the linear momentum of a bullet-gun system is zero before the gun fires. afterwards: i. the kinetic energy is zero ii. the momentum is zero group of answer choices i & ii i ii neither i nor ii

Answer:

Help with what??

Explanation:

Explanation:

there is no question to answer..

The x ray photons have 885234000 J of energy, and the g-ray photons have an energy of 5.57 x 10^12 J in a total of 1 mol of each of these.

The distance calculated over which a periodic wave's shape repeats itself is known as the wavelength in physics. This wavelength can be described as the space between waves' crests, particularly between electromagnetic or sound wave points.

The distance that any kind of a wave travels between its crests or troughs, it is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave).

Here we have to use the formula

E= hc/λ

To calculate energy of x-ray photons, we have

a) E = [6.626 x 10^(-34) x 3 x 10^8] / 0.135 x 10^(-9)

⇒ E= 1.47 x 10^(-15) J per photon

Using Avogadro's number, the energy calculated per mole can be calculated as

E= 1 mol x 6.022 x 10^23 x 1.47 x 10^-15

E= 885234000 J

Then for the energy of g-ray photons, can be calculated as

b) E = [6.626 x 10^(-34) x 3 x 10^8] / 2.15 x 10^(-14)

E= 9.25 x 10^-12 J per photon

Then using Avogadro's number, we have

E = 1 mol x 6.022 x 10^23 x 9.25 x 10^-12

E = 5.57 x 10^12 J

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The height of the cliff from the rock is thrown with an initial velocity of 8.2 m/s is 56.14 m

The formula for the downward vertical launch and the procedure we will use is:

y = V₀*t + (gt²) /2

Where:

Information about the problem:

With the information gave, we can calculate the height from the rock is thrown, using the formula of downward vertical launch:

y = V₀*t + (gt²) /2

y = (8.2 m/s * 2.65 s) + [9.8 m/s² *  (2.65 s)²] /2

y = (21.73 m) + [9.8 m/s² * 7.0225 s²] /2

y = (21.73 m) + 68.821 m /2

y = 21.73 m + 34.41 m

y = 56.14 m

In physics vertical launch is the motion described by an object that has been launched vertically in which the acceleration is the earth's gravitational force.

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When Tron accelerates vertically upward, traveling 4.50 m in the first 3.00 ms after it is released. Then magnitude of the electric field is E= 3.4893 N/C.

The electric force per unit charge is referred to as the "electric field." It is thought that the field's direction corresponds to the force it would apply to a positive test charge.

The SI unit for the electrical field is volts per meter (V/m). This unit is equivalent to the Newtons per coulomb. Both Newton, which represents for force, and Coulomb, which stands for charge, are the ancestors of these units.

Around a charged object, an electric field is produced that affects the surrounding environment.

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The electric fields is always directed from higher potential to the lower potential.

The electric fields always aiming from the region of higher potential to the region of lower potential. So the force of electrostatic and the direction of the travel of electrons will be always from lower potential to the region of higher potential.

An electric field is defined as the physical field which covers the electrically charged particles and also they can apply force on all other charged particles.

So we can conclude that the electric fields is always directed from higher potential to the lower potential.

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If the motion (or polarity of the magnet) is reversed, the direction of deflection in a galvanometer is also reversed.

An electromechanical device used to measure electric current is a galvanometer. Early galvanometers were not calibrated, but later models, known as ammeters, were, and could measure current flow more precisely.

If the motion (or polarity of the magnet) is reversed, the direction of deflection in a galvanometer is also reversed. This suggests that an emf is produced anytime the magnetic flux connected to a coil changes.

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Answer:

The capacitance of the capacitor with two plates of area 377 cm2377 cm2 each separated by a distance 11.5 cm.11.5 cm in microfarads is 2.90 * 10-16 µF

Explanation:

Capacitance is proportional to the physical size of the plates as indicated by the plate area, A, and inversely proportional to the distance between the plates. The plate separation is denoted as d. Capacitance is also related to the dielectric constant. Farads are used to express it.

Using the formula: C=εoA/d

Where C is capacitance

A is Area

d is distance

εo is the permittivity of free space

εo = 8.854 * 10-12 F/m

A= 377 cm2 =3.77m

d = 11.5 cm2= 0.115m

C= 8.854 * 10-12*3.77m2 /0.115 m2

C=290.26*10-12 F

C= 2.90 * 10-16 µF

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Answer:

a = (v2 - v1) / t

If the velocity is changing but not the magnitude of speed then

the change in velocity is directed perpendicular to the current velocity of the object

(An example is an object undergoing uniform circular motion where the speed of the object around the circle is constant but the change in velocity is always directed toward the center of rotation)

The correct answer is 29883.3m/s

The pace at w.hich an object's position changes in relation to a frame of reference is known as its velocity, which is a time-dependent quantity. The speed and direction of an object's motion are its velocity. The rate at which an object's velocity changes in relation to time is defined as its acceleration.

