the graph represents an object that is shot upward from a tower and then falls to the ground. The independent variable is time in seconds and the dependent variable is the object's height above the ground in meters. 1. How tall is the tower from which the object was shot?2. when did the object hit the ground?3. estimate the greatest height the object reached and then the time it took to reach that heightindicate this situation on the graph below by drawing on the graph given

The Graph Represents An Object That Is Shot Upward From A Tower And Then Falls To The Ground. The Independent

Answers

Answer 1

In the graph, the height, measured in meters, is on the y-axis and the time, measured in seconds, is on the x-axis. It shows the variation of the height of an object shot from a tower with respect to the time.

1. Since the shot was made from the top of the tower, the starting height of the object (time zero) is equal to the height of the tower. This is represented in the graph by the y-intercept of the function, that is, the value of y when x=0.

The y-intercept is at (0,10) which indicates that the height of the tower is 10m

2. The point where the object hit the ground, the height is zero meters, so in the graph, it is determined by the point where the parabola reaches the x-axis (y=0) known as the x-intercept.

The coordinates of the x-intercept are (6,0)

This indicates that the object hit the ground 6 seconds after being shot.

3. The variability of the object's height describes a parabola, where the vertex of the parabola indicates the highest point the object can reach.

You have to determine the coordinates of the vertex by looking at the graph. These are, approximately (2.8,93)

The y-coordinate of the vertex indicates the highest point of the object, which is 93meters.

The x-coordinate of the vertex indicates the time it took the object to reach said height, which is 2.8 seconds


Related Questions

How to I get the answer? (-6)(-2)+(+8)(-4)=

Answers

Step 1. The expression that we have is:

[tex]\left(-6\right)\left(-2\right)+\left(+8\right)\left(-4\right)[/tex]

And we need to solve the operations to find the answer.

Step 2. We need to make the multiplications first:

(-6)(-2)=12

and

(+8)(-4)=-32

here we have applied the law of signs:

[tex]\begin{gathered} (-)(-)=+ \\ (+)(-)=- \end{gathered}[/tex]

The solution to the multiplications is shown here:

The expression now is:

[tex]12+(-32)[/tex]

Step 3. Now we solve the expression considering that

(+)(-) is -

[tex]12-32[/tex]

The result of the subtraction is:

[tex]-20[/tex]

Answer:

[tex]-20[/tex]

The current (I) in a wire varies directly as the voltage (v) and inversely as the resistance (r). If the current is 27.5 amps when the voltage is 110 volts and the resistance is 4 ohms, find the current when the voltage is 125 volts and the resistance is 16 ohms. (Round your answer to two decimal places.)

Answers

ANSWER

Current (l) = 7.81 amps (rounded to 2 decimal places)

EXPLANATION

Declaration of Variables

Let l represent the current in a wire,

v represent the voltage, and

r represent the resistance

Desired Outcome

The current (l)

Equation formation

[tex]\begin{gathered} l\propto\frac{v}{r} \\ l\text{ = }\frac{kv}{r} \end{gathered}[/tex]

where k is the constant of proportionality.

Determine the value of k given l = 27.5, v = 110, and r = 4.

[tex]\begin{gathered} l\text{ = }\frac{kv}{r} \\ 27.5\text{ = }\frac{k\times110}{4} \\ 110k\text{ = 27.5}\times4 \\ 110k\text{ = 110} \\ k\text{ = }\frac{110}{110} \\ k\text{ = 1} \end{gathered}[/tex]

Find the current (l) given v = 125, and r = 16.

[tex]\begin{gathered} l\text{ = }\frac{kv}{r} \\ l\text{ = }\frac{1\times125}{16} \\ l\text{ = 7.8125 amps} \end{gathered}[/tex]

Hence, the current (l) when the voltage is 125 volts and the resistance is 16 ohms is 7.81 amps (rounded to 2 decimal places).

Which of the following values are in the range of the function graphed below?Check all that apply.10+-10. 1002O A. -1OB. 2O C. 1O D. -6E. -2

Answers

The answer is (5, - 4) (Option D)

We are required to solve the system of equations:

[tex]\begin{gathered} 4x+y=16\text{ (Equation 1)} \\ 2x+3y=-2\text{ (Equation 2)} \end{gathered}[/tex]

In order to solve the equations, we need to make sure that one of the terms in both equations is the same.

