The marks obtained by the students in physics and in mathematics are as follows. Marks in Physics 35 23 47 17 10 43 9 6 28
Marks in Mathematics 30 33 45 23 8 49 12 4 31
Compute of correlation of ranks.
A. 0.2
B. 0.3
C. 0.7
D. 0.9

Answers

Answer 1

The correlation of ranks is approximately 0.2.

Option A is the correct answer.

We have,

To compute the correlation of ranks, we first need to rank the scores in each subject:
Physics: 10, 17, 23, 28, 35, 43, 47
Rank: 1, 2, 3, 4, 5, 6, 7
Mathematics: 4, 8, 12, 23, 30, 31, 33, 45, 49
Rank: 1, 2, 3, 4, 5, 6, 7, 8, 9

Then, we can calculate the differences between the ranks for each student:
Physics ranks: 1-5, 2-3, 3-7, 4-6, 5-1, 6-4, 7-2
Differences: -4, -1, -4, -2, 4, 2, 5
Mathematics ranks: 1-8, 2-6, 3-7, 4-4, 5-1, 6-5, 7-2, 8-3, 9-9
Differences: -7, -4, -4, 0, 4, -1, 5, 5, 0

Next, we can calculate the sum of the products of the differences:
= Sum of products

= (-4)(-7) + (-1)(-4) + (-4)(-4) + (-2)(0) + (4)(4) + (2)(-1) + (5)(5)
= 28 + 4 + 16 + 0 + 16 - 2 + 25
= 87

Finally, we can use the formula for the correlation of ranks:
r = 1 - (6Σd²)/(n(n² - 1))
where d is the difference in ranks and n is the number of scores

Plugging in the values, we get:
r = 1 - (6(87))/(9(81-1))
= 1 - (522)/(648)
= 1 - 0.8056
= 0.1944

= 0.2

Therefore,

The correlation of ranks is approximately 0.2.

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Related Questions

DUE YESTERDAY! BRAINLIST
WORTH 10 MARKS!

Answers

Answer:

Step-by-step explanation:

Calculating Delta Chi-Square, Delta, Deviance, and Delta Beta is done using ___ like we used in MLR. A. VIF B. Residuals C.Jackknifingo D. Cook's D

Answers

Calculating Delta Chi-Square, Delta, Deviance, and Delta Beta is done using C. Jackknifing, like we used in MLR (Multiple Linear Regression).

Jackknifing is a resampling technique that helps to estimate the stability and accuracy of statistical measures. In this method, one observation is removed at a time, and the model is recalculated to determine the impact of that observation on the overall result. This process is repeated for each observation, which helps to assess the influence of each data point on the model's performance.

Delta Chi-Square is a measure of the change in the goodness of fit of the model when a variable is added or removed. Delta measures the change in the estimated coefficient of a variable when another variable is added or removed from the model. Deviance measures the difference between the log-likelihood of the model and the log-likelihood of the saturated model, which is the model that perfectly fits the data.

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22. which of the following is false? (a) a chi-square distribution with k degrees of freedom is more right-skewed than a chi-square distribution with k 1 degrees of freedom. (b) a chi-square distribution never takes negative values. (c) the degrees of freedom for a chi-square test is deter- mined by the sample size. (d) p(c2 > 10) is greater when df

Answers

The false statement is (a) a chi-square distribution with k degrees of freedom is more right-skewed than a chi-square distribution with k+1 degrees of freedom.

In fact, as the degrees of freedom increase, the chi-square distribution becomes less skewed and approaches a normal distribution. Statement (b) is true, a chi-square distribution never takes negative values. Statement (c) is generally true, the degrees of freedom for a chi-square test are determined by the sample size minus one. Statement (d) is incomplete, as there is no specified value for df. The larger the degrees of freedom, the smaller the p-value for a given chi-square value.

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The quality control inspector of a factory manufacturing screws found that the samples of screws are normally distributed with a mean length of 5.5 cm and a standard deviation of 0.1 cm.

If the distribution is normal, what percent of data lies between 5.3 centimeters and 5.7 centimeters?
A. 95%
B. 99.7%
C. 68%
D. 34%

Answers

In this case, the mean is 5.5 cm and the standard deviation is 0.1 cm. So, one standard deviation below the mean is 5.4 cm and one standard deviation above the mean is 5.6 cm. Therefore, about 68% of the data falls between 5.4 cm and 5.6 cm, which includes the range of 5.3 cm to 5.7 cm.

Your question involves a normal distribution with a mean (µ) of 5.5 cm and a standard deviation (σ) of 0.1 cm. You want to find the percentage of data between 5.3 cm and 5.7 cm.

First, we need to standardize the scores using the z-score formula: z = (x - µ) / σ

For 5.3 cm: z1 = (5.3 - 5.5) / 0.1 = -2
For 5.7 cm: z2 = (5.7 - 5.5) / 0.1 = 2

Now, referring to a standard normal distribution table or using a calculator, we find the area between these z-scores:

This can be determined using the empirical rule, also known as the 68-95-99.7 rule, which states that for a normal distribution:
- About 68% of the data falls within one standard deviation of the mean
- About 95% of the data falls within two standard deviations of the mean
- About 99.7% of the data falls within three standard deviations of the mean

P(-2 < z < 2) = P(z < 2) - P(z < -2) = 0.9772 - 0.0228 = 0.9544

Converting it to a percentage, we get 95.44%, which is approximately 95%.

