The function c (x) = .5x + 70 represent the cost c(in dollars) of renting a truck from a moving company where x is the number of miles you drive the truck

Answers

Answer 1

For the given function c(x) = 0.5x +70 where c is the cost of renting a truck  and x is the number of miles drive by truck , then domain and range of the function in inequalities are domain is x ≥ 0 and range is

y ≥70.

Graph is attached.

As given in the question,

Given function :

c(x) = 0.5x +70

where c is the cost of renting a truck  and x is the number of miles drive by truck.

Graph of the function is attached.

c(x) represented on y-axis.

Values for the graph of the function  c(x) = 0.5x +70 is,

x= 0

⇒ c(0) = 0.5(0) +70

⇒c(0) = 70

x =1

⇒ c(1) = 0.5(1) +70

⇒c(1) = 70.5

x=2

⇒ c(2) = 0.5(2) +70

⇒c(2) = 71

.... and so on.

Domain is x = 0,1,2,3,...

Range is c(x) = 70 , 70.5, 71, ....

In inequalities form:

Domain x ≥ 0

Range c(x) ≥ 70

Therefore, for the given function c(x) = 0.5x +70 where c is the cost of renting a truck  and x is the number of miles drive by truck , then domain and range of the function in inequalities are domain is x ≥ 0 and range is y ≥70.

Graph is attached.

The complete question is :

The function c(x) = 0.5x+70 represents the cost c (in dollars) of renting a truck from a moving company, where x is the number of miles you drive the truck.

a. Graph the function and identify its domain and range. Write your answers as inequalities.

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The Function C (x) = .5x + 70 Represent The Cost C(in Dollars) Of Renting A Truck From A Moving Company

Related Questions

The area of the triangle below is 10.98 square feet. What is the length of the base? 3.6 ft)

Answers

Remember that

the area of a triangle is equal to

[tex]A=\frac{1}{2}\cdot b\cdot h[/tex]

we have

A=10.98 ft2

h=3.6 ft

substitute the given values

[tex]\begin{gathered} 10.98=\frac{1}{2}\cdot b\cdot3.6 \\ \\ b=\frac{10.98\cdot2}{3.6} \\ \\ b=6.1\text{ ft} \end{gathered}[/tex]

answer is 6.1 ft

IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual is randomly chosen. Let X= IQ of an individual.(a) Find the z-score for an IQ of 124, rounded to three decimal places. (b) Find the probability that the person has an IQ greater than 124.

Answers

In this problem we have a normal distribution with:

• μ = mean = 100,

,

• σ = standard deviation = 15.

(a) The z-score for a value x = 124 is:

[tex]z=\frac{x-\mu}{\sigma}=\frac{124-100}{15}=\frac{24}{15}=1.6.[/tex]

(b) We must compute the probability that x is greater than 124, which is equivalent to the probability of having z greater than 1.6. Using a table of z-score, we find that:

[tex]P(x>124)=P(z>1.6)=0.0548.[/tex]

Answer

• (a), z = 1.6

,

• (b), P(x > 124) = 0.0548

Use the bar graph to determine the percent of increase in sales from the first to the second quarter

Answers

From the bar graph, we have:

Sales in first quarter (Jan - Mar) = $155,000

Sales in second quarter(Apr to JUn) = $232,500

Sales in third quarter (Jul to Sep) = $135,000

Sales in fourth quarter (Oct to Dec) = $160,000

Let's find the percent increase in sales from the first to second quarter.

To find the percent increase from first to second quarter, apply the formula:

[tex]\text{Perecent increase = }\frac{Sales\text{ in Q2 - Sales in Q1}}{Sales\text{ in Q1}}\times100[/tex]

Thus, we have:

[tex]\begin{gathered} \text{Percent increase=}\frac{232500-155000}{155000}\times100 \\ \\ \text{Percent increase = }\frac{77500}{155000}\times100 \\ \\ \text{Percent increase = 0.5 x 100 = 50\%} \end{gathered}[/tex]

Therefore, the percent increase from first to second quarter is 50 percent.

