The kinetic energy, E₁, in kilograms meters squared per second squared (kg- m²/sec) of an object can be
where m is the object's mass in kilograms and v is the object's
modeled with the equation E, = -mv².
m²,
velocity in meters per second.
A physics student is investigating 2 moving objects:
.
Object A's kinetic energy is 100 kg m²/sec².
.
Object B's kinetic energy is 25 kg m²/sec²
.
.
Write equations for each object's velocity, in meters/second, in terms of its mass in kilograms. Then
graph the two functions on the same coordinate grid. Provide evidence to support your answer.

Answers

Answer 1

The equations for each object's velocity, in meters/second, in terms of its mass in kilograms are:

[tex]V_A=\sqrt{\frac{200}{m} }\\\\V_B=\sqrt{\frac{50}{m} }[/tex]

A graph of the two functions is shown below.

How to calculate kinetic energy?

In Mathematics, the kinetic energy of an object can be calculated by using the following equation (formula):

K.E = 1/2 × mv²

Where:

K.E represent the kinetic energy.m represent the mass.v represent the speed or velocity.

By making velocity (v) the subject of formula, we have:

[tex]V= \sqrt{\frac{2K.E}{m} }[/tex]

In this context, the equations for each object's velocity, in terms of its mass can be written as follows;

Velocity of object A = [tex]V_A= \sqrt{\frac{2(100)}{m} }[/tex]

Velocity of object A = [tex]V_A= \sqrt{\frac{200}{m} }[/tex]

Velocity of object B = [tex]V_B= \sqrt{\frac{2(25)}{m} }[/tex]

Velocity of object B = [tex]V_B= \sqrt{\frac{50}{m} }[/tex]

When mass (m) = 2 kg, the velocity of object A can be calculated as follows;

[tex]V_A=\sqrt{\frac{200}{m} } \\\\V_A=\sqrt{\frac{200}{2} }\\\\V_A=10 \;m/s[/tex]

When mass (m) = 2 kg, the velocity of object B can be calculated as follows;

[tex]V_B=\sqrt{\frac{50}{m} } \\\\V_B=\sqrt{\frac{50}{2} }\\\\V_B=5 \;m/s[/tex]

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Complete Question:

The kinetic energy, E₁, in kilograms meters squared per second squared (kg.m²/sec) of an object can be modeled with the equation E, = 1/2mv².

where m is the object's mass in kilograms and v is the object's velocity in meters per second.

A physics student is investigating 2 moving objects:

Object A's kinetic energy is 100 kg m²/sec².

Object B's kinetic energy is 25 kg m²/sec²

Write equations for each object's velocity, in meters/second, in terms of its mass in kilograms. Then graph the two functions on the same coordinate grid. Provide evidence to support your answer.

The Kinetic Energy, E, In Kilograms Meters Squared Per Second Squared (kg- M/sec) Of An Object Can Bewhere

Related Questions

suppose that 64% of people own dogs. if you pick two people at random, what is the probability that they both own a dog

Answers

The probability that both people own a dog is approximately 0.4096, or 40.96%.

To solve this problem, we can use the formula for calculating the probability of the intersection of two independent events: P(A and B) = P(A) x P(B).

Let's define A as the event that the first person owns a dog, and B as the event that the second person owns a dog. Since the two people are chosen at random, we can assume that these events are independent.

According to the problem, P(A) = P(B) = 0.64, since 64% of people own dogs. Therefore, the probability of both events occurring is:

P(A and B) = P(A) x P(B) = 0.64 x 0.64 = 0.4096

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an experiment of flipping a coin was run 200 times with the results shown below. What is the difference between the experimental probability and the theoretical probability of landing on heads?

heads = 140
tails = 60

Answers

Theoretical probability describes how likely an event is to occur, and experimental probability describes how frequently an event actually occurred in an experiment.

hope this helps

Of the students at Milton Middle School, 170 are girls. If 50% of the students are girls, how many total students are there at Milton Middle school?

Answers

The solution is :

There are 240 students in the school.

Here, we have,

Givens

55% of the total number of students in a school are girls.

Equation

55/100 * x = 132

Solution

Multiply both sides of the equation  by 100

55/100x * 100  = 132 * 100

55x = 13200                        [  Divide by 55  ]

55x/55  = 13200/55

x = 240

Hence, The solution is :

There are 240 students in the school.

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complete question:

Of the students at milton middle school, 132 are girls. if 55% of the students are girls, how many total students are there at milton middle school?

Taryn bought all her school supplies on tax-free weekend and spent $180. If sales tax is normally 7. 5%, how much did Taryn save by shopping on tax-free weekend?

