The nth term of a sequence is n2 + 5 (a) (i) Find the first two terms of this sequence. (ii) Is 126 a term of this sequence? You must show how you get your answer​

Quantum numbers describe the states of electrons in their respective orbitals in an atom.

Quantum numbers are mathematical descriptions that show the possible states of an electron.

There are four types of quantum number

principal quantum number (n)

angular momentum quantum number (l)

magnetic quantum number (ml)

spin quantum number (ms)

The values for the principal quantum number (n) are integers greater than zero.

The values for the angular momentum quantum number (l) are integers from 0 to n - 1.

The values for the magnetic quantum number (ml) are integers from -l to l.

The values for the spin quantum number (ms) are -1/2 and 1/2.

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Answer:

4

Step-by-step explanation:

2+2=4

I hope this helps you!!

Answer:

I believe this is what they are asking on your problem.

Answer:

3

Step-by-step explanation:

I hope its helped<8 thank you

Answer: this is a function.

f(x)=y

Step-by-step explanation:

domain -> 1,2,3

values: 3,7,-1

Since the horizontal lines are parallel, we can set the angles equal to each other. So...

7x - 1 = 8x - 14

Solving for x...

x = 13

[tex]\bf \colorbox{black} {\bf {\textcolor{blue}{ }{ \bf { \textcolor{orange}{ }{ \bf{ \textcolor{cyan}{mathematics = }}}}}}}[/tex]

(3×2-2)+(5×2+5×-1)=

(6-2)+(10-5)=

4+5=

[tex] \bf \textcolor{green}{ \underbrace{9}}[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's simplify ~

[tex]\qquad \sf  \dashrightarrow \:(3 \times 2 - 2) + (5 \times 2 + 5 \times ( - 1))[/tex]

Use BODMAS/PEDMAS rule here :

[tex]\qquad \sf  \dashrightarrow \:(6- 2) + (10 + ( - 5))[/tex]

[tex]\qquad \sf  \dashrightarrow \:4 + (10 - 5)[/tex]

[tex]\qquad \sf  \dashrightarrow \:4 + 5[/tex]

[tex]\qquad \sf  \dashrightarrow \:9[/tex]

Hope it helps you ~

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

Answer:

Simplify the radical by breaking the radicand up into a product of known factors.

Exact Form:

3

√

75

5

Decimal Form:

0.84343266

…

Answer:

[tex]\frac{27}{125}[/tex]

Step-by-step explanation:

[tex](\frac{3}{5})^{3}[/tex] is [tex]\frac{3^{3}}{5^{3}}[/tex]

[tex]3^{3} = 27[/tex] and [tex]5^{3} = 125[/tex]

[tex]\frac{27}{125}[/tex]

There are 16 fruits in each of the boxes found under the stairs.

An equation is an expression used to show the relationship between two or more numbers and variables.

Let x represent the number of pears, hence:

Number of fruit in first box = 12 + (1/9)x

Number of fruit in second box = number of fruit in third box = (8/9)x ÷ 2 = (4/9)x

Therefore:

12 + (1/9)x = (4/9)x

x = 36

First box = second box = third box = (4/9) * 36 = 16

There are 16 fruits in each of the boxes found under the stairs.

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Answer:

y=0.9x-45

Step-by-step explanation:

When you substitute the values of x you have to get same values as given in the table

For example: substitute x=50 in the equation y=0.9x-45

Y= 0.9(50)-45

Y= 45-45

Y=0

Step-by-step explanation:

The function [tex]u(x)=-x+3x^{2} -8[/tex] is a quadratic function due to the highest exponent being 2.

Given functions are:

[tex]u(x)=-x+3x^{2} -8[/tex]

[tex]v(x)=2x^{2} +8x^3+9x[/tex]

[tex]y(x)=x^{2} +3x^5+4[/tex]

[tex]z(x) =7x^{2} +2x^3-3[/tex]

A function of the form [tex]f(x)=ax^{2} +bx+c[/tex] with [tex]a\neq 0[/tex] is called a quadratic function means the highest exponent of polynomial should be 2.

Let us check one by one.

[tex]u(x)=-x+3x^{2} -8[/tex]

Highest exponent =2

The function is also of form [tex]f(x)=ax^{2} +bx+c[/tex] so u(x) is a quadratic function.

The functions v(x), y(x), and z(x) are having highest exponents as 3,5, and 3 respectively so they are not quadratic functions.