So, the answer is A. 95%.

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E-Loan, an online lending service, recently offered 60-month auto loans at 3.9% compounded monthly to applicants with good credit ratings. a. If you have a good credit rating and can afford monthly payments of $586, how much can you borrow from E-Loan?
b. What is the total interest you will pay for this loan?
E-Loan:
Electronic loan or E-loan refers to the services in which banks or other financial institutions provide loans to their customers through online modes, subject to successful verification of certain documents.

Answers

a. If you have a good credit rating and can afford monthly payments of $586, you can borrow $32,521.48 from E-Loan. This can be calculated using the formula for a present value annuity:

PV = PMT x ((1 - (1 + r/n)^(-nt)) / (r/n))

Where PV is the present value, PMT is the monthly payment, r is the annual interest rate (3.9%), n is the number of times the interest is compounded per year (12 for monthly compounding), and t is the number of years (5 for a 60-month loan). Plugging in these values, we get:

PV = $586 x ((1 - (1 + 0.039/12)^(-12*5)) / (0.039/12)) = $32,521.48

b. The total interest you will pay for this loan is $3,911.88. This can be calculated using the formula for total interest paid on a loan:

Total interest = (PMT x n x t) - PV

Where PMT, n, and t are the same as before, and PV is the amount borrowed. Plugging in the values, we get:

Total interest = ($586 x 60 x 5) - $32,521.48 = $3,911.88

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. If Maria saves $300 every month for 2 years, find the present value of her investment assuming 12% annual
nterest rate, compounded monthly.

$5,674.18
$3,376.52
$6,373.02
$2,124.34

Answers

Answer:

The correct answer is $6,373.02.

We can use the formula for present value of an annuity:

PV = PMT x ((1 - (1 + r/n)^(-n*t)) / (r/n))

Where PV is the present value, PMT is the monthly payment, r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the number of years.

Plugging in the values, we get:

PV = 300 x ((1 - (1 + 0.12/12)^(-12*2)) / (0.12/12))

PV = $6,373.02

Therefore, the present value of Maria's investment is $6,373.02.

Using the simple random sample of weights of wanien from a data set, we obtain these sample startinica 2 49 and = 144.970. Research trom other sources suggests that the population of weights of women has a standen devation given by 30.766 Find the best pont estimate of the mean weight of all women b. Find a 96% condence intervalimate of the moon weight of all women Click here w...butonable Chicken 00000dard om dit Click here to W.2 of the standardimal.distale CD The best point estimate Type an integer or a decimal

Answers

We can be 96% confident that the true mean weight of all women lies between 129.21 and 367.11.

The best point estimate of the mean weight of all women can be calculated using the formula:

Point estimate = sample mean = (sum of sample weights) / sample size

Here, the sample size is not given, so we cannot calculate the sample mean directly. However, we are given two sample statistics: the sample starting point (2) and the sample statistic (s) which is the sample standard deviation.

We can use the formula for the t-distribution to estimate the population mean:

t = (x - μ) / (s / √n)

where x is the sample mean, μ is the population mean, s is the sample standard deviation, and n is the sample size.

To find the point estimate, we can rearrange this formula to solve for x:

x = μ + t(s / √n)

Since we don't know the population mean μ, we will use the sample starting point 2 as an estimate. We also know the sample standard deviation s = 30.766 and we are given a 96% confidence interval, so we need to find the critical value of t for a two-tailed test with 96% confidence and degrees of freedom (df) = n - 1.

Using a t-distribution table or calculator, we find that the critical value for df = n - 1 = 1 is t = 12.71.

Plugging in the values, we get:

2 + 12.71 * (30.766 / √n) = x

Solving for x, we get:

x = 2 + 12.71 * (30.766 / √n)

We still need to find the sample size n in order to calculate the point estimate. We can use the sample statistic given, which is the sample standard deviation s = 30.766, to estimate the sample size using the formula:

s = √[(n-1)/n] * σ

where σ is the population standard deviation.

Plugging in the values, we get:

30.766 = √[(n-1)/n] * 30.766

Solving for n, we get:

n = 2.24

This suggests that the sample size is quite small, which may limit the accuracy of our point estimate.

Plugging in the value of n, we get:

x = 2 + 12.71 * (30.766 / √2.24)

x = 2 + 12.71 * 19.398

x = 248.16

Therefore, the best point estimate of the mean weight of all women is 248.16.

b. To find a 96% confidence interval for the mean weight of all women, we can use the formula:

CI = x ± t(α/2, df) * (s / √n)

where x is the point estimate, t(α/2, df) is the critical value for a two-tailed test with α = 0.04 and df = n - 1, s is the sample standard deviation, and n is the sample size.

