The nutritional content per ounce of three foods is presented in the table below. If a meal consisting of the three foods allows exactly
1800 calories, 75 grams of protein, and 5650 milligrams of vitamin C, how many ounces of each kind of food should be used?
Food A
Food B
Food C
Calories
100
500
200
Protein
(in grams)
5
6
11
Vitamin C
(in milligrams)
400
2050
400
Food A:
OZ
Food B:
OZ
Food C:
OZ

Answers

Answer 1

Answer:

A = 5 ounces

B = 1 ounces

C = 4 ounces

Step-by-step explanation:

The 3 foods contain exactly 1800 calories but food A is 100 calories, food B is 500 calories and food C is 200 calories. Thus;

100A + 500B + 200C = 1800 - - - (eq 1)

The 3 meals allows exactly 75 grams of protein while A is 5 grams, B is 6 grams, C is 11 grams.

Thus;

5A + 6B + 11C = 75 - - - (eq 2)

The 3 meals allows exactly 5650 milligrams of vitamin C while A is 400 mg, B is 2050 mg and food C is 400 mg. Thus;

400A + 2050B + 400C = 5650 - -(eq 3)

Solving the 3 equations simultaneously online, we have;

A = 5 ounces

B = 1 ounces

C = 4 ounces

Answer 2

Food A is 5 ounces, Food B is 1 ounce, and Food C is 4 ounces and this can be determined by forming the linear equation in three variables.

Given :

The nutritional content per ounce of three foods is presented in the given table.A meal consisting of the three foods allows exactly  1800 calories, 75 grams of protein, and 5650 milligrams of vitamin C.

Let the total amount of Food A be 'A', total amount of Food B be 'B', and the total amount of Food C be  'C'.

The linear equation that represents total calories in each food is:

100A + 500B + 200C = 1800  

[tex]\rm A =\dfrac{ 1800 - 500B-200C}{100}[/tex]      

[tex]\rm A =18 - 5B-2C[/tex]       --- (1)

The linear equation that represents total protein in each food is:

5A + 6B + 11C = 75    ---- (2)

The linear equation that represents total Vitamin C in each food is:

400A + 2050B + 400C = 5650   --- (3)

Now, substitute the value of 'A' in equation (2).

[tex]\rm 5(18-5B-2C)+6B+11C=75[/tex]

Simplify the above equation.

90 - 25B - 10C + 6B + 11C = 75

C - 19B = -15

C = 19B - 15     ---- (4)

Now, substitute the value of 'C' in equation (1).

A = 18 - 5B - 2(19B - 15)

A = 18 - 5B - 38B + 30

A = 48 - 43B  --- (5)

Now, substitute the value of A and C obtains in equations (4) and (5) in equation (3).

A = 5 ounces

B = 1 ounce

C = 4 ounces

For more information, refer to the link given below:

https://brainly.com/question/2263981


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Complete question :

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