Answers
Answer
Missing term in the sequence = 36
Explanation
Looking at the sequence, we can see that it is a geometric progression.
And the general form for the nth term of an geometric progression is
aₙ = a (rⁿ⁻¹)
where
aₙ = nth term = 3rd term
a = first term = 4
n = number of terms = 3
r = common ratio = ratio of consecitive terms = (second term)/(first term) = (fifth term)/(fourth term) = (12/4) = (324/108) = 3
For the third term now,
aₙ = a (rⁿ⁻¹)
a₃ = 4 (3³⁻¹)
a₃ = 4 (3²)
a₃ = 4 (9)
a₃ = 36
Hope this Helps!!!
Related Questions
Moore's Law predicts that the number of transistors that can be fit on a microchip willincrease by 41% every year. If microchips from a given year could hold about 949,000transistors, how many transistors could fit on a microchip 7 years later?If necessary, round your answer to the nearest whole number.transistors
Answers
The equation of a exponential growth function is equal to:
[tex]y=a(1+r)^x[/tex]Where:
y = the number of transistors
x = the number of years = 7 years
a = the initial value = 949,000
r = the rate of change = 41% = 0.41
Substitute the values:
[tex]y=949000(1+0.41)^7=949000(1.41)^7=10514775.41[/tex]Round to the nearest whole number: 10,514,775
Answer: 10,514,775 transistors
Find the area of the composite figure. First, find the area of the parallelogram. 12 cm Parallelogram Area = [?] cm2 :6 cm [ Triangle Area = [ ] cm2 L: 4 cm Total Area of Composite Figure = [] cm2 Enter
Answers
ANSWER
• Parallelogram Area = 72 cm²
,• Triangle Area = 24 cm²
,• Area of composite figure = 96 cm²
EXPLANATION
The area of a parallelogram is the product between the length of the base and the height of the parallelogram,
[tex]A_{parallelogram}=b\cdot h[/tex]In this case, b = 12cm and h = 6cm,
[tex]A_{parallelogram}=12cm\cdot6cm=72cm^2[/tex]The area of a triangle of base b and height h is,
[tex]A_{triangle}=\frac{b\cdot h}{2}[/tex]In this case, b = 12cm and h = 4cm,
[tex]A_{triangle}=\frac{12\operatorname{cm}\cdot4\operatorname{cm}}{2}=\frac{48cm^2}{2}=24cm^2[/tex]The area of the composite figure is the sum of the areas of the two figures,
[tex]A_{figure}=A_{parallelogram}+A_{triangle}=72cm^2+24cm^2=96cm^2[/tex]The total area of the composite figure is 96 cm²
could someone help me with number 4? as long as A, B, C
Answers
Part A.
To determine the volume of the barrel we use the formula for the volume of a cylinder:
[tex]V=r^2\pi h,[/tex]where r is the radius of the base of the cylinder and h is its height.
For the barrel:
[tex]\begin{gathered} h=27\text{ in, } \\ r=\frac{25\text{ in}}{2}=12.5in. \end{gathered}[/tex]Substituting the above values in the formula, we get:
[tex]V=13246.875in^3.[/tex]Answer part A:
[tex]V=13,246.875\imaginaryI n^3[/tex]Part B.
Recall that:
[tex]1\text{ gallon=231in}^3.[/tex]Answer part B: There are 231 cubic inches in 1 gallon.
Part C.
Diagram:
The barrel can contain 57 gallons of water, if it is at 2/3 of its capacity then there are
[tex]57gallons*\frac{2}{3}=38\text{ gallons}[/tex]of water inside the barrel.
Answer part C:
[tex]38\text{ gallons.}[/tex]Write an addition equation or subtraction equation your choice to describe the diagram. I will attach a screenshot of the problem I am confused with.
Answers
First, identify the length of each arrow and the corresponding sign:
Notice that the combination of both arrows represents the number -13.
Then, an equation that can be used to represent the same information as in the diagram, is:
[tex]-4-9=-13[/tex]Compute the exact value of the function for the given x-value without using a calculator.f(x) - 6* for x = -3
Answers
Answer
f(x) = (1/216)
when x = -3
Explanation
We are asked to find the value of f(x) when x = -3
f(x) = 6ˣ
When x = -3
f(x = -3) = 6⁻³ = (1/6³) = (1/216)
Hope this Helps!!!
