6)=27 \end{gathered}[/tex]For g(-9)
[tex]\begin{gathered} g(x)=3x-4x^2 \\ g(-9)=3(-9)+4(-9)^2 \\ g(-9)=297 \end{gathered}[/tex]For f(-9) + g(-9)
[tex]\begin{gathered} f(x)=3-4x \\ g(x)=3x+4x^2 \\ f(-9)+g(-9)=3-4(-9)+3(-9)+4(-9)^2=336 \end{gathered}[/tex]for g(-6) - f(-9)
[tex]\begin{gathered} g(x)=3x+4x^2 \\ f(x)=3-4x \\ g(-6)-f(-9)=3(-6)+4(-6)^2-(3-4(-9))=87 \end{gathered}[/tex]For f(-9).g(-7)
[tex]\begin{gathered} g(x)=3x+4x^2 \\ f(x)=3-4x \\ f(-9).\text{g}(-7)=3-4(-9)\times3(-7)+4(-7)^2=39\times175=6825 \end{gathered}[/tex]For f(-6) / g(-7)
[tex]\begin{gathered} f(x)=3-4x \\ g(x)=3x+4x^2 \\ \frac{f(-6)}{g(-7)}=\frac{3-4(-6)}{3(-7)+4(-7)^2}=\frac{27}{175} \end{gathered}[/tex]From the calculations above, i believe you must've seen your mistaken and taken the necessary correction.
Therefore the answers are
1 = 27
2 = 297
3 = 336
4 = 87
5 = 6825
6 = 27/175