In (Equation 1), there is a 4x term. In (Equation 2), there is a 2x term.

We can make 2x in (Equation 2), the same as 4x in (Equation 1), by multiplying the whole of (Equation 2) by 2

Let us perform this multiplication below:

[tex]\begin{gathered} 4x+y=16\text{ (Equation 1)} \\ 2x+3y=-2\text{ (Equation 2)} \\ \text{ Multiply (Equation) 2 by 2} \\ 2\times(2x+3y)=-2\times2 \\ 4x+6y=-4\text{ (Equation 3)} \\ \\ \text{Now we have two equations with 4x as a common term. They are:} \\ \\ 4x+y=16\text{ (Equation 1)} \\ 4x+6y=-4\text{ (Equation 3)} \end{gathered}[/tex]

Now that we have a similar term in both (Equation 1) and (Equation 2), we can subtract both equations to eliminate that term and then find the value of y.

This is done below:

[tex]\begin{gathered} 4x+y=16 \\ -(4x+6y)=-(-4)_{} \\ \\ 4x+y=16 \\ -4x-6y=4 \\ \\ 4x-4x+y-6y=16+4 \\ -5y=20\text{ (Divide both sides by -5)} \\ \\ \therefore y=-\frac{20}{5}=-4 \end{gathered}[/tex]

Now that we have the value of y, we can substitute this value into Equation 1 to get the value of x

This is done below:

[tex]\begin{gathered} \text{Equation 1:} \\ 4x+y=16 \\ \text{but y = -4} \\ \\ 4x+\text{ -4= 16} \\ 4x-4=16 \\ \\ \text{add 4 to both sides} \\ \\ 4x-4+4=16+4_{} \\ 4x=20\text{ (Divide both sides by 4)} \\ \\ x=\frac{20}{4}=5 \end{gathered}[/tex]

Therefore, the solution to the system of equations is:

x = 5, y = -4

Thus the final answer is (5, - 4) (Option D)

the expression -25t + 1250 represents the volume of liquid of a container after t seconds. the expression 50t + 250 represents the volume of liquid of another container after t seconds. what does the equation -25 + 1250= 50t +250 mean in this situation?

Answers

The volume of liquid (V1) in first container at any time 't' is given as,

[tex]V_1=-25t+1250[/tex]

The volume of liquid (V2) in other container at any time 't' is given as,

[tex]V_2=50t+250[/tex]

Consider the equation,

[tex]\begin{gathered} -25+1250=50t+250 \\ V_1=V_2 \end{gathered}[/tex]

Thus, the given equation represents the situation when the volume in both the containers are equal.

EXTREMELY URGENT WILL GIVE BRAINLIESTQuestion 1: The graph of h(x) is shown.Graph of h of x that begins in quadrant two and decreases rapidly following the vertical line which is 5 units to the left of the y-axis. The curve crosses the x-axis 4 units to the left of the origin and crosses the y-axis one unit below the origin and then continues to decrease to the right in quadrant 4.What are the intercepts and asymptote(s) of h(x)? Explain how to find these using the graph.Question 2: Using f(x) = log x, what is the x-intercept of g(x) = log (x + 4)? Explain your reasoning.Question 3: The table represents a logarithmic function f(x).x y1 over 125 −31 over 25 −2one fifth −11 05 125 2125 3What are the domain and range of f(x)? Explain your reasoning.Question 4: Given f(x) = log x, what transformations are needed to produce g(x) = log (x) − 3?Question 5: The logarithmic functions, f(x) and g(x), are shown on the graph.Graph depicting two curves, g of x and f of x equals log x. Curve g of x is increasing from the left asymptotic to the line x equals negative 1 and bends to the right and passes through zero comma four. Curve f of x equals log x increasing from the left asymptotic to the y-axis and bends to the right and passes through one comma zero.What is the equation that represents g(x)? Explain your reasoning.PLEASE HELP AND THANK YOU IN ADVANCE

Answers

Given: A graph of a function

[tex]h(x)[/tex]

The intercepts and the aymptotes of h(x) using the graph

From the given graph

Y-intercept is the point where the curves crosses the y-axis

From the graph, the coordinate of the y-intercep is

[tex]C_{y-\text{intercept}}=(0,-1)[/tex]