Plugging in the values, we get:

CI = 248.16 ± 12.71 * (30.766 / √2.24)

CI = 248.16 ± 118.95

CI = (129.21, 367.11)

Therefore, we can be 96% confident that the true mean weight of all women lies between 129.21 and 367.11.

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A weight is attached to the end of a frictionless spring, pulled down to extend the
spring, and then released. Let d be the distance of the weight above the floor at
time t, where d is in centimeters and t is in seconds. The distance varies
sinusoidally over time.

A stopwatch reads 0.5 seconds when the weight reaches its first high point 42
centimeters above the floor, and the next low point 11 centimeters above the floor,
occurs at 1.2 seconds.

Write a trigonometric equation to express d in terms of t, and use your equation to
determine the weights distance from the floor at 4 seconds. Round to the nearest
centimeter.

Answers

Therefore, the Distance from floor = 11 cm

How to solve

Given : Max height achieved = 42 cm t = 0.5 s

Min. height = -11 cm t = 1.2 s ( negative sign shows below floor level assuming floor to be at 0 )

To find : SInusoidal Function representing this sysytem

Mid line = (42 + (-11)) / 2 = 15.5

Amplitude = 42 - 15.5 = 26.5 cm = A

Vertical shift = 15.5 cm = D

Time period = 2 x ( 1.2 - 0.5 ) = 1.4 s ==== T = 2pi/B == B = 2pi/1.4 = 1071/7

General equaion : y = A sin (B(x-c)) + D

y = 26.5 sin ( 1071/7 ( x - 0.15) ) + 15.5

EQUATION WILL BE - D = 26.5 sin ( 1071/7 ( t - 0.15 )) + 15.5

(B) distance at t = 4s

putting t = 4 in the equation

D = -11

Therefore, the Distance from floor = 11 cm

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Let a,b and c be three positive integers. Find a formula for lcm(a, b, c).

Answers

LCM stands for "Least Common Multiple". It is the smallest positive integer that is a multiple of two or more numbers

To find a formula for the least common multiple (LCM) of three positive integers a, b, and c.

The formula for LCM(a, b, c) is:
LCM(a, b, c) = LCM(LCM(a, b), c)

To find the LCM of two numbers, you can use the formula:
LCM(a, b) = (a * b) / GCD(a, b)
where GCD(a, b) is the greatest common divisor of a and b.

So, to find the LCM(a, b, c), follow these steps:

1. Calculate GCD(a, b)
2. Calculate LCM(a, b) = (a * b) / GCD(a, b)
3. Calculate GCD(LCM(a, b), c)
4. Calculate LCM(a, b, c) = LCM(LCM(a, b), c) = (LCM(a, b) * c) / GCD(LCM(a, b), c)

That's the formula and the step-by-step process to find the LCM of three positive integers a, b, and c.

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Using the Laplace transform, solve the IVPy₁ = 5y1-4y2-9t2+2t, y2 = 10y1-772-172-2t, 31(0) = 3, yz(0) = 0y1(t) =y2(t) =

Answers

The solution to the given initial value problem is:

y1(t) = 3t - 2sin(2t) + 11/10sinh(t) - 11/10sinh(2t)

y2(t) = 6t + 7/10cosh(t) - 17/10sinh(t)

Taking the Laplace transform of the given system of differential equations, we get:

sY1(s) - y1(0) = 5Y1(s) - 4Y2(s) - 2(2/(s^3)) + 2(1/(s^2))

sY2(s) - y2(0) = 10Y1(s) - 77(1/s) - 17(1/(s^2)) - 2(1/(s^2))

Applying the initial conditions, we get:

sY1(s) - 3 = 5Y1(s) - 4Y2(s) - 4/s^3 + 2/s^2

sY2(s) = 10Y1(s) - 77/s - 17/s^2 - 2/s^2

Solving for Y2(s), we get:

Y2(s) = (10Y1(s) - 77/s - 17/s^2 - 2/s^2)/s

Substituting this in the equation for Y1(s), we get:

sY1(s) - 3 = 5Y1(s) - 4[(10Y1(s) - 77/s - 17/s^2 - 2/s^2)/s] - 4/s^3 + 2/s^2

Simplifying and solving for Y1(s), we get:

Y1(s) = (3s^3 + 10s^2 + 8s + 154)/(s^5 + 5s^3 + 4s)

Taking the inverse Laplace transform, we get:

y1(t) = 3t - 2sin(2t) + 11/10sinh(t) - 11/10sinh(2t)

y2(t) = 6t + 7/10cosh(t) - 17/10sinh(t)

Therefore, the solution to the given initial value problem is:

y1(t) = 3t - 2sin(2t) + 11/10sinh(t) - 11/10sinh(2t)

y2(t) = 6t + 7/10cosh(t) - 17/10sinh(t)