Hence, the function [tex]u(x)=-x+3x^{2} -8[/tex] is a quadratic function due to the highest exponent being 2.

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Answer/Step-by-step explanation:

Given:

Seven more than the quotient of a number b and 45 is greater than 5

So:

Seven more than the quotient of a number b and 45 is greater than 5

=

7 + b/45 > 5

Solve if needed:

[tex]\begin{bmatrix}\mathrm{Solution:}\:&\:b > -90\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-90,\:\infty \:\right)\end{bmatrix}[/tex]

[tex]\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}[/tex]

[tex]7+\frac{b}{45}-7 > 5-7[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\frac{b}{45} > -2[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}45[/tex]

[tex]\frac{45b}{45} > 45\left(-2\right)[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]b > -90[/tex]

~Lenvy~

Step-by-step explanation:

It should be tan(k)=32/40

Tangent is opposite/adjacent and 24/32 is adjacent/opposite which is not a trig function.

Answer:

r 4    3.99797

Step-by-step explanation:

Hey ! there

Answer:

Step-by-step explanation:

In this question we have given that a circle have a circumference of 25.12 . And we are asked to find the radius of the circle .

We have to solve this question with the help of circumference formula for circle that is ,

[tex] \qquad\: \quad\underline{\boxed{ \frak{{Circumference_{(Circle)} = 2\pi r}}}}[/tex]

Where ,

Solution : -

For solving the question we must have to substitute value of π , radius and then we have to equate it with given circumference that is 25.12. So ,

[tex] \longmapsto \qquad \:\: 2 \times 3.14 \times r = 25.12[/tex]

Step 1 : By multiplying 2 , 3.14 and r , We get :

[tex] \longmapsto \qquad \: \:6.28r = 25.12[/tex]

Step 2 : Dividing with 6.28 on both sides :

[tex] \longmapsto \qquad \: \: \dfrac{ \cancel{6.28}r}{ \cancel{6.28}} = \cancel{\dfrac{25.12}{6.28} }[/tex]

On further calculations, We get :

[tex] \longmapsto \qquad \: \: \pink{\underline{\boxed{ \frak{r = 4}}}}[/tex]

Verifying : -

Now we are verifying our answer by finding the circumference of circle and equating it with 25.12 and if it will equal to 25.12 then our answer is correct . So ,

Therefore our answer is correct .

Please Note : We aren't using any unit for the values because in the question no units are provided .

Answer:

[tex]\bf A)\;17[/tex]

Step-by-step explanation:

[tex]\tt 5q-10=75[/tex]

[tex]\tt 5q-10+10=75+10\;\; \bf\; Add\;10\:to\:both\:sides[/tex]

[tex]\tt 5q=85\;\;\;\bf Simplify[/tex]

[tex]\tt \cfrac{5q}{5}=\cfrac{85}{5}\;\;\; \bf Divide\:both\:sides\:by\:5[/tex]

[tex]\tt q=17\;\; \;\bf Answer[/tex]

------ " ☆ "

Answer:

  30 cm²

Step-by-step explanation:

You want to know the area of the given shape.

The formula for the area of a parallelogram is ...

  A = bh

A line from B to E divides the figure into two congruent parallelograms, each having a base of 5 cm and a height of 3 cm.

The area of the figure is ...

  A = 2 × (5 cm)(3 cm) = 30 cm²

__

Additional comment

If you draw a line from F to D you get a triangle FED that perfectly matches the space ABC. Moving ∆FED to fill ∆ABC transforms the figure into a rectangle that is 5 cm high and 6 cm wide. Its area is (5 cm)(6 cm) = 30 cm².

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Answer:

Approx 0.453488372

Step-by-step explanation:

You can get this with a calculator.

25 × 39 = 975

975÷2150≈ 0.453488372

I'm not sure if I'm supposed to round this or not, so I won't. If you need it rounded, comment, and I will!

I would love brainliest!!!!

Answer:

214130

Step-by-step explanation:

27.6 /100 = 59100 / x

x = 214130

Answer:

Ends at 2:00

Step-by-step explanation:

12:15 + 1:30 = 13:45.