The following kinematic equation can be used to connect velocity and acceleration:

v_1=v_0+at

Where v_1 denotes the ultimate velocity, v_0 denotes the starting velocity, a denotes the acceleration, and t is the passing of time.

Calculate the length of the Earth's orbit around the Sun to get started. For this issue, a circle rather than an ellipse can be used to represent the Earth's orbit.

Circumference = C=πD=2πR

=2π(1.5×10km)

=9.424π×10^8

Do a dimensional analysis to convert the speed of the Earth around the Sun from miles per hour to metres per second:

s_earth= 9.424π×10^8/1year × (1year×100m×1day×1hour×1min)/(1km×365days×24hours×3600seconds)

=29883.3m/s

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A beaker (glass jar) contains 1 kg of water; when converted to a volume measurement it is the same as: 1,000 ml 1,000 l 1,000 cm 3

Volume of water in ml  = 1000 ml

Volume of water in cm³ =  100cm³

Given that

To find

So, According the question

We have

For convert it in volume, we can follow some simple steps

So, we know

            [tex]= \frac{1}{1000}[/tex]

       volume of water in m³  v = 0.001 m³

   3. Now volume of water in ml = 0.001 × 10⁶ = 1000 ml

   4 . Now volume of water in cm³ = 0.001 × 10⁵ = 100cm³

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The magnitudes of these two vectors could be the same which could be 100 for each.

A vector quantity has both magnitude and direction. Some of the examples of vectors quantities are;

Given that two vectors of fixed magnitude, but variable direction, are added. the result has a minimum magnitude of 0 and a maximum magnitude of 200.

When the two vectors are parallel and move opposite direction to each other, the resultant will be zero. That is,

Resultant vector = 100 - 100 = 0

But when the two vectors are parallel and move in the same direction to each other, the resultant will be 200. That is,

Resultant vector = 100 + 100 = 200

Therefore, the magnitudes of these two vectors could be the same which could be 100 for each.

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In a two-d coordinate system, every vector can be broken down and considered as the x-component and y-component.

A vector quantity has two characteristics, a magnitude and a direction. And these two characteristics are accompanied by two components.

If the vector is V, then these components can be represented as vx and vy.

These vx and vy are the parts of the vector that are generated along the axes of the coordinate plane.

Any vector with a two-dimensional direction can be conceived of as having two distinct parts. A single vector's component specifies how that vector acts in a certain direction.

If the magnitude of the vector is given as a and the direction is given as [tex]\theta[/tex] of a two-dimensional vector, then the components of the vector can be found out using the following formulas:

vx=vcosθ for the x component

and

vy=vsinθ for the y component

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The 'advanced' material that changes shape with an applied voltage is: a. piezoelectric

A piezoelectric material has the ability to transform electrical energy into mechanical energy and mechanical energy into electrical energy and  due to this can change its shape in response to applied voltage.

The piezoelectric materials are natural or synthetic crystals that do not have a defined center of symmetry. Some piezoelectric materials are found naturally as some crystals, ceramics, DNA, enamel and others.

These materials are classified into two groups:

Voltage is the quantity that expresses the amount of electricity that exists in an electrical circuit.

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Answer:

Average speed: approximately [tex]76.9\; {\rm m\cdot s^{-1}}[/tex].

Average velocity: approximately [tex]38.5\; {\rm m \cdot s^{-1}}[/tex] (to the north.)

Explanation:

Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.

In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.

In this question, the path George took required him to travel [tex]750\; {\rm m} + 250\; {\rm m} = 1000\; {\rm m}[/tex] in total. Hence, the distance George travelled would be [tex]1000\; {\rm m}[/tex]. However, since George stopped at a point [tex](750\; {\rm m} - 250\; {\rm m}) = 500\; {\rm m}[/tex] to the north of where he started, his displacement would be only [tex]500\; {\rm m}[/tex] to the north.

Divide total distance by total time to find the average speed.

Divide total displacement by total time to find average velocity.