A $2. 40

B $13. 50

C $24. 00

D $135. 0

Answers

Taryn saved $13.50 by shopping on tax-free weekend, since she did not have to pay any sales tax on her $180 purchase.

to calculate how much taryn saved by shopping on tax-free weekend, we first need to calculate how much she would have paid in sales tax if she had bought her school supplies on a regular day.

if the sales tax is normally 7.5%, then the amount of sales tax taryn would have paid is:

0.075 x $180 = $13.50 the answer is (b) $13.50.

Taryn bought all her school supplies on tax-free weekend and spent $180. If sales tax is normally 7. 5%,

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find an equation for the plane consisting of all points that are equidistant from the points (5, 0, −2) and (7, 8, 0)

Answers

An equation for the plane consisting of all points equidistant from the points (5, 0, −2) and (7, 8, 0) is -2y + 8z = -8x + 32.

To find an equation for the plane consisting of all points equidistant from the points (5, 0, -2) and (7, 8, 0), we can use the fact that the set of points equidistant from two non-coincident points forms the perpendicular bisector of the line segment joining those two points.

First, we can find the midpoint of the line segment joining the two points:

midpoint = ((5 + 7) / 2, (0 + 8) / 2, (-2 + 0) / 2) = (6, 4, -1)

Next, we can find the direction vector of the line segment joining the two points:

direction vector = (7, 8, 0) - (5, 0, -2) = (2, 8, 2)

Now, we can find a vector normal to the plane by taking the cross product of the direction vector and any vector in the plane. Let's use the vector (1, 0, 0):

normal vector = (2, 8, 2) x (1, 0, 0) = (0, -2, 8)

Finally, we can use the point-normal form of the equation for a plane to write the equation of the plane:

0(x - 6) - 2(y - 4) + 8(z + 1) = 0

Simplifying:

-2y + 8z = -8x + 32

Therefore, an equation for the plane consisting of all points equidistant from the points (5, 0, −2) and (7, 8, 0) is -2y + 8z = -8x + 32.

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find derivative of ² (20) = √₂2²² f 2-2 √1 t4 dt as your answer please input f' (2) in decimal form with three significant digits after the decimal place.

Answers

The value of f'(2) in decimal form with three significant digits after the decimal place is -1.14.

To find the derivative of the given function, we need to use the chain rule and the power rule of differentiation. Firstly, we can simplify the given function as:
²(20) = 2²² = 4¹¹
√₁ t⁴ = t²
Therefore, the given function can be written as:
f(t) = 4¹¹ × (t²)⁻²√₁
Now, using the power rule and the chain rule, we get:
f'(t) = -8 × t × (t²)⁻³√₁
f'(2) = -8 × 2 × (2²)⁻³√₁
f'(2) = -1.14 (rounded to three significant digits after the decimal place)
Therefore, the value of f'(2) in decimal form with three significant digits after the decimal place is -1.14.

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a computer system is modeled as a m/m/1 queue. the expected inter-arrival time is 50 msec and the expected service time is 45 msec. calculate the following measures of system performance:

Answers

Utilization=  0.90909 or 90.909%

Average number of jobs in the system=10

Average number of jobs in queue = 9.091

End to end response time = 500

Queuing time = 454.545

Probability of 5 or more jobs in the system=0.59049

What is probability?

Probability means possibility of any incident. It is a branch of mathematics which deals with the occurrence of any random event. The value can be  expressed from zero to one. Probability has been introduced in Mathematics to give a  prediction of how likely events are to happen. The meaning of probability is nothing but the extent to which something is likely to happen.

In a M/M/1 model the expected  inter-arrival time is 50 msec and the expected service time is 45 msec.

So the mean rate of arrival (λ) = 1/ 50 = 0.02

The mean service rate(μ) = 1/ 45= 0.022

a) Utilization = λ/μ = 0.02/ 0.022= 0.90909 or 90.909%

b) Average number of jobs in the system= λ/ (μ-λ)

                                                                     = 0.02/(0.022-0.02)

                                                                       = 10

c) Average number of jobs in queue = λ² / (μ(μ-λ))

                                                           = 0.0004/ 0.000044

                                                            = 9.091

d) End to end response time = Average number of time in the system/ arrival rate

                                               = 10/ 0.02

                                              = 500

e) Queuing time = λ/( μ(μ-λ))

                           = 0.02/ 0.000044

                           = 454.545

f) Probability of 5 or more jobs in the system= P(n≥5)= (λ/μ)⁵

                                                                                          = (0.9)⁵

                                                                                         = 0.59049

Hence,

Utilization=  0.90909 or 90.909%

Average number of jobs in the system=10

Average number of jobs in queue = 9.091

End to end response time = 500

Queuing time = 454.545

Probability of 5 or more jobs in the system=0.59049

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Correct question is "a computer system is modeled as a m/m/1 queue. the expected inter-arrival time is 50 msec and the expected service time is 45 msec. calculate the following measures of system performance:

UtilizationAverage number of jobs in the systemAverage number of jobs in queue End to end response time Queuing time Probability of 5 or more jobs in the system."