Create an equation of a line that is perpendicular to the equation f (x) = 5x – 4
Answers
The given linear function is
[tex]f(x)=5x-4[/tex]This equation represents a straight line with a slope of 5. (Remember that the slope is the coefficient of the x).
Since we have to find a perpendicular line to f(x), we have to use the perpendicularity criteria to find the slope first:
[tex]m_1\cdot m_2=-1[/tex]Where the first slope is 5.
[tex]\begin{gathered} 5\cdot m_2=-1 \\ m_2=-\frac{1}{5} \end{gathered}[/tex]This means the new perpendicular line has a slope of -1/5.
Now, we use this slope, a random point (-1,2), and the point-slope formula, to find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-2=-\frac{1}{5}(x-(-1)) \\ y=-\frac{1}{5}(x+1)+2 \\ y=-\frac{1}{5}x-\frac{1}{5}+2 \\ y=-\frac{1}{5}x-\frac{1+10}{5} \\ y=-\frac{1}{5}x-\frac{11}{5} \end{gathered}[/tex]Therefore, a perpendicular line to f(x) would be[tex]y=-\frac{1}{5}x-\frac{11}{5}[/tex]A shoe store uses a 60% markup for all of the shoes it sells. What would be the selling price of apair of shoes that has a wholesale cost $55?
Answers
A shoe store uses a 60% markup for all of the shoes it sells. What would be the selling price of a
pair of shoes that has a wholesale cost $55?
we know that
the markup is the price spread between the cost to produce a good or service and its selling price
so
we have
100%+60%=160%=160/100=1.6
so
To find out the selling price, multiply the cost for 1.6
$55*1.6=$88
therefore
the answer is $88A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as editing) and variable costs (such as printing). The one-time fixed costs will total $43,400. The variable costs will be $10 per book. The publisher will sell the finished product to bookstores at a price of $22.50 per book. How many books must the publisher produce and sell so that the production costs will equal the money from sales?
Answers
Let x be the number of books. The cost of printing x books is given by:
[tex]C=10x+43400[/tex]The revenue for selling x books is given:
[tex]R=22.5x[/tex]Equating the expressions and solving for x we have:
[tex]\begin{gathered} 10x+43400=22.5x \\ 22.5x-10x=43400 \\ 12.5x=43400 \\ x=\frac{43400}{12.5} \\ x=3472 \end{gathered}[/tex]Therefore, the publisher needs to produce and sell 3472 books to break even
the population of sweden is about 1 11/16 times as great as the populaiton of denmark. find the population of sweden if the populatio of denmark is about 5,190,000
Answers
If the population of Sweden is about 1 11/16 times as great as the population of Denmark, and the population of Denmark is about 5,190,000, we get that the population of Sweden is about:
[tex](1\frac{11}{16})5,190,000=(\frac{27}{16})5,190,000=8,758,125[/tex]Answer: 8,758,125.
Chose the line with the grater slope. L1L2 Cannot be determined
Answers
step 1
Find the slope of the blue line
we need two points
so
looking at the graph
we take
(1,0) and (2,1)
m=(1-0)/(2-1)
m=1/1
m=1
step 2
Find the slope of the red line
we take the points
(0,1) and (1,0)
m=(0-1)/(1-0)
m=-1
step 3
Compare the values
1 is greater than -1
therefore
the blue line has a greater slopeDo you have the options for this question?
Complete the statements about the following numbers 2/7 0.1 0.9 6/8 the point closest to the benchmark one is at
Answers
SOLUTION
From the question, I understand you are asked which of the numbers are closest to 1
This becomes
[tex]\begin{gathered} \frac{2}{7}=0.3 \\ 0.1 \\ 0.9 \\ \frac{6}{8}=0.8 \end{gathered}[/tex]The largest decimal is 0.9, and it is the closest to 1. This is because 0.9 when rounded up gives 1 and it is the largest of all the decimals as we can see above.
Hence the answer is 0.9 is closest to the benchmark 1.
Given P(A)=0.8P(A)=0.8, P(B)=0.51P(B)=0.51 and P(A\cap B)=0.468P(A∩B)=0.468, find the value of P(B|A)P(B∣A), rounding to the nearest thousandth, if necessary.
