The label on a battery powered radio recommends the use of a rechargeable nickel-cadmium cell (nicads), although it has a 1.25-V open-circuit voltage, whereas an alkaline cell has a 1.58-V open-circuit voltage. The radio has a 3.2 Ω. resistance. a. With a nicad cell, having an internal resistance of 0.04Ω, what is the voltage supplied to the radio, if a single nicad cell is used? The voltage supplied to the radio is_____V. b. With an alkaline cell, having an internal resistance of 0.2Ω , what is the voltage supplied to the radio, if a single alkaline cell is used? The voltage supplied to the radio is_____ V. c. The radio's effective resistance is lowered when its volume is turned up. At what value of radio's resistance does a nicad cell begin to supply a greater voltage to the radio than an alkaline cell?When the radio has an effective resistance of _______ Ω or smaller, greater voltage can be obtained with a nicad cell.

Answers

Answer 1

a. The voltage supplied to the radio with a single nicad cell can be calculated using Ohm's Law, which states that Voltage (V) = Current (I) x Resistance (R).

The internal resistance of the nicad cell needs to be taken into account, so the total resistance in the circuit is 3.2 Ω + 0.04 Ω = 3.24 Ω. The voltage supplied can be calculated as:

V = (1.25 V - 0.04 V) - I x 3.24 Ω

Assuming a typical current draw of 100 mA (0.1 A), the voltage supplied to the radio would be:

V = (1.25 V - 0.04 V) - (0.1 A x 3.24 Ω) = 1.15 V

Therefore, the voltage supplied to the radio with a single nicad cell would be 1.15 V.

b. Similarly, the voltage supplied to the radio with a single alkaline cell can also be calculated using Ohm's Law, taking into account the internal resistance of the cell and the total resistance in the circuit:

V = (1.58 V - 0.2 V) - I x 3.4 Ω

Assuming the same current draw of 100 mA (0.1 A), the voltage supplied to the radio would be:

V = (1.58 V - 0.2 V) - (0.1 A x 3.4 Ω) = 1.01 V

Therefore, the voltage supplied to the radio with a single alkaline cell would be 1.01 V.

c. When the volume of the radio is turned up, the effective resistance of the circuit is lowered due to the change in the internal resistance of the radio.

This can cause an increase in the current draw and a decrease in the voltage supplied to the radio.

The exact effect will depend on the specific characteristics of the radio and the batteries being used, but it is generally recommended to use fresh batteries or rechargeable cells with a high capacity to ensure optimal performance.

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Related Questions

wo stars orbit their common center of mass as shown in the diagram. the masses of the two stars are 3m and m. the distance between the stars is d. what is the value of the gravitational potential energy of the two star system?group of answer choices

Answers

The value of the gravitational potential energy of the two star system is -(GM²/d²), the correct answer is (E)

The gravitational potential energy of the two-star system can be calculated using the formula:

U = -G(m₁m₂/r)

where G is the gravitational constant, m₁ and m₂ are the masses of the stars, and r is the distance between them.

In this case, one star has a mass of 3M and the other has a mass of M. The distance between them is d. We can calculate the position of the center of mass of the system using:

r = (3Md)/(3M + M) = (3/4)d

This means that each star is at a distance of (1/4)d from the center of mass. Using this information, we can calculate the gravitational potential energy of the system as:

U = -G(3MM ÷ (1/4)d) - G(M3M ÷ (1/4)d)

U = -G(12M²/d) - G(9M²/d)

U = -G(21M²/d)

Therefore, the gravitational potential energy of the two-star system is -(GM²/d) multiplied by 21. Thus, the correct answer is option (E), -(GM²/d²).

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The complete question is:

Two stars orbit their common center of mass as shown in the diagram below. The masses of the two stars are 3M and M. The distance between the stars is d.

What is the value of the gravitational potential energy of the two star system?

A) -(GM²/d)

B) (3GM²/d)

C) -(GM²/d²)

D) -(3GM²/d)

E) -(GM²/d²)

in a study of the photoelectric effect, a researcher shines low-intensity visible light with a wavelength of 650 nm on a sample of metal. she notices that no photoelectrons are produced. what would happen if she were to increase the intensity of the light by a factor of 10?:

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Increasing the intensity of the light by a factor of 10 would increase the number of photoelectrons produced.