If you have a short position in a bond futures contract, you expect that bond prices will ________. Question 16 options: 1) Rise 2) Fall 3) not change 4) fluctuate

Answers

If you have a short position in a bond futures contract, you expect that bond prices will fall.

This is because when you have a short position in a bond futures contract, you are essentially betting that the price of the underlying bond will decrease over time.

As bond prices fall, the value of the bond futures contract will also decrease, allowing you to buy it back at a lower price and pocket the difference as profit.Bond prices are affected by a number of factors, including interest rates, inflation expectations, and market demand. When interest rates rise, bond prices tend to fall, as investors demand higher yields to compensate for the increased risk. Similarly, when inflation expectations rise, bond prices tend to fall, as investors demand higher yields to protect against the eroding value of their investment.In general, bond prices and bond futures contracts tend to move in opposite directions. When bond prices rise, the value of a short position in a bond futures contract will decrease, and vice versa. This relationship allows investors to hedge against fluctuations in bond prices by taking opposite positions in the bond market and the futures market.

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Evaluate the function at the specified points.

f(x,y)=x+yx^5, (-1,-3),(-2,4),(2,-2)

At (-1,-3):

At (-2,4):

At (2,-2):

Answers

In each case, we evaluated the function by substituting the given values of x and y into the formula for f(x,y).

At (-1,-3):

f(x,y) = x + yx^5

f(-1,-3) = (-1) + (-3)(-1)^5 = -2

At (-2,4):

f(x,y) = x + yx^5

f(-2,4) = (-2) + (4)(-2)^5 = -126

At (2,-2):

f(x,y) = x + yx^5

f(2,-2) = (2) + (-2)(2)^5 = -30

For example, when evaluating f(-1,-3), we substituted x = -1 and y = -3 into the formula to get f(-1,-3) = (-1) + (-3)(-1)^5 = -2. Similarly, for f(-2,4), we substituted x = -2 and y = 4 into the formula to get f(-2,4) = (-2) + (4)(-2)^5 = -126. Finally, for f(2,-2), we substituted x = 2 and y = -2 into the formula to get f(2,-2) = (2) + (-2)(2)^5 = -30.

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a convention manager finds that she has $1320, made up of twenties and fifties. she has a total of 48 bills. how many fifty-dollar bills does the manager have?

Answers

The required manager has 12 fifty-dollar bills as of the given condition.

Let's denote the number of twenty-dollar bills as "x" and the number of fifty-dollar bills as "y".

We know that the convention manager has a total of 48 bills, so:
x + y = 48

We also know that the total amount of money she has is $1320, which can be expressed as:
20x + 50y = 1320

To solve for "y", we can rearrange the first equation to get:
y = 48 - x

Then substitute this expression for "y" in the second equation:

20x + 50(48 - x) = 1320

Expanding the expression and simplifying:
20x + 2400 - 50x = 1320
-30x = -1080
x = 36

So the manager has 36 twenty-dollar bills. To find the number of fifty-dollar bills, we can use the first equation:

x + y = 48

36 + y = 48

y = 12

Therefore, the manager has 12 fifty-dollar bills.

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find the inverse function of f
f(x)=1/2x+7

Answers

To find the inverse function of f(x) = (1/2)x + 7, we can follow these steps:

Step 1: Replace f(x) with y. This gives us:
y = (1/2)x + 7

Step 2: Swap the x and y variables to obtain:
x = (1/2)y + 7

Step 3: Solve for y in terms of x:
x - 7 = (1/2)y
2(x - 7) = y

Step 4: Replace y with f^(-1)(x) to obtain the inverse function:
f^(-1)(x) = 2(x - 7)

Therefore, the inverse function of f(x) = (1/2)x + 7 is f^(-1)(x) = 2(x - 7).

Find the curve y=f(x) in the xy-plane that passes through the point (9,4) and whose slope at each point is 3 √(x)?

Answers

The curve is given by f(x) = 2x^(3/2) - 14, which passes through (9, 4) and has a slope of 3√(x) at each point.

To find the curve y=f(x) in the xy-plane that passes through a given point and has a given slope at each point, we need to integrate the slope function to get the formula for f(x) and use the initial point to determine the value of the constant of integration.

The slope of the curve at each point is given by 3√(x). This means that df/dx = 3√(x), where f(x) is the desired function. Integrating both sides with respect to x gives:

f(x) = 2x^3/2 + C

where C is the constant of integration.