The total time of travel in this question is [tex]13\; {\rm s}[/tex].. Therefore:

[tex]\begin{aligned}\text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &= \frac{1000\; {\rm m}}{13\; {\rm s}} \\ &\approx 76.9\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

[tex]\begin{aligned}\text{average velocity} &= \frac{\text{total displacement}}{\text{total time}} \\ &= \frac{500\; {\rm m}}{13\; {\rm s}} && \genfrac{}{}{0px}{}{(\text{to the north})}{}\\ &\approx 38.5\; {\rm m\cdot s^{-1}} && (\text{to the north})\end{aligned}[/tex].

Answer:

The sum of the currents entering a junction equals the sum of the currents leaving a junction because no charge is lost.

Explanation:

The law of conservation of charge as proposed by Kirchoff ensures that the sum of currents entering and leaving a circuit are the same. Kirchoff's law asserts that the total current entering a circuit's junction is precisely equal to the total current exiting the same junction for a parallel line. Because no charge is lost, the currents have nowhere else to go. This implies that the algebraic total of ALL currents entering and exiting a junction must equal zero. Kirchoff’s first law is alternatively referred to as the law of conservation of charge.

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The overall efficiency (in %) of the plant is 30% if the steam power plant with a power output of 150 MW consumes coal at a rate of 60 tons/h.

Efficiency is the capacity to achieve something or get the desired outcome without wasting resources, time, money, energy, or effort.

It is given that:

A steam power plant with a power output of 150 MW consumes coal at a rate of 60 tonnes per hour.

As we know,

Thermal efficiency Te = (W/Q)x100

m(coal) = 60 tons/h = 50/3 kg/s

The heating value of the coal is 30,000 kj/k = 30 MJ/kg

Q = (50/3)30

Q = 500 MW

Te = (150/500)100

Te = 30%

Thus, the overall efficiency (in %) of the plant is 30% if the steam power plant with a power output of 150 MW consumes coal at a rate of 60 tons/h.

The question is incomplete.

The complete question is:

A steam power plant with a power output of 150 MW consumes coal at a rate of 60 tonnes per hour. If the heating value of coal is 30,000 KJ/kg, determine the overall efficiency (in %) of the plant.

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The amount of heat this resistor gives in 24 hours and heat fiux q is mathematically given as

Qd=4340.589 W/m^2

Q_t amp;=Q*time

amp;=1.2 *J*(24*3600)

Q_damp=03680J

Q_damp;=103.680

[tex]A_s &=\frac{\pi}{4} d^2 \times 2+\pi d L \\\\A &=\frac{\pi}{4} \times 0.4^2 \times 2+\pi \times 0.4 \times 2[/tex]

A amp;=2.764601 cm^2

[tex]\\\q &=\frac{1.2 \times 104^{+}}{2.764601}=4340.589(\mathrm{~W} / \mathrm{m})[/tex]

qamp;=4340.589mm^2

In conclusion,

Qd=103.680Jq

Qd=4340.589 W/m^2

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At the instant a current of 0.20 a is flowing through a coil of wire, the energy stored in its magnetic field is 6.0 x 10-3 j. The self inductance of the coil will be 0.30 H.

What is self inductance?

An example of electromagnetic induction is the property of self-inductance. The definition of self inductance is something like induction of a voltage in a wire that carries current when the current in the wire is changing. In the instance of self-inductance, the circuit itself induces a voltage through the magnetic field produced by a changing current. The voltage is thus self-induced.

Given,

Current (I) = 0.20 A

Energy (U)= 6.0 x 10⁻³

By the equation,

U = 1/2 (LI²)

L = 2U/I²

Putting the values given in the above equation,

L = 2(6.0 x 10⁻³) / (0.20)²

L = 0.30

Hence, the self inductance in the coil is 0.30 H.

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The rating of the branch-circuit protective device is affected when the conductors used are of a larger size than called for by the code of up the amps and up the AWG.

Branch circuit protection devices are also known as UL 489 circuit breakers.

These devices are tasked to provide protection to all sorts of circuit wiring by keeping in control the amps and AWG.

In addition to this, they also help prevent fire and electric shocks and are also suitable for electrical isolation.

During the maintenance period, they limit the flow of current and also serve as means to cut off the electricity supply.

If large-sized conductors are used then the performance of the branch-circuit protective device may get affected.

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The sound intensity [tex]I_1[/tex] a distance [tex]d_1[/tex] = 15.0 m from a chain saw is 0.280 [tex]W/m^2[/tex]The sound intensity [tex]I_2[/tex] a distance [tex]d_2[/tex] = 32.0 m from the chain saw will be [tex]0.0615W/m^2[/tex].