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(-76.25 Points] DETAILS BBBASICSTATSACC 8.1.018.MI. MY NOTES ASK YOUR TEACHER What price do farmers get for their watermelon crops? In the third week of July, a random sample of 42 farming regions gave a sample mean of x = $6.88 per 100 pounds of watermelon. Assume that o is known to be $1.92 per 100 pounds. (a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their watermelon crop (in dollars). What is the margin of error in dollars)? (For each answer, enter a number. Round your answers to two decimal places.) lower limit क upper limit $ margin of error (6) Find the sample size necessary for a 90% confidence level with maximal error of estimate E = 0.25 for the mean price per 100 pounds of watermelon. (Enter a number. Round up to the nearest whole number.) farming regions (c) A farm brings 15 tons of watermelon to market. Find a 90% confidence interval for the population mean cash value of this crop in dollars). What is the margin of error (in dollars)? Hint: 1 ton is 2000 pounds. (For each answer, enter a number. Round your answers to two decimal places.) Tower limit S 6 upper limit margin of error S

Answers

Answer:

I'm not quite sure if you are joking or not, but here is your answer:
(a) The point estimate for the population mean price (per 100 pounds) is x = $6.88. The standard deviation is known to be σ = $1.92. The sample size is n = 42. For a 90% confidence interval, the critical value is 1.645 (obtained from a t-distribution table with 41 degrees of freedom). The margin of error is:

Margin of error = Critical value x Standard error

Standard error = Standard deviation / sqrt(sample size) = 1.92 / sqrt(42) = 0.2968

Margin of error = 1.645 x 0.2968 = 0.4882 ≈ 0.49

The lower limit of the confidence interval is:

Lower limit = Point estimate - Margin of error = 6.88 - 0.49 = $6.39

The upper limit of the confidence interval is:

Upper limit = Point estimate + Margin of error = 6.88 + 0.49 = $7.37

Therefore, the 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their watermelon crop is $6.39 to $7.37. The margin of error is $0.49.

(b) The maximal error of estimate is E = 0.25. The confidence level is 90%. The standard deviation is known to be σ = $1.92. We need to find the sample size (n) that satisfies the following formula:

Margin of error = Critical value x Standard error

Standard error = Standard deviation / sqrt(sample size)

For a 90% confidence interval, the critical value is 1.645. Substituting the known values and solving for n, we get:

0.25 = 1.645 x (1.92 / sqrt(n))

sqrt(n) = (1.645 x 1.92) / 0.25

n = [(1.645 x 1.92) / 0.25]^2

n ≈ 113

Therefore, a sample size of 113 farming regions is necessary for a 90% confidence level with maximal error of estimate E = 0.25 for the mean price per 100 pounds of watermelon.

(c) The farm brings 15 tons of watermelon to market, which is equivalent to 30,000 pounds (since 1 ton = 2,000 pounds). The point estimate for the population mean cash value of this crop is unknown. We can use the confidence interval obtained in part (a) to estimate this interval. Multiplying the lower and upper limits by 300 (since 300 pounds of watermelon correspond to $6.88), we get:

Lower limit = 6.39 x 300 = $1917

Upper limit = 7.37 x 300 = $2211

Therefore, the 90% confidence interval for the population mean cash value of this crop is $1917 to $2211. The margin of error is:

Margin of error = (Upper limit - Lower limit) / 2 = (2211 - 1917) / 2 = $147

PLS HELP ASAP 100 POINTS
Find the measure of ∠YOZ by answering the questions.
1. Find the measure of ∠WOV. Which angle relationship did you use? (3 points)
2. Now find the measure of ∠YOZ. Which angle relationship did you use?
3. Check your answer by using another strategy to find the measure of ∠YOZ. Describe your strategy, and show that it gives the same measure for ∠YOZ. (4 points)

Answers

Answer:

60°60°, vertical angles60°, measure of a straight angle

Step-by-step explanation:

Given right angle XOV and 30° angle XOW, you want to know the measure of angle WOV. You also want to find the measure of angle YOZ, which is opposite angle VOW, where XOY is a right angle, and WOZ is a straight angle.

1. WOV

The angle addition theorem tells you that ...

  ∠XOW +∠WOV = ∠XOV

Angle XOV is given as a right angle, and angle XOW is shown as 30°, so we have ...

  30° +∠WOV = 90°

  ∠WOV = 60° . . . . . . . . . subtract 30° from both sides

Angle WOV is 60° using the angle addition theorem.

2. YOZ

Rays OY and OV are opposite rays, as are rays OZ and OW. This means angles YOZ and VOW are vertical angles, hence congruent.

  ∠YOZ = ∠WOV = 60°

Angle YOZ is 60° using the congruence of vertical angles.

3. YOZ another way

As in part 2, angle WOZ is a straight angle, so measures 180°. The angle addition theorem tells you this is the sum of its parts:

  ∠ZOY +∠YOX +∠XOW = ∠ZOW

  ∠ZOY +90° +30° = 180°

  ∠ZOY = 60° . . . . . . . . . . . . . subtract 120° from both sides

Angle YOZ is 60° using the measure of a straight angle.

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You spin the spinner once.

3456


What is P(3)?

Write your answer as a fraction or whole number.

Answers

The value of the probability P(3) is 1/4.

We have,

There are 4 outcomes.

i.e

3, 4, 5, and 6.

Now,

P(3)

This means,

The probability of getting 3 as the outcome when spun.

So,

P(3) = 1/4

Thus,

The value of the probability P(3) is 1/4.

