Answer:
E) Two of the above statements are true.
Explanation:
The options are:
A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin. TRUE. Before the solution is titrated, there is an excess of NaOH (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of HCl, the pH is acidic and phenolphtalein is colorless.
B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added. FALSE. As was explained, before the titration, the solution is pink.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. TRUE. Aspirin requires an excess of base (NaOH) for a complete dissolution (Hydrolysis). Then, we add H+ as HCl to know the excess moles of OH-. As we know the added moles of OH-, we can find the moles of OH that reacted = Moles of aspirin.
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin. FALSE. NaOH can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely
E) Two of the above statements are true. TRUE
Right option is:
E) Two of the above statements are true.In this exercise it is necessary to identify the true alternatives and the false alternatives. Thus, classifying these alternatives we have:
A) True
B) False
C) True
D) False
E) True
So we can say that: Two of the above statements are true.
The options are:
A) Before the solution is titrated with [tex]HCl[/tex] it is pink and when the color changes from pink to colorless, the moles of [tex]H*(aq)[/tex] equals the moles of [tex]OH"(aq)[/tex] used in the hydrolysis of the neutralized aspirin. TRUE. Before the solution is titrated, there is an excess of [tex]NaOH[/tex] (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of [tex]HCl[/tex], the pH is acidic and phenolphtalein is colorless.
B) Before the solution is titrated with [tex]HCl[/tex] it is colorless and when the color changes from colorless to pink, the moles of [tex]H*(aq)[/tex] equals the excess moles of [tex]OH(aq)[/tex] added. FALSE. As was explained, before the titration, the solution is pink.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with [tex]HCl[/tex] allows us to determine the moles of excess [tex]OH(aq)[/tex] added. Once we determine the moles of excess [tex]OH(aq)[/tex], we can determine moles of [tex]OH"(aq)[/tex] used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. TRUE. Aspirin requires an excess of base [tex](NaOH)[/tex] for a complete dissolution (Hydrolysis). Then, we add [tex]H+[/tex] as [tex]HCl[/tex] to know the excess moles of [tex]OH-[/tex]. As we know the added moles of [tex]OH-[/tex], we can find the moles of [tex]OH[/tex] that reacted (Moles of aspirin).
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the [tex]0.100 M NaOH[/tex] to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the [tex]0.100 M HCl[/tex] is to confirm the moles of aspirin in the recrystallized aspirin. FALSE. [tex]NaOH[/tex] can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely
E) Two of the above statements are true. TRUE
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Practice by predicting what would happen if the following underwent beta decay: (2
iv. Carbon -10 __________+ _____
v. Cesium-137 __________+ _____
vi. Thorium-234 __________+ _____
Answer:
See explanation and image attached
Explanation:
During beta emission, neutrons are converted into protons and electrons. The anti neutrino balances the spins.
When a nucleus undergoes beta emission, the mass number of the daughter nucleus produced in the process is the same as that of the parent nucleus but the atomic number of the daughter nucleus increases by one unit.
The product of the beta decay of the nuclides shown in the question is described in the image attached to this answer.
Solid strontium chromate, SrCrO4, dissolves into its respective ions at 25°C. Suppose that in a particular solution, [Sr^2+]=6.0x10^-3M. Find the value of Ksp.
A) 3.6 x 10^-5
B) 6.0 x 10^-3
C) 3.6 x 10^-2
D) 7.7 x 10^-2
Answer:
A) 3.6 x 10^-5.
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary to write the equilibrium expression for the dissociation of strontium chromate:
[tex]Ksp=[Sr^{2+}][CrO_4^{2-}][/tex]
Thus, since strontium and chromate ions are in a 1:1 mole ratio, we can tell the concentration of both ions as the same; and therefore, the Ksp is:
[tex]Ksp=(6.0x10^{-3}M)(6.0x10^{-3}M)\\\\Ksp=3.6x10^{-5}[/tex]
Or option A) 3.6 x 10^-5.
Regards!
In what kind of orbitals do the lone-pair electrons on the singly bonded oxygen of methyl acetate reside, and are they in the same plane as the group
Answer:
Both lone pairs reside in sp3 orbitals; they are co-planar with the CH3 group.
