The maximum allowable potential difference across a 250 mH inductor is 360 V . You need to raise the current through the inductor from 1.5 A to 2.5 A . What is the minimum time you should allow for changing the current?

Answer:

Below

Explanation:

On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.

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Answer:

"the spark plug gap"

The plug provides a gap between the input voltage and the ground supplied by the car chassis.

Answer:

P V = N R T      ideal gas equation

V = .19 * A      volume of enclosed gas

.19 P = N R T / A      using volume of enclosed gas

P = Po + Phg       pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury

.19 (Po + Phg) = N R T / A which is what was asked

Note Phg = density of Hg * height of Hg * acceleration due to gravity

A tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. There will atmospheric pressure and pressure due to mercury column on trapped gas column  having length 0.19m which is given by,

(p₀+pm)×0.190 = nRT÷A.

Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area.  its SI unit is Pascal (Pa) which is equal to N/m².  is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].

Looking at the figure from top to bottom, we can see the top end of the tube is opened. There is 0.035m of mercury column below which we have a air 0.190m of gas column.

We can feel the physics behind this figure what is happening here, top of the tube is open so there is atmospheric pressure acting on the mercury column and mercury column is above the gas column, it means that both atmospheric pressure and mercury pressure will act on gas column.

i.e.  (p₀+pm) = pressure on the air column

this (p₀+pm) is downward pressures, hence gas inside the tube gets compressed due to this pressure because bottom end is closed. it means that back pressure will be created inside the gas in upward direction and both pressures becomes equal at equilibrium.

i.e. (p₀+pm) = back pressure inside the gas column......1)

according to ideal gas equation, PV=nRT

pressure inside the air column is P = nRT÷V

where V is volume of gas that is A×0.190.

P = nRT÷(A×0.190).....( back pressure inside the gas column).

equation 1 becomes

(p₀+pm) = nRT÷(A×0.190).

Hence we get

(p₀+pm) ×0.190= nRT÷(A).

Hence proved.

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Answer:

1. wisest

2. more delicious

3. majestic (not sure about this one)

4. industrious

5. happiest

Answer: A force can change the direction in which an object is moving

Explanation: A bigger force of an object will produce a bigger change in motion

Answer:

A

Explanation:

Convergence is pushing them together so C is out of the question.

B and D are wrong because it is an oceanic plate. B and D are for continental plates.

Explanation:

Uhhhh here is an example

a=vt. =27 m/s10 s. =2.7 m/s2.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Acceleration of the car is ~

[tex] \boxed{1.5 \: \: m/s}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

We know that,

Acceleration = rate of change in velocity ~

that is ~

where,

now, let's solve ~

Answer:

C

Explanation:

fuses of same kind can be used for different things, and of different kinds could be used for different things as well.

Let the ball at the ground be A and that at the top be B.

Assume that you see the motion of A while sitting at B.

You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.

Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.

Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.

Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.

Since B falls freely, he covers a distance of  1/2(g)(1²)=5  (assuming g = 10m/s²)

Thus, they meet at a height of (20–5)m = 15m from the ground.

Answer:

Explanation:

It will be B.

The correct answer is the same mass and less weight.

The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.

Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.

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Answer:

65km/h

Explanation:

Here,

Relative velocity of car moving in different directions with different velocities =Va + Vb

=25+40

=65 km/h

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The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]  

the momentum is defined by the product of the mass and the velocity of the body.

        p = mv

The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.

If the system is isolated, the forces during the collision are internal and the it  is conserved. Let's find the momentum is two instants.

Initial instant. Before crash.

      p₀ = m₁ u₀ + 0

Final moment. After crash.

      [tex]p_f = m_1 u_f + m_2 v_f[/tex]  

The momentum is preserved.

      p₀ = [tex]p_f[/tex]  

      [tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]  

Since the collision is elastic, the kinetic energy is conserved.

      K₀ = [tex]K_f[/tex]

      ½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex]  + ½ m₂  [tex]v_f^2[/tex]  

Let's write our system of equations.

       [tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]

Let's solve

       [tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]

       [tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]  

        [tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]

In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]  

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Answer:

So this is just a ratio/proportion problem

so lets say its in boys:minutes

so in the first scenario

20:8

and we want to find

x:10

So proportion really

20/8=x/10

cross multiply

25

25 boys can sweep it in 10 minutes

Answer:

A

Explanation:

Answer:

A force of 20N acts on each cm^2 of area

There's no way to tell, without knowing the resistance of either X-1 or X-2, or the reading on A3.

Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.

They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.

See full question below

Which is not a general characteristic of starburst galaxies?

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Answer:

They will go backwards?

Explanation:

If positive they go forward but is negative they go backwards.

The best example of physics in the body is the movement of an arm throwing a ball. The correct option is D.

Physics is the branch of science that studies the structure of matter and how the universe's fundamental constituents interact.

It investigates objects ranging from the very small to the entire universe using quantum mechanics and general relativity.

Physics is the natural science that investigates matter, its fundamental constituents, its motion and behavior in space and time, as well as the related entities of energy and force.

Physics is one of the most fundamental scientific disciplines, with the primary goal of understanding how the universe functions.

The movement of an arm throwing a ball is the best example of physics in the body.

Thus, the correct option is D.

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Answer:

c. lubricant..........

The mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

Let us recall that the law of conservation of mass states that, mass can neither be created nor destroyed but is converted from one form to another. In accordance with this law of conservation of mass. The mass of the orange must remain the same after it has been cut in pieces.

Hence, If the mass of an orange is measured after it has been cut into pieces, the mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

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Can i ask u a question

Brainliest me please

Answer:

2hr 21 min

Explanation:

0 days 2 hours 20 minutes 0 seconds

+ 0 days 0 hours 0 minutes 60 seconds

= 0 days 2 hours 21 minutes 0 seconds

Answer:

directly proportional

Explanation:

Please find attached photograph for your answer.

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Answer:

Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?

Liquid is the answer

Explanation:

The coefficient of kinetic friction between the block and the horizontal surface is 0.051.

The given parameters;

The acceleration of the block is calculated as follows;

[tex]v^2 = u^2 + 2(-a)s\\\\v^2 = u^2 - 2as\\\\a = \frac{u^2 - v^2}{2s} \\\\a = \frac{3^2 - 0^2}{2\times 9} \\\\a =0.5 \ m/s^2[/tex]

The coefficient of kinetic friction between the block and the horizontal surface is calculated as follows;

[tex]\mu_k mg = ma\\\\\mu_k = \frac{a}{g} \\\\\mu_k = \frac{0.5}{9.8} \\\\\mu_k = 0.051[/tex]

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Answer:

60 N.C

Explanation:

The box will move in the direction of the push and pull with a force of 60 N. C.

If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. , then the distance must she travel so the two of you can travel at the same speed would be 30 feet.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes.

The distance traveled by box = 20 + 10

                                                 = 30 feets

Thus, the distance must she travel so the two of you can travel at the same speed would be 30 feet.

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Answer:

no work done

Explanation:

unless you moved the object

When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.

Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:

Work done= Force* Displacement

When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.

Suppose that displacement is zero then,

W=f×0

Work done is zero

Thus, the work done is zero.

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Answer:

Work = (force) x (distance)

Work = (33N) x (13m) = 429 N-m = 429 joules

IF the force is in exactly the same direction as the motion of the wagon.

Explanation:

pa mark ng brainliest