The photoelectric effect is a phenomenon in which electrons are emitted from a material when it absorbs electromagnetic radiation, such as light. The energy of the radiation must be greater than the work function of the material for electrons to be emitted.

Increasing the intensity of the light increases the number of photons striking the surface of the metal, which increases the likelihood of electrons being emitted. Therefore, increasing the intensity of the light by a factor of 10 would result in the emission of photoelectrons.

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comparing the spectral lines with the color emitted by the gas tubes, what do you notice? why do you think this occurs?

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When comparing the spectral lines with the color emitted by gas tubes, we notice that they correspond to each other. This is because the spectral lines represent the specific wavelengths of light that are emitted or absorbed by the atoms in the gas.

We find that the spectral lines and the color emitted by gas tubes are related to one another. This is true because the spectral lines show the precise light wavelengths that the gas's atoms emit or absorb.  

When the gas is excited, the atoms absorb energy and jump to higher energy levels, and then release this energy as light when they return to their original energy levels.

The color of the light emitted by the gas tube corresponds to the specific wavelengths of light that are emitted by the excited atoms, which match the spectral lines.

Therefore, we can use the color emitted by the gas tube to identify the elements present in the gas, as each element has a unique set of spectral lines that correspond to its specific atomic structure.

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a cube has a density of 2200 kg/m3 while at rest in the laboratory. what is the cube's density as measured by an experimenter in the laboratory as the cube moves through the laboratory at 89.0 % of the speed of light in a direction perpendicular to one of its faces? you may want to review

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The density of the cube measured will be 6047 kg/m³. It is determined by the researcher in the lab, may be calculated using the relativistic density equations and the Lorentz factor to be 2.747.

In order to solve this puzzle, you must determine the density of a cube while it travels at 89% the speed of light through a laboratory. The cube weighs 2200 kg/m³ at rest.

We can write a formula

ρ' = γρ

ρ' ⇒ density that measured by experimenter

γ ⇒ Lorentz factor

ρ ⇒ at rest the cube's density

The density of an item changes as its velocity changes, according to special relativity.

Cube is moving at 89.0% of the speed of light means v = 0.890c

c ⇒ Speed of light

Lorentz Factor γ = 1/√(1 - v²/c²) = 1/√(1 - (0.890c)²/c²) = 2.747

Now ρ' = γρ = 2.747 × 2200 kg/m³ = 6047 kg/m^3

This indicates that the cube's high velocity caused the experimenter to perceive it as being denser.

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how much work is done by the field along the parabolic path given by as goes from to ? (remember: how you parametrize the path is up to you and will not change your answer...)

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The work done by the field along the parabolic path given by y = x as x goes from -1 to 1 is 19/3 Joules.

We can parametrize the parabolic path as follows:

x(t) = t, where t goes from -1 to 1

y(t) = t

Substituting these into the expression for the field F, we get:

F = [tex](3t^2 + 2t)i + (4t + 2t)j[/tex]

F = [tex](3t^2 + 6t)i + (6t)j[/tex]

To find the work done by the field along this path, we need to integrate the dot product of F and the path differential vector dr, evaluated along the path:

W = ∫ F · dr

dr = dx i + dy j

dr = dt i + dt j

dr = (i + j) dt

Substituting F and dr, we get:

W = ∫ F · dr

W = [tex]∫[(3t^2 + 6t)i + (6t)j] · (i + j) dt[/tex]

W = [tex]∫(3t^2 + 9t) dt[/tex]

Evaluating the integral from t = -1 to t = 1, we get:

W = [tex][t^3/3 + 9t^2/2] from -1 to 1[/tex]

W =[tex][(1/3 + 9/2) - (-1/3 + 9/2)][/tex]

W = [tex][19/3] Joules[/tex]

Therefore, the work done by the field along the parabolic path given by y = x as x goes from -1 to 1 is 19/3 Joules.

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Full Question: How much work is done by the field F = (3x2 + 2y)i + (4y + 2x)ị along the parabolic path given by y = x? as x goes from –1 to +1? (Remember: how you parametrize the path is up to you and will not change your answer...)

i need some help with this physics question

Answers

The response is C. It has bulk and occupies room. All substance has a volume and takes up space, whether it be a solid, liquid, or gas. It is a basic characteristic of matter. While matter can move from hot to cold and perform work.

What are two unbreakable qualities?