How to find the sound intensity at the given distance?

To find the sound intensity, following formula is used:

[tex]\frac{I_1}{I_2} =\frac{d_2^2}{d_1^2}[/tex]

We will substitute the numerical values, we get:

[tex]\frac{0.280}{I_2} =\frac{32^2}{15^2} \\I_2=\frac{15^2\times0.280}{32^2} =0.0615W/m^2[/tex]

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(a) Its instantaneous velocity at t = 10.0s is 0.4m/s.

(b) Its instantaneous velocity at t = 30.0s is 0.5 m/s.

(c) Its average velocity between t = 0 and t=5.0s is 0.6 m/s.

(d) Its average velocity between t = 25.0s and t=30.0s is 1.4 m/s.

(e) Its average velocity between t=40.0s and t=50.0s is -1 m/s.

Instantaneous velocity is defined as the velocity of an object under motion at a specific point of time.

at time, t = 10 seconds, x = 4 m

v = 4 m / 10 s = 0.4 m/s

at time, t = 30 seconds, x = 15 m

v = 15 m / 30 s = 0.5 m/s

v(avg) = Δx / Δt

v(avg) = (3 - 0)/(5 - 0) = 0.6 m/s

v(avg) = Δx / Δt

v(avg) = (15 - 8)/(30 - 25) = 1.4 m/s

v(avg) = Δx / Δt

v(avg) = (10 - 20)/(50 - 40) = -1 m/s

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The current motion of HNLC on Oahu compare to the direction of the pacific plate motion relative to the hawaiian hot spot over the past 42 million years is North direction.

Because of plate tectonics now the islands are moving more north compared to before.

The theory of plate tectonics is the modern update to continental drift(opens in new tab), an idea first proposed by scientist Alfred Wegener in 1912 which stated that Earth’s continents had "drifted" across the planet over time. Wegener didn't have an explanation for how continents could move around the planet, but researchers do now: Plate tectonics.

Plate tectonics is the theory that Earth's outer shell is divided into large slabs of solid rock, called “plates,” that glide over Earth's mantle, the rocky inner layer above Earth’s core. Earth’s solid outer layer, which includes the crust and the uppermost mantle, is called the lithosphere.

It is 100 km (60 miles) thick, according to the Encyclopedia Britannica(opens in new tab). Below the lithosphere is the asthenosphere a viscous layer kept malleable by heat deep within the Earth(opens in new tab). It lubricates the undersides of Earth's tectonic plates, allowing the lithosphere to move around.

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Tech B is correct as any coil of wire in an electrical system can produce hundreds of volts when it is de-energized, because of reverse voltage spike.

When there is no load attached and no current flowing, a voltage source (batteries, power supplies, etc.) is said to have an open circuit. It will always be greater than any voltage in a "closed circuit." The output voltage decreases as soon as you start drawing current from the source because of a voltage drop across that resistance.

Back EMF is the term for the reverse voltage spike that results from the coil's magnetic field collapsing when the armature moves away from coil after it has been de-energized (Electromotive Force).

Therefore, Tech B is correct as any coil of wire in an electrical system can produce hundreds of volts when it is de-energized, because of reverse voltage spike.

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Answer:

The acceleration of the ball (excluding air resistance) is

9.80 m/s^2 in the downward direction.

That's all that can be inferred from the problem as it is stated.

Answer:

what graph?

Explanation:

please give the proper information

The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues.

The test is used to measure a student's aerobic capacity as part of the FitnessGram assessment. Students run back and forth as many times as they can, each lap signaled by a beep sound. The test get progressively faster as it continues until the student reaches their max lap score.

The PACER Test score is combined in the FitnessGram software with scores for muscular strength, endurance, flexibility and body composition to determine whether a student is in the Healthy Fitness Zone™ or the Needs Improvement Zone™.

The capacitance of the capacitor varies with time. i'm doubtful if this RC circuit should be called a linear circuit.

According to the definition, a linear circuit obeys principle of superposition . The RC circuit with variable capacitor still obeys principle of superposition at any instant of time.

On the opposite hand, traditional analysis techniques for linear circuits might not be applicable for the analysis of this RC circuit.

A device or system is said to be time-invariant if and only if shifting in time its zero-state response by some constant always results in only shifting in time its zero-state response by that same constant, valid for all time, all possible inputs, and every one possible time shifts.