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What is the value of x in this system of equations? Express the answer as a decimal rounded to the nearest tenth.


Negative 5 x minus 12 y = negative 8. 5 x + 2 y = 48.


on a time limit!!!!

Answers

The value of x is 5 and y is 4.

What is Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

The Equations are:

5x - 12y= -8...................(1)

and, 5 x + 2 y = 48 ..................(2)

Solving the Equation (1) and (2) we get

-12y -2y = -8 - 48

-14y = -56

y= -56 /(-14)

y = 4

and, 5x +2y= 48

5x + 8 = 48

5x= 40

x= 5

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Bacteria colonies can increase by 67% every 2 days. If you start with 55 bacteria microorganisms, how large would the colony be after 10 days? Future Amount = [?](1+ Future Amount = I(1 + r)t​

Answers

After 10 days, the colony would be as large as 989, based on the exponential growth of 67% every 2 days.

What is exponential growth?

An exponential growth refers to a constant rate or percentage of growth in the number or value of some variables.

Exponential growth can be modeled using the exponential growth function and used to determine the future quantity or amount of the variables.

Initial number of the bacteria microorganisms = 55

Growth rate = 67% every 2 days

Daily growth rate = 33.5% (67% ÷ 2)

The number of days involved, t = 10 days

The ending number of the bacteria microorganisms = Future Amount = 55(1 + 33.5%)^t

= 55(1.335)^10

= 989

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Answer:

55 0.67 ^5

Step-by-step explanation:

The future amount = ? micro organisms

xamine the given statement, then identify whether the statement is a null hypothesis, an alternative hypothesis, or neither. the mean income of workers who have majored in history is less than $25,000.

Answers

The given statement, "The mean income of workers who have majored in history is less than $25,000," is an alternative hypothesis.

An alternative hypothesis is a statement that is tested against the null hypothesis, which generally claims no relationship or effect. In this case, the null hypothesis would be, "The mean income of workers who have majored in history is greater than or equal to $25,000."

We must first comprehend the idea of null and alternative hypotheses in hypothesis testing before we can comprehend why the above statement is an alternate hypothesis.

When doing a hypothesis test, we begin with a null hypothesis, which is a claim that there is no connection between the variables under investigation.

The null hypothesis in this situation would be "The mean income of workers with history majors is greater than or equal to $25,000."

On the other side, the competing hypothesis asserts that the median income of people who majored in history is less than $25,000.

The supplied claim, "The mean income of workers who majored in history is less than $25,000," is, therefore, a counterclaim.

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Answer all boxes and read the questions

Answers

The amount of paper used for the label on the can of tune is 12.57 in²

Here, the shape of the can of can is cylindrical.

The area of the cured surface of cylinder is given by formula,

A = 2πrh

where r is the radius of the cylinder

and h is the height of the cylinder

Here, r = 2 in and h = 1 in

so, the area of the lateral surface of cylinder would be,

A = 2 × π × r × h

A = 2 × π × 2 × 1

A = 4 × π

A = 12.57 sq. in.

Therefore, the required amount of paper = 12.57 in²

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Question 4 Write the system 1-x+2y+z =7 2z-y+4z=17 3x - 2y +2z = 14 in the matrix form by using matrix multiplication. Question 5 Solve the equation system in Question 4 by using Cramer's method.

Answers

The solution to the system of equations is x=-3.35, y=-7, z=3 using Cramer's method.

| 1  -1  2 |   | x |   | 7 |

| 0  -1  6 | x | y | = |17 |

| 3  -2  2 |   | z |   |14 |

We can use Cramer's rule to solve this system of equations by finding the determinants of the coefficient matrix and the matrices obtained by replacing each column with the constant terms.

The determinant of the coefficient matrix is:

| 1  -1  2 |

| 0  -1  6 |

| 3  -2  2 |

= 1(-1*2 - 6*(-2)) - (-1*2 - 6*3) + 2*(2*(-1) - (-1)*(-2))

= 20

The determinant obtained by replacing the first column with the constant terms is:

| 7  -1  2 |

|17  -1  6 |

|14  -2  2 |

= 7(-1*2 - 6*(-2)) - (-1*17 - 6*14) + 2*(2*(-1) - (-1)*(-2))

= -67

The determinant obtained by replacing the second column with the constant terms is:

| 1  7  2 |

| 0 17  6 |

| 3 14  2 |

= 1(17*2 - 6*14) - 7(3*2 - 14*2) + 2(3*17 - 14*0)

= -140

The determinant obtained by replacing the third column with the constant terms is:

| 1  -1  7 |

| 0  -1 17 |

| 3  -2 14 |

= 1(-1*14 - 17*(-2)) - (-1*7 - 17*3) + 7*(2*(-2) - (-1)*(-2))

= 60

Therefore, the solution to the system of equations is:

makefile

Copy code

x = -67/20

y = -140/20

z = 60/20

x = -3.35

y = -7

z = 3

Hence, the solution to the system of equations is x=-3.35, y=-7, z=3 using Cramer's method.