To determine the value of C, we use the fact that the curve passes through the point (9, 4). Substituting x=9 and y=4 into the equation for f(x), we get:

4 = 2(9)^3/2 + C

Simplifying this equation gives C = -14.

Therefore, the curve y=f(x) that passes through the point (9, 4) and has a slope of 3√(x) at each point is given by:

f(x) = 2x^3/2 - 14

This curve passes through points (9,4) and has a slope of 3√(x) at each point, as desired.

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The table shows a proportional relationship.
X1 23
y 16 32 48
Write an equation that represents the proportional relationship.

Answers

The equation that represents the proportional relationship is y = 16x.

To find the equation that represents the proportional relationship, we need to determine the constant ratio between the values of x and y.

Let's observe the given values:

x: 1 2 3

y: 16 32 48

We can see that when x increases by 1, y increases by 16. This means that the constant ratio between x and y is 16.

To write the equation representing this proportional relationship, we can use the formula:

y = kx

Where:

y represents the dependent variable (in this case, the y-values)

x represents the independent variable (in this case, the x-values)

k represents the constant of proportionality (the ratio between x and y)

Substituting the values into the equation:

y = 16x

Therefore, the equation that represents the proportional relationship is y = 16x.

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Of the smoothies sold yesterday at Robert's Smoothies Shop, 5/12 were banana and another 5/12 were strawberry. What fraction of the smoothies sold were either banana or strawberry?

Answers

the answer should be 10/12

7. answer the following questions. (a) find the values of k for which the matrix a = 1 2 k k 1 2 2 1 k is singular

Answers

To find the values of k for which the matrix a is singular, we need to determine when the determinant of a is equal to 0.

The determinant of a 2x2 matrix is simply the product of the diagonal elements minus the product of the off-diagonal elements. For a 3x3 matrix like a, we need to use a more complex formula:

det(a) = 1*(2*2 - k*1) - 2*(1*2 - k*1) + k*(1*2 - 2*k)

Simplifying this expression, we get:

det(a) = 4 - 2k - 4 + 2k + 2k²
det(a) = 2k²

So, det(a) is equal to 0 when k is equal to 0 or when k is equal to 0. Therefore, the matrix a is singular when k is equal to 0.

Explanation: To determine when a matrix is singular, we need to find when its determinant is equal to 0. We used the formula for the determinant of a 3x3 matrix to calculate the determinant of a and then solved for the values of k that make det(a) equal to 0.

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a wellness director at a company in new york city wants to investigate whether it is unusual for one person working in the city who wears an activity tracker to record approximately 8,500 steps on a typical workday. is it appropriate to use the confidence interval found in part (a) to conduct the investigation? explain your answer.

Answers

a) The (9,009, 10,585) range represents the 99% confidence interval for the mean number of steps taken on an average workday for all New York City employees who wear activity trackers. No, we are unable to determine the likelihood of specific values using the confidence interval. Only inferences about the population mean can be drawn from it.

A 99% confidence interval for the mean needs to be calculated.

Since the population standard deviation is unknown, we must infer it from the sample standard deviation in order to get the critical number using a t-students distribution.

Sample Mean(M) = 9,797

Sample Standard Deviation(s) = 2,313.

Sample Size(N) = 61

When σ is unknown, an estimation of σM is made by dividing s by the square root of N:

S = s/√n

S = 2313/√61

S = 2313/7.8102

S = 296.1512

These sample size's degrees of freedom are:

df = n - 1

df = 61 - 1

df = 60

With 61 degrees of freedom and a 99% confidence interval, the t-value is 2.66.

The Margin of Error calculated as:

MOE = t × S

MOE = 2.66 × 296.1512

MOE = 787.7622

The confidence interval's lower and upper bounds are as follows:

Lower Bound = M - MOE

Lower Bound = 9797 - 787.7622

Lower Bound = 9,009.2378

Lower Bound = 9,009(approx)

Upper Bound = M + MOE

Upper Bound = 9797 + 787.7622

Upper Bound = 10,584.7622

Upper Bound = 10,585(approx)

We have a 95% confidence interval between 9,009 and 10,585 steps as the mean number of steps taken on a normal workday for all New York City employees using activity trackers.

b) The value of 8,500 steps is outside the confidence interval, which indicates that it is a high figure for the average number of steps taken by all New Yorkers using activity trackers.

The confidence interval cannot be used to calculate the likelihood of specific values.