X-intercept is the point where the curves crosses the x-axis

From the graph, the oordinate of the x-intercept is

[tex]C_{x-\text{intercept}}=(-4,0)[/tex]

Answer:

x intercept= -4

y intercept= -1

Asymptote for H(x)= -5

Step-by-step explanation:

Yw;)

The bar graph to the right shows the average number of hours that people sleep per day by age group use this information to complete parts A and b. A. Consider a function of those the domain is the set of six ages shown let the range be the average number of hours that people sleep per day write the function as a set of ordered pairs

Answers

We must write the relation between the age and the average number of hours slept as a set of ordered pairs.

Notice that the average number of hours slept by age is the following:

[tex]\begin{gathered} 17\text{ years}\rightarrow9.4\text{ hours} \\ 22\text{ years}\rightarrow9.2\text{ hours} \\ 35\text{ years}\rightarrow8.8\text{ hours} \\ 45\text{ years}\rightarrow8.9\text{ hours} \\ 55\text{ years}\rightarrow8.5\text{ hours} \\ 65\text{ years}\rightarrow8.2\text{ hours} \end{gathered}[/tex]

To write the function as a set of ordered pairs, use the data from the domain (years) and from the range (hours) to form ordered pairs as (years,hours).

Then, the function as a set of ordered pairs is:

[tex]\mleft\lbrace(17,9.4\mright),(22,9.2),(35,8.8),(45,8.9),(55,8.5),(65,8.2)\}[/tex]

The 60 members of a school’s glee club need to raise at least $5,000 for a trip to a national competition. The school agreed to contribute $1,000 toward the trip. Which inequality below shows the amount of money that each glee club member needs to raise for the trip?

Answers

Since the club needs to raise $ 5, 000

And the school agrees to contribute $1000

Then if the least amount each of the 60 members of the club is represented by x

then

[tex]1000\text{ + 60x }\leq\text{ 5000}[/tex]

Alonso has $460 to spend at a bicyclestore for some new gear and bikingoutfits. Assume all prices listed includetax.• He buys a new bicycle for $270.71.•He buys 4 bicycle reflectors for $3.09each and a pair of bike gloves for$33.71.• He plans to spend some or all of themoney he has left to buy new bikingoutfits for $68.20 each.Write and solve an inequality which canbe used to determine x, the number ofoutfits Alonso can purchase while stayingwithin his budget.>Inequality:XîVIAI>

Answers

Solution:

[tex]\begin{gathered} 68.20x+307.51\leq460 \\ x\leq2.236 \end{gathered}[/tex]

Analysis:

We have a budget of $ 460. In the first step, we need to calculate the total amount of money spent on a bicycle, reflectors, and bike gloves.

[tex]Total\text{ }amount\text{ }spent=270.71+(4\ast3.09)+33.71=316.78[/tex]

When we calculate the amount spent, we can write the inequation:

[tex]68.20x+316.78\leq460[/tex]

X would be the number of outfits and adding to 316.78, it has to be less or equal to 460.

Now, let's

please help , i don’t know what to do !

Answers

Given the inequality:

[tex]v<-7[/tex]

So, we will select the values of v that is less than (-7)

The solution on the number line is as shown in the following figure:

So, we will select the numbers that are shown in the following figure:

The answer is the numbers with the red color.

Describing trends in scatter plotsA bus company wanted to know if the number of complaints theyreceived was a function of the number of buses it can Thecompany carried out a study comparing the average number ofbuses per hour for different days, and the number of complaintsthat it received on those days. The results are shown in the graph.

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Answer:

B. There tended to be fewer complaints on days with more buses.

Explanation:

From the scatterplot, when the number of buses per hour increased, the number of complaints reduced.

A line of best fit drawn on the scatterplot will have a negative slope.

The diagram below illustrates a negative and positive slope on the line of best fit.

Thus, we can say that there tended to be fewer complaints on days with more buses.

The correct option is B.