ANSWER:

50%

15) Describe what is wrong with this solution (there could be numerous mistakes):I-4x + 1I > 3- 4x + 1 > 3- 4x > 4x < - 1-4x + 1 > - 3- 4x > 2x < 1/2

Answers

For the first solution, the error is adding 1 to 3 to get 4 instead of subtracting 1 from 3 to get 2.

It should have been

I-4x + 1I > 3

- 4x + 1 > 3

- 4x > 3 - 1

- 4x > 2

x < - 2/4

x < - 1/2

For the second solution, the error was omitting the negative sign in the final answer. It should have been

-4x + 1 > - 3

- 4x > 2

x < -1/2





A rectangular room is 1.6 times as long as it is wide, and its perimeter is 30 meters. Find the
dimension of the room.

Answers

Let

L ----> the length

W ----> the width

The perimeter is equal to

P=2(L+W)

we have that

P=30 m ----> given

L=1.6W ---> given

substitute in the formula of perimeter

30=2(1.6W+W)

solve for W

15=2.6W

W=5.77 m

L=1.6*5.77

L=9.23 m

therefore

the dimensions are

length is 9.23 meterswidth is 5.77 meters

Line m passes through the points (-4-11) and (3.3). Line n passes through the points (5,-2) and (-6,9). Which of the following explains whether lines m and m

Answers

The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

The slope of the line that passes through (-4, -11) and (3, 3) is:

[tex]m_1=\frac{3-(-11)}{3-(-4)}=\frac{14}{7}=2[/tex]

The slope of the line that passes through (5, -2) and (6, -9) is

[tex]m_2=\frac{-9-(-2)}{6-5}=-7[/tex]

Yes, lines m and n intersect because their slopes are different

A box contains 1 plain pencil and 3 pens. A second box contains 2 color pencils and 6 crayons. One Item from each box is chosen at random. What is theprobability that a pen from the first box and a crayon from the second box are selected?write your answer as a fraction in simplest form.

Answers

3/4

Explanation:

First box:

number of pencils = 1

number of pens = 3

Probability of picking pen in the first box = number of pens /total number in the box

Total = 1 + 3 = 4

probability of picking pen in the 1st box = 3/4

2nd box:

number of color pencils = 2

number of crayons = 6

Total = 2 + 6 = 8

Probability of picking crayons in the 2nd box = number of crayons/total number in the box

Probability of picking crayons in the 2nd box = 6/8 = 3/4

Probability of picking a pen from the first box and a crayon from the second box = probability of picking pen in the 1st box × Probability of picking crayons in the 2nd box

Probability of picking a pen from the first box and a crayon from the second box = 3/4 × 3/4

Probability of picking a pen from the first box and a crayon from the second box = 9/16

Find the missing number so that the equation has no solutions. 2(4x - 12) = 2(-3x - 10) + X + 10

Answers

We find the missing number as follows:

[tex]2(4x-12)=2(-3x-10)+\mleft\lbrace \mright\rbrace x+10\Rightarrow8x-24=-6x-20+\mleft\lbrace \mright\rbrace x+10[/tex][tex]\Rightarrow8x+6x-\mleft\lbrace \mright\rbrace x=-20+10+24\Rightarrow14x-\mleft\lbrace \mright\rbrace x=14[/tex][tex]\Rightarrow x(14-\mleft\lbrace \mright\rbrace)=14[/tex][tex]14-\mleft\lbrace \mright\rbrace=0\Rightarrow\mleft\lbrace \mright\rbrace=14[/tex]

If we have that "blank" has a value of 14, then the equation would not make sense and therefore has no solutions.

Find the number of permutations of letters in the wordEFFECTIVE

Answers

To determine the distinguishable permutations of the given word, here are the steps.