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The complete question is:

Activity trackers are electronic devices that people wear to record physical activity. Researchers wanted to estimate the mean number of steps taken on a typical workday for people working in New York City who wear such trackers. A random sample of 61 people working in New York City who wear an activity tracker was selected. The number of steps taken on a typical workday for each person in the sample was recorded. The mean was 9,797 steps and the standard deviation was 2,313 steps.

a. Construct and interpret a 99 percent confidence interval for the mean number of steps taken on a typical workday for all people working in New York City who wear an activity tracker.

b. A wellness director at a company in New York City wants to investigate whether it is unusual for one person working in the city who wears an activity tracker to record approximately 8,500 steps on a typical workday. Is it appropriate to use the confidence interval found in part (a) to conduct the investigation.

Suppose 128 ounces of a radioactive substance exponentially decays to 28 ounces in hours. What is the half-life of the substance? The half-life is: (A) Less than 1 hour (B) Between 1 hour and 2 hours (C) Between 2 hours and 3 hours (D) Between 3 hours and 4 hours (E) Greater than 4 hours

Answers

The required half-life of the substance is 1 hour and 2 hours.

To determine the half-life of a substance undergoing exponential decay, we can use the formula:

[tex]N = N₀ * (1/2)^{(t / h)}[/tex]

where:

N is the remaining amount of the substance,

N₀ is the initial amount of the substance,

t is the time that has elapsed, and

h is the half-life of the substance.

In this case, we know that N₀ = 128 ounces and N = 28 ounces after a certain number of hours. Plugging in these values, we get:

[tex]28 = 128 * (1/2)^{(t / h)}[/tex]

We can rearrange this equation to solve for t / h:

[tex](1/2)^{(t / h) }= 28 / 128.[/tex]

Taking the logarithm of both sides with base 1/2, we have:

[tex]log₂((1/2)^{(t / h))} = log₂(28 / 128).[/tex]

Applying the logarithmic identity, we can bring the exponent down:

(t / h) * log₂(1/2) = log₂(28 / 128).

Simplifying further, we know that log₂(1/2) is -1:

-(t / h) = log₂(28 / 128).

Multiplying both sides by -1, we have:

t / h = -log₂(28 / 128).

Using a calculator, we find that -log₂(28 / 128) is approximately 1.609.

Therefore, t / h ≈ 1.609.

Since t is the time elapsed and h is the half-life, t / h represents the number of half-lives that have occurred. If t / h is approximately 1.609, it means that around 1.609 half-lives have passed.

Now we can determine the possible options for the half-life based on the given choices:

(A) Less than 1 hour: This would mean the half-life is less than 1 hour. However, 1.609 is greater than 1, so this option can be eliminated.

(B) Between 1 hour and 2 hours: This option is a possibility, as 1.609 is between 1 and 2.

(C) Between 2 hours and 3 hours: This option is not possible since 1.609 is less than 2.

(D) Between 3 hours and 4 hours: This option is not possible either since 1.609 is less than 3.

(E) Greater than 4 hours: This option is also not possible as 1.609 is less than 4.

Based on the analysis, the correct answer is (B) Between 1 hour and 2 hours.

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A sample of adults was asked to choose their favorite sport to watch from a list of four sports. Age Range 18-30 31-50 51 Total Sport Football 15 19 17 51 Baseball 7 12 18 37 Basketball 15 8 11 34 Soccer 12 9 6 27 Total 49 48 52 149 What proportion of those surveyed chose basketball as their favorite sport? StartFraction 34 Over 149 EndFraction StartFraction 15 Over 49 EndFraction StartFraction 18 Over 52 EndFraction StartFraction 37 Over 149 EndFraction

Answers

The proportion of those surveyed who chose basketball as their favorite sport is 34.149 (option a)

Let's denote the proportion of adults who chose basketball as their favorite sport as P(Basketball). To calculate P(Basketball), we need to divide the total number of adults who chose basketball by the total number of surveyed adults. Mathematically, it can be represented as:

P(Basketball) = (Number of adults who chose basketball) / (Total number of surveyed adults)

To calculate the number of adults who chose basketball, we sum up the values from the age range categories:

Number of adults who chose basketball = Number of adults (18-30) who chose basketball + Number of adults (31-50) who chose basketball + Number of adults (51 and above) who chose basketball

Looking at the table, we find that the number of adults (18-30) who chose basketball is 15, the number of adults (31-50) who chose basketball is 8, and the number of adults (51 and above) who chose basketball is 11. Adding these values together, we get:

Number of adults who chose basketball = 15 + 8 + 11 = 34

Now, let's calculate the total number of surveyed adults. We can sum up the values from the age range categories:

Total number of surveyed adults = Total number of adults (18-30) + Total number of adults (31-50) + Total number of adults (51 and above)

From the table, we find that the total number of adults (18-30) is 49, the total number of adults (31-50) is 48, and the total number of adults (51 and above) is 52. Adding these values together, we get:

Total number of surveyed adults = 49 + 48 + 52 = 149

Now, we have the values we need to calculate the proportion:

P(Basketball) = (Number of adults who chose basketball) / (Total number of surveyed adults)

= 34 / 149

Hence the correct option is (a).