Explanation:
In the compound, methyl acetate, the lone-pair of electrons on the singly bonded oxygen atom is accommodated in sp3 hybridized orbitals.
If we look at the compound, we will notice the both lone pair of electrons on oxygen are accommodated in sp3 orbitals which are co-planar with the CH3 group in the molecule.
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 7.40 moles of magnesium perchlorate, Mg(ClO4)2. Express the number of moles of Mg, Cl, and O atoms numerically, separated by commas.
Answer:
Number of moles Magnesium (Mg) = 7.40 moles
Number of moles Chlorine (Cl) = 14.8 moles
Number of moles of oxygen atoms = 29.6 moles
7.40;14.8;29.6
Explanation:
Step 1: Data given
Number of moles of magnesium perchlorate, Mg(ClO4)2 = 7.40 moles
Step 2: Calculate number of moles
In 1 mol of magnesium perchlorate, Mg(ClO4)2, we have:
1 Mol Magnesium (Mg)
2 moles of Chlorine (Cl)
8 moles of oxygen (O)
This means that for 1 mol of magnesium perchlorate, Mg(ClO4)2, we have the same amount of moles Magnesium (Mg), the double amount of moles of Chlorine (Cl) and 4x the amount of moles of oxygen (O)
Number of moles Magnesium (Mg)= 1 * 7.40 moles = 7.40 moles
Number of moles Chlorine (Cl) = 2 * 7.40 moles = 14.8 moles
Number of moles of oxygen atoms = 4 * 7.40 moles = 29.6 moles
7.40;14.8;29.6
Density is the ratio of a sample's mass to its volume. A bar of lead has a mass of 115.2 g. When it is submerged in 25.0 mL of water in a graduated cylinder, the water level rises to 35.5 mL. What is the density of the lead
Answer:
[tex]$10.97 \ g/cm^3$[/tex]
Explanation:
Given :
Mass of a bar of lead = 115.2 g
Initial water level [tex]$\text{in the graduated cylinder}$[/tex] = 25 mL
Final water level [tex]$\text{in the graduated cylinder}$[/tex] = 35.5 mL
Difference in the water level = 35.5 - 25
= 10.5 mL
= [tex]10.5 \ cm^3[/tex]
We know that when a body is submerged in water, it displaces its own volume of water.
Therefore, the volume of the lead bar = volume of the water displaced = 10.5 mL = [tex]10.5 \ cm^3[/tex]
We know that mathematically, density is the ratio of mass of body to its volume.
Density of the lead bar is given by :
[tex]$\rho =\frac{\text{mass}}{\text{volume}}$[/tex]
[tex]$\rho =\frac{\text{115.2 g}}{\text{10.5 cm}^3}$[/tex]
= [tex]$10.97 \ g/cm^3$[/tex]
Rank the following four isomeric hydrocarbons in order of increasing stability: - cis-1,4-Dimethylcyclohexane - 1-Cyclopropylpentane - Ethylcyclohexane - cis-1-Ethyl-2-propylcyclopropane
Answer:
cis-1-Ethyl-2-propylcyclopropane <1-Cyclopropylpentane <cis-1,4-Dimethylcyclohexane <Ethylcyclohexane
Explanation:
The least is the number of additives especially at the position 1,4 of the cyclohexane, the more is the stability.
Hence, the correct order of increasing stability is
cis-1-Ethyl-2-propylcyclopropane <1-Cyclopropylpentane <cis-1,4-Dimethylcyclohexane <Ethylcyclohexane
The atomic particle with a charge of -1.6 x 10-19 C is
Explanation:
Proton +1.60 x 10-19 C 1.672 x 10-24 g
Electron -1.60 x 10-19 C 9.05 x 10-28 g
Neutron neutral 1.674 x 10-24 g
Identify the components of tourism and hospitality and discuss?
Answer: he basic components or 4'A' s of tourism are as follows:
ATTRACTION: It is the most important element & object that attract people to travel. ...
ACCESSIBILITY: It is important key factor for the development of tourism. ...
ACCOMMODATION: -It includes food & lodging facilities to the guest. ...
AMENITIES:
What are the components of tourism and hospitality?
Accommodations and.
Lodging.
Recreation and.
Entertainment.
Travel Services.
Food and Beverage Services.
