The graph shows government receipts and outlays​ (both on-budget and​ off-budget) for . In what years did receipts appear to climb faster than​ outlays?

Answer:

sin(O) = 2/sqrt(5)   or 2sqrt(1/5)

Step-by-step explanation:

using 1+cot^2(x) = csc^2(x)

we have, taking reciprocal on both sides,

sin(x) = 1/sqrt(1+cot^2(x)

= 1/sqrt(1+(-1/2)^2)

= 1/sqrt(5/4)

= 2/sqrt(5)   or 2sqrt(1/5)

Since angle x is in the second quadrant, sin(x) is positive.

Answer:

0, 22, 44, 66

Step-by-step explanation:

Given the equation for the model, [tex] d = 11t [/tex] , you can complete the table above by simply plugging in each value of "t" has given in the table to solve for "d".

*When t (seconds) = 0, distance (feet) would be:

[tex] d = 11(0) [/tex]

[tex] d = 0 [/tex]

*When t (seconds) = 2, distance (feet) would be:

[tex] d = 11(2) [/tex]

[tex] d = 22 [/tex]

*When t (seconds) = 4, distance (feet) would be:

[tex] d = 11(4) [/tex]

[tex] d = 44 [/tex]

*When t (seconds) = 6, distance (feet) would be:

[tex] d = 11(6) [/tex]

[tex] d = 66 [/tex]

Answer:

a)The calculated value t = 4.111 > 1.9925 at 5 % level of significance

Null hypothesis is rejected

The claim that the average time on death row is not 15 years

b) The p-value is 0.000101<0.05

we reject Null hypothesis

The claim that the average time on death row is not 15 years

Step-by-step explanation:

Step(i):-

Sample size 'n' =75

Mean of the sample x⁻ = 17.8

standard deviation of the sample (S) = 5.9

Mean of the Population = 15

Null hypothesis:H₀:μ = 15 years

Alternative Hypothesis :H₁:μ≠15 years

Step(ii):-

Test statistic

                         [tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }[/tex]

                        [tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }=\frac{17.8-15}{\frac{5.9}{\sqrt{75} } }[/tex]

                    t = 4.111

Degrees of freedom

ν = n-1 = 75-1=74

t₀.₀₂₅ = 1.9925

The calculated value t = 4.111 > 1.9925 at 5 % level of significance

Null hypothesis is rejected

The claim that the average time on death row is not 15 years

P-value:-

The p-value is 0.000101<0.05

we reject Null hypothesis

The claim that the average time on death row is not 15 years

Answer: 6 with milk, 9 without

Step-by-step explanation:

2/5 of the cookies he eats are dunked.  Thus, simply do 2/5, or .4*15 to get that 6 cookies are dunked, and 15-6 to get that 9 cookies are not dunked.

Hope it helps <3

Answer:

[tex]\boxed{Mean = 34.33}[/tex]

Step-by-step explanation:

Mean = Sum of Observations / No. Of Observations

Mean = (24+18+37+82+17+26)/6

Mean = 206 / 6

Mean = 34.33

Answer:

The answer is option A.

Step-by-step explanation:

Using the properties of logarithms

that's

[tex] log(x) - log(y) = log( \frac{x}{y} ) [/tex]

log 2 - log 14 is

[tex] log(2) - log(14) = log( \frac{2}{14} ) [/tex]

Simplify

We have the final answer as

[tex] log( \frac{1}{7} ) [/tex]

Hope this helps you

Answer:

log ( 1/7)

Step-by-step explanation:

log2-log14

We know that log ( a/b) = log a - log b

log (2 /14)

log ( 1/7)

Answer:

Answer is 24288.

Step-by-step explanation:

Given that there are 18 senior and 22 junior partners.

To find:

Number of ways of selecting at least one junior partner to form a committee of 3 partners.

Solution:

At least junior 1 member means 3 case:

1. Exactly 1 junior member

2. Exactly 2 junior member

3. Exactly 3 junior member

Let us find number of ways for each case and then add them.