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Based on the figure below, what is the value of x? A right angle is shown divided in two parts. The measure of the angle of one part is 30 degrees and the measure of the other part is 5x plus 15 degrees. a3 b9 c12 d15

Answers

The value of x is 9. Thus, the correct answer choice is (b) 9.

We know that the sum of the angles in a right angle is 90 degrees.

One part of the angle measures 30 degrees, and the other part measures 5x + 15 degrees.

So, we can write the equation:

30 + 5x + 15 = 90

5x + 45 = 90

5x = 90 - 45

5x = 45

x = 9

Thus, the correct answer choice is (b) 9.

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PLS HELP ASAP I WILL GIVE 50 POINTS AND BRAINIEST IM DESPERATE !!!!
Explain how you would find the area of the shape below.

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Answer:

An area is calculated by multiplying the length of a shape by its width

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Step-by-step explanation:

For consumption smoothers, the marginal propensity to consume out of anticipated changes in income is: 1. always close to 1. 2. negative. 3. zero. 4. one.

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For consumption smoothers, the marginal propensity to consume out of anticipated changes in income is one. Option 4 is answer.

Consumption smoothers are individuals who smooth out their consumption patterns in the face of anticipated changes in income. In other words, they tend to spend a smaller portion of any additional income than those who do not smooth their consumption. Therefore, the marginal propensity to consume out of anticipated changes in income is one, meaning that for every additional unit of anticipated income, consumption increases by one unit. Option 4 is the correct answer.

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The average number of miles (in thousands) that a car's tire will function before needing replacement is 65 and the standard deviation is 17. Suppose that 50 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. b. What is the distribution of ¯xx¯? ¯xx¯~ N( ? ), (?) c. If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 67.4 and 69.6? d. For the 50 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 67.4 and 69.6 ?

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A standard normal distribution table or a calculator that can perform the calculations based on the given z-scores.

To solve these problems, we'll use the properties of the normal distribution. Let's go through each question step by step:

b. What is the distribution of ¯xx¯? ¯xx¯~ N( ? ), (?)

The average of a sample follows a normal distribution with the same mean as the population and a standard deviation equal to the population standard deviation divided by the square root of the sample size. In this case, the population mean is 65, and the population standard deviation is 17. Since we have 50 randomly selected tires, the sample size is 50.

Therefore, the distribution of the sample mean ¯xx¯ is ¯xx¯~N(65, 17/√50).

c. If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 67.4 and 69.6?

To find this probability, we need to standardize the values using the z-score formula:

z = (x - μ) / σ

where x is the value we're interested in, μ is the population mean, and σ is the population standard deviation.

For 67.4:

z1 = (67.4 - 65) / 17

For 69.6:

z2 = (69.6 - 65) / 17

We can now use these z-scores to find the probabilities associated with the values using a standard normal distribution table or a calculator. The probability will be the difference between the two probabilities:

P(67.4 ≤ x ≤ 69.6) = P(z1 ≤ Z ≤ z2)

d. For the 50 tires tested, find the probability that the average miles (in thousands) before the need for replacement is between 67.4 and 69.6?

Since we're dealing with the average of the sample, we use the distribution ¯xx¯~N(65, 17/√50) as calculated in part b.

Again, we'll use the z-score formula to standardize the values:

z1 = (67.4 - 65) / (17 / √50)

z2 = (69.6 - 65) / (17 / √50)

Using these z-scores, we can find the probability:

P(67.4 ≤ ¯xx¯ ≤ 69.6) = P(z1 ≤ Z ≤ z2)

Please note that to obtain the precise probabilities, we would need to use a standard normal distribution table or a calculator that can perform the calculations based on the given z-scores.

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find the common difference of the arithmetic sequence -15,-13,-11, …

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Answer:

2

Step-by-step explanation:

In an arithmetic sequence, the common difference refers to the constant amount added or subtracted between consecutive terms. To find the common difference, we can subtract any term from the following term.

Let's subtract the second term (-13) from the first term (-15):

-13 - (-15) = -13 + 15 = 2

So, the common difference in the arithmetic sequence -15, -13, -11, ... is 2.

A car was valued at $38,000 in the year 2007. By 2013, the value had depreciated to $11,000 If the car’s value continues to drop by the same percentage, what will it be worth by 2017?

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The value of the car in the year 2017 will be $4973.

Given that a car's value is decreasing, it had a value of $38,000 in the year 2007.

By 2013, the value had depreciated to $11,000.

The car’s value continues to drop by the same percentage, we need to find the price of the car in year 2017.

