The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with 155 grams of a radioactive isotope, how much will be left after 5 half-lives?
Use the calculator provided and round your answer to the nearest gram.

The correct option -D. 5;  Thus, the value of x for the given external secant segment and the tangent on the circle is found as:x = 5.

A line that precisely intersects a circle at two points is said to be a secant.

The size of the angle created when two tangents, two secants, or two tangents cross outside of a circle is equal to one-half a positive difference between the sizes of the intercepted arcs.

Using the Theorem:

The square of a length of tangent is equal the the product of such external secant segment and the overall length of the secant if one secant and one tangent both drawn to a circle from a single exterior point:

4(4 + x) = 6²

16 + 4x = 36

4x = 36 - 16

4x = 20

x = 20/4

x = 5

Thus, the value of x for the given external secant segment and the tangent on the circle is found as:x = 5.

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According to the information, we know that the term 125x^5y^4 appears in the expansion when n = 6 and the coefficient of x^6y^7 in the expansion is zero, and the x^6y^7 term does not appear in the expansion.

We know that the binomial expansion of (x-y)^n is given by the formula:

where nCk represents the binomial coefficient "n choose k".

We are given that the term 125x^5y^4 appears in the expansion, so we can set up an equation using the binomial coefficient for that term:

Simplifying this equation, we get:

We can solve for n by finding the smallest value of n for which nC5 is greater than or equal to 125. We can use the formula for binomial coefficients:

to calculate the values of nCk for different values of n and k. However, it is easier to use Pascal's triangle to find the binomial coefficients quickly. The fifth row of Pascal's triangle is:

We see that the sixth term of this row is 10C5 = 252, which is greater than 125. Therefore, we know that the term 125x^5y^4 appears in the expansion when n = 6.

To find the x^6y^7 term in the expansion, we need to find the coefficient of x^6y^7 in the expansion. We can use the same formula as before, but with k = 7 instead of k = 5:

We can simplify this expression using the fact that (-1)^7 = -1:

We want to find the value of this expression, so we need to find the value of n. We know that n = 6 because the term 125x^5y^4 appears in the expansion. Therefore, we can substitute n = 6 into the expression:

We see that 6C7 is zero because we cannot choose 7 items from a set of 6. Therefore, the coefficient of x^6y^7 in the expansion is zero, and the x^6y^7 term does not appear in the expansion.

To find the x^7y^2 term in the expansion, we can use the same formula as before, but with k = 2:

We can simplify this expression using the fact that (-1)^2 = 1:

We want to find the value of this expression, so we need to find the value of n. We know that n = 6 because the term 125x^5y^4 appears in the expansion. Therefore, we can substitute n = 6 into the expression:

We can use Pascal's triangle to find that 6C2 = 15. Therefore, the coefficient of x^7y^2 in the expansion is 15, and the x^7y^2 term appears in the expansion as:

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The depreciation expense for each year is 1,000,000 shs.

Accumulated depreciation up to year 6 is 6,000,000 shs.

The depreciation using the straight line method is given by the formula:

Depreciation expense per year = (Initial cost - Salvage value) / Useful life

Initial cost = 5,000,000 + 800,000 + 1,500,000 = 7,300,000 shs.

Salvage value = 1,300,000 shs.

Depreciation expense per year = (7,300,000 - 1,300,000) / 6

                                                    = 6,000,000 / 6

                                                    = 1,000,000 shs.

Thus, the depreciation expense for each year is 1,000,000 shs.

Accumulated depreciation up to year 6 = Depreciation expense per year * Number of years

Accumulated depreciation up to year 6 = 1,000,000 * 6 = 6,000,000 shs.

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Answer:

Tyshawn would have to sell 6 computers on a given day to get paid $225

Step-by-step explanation:

We can use the information in the table to find the equation of the linear relationship between a (the number of computer sales) and p (Tyshawn's total pay):p = 75 + 25aThis equation tells us that Tyshawn's total pay is $75 plus $25 for each computer he sells.To find out how many computers Tyshawn would have to sell in order to get paid $225 on a given day, we can substitute p = 225 into the equation and solve for a:225 = 75 + 25a150 = 25aa = 6

Answer:

D

Step-by-step explanation:

A rotation and translation preserves the length measures of the sides, so FD is equal to 7 inches

Answer: D

Step-by-step explanation:

Answer:

1/8

Step-by-step explanation:

If "over" refers to (4 * 6) as a whole,

[tex]\frac{3}{4*6}\\\\=\frac{3}{24}\\\\=\frac{1}{8}[/tex]

If "over" refers to division,

[tex]3 \div 4 \times 6\\= 0.75 \times 6\\= 4.5[/tex]

I would suppose it's the first one, so, ignore the second one if you haven't learnt BODMAS yet.