If the capacitance varies only with time, then that's a linear time-variant capacitor. If the resistance is constant or may be a function of time only, then that's a linear time-invariant or linear time-variant resistor respectively. therefore the RC network is linear time-variant. (It is time-variant due to the capacitor, whether the resistor is time-invariant or time-variant.)

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The mass of silver chloride  be produced from 1.39 ll of a 0.209 mm solution of silver nitrate is 28.3g.

With the chemical formula AgCl, silver chloride is a substance. The poor solubility of this white crystalline solid in water is widely recognised. Silver chloride undergoes a conversion to silver upon lighting or heating, which is shown by the coloring of certain samples changing from grey to black or purple.

used to create alloys, polish mirrors, and electroplate metals. used as a countermeasure that, when combined with the toxin, produces a safe chemical product. utilised in pharmaceuticals, and photographic films employ silver salts.

[tex]2{\rm{AgN}}{{\rm{O}}_3}\left( {aq} \right) + {\rm{CaC}}{{\rm{l}}_2}\left( {aq} \right)\longrightarrow{{}}2{\rm{AgCl}}\left( s \right) + {\rm{Ca}}{\left( {{\rm{N}}{{\rm{O}}_3}} \right)_2}\left( {aq} \right)[/tex]

[tex]\begin{array}{l}\\{\rm{Molarity}} = \frac{{{\rm{Moles}}}}{{{\rm{Volume}}}}\\\\0.209{\rm{ M}} = \frac{{{\rm{Moles}}}}{{1.39{\rm{ L}}}}\\\\{\rm{Moles}} = \left( {0.209{\rm{ mol/L}}} \right)\left( {1.39{\rm{ L}}} \right)\\\\{\rm{ = 0}}{\rm{.198 mol}}\\\end{array}\\[/tex]

[tex]\frac{{\left( {0.198{\rm{ mol AgN}}{{\rm{O}}_3}} \right)\left( {2{\rm{ mol AgCl}}} \right)}}{{\left( {2{\rm{ mol AgN}}{{\rm{O}}_3}} \right)}} = 0.198{\rm{ mol AgCl}}[/tex]

[tex]\begin{array}{l}\\{\rm{Moles}} = \frac{{{\rm{Mass}}}}{{{\rm{Molar mass}}}}\\\\0.198{\rm{ mol}} = \frac{{{\rm{Mass}}}}{{143{\rm{ g/mol}}}}\\\\{\rm{Mass}} = \left( {0.198{\rm{ mol}}} \right)\left( {143{\rm{ g/mol}}} \right)\\\\{\rm{ = 28}}{\rm{.3 g}}\\\end{array}[/tex]

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The correct option is option (D) Was an excellent north pole star in 3,000 BC.

Thuban (/jubaen/), also known as Alpha Draconis or Draconis, is a binary star system. It is a faint star in the Northern Hemisphere’s night sky, but because it served as the north pole star from the fourth to the second millennium BC, it is noteworthy historically. Thuban is the only member of Johann Bayer’s secondary magnitude class in the constellation Draco, despite the fact that at its current apparent magnitude of 3.65, it is 3.7 times fainter than Gamma Draconis (formerly called Eltanin), the brightest star in the constellation, which Bayer placed in his tertiae magnitude class despite its current apparent magnitude of 2.24.Thuban’s positioning regard to the Big Dipper (also known as the Plough) asterism of Ursa Major makes it very simple to see in the night sky under ideal viewing conditions. The two inner stars, Phecda and Megrez, point to Thuban, which is located only 15 degrees of arc from Megrez.Thuban is not bright enough to be seen in locations with significant light pollution.  

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When a body moves in a simple harmonic motion, its acceleration at the ends of its path is: zero. So, the correct option is (a).

Simple harmonic motion is the motion of a particle moving in a straight line with an acceleration that is always directed towards a fixed point on the line and whose magnitude is proportional to the distance from the fixed point.

There is no restoring force once the mass has reached equilibrium. Therefore, there is no acceleration, but the mass is travelling at its fastest rate. The mass will continue past the equilibrium position due to its inertia, stretching the string.

Therefore, when a body moves in a simple harmonic motion, its acceleration at the ends of its path is: zero. So, the correct option is (a).

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dimension = 30.0 m ✕ 15.0 m ✕ 5.0 m.

density = 1.20 kg/m3

(a)volume = lenght * breadth * height

      = 30 * 15 * 5

      = 2250 metre cube = 2.25 cubic meter

(b)   mass of air = density * volume

        mass of air = 1.2 * 2250

mass of air = 2700kg

weight  = mass * 9.8

             = 2700 * 9.8

             = 26,460 N

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