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5. A woman pays $2.78 for some bananas and eggs. If each banana costs $0.69 and each egg costs $0.35, how many eggs and how many bananas did the woman buy

Answers

If a woman pays $2.78 for some bananas and eggs. If each banana costs $0.69 and each egg costs $0.35, then she bought 4 bananas and 6 eggs.

Let's assume the woman bought x bananas and y eggs.

According to the problem, each banana costs $0.69 and each egg costs $0.35.

So the cost of x bananas would be 0.69x and the cost of y eggs would be 0.35y.

The total cost of the bananas and eggs is given as $2.78. So we can write the equation:

0.69x + 0.35y = 2.78

Now we need to solve for x and y.

We can start by multiplying the entire equation by 100 to get rid of the decimals:

69x + 35y = 278

We can also simplify the equation by dividing both sides by 1 (which doesn't change the equation):

69x/1 + 35y/1 = 278/1

Now we can use a system of equations to solve for x and y.

Let's solve for y in terms of x by isolating y on one side of the equation:

35y = 278 - 69x

y = (278 - 69x)/35

Now we can substitute this expression for y into the original equation:

0.69x + 0.35((278 - 69x)/35) = 2.78

Simplifying this equation, we get:

0.69x + 8 - 2x = 2.78

Solving for x, we get:

0.69x - 2x = 2.78 - 8

-1.31x = -5.22

x = 4

So the woman bought 4 bananas.

Now we can substitute this value for x into the expression we derived for y:

y = (278 - 69(4))/35

y = 6

So the woman bought 6 eggs.

Therefore, the woman bought 4 bananas and 6 eggs.

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Let X is a random variable with probability density function f(x) = {3x? for 0

Answers

The variance of X is 3/80.

Given the probability density function of X,

f(x) = {3x² for 0 < x < 1

{0 otherwise

We can use this to answer the following:

(a) Find P(X < 0.5)

To find P(X < 0.5), we need to integrate the density function from 0 to 0.5:

P(X < 0.5) = ∫[0,0.5] f(x) dx

= ∫[0,0.5] 3x² dx

= [x³]₀.₃

= 0.125

(b) Find the cumulative distribution function of X, F(x)

The cumulative distribution function (CDF) of X is given by:

F(x) = P(X ≤ x) = ∫[0,x] f(t) dt

If x ≤ 0, then F(x) = 0. If 0 < x ≤ 1, then

F(x) = ∫[0,x] f(t) dt

= ∫[0,x] 3t² dt

= [t³]₀.ₓ

= x³

If x > 1, then F(x) = 1. So, the CDF of X is:

F(x) = {0 if x ≤ 0

{x³ if 0 < x ≤ 1

{1 if x > 1

(c) Find the expected value of X, E(X)

The expected value of X is given by:

E(X) = ∫[−∞,∞] x f(x) dx

Since the density function f(x) is zero outside the interval [0,1], we can restrict the integration to this interval:

E(X) = ∫[0,1] x f(x) dx

= ∫[0,1] 3x³ dx

= [3/4 x⁴]₀.₁

= 3/4 * 1⁴ - 0

= 3/4

Therefore, the expected value of X is 3/4.

(d) Find the variance of X, Var(X)

The variance of X is given by:

Var(X) = E(X²) - [E(X)]²

We have already found E(X) in part (c). To find E(X²), we integrate x² times the density function:

E(X²) = ∫[0,1] x² f(x) dx

= ∫[0,1] 3x⁴ dx

= [3/5 x⁵]₀.₁

= 3/5 * 1⁵ - 0

= 3/5

Substituting into the formula for variance:

Var(X) = E(X²) - [E(X)]²

= 3/5 - (3/4)²

= 3/5 - 9/16

= 3/80

Therefore, the variance of X is 3/80.

Complete question: Let X be a random variable defined by the density function

[tex]$$f(x)=\left\{\begin{array}{cl}3 x^2 & 0 \leq x \leq 1 \\0 & \text { otherwise }\end{array}\right.$$[/tex]

Find

(a)[tex]$E(X)$[/tex]

(b) [tex]$E(3 X-2)$[/tex]

(c) [tex]$E\left(X^2\right)$[/tex]

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The rectangle ok the right is a scaled copy of the rectangle on the left. Identify the scale factor. Express your answer as a whole number or fraction in simplest form.

Answers

If right is a scaled copy of the rectangle on the left then the scale factor is  1/2.

The scale factor can be calculated by dividing the corresponding lengths (or widths) of the two rectangles.

The length of the left rectangle is 20 units, and the length of the right rectangle is 10 units.

Therefore, the scale factor for the length is:

scale factor for length = length of right rectangle / length of left rectangle

= 10 / 20

= 0.5

scale factor for width = width of right rectangle / width of left rectangle

= 5 / 10

= 0.5

Since the two scale factors are the same, we can conclude that the rectangles are scaled by the same factor of 0.5 in both the length and the width.

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5(x+3)=17x-93 solve for x

Answers

I think it's 9, tell me if I'm wrong

which of the following describes the type of externality generated by the unregulated private market and the resulting deadweight loss?\

Answers

The type of externality generated by an unregulated private market is a negative externality. This occurs when the production or consumption of a good or service imposes a cost on a third party, without compensation.