So, 2013-2007 = 6 years

Using the exponential decay formula,

P = P₀(1-r)ⁿ

11000 = 38000(1-r)⁶

0.29 = (1-r)⁶

Taking log to both sides,

㏒(0.29) = 6 ㏒(1-r)

-0.53 / 6 = ㏒(1-r)

-0.089 = ㏒(1-r)

r = 18%

Now, 2017 - 2013 = 4

So,

P = 11000(1-0.18)⁴

P = 4973.33

Hence the value of the car in the year 2017 will be $4973.

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congratulations! you have been selected as a contestant on a televised game show, and you have a chance to win the car of your dreams, hidden behind one of three doors, a, b, and c, but only if you can guess the correct door. after you choose door c, the host opens door b and shows you that there is no car behind that door. now what is your probability that the car is behind door c? what assumptions are you making to reach that judgment? would you make those same assumptions if you were actually on the game show and competing for the car?

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The probability that the car is behind door C given that the host opened door B and revealed that there is no car behind it is 2/3.

In this classic scenario known as the Monty Hall problem, you initially had a 1 in 3 chance of choosing the door with the car behind it. Let's call this event A. The probability of event A is P(A) = 1/3.

After you chose door C, the host opened door B and revealed that it did not have the car behind it. Let's call this event B. The probability of event B, given that the car is not behind door C, is P(B|not C) = 1.

We are interested in the probability of the car being behind door C, given that door B was opened and revealed to not have the car behind it. Let's call this event C. We want to calculate P(C|B).

To solve the problem, we can use Bayes' theorem, which states that:

P(C|B) = P(B|C) * P(C) / P(B)

where P(B|C) is the probability of observing event B given that the car is behind door C, P(C) is the prior probability of the car being behind door C before any information is revealed, and P(B) is the probability of observing event B (i.e., the host opening door B) regardless of which door the car is behind.

Using the Law of Total Probability, we can calculate P(B) as:

P(B) = P(B|A) * P(A) + P(B|not A) * P(not A)

where P(B|A) is the probability of observing event B given that the car is behind door A, P(not A) is the probability that the car is not behind door A, and P(B|not A) is the probability of observing event B given that the car is not behind door A.

Since we know that the host opened door B and revealed that there is no car behind it, we can simplify the expression for P(B) to:

P(B) = P(B|A) * P(A) + P(B|not A) * P(not A|B)

where P(not A|B) is the probability that the car is not behind door A given that the host opened door B and revealed that there is no car behind it. We can calculate P(not A|B) using Bayes' theorem:

P(not A|B) = P(B|not A) * P(not A) / P(B)

Now we can substitute these values into the expression for P(C|B):

P(C|B) = P(B|C) * P(C) / P(B)

where P(B|C) is the probability of observing event B given that the car is behind door C. In this case, the host cannot open door C to reveal the car, so P(B|C) = 1.

P(C) is the prior probability of the car being behind door C before any information is revealed. Initially, this probability was 1/3, since there were three doors and only one car. So P(C) = 1/3.

We have already calculated P(B), which is the probability of observing event B regardless of which door the car is behind. We found that:

P(B) = P(B|A) * P(A) + P(B|not A) * P(not A|B)

where P(A) is the probability that the car is behind door A, which is also 1/3, and P(not A|B) is the probability that the car is not behind door A given that the host opened door B and revealed that there is no car behind it.

Using Bayes' theorem, we found that:

P(not A|B) = P(B|not A) * P(not A) / P(B)

We can calculate P(B|not A) as follows:

P(B|not A) = P(B and not A) / P(not A)

Since the host will always open a door with no car behind it, we know that P(B and not A) = 1/2, since there are two remaining doors after you choose door C. Therefore:

P(B|not A) = (1/2) / (2/3) = 1/3

Substituting these values into the expression for P(not A|B), we get:

P(not A|B) = (1/3) * (2/3) / P(B)

Substituting P(B|C) = 1, P(C) = 1/3, and the above expression for P(not A|B) into the expression for P(C|B), we get:

P(C|B) = (1 * 1/3) / ((1/3)(1) + (1/3)(1/3)*(2/3)) = 2/3

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Carol is comparing two rectangular tiles for a flooring project. The blue tile is 8 centimeters long and 6 centimeters wide. The yellow tile is yo millimeters long and 68 millimeters wide. Which tile covers the greater area? How much greater is the area?

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The area of the yellow tile is 0.28 cm² greater than the area of the blue tile.

To compare the areas covered by the blue and yellow tiles, we need to convert the measurements to the same units. Let's convert the measurements for the yellow tile from millimeters to centimeters, since the measurements for the blue tile are in centimeters.