1. Count the number of letters in the given word. In the word EFFECTIVE, there are 9 letters.

2. Calculate 9!.

[tex]9!=9\times8\times7\times6\times5\times4\times3\times2\times1=362,880[/tex]

3. Determine what are the letters found in the word effective and count how many times the letter occurred.

Letter E - 3 times

Letter F - 2 times

Letter C - 1 time

Letter T - 1 time

Letter I - 1 time

Letter V - 1 time

4. Get the product of the factorial of the letters that occurred more than once.

[tex]3!\times2!=(3\times2\times1)\times(2\times1)=12[/tex]

5. Divide the result of step 2 by the result of step 4.

[tex]362,880\div12=30,240[/tex]

Therefore, there are 30,240 different permutations of the word EFFECTIVE.

which of the following is an equivalent expression for 9 ^ 7 * 9 ^ 6?

Answers

[tex]9^7\times9^6[/tex]

with the same base if we multiplicate this expression we sum the exponents

the result will be

[tex]9^7\times9^6=9^{7+6}=9^{13}[/tex]

the result is 9^13 the last option

mZTRI 3x - 5, MZIRB = x + 27, and mTRB Does RI bisect TRB?

Answers

1) Let's draw that to better understand this

The Bisector Theorem states that the angle bisected is equally divided

since the angle TRB = 86º . Besides that the m TR

To determine whether it does bisect let's set an equation in which x +27 = the half of 86º

x+27 =43

x=16

3x -5 =43

3x =48

x=16

So, RI bisects the angle TRB, for each angle is half of the measure of TRB.

A round plastic wading pool has diameter 5 FEET. It is filled with water to a depth of 6 INCHES. What is the volume of water in the pool? Round to one decimal place and include unit.

Answers

To find the volume of water in the pool, we would find the area of the pool's surface and multiply it by the depth of the pool. The area of the pool's surface would be determined by the formula,

Area = pi x radius^2

From the information given,

diameter = 5

recall,

radius = diameter/2

Thus,

radius = 5/2 = 2.5

depth = 6 inches

We would convert from inches to feet

Recall,

12 inches = 1 foot

6 inches = 6/12 = 0.5 foot

Thus, depth = 0.5

pi = 3.14

Thus,

Area = 3.14 x 2.5^2 = 19.625

Volume = 19.625 x 0.5 = 9.8125

Volume of water in pool is 9.8 cubic feet to 1 decimal place

Cool Down: Lift OffShortly after takeoff, an airplane is climbing 250 feet for every 1,000 feet it travels.Estimate the airplane's climb angle while this is happening.Tons of Trianglesadjacentoppositeleghypotenuse leghypotenuseangleoppositeleg + adjacent leg10degrees0.9850.1740.176С20degrees09400.342246425030degrees0.8660.5000577B40degrees0.7660.6430.8391000A50degrees0.6430.7661.19260degrees0.5000.8661.73270degrees0.3420.9402.74780degrees0.1740.9855.571

Answers

[tex]\begin{gathered} \tan \theta=\frac{opposite}{adjacent} \\ \\ \tan \theta=\frac{250}{1000} \\ \\ \theta=\tan ^{-1}(\frac{250}{1000}) \\ \\ \theta=14 \\ \text{The climbing angle is 14\degree} \end{gathered}[/tex]

Eliza reads 1··7of her book on Monday. On Tuesday and Wednesday combined, she reads three times as much as she reads on Monday. The expression 1··7r 1 3 1 1··7r 2 can be used to determine the number of pages Eliza reads on Monday, Tuesday, and Wednesday combined. The variable r represents the total number of pages in the book. Part A Eliza’s book has a total of 357 pages. How many pages does Eliza read on Monday, Tuesday, and Wednesday combined? A 306 B 204 C 153 D 51

Answers

The expression :

[tex]\frac{1}{7}r+3(\frac{1}{7}r)[/tex]

gives the number of pages Eliza read in those three days. If r=357, then we have that:

[tex]\frac{1}{7}(357)+3(\frac{1}{7}\cdot357)=51+153=204[/tex]

She read 204 pages on those days. Therefore, the answer is B.

The graph of relation H is shown belowThe domain F range of H. Right here it answers using set notation.

Answers

Answer:

• Domain: {-2, 1, 4}

,

• Range: (-4, 0}

Explanation:

The points on the graph of relation H are:

[tex]\lbrace(-2,-4),(1,0),(4,-4)\}[/tex]

Domain of H

The domain of H is the set of all te xvalues of the relation.