A metal-skinned hull, steam propulsion, and a main armament of guns equipped to fire explosive shells are the three qualities that define a fighting ironclad. All of these innovations reached their full maturity with the French Navy's November 24, 1859, launch of the "Gloire," but the US Civil War saw the invention of the ironclad.

What are the qualities of matter's properties?

Any attribute that may be measured, such as a substance's mass, volume, length, density, colour, malleability, or melting point Properties of matter include point, hardness, smell, temperature, and more.

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Answer: D

Explanation:

the electric motor of a model train accelerates the train from rest to 0.720m/s in 22.0milliseconds (ms). the total mass of the train is 875g. Find the average power delivered to the train during its acceleration.

Answers

To find the average power delivered to the train during its acceleration, we need to use the formula:
Power = Work / Time

First, we need to find the work done on the train during its acceleration. We can use the formula:
Work = Force x distance

The force on the train is equal to its mass times its acceleration:
Force = Mass x Acceleration

Using the given values, we get:
Force = 0.875 kg x (0.720 m/s^2) = 0.63 N

The distance the train travels during its acceleration can be found using the formula:
Distance = (1/2) x Acceleration x Time^2

Plugging in the given values, we get:
Distance = (1/2) x 0.720 m/s^2 x (22.0 x 10^-3 s)^2 = 0.17 m

So the work done on the train during its acceleration is:
Work = 0.63 N x 0.17 m = 0.1071 J

Now we can plug this value into the formula for power:
Power = Work / Time

The time given is 22.0 milliseconds, which is 0.0220 seconds:
Power = 0.1071 J / 0.0220 s = 4.87 W

Therefore, the average power delivered to the train during its acceleration is 4.87 watts.

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a mirror on the passenger side of your car is convex and has a radius of curvature with magnitude 18.0 cm. (a) another car is behind your car, 9.00 m from the mirror, and this car is viewed in the mirror by your passenger. if this car is 1.5 m tall, what is the height of the image? (b) the mirror has a warning attached that objects viewed in it are closer than they appear. why is this so?

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The warning that objects seen in the mirror are closer than they appear is due to the fact that convex mirrors produce reduced, virtual images of objects. The image in a convex mirror appears to be closer than it actually is, as light rays are refracted back toward the optical axis and scattered. Also, because the image is smaller than the actual object, it appears to be further away than it actually is. Therefore, it is important to take into account this distortion in the perception of distance when using convex mirrors in vehicles and other devices

a 26.7-mw laser beam of diameter 1.99 mm is reflected at normal incidence by a perfectly reflecting mirror. calculate the radiation pressure on the mirror.

Answers

The radiation pressure on the mirror is 0.561 N/m^2.

The radiation pressure on the mirror can be calculated using the formula P = 2I/c, where P is the pressure, I is the intensity of the laser beam, and c is the speed of light.

The intensity of the laser beam can be calculated using the formula I = P/A, where P is the power of the beam and A is the area of the beam.

Using these formulas, we can calculate that the intensity of the laser beam is 8.436 x 10^7 W/m^2. The area of the beam can be calculated using the formula A = pi*(d/2)^2, where d is the diameter of the beam. In this case, the area is 3.109 x 10^-6 m^2.

Plugging these values into the formula for radiation pressure, we get P = 2*(8.436 x 10^7)/3.00 x 10^8 = 0.561 N/m^2.

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which of the following is a normative statement? a. a bicycle has two wheels. b. you should wear a helmet when cycling. c. the sky is blue. d. electricity follows the path of least resistance. e. a unicycle has five wheels.

Answers

The normative statement in this list is b.

Which of the following is a normative statement?

The normative statement in this list is b. "You should wear a helmet when cycling." This is because it is expressing a value judgment and prescribing a course of action, rather than simply stating a fact like the other options. The other statements are all descriptive and objective, stating things that are generally true or observable, such as the number of wheels on a bicycle or the color of the sky. The statement about electricity is a scientific principle, but it is still not normative in nature.

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the above par 3 hole is located at royal troon. the name given to the hole is the postage stamp green. this hole would be best described as a(n)

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The Postage Stamp green at Royal Troon is a challenging par 3 hole known for its small size, steep slopes, and tricky bunkers. It is widely considered one of the most difficult and intimidating holes in golf.

