The number of representatives of a multi-level marketing company as a function of the number of days that have passed can be modelled by the exponential function R(d). About how many representatives does the company have after 75 days have passed if R(d) =150(1.03)^d

Answer:

y = 8

Step-by-step explanation:

The question is simply asking for the y-value when x = 6. We look at the graph when x = 6 and see what y-value it gives us. We find that when x = 6, we have y = 8.

Answer:

2288

Step-by-step explanation:

Answer:

720 seating arrangments

Step-by-step explanation:

There are eight people but driver is always the same so we only have to deal with combinations of the other 7 seats.

the combination of the five seats has 5! times 2 combinations for each of the 3 passengers willing to ride in the two boat seats thus the total number of different seating arrangements is 5! times 3! or 720

hope this helps :)

Using the Fundamental Counting Theorem, it is found that there are 5760 possible seating arrangements.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem:

Hence:

[tex]N = 8 \times 6 \times 5! = 5760[/tex]

There are 5760 possible seating arrangements.

More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866

Answer:

-5-2c

Step-by-step explanation:

The additive inverse of a term must be the opposite of it.

●-(5+2c)

●-5-2c

Answer:

Step-by-step explanation:

The additive inverse is just the opposite of the binomial in terms of the signs. The additive inverse of 5 + 2C is -(5 + 2C) which is, without parenthesis,        -5 - 2C.

Answer:

The possible number of goats is 6 and the possible number of chicken is 24

Step-by-step explanation:

Let

chicken=c

Goat=g

the number of chickens could be four times the number of goats

c=4g

Total number of animals=30

c+g=30

Recall, c=4g

So,

c+g=30

4g+g=30

5g=30

Divide both sides by 5

5g/5=30/5

g=6

Recall,

c+g=30

c+6=30

c=30-6

=24

c=24

The possible number of goats is 6 and the possible number of chicken is 24 making a total of 30 animals

Answer:

x = - 1, x = 1

Step-by-step explanation:

Given

f(x) = [tex]\frac{2x^2+3x+6}{x^2-1}[/tex]

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

x² - 1 = 0 ← difference of squares

(x - 1)(x + 1) = 0

x - 1 = 0 ⇒ x = 1

x + 1 = 0 ⇒ x = - 1

x = - 1 and x = 1 are vertical asymptotes

Answer:

a) 3/1 that is 3

b) 8/7

c) the mixed fraction is converted into simple fraction: 3*2+2/3 = 8/3

therefore the reciprocal is 3/8

d) 1/5

e) the mixed fraction is converted into simple fraction: 6*6+1/6 = 37/6

therefore the reciprocal is 6/37.

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Answer:

a. [tex]3[/tex]

b. [tex] \frac{8}{7} [/tex]

c. [tex] \frac{3}{8} [/tex]

d. [tex] \frac{1}{5} [/tex]

e. [tex] \frac{6}{37} [/tex]

Step-by-step explanation:

a. [tex] \frac{1}{3} [/tex]

Just flip the fraction , you will get:

[tex] = \frac{3}{1} [/tex]

[tex] = 3[/tex]

b. [tex] \frac{7}{8} [/tex]

flip the fraction

[tex] = \frac{8}{7} [/tex]

c. [tex]2 \frac{2}{3} [/tex]

The first thing you have to do is that convert mixed fraction into improper fraction

[tex] \frac{8}{3} [/tex]

Flip the fraction

[tex] = \frac{3}{8} [/tex]

d. [tex]5[/tex]

flip the fraction

[tex] = \frac{1}{5} [/tex]

e. [tex]6 \frac{1}{6} [/tex]

Convert mixed fraction into improper fraction

[tex] = \frac{37}{6} [/tex]

Flip the fraction in order to get reciprocal

[tex] = \frac{6}{37} [/tex]

Hope this helps...

Best regards!!

Answer: x = 137°

Step-by-step explanation:

When a quadrilateral is inscribed in a circle, the opposite angles are supplementary.

x + 43° = 180°

      x   =  137°

The value of x is 137°.

The quadrilateral whose all 4 vertices lie on the circumference of the circle is called an inscribed quadrilateral.

In inscribed quadrilateral opposite angles are supplementary i.e. sum of those opposite angles is 180°.

Here given in the picture that the measurements of the two opposite angles in the inscribed quadrilateral in the circle are 43° and x°.

So as we know in the inscribed quadrilateral opposite angles are supplementary.

So sum of those opposite angles in the quadrilateral is 180°.

so we can write x+43°= 180°

⇒ x = 180°- 43°

⇒ x = 137°

Therefore the value of x is 137°.

Learn more about inscribed quadrilateral

here: https://brainly.com/question/26690979

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Answer:

The amount of CD's she could buy would be 3.

Step-by-step explanation:

80-20=60

60÷18 = 3 CD's

Answer:

1,2,3

Step-by-step explanation:

Answer:

$5.70

Step-by-step explanation:

1. 25.00 - 2.20 = $22.80

2. 22.80 divided by 4 = $5.70

Answer:

$5.70

Step-by-step explanation:

let the price for each canvas be $x

hence the price of 4 canvases will be $4x

It is given that after she paid for 4 canvases, she had a balance of $2.20 on her orginally $25 gift card.

Hence we can assemble an equation:

$4x + $2.20 = $25

4x + 2.2 = 25   (subtract 2.2 from both sides)

4x = 25 - 2.2

4x =22.8  (divide both sides by 4)

x = 22.8 / 4

x = 5.7

Hence each canvas cost $5.70

Answer:

Option A.

Step-by-step explanation:

See attachment.

Basically, the reason why I left it at cm(3) was because that's the standard unit for volume, any length of measurement to the third power.

Answer:

[tex]3 -\sqrt[2]3[/tex]

Step-by-step explanation:

Given

[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex]

Required

Simplify

Rewrite the given expression in index form

[tex]\frac{2 * 9 ^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 9^{\frac{1}{3}}}[/tex]

Express 9 as 3²

[tex]\frac{2 * 3^2^*^\frac{1}{3}}{1 + 3^{\frac{1}{3}} + 3^2^*^{\frac{1}{3}}}[/tex]

[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}}[/tex]

Multiply the numerator and denominator by [tex]1 - 3^{\frac{1}{3}}[/tex]

[tex]\frac{2 * 3^\frac{2}{3}}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}}} * \frac{1 - 3^{\frac{1}{3}}}{1 - 3^{\frac{1}{3}}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) (1 - 3^{\frac{1}{3}})}{(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})(1 - 3^{\frac{1}{3}})}[/tex]

Open the bracket

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2}{3})(3^{\frac{1}{3}})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

Simplify the Numerator using Laws of Indices

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{2+1}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

Further Simplify

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^\frac{3}{3})}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3^1)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}}(1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}})}[/tex]

Simplify the denominator

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1}{3}})(3^{\frac{1}{3}}) - (3^{\frac{1}{3}})(3^{\frac{2}{3}})}[/tex]

Further Simplify Using Laws of Indices

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - (3^{\frac{1+1}{3}}) - (3^{\frac{1+2}{3}})}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^{\frac{3}{3}}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3^1}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 + 3^{\frac{1}{3}} + 3^{\frac{2}{3}} - 3^{\frac{1}{3}} - 3^{\frac{2}{3}} - 3}}[/tex]

Collect Like Terms

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{1 - 3+ 3^{\frac{1}{3}} - 3^{\frac{1}{3}}+ 3^{\frac{2}{3}} - 3^{\frac{2}{3}} }}[/tex]

Group Like Terms for Clarity

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(1 - 3) + (3^{\frac{1}{3}} - 3^{\frac{1}{3}}) + (3^{\frac{2}{3}} - 3^{\frac{2}{3}} )}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{(- 2)+ (0) + (0)}}[/tex]

[tex]\frac{2 (3^\frac{2}{3}) -2 (3)}{-2}}[/tex]

Divide the fraction

[tex]-(3^\frac{2}{3}) + (3)[/tex]

Reorder the above expression

[tex]3 -3^\frac{2}{3}[/tex]

The expression can be represented as

[tex]3 -\sqrt[2]3[/tex]

Hence;

[tex]\frac{2\sqrt[3]{9}}{1 + \sqrt[3]{3} + \sqrt[3]{9}}[/tex] when simplified is equivalent to [tex]3 -\sqrt[2]3[/tex]

Answer:

b^8

Step-by-step explanation:

When multiplying exponents with the same base, we can add the exponents

b^2 * b^6

b^ (2+6)

b^8

Answer:b8 x

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "b6"   was replaced by   "b^6".  1 more similar replacement(s).