Case 1:

Exactly 1 junior member:

Number of ways to select 1 junior member out of 22: 22

Number of ways to select 2 senior members out of 18: 18 [tex]\times[/tex] 17

Total number of ways to select exactly 1 junior member in 3 member committee: 22 [tex]\times[/tex] 18 [tex]\times[/tex] 17 = 6732

Case 2:

Exactly 2 junior member:

Number of ways to select 2 junior members out of 22: 22 [tex]\times[/tex] 21

Number of ways to select 1 senior member out of 18: 18

Total number of ways to select exactly 2 junior members in 3 member committee: 22 [tex]\times[/tex] 21 [tex]\times[/tex] 18 = 8316

Case 3:

Exactly 3 junior member:

Number of ways to select 3 junior members out of 22: 22 [tex]\times[/tex] 21 [tex]\times[/tex] 20 = 9240

So, Total number of ways = 24288

There is only one distinct triangle possible, with m N= 33º. Therefore, option B is the correct answer.

Law of Sines In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of any triangle to the sines of its angles.

The formula for sine rule is sinA/a=sinB/b=sinC/c

Given that, in ΔMNO, m = 20, n = 14, and m∠M = 51°.

Now, sin51°/20=sinN/14

0.7771/20=sinN/14

0.038855=sinN/14

sinN=14×0.038855

sinN=0.54397

N=33°

Therefore, option B is the correct answer.

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Answer:

x=-11

Step-by-step explanation:

x+8=-3

x=-3-8 :- collect like term

since we are adding two negative numbers, we will let the number be negative but add them.

x=-11

Hope it helps :)

Answer:

x=-11

Step-by-step explanation:

x+8=-3

collect like terms;

x=-3-8

x=-11

Answer:

(f+g)(x)= 9x² + 9x

(f+g)(3) = 108

Step-by-step explanation:

f(x)=8x² +7x

g(x)= x² +2x

(f+g)(x) = f(x) + g(x) = 8x² +7x +x² +2x = 9x² + 9x

(f+g)(x)= 9x² + 9x

(f+g)(3)= 9*3² + 9*3 = 108

Answer: The rule of complements is apprising us that, the person selected will.eithwr have a type B blood or will not have a type B blood

Step-by-step explanations:

Find explanations in the attachment

Answer:

0.0414 with an upper tailed test

Step-by-step explanation:

Claim: P1P1 = P2P2

The above is a null hypothesis

The alternative hypothesis for a two-tailed test would be:

P1P1 \=/ P2P2

Where "\=/" represents "not equal to".

Using a z-table or z-calculator, we derive the p-value (probability value) for the z-score 2.04

With an upper tailed test, the

2 × [probability that z>2.04] = 2[0.0207] = 0.0414

This is the p-value for the test statistic.

Focus is on the alternative hypothesis.

Answer:

The Man needs to run at 9 mph

Step-by-step explanation:

Let M stand for the man's speed in mph.  When the man  

runs toward point A, the relative speed of the train with respect  

to the man is the train's speed plus the man's speed (45 + M).  

When he runs toward point B, the relative speed of the train is the  

train's speed minus the man's speed (45 - M).

When he runs toward the train the distance he covers is 2 units.  

When he runs in the direction of the train the distance he covers  

is 3 units. We can now write that the ratio of the relative speed  

of the train when he is running toward point A to the relative speed  

of the train when he is running toward point B, is equal to the  

inverse ratio of the two distance units or

              (45 + M)          3

              -----------  =      ---

              (45 - M)          2

          90+2 M=135-3 M

⇒5 M = 45

⇒ M = 9 mph

The Man needs to run at 9 mph

Answer: 9 mph

Step-by-step explanation:

Given that a man walking on a railroad bridge is 2/5 of the way along the bridge when he notices a train at a distance approaching at the constant rate of 45 mph .

If the man tend to run in the forward direction, he will cover another 2/5 before the train reaches his initial position. The distance covered by the man will be 2/5 + 2/5 = 4/5

The remaining distance = 1 - 4/5 = 1/5

If the man can run at a constant rate in either direction to get off the bridge just in time before the train hits him, the time it will take the man will be

Speed = distance/time

Time = 1/5d ÷ speed

The time it will take the train to cover the entire distance d will be

Time = d ÷ 45

Equate the two time

1/5d ÷ speed = d ÷ 45

Speed = d/5 × 45/d

Speed = 9 mph

D. All numbers greater than -10 and less than or equal to 8

Answer:

There is a solution. The ordered pair is (4, 2).