Answers
Find the slope of a line parallel to the given line: 5x + y = 3
Answers
Answer
Slope of a line parallel to the given line = -5
Explanation
Two parallel lines have the same slopes.
So, if we obtain the slope of one line, we will obtain the slope of the other line.
The slope and y-intercept form of the equation of a straight line is given as
y = mx + b
where
y = y-coordinate of a point on the line.
m = slope of the line.
x = x-coordinate of the point on the line whose y-coordinate is y.
b = y-intercept of the line.
So, we need to put the given equation of the line in the y = mx + b form to obtain m.
5x + y = 3
y = -5x + 3
Comaparing this with y = mx + b
m = slope = -5
Hope this Helps!!!
So I got the first one answer thingy for the question right now I just need the other part
Answers
The original price was $105.04 and the discount is 10%.
Calculate the discount:
10 * 105.04 / 100 = 10.50
The discount is $10.50
The final (sale) price is:
$105.04 - $10.50 = $94.54
What is the slope of the line below? * A. y = 3x - 10B. y = 2x + 2C. y = -x + 2D. None of the above
Answers
Apply the slope formula.
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Where:
(x1,y1) = (3,-1)
(x2,y2)= (5,5)
Replacing:
[tex]m=\frac{5-(-1)}{5-3}[/tex][tex]m=\frac{5+1}{5-3}=\frac{6}{2}=3[/tex]The only option that has a slope =3
A. y=3x-10
Answer:
See below
Step-by-step explanation:
SLope is also = rise / run
from the two red points rise = 6 run = 2
6/2 = 3 = m = slope
Write each standard form:1. 7-4x=2x²2. 5+8x²=3x4. (x-2)(x+2) 5. 4x-6=106. 2x(x+3)=47. (x+1)²=08. (x+1)²=(x-4)²9. 3x(2x+5)=0
Answers
Given:
[tex]\begin{gathered} 7-4x=2x^2 \\ 5+8x^2=3x \\ 4(x-5)=15 \\ (x-2)(x+2) \\ 4x-6=10 \end{gathered}[/tex]Required:
To write the given equations in standard form.
Explanation:
Consider
[tex]\begin{gathered} 7-4x=2x^2 \\ 2x^2+4x-7=0 \\ \\ 5+8x^2=3x \\ 8x^2-3x+5=0 \\ \\ 4(x-5)=15 \\ 4x-20-15=0 \\ 4x-35=0 \\ \\ (x-2)(x+2)=0 \\ x^2-2x+2x-4=0 \\ x^2-4=0 \\ \\ 4x-6=10 \\ 4x-6-10=0 \\ 4x-16=0 \end{gathered}[/tex]Final Answer:
[tex]\begin{gathered} 1)2x^2+4x-7=0 \\ \\ 2)8x^2-3x+5=0 \\ \\ 3)4x-35=0 \\ \\ 4)x^2-4=0 \\ \\ 5)4x-16=0 \end{gathered}[/tex]Determine which measure(s) of center would best reflect the data and explain how you know
Answers
If we rearrage the data in ascending order,we get:
[tex]\begin{gathered} 9,10,10,10,10,10,10,10,11,11,11,11,11,11,12,12,12,12,12,13,13, \\ 13,13,14,14,14,14,15,15,15,15,15,15,15,16,17,17,17,17,17 \end{gathered}[/tex]notice that the median in this case is m = 13, while for the mean, we have:
[tex]\begin{gathered} \mu=\frac{9+7(10++6(11)+5(12)+4(13)+7(15)+16+5(17)}{40} \\ =\frac{9+70+66+60+52+56+105+16+85}{40}=\frac{519}{40}=12.98 \\ \mu=12.98 \end{gathered}[/tex]as we can see, the mean is nearly the same value as the median. This is evident since there are no outliers on the data. Thus, the median or the mean can be used to describe the dataset
Imagine you are in an argument with your sibling or friends about the size of the slice of pizza that you were both served. They say that it was unfair because you got a bigger piece. What information would you need to know about each slice of pizza in order to calculate which one had a larger area? Explain (Hint: remember the formula for the area of a sector of a circle!!)
Answers
Ok, so
Remember that the formula of the area of a sector of a circle is given by:
[tex]A=\frac{1}{2}r^2\theta[/tex]Where r is the radius of the circle and Θ is the angle (in radians) of the sector.