STEP

1

:

Multiplying exponential expressions

1.1    b2 multiplied by b6 = b(2 + 6) = b8

Final result :

 b8x

Answer:

c is 35

d is 13

Step-by-step explanation:

I multiplied both sides, and then simplified the equation.

( plz give me brainliest, that would be most appreciated! )

Answer:

option three!!!!!

Step-by-step explanation:

its closed circle

on 6

and pointing  left

Answer:

Hello! The answer to your question will be below.

Step-by-step explanation:

The answer would be clockwise.

So point k was rotated 90 degrees clockwise.....

Review.....

Question:

Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.

THE DIRECTION OF THE ROTATION WAS CLOCKWISE.

Hope this helps! :)

⭐️Have a wonderful day!⭐️

Answer:

clockwise.

So point k was rotated 90 degrees clockwise.....

Review.....

Question:

Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.

Step-by-step explanation:

Answer:

1. Cosine

2. x = 49°

3. Sine

4. y = 41°

Step-by-step explanation:

1. The trig function that will be used to solve for x is cosine.

2. Determination of angle x

x° =..?

Adjacent = 13

Hypothenus = 20

Cos x = Adjacent /Hypothenus

Cos x = 13/20

Take the inverse of Cos

x = Cos¯¹ (13/20)

x = 49°

3. The trig function that will be used to solve for y is sine.

4. Determination of angle y.

y° =..?

Opposite = 13

Hypothenus = 20

Sine y = Opposite /Hypothenus

Sine y = 13/20

Take the inverse of Sine

y = Sine¯¹ (13/20)

y = 41°

Answer:

If you wish to find any term (also known as the {n^{th}}n  

th

 term) in the arithmetic sequence, the arithmetic sequence formula should help you to do so. The critical step is to be able to identify or extract known values from the problem that will eventually be substituted into the formula itself.

Step-by-step explanation:

Answer: 6 - 5

Step-by-step explanation:

|z - 6| - |z - 5|    ; z < 5

Since z < 5, then

|z - 6| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:

-(z - 6) =  -z + 6

|z - 5| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:  

-(z - 5) = -z + 5

Now subtract them without the absolute value signs:

-z + 6 - (-z + 5)

Distribute the negative sign:

-z + 6 + z - 5

-z + z = 0 which leaves:

6 - 5

Answer: 1

Step-by-step explanation: first you need to pretend that the absolute value bars are parentheses. Then substitute a with any number less that five, for example z=3

Now we can write our new equation: (3-6)-(3-5)

now we have to determine if the final answer inside the parentheses is positive or negative. In the first parentheses 3-6=-3 with is negative. In our second parentheses we have 3-5=-2 which is a also negative.

Knowing that both parentheses are negative results we can set up an equation using z instead of 3:

-(z-6)-(-(z-5)) is our new equation. If we simplify this equation we get 1 for an answer

Answer:

The mean number of the children is 1.2

Step-by-step explanation:

Given

Children: 0, 1, 2, 1, 2

Required

Determine the Mean number

The mean of a set is calculated as follows;

[tex]Mean = \frac{\sum x}{n}[/tex]

Where x is the given set and n is the number of sets

In this case, n = 5 children

Hence;

[tex]Mean = \frac{0 + 1 + 2 + 1 + 2}{5}[/tex]

[tex]Mean = \frac{6}{5}[/tex]

[tex]Mean = 1.2[/tex]

Hence, the mean number of the children is 1.2

Answer:

  3.5 times as large

Step-by-step explanation:

The ratio can be written using a colon or a fraction bar. In the latter case, simplifying the fraction gives you your answer:

  a : b = 7 : 2 = 7/2

'a' is 7/2 = 3.5 times as large as 'b'

Answer:

46°

Step-by-step explanation:

We can tell that this triangle is an isosceles triangle because 2 of it's sides are the same, therefore, two of it's angles are the same.

Looking at it, we can assume that the two angles not defined (x and the other one) are the two angles that are the same because they look similar.

Now, the angles of all triangles add up to 180°. So, we can subtract 88° from 180 to see what the two angles add up to.

[tex]180-88=92[/tex]

So both of these angles add up to 92 degrees. Since there are two, we divide 92 by 2.

[tex]92 \div 2 = 46[/tex]

Hope this helped!

Answer: A. 82

Step-by-step explanation:

The measure of <BAD can be found by simply adding 25(<BAC)+57(<CAD) = 82.

[tex]\mathrm{BAD}=\mathrm{BAC}+\mathrm{CAD}=25^{\circ}+57^{\circ}=82^{\circ}[/tex].

Hope this helps.

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = [tex]x[/tex]

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

[tex]\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)[/tex]

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

[tex]\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)[/tex]

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

[tex]\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8[/tex]

So, the answer is:

Colin has 8 sheets left for his third class.

Answer:

Step-by-step explanation:

In triangle DEF, we have:

Given:

<EDF=56°

<EFD=84°

So, <DEF =180° - 56° - 84° =40° (sum of triangle angles is 180°)

____________

DE is a midsegment of triangle ACB

( since CD=DA(given)=>D is midpoint of [CD]

and BE = EA => E midpoint of [BA] )

According to midsegment Theorem,

. (DE) // (CB) "//"means parallel

. DE = CB/2 = FB =CF

___________

DEBF is a parm /parallelogram.

Proof: (DE) // (FB) [(DE) // (CB)]

AND DE = FB

Then, <EBF = <EDF = 56°

___________

DEFC is parm.

Proof: (DE) // (CF) [(DE) // (CB)]

And DE = CF

Therefore, <DCF = <DEF =40°

___________

In triangle ACB, we have:

<CAB =180 - <ACB - <ABC =180° - 40° - 56° =84° (sum of triangle angles is 180°)

[tex]HOPE \: THIS \: HELPS.. GOOD \: LUCK![/tex]

Answer:

67 - p = 52

Step-by-step explanation:

the train starts with 47 people:      47

it picks up 20 more:      47 + 20 = 67

p people get off:                            67 - p

52 people are left on train:           67 - p = 52

Answer:

x=-15/2 and x=1

x=6 and x=3/4

Step-by-step explanation:

You have the following equations:

[tex]\frac{4x-3}{x+2}=\frac{2x}{x+5}[/tex]

[tex]\frac{2}{x-2}+\frac{3}{x}-\frac{9}{x+3}[/tex]

To solve both equations you can first multiply by the m.c.m of the denominators, and then solve for x, just as follow:

first equation:

[tex][\frac{4x-3}{x+2}=\frac{2x}{x+5}](x+2)(x+5)\\\\(4x-3)(x+5)=2x(x+2)\\\\4x(x)+4x(5)-3(x)-3(5)=2x(x)+2x(2)\\\\4x^2+20x-3x-15=2x^2+4x\\\\4x^2-2x^2+20x-3x-4x-15=0\\\\2x^2+13x-15=0[/tex]

In this case you use the quadratic formula:

[tex]x_{1,2}=\frac{-13\pm \sqrt{(13)^2-4(2)(-15)}}{2(2)}\\\\x_{1,2}=\frac{-13 \pm 17}{4}\\\\x_1=-\frac{15}{2}\\\\x_2=1[/tex]

Then, for the first equation the solutions are x=-15/2 and x=1

second equation:

[tex][\frac{2}{x-2}+\frac{3}{x}=\frac{9}{x+3}]x(x-2)(x+3)\\\\2x(x+3)+3(x-2)(x+3)=9x(x-2)\\\\2x^2+6x+3(x^2+3x-2x-6)=9x^2-18x\\\\2x^2+6x+3(x^2+x-6)=9x^2-18x\\\\2x^2+6x+3x^2+3x-18-9x^2+18x=0\\\\-4x^2+27x-18=0[/tex]

Again, you use the quadratic formula:

[tex]x_{1,2}=\frac{-27\pm \sqrt{(27)^2-4(-4)(-18)}}{2(-4)}\\\\x_{1,2}=\frac{-27\pm 21}{-8}\\\\x_1=6\\\\x_2=\frac{3}{4}[/tex]

Then, the solutions for the second equation are x=6 and x=3/4

Diagram related to the question can be found in the attached picture below :

Answer: 6 units

Step-by-step explanation:

From the diagram attached to the question:

Length AB = 17

Length DC = 8

height (h) = x

Area of trapezium = 75sq units

The Area (A) of a trapezium is given by:

(1/2) × (a + b) × h

Where ;

a and b are the upper and base lengths of the trapezium

h = height of trapezium

A = (1/2) × (a + b) × h

75 = (1/2) * (17 + 8) * x

75 = 0.5*25*x

75 = 12.5x

x = 75 / 12.5

x = 6 units