Step-by-step explanation:

Solve the system of equations by using the substitution method.

[tex]x+y=6\\x=2y[/tex]

Substitute x as 2y in the first equation and solve for y.

[tex]2y+y=6\\ 3y=6\\(3y)/3=6/3\\y=2[/tex]

Substitute y as 2 in the second equation and solve for x.

[tex]x=2(2)\\x=4[/tex]

Answer:

[tex]\boxed{(1, -3)}[/tex]

Step-by-step explanation:

[tex]y+3=2 (x-1)[/tex]

Put equation in slope-intercept form.

[tex]y=mx+b[/tex]

[tex]y=2(x-1)-3[/tex]

[tex]y=2x-2-3[/tex]

[tex]y=2x-5[/tex]

Let x = 1

[tex]y=2(1)-5[/tex]

[tex]y=2-5[/tex]

[tex]y=-3[/tex]

The point (1, -3) lies on the line.

Answer:

$16,750.00

Step-by-step explanation:

Simple interest:

I = Prt

Value of an investment of value P over t years at r interest rate:

F = P + Prt

F = P(1 + rt)

19,513.75 = P(1 + 0.03 * 5.5)

1.165P = 19,513.75

P = 16,750

Answer: $16,750.00

The present value of the investment was $16,750 which is worth $19,513.75 after earning 3% simple interest for 512 years.

Simple interest is defined as interest paid on the original principal and calculated with the following formula:

S.I. = P × R × T, where P = Principal, R = Rate of Interest in % per annum, and T = Time, usually calculated as the number of years. The rate of interest is in percentage r% and is to be written as r/100

We have been given data as:

Rate of Interest (R) = 3% = 3/100 = 0.03

Time (T) = 512  years

Value of an investment of value P over t years at r interest rate:

A = P + Prt

A = P(1 + rt)

19,513.75 = P(1 + 0.03 × 5.5)

19,513.75 = 1.165P

1.165P = 19,513.75

P = 19,513.75/1.165

P = 16,750

Thus, the present value of the investment was $16,750 which is worth $19,513.75 after earning 3% simple interest for 512 years.

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Answer:

x = -4/3 and x = 5/2.

Step-by-step explanation:

6x² - 7x = 20

6x² - 7x - 20 = 0

To solve this, we can use the quadratic formula to solve this.

[please ignore the A-hat; that is a bug]

[tex]\frac{-b±\sqrt{b^2 - 4ac} }{2a}[/tex]

In this case, a = 6, b = -7, and c = -20.

[tex]\frac{-(-7)±\sqrt{(-7)^2 - 4 * 6 * (-20)} }{2(6)}[/tex]

= [tex]\frac{7±\sqrt{49 + 80 * 6} }{12}[/tex]

= [tex]\frac{7±\sqrt{49 + 480} }{12}[/tex]

= [tex]\frac{7±\sqrt{529} }{12}[/tex]

= [tex]\frac{7±23 }{12}[/tex]

[tex]\frac{7 - 23 }{12}[/tex] = [tex]\frac{-16 }{12}[/tex] = -8 / 6 = -4 / 3

[tex]\frac{7 + 23 }{12}[/tex] = [tex]\frac{30}{12}[/tex] = 15 / 6 = 5 / 2

So, x = -4/3 and x = 5/2.

Hope this helps!  

Answer:

Step-by-step explanation:

[tex]6 {x}^{2} - 7x = 20[/tex]

Move constant to the left and change its sign

[tex] {6x}^{2} - 7x - 20 = 0[/tex]

Write -7x as a difference

[tex]6 {x}^{2} + 8x - 15x - 20 = 0[/tex]

Factor out 2x from the expression

[tex]2x(3x + 4) - 15x - 20 = 0[/tex]

Factor out -5 from the expression

[tex]2x(3x + 4) - 5(3x + 4) = 0[/tex]

Factor out 3x + 4 from the expression

[tex](3x + 4)(2x - 5) = 0[/tex]

When the product of factors equals 0 , at least one factor is 0

[tex]3x + 4 = 0[/tex]

[tex]2x - 5 = 0[/tex]

Solve the equation for X1

[tex]3x + 4 = 0[/tex]

Move constant to right side and change its sign

[tex] 3x = 0 - 4[/tex]

Calculate the difference

[tex]3x = - 4[/tex]

Divide both sides of the equation by 3

[tex] \frac{3x}{3} = \frac{ - 4}{3} [/tex]

Calculate

[tex]x = - \frac{4}{3} [/tex]

Again,

Solve for x2

[tex]2x - 5 = 0[/tex]

Move constant to right side and change its sign

[tex]2x = 0 + 5[/tex]

Calculate the sum

[tex]2x = 5[/tex]

Divide both sides of the equation by 2

[tex] \frac{2x}{2} = \frac{5}{2} [/tex]

Calculate

[tex]x = \frac{5}{2} [/tex]

[tex]x1 = - \frac{4}{3} [/tex]

[tex]x2 = \frac{5}{2} [/tex]

Hope this helps...

Best regards!!

Answer:

The range of T is a subspace of W.

Step-by-step explanation:

we have T:V→W

This is a linear transformation from V to W

we are required to prove that the range of T is a subspace of W

0 is a vector in range , u and v are two vectors in range T

T = T(V) = {T(v)║v∈V}

{w∈W≡v∈V such that T(w) = V}

T(0) = T(0ⁿ)

0 is  Zero in V

0ⁿ  is zero vector in W

T(V) is not an empty subset of W

w₁, w₂   ∈ T(v)

(v₁, v₂ ∈V)

from here we have that

T(v₁) = w₁

T(v₂) = w₂

t(v₁) + t(v₂) = w₁+w₂

v₁,v₂∈V

v₁+v₂∈V

with a scalar ∝

T(∝v) = ∝T(v)

such that

T(∝v) ∈T(v)

so we have that T(v) is a subspace of W. The range of T is a subspace of W.

Answer:

60 and 87

Step-by-step explanation:

Question 1: The chance of losing would be 100% - 40% = 60%.

Question 2: Again, we just have to do 100% - 13% = 87%.

Answer:

Below

Step-by-step explanation:

First question:

Jade has a 40% chance of winnig wich could be expressed as 2/5

The chance of losing is the remainning pourcentage from 100%

●100-40 =60%

60% is the chance of losing wich could be expressed as 3/5

The sum of 3/5 and 2/5 is 1 so it's true.

■■■■■■■■■■■■■■■■■■■■■■■■■

Same method for the 2nd question:

The person has a 13 % chance of winning.

The chance of losing is 87%

● 100-13 =87

Answer:

Step-by-step explanation:

The p value (probability of obtaining results as extreme the z score if null is true) is usually the value derived to make a conclusion and in this case the p value is 0.03

The level of significance is the value usually compared with the p value which is 0.05

The sample promotion is 65 out of 100 = 65/100 = 0.65

The sample size is the total number of consumers which is 100

The null value is usually the default value. The null value would assume that there is no difference in the proportions who prefer each type in the population. There are two preferences: 100/2 = 50- 0.5 for each preference.

Answer:

[tex](x + {y}^{2}) = {x}^{2} + 2x {y}^{2} + {y}^{4} [/tex]

Thanks!!!!

Answer: try using sine for this equasion

Step-by-step explanation:

A - No

B - No

C - Yes

D - Yes

.

C and D are alternate exterior angles

Answer:

11% of the Total the entire voting population

Step-by-step explanation:

Let's bear in mind that the total number of sample candidates is equal to 600.

But out of 600 only 66 preffered candidate A.

The proportion of sampled people to that prefer candidate A to the total number of people is 66/600

= 11/100

In percentage

=11/100 *100/1 =1100/100

=11% of the entire voting population

Answer:  ($143.69, $156.31)

Step-by-step explanation:

Confidence interval to estimate  population mean :

[tex]\overline{x}\ \pm z\dfrac{\sigma}{\sqrt{n}}[/tex]

, where [tex]\sigma[/tex] = population standard deviation

n= sample size

[tex]\overline{x}=[/tex] Sample mean

z= critical value.