Conventions and Event.
Management.
Explanation:
NOT MY WORDS! I HOPE ThIS HELPS!
How much energy would it take to freeze 12.5 g of water?
The amount of energy needed to freeze 12.5 grams of water into ice is equals to 14.295 kilo joules.
How do we calculate energy?Energy required to freeze water will be calculated by using the following equation as:
Q = mcT, where
m = mass of water = 12.5g = 0.0125kg
c = specific heat of water = 4.187 kJ/kg.K
T = temperature to freeze = 0 degree C = 273.15 K
On putting values we get,
Q = (0.0125)(4.187)(273.15)
Q = 14.295 kJ
Hence required amount of energy is 14.295 kJ.
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plz who can help me i have a final project and i am ready to pay 20$
Answer:
hey friend
how can I help you
HELP PLEASE!!!!!
Can someone please help me I should submit it today and the answer should be as paragraph
Answer:
National fire protection Association
Explanation:
the nfpa is a global self funded nonprofit orgnazation establised in 1896 devoted to eliminating death injury protery loss and ecomomic loss due to fire and electrical hazards
how to find the group number of f block elements
Answer:
I hope you understand please follow me please
g An ionic bond involves ____ a. molecules that gain or lose an atom to develop a bonding charge b. molecules that bond together through a weak force c. atoms that either lose or gain an electron in order to bond d. atoms that share an electron to tightly bond
Answer:
a. molecules that gain or lose an atom to develop a bonding charge
Explanation:
Given a 0.200 M solution of anserine at its isoelectric point and ready access to 0.100 M HCl, 0.100 M NaOH and distilled water, describe the preparation of 1 L of 0.0400 M anserine buffered solution, pH 7.20.
Solution :
Given :
Amount of anserine solution = 0.200 M
pH value is = 7.20
Preparation of 0.04 M solution of anserine from the 0.2 M solution.
0.2 M x [tex]x[/tex] = 0.04 M x 1000 ml
[tex]x[/tex] = 200 ml
So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.
0.1 M x [tex]x[/tex] = 0.04 x 1000 ml
[tex]x[/tex] = 400 ml
Therefore, 400 ml of HCl is needed.
True or false
Bases will have a relatively high concentration of hydroxide ions and a pH around 10.
Answer:
false
Explanation:
It is because the pH for Hydroxide ions is 7
Answer:
True
Explanation:
Acids have a low concentration of hydroxide ions and a pH of 1-6, while bases have a high concentration of hydroxide ions and a pH of 8-14
13. (08.04 LC)
Which type of substance ionizes partially and gives off hydrogen ions when dissolved in water? (5 points)
a. Strong acid
b. Strong base
c. Weak acid
d. Weak base
anyone know??? HELPPPPP
Answer:
c. Weak acid
Explanation:
A substance that gives off hydrogen ions (H⁺) when dissolved in water is an acid.An acid that ionizes only partially when dissolved in water is a weak acid.Thus the correct answer is option c. Weak acid.
A strong acid would ionize completely, while a base would give off hydroxide ions (OH⁻).
Write balanced equations and solubility product expressions for the following compounds
a. CuBr
b. ZnC2O4
c. Ag2CrO4
d. Hg2Cl2
e. AlCl3
f. Mn3(PO4)3
Explanation:
Solubility product is defined as the product of the concentrations or solubilities of the ions each raised to the power their stoichiometric coefficients present in the solution. It is expressed as [tex]K_{sp}[/tex].