In an unregulated market, private individuals and businesses are free to make their own decisions without any external intervention, which can lead to the overproduction of negative externalities. The resulting deadweight loss refers to the loss of economic efficiency that occurs when the quantity of a good or service produced is not at the socially optimal level. In the case of a negative externality, the market produces more of the good than is socially desirable, leading to a deadweight loss. This loss represents a net decrease in the overall welfare of society. Therefore, it is essential for governments to regulate private markets to reduce negative externalities and prevent deadweight loss, leading to a more efficient allocation of resources.
The type of externality generated by an unregulated private market can be described as a negative externality. A negative externality occurs when a private market transaction results in an adverse effect on third parties who are not directly involved in the transaction. This leads to a misallocation of resources, as the market does not account for these external costs, and thus creates a deadweight loss.

In an unregulated private market, firms may not consider the external costs their actions impose on society, such as pollution or depletion of natural resources. As a result, the market equilibrium fails to reflect the true social cost of production. Consequently, there may be overproduction of goods and services that generate negative externalities, which in turn leads to a deadweight loss.

The deadweight loss is the reduction in overall economic efficiency caused by this misallocation of resources. It represents the value of potential gains that are not realized due to the market's failure to account for the negative externality. In order to reduce or eliminate the deadweight loss, government intervention in the form of regulation, taxes, or subsidies may be necessary to internalize the externality and restore the market to its socially optimal level of output.

In summary, the unregulated private market generates negative externalities, leading to a deadweight loss, as the true social cost of production is not reflected in the market equilibrium. Government intervention may be required to address this issue and restore economic efficiency.

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Please helppppppppppppp

Answers

Answer:

BE = 7.73

Step-by-step explanation:

All the angles in ΔABC are 60 because it's an equilateral triangle

AB = AE = 4

m∠BAE = 60 + 90 = 150

(1/2)m∠BAE = 150/2  = 75

sin75 = (1/2)(BE) / 4

1/2(BE) = sin75(4)

BE = sin75(4)(2) = 7.73

Question 6 Suppose a Pharmaceutical company manufactures a specific drug and needs to perform some quality assurance to ensure that they have the correct dosage, which is supposed to be 500 mg. In a random sample of n=125 units of the drug, there is an average dose of x=499.3 mg with a standard deviation of =6 mg. What is the likelihood that the drugs produced will actually contain a dosage of 500 mg?

Answers

If in a random sample of n=125 units of the drug, there is an average dose of x=499.3 mg with a standard deviation of =6 mg the likelihood of the drugs produced containing a dosage of 500 mg is fairly high.

Based on the information provided, we can use the concept of the standard error of the mean to determine the likelihood that the drugs produced will contain a dosage of 500 mg.

The formula for the standard error of the mean is:

SE = s/√n

Where:
s = standard deviation of the sample
n = sample size

Substituting the values given, we get:

SE = 6/√125
SE = 0.54

This means that the sample mean of 499.3 mg is 0.54 units away from the true population mean of 500 mg.

To determine the likelihood of the drugs produced containing a dosage of 500 mg, we can use a confidence interval. A 95% confidence interval for the mean dosage can be calculated as:

Mean dosage ± 1.96(SE)

Substituting the values given, we get:

499.3 ± 1.96(0.54)
499.3 ± 1.06

The 95% confidence interval for the mean dosage is (498.24, 500.36).

Therefore, there is a 95% chance that the true population means dosage falls within this interval. Since the interval includes the value of 500 mg, we can conclude that the likelihood of the drugs produced containing a dosage of 500 mg is fairly high.

In a random sample of n=125 units of the drug, there is an average dose of x=499.3 mg with a standard deviation of =6 mg is very high.

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I need help really bad

Answers

A)

1) the area of the shapes are given as follows:

Circle = 113.10Triangle = 225Board = 450

2) The probabilities are:

P (circle) ≈ 0.2513P (triangle and not circle) ≈ 0.2376P (neither) ≈ 0.5111

B)

1) The area of Board is = 384

The area of the circles are:

Large  = 201.06Medium  = 113.10Small = 50.27

2) The probabilities are:

P (coin falls in the smallest circle) = 0.13%P (coin fall in the largest circle but not in the other two circles = 0.55%P (Coin fall in the board but not in the circles =  0.52%

How did we do the above calculation?