A foam cylinder, with a diameter of 3 inches and height of 8 inches, is carved into the shape of a cone. What is the maximum volume of a cone that can be carved? Round your answer to the hundredths place.Group of answer choices75.40 in318.85 in328.27 in356.55 in3

Answers

SOLUTION:

Step 1:

In this question, we are given the following:

A foam cylinder, with a diameter of 3 inches and a height of 8 inches, is carved into the shape of a cone.

What is the maximum volume of a cone that can be carved? Round your answer to the hundredth place.

Step 2:

The details of the solution are as follows:

[tex]\begin{gathered} Volume\text{ of a cylinder = }\pi\text{ r}^2h \\ where\text{ radius, r = }\frac{Diameter}{2}=\frac{3\text{ inches}}{2} \end{gathered}[/tex][tex]Height,\text{ h = 8 inches}[/tex][tex]Volume\text{ of the cylinder = }\pi\text{ x \lparen}\frac{3}{2})^2\text{ x 8 = 18 }\pi\text{ inches}^3[/tex][tex]\begin{gathered} Then,\text{ volume of the cone = }\frac{1}{3}\pi r^2h\text{ = }\frac{1}{3}\text{ \lparen }\pi r^2h)\text{ = }\frac{1}{3}\text{ \lparen 18}\pi\text{ \rparen = 6 }\pi \\ Hence,\text{ the maximum volume of the cone = 18. 85 inches}^3\text{ \lparen OPTION B \rparen} \end{gathered}[/tex]

CONCLUSION:

The

Identify the quadratic term, linear terms, and constant term: f(x) = 7x^2 + 12x + 19

Answers

Explanation

We are given the following equation:

[tex]7x^2+12x+19[/tex]

We are required to determine the quadratic term, the linear term, and the constant term.

This is achieved thus:

We know that given the general form of a quadratic equation, we have;

[tex]\begin{gathered} ax^2+bx+c=0 \\ where \\ a\Rightarrow quadratic\text{ }term \\ b\Rightarrow linear\text{ }term \\ c\Rightarrow constant\text{ }term \end{gathered}[/tex]

Hence, the answer is:

[tex]\begin{gathered} Quadratic\text{ }term:7 \\ Linear\text{ }term:12 \\ Constant\text{ }term:19 \end{gathered}[/tex]

ABCD is a rhombus. If AB = 2x + 12 , AC = 7x - 3, ∠=12°,m∠APB=12y°, and ∠m∠ACP= (4y - 1)°.CD = __ .

Answers

Given: A rhombus ABCD

[tex]\begin{gathered} AB=2x+12 \\ AC=7x-3 \\ m\angle APB=12y^0 \\ m\angle ACP=(4y-1)^0 \end{gathered}[/tex]

To Determine: The CD

Solution

Please note that the four sides of a rhombus are the same side lengths

[tex]\begin{gathered} AB=AC=CD=BD \\ Therefore \\ AB=AC \\ 2x+12=7x-3 \\ 2x-7x=-3-12 \\ -5x=-15 \\ \frac{-5x}{-5}=\frac{-15}{-5} \\ x=3 \end{gathered}[/tex][tex]\begin{gathered} AB=2x+12 \\ AB=2(3)+12 \\ AB=6+12 \\ AB=18 \end{gathered}[/tex]

Since all the side lengths of the rhombus are the same, then CD = 18 units

Write an equation for a polynomial with all the following features: The degree is 5, the polynomial has 4 terms and the graph of the polynomial crosses the vertical axis at y=12

Answers

we must apply the formula

[tex]y=x^2+bx\times c[/tex][tex]3.25x^5+4x^{4^{}}\text{ }+5.5x^{3\text{ }}+x^2[/tex]

now we apply the formula to find x,

[tex]\begin{gathered} h=\frac{b}{2(a)} \\ h=\frac{-4}{2(1)} \\ h=-2 \end{gathered}[/tex]

having already x now we apply the formula to find the vertex at y that intersects at point 12.

[tex]\begin{gathered} f(-2)=3.25(-2)^{5\text{ }}+4(-2)^{4^{}}+5.5(-2)^{3^{}}\text{ }+(-2)^{2^{}} \\ f(-2)=104-64-44-8 \\ =-12 \end{gathered}[/tex]

Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.An employee at a construction company is ordering interior doors for some new houses that are being built. There are 5 one-story houses and 5 two-story houses on the west side of the street, which require a total of 115 doors. On the east side, there are 2 one-story houses and 5 two-story houses, which require a total of 85 doors. Assuming that the floor plans for the one-story houses are identical and so are the two-story houses, how many doors does each type of house have?