(a): CuBr
The chemical equation for the dissociation of CuBr into its ions follows:
[tex]CuBr\rightleftharpoons Cu^++Br^-[/tex]
The expression of [tex]K_{sp}[/tex] for CuBr follows:
[tex]K_{sp}=[Cu^+][Br^-][/tex]
(b): [tex]ZnC_2O_4[/tex]
The chemical equation for the dissociation of [tex]ZnC_2O_4[/tex] into its ions follows:
[tex]ZnC_2O_4\rightleftharpoons Zn^{2+}+C_2O_4^{2-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]ZnC_2O_4[/tex] follows:
[tex]K_{sp}=[Zn^{2+}][C_2O_4^{2-}][/tex]
(c): [tex]Ag_2CrO_4[/tex]
The chemical equation for the dissociation of [tex]Ag_2CrO_4[/tex] into its ions follows:
[tex]Ag_2CrO_4\rightleftharpoons 2Ag^{+}+CrO_4^{2-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]Ag_2CrO_4[/tex] follows:
[tex]K_{sp}=[Ag^{+}]^2[CrO_4^{2-}][/tex]
(d): [tex]ZnC_2O_4[/tex]
The chemical equation for the dissociation of [tex]Hg_2Cl_2[/tex] into its ions follows:
[tex]Hg_2Cl_2\rightleftharpoons 2Hg^{+}+2Cl^{-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]Hg_2Cl_2[/tex] follows:
[tex]K_{sp}=[Hg^{+}]^2[Cl^{-}]^2[/tex]
(e): [tex]AlCl_3[/tex]
The chemical equation for the dissociation of [tex]AlCl_3[/tex] into its ions follows:
[tex]AlCl_3\rightleftharpoons Al^{3+}+3Cl^{-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]AlCl_3[/tex] follows:
[tex]K_{sp}=[Al^{3+}][Cl^{-}]^3[/tex]
(f): [tex]ZnC_2O_4[/tex]
The chemical equation for the dissociation of [tex]Mn_3(PO_4)_2[/tex] into its ions follows:
[tex]Mn_3(PO_4)_2\rightleftharpoons 3Mn^{2+}+2PO_4^{3-}[/tex]
The expression of [tex]K_{sp}[/tex] for [tex]Mn_3(PO_4)_2[/tex] follows:
[tex]K_{sp}=[Mn^{2+}]^3[PO_4^{3-}]^2[/tex]
1. Make ___________________
Observe an event. State only what we can
________ or ____________.
2. Ask ___________________
Ask a question that helps us find out _______ and _______ the event happened. We must be
able to answer the question with ________, or ________. We may need to __________ our question several times before it is__________.
3. Construct a_____________________
State the answer we think we’ll get when we ask
our question. This is called a
_________________. It’s based on our best
understanding of the event.
4. Test the hypothesis with an
_______________________
Test whether the hypothesis is ___________.
During the investigation, we collect _______ that
answers the testable question we asked.
Answer:
Explanation:
ANCHOR ANCHOR ANCHOR ANCHOR
predict the major and minor products of the reaction. name the products using systematic names. ch3ch=ch2+h2o-->h+
Answer:
major will be propan-2-ol
minor will be propan-1-ol
The temperature of 10 kg of a substance rises by 55oC when heated. Calculate the temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Answer:
The temperature rise is 25°C
Explanation:
The heat of a substance is obtained using the equation:
Q = m*S*ΔT
Where Q is heat in kJ, m is the mass of the susbtance, S is specific heat of the material and ΔT change in temperature.
Replacing:
Q/S = m*ΔT
As Q is constant because the heat is the same and S is the specific heat of the material (Constant). We can write:
m1*ΔT1 = m2*ΔT2
Where m is mass and ΔT change in temperature of 1, initial conditions of the substance and 2, final conditions of the substance.
Replacing:
m1 = 10kg
ΔT1 = 55°C
m2 = 22kg
ΔT2 = ?
10kg*55°C = 22kg*ΔT2
ΔT2 = 25°C
The temperature rise is 25°C
what is the correct symbol for the element copper
Answer:
the correct symbol for copper is:CUAnswer:Cu
Explanation
First letter is usually capital then the other letters are usually in small letters
Someone plssss help meeee !!!! How much energy is required to vaporize 112 g of water? ???
Answer:
6.05 × 10⁴ cal
Explanation:
Step 1: Given and required data
Mass of water (m): 112 g
Enthalpy of vaporization of water (ΔHvap): 540 cal/g
Step 2: Calculate how much energy is required to vaporize 112 g of water
Vaporization is a physical change in which a substance goes from the liquid state to the gaseous state. We can calculate the energy required (Q) using the following expression.
Q = ΔHvap × m
Q = 540 cal/g × 112 g = 6.05 × 10⁴ cal
How many tons are contained in 825 megagrams?
Answer:909
Explanation:
PLZ Answer ASAP
I need help with this thank you if you get it right
Answer:
A) -277.6 KJ/mol
Explanation:
The enthalpy data for first equation is not given but it should be somewhere around ΔH = –1367 kJ/mol.
So, Basically you want to rearrange the given three equations to match the equation they want you to have. To get the final equation, reverse reaction first reaction (turn its value into positive), multiply second equation by 2, multiply third equation by 3 and you add em all up:
You get 1367 + (2* -393.5) + (3 * -285.8) ~ -277.6 KJ/mol
A metal forms the fluoride MF3. Electrolysis of the molten fluoride by a current of 3.86 A for 16.2 minutes deposits 1.25 g of the metal. Calculate the molar mass of the metal.
Answer: The molar mass of the metal is 96.45 g/mol
Explanation:
The fluoride of the metal formed is [tex]MF_3[/tex]
The oxidation half-reaction follows:
[tex]M\rightarrow M^{3+}+3e^-[/tex]
Calculating the theoretical mass deposited by using Faraday's law, which is:
[tex]m=\frac{M\times I\times t(s)}{n\times F}[/tex] ......(1)
where,
m = actual mass deposited = 1.25 g
M = molar mass of metal = ?
I = average current = 3.86 A
t = time period in seconds = 16.2 min = 972 s (Conversion factor: 1 min = 60 sec)
n = number of electrons exchanged = [tex]3mol^{-1}[/tex]
F = Faraday's constant = 96500 C
Putting values in equation 1, we get:
[tex]1.25g=\frac{M\times 3.86A\times 972s}{3mol^{-1}\times 96500 C}\\\\M=\frac{1.25g\times 3mol^{-1}\times 96500 C}{3.86A\times 972s}\\\\M=96.45g/mol[/tex]
Hence, the molar mass of the metal is 96.45 g/mol
The molar mass of metal present in MF₃ is calculated by using faraday's law and is equal to 96.45 g/mole.
How we calculate the molar mass?Molar mass of the metal will be calculated by using the Faraday's law as:
m = (M × I × t(s)) / n × F.
Chemical reaction for the given metal will be represented as:
M → M³⁺ + 3e⁻
And according to the Faraday's law given entities are:
m = given deposited mass = 1.25 g
I = average current = 3.86 A
t = time period in seconds = 16.2 min = 972 s
n = number of electrons exchanged = 3
F = Faraday's constant = 96500 C
M = molar mass of metal = to find?
Putting all these values in the above equation and calculate for M as:
M = (1.25)(3)(96500) / (3.86)(972) = 96.45 g/mole
Hence, the molar mass of metal is 96.45 g/mole.
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30 POINTS! PLEASE HELP!! WILL GIVE BRAINLIEST
----- Will report you if you comment for just the points -----
Identify the number of electrons each of the following atoms needs to gain or lose to have a stable outer electron configuration:
Sulfuric acid:
Calcium nitrate:
Sucrose:
Ammonium phosphate
Answer:
Sulfuric acid (American spelling) or sulphuric acid (Commonwealth spelling), also known as oil of vitriol, is a mineral acid composed of the elements sulfur, oxygen and hydrogen, with molecular formula H2SO4. It is a colorless, odorless and viscous liquid that is miscible with water.
Calcium nitrate is produced by applying nitric acid to limestone and then adding ammonia. It is known as a double salt, since it is comprised of two nutrients common in fertilizers which are high in sodium. The processed result also looks crystallized like salt.
Sucrose is common sugar. It is a disaccharide, a molecule composed of two monosaccharides: glucose and fructose. Sucrose is produced naturally in plants, from which table sugar is refined. It has the molecular formula C₁₂H₂₂O₁₁.
Explanation:
BRO YOU CAN TRUST ME XD ♥️♥️
Which represents the correct equilibrium constant expression for the reaction below?
Answer:
b
Explanation:
because it is products /reactants :)
Write the reaction of maleic acid with Br2
A balloon filled with air has a volume of 4.24 liters at 23.00°C. If the balloon is cooled at a constant pressure to 5.00°C, what is the new volume?
if The difference in height of mercury in the two arms is 435 mm. What is the pressure of the nitrogen gas in kPa?
Answer:
Therefore, Pnitrogen=97.5kpa
Explanation:
100.0-2.49
=97.5
435= i don't know