[tex]\lbrace-2,1,4\rbrace[/tex]

Range of H

The range of H is the set of all the y-values of the relation.

[tex]\lbrace-4,0\rbrace[/tex]

by h a19.2 cmX 9.212413.5 cm2. Find the base of a parallelogram with height 0.4 yards and an areaof 8.2 square yards.

Answers

Recall that the formula for determining the area of a parallelogram is

[tex]\begin{gathered} A_{\text{parallelogram}}=bh \\ \text{where} \\ b\text{ is the base} \\ h\text{ is the height} \end{gathered}[/tex]

Given that the height is 0.4 yards, and the area is 8.2 square yards. Substitute the following values and we get

[tex]\begin{gathered} A=b\times h \\ 8.2\text{ yards}^2=b\times0.4\text{ yards} \\ \\ \text{Divide both sides by 0.4 yards} \\ \frac{8.2\text{ yards}^2}{0.4\text{ yards}}=\frac{b\times0.4\text{ yards}}{0.4\text{ yards}} \\ b=20.5\text{ yards} \end{gathered}[/tex]

Therefore, the base of the parallelogram is equal to 20.5 yards.

Which of the following would be a solution to the system of inequalities below? < > 2 y 5 2x + y > 6 O (3,5) 0 (3,0) O (3, 2) O ( 3-1) I give you a picture for this one

Answers

Solution

Given the following:

[tex]\begin{cases}x>2 \\ y<5 \\ 2x+y>6\end{cases}[/tex]

when x is greater than 2

[tex]x=3,4,5,\ldots\ldots[/tex]

when y is less than 5

[tex]y=0,1,2,3,4,\ldots\ldots[/tex]

Therefore the best option is when x = 3 and y = 2

[tex]\begin{gathered} x=3,y=2 \\ 2x+y>6 \\ 2(3)+2=8 \\ 8>6 \end{gathered}[/tex]

it is correct because 8 is greater than 6

Therefore the best option is (3, 2)

Hence the correct answer is Option C

Answer this: please I don’t need u to tutor just anwer

Answers

For the given question, we will write the rules of the sign when multiplying or dividing the integers:

[tex]\begin{gathered} (+)\times(+)=+ \\ (+)\times(-)=- \\ (-)\times(-)=+ \end{gathered}[/tex]

The same rules are correct when replacing the product sign with the divided sign

3. 3x + 4y = 8 x=16-4y

Answers

Solving a system of equations

We want to find where x and y are equal in both equations.

First step: replacing the x value given by the second equation in the first

3x + 4y = 8

x = 16 - 4y​

3(16 - 4y​) + 4y = 8

Distributing the parenthesis:

3 · 16 - 3 · 4y + 4y = 8

48 - 12y + 4y = 8

48 - 8y = 8

Rearranging the equation:

48 - 8y = 8

48 - 8 = 8y

40 = 8y

40/8 = y

5 = y

Second step: replacing the 5 = y value in one of the equations

We replace it in the second equation:

x = 16 - 4y​

x = 16 - 4 · 5

x = 16 - 20

x = -4

Solution: y = 5 amd x = -4

Consider the statement below.If AB = CD + EF and CD + EF = GH, then AB = GH.Which property can be used to justify the conclusion? O A.Subtraction property of equalityO B. Symmetric property of equality Ос.Addition property of equalityO D.Transitive property of equ

Answers

To answer this question, we have the next statement:

[tex]AB=CD+EF[/tex]

And

[tex]CD+EF=GH[/tex]

Then

[tex]AB=GH[/tex]

This property can also be represented as follows, and has the following structure:

If a = b and b = c, then a = c

Using an analogy, we can say that:

• a = AB

,

• b = CD + EF

,

• c = GH

And we end up with the same statement written above:

• AB = CD + EF and CD + EF = GH, then AB = GH

This property is called the Transitive Property of Equality.

In summary, the answer to this question is option D: Transitive Property of Equality.