As per given,

n= 40

[tex]\sigma[/tex] = $15.50

[tex]\overline{x}=[/tex] $150

Critical value for 99% confidence level = 2.576

Then, 99% confidence interval for the population mean:

[tex]150\pm(2.576)\dfrac{15.50}{\sqrt{40}}\\\\\Rightarrow\ 150\pm6.31 \ \ (approx)\\\\\Rightarrow(150-6.31,150+6.31)=(143.69,156.31)[/tex]

Hence, the required confidence interval : ($143.69, $156.31)

Answer:

Step-by-step explanation:

Given the half like of a material to be 8.3 hours and the amount of iron-52 left after t hours is modeled by the equation [tex]A(t) = A_0 a^{t}[/tex], we can get A(t) as shown;

At t = 8.3 hours, A(8.3) = 1/2

Initially at t = 0; A(0) = 1

Substituting this values into the function we will have;

[tex]\frac{1}{2} = 1 * a^{8.3}\\\\Taking \ the \ log \ of\ both \ sides;\\\\log(\frac{1}{2} ) = log(a^{8.3} )\\\\log(\frac{1}{2} ) = 8.3 log(a)\\\\\fr-0.30103 = 8.3 log(a)\\\Dividing\ both\ sides\ by \ 8.3\\\\\frac{-0.30103}{8.3} = log(a)\\\\log(a) = - 0.03627\\\\a =10^{-0.03627} \\\\a = 0.919878 (to\ 6dp)[/tex]

Answer:

B. edge 2021

B. is correct for the next one too.

Step-by-step explanation:

B. is the correct answer for the first one
B. is also the correct answer for the second one

Answer:

[tex]AG=22[/tex]

Step-by-step explanation:

Follow the next steps:

[tex]\frac{A-B}{A-E} =\frac{B-C}{E-F} =\frac{C-D}{F-G} =\frac{A-C}{A-F} =\frac{B-D}{E-G} =\frac{A-D}{A-G}[/tex]

Let:

[tex]\frac{A-B}{A-E} =\frac{B-C}{E-F}\\ \\\frac{4}{A-E} =\frac{5}{10x}\\ \\Solving\hspace{3}for\hspace{3}A-E\\\\A-E=8x[/tex]

Now:

[tex]\frac{C-D}{F-G} =\frac{A-C}{A-F} \\\\\frac{2}{F-G} =\frac{9}{18x} \\\\Solving\hspace{3}for\hspace{3}F-G\\\\F-G=4x[/tex]

Hence:

[tex]A-G=(A-E)+(E-F)+(F-G)=22x[/tex]

Finally:

[tex]\frac{B-D}{E-G} =\frac{A-D}{A-G}\\\\\frac{A-D}{B-D} =\frac{A-G}{E-G}\\[/tex]

[tex]\frac{11}{7} =\frac{22x}{14x} \\\\\frac{11x^{2} }{7} -\frac{11}{7} =0\\\\[/tex]

Hence:

[tex]x=1\\x=-1[/tex]

Since it would be absurd for [tex]x=-1[/tex], the real solution is [tex]x=1[/tex]

Therefore:

[tex]AG=22[/tex]

Answer: the numbers are 3 and -3

Step-by-step explanation:

let the unknown number be x

The first UNKNOWN NUMBER = X

The second unknown number is = 6 + x

Their product = -9

(X)(6 + X) = -9

6x +[tex]x^{2}[/tex]=-9

[tex]x^{2}[/tex] +6x +9=0

we multiply the coefficient of x which is 1 with 9

now, we look for two numbers that when multiplied will give us 9 and when added will give 6 and that is 3 and 3

[tex]x^{2}[/tex] +3x+3x +9 = 0

x(x+3) +3(x+3) = 0

(x +3 ) = 0

or (x +3)=0

x +3 =0

x=0 -3

x =-3

x +3=0

x =0-3

x =-3

since the numbers are the same ,we pick one

therefore,the first number =x =-3

the second number is 6 + x=6 + (-3)

6-3=3