Therefore, we would need to know the radius of the pizza, and the angle of each slice of pizza in order to calculate which one had a larger area.
Use Cramer's Rule to find the solution of the system of linear equations, if a unique solution exists.–5x + 2y – 2z = 263x + 5y + z = –22–3x – 5y – 2z = 21(–1, –7, 2)(–6, –1, 1)(–1, 3, 1)no unique solution
Answers
A system of three equations with three unknowns can be written in matrix form as shown below:
[tex]\begin{gathered} a_1x+b_1y+c_1z=d_1 \\ a_2x+b_2y+c_2z=d_2 \\ a_3x+b_3y+c_3z=d_3 \\ \Leftrightarrow \\ \begin{bmatrix}{a_1} & {b_1} & {c_1} \\ {a_2} & {b_2} & {c_2} \\ {a_3} & {b_3} & {c_3}\end{bmatrix}\begin{bmatrix}{x} & {} & \\ {y} & {} & \\ {z} & {} & {}\end{bmatrix}=\begin{bmatrix}{d_1} & & {} \\ {d_2} & {} & {} \\ {d_3} & {} & {}\end{bmatrix} \end{gathered}[/tex]Then, x, y, and z are given by the expressions:
[tex]x=\frac{\det(\begin{bmatrix}{d_1} & {b_1} & {c_1} \\ {d_2} & {b_2} & {c_2} \\ {d_3} & {b_3} & {c_3}\end{bmatrix})}{\det(\begin{bmatrix}{a_1} & {b_1} & {c_1} \\ {a_2} & {b_2} & {c_2} \\ {a_3} & {b_3} & {c_3}\end{bmatrix})},y=\frac{\det(\begin{bmatrix}{a_1} & {d_1} & {c_1} \\ {a_2} & {d_2} & {c_2} \\ {a_3} & {d_3} & {c_3}\end{bmatrix})}{\det(\begin{bmatrix}{a_1} & {b_1} & {c_1} \\ {a_2} & {b_2} & {c_2} \\ {a_3} & {b_3} & {c_3}\end{bmatrix})},z=\frac{\det(\begin{bmatrix}{a_1} & {b_1} & {d_1} \\ {a_2} & {b_2} & {d_2} \\ {a_3} & {b_3} & {d_3}\end{bmatrix})}{\det(\begin{bmatrix}{a_1} & {b_1} & {c_1} \\ {a_2} & {b_2} & {c_2} \\ {a_3} & {b_3} & {c_3}\end{bmatrix})}[/tex]Then, in our problem:
[tex]\begin{bmatrix}{-5_{}} & {2_{}} & {-2_{}} \\ {3_{}} & {5_{}} & {1_{}} \\ {-3_{}} & {-5_{}} & {-2_{}}\end{bmatrix}\begin{bmatrix}{x} & {} & \\ {y} & {} & \\ {z} & {} & {}\end{bmatrix}=\begin{bmatrix}{26_{}} & & {} \\ {-22_{}} & {} & {} \\ {21_{}} & {} & {}\end{bmatrix}[/tex]Therefore, x is equal to
[tex]\begin{gathered} \Rightarrow x=\frac{\det(\begin{bmatrix}{26_{}} & {2_{}} & {-2_{}} \\ {-22_{}} & {5_{}} & {1_{}} \\ {21_{}} & {-5_{}} & {-2_{}}\end{bmatrix})}{\det(\begin{bmatrix}{-5_{}} & {2_{}} & {-2_{}} \\ {3_{}} & {5_{}} & {1_{}} \\ {-3_{}} & {-5_{}} & {-2_{}}\end{bmatrix})},=\frac{-186}{31}=-6 \\ \Rightarrow x=-6 \end{gathered}[/tex]Therefore, x= -6
As for y,
[tex]\begin{gathered} y=\frac{\det(\begin{bmatrix}{-5_{}} & {26_{}} & {-2_{}} \\ {3_{}} & {-22_{}} & {1_{}} \\ {-3_{}} & {21_{}} & {-2_{}}\end{bmatrix})}{\det(\begin{bmatrix}{-5_{}} & {2_{}} & {-2_{}} \\ {3_{}} & {5_{}} & {1_{}} \\ {-3_{}} & {-5_{}} & {-2_{}}\end{bmatrix})}=\frac{-31}{31}=-1 \\ \Rightarrow y=-1 \end{gathered}[/tex]Thus, y= -1.
Finally solving for z:
[tex]\begin{gathered} z=\frac{\det (\begin{bmatrix}{-5_{}} & {2_{}} & {26_{}} \\ {3_{}} & {5_{}} & {-22_{}} \\ {-3_{}} & {-5_{}} & {21_{}}\end{bmatrix})}{\det (\begin{bmatrix}{-5_{}} & {2_{}} & {-2_{}} \\ {3_{}} & {5_{}} & {1_{}} \\ {-3_{}} & {-5_{}} & {-2_{}}\end{bmatrix})}=\frac{31}{31}=1 \\ \Rightarrow z=1 \end{gathered}[/tex]Hence, z=1
The answer is (-6, -1, 1)
how do i od this linear equation in slope form
Answers
y = -x + 4
The correct option is B
Explanation:Given the point (1, 3) and (3, 1)
The equation of a line is given as:
y = mx + b
Where m is the slope and b is the y-intercept.
To obtain the slope, we use the formula:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ =\frac{1-3}{3-1}=\frac{-2}{2}=-1 \end{gathered}[/tex]The equation now becomes:
y = -x + b
We can use the point (1, 3) to obtain the y-intercept. Using x = 1, and y = 3
3 = -1 + b
b = 3 + 1 = 4
Finally, we can write the equation as:
y = -x + 4
1Find the 9th term of the geometric sequence whose common ratio is 1/2and whose first term is 6.
Answers
General category: Sequences, Series, and Mathematical Induction
Sub-category: Formulas and Notation for Sequences and Series
Topic: Recursive Formulas and explicit Formulas.
Introduction:
Given a geometric sequence with the first term a_1 and the common ratio r, the nth term is given by the following formula:
[tex]a_n=a_1\cdot r^{n\text{ -1}}[/tex]Explanation:If we have a geometric sequence whose common ratio is 1/2 and whose first term is 6, then the nth term is given by the following formula:
[tex]a_n=6\cdot(\frac{1}{2})^{n\text{ -1}}[/tex]thus, if n= 9, we get:
[tex]a_9=6\cdot(\frac{1}{2})^{9\text{ -1}}[/tex]that is:
[tex]a_9=6\cdot(\frac{1}{2})^8[/tex]this is equivalent to:
[tex]a_9=\frac{6}{2^8}=\frac{6}{256}=\frac{3}{128}[/tex]we can conclude that the correct answer is:
Answer:The 9th term is:
[tex]\frac{3}{128}[/tex]<45Can a matrix with dimensions of 3 X 6 be added to another matrix with dimensions of 6 X 3?O yesO no
Answers
No
1) Since when adding matrices they both must share the same number of rows and columns. Then we can not add matrices with different dimensions.
2) Hence, the answer is No
Find the distance between the two points.(-3, -1) (-1,-5) We have to use a^2 + b^2 = c^2
Answers
The formula between the distance (c) is,
[tex]c=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Where,
[tex]\begin{gathered} a=(x_2-x_1) \\ b=(y_2-y_1) \end{gathered}[/tex]Given
[tex]\begin{gathered} (x_1,y_1)=(-3,-1) \\ (x_2,y_2)=(-1,-5) \end{gathered}[/tex]Therefore,
[tex]c=\sqrt{(-1--3)^2+(-5--1)^2}[/tex]Simplify
[tex]\begin{gathered} c=\sqrt{(-1+3)^2+(-5+1)^2}=\sqrt{2^2+(-4)^2}=\sqrt{4+16}=\sqrt{20}=\sqrt{4\times5} \\ c=\sqrt{4}\times\sqrt{5}=2\times\sqrt{5}=2\sqrt{5}=\:4.47213\approx4.5 \end{gathered}[/tex]Hence, the answer is
[tex]c=4.5[/tex]Hello! I am needing some reassurance please. Just the top question.
Answers
ANSWER
840
EXPLANATION
Lauren has 7 trophies and wants to know how many possible arrangements with 4 trophies there are. If we want to know how many different arrangements, then order matters so we would use a permutation.