[The other options do not correspond to this answer.]

What is the value of the expression below? 3 1 over 4 - 1 7 over 8

Answers

The value of the expression is;

[tex]1\frac{3}{8}[/tex]

Here, we want to make a fraction subtraction

To do this, we will have to convert the mixed fraction to improper fraction and then proceed to subtract

To make the fraction improper, we multiply the denominator by the stand-alone number and add the numerator;

so we have;

[tex]\begin{gathered} 3\frac{1}{4}\text{ = }\frac{13}{4} \\ 1\frac{7}{8}\text{ = }\frac{15}{8} \\ \\ \frac{13}{4}-\frac{15}{8}\text{ = }\frac{2(13)-15}{8}\text{ = }\frac{26-15}{8}\text{ = }\frac{11}{8}\text{ = 1}\frac{3}{8} \end{gathered}[/tex]

When the system of equations y + 2 = (1-4) and 2x + y - 6 = 0 is solved algebraically, the solution A 1-4,-2) and (-1,2) B. 14.-2) and (2.21 C. 1-1.25 and 1-6:6) 1:21 and 16.5

Answers

B ) S ={(2, 2), (4,-2)}

1) Setting the system:

y + 2 = (x-4)²

And adding the 2nd Equation to the System:

y+2 = (x-4)²

2x -y - 6 =0

2) Now let's solve it by using the Addition Method:

y+2 = (x-4)²

2x -y - 6 =0 x (-1)

y+2 = (x-4)²

-2x +y + 6 =0

-------------------------

-2x +8 = (x-4)²

-2x +8 = x² -8x +16

-x²+8x -16-2x +8 =0

-x² +6x -8 =0

x² -6x +8 = 0

Factoring it we have:

(x-2)(x-4) = 0 So the solution set i

x- 2 =0

x = 2

x-4= 0

x=4

3) Plug into the first equation x = 4:

y +2 = (x-4)²

y+2 =(4-4)²

y = -2

Finally, plugging x = 2 into the same equation:

y +2 = (x-4)²

y +2 = (2 -4)²

y+2 = (-2)²

y +2 = 4

y = 4-2

y= 2

So the answer is S ={(2, 2), (4,-2)} s

0

Using Radians find the amplitude and period of each function. Then Graph. Question 8. Please make sure to make the graph correctly

Answers

SOLUTION

Given the information and graph on the question tab;

[tex]\begin{gathered} \text{y=3cos\lparen}\frac{\theta}{3}\text{\rparen----equation1} \\ \\ \end{gathered}[/tex]

Given that the general cosin function is expressed as

[tex]\begin{gathered} y=Acos(Bx+C)----\text{ equation2} \\ where \\ A=amplitude \\ period=\frac{2\pi}{B} \end{gathered}[/tex]

By comparing equations 1 and 2, we have

[tex]\begin{gathered} A=3 \\ B=\frac{1}{3} \end{gathered}[/tex]

Thus, we have

[tex]\begin{gathered} Amplitude\text{ =3} \\ Period=\frac{2\pi}{\frac{1}{3}}=2\pi\times3=6\pi \end{gathered}[/tex]

what is the commutative propertyWhat is the associative propertyWhat is the identity propertyWhat is the multiplication property of zero

Answers

We will address different properties that are applied to integers.

Commulative property:

The commulative property states that if you change the order of integers while applying the basic mathematical operations of ( Addition and Multiplication ) the answer will remain unchanged. We will illustrate this with help of an example as follows:

[tex]\begin{gathered} 2\text{ + 4 = 6 , 4 + 2 = 6 }\ldots\text{ Commulative of Addition} \\ \\ 4\cdot\text{ 2 = 8 , 2}\cdot4\text{ = 8 }\ldots\text{ Commulative of multiplicity} \\ \text{Hence,} \\ 0\text{ + 4 = 4 , 4 + 0 = 4 }\ldots\text{ Commulative of Zero} \end{gathered}[/tex]

We tried changing the order of real numbers used in the two basic operations. We saw that the answer of each remain unchanged if we changed the order. Hence, Commulative property.

