Answer:
oh cool I'm gonna try that
. Which responsibility belongs to the marketing function?
Answer:
The marketing functions involves various responsibilities of the business organization, these functions are responsible for the growth of company. The key roles and responsibilities of marketing functions are market research, finance, product development, communication, distribution, planning, promotion, selling etc.
Name 4 components of a components system
Create a map using the Java map collection. The map should have 4 entries representing students. Each entry should have a unique student ID for the key and a student name for the element value. The map content can be coded in directly, you do not have to allow a user to enter the map data. Your program will display both the key and the value of each element.
Answer:
In Java:
import java.util.*;
public class Main{
public static void main(String[] args) {
Map<String, String> students = new HashMap<>();
students.put("STUD1", "Student 1 Name");
students.put("STUD2", "Student 2 Name");
students.put("STUD3", "Student 3 Name");
students.put("STUD4", "Student 4 Name");
for(Map.Entry m:students.entrySet()){
System.out.println(m.getKey()+" - "+m.getValue()); }
}}
Explanation:
This creates the map named students
Map<String, String> students = new HashMap<>();
The next four lines populates the map with the ID and name of the 4 students
students.put("STUD1", "Student 1 Name");
students.put("STUD2", "Student 2 Name");
students.put("STUD3", "Student 3 Name");
students.put("STUD4", "Student 4 Name");
This iterates through the map
for(Map.Entry m:students.entrySet()){
This prints the details of each student
System.out.println(m.getKey()+" - "+m.getValue()); }
10.11 LAB: Pet information (derived classes) The base class Pet has private data members petName, and petAge. The derived class Dog extends the Pet class and includes a private data member for dogBreed. Complete main() to: create a generic pet and print information using PrintInfo(). create a Dog pet, use PrintInfo() to print information, and add a statement to print the dog's breed using the GetBreed() function.
Answer:
Answered below.
Explanation:
//Program in Java
Class Test{
public static void main (String[] args){
//create a pet object
Pet pet = new Pet();
//call pet object's printInfo method
pet.printInfo();
//create a new Dog object
Dog dog = new Dog();
//dog can access the printInfo method of the Pet class because it derives from it
dog.printInfo();
//dog can also call it's private method.
dog.getBreed();
}
}
Mathilda’s computer has been running slow the past few months. She observed that the system unit becomes too hot. What does she need to do to fix this issue?
A.
She needs to make sure that the keyboard and mouse are properly connected.
B.
She needs to install antivirus software.
C.
She needs to delete unwanted files from her hard disk.
D.
She needs to clean the dust from the system unit fan.
Answer:
The answer is D
Explanation:
8. What's the output of this code?
1
def sum(x, y):
return(x+y)
print(sum (sum(1,2), sum(3,4)))
Answer:
10
Explanation:
[tex]sum(1,2) = 3\\sum(3,4) = 7\\sum(3,7) = 10\\[/tex]
Basically, sum((1+2) + (3+4)) = sum(3,7) = (3+7) = 10
HLOOKUP is used for Horizontal Data look ups while VLOOKUP is for Vertical Data look ups
Select one:
True
False
Answer:
True
Explanation:
Both HLOOKUP and VLOOKUP are excel functions used for searching through tables for a specified lookup value to either get an exact or approximate match. The VLOOK and HLOOKUP functions have identical syntax which only differs with the HLOOKUP requiring the row index number to search through the rows while, VLOOKUP requires the column index number to search through the columns. Other than this difference, the other syntax values are the same.
VLOOKUP(lookup_value, table_array, col_index_num, [range_lookup])
HLOOKUP(lookup_value, table_array, row_index_num, [range_lookup])
Describe a problem you’ve solved or a problem you’d like to solve. It can be an intellectual challenge, a research query, an ethical dilemma — anything of personal importance, no matter the scale. Explain its significance to you and what steps you took or could be taken to identify a solution.
Answer:
Explanation:
I run an online e-commerce store and lately its been very difficult keeping track of customer detail, incoming orders, keyword generation etc. One solution that I thought about would be an application that controls all of that for me. In order to accomplish this I would first need to design and create a GUI that contains all of the necessary buttons and displays for the information. Then I would need to code a webscraper using Python to grab all of the data from e-commerce store as soon as it becomes available, organize it, and display it within the GUI.
Suppose a byte-addressable computer using set-associative cache has 2 16 bytes of main memory and a cache size of 32 blocks and each cache block contains 8 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the size of the tag, set, and offset fields
Answer:
Following are the responses to these question:
Explanation:
The cache size is 2n words whenever the address bit number is n then So, because cache size is 216 words, its number of address bits required for that cache is 16 because the recollection is relational 2, there is 2 type for each set. Its cache has 32 blocks, so overall sets are as follows:
[tex]\text{Total Number of sets raluired}= \frac{\text{Number of blocks}}{Associativity}[/tex]
[tex]=\frac{32}{2}\\\\ =16\\\\= 2^4 \ sets[/tex]
The set bits required also are 4. Therefore.
Every other block has 8 words, 23 words, so the field of the word requires 3 bits.
For both the tag field, the remaining portion bits are essential. The bytes in the tag field are calculated as follows:
Bits number in the field tag =Address Bits Total number-Set bits number number-Number of bits of words
=16-4-3
= 9 bit
The number of bits inside the individual fields is therefore as follows:
Tag field: 8 bits Tag field
Fieldset: 4 bits
Field Word:3 bits