A)

1)

Area of circle = πr ² = π (d/2) ² = 3.142  x (12 /2)² = 113.10

Area of the triangle = (b x h)/ 2 = (30 x15 )/ 2 = 225Area of theBoard = l x w = 30 x15 = 450

2)

i) The probability of coin landing in the circle   is given by   the ratio of the area of the circle to the area of the   board:

P(circle) = Area of circle / Area of board = 36pi / 450 ≈ 0.2513

ii)

The probability of a coin landing in the triangle but not in the circle is

P(triangle and not circle) = (A are of triangle -  area of circle) / Area of board = (225 - 36pi) / 450 ≈ 0.2376

iii) The probability of a coin landing in neither the circle nor the triangle is  P (neither) = 1 - (P(circle) +  P (triangle and not circle)) = 1 - (0.2513 + 0.2376 ) = 0.5111

B)

1)

Area of the board = 24 x 16 = 384The largest circle has a area of π(8)² = 64π = 201.06

The medium     circle has an area of π(6)² = 36π = 113.10The smallest circle has an area of π(4)² = 16π = 50.27

2)

P (coin falls in the smallest circle) = P (Area of the Smallest Circle/Area of the Board)
P  (smallest circle) = 50.27/384  = 0.13%P (coin fall in the largest circle but not in the other two circles = P(LC)/P(All Circles) = 201.06/(201.06 + 113.10 + 50.27) = 0.55%P (Coin fall in the board but not in the circles = Area of Board/Area of Circle = 201.06/384 = 0.52%


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Help please. How many roots and what are they?

Answers

The function f(x) = 3x³ - 2x² - 2x + 3 has one root and the root is x = 1

How many roots and what are the roots?

From the question, we have the following parameters that can be used in our computation:

f(x) = 3x³ - 2x² - 2x + 3

Next, we plot the graph of the function f(x)

See attachment

From the graph, we can see that the graph intersects with the x-axis once at x = -1

This means that it has one root and the root is x = 1

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Use the figure to find the Surface Area.



32 sq. units
64 sq. units
85 1/3 sq. units

Answers

The surface area of the sphere is 64π square units.

Option B is the correct answer.

We have,

Surface area of a sphere = 4πr² ______(1)

Now,

Radius = 4 units

Substituting in (1)

The surface area of a sphere

= 4πr²

= 4 x π x 4²

= 4π x 16

= 64π square units

Thus,

The surface area of the sphere is 64π square units.

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On tax free weekend, Ben buys school supplies totaling $47.50. He has a sale coupon for 15% off his entire purchase. What will Ben's final cost be after the 15% discount?

Answers

Ben's final cost after the 15% discount will be $40.375

What will Ben's final cost be after the 15% discount?

From the question, we have the following parameters that can be used in our computation:

Discount = 15%

Total purchase = $47.50

Using the above as a guide, we have the following:

Final cost = Total purchase * (1 -Discount)

Substitute the known values in the above equation, so, we have the following representation

Final cost = 47.50 * (1 -15%)

Evaluate

Final cost = 40.375

Hence, the final cost is $40.375

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Consider a game where you toss three dice independently. If at least one of the dice
comes up 6, you win $5. Otherwise, you lose $1. If you play this game 100 times, independently, please answer the following question.
(a) Let X be the random variable of the profit from one round of the game. Please write down the probability distribution of X.
(b) Please compute the expectation and standard deviation of X.
(c) Let X be the average profit over 100 rounds, please give the (approximate) distribution
of X.
(d) What is the probability your total profit over 100 rounds is at most $80?

Answers

a. The probability of winning $5 is when at least one dice comes up 6, which is 1 - 125/216 = 91/216.

b. The standard deviation of X is the square root of the variance:

SD(X) = √(9.828) = 3.135

c. The average profit over 100 rounds, X, will be approximately normally distributed with mean μ = E(X) = 0.6944 and standard deviation σ = SD(X)/√(n) = 3.135/√(100) = 0.3135.

d. The probability that Y is at most $80 is approximately 0.6325.

What is probability?

Probability is a measure of how likely an event is to occur. Many events are impossible to forecast with absolute accuracy. We can only anticipate the possibility of an event occurring, i.e. how probable they are to occur, using it.

(a) The probability distribution of X can be represented by the following table:

| X      | -1    | 5     |

|--------|------|-------|

| P(X=x) | 125/216  | 91/216 |

The probability of losing $1 is when none of the dice comes up 6, which is (5/6) x (5/6) x (5/6) = 125/216. The probability of winning $5 is when at least one dice comes up 6, which is 1 - 125/216 = 91/216.

(b) The expectation of X can be calculated as:

E(X) = (-1) x (125/216) + (5) x (91/216) = 0.6944

The variance of X can be calculated as:

Var(X) = [(−1 − 0.6944)² × 125/216] + [(5 − 0.6944)² × 91/216] = 9.828

The standard deviation of X is the square root of the variance:

SD(X) = √(9.828) = 3.135

(c) By the Central Limit Theorem, the average profit over 100 rounds, X, will be approximately normally distributed with mean μ = E(X) = 0.6944 and standard deviation σ = SD(X)/√(n) = 3.135/√(100) = 0.3135.

(d) Let Y be the total profit over 100 rounds. Then Y is the sum of 100 independent and identically distributed random variables with the same probability distribution as X. Therefore, by the Central Limit Theorem, Y is approximately normally distributed with mean μ_Y = 100μ = 69.44 and standard deviation σ_Y = √(100)σ = 31.35.

To find the probability that Y is at most $80, we standardize the variable:

Z = (80 - μ_Y)/σ_Y = (80 - 69.44)/31.35 = 0.337

Using a standard normal distribution table or calculator, we find that the probability of Z being less than or equal to 0.337 is 0.6325. Therefore, the probability that Y is at most $80 is approximately 0.6325.

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