Hope this helps and be sure to mark this as brainliest! :)

Given polygons ABCD and A'B'C'D' have scale factors of 1/4 since their respective side ratios are the same.

The amount by which a shape is made smaller or larger is referred to as its scale factor. This method is employed when a 2D polygon, irregular or regular shape, such as a circle, triangle, square, or rectangle, needs to be enlarged larger. In the equation y = px, p is the scale factor for x. One may identify the scale factor between any two shapes or figures by comparing the measurements of the new shape to those of the prior shape.

Scale factor = Dimensions of new shape/Dimensions of original shape

given the original polygon's coordinates:

A(4,4) ; B(12,4) ; C(12,8) ; D(4,8)

Distance AB = X₂ - X₁

                     = 12 - 4

                     = 8 units

Distance BC = Y₂ - Y₁

                     = 8 - 4

                     = 4 units

Distance CD = X₂ - X₁

                     = 12 - 4

                     = 8 units

Distance DA = Y₂ - Y₁

                     = 8 - 4

                     = 4 units

Added coordinates for the new polygon:

A'(1,1) ; B(3,1) ; C(3,2) ; D(1,2)

Distance A'B' = X₂ - X₁

                      = 3 - 1

                      = 2 units

Distance B'C' = Y₂ - Y₁

                      = 2 - 1

                      = 1 units

Distance C'D' = X₂ - X₁

                      = 3 - 1

                      = 2 units

Distance D'A' = Y₂ - Y₁

                      = 2 - 1

                      = 1 units

Scale factor = [tex]\frac{A^{\prime} B^{\prime}}{A B}=\frac{B^{\prime} C^{\prime}}{B C}=\frac{C^{\prime} D^{\prime}}{C D}=\frac{D^{\prime} A^{\prime}}{D A}[/tex]

[tex]\frac{A B}{A^{\prime} B^{\prime}}=\frac{2}{8}=\frac{1}{4}\\\\\frac{B^{\prime} C^{\prime}}{B C}=\frac{1}{4}\\\\\frac{C^{\prime} D^{\prime}}{C D}=\frac{2}{8}=\frac{1}{4}\\\\\frac{D^{\prime} A^{\prime}}{D A}=\frac{1}{4}[/tex]

Scale factor = [tex]\frac{A^{\prime} B^{\prime}}{A B}=\frac{B^{\prime} C^{\prime}}{B C}=\frac{C^{\prime} D^{\prime}}{C D}=\frac{D^{\prime} A^{\prime}}{D A}=\frac{1}{4}[/tex]

The image was reduced using a one-fourth scale factor.

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Refer to the attachment for the graph.

In the given right triangle, by using the Pythagorean theorem, the value of x is 5√2 and the value of y is 5√2

From the question, we are to determine the value of x and y in the given diagram

The diagram shows a right triangle with a hypotenuse of 10.

The right is a special type of right triangle. The base angles of the triangle are equal.

Thus,

The right triangle is an isosceles right triangle.

This means the legs of the triangle are equal.

That is,

x = y

From the Pythagorean theorem, we can write that

x² + y² = 10²

Since x = y, we can write that

x² + x² = 10²

2x² = 100

x² = 50

x = √50

x = 5√2

Hence,

y = 5√2

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Answer:

  (d)  25 feet and 20 feet​

Step-by-step explanation:

You want the possible dimensions of a pool with an area of 500 square feet and a perimeter of 90 feet.

The area is the product of the length and width. The area of the pools offered in the answer choices are ...

  (a)  15·30 = 450 . . . square feet

  (b)  10·35 = 350 . . . square feet

  (c)  50·10 = 500 . . . square feet

  (d)  25·20 = 500 . . . square feet

The area requirement eliminates answer choices A and B.

The perimeter is twice the sum of length and width. The perimeters of the possible pools are ...

  (c) 2(50 +10) = 120 . . . feet

  (d) 2(25 +20) = 90 . . . feet

The perimeter requirement eliminates answer choice C.

The pool's possible length and width are 25 feet and 20 feet, choice D.

__

Additional comment

You could write a quadratic equation for the pool dimensions, but doing that will generally involve more work than checking the given answer choices.

If x is the width, then 45-x is the length, and the area is ...

  x(45 -x) = 500

  x² -45x +506.25 = -500 +506.25 . . . multiply by -1, complete the square

  x = 22.5 -√6.25 = 20 . . . . take the square root; width is the smaller dimension

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The flow chart is complete and the answers are given below.

Those figures that have same shape and size are called Congruent Figures.

The flow diagram will be completed as follows

∠2 ≅ ∠4 (  vertical angle theorem )

∠1   ≅  ∠2  ( Given )

∠1  ≅ ∠ 3  ( Vertical Angle Theorem)

∠3   ≅  ∠4  ( Transitive Property of congruence)

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The value of GH in the right angle triangle, given FH and Angle FHG is 22.46 inches.

Since we have the adjacent side (FH) and want to find the hypotenuse (GH), we can use the cosine function.

cos(35°) = adjacent side (FH) / hypotenuse (GH)

We know that FH = 18.4 in. So, we can write the equation as:

cos(35°) = 18.4 / GH

GH = 18.4 / cos(35°)

GH = 18.4 / 0.81915

=  22.46 inches

So, the length of GH, the hypotenuse, is approximately 22.46 inches.

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Answer:

$3.25

Step-by-step explanation:

An ice cream cone that has x scoops of ice cream costs 1 + 0.75x.

So an ice cream cone that has 3 scoops of ice cream costs
1 + 0.75×3 = 3.25 (dollars)

In a a case whereby factory that has 6 X 10³ workers makes 2.4 X 105 products each day, the average amount of products made per worker is 4 *10^1 products per worker

The term "average" in mathematics typically refers to a measure of central tendency, which is a way to describe the typical or common value in a set of numbers. There are several types of averages.

We can calculate the required value as

( 2.4 X 10^5 )/ (6 X 10³)

=4 *10^1 products per worker

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Let [tex]x[/tex] be the unknown side of the triangle. Find the length of this side from the Pythagorean Theorem;

Another root of the equation is also negative, but we've eliminated it because length can't be a negative value.

To find the area of a triangle, we multiply the height of the triangle by the base length and take half.

a) The angular velocity = 0.4π rad/s b) The linear velocity of the hamster = 4π cm/s.

Linear velocity is the rate of change of an object's position with respect to time. It measures how fast an object is moving in a straight line, and is often expressed in units of distance per time, such as meters per second or kilometers per hour.

a) The angular velocity of the wheel can be calculated as follows:

Angular velocity = (2π * number of revolutions) / time

Here, the wheel completes one revolution in 5 seconds, so the number of revolutions is 1 and the time is 5 seconds. Therefore,

Angular velocity = (2π * 1) / 5

Angular velocity = 0.4π rad/s (or approximately 1.26 rad/s)

b) The linear velocity of the hamster can be calculated as follows:

Linear velocity = radius * angular velocity

Here, the radius of the wheel is 10 cm, and the angular velocity we found in part (a) is 0.4π rad/s. Therefore,

Linear velocity = 10 cm * 0.4π rad/s

Linear velocity = 4π cm/s (or approximately 12.57 cm/s)

So the hamster is running at a linear velocity of approximately 12.57 cm/s.

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The appropriate measurement unit for force is  kg.m/s²

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration

One Newton is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared.

Since F = m × a

Plug in m = kg and a = m/s²

F = kg × m/s²

F = kg.m/s²

Therefore, the unit of measurement is kg.m/s².

Option B is the correct answer.

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The truth table for the given expression can be given using p= T q = T, p^q = T, ~p = F, ~q = F, ~q v ~p = T, and  (p ^ q) =~p v ~q = T, thus proving the required.

The field of symbolic logic known as propositional logic, also referred to as sentential logic or statement logic, is concerned with propositions or statements, which are declarative phrases that can be true or untrue. To represent propositions and their relationships, propositional logic employs symbols and operators.

Many disciplines, including mathematics, computer science, philosophy, and others, employ propositional logic as a tool for debating the truth or falsity of propositions and analysing arguments.

The truth table for the given expression can be given as:

p  |  q  |  p ^ q  |  ~p  |  ~q  |  ~q v ~p  |  (p ^ q) =~p v ~q

-------------------------------------------------------------

T  |  T  |    T    |   F  |  F   |    T     |         T

T  |  F  |    F    |   F  |  T   |    T     |         T

F  |  T  |    F    |   T  |  F   |    T     |         T

F  |  F  |    F    |   T  |  T   |    T     |         T

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The histogram should be modified as follows:

A histogram is a type of graphical representation that displays the distribution of a dataset. It is a bar graph-like chart where the data is divided into intervals, called "bins", which are represented by adjacent rectangular bars of varying heights.

Then the height of the histogram gives the number of observations into each data interval.

Hence the histogram should be modified as follows:

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The requried quantity of drug that remains in the body, in the long run, is 220 mg.

Let's denote the amount of drug in the body just before taking the nth tablet by [tex]D_n[/tex]. We know that [tex]D_0 = 0[/tex](since the patient hasn't taken any tablets yet) and that 5% of the drug is present in the body just before taking a tablet remains in the body. Therefore, we can write:

[tex]D_1 = 110\\D_2 = 0.95 * D_1 + 110 = 203.5\\D_3 = 0.95 * D_2 + 110 = 292.225\\D_4 = 0.95 * D_3 + 110 = 376.81375[/tex]

We can see that the formula for [tex]D_n[/tex] is:

[tex]D_n = 110 * (1 - 0.05)^n + 110 * (1 - (1 - 0.05)^n) / 0.05[/tex]

Simplifying this formula, we get:

[tex]D_n = 220 * (1 - 0.95^n)[/tex]

Now, we want to find the amount of drug that remains in the body in the long run. This means we want to find the limit of [tex]D_n[/tex]  as n goes to infinity. Using the formula above, we can see that:

[tex]lim_ {n- > oo} D_n = lim_ {n- > oo} 220 * (1 - 0.95^n) = 220[/tex]

Therefore, the quantity of drug that remains in the body, in the long run, is 220 mg.

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Answer:

Trapezoid

Step-by-step explanation:

It's a quadrilateral and it only has one pair of parallel sides.

One such tool that enables us to visualise the given math issue using various-sized rectangles or bars is the bar model.

A bar model in mathematics is a visual representation of a subject or problem where the known and unknown quantities are represented by bars or boxes. To answer issues involving the four operations of addition, subtraction, multiplication, and division, bar models are most frequently utilised.

To help kids "see" mathematical structure, the bar model is utilised in teaching for mastery. It is not a method for solving issues, but rather a strategy to uncover the mathematical underpinnings of a problem and obtain knowledge and clarity to aid in its resolution.

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Image attached below,

Note that the median of the distribution or the density curve is -6. (Option C)

If the curve is a straight line and the area under the curve appears to be a rectangle, then we can assume that the density curve is a uniform distribution. In this case, the median of the distribution is simply the midpoint of the interval, which would be

(-10 + (-2))/2

= -6.

A density curve is a mathematical model used to describe the overall pattern of a dataset. It is a smooth curve that approximates the distribution of the data and shows the relative frequencies of observations at different values.

The area under the curve represents the total proportion of observations in the dataset, and the curve is normalized such that the total area under the curve equals one. Density curves are used in statistics to analyze and interpret data, and can be used to make predictions about future observations.

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Using the total area of the rectangular pool we know that the required width of the pathway is 3.6 ft respectively.

In the Euclidean plane, a rectangle is a quadrilateral with four right angles.

A parallelogram with a right angle or an equiangular quadrilateral, where equiangular means that all of its angles are equal, are other ways to define it.

A rectangle with four equal-length sides is a square.

Squares are not always rectangles, but rectangles are always squares.

So, the pool and walkway together have a 360 square foot total space.

Assume that the walkway is w feet in width.

Since the pool has an additional w feet of width on both sides, the total area's measurements can be expressed as (8 + 2w) by (10 + 2w).

Thus, we can construct the following equation:

(8 + 2w) x (10 + 2w) = 360

By enlarging and condensing the left side, we obtain:

4w² + 36w - 80 = 0

Using the quadratic formula, we can find w:

w = (-b ± √(b² - 4ac)) / 2a

Here, an equals 4, b equals 36, and c equals -80. When these values are added to the formula, we obtain:

w = (-36 ± √(36² - 4(4)(-80))) / 8

w = (-36 ± √(1872)) / 8

w ≈ -5.6 or w ≈ 3.6

We can ignore the first option because the width cannot be negative. Consequently, the pathway should be around 3.6 feet wide.

Therefore, using the total area of the rectangular pool we know that the required width of the pathway is 3.6 ft respectively.