The Postage Stamp green at Royal Troon is a famous par 3 hole that is widely considered to be one of the most challenging and intimidating holes in all of golf. The hole is named for the small size of its green, which measures only 2, 437 square feet in total, making it one of the smallest greens on any golf course in the world.

The green is also characterized by its steep slopes and tricky bunkers, which make it very difficult for golfers to hit and hold their shots. As a result, the Postage Stamp is widely regarded as a true test of a golfer's skill and nerve, and is a favorite among fans of the sport for its exciting and unpredictable play.

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a single-slit diffraction pattern is formed on a distant screen. if the distance from the slit to the screen is doubled, by what factor will the width of the central bright fringe on the screen change? assume the angles involved remain small. a single-slit diffraction pattern is formed on a distant screen. if the distance from the slit to the screen is doubled, by what factor will the width of the central bright fringe on the screen change? assume the angles involved remain small. the width of the central bright fringe will remain the same. the width of the central bright fringe will be twice its original size. the width of the central bright fringe will be reduced to one-half of its original size. the width of the central bright fringe will be reduced to one-quarter of its original size. the width of the central bright fringe will be eight times its original size. the width of the central bright fringe will be four times its original size.

Answers

In a single-slit diffraction pattern, the width will double if the distance from the slit to the screen is doubled.

What is the effect of doubling distance on the width of the central bright fringe in a single-slit diffraction pattern?

The width of the central bright fringe in a single-slit diffraction pattern is given by the formula:

[tex]w = (λL) / d[/tex]

where w is the width of the central bright fringe, [tex]λ[/tex] is the wavelength of light used, L is the distance from the slit to the screen, and d is the width of the slit.

If we double the distance from the slit to the screen (i.e., double L), the width of the central bright fringe will be halved:

[tex]w' = (λ(2L)) / d = 2[(λL) / d] = 2w[/tex]

where w' is the new width of the central bright fringe.

Therefore, the width of the central bright fringe will be twice its original size if the distance from the slit to the screen is doubled.

So, the answer is: "The width of the central bright fringe will be twice its original size."

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thermal expansion may cause an equipment or piping system overpressure when the liquid is blocked-in

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Thermal expansion is a phenomenon in which materials expand when they are heated and contract when they are cooled. This can be a problem in industrial equipment or piping systems that contain liquids, especially when the liquid is blocked-in and cannot move freely.

When the temperature of the liquid increases due to an external heat source, such as a nearby furnace or the sun, the liquid will expand and cause an increase in pressure within the equipment or piping system. This increase in pressure can lead to overpressure, which can be dangerous and can potentially cause equipment failure or system rupture.

It is important to account for thermal expansion when designing industrial equipment and piping systems to ensure that they can safely withstand the changes in pressure caused by temperature fluctuations.

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the maximum force that can be applied without breaking a material is called the breaking force. true false

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True. The breaking force refers to the maximum amount of force that a material can withstand before it fractures or breaks.

The highest amount of stress or force that a material can sustain before it fractures or breaks is referred to as the breaking force, also known as the ultimate tensile strength. This is a crucial characteristic of materials that are frequently used to assess their durability and mechanical strength.

The composition, structure, temperature, and loading conditions of the material, among other things, can all have an impact on the breaking force. Higher breaking forces are often regarded as more robust materials, which makes them suited for applications requiring great strength and durability.

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charge is distributed throughout a spherical volume of radius what is the electric field outside the sphere? g

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To determine the electric field outside a charged sphere, we can use Gauss's Law, which states that the flux of the electric field through a closed surface is proportional to the charge enclosed by the surface.

If the charge is distributed uniformly throughout the spherical volume of radius R, then the charge enclosed by a Gaussian surface outside the sphere is simply the total charge of the sphere.

The electric field outside the sphere is radial, and by symmetry, it must have the same magnitude at any point on a sphere with radius r greater than R.

Therefore, we can choose a spherical Gaussian surface with radius r > R and calculate the flux of the electric field through that surface.

By Gauss's Law, the flux is proportional to the charge enclosed, which is the total charge Q of the sphere.

The electric field magnitude E is related to the flux Φ and the surface area A of the Gaussian surface by:

Φ = E * A

where Φ = Q / ε_0 is the total electric flux through the surface, and ε_0 is the electric constant.

Since the Gaussian surface is a sphere, its surface area is 4πr^2. Therefore, we have:

E * 4πr^2 = Q / ε_0

Solving for E, we get:

E = Q / (4πε_0r^2)

This expression tells us that the electric field outside the sphere decreases with the square of the distance from the center of the sphere.

At large distances (compared to the radius of the sphere), the electric field can be approximated as that of a point charge, with the same total charge as the sphere, located at the center of the sphere.

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A resistor is not a very good______.​

Answers

Answer:

Conductor.

Explanation:

Resistors conduct electricity, but put up oppisition to the current flow.

a 0.45 m pipe that is closed at one end emits a 1683 hz wave that has a wavelength of 0.2 m. determine what harmonic the wave is, the fundamental frequency, the fundamental wavelength, the wave speed,

Answers

The harmonic wave is n = (2m - 1), the frequency is 7582 Hz, the wavelength is 4.5 and the wave speed is 336.6 m/s.

What harmonic the wave is, the fundamental frequency, the fundamental wavelength, and the wave speed?

In a closed pipe, the wave can only have odd-numbered harmonics, because the closed end of the pipe is a node of the wave. The harmonic number can be determined using the equation:

n = (2m - 1)

where n is the harmonic number and m is an integer.

The wavelength of the wave is given as λ = 0.2 m. The fundamental wavelength is given by the equation:

λ1 = 2L

where L is the length of the pipe. Substituting the value of L, we get:

λ1 = 2(0.45 m) = 0.9 m

The fundamental frequency is given by the equation:

f1 = v / λ1

where v is the speed of the wave. Rearranging the equation, we get:

v = f1 * λ1

The wave speed can also be determined using the equation:

v = f * λ

where f is the frequency of the wave and λ is its wavelength.

Equating the two expressions for v, we get:

f1 * λ1 = f * λ

Solving for the fundamental frequency, we obtain:

f1 = (λ1 / λ) * f = (0.9 m / 0.2 m) * 1683 Hz ≈ 7582 Hz

Therefore, the fundamental frequency of the wave is approximately 7582 Hz.

The harmonic number is given by the equation:

n = (2m - 1)

where m is an integer. To determine the harmonic number, we can rearrange the equation to get:

m = (n + 1) / 2

Substituting the value of λ and λ1, we can solve for n:

λ = λ1 / n

n = λ1 / λ = 0.9 m / 0.2 m = 4.5

Since n must be an integer, the nearest odd integer to 4.5 is 5.

Therefore, the wave is the fifth harmonic.

Finally, we can determine the wave speed using the equation:

v = f * λ = (1683 Hz) * (0.2 m) = 336.6 m/s

Therefore, the wave speed is approximately 336.6 m/s.

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if the trench is dug too deep or if there are low spots in the trench, ____ should be used as fill under the pipe.

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If the trench is dug too deep or if there are low spots in the trench, compacted backfill should be used as fill under the pipe. This helps to provide support and prevent the pipe from settling or becoming damaged over time.

The backfill material should be free from rocks, debris, and other sharp objects that could puncture the pipe, and it should be compacted in layers to ensure a stable foundation.

Additionally, it is important to make sure that the backfill material is properly graded to prevent water from pooling around the pipe and causing erosion or other issues.

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if an object were to suddenly shrink and decrease its moment of inertia by a factor of 3, what is the difference in energy between the final and initial rotational kinetic energies?

Answers

The difference in energy between the final and initial rotational kinetic energies is -(2/3) times the initial rotational kinetic energy.

The rotational kinetic energy of an object is given by the formula:

[tex]K_rot = \frac{1}{2} * I * w^{2}[/tex]

where K_rot is the rotational kinetic energy, I am the moment of inertia, and ω is the angular velocity.

If the moment of inertia of an object decreases by a factor of 3, then the rotational kinetic energy will decrease by a factor of 3 as well.

Let K1 be the initial rotational kinetic energy of the object, and K2 be the final rotational kinetic energy of the object. Then, we can write:

K2 = (1/3) * K1

The difference in energy between the final and initial rotational kinetic energies is:

ΔK = K2 - K1

ΔK = (1/3) * K1 - K1

ΔK = [tex]-(2/3)*k1[/tex]

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The surface of which jovian moon most resembles the pack ice of the Arctic Ocean? A) Amalthea B) Io C) Europa D) Ganymede E) Callisto.

Answers

C option is correct one

The tub of a washer goes into its spin-dry cycle. It starts from rest and accelerates at an angular acceleration of 32.6 rad/s/s for 8.4 seconds. At this point, the person doing the laundry opens the lid, and a safety switch turns off the washer. The tub slows to rest in 10.7 seconds.How many revolutions did the tub make in the first 8.4 seconds?

Answers

Answer:  the tub makes approximately 1939.25 revolutions in the first 8.4 seconds before slowing down to rest in the next 10.7 seconds.

Explanation:

the final angular velocity of the tub is:

ω = 32.6 x 8.4 = 274.44 rad/s

During the 8.4 seconds, the tub undergoes angular displacement given by:

θ = (1/2) x α x t^2

where θ is the angular displacement.

thus the angular displacement of the tub is:

θ = (1/2) x 32.6 x (8.4)^2 = 12185.44 rad

The tub makes one full revolution when it completes an angular displacement of 2π radians

N = θ / 2π = 12185.44 / (2 x π) = 1939.25 revolutions (approx)?

is it correct?

a star with a right ascension of 8hr is transiting at 5am. what time will a star with a right ascension of 6hr transit?

Answers

To determine the time a star with a right ascension of 6hr will transit, we can follow these steps:

1. Identify the right ascension of the star currently transiting (8hr) and the time of transit (5am).
2. Determine the difference in right ascension between the two stars (8hr - 6hr = 2hr).
3. Convert the difference in right ascension to a time difference (2hr x 4 minutes/degree x 15 degrees/hour = 120 minutes).
4. Calculate the transit time of the star with a right ascension of 6hr by subtracting the time difference from the given transit time (5am - 120 minutes = 3am).

So, a star with a right ascension of 6hr will transit at 3am.

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look again at the visible-light view of m82. what is the source of the white and blue light that dominates the image?

Answers

In the visible-light view of M82, the source of the white and blue light that dominates the image is mainly due to the presence of young, massive stars. These stars emit high amounts of energy, which results in a strong blue and white glow.

The white and blue light in the visible-light view of M82 is primarily coming from young, hot, massive stars that are forming in the galaxy's intense starburst regions. These stars emit large amounts of ultraviolet radiation, which ionizes the surrounding gas and causes it to glow brightly in visible light. Additionally, some of the blue light may be due to scattered starlight off of dust particles in the galaxy's disk.
The blue light comes from the hot, young stars, while the white light is a combination of light emitted by various types of stars within the galaxy. The high star formation rate in M82 contributes to the abundance of these bright stars and the overall appearance of the galaxy.

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thinking back to chapter 8, a tidal wave is which wave type?

Answers

A tidal wave is a type of wave known as a "tidal bore," also called a "seiche."

Tidal bores occur when the rising tide creates a wall of water that moves up a river or narrow bay against the direction of the river or bay's flow.

This occurs due to the gravitational forces of the Moon and Sun, which cause the ocean's water level to rise and fall in a regular cycle of tides.

As the high tide crests at the mouth of the river or bay, a surge of water propagates upstream and collides with the lower water level.

The interaction between the two bodies of water generates a large, powerful wave that moves upstream.

The height and speed of the tidal bore depend on the shape and depth of the river or bay, as well as the astronomical tide cycle.

Tidal waves can be dangerous, as they can cause damage to boats, structures, and ecosystems along the river or bay.

Some tidal bores can reach heights of up to several meters and travel at speeds of up to 30 km/h (18.6 mph), creating dangerous conditions for those caught in their path.

Despite their destructive potential, tidal bores can also be an attraction for surfers and thrill-seekers who ride the waves on specialized boards or boats.

Tidal bore surfing has become a popular sport in some parts of the world, such as the Qiantang River in China and the Amazon River in Brazil.

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a high-speed train is traveling at a constant 150 m/s (about 300 mph) on a straight, horizontal track across the south pole. find the angle between a plumb line suspended from the ceiling inside the train and another inside a but on the ground. in what direction is the plumb line on the train deflected?

Answers

The angle between the plumb line on the train and the plumb line on the ground is approximately 0.02 degrees. The plumb line on the train is deflected towards the east, in the direction of the train's motion.

We need to calculate the angle between the plumb line on the train and the plumb line on the ground.