Associative property:

Refers to grouping of real number by adding paranthesis ( ) around a set of operations in a bigger chain of operations. So the property asserts that the choice of grouping the smaller sets does not affect the final answer. We will illustrate this with help of an example as follows:

[tex]\begin{gathered} \text{Original: 2 + 4 + 1} \\ \text{ } \\ (\text{ 2 + 4 ) + 1 = 6 + 1 = 7 , 2 + ( 4 + 1 ) = 2 + 5 = 7 , 4 + ( 2 + 1 ) = 4 + 3 = 7} \end{gathered}[/tex]

We made three combinations for selecting a smaller operations within a larger chain operation of addition. We grouped a pair of real numbers using parenthesis and resolved the parenthesis first then applied the last operation in each of the 3 cases illustrated above.

Identity property:

This property is divided into properties of addition and multiplication, where the identity is a real number ( 0 or 1 ) respectively. Both types of identity property are illustrated below as follows:

[tex]\begin{gathered} \text{\textcolor{#FF7968}{Identity of Add}} \\ 0\text{ + 5 = 5 , 0 + 100 = 100 , 0 + 25 = 25 , 0 + 13 = 13 , }\ldots \\ \text{\textcolor{#FF7968}{Identity of Multiplication:}} \\ 1\cdot\text{ 5 = 5 , 1 }\cdot\text{ 100 = 100 , 1 }\cdot\text{ 25 = 25 , 1 }\cdot\text{ 13 = 13 , }\ldots \end{gathered}[/tex]

Both the identity property leaves to the same conclusion i.e any "number" added to (0) is always the " number ". Any "number" multiplied with digit ( 1 ) is the "number" itself.

Multiplication property of zero:

This property states that any real or imaginary number multiplied with ( 0 ) always results in 0. Illustrated below:

[tex]1\cdot\text{ 0 = 0 , 3 }\cdot\text{ 0 = 0 , 4 }\cdot\text{ 0 = 0 , 125 }\cdot\text{ 0 = 0 , 259 }\cdot\text{ 0 = 0 , }\ldots[/tex]

Find the area of this triangle.Round to the nearest tenth.8 mho62°12 m[?] m2

Answers

we have two sides and a known angle, then we use the following formula for area

[tex]=\frac{a\cdot b\cdot\sin C}{2}[/tex]

where a = 8. b = 12 and C = 62°, so

[tex]\begin{gathered} A=\frac{8\cdot12\cdot\sin 62}{2} \\ A=\frac{96\cdot\sin 62}{2} \\ A=48\cdot\sin 62 \\ A=42.4 \end{gathered}[/tex]

answer: 42.4 m^2

Solve for x.X-8.9 = 9.1X=

Answers

ANSWER

[tex]undefined[/tex]

EXPLANATION

Given;

[tex]x-8.9=9.1[/tex]

To find x, we add 8.91 to both side, hence we have

[tex]undefined[/tex]

Now, 8.91 will cancel out aand then we have;

[tex]undefined[/tex]

Colin is making a 10-lb bag of trail mix for his upcoming backpacking trip. If chocolates cost $2.00 per pound and mixed nuts cost $8.00 per pound and Colin has budget of $6.20 per pound of trail mix, how many pounds of each should he use? A) pounds of chocolate? B) Pounds of nuts?

Answers

Answer:

• A) 3 pounds of chocolate.

,

• B) 7 Pounds of nuts.

Explanation:

• Let the number of pounds of chocolate he should use = c

,

• Let the number of pounds of nuts he should use = n

Colin is making a total of 10-lb bag of trail mix, therefore:

[tex]\begin{gathered} c+n=10 \\ \implies c=10-n \end{gathered}[/tex]

• Chocolates cost $2.00 per pound and mixed nuts cost $8.00.

,

• Colin has a budget of $6.20 per pound of trail mix

,

• He needs to make 10 pounds of trail-mix.

[tex]2.00c+8n=6.20\times10\text{ pounds}[/tex]

We solve the two equations simultaneously.