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Answer:

5.4

Step-by-step explanation:

square of 29 = 5.385164807

5.385164807 estimated is 5.4

Step-by-step explanation:

to find the interest she needs to pay back every month, we need to use this formula:

I = PRT/12

in this case the principle is $300,000, the rate is 7% p.a. and the amount of time is 1 year, if we substitute in our values we:

I = (300,000)(7)(1)/12 = $17,500 in interest every month

to find her yearly income from rent, we have to multiply the monthly rent by 12

1500 × 12 = $18,000

to calculate her loss percentage in a year, we have to subtract 18,000 from 3000 which is 15,000

she said that she hopes the property's value will increase to cover the loss she made.

to cover the loss of $15000 per year, the property needs to increase in value by at least $15000. the percentage increases value can be written as

Percentage increase = (difference in increase/Original price) × 100

so

percentage increase = (15000/300000) × 100 = 5%

so the property needs to increase in value by at least 5% per year to cover the loss.

The woman needs to pay $1750 monthly as interest. Her yearly income from the rent is $18,000. After considering all other costs, she is at a loss of $6000 per year, so the property needs to increase in value by 2% per year to cover this loss.

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a) the exponential equation equivalent to log8 1/64 = 2 is 1/64 = [tex]8^{(-2)}[/tex]

b)  the logarithmic equation equivalent to 3^0 = 1 is log3 1 = 0.

What is exponential equation?

An exponential equation is one in which the exponent contains a variable.

(a) We can rewrite the logarithmic equation as an exponential equation by using the definition of logarithms. The logarithmic equation

log8 1/64 = 2

means that 8 raised to the power of 2 is equal to 1/64:

[tex]8^2 = 1/64[/tex]

Thus, we can write the exponential equation as:

[tex]1/64 = 8^{(-2)}[/tex]

Therefore, the exponential equation equivalent to log8 1/64 = 2 is 1/64 = [tex]8^{(-2)}.[/tex]

(b) We can rewrite the exponential equation as a logarithmic equation by using the definition of logarithms. The exponential equation

[tex]3^0 = 1[/tex]

means that the logarithm of 1 to the base 3 is equal to 0:

log3 1 = 0

Therefore, the logarithmic equation equivalent to 3^0 = 1 is log3 1 = 0.

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Answer:

33 thats with the 1 dollar subtracted for the entry fee

Step-by-step explanation:

first you add all the number of marbles you have then you get 41 then divide it by 12 because you have 2 gold and 10 silver and you get 3.4 and multiply that by 10 because its 6 and 4 and you get 34 subtract the entry fee

The expression (23,000-789) * 19 = = 421409.

An expression can contain variables, constants, and mathematical operations, and it can be used to represent a wide variety of mathematical concepts and relationships.

According to given information:

To solve the expression (23,000-789) * 19, we need to perform the subtraction operation inside the parentheses first and then multiply the result by 19.

(23,000-789) equals 22,211.

So, we have:

(23,000-789) * 19 = 22,211 * 19

Now, we can multiply the two numbers using the standard multiplication method. We multiply each digit of 19 with the digits of 22,211 starting from the right and then add the results.

22,211 x  19 =

444422  (19 x 1 = 19, write 9 and carry 1) + 420789  (19 x 1 = 19, write 9 and carry 1, 19 x 2 = 38, write 8 and carry 3)

= 421409

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One per 2,500 can be used to represent the rate of 80cm to 2km.

To write 80cm to 2km as a rate, we need to convert the units to the same system. We can convert 80cm to kilometers by dividing by 100,000 (since there are 100,000 centimeters in a kilometer):

80 cm/100,000 = 0.0008 km

Now we can express the rate as:

0.0008 km per 2 km

Or we can simplify it by dividing both the numerator and denominator by 0.0008:

1 per 2,500

Therefore, 80cm to 2km can be expressed as a rate of 1 per 2,500.

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The surface soil of the entire garden within the fencing that needs to be turned prior to planting is approximately 176.625 square feet.

Radius is a mathematical term that refers to the distance from the center of a circle, sphere, or other curved object to any point on its circumference or surface. It is typically denoted by the letter "r".

Let's call the radius of the circular garden "r". We know that the circumference of the garden (the length of the fence) is 47.1 feet, so we can set up the equation:

2πr = 47.1

Simplifying this equation by dividing both sides by 2π, we get:

r = 47.1/(2π)

Using 3.14 as a substitute for π, we can calculate:

r ≈ 7.5 feet

Now that we know the radius of the garden, we can calculate the area of the garden by using the formula for the area of a circle:

A = πr²

A = 3.14 * 7.5²

A ≈ 176.625 square feet

Therefore, the surface soil of the entire garden within the fencing that needs to be turned prior to planting is approximately 176.625 square feet.

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