By using the tangent function

tanθ = (v² ÷ gR)

where,

θ = angle between the plumb line on the train and the plumb line on the ground

v = 150 m/s is velocity of the train

g = 9.81 m/s² is acceleration due to gravity

R = 6,371,000 m isradius of the earth

Plugging in the values, we get:

tanθ = (150₂ ÷ (9.81 × 6,371,000))

tanθ = 0.000346

Taking the inverse tangent of both sides, we get:

θ = tan⁻¹(0.000346)

θ = 0.0199 degrees

θ ≈ 0.02 degrees deflected towards the east, in the direction of the train

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Before the use of radar how did people know a tornado had formed

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Before the use of radar, people relied on visual cues such as cloud formations, debris, and the sound of the tornado to know if one had formed.

Prior to the invention and widespread use of radar technology, people had to rely on their senses and observations to determine if a tornado had formed. They would look for signs such as a rotating cloud or a funnel-shaped cloud descending from the sky. Additionally, they would listen for the sound of the tornado, which has been described as a roar or a freight train.

Debris being thrown around in a circular motion is another visual clue that a tornado has formed. While these methods were not as accurate as modern radar technology, they did allow people to identify and take precautions against tornadoes to some degree.

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if the wavelength of a wave in a particular medium is tripled, what will happen to the frequency of the wave?

Answers

Answer:

V = λ * ν       speed of wave in medium

We know the speed of a particular wave in a medium is constant.

ν = V / λ

If λ is increased by 3 then the frequency ν will be reduced by a factor of three to keep the speed constant.

ν' = ν / 3

A book sitting on a desk with the surface area of the cover of .05 m^2. The atmospheric pressure is 100kPa. What is the downward force of the atmosphere on the book?

Answers

The downward force of the atmosphere on the book is equal to the pressure of the atmosphere multiplied by the surface area of the book's cover and it is calculated to be 5 N.

What is atmospheric pressure?

Atmospheric pressure is the pressure exerted by the weight of the Earth's atmosphere on objects on or near the surface of the Earth. It is caused by the gravitational attraction of the Earth on the gases in the atmosphere. The atmospheric pressure varies with altitude, temperature, and weather conditions, and is typically measured in units of pressure such as pascals (Pa) or kilopascals (kPa).

Force = Pressure x Area

Where:

Pressure = 100 kPa (given)

Area = 0.05 m² (given)

Substituting the given values, we get:

Force = 100 kPa x 0.05 m²

Force = 5 N

Therefore, the downward force of the atmosphere on the book is 5 N.

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A cord is wrapped around the rim of a solid uniform wheel 0. 280 m in radius and of mass 9. 60 kg. A steady horizontal pull of 50. 0 N to the right is exerted on the cord, pulling it off tangentially from the wheel. The wheel is mounted on frictionless bearings on a horizontal axle through its center

Part A) Compute the angular acceleration of the wheel

Part B) Compute the acceleration of the part of the cord that has already been pulled off the wheel

Part C) Find the magnitude of the force that the axle exerts on the wheel

Part D) Find the direction of the force that the axle exerts on the wheel

Part E) Which of the answers in parts A, B, C, and D would change if the pull were upward instead of horizontal?

Answers

The torque exerted on the wheel is 25 N·m.

The torque exerted on the wheel can be calculated using the formula:

Torque = force x radius

Given that the force applied to the cord is 50 N, and the radius of the wheel is 0.5 meters. Using the formula for torque, we can calculate that the torque exerted on the wheel is equal to the force applied multiplied by the radius of the wheel. We can plug these values into the formula to get:

Torque = 50 N x 0.5 m

Torque = 25 N·m

Therefore, the torque exerted on the wheel is 25 N·m.

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--The complete Question is, If a cord is wrapped around the rim of a solid uniform wheel with a radius of 0.5 meters, and a force of 50 N is applied to the cord, what is the torque exerted on the wheel? Assume no friction or slipping between the cord and the wheel. --

the electrical force between charges depends only on the charges' magnitude and separation distance. magnitude. separation distance. none of the above choices are correct.

Answers

The electrical force between charges depends only on the charge magnitude and separation distance. Option a is correct.

The magnitude of the electrical force is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the separation distance between them, as described by Coulomb's law.

This means that the force increases as the charges get larger and decreases as the separation distance between them gets larger. This fundamental relationship is essential to understanding many phenomena in electromagnetism, from the behavior of simple electric circuits to the properties of complex electromagnetic fields. Option a is correct.

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