But we can also think it logically and we will get the same answer if we do it right. Let's see, for the first shelf space, there are 7 trophies available to pick from. Then for the second shelf space, there are 6 trophies left. Then, for the third space, there are 5 trophies left and, finally, for the fourth space there are 4 trophies to pick from,
[tex]7\cdot6\cdot5\cdot4=840[/tex]If we do it with a permutation,
[tex]_7P_4=\frac{7!}{(7-4)!}=\frac{7!}{3!}=\frac{7\cdot6\cdot5\cdot4\cdot3!}{3!}=7\cdot6\cdot5\cdot4=840[/tex]Hence, there are 840 possible arrangements.
A hot air balloon is rising. The expression 120 + 2t represents theheight of the hot air balloon in meters after t seconds. Use theexpression to find the height of the balloon after 15 s.Show your work. .
Answers
We are told that the height of the ballon after t seconds is given by the equation
[tex]\text{height}=120+2t[/tex]and we are asked to find the height after 15 seconds.
To answer this question we simply put in t =15 in the above formula to get
[tex]\text{height}=120+2(15)[/tex]This gives
[tex]\text{height}=120+30[/tex][tex]\text{height}=150m[/tex]Hence, the height of the ballon after 15 s is 150m
.
5. An observer located 3 km from a rocket launch site sees a rocket at an angle of elevation of 38°. How high is the rocket at that moment?
Answers
We solve as follows:
+First, we determine the value of the hypotenuse:
[tex]\cos (38)=\frac{3}{h}\Rightarrow h=\frac{3}{\cos(38)}\Rightarrow h\approx3.8[/tex]Now, we use this to find the missing side (the altitude of the rocket):
[tex]a=\sqrt[]{(\frac{3}{\cos(38)})^2-3^2}\Rightarrow a\approx2.34[/tex]So, the rocket had an altitude of approximately 2.34 Km.
Which statement is an example of the identify property of multiplication?8x0=08x1=88•-1=-8-8•-1=-8What is another way to write-3•(4+7)?-3•4+7-3•4•7-3•4+4•7-3•4+(-3)•7Which property is represented by 5+(-8)=-8+5?IdentityAssociativeCommutativeDistributive
Answers
Identity property of multiplication indicates that when the "1" is is multiplied with any other number, the answer will be the number.
From the question, the statement that is an example of identity property of multiplication is:
8 x 1=8
What is the product of (2x - 5)(2x + 5)?A. 4x²-25B. 4x2+20x-25C. 4x2² - 10D. 4x² + 20x-10
Answers
Explanation
The product of (2x - 5)(2x + 5) can be seen below.
[tex]\begin{gathered} \left(2x-5\right)\left(2x+5\right) \\ =2x\left(2x+5\right)-5\left(2x+5\right) \\ =4x^2+10x-10x-25 \\ =4x^2-25 \end{gathered}[/tex]I have an online class and I need a little help please. I just need the domain and range.
Answers
TED BORROWED $1,200 FOR TWO YEARS AND HE MADE MONTHLY PAYMENTS. IF THE TOTAL FINANCE CHARGE IS $175.92 WHAT IS THE APR? ANNUAL PERCENT RATE?
Answers
Given:
The borrowed amount is $1200.
The finance charge is $175.92
The period of time =2 years ( 24 months)
Required:
We need to find APR.
Explanation:
Let r be the APR.
The monthly interest rate is r/12.
[tex]Total\text{ amount =1200+175.92=1375.92}[/tex]P=1200 and t =24.
[tex]Total\text{ amount =P\lparen1+}\frac{r}{n}\text{\rparen}^{nt}[/tex][tex]1375.92=1200(1+\frac{r}{12})^{12\times2}[/tex][tex]1375.92=1200(1+\frac{r}{12})^{24}[/tex][tex]\frac{1375.92}{1200}=\frac{1200}{1200}(1+\frac{r}{12})^{24}[/tex][tex]1.1466=(1+\frac{r}{12})^{24}[/tex][tex]1.00571631955=1+\frac{r}{12}[/tex][tex]1.00571631955-1=\frac{r}{12}[/tex][tex]0.00571631955\times12=r[/tex][tex]0.06859583463=r[/tex]Multiply by 100, to find APR
[tex]6.86\text{ \%}=APR[/tex]Final answer:
[tex]APR=6.82\text{ \%}[/tex]