[tex]\begin{gathered} 2c+8n=62 \\ \text{From the first equation : }c=10-n \\ 2(10-n)+8n=62 \\ \text{Open the bracket} \\ 20-2n+8n=62 \\ 20+6n=62 \\ \text{Subtract 20 from both sides of the equation.} \\ 20-20+6n=62-20 \\ 6n=42 \\ \text{Divide both sides by 6} \\ \frac{6n}{6}=\frac{42}{6} \\ n=7 \end{gathered}[/tex]

Recall that c=10-n.

[tex]c=10-7=3[/tex]

Therefore, Colin should use (A) 3 pounds of chocolate; and (B) 7 Pounds of nuts.

A group of students want to determine if a person's height is linearly related to the distance they are able to jump.To determine the relationship between a person's height and the distance they are able to jump, the group of students measured the height, in inches, of each person in their class and then measured the distance, in feet, they were able to jump from a marked starting point.Each student was given three tries at the jump and their longest jump distance was recorded. The data the students collected is shown below.

Answers

Explanation

We are required to determine the correlation coefficient (r) of the data provided. This should be calculated with the formula:

[tex]r_{xy}=\frac{\sum_{i\mathop{=}1}^n(x_i-\bar{x})(y_i-\bar{y})}{\sqrt{\sum_{i\mathop{=}1}^n(x_i-\bar{x})^2\sum_{i\mathop{=}1}^n(y_i-\bar{y})^2}}[/tex]

The information can be represented in a table as:

From the table, we have:

[tex]\begin{gathered} \sum_{i\mathop{=}1}^n(X-M_X)(Y-M_Y)=\sum_{i\mathop{=}1}^n(x_i-\bar{x})(y_i-\bar{y})=31.800 \\ \\ \sum_{i\mathop{=}1}^n(X-M_X)^2=\sum_{i\mathop{=}1}^n(x-\bar{x})^2=288.438 \\ \\ \sum_{i\mathop{=}1}^n(Y-M_Y)^2=\sum_{i\mathop{=}1}^n(y-\bar{y})^2=4.520 \end{gathered}[/tex]

Therefore, we can calculate the correlation coefficient as:

[tex]\begin{gathered} r_{xy}=\frac{\sum_{i\mathop{=}1}^n(x_i-\bar{x})(y_i-\bar{y})}{\sqrt{\sum_{i\mathop{=}1}^n(x_i-\bar{x})_{i\mathop{=}1}^{2\sum n}(y_i-\bar{y})}}\frac{}{} \\ \\ r_{xy}=\frac{31.800}{\sqrt{288.438\times4.520}} \\ \\ r_{xy}=0.8807 \\ \\ r_{xy}\approx0.88 \end{gathered}[/tex]

Hence, the answer is 0.88.

19. Name the minor arc and find its measure.A1150DBA. ADB; 245B.AB; 245C. AB; 115D. ADB; 30

Answers

An arc is the path along the circumference of a circle.

When a circle is divided into two parts unevenly, there are two arcs, the shorter one and the longer one.

In our circle, there's arc AB and ADB and the shorter path is arc AB with angle 115 degrees, option C

A storage bin has the shape of a Square Prism with a Pyramid top. What is the volume of the storage bin ifits side length is s = 3 in, the height of the prism portion is h = 11 in, and the overall height is H = 18 in?

Answers

Given,

The height of the shape is 18 inches.

The height of cuboidal part is 11 inches.

The height of pyramid part is 18- 11 = 7 inches.

The side of the cuboidal part is 3 inches.

The base of the pyramid part is also 3 inches.

The volume of the cuboidal part is,

[tex]\begin{gathered} \text{Volume =l}\times b\times h \\ \text{Volume =s}\times\text{s}\times h \\ \text{ =3}\times3\times11 \\ \text{ =}99inches^3^{} \end{gathered}[/tex]

The volume of pyramid part is,

[tex]\text{Volume =}a^2+2a\sqrt{\frac{a^2}{4}+h^2}[/tex]

Here, the value of a is 3 and h is 7 then,

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