Answers

"There are 5 one-story houses and 5 two-story houses on the west side of the street, which require a total of 115 doors." translates to 5x + 5y = 115

"there are 2 one-story houses and 5 two-story houses, which require a total of 85 doors." translates to 2x + 5y = 85

[tex]\begin{gathered} \text{Solve by elimination} \\ 5x+5y=115 \\ 2x+5y=85 \\ \text{Multiply the second equation by -1, then add the equations together.} \\ (5x+5y=115) \\ -1(2x+5y=85 \\ \downarrow \\ 5x+5y=115 \\ -2x-5y=-85 \\ \text{Add these equations to eliminate y:} \\ 3x=30 \\ \text{Divide both sides by 3} \\ \frac{3x}{3}=\frac{30}{3} \\ x=10 \\ \text{Substitute }x=10\text{ to any of the equation} \\ 5x+5y=115 \\ 5(10)+5y=115 \\ 50+5y=115 \\ 5y=115-50 \\ 5y=65 \\ \frac{5y}{5}=\frac{65}{5} \\ y=13 \end{gathered}[/tex]

Substitute x = 10 for one story houses, and y = 13 for two story houses.

[tex]\begin{gathered} \text{West Side Houses} \\ 5x+5y=115 \\ 5(10)=50 \\ 5(13)=65 \\ \text{There are 50 doors for one-story house and 65 for the two-story house on west side} \\ \\ \text{East Side houses} \\ 2x+5y=85 \\ 2(10)=20 \\ 5(13)=65 \\ \text{There are 20 doors for one-story house and 65 for the two-story house on the east side} \end{gathered}[/tex]

Ken has a food truck that sells for 5 dollars and up. Bryan buys $20 worth of food. How much money will Ken make in one hour if the price of the food goes up by $10 every 2 minutes and 30 seconds for the tourist visits

Answers

Let:

M(t) = Money earned by ken as a function of time

Let's asume ken earned 20 dollars for the purchase of Bryan

And let's make a conversion:

2 min * 60 s/1min = 120s

So, the food goes up every 150s

Hence the function M(t) would be:

Let's define t2= 150s

M(t) = $20 + ($5+$10t/t2)

Because he sells his food for $5 and the price goes up by $10 every 150s

Ok, now an hour has 3600s:

So:

3600s/150s = 24

We can conclude that in one hour the food went up in price 24 times

Now, using the function:

M(t) = $20 + ($5+$10t/t2)

For t = 3600

M(3600) = $20 + ($5 + $10 * (3600)/(150))

M(3600) = $20 + ($5 + $10*24)

M(3600) = $20 + $5 + $240 = $265

Ken will make $265 in one hour

solve each inequality using adding subtraction multiplication and divison

Answers

1.5 + 0.3> 3.6

1.8>3.6 is a contradiction, then the given inequality is False.

Given triangle FGH is similar to triangle LMN, which must be true?

Answers

Answer:

Options A, B, and E

Explanations:

See below the diagramatic representations of the two congruent triangles

Since △FGH ∼ △LMN:

All corresponding sides are similar

The ratio of two corresponding sides are equal

Corresponding angles are congruent

Therefore:

[tex]\begin{gathered} \frac{FG}{LM}=\text{ }\frac{FH}{LN} \\ FH\text{ }\sim LN \\ m

Can u help me answer question 25 BTW this is lesson 6 the distributive property Question: Mrs.singh brought 9 folders and 9 notebooks. the cost of each folder was $2 50. each notebook cost $4. write two equivalent expressions and then find the total cost

Answers

∵ The number of the folders = 9

∵ The cost of each folder = $2.50

∴ The cost of the folders = 9 x 2.50

Find the volume of the triangular prism.i have worked on it a bit but I'm unsure if I'm correct.

Answers

The volume of a prism is equal to the area A of its base times its height h:

[tex]V=h\cdot A[/tex]

On the other hand, there is a formula to find the area of a triangle if the lengths of 3 sides are given.

Let a, b and c be the lengths of the sides of a triangle.

We define the semiperimeter s of the triangle as:

[tex]s=\frac{a+b+c}{2}[/tex]

Then, the area of the triangle is given by the Heron's formula:

[tex]A=\sqrt[]{s(s-a)(s-b)(s-c)}[/tex]

Replace a=3cm, b=6cm and c=5cm to find s:

[tex]s=\frac{3\operatorname{cm}+6\operatorname{cm}+5\operatorname{cm}}{2}=\frac{14\operatorname{cm}}{2}=7\operatorname{cm}[/tex]

Replace the values of a, b and c as well as s=7cm into Heron's formula to find the area of the triangular base:

[tex]\begin{gathered} A=\sqrt[]{7\operatorname{cm}\cdot(7cm-3cm)(7cm-6cm)(7cm-5cm)} \\ =\sqrt[]{7\operatorname{cm}\cdot4\operatorname{cm}\cdot1\operatorname{cm}\cdot2\operatorname{cm}} \\ =\sqrt[]{56\operatorname{cm}^4} \\ =\sqrt[]{56}\cdot cm^2 \\ \approx7.48\operatorname{cm}^2 \end{gathered}[/tex]

Replace the value of A and h=15cm into the equation to find the volume of the prism:

[tex]\begin{gathered} V=h\cdot A \\ =15\operatorname{cm}\cdot\sqrt[]{56}\cdot cm^2 \\ =15\cdot\sqrt[]{56}\cdot cm^3 \\ \approx112.25\operatorname{cm}^3 \end{gathered}[/tex]

Therefore, to the nearest cubic centimeter, the volume of the prism is 112 cm^3.

When a plane flies with the wind, it can travel 1440 miles in 3 hours. When the plane flies in the opposite direction against the wind it takes 4 hours to fly the same distance. Find the rate of the plane in still air Find the rate of the wind

Answers

We know that

• The plane travels 1440 miles in 3 hours with the wind.

,

• It takes 4 hours against the wind to travel the same distance.

Let's call p the rate of the plane in still air, and w the speed of the wind.

Traveling with the wind would be expressed as follows.

[tex]3(p+w)=1440[/tex]

This expression is deducted from the distance formula d = v*t.

The expression that represents against the wind would be.

[tex]4(p-w)=1440[/tex]

To solve the system we just formed.

[tex]\begin{gathered} 3p+3w=1440 \\ 4p-4w=1440 \end{gathered}[/tex]

Let's multiply the first equation by 4 and the second equation by 3.

[tex]\begin{gathered} 12p+12w=5760 \\ 12p-12w=4320 \end{gathered}[/tex]

Now, let's combine the equations.

[tex]\begin{gathered} 12p+12p+12w-12w=5760+4320 \\ 24p=10080 \\ p=\frac{10080}{24} \\ p=420 \end{gathered}[/tex]

The rate of the plane in still air is 420 miles per hour.

Now, let's find w.

[tex]\begin{gathered} 3p+3w=1440 \\ 3\cdot420+3w=1440 \\ 1260+3w=1440 \\ 3w=1440-1260 \\ w=\frac{180}{3} \\ w=60 \end{gathered}[/tex]

The rate of the wind is 60 miles per hour.

The function f(x) = 22 + 1 is graphed below: x Is this a growth or decay function? growth Domain: Range: > y-intercept:

Answers

A function showing an exponential growth is modelled in the form,

y = Aoe^kt

where k is the rate of growth

If k is negative, then it is the rate of decay and the function would be a decay function

can someone match the following parts of the circle with its correct name?

Answers

SOLUTION

First, we will define the terms and match the line that matches the definition.

RADIUS

A straight line from the center to the circumference of a circle

[tex]\bar{PB}=radius[/tex]

DIAMETER

A straight line passing from side to side through the center of a body(circle)

[tex]\bar{EB}=diameter[/tex]

CHORD

The chord of a circle can be defined as the line segment joining any two points on the circumference of the circle.

[tex]\bar{DA}=chord[/tex]

TANGENT

The tangent to a circle is defined as a straight line that touches the circle at a single point.

[tex]\bar{EF}=tangent[/tex]

If clay’s buss pass has $50 on it and each ride cost $3.00, choose the inequality that represents this situation.

Answers

x will represent the number of rides Clay do

The cost of the rides must be less or equal to 50. Therefore the inequality is

[tex]3x\le50[/tex]

ANSWER

3x<=50

7. Identify a horizontal or vertical stretch or compression of the function f(x)=√x by observing the equation of the function g(x)=√3x.

Answers

Given:

The function is:

[tex]\begin{gathered} f(x)=\sqrt{x} \\ \\ g(x)=\sqrt{3x} \end{gathered}[/tex]

Find-:

The horizontal or vertical stretch or compression of the function

Explanation-:

The graph of a function is:

The f(x) is:

[tex]f(x)=\sqrt{x}[/tex]

The graph of function is:

[tex]g(x)=\sqrt{3x}[/tex]

So, the both function is:

So, the graph is vertically stretch by √3

[tex]\begin{gathered} f(x)=\sqrt{x} \\ \\ g(x)=\sqrt{3x} \\ \\ g(x)=\sqrt{3}\sqrt{x} \end{gathered}[/tex]

what are the angles of rotation for a rectangle ?

Answers

A rectange has four sides. Two sides with the same length and other two sides of the same length.

This means that if you rotate the rectangle you will obtain the same figure only for rotation of 180°.

You can notice the previous conclusion in the following image:

The rectangle with black lines is the original one, and the rectangle with red lines is the rotated rectangle with a rotation of 180°. You can observe that for such a rtation yo obtain the same figure.

What is the volume of the following prism?A. 50 m³B. 150 m³C. 75 m³D. 225 m³

Answers

In order to find the volume of a traingular prism, we do:

1/2 ( b x h x l) = 1/2 (5x2x15)

1/2(150)

= 75 m³

Letter C

A diagram of a rectangular pool with a diagonal of 50 meters is shown below. Connected to the pool is a square shaped kid’s pool.What is the area of the kid’s pool in the diagram? Ulysses says the area of the kid’s pool is 900 square meters.Ursula says the area of the kid’s pool is 120 square meters. Which student is correct?

Answers

Let's find the length of the side of the pool.

Let it be x, so the diagram is:

Using the pythagorean theorem, we can figure out x. Shown below:

[tex]\begin{gathered} x^2+40^2=50^2 \\ x^2=50^2-40^2 \\ x^2=900 \\ x=\sqrt[]{900} \\ x=30 \end{gathered}[/tex]

So, 30 meters is the side length of the square (pool).

The area of a square is:

[tex]A=s^2[/tex]

Where "s" is the side length

We found s to be 30, thus the area of the pool is:

[tex]\begin{gathered} A=s^2 \\ A=(30)^2 \\ A=900 \end{gathered}[/tex]

Thus,

Ulysses is correct.

On a circle of radius 6 feet, what angle would subtend an arc of length 6 feet?

Answers

Given the word problem, we can deduce the following information:

Radius of a circle = 6 feet

Arc length = 6 feet

To determine the central angle, we use the formula:

[tex]\theta=\frac{L}{r}(\frac{360}{2\pi})[/tex]

where:

L=arc length

r=radius

θ= central angle in degrees

We plug in what we know:

[tex]\begin{gathered} \theta=\frac{L}{r}(\frac{360}{2\pi}) \\ =\frac{6}{6}(\frac{360}{2\pi}) \\ \text{Simplify} \\ \theta=\frac{180}{\pi} \\ \\ \text{Calculate} \\ \theta=57.30\degree \end{gathered}[/tex]

Therefore, the angle is 57.30°.

A ladder is leaning against a building and makes a 32° angle with the ground the top of the ladder which is 20 feet up on the building what is the length of the ladder around the final answer to the nearest foot

Answers

Given

Angle = 32°

top of the ladder is 20 feet up on the building

Find

length of the ladder

Explanation

let length of ladder = h

here we use trigonometric ratio.

[tex]\sin C=\frac{opposite}{Hypotenuse}[/tex]

so ,

[tex]\begin{gathered} \sin32=\frac{20}{h} \\ \\ h=\frac{20}{\sin32} \\ \\ h=\frac{20}{0.52991926423b} \\ \\ h=37.74\approx38ft \end{gathered}[/tex]

Final Answer

Hence , the length of ladder in nearest foot is 38 ft

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