To convert millimeters to centimeters, we divide by 10:

Length of yellow tile: y/10 cm (where y is the length in millimeters)

Width of yellow tile: 6.8 cm (since 68 mm = 6.8 cm)

Now we can calculate the areas of each tile:

Area of blue tile: 8 cm x 6 cm = 48 cm²

Area of yellow tile: (y/10 cm) x 6.8 cm = (0.68y) cm²

To compare the areas, we can set up an inequality:

0.68y > 48

Solving for y:

y > 48/0.68 = 70.59

So the yellow tile must be longer than 70.59 millimeters to cover a greater area than the blue tile.

To find how much greater the area is, we can substitute y = 71 (rounding up from 70.59) into the equation for the area of the yellow tile:

Area of yellow tile = (71/10 cm) x 6.8 cm = 48.28 cm²

The area of the yellow tile is 48.28 cm² - 48 cm² = 0.28 cm² greater than the area of the blue tile.

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A teacher wishes to divide her class of twenty students into four groups, each of which will have three boys and two girls. How many possible groups can she form?

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There are 21,600 possible groups that the teacher can form.

What is Combinations:

Combinations is a method of counting the number of ways to select a specific number of items from a larger set without regard to their order.

Specifically, the problem involves finding the number of ways to select three boys and two girls from a group of twenty students.

C(20, 3) * C(17, 2)

Here we have

A teacher wishes to divide her class of twenty students into four groups, each of which will have three boys and two girls.

Assume that there are two equal number of boys and girls

Now we need to choose 3 boys out of 10 and 2 girls out of 10 for each group, as there are 10 boys and 10 girls in the class.

We can do this in the following way:

Number of ways to choose 3 boys out of 10 = C(10,3) = 120

Number of ways to choose 2 girls out of 10 = C(10,2) = 45

Hence,

The number of ways to form a group of 3 boys and 2 girls

= 120 × 45 = 5400

Since we need to form 4 such groups,

The total number of possible groups that the teacher can form is:

=> 4 × 5400 = 21600

Therefore,  

There are 21,600 possible groups that the teacher can form.

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A boy earned 75cedis. He saved 20cedis and used the rest of the amount to buy text books. How much was each text book if he bought 11 text books

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Each text book cost 5cedis for the amount.

The word "amount" refers to a thing's quantity or sum. It is a blanket phrase that can be used to many different dimensions or amounts. The precise meaning of "amount" depends on the context in which it is used. It can be used to describe a numerical value, such as the volume of liquid in a container, the balance in a bank account, or the duration of an activity. It can also be used to indicate an elusive number, such the degree of someone's enjoyment or worry. In general, the word "amount" communicates the sense of measuring or quantifying a specific thing or quality.

If the boy earned 75cedis and saved 20cedis, then he used 75-20=<<75-20=55>>55cedis to buy text books.

To find the price of each text book, we need to divide the total amount spent on text books by the number of text books bought.

Total amount spent on text books = 55cedis
Number of text books bought = 11
Price of each text book = Total amount spent on text books / Number of text books bought

Price of each text book = 55cedis / 11

Price of each text book = 5cedis

Therefore, each text book cost 5cedis.


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Marked price 816 selling price 800 what is the discount

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Step-by-step explanation:

Price is 16 off of 816   ..... 16 is what percent of 816 ?

16/ 816  * 100% = ~ 1.961 %

Suppose you want to test the claim that μ>25.6. Given a sample size of n=51 and a level of significance of a=0.01, when should you reject H0?A) Reject H0 if the standardized test statistic is greater than 1.645.B) Reject H0 if the standardized test statistic is greater than 2.33.C) Reject H0 if the standardized test statistic is greater than 2.575.D) Reject H0 if the standardized test statistic is greater than 1.28

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When testing the claim that μ > 25.6 with a sample size of n=51 and a level of significance of α=0.01, you should reject H₀ if the standardized test statistic is greater than the critical value.

To determine when to reject H₀ (the null hypothesis that μ=25.6), we need to calculate the standardized test statistic using the sample size (n=51) and level of significance (a=0.01).The appropriate critical value for a one-tailed test at a 0.01 level of significance is 2.33. Therefore, we should reject H₀ if the standardized test statistic is greater than 2.33.The formula for calculating the standardized test statistic is: [tex]$\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}}}$[/tex], where [tex]$\bar{x}$[/tex] is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.

With a sample size of 51, we can use the Central Limit Theorem to assume that the sample mean is normally distributed. We would calculate the standardized test statistic and compare it to the critical value of 2.33 to determine whether or not to reject H₀. In this case, the critical value can be found using a Z-table or calculator for a one-tailed test with α=0.01. The critical value is 2.33. Therefore, you should reject H₀ if the standardized test statistic is greater than 2.33.

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