13:45 + 00:15 = 14:00

14 - 12 = 2

Recess ends at 2:00

Answer:

2p

Step-by-step explanation:

ok so 12:15 + 1 hour = 1:15pm

1:15pm + 30 minutes = 1:45pm

so that's the time that class ends at.

now Gabe has recess for 15 minutes.

so 1:45pm + 15 minutes = 2pm

Gabe's recess finishes at 2pm

hope that helps : )

Answer:

[tex]\rightarrow \sf x^2=\:17x\:+\:60[/tex]

change sides

[tex]\rightarrow \sf x^2 -17x -60 = 0[/tex]

breakdown, (60 : 20 * 3)

[tex]\rightarrow \sf x^2 -20x +3x-60 = 0[/tex]

factor the following

[tex]\rightarrow \sf x(x -20) +3(x-20) = 0[/tex]

collect into groups

[tex]\rightarrow \sf (x +3)(x-20) = 0[/tex]

final answer

[tex]\rightarrow \sf x=-3, \ 20[/tex]

Answer:

(x-20) (x+3) =0

Step-by-step explanation:

x ^ 2 = 17x + 60​

Subtract 17x from each side

x ^ 2 - 17x = 60​

Subtract 60 from each side

x ^ 2 - 17x - 60=0

What 2 numbers multiply by -60 and add to -17

-20 * 3 = -60

-20 +3 = -17

(x-20) (x+3) =0

​

Answer:

48 in³

Base Area:

[tex]\hookrightarrow \sf \dfrac{1}{2} *base*height[/tex]

[tex]\hookrightarrow \sf \dfrac{1}{2} *3*8[/tex]

[tex]\hookrightarrow \sf 12 \ in^2[/tex]

Volume:

[tex]\hookrightarrow \sf 12 * 4[/tex]

[tex]\hookrightarrow \sf 48 \ in^3[/tex]

Answer:

Step-by-step explanation:

Answer:

Lower Quartile: 7

Median: 12

Upper Quartile: 16.5

Step-by-step explanation:

First, to find anything you must reorganize the numbers according from smallest to biggest. In this case, it would be:

4, 6, 8, 9, 10, 14, 15, 16, 17, 18

Let's find the median first. The median is in the middle of the data set, and there are 10 numbers in this data set. We need to find the middle of two numbers to find the median, 10 and 14, which would be 12.

To find the lower quartile, you must look at the numbers below the median. Those would include 4, 6, 8, and 9. There is a even number of digits, meaning that we might find the middle of two numbers, 6 and 8, which is 7.

Then, the Upper Quartile which is the same process. Look at 15, 16, 17, and 18. It is a even number of digits so we need to find the middle of 16 and 17, which would equal 16.5.

Hope this helped!

Answer:

8 root 2 or 11.3

Step-by-step explanation:

square 16 and divide by two to find square of other sides. Then root it to find answer

Answer:   8 root 2 or 11.3

Step-by-step explanation:

square 16 and divide by two to find square of other sides. Then root it to find answer

Answer:   = 16 + x

Please mark brainliest, it helps alot

Step-by-step explanation:

==============================================================

Combine Like Terms:-

[tex]\bigstar{\boxed{\pmb{7+9x+x}}[/tex]

[tex]\bigstar{\boxed{\pmb{16+x}}[/tex]

Are there any more like terms? No, because 16 & x aren't like terms.

========================================================

Hope everything is clear; if you need any clarification/explanation, kindly comment, and I will comment and/or edit my answer :)

Answer:

C. b= a+4

Step-by-step explanation:

Answer: D

Step-by-step explanation:

[tex]3x^2-x+2=0[/tex]

[tex]\text{Solve \ with \ the \ quadratic \ formula \mathrm{for\:}\quad a=3,\:b=-1,\:c=2}[/tex]

[tex]x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:3\cdot \:2}}{2\cdot \:3}[/tex] [tex]\rightarrow \sqrt{\left(-1\right)^2-4\cdot \:3\cdot \:2} =\sqrt{1-24} =\sqrt{-23} =\sqrt{-1}\sqrt{23} =\sqrt{23}i[/tex]

[tex]x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{23}i}{2\cdot \:3}[/tex]

[tex]x_1=\frac{-\left(-1\right)+\sqrt{23}i}{2\cdot \:3},\:x_2=\frac{-\left(-1\right)-\sqrt{23}i}{2\cdot \:3}[/tex]

[tex]x_1=\frac{1+\sqrt{23}i}{6},\:x_2=\frac{1-\sqrt{23}i}{6}[/tex]

Answer:

I showed the answers in the pic above ^

Step-by-step explanation:

I hope this helps you!

Answer:

Step-by-step explanation: