Answer:
2x8=16 so there for y=x^18
Step-by-step explanation:
6) 5 mi
11 mi
7) 22 m
11 m
8) 22 yd
25 yd
Answer:
#6=perimeter=32 area=55
#7=perimeter=66 area=242
#8=perimeter=94 area=550
Step-by-step explanation:
5+5+11+11=32
5x11=55
22+22+11+11=66
22x11=242
22+22+25+25=94
22x25=550
Given f(x) = 3x2 + kx – 7, and the remainder when f (x) is divided by x – 4 is
81, then what is the value of k?
Answer:
-243
Step-by-step explanation:
{3׳ykx-7 incluye
what is the square root of 6
Chloe has taken four tests this semester. Her scores on the three tests are 87, 78, and 61. If her test average is 78.5, what is her grade on her 4th test?
n = last test
(87 + 78 + 61 + n) : 4 = 78,5
87 + 78 + 61 + n = 78,5 x 4
n = 314 - 226
n = 88
I have to finish this before next week because of grades please thanks
Answer:
D
Step-by-step explanation:
Khalil has a game board as shown below, which is a square with 20 cm sides. The area of the largest circle is 314
square centimeters
What is the probability of scoring 1, 3, or 5 points with one randomly thrown dart?
O 50%
O 62.5%
O75%
O78.5%
Answer:
78.5
Step-by-step explanation:
The probability of scoring 1 , 3 or 5 points is 78.5% ( optionD)
What is probability?A probability is a number that reflects the chance or likelihood that a particular event will occur. The certainty of an event is 1 and it's 100% in percentage.
probability is expressed as;
probably = sample space/total outcome
The area of the square is expressed as;
A = l²
= 20 × 20
= 400cm²
The area of the biggest circle is 314 cm²
The probability of scoring 1, 3 or 5
= 314/400 = 0.785
in percentage = 0.785 × 100
= 78.5%
learn more about probability from
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4.
Which expression is equivalent to x^4 – 2x^3 + x^2 ?
-
A. x²(x - 1)^2
B. x²(x + 1)^2?
C. (x + 9)(x - 9)
D. 2(x+ 3)(x - 3)
Answer:
Dont have an answer but maybe this will help
Step-by-step explanation:
Combine any like terms on each side of the equation: x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.
A triangle has two sides of length 4 and 2. What is the smallest possible whole-number length for the third side?
Answer:
19
Step-by-step explanation:
(За + 2b) (2а — b) HELP ME PLEASE
Answer:
6a^2 + ab - 2b^2
Step-by-step explanation:
[insert something smart]
let f(x)=3x+4 and g(x)=2x-5 find (f-g)(x)
Step-by-step explanation:
find; (f-g)(x)
(f(x) - g(x))
f(x) = 3x + 4, g(x) = 2x - 5
3x + 4 - 2x + 5
x +9
If Sam has 120 dollars to spent what will he use it on, 20 apples that cost $6 or 50 pears that cost $3 dollars
Answer:
50 pears = 3 dollars
Step-by-step explanation:
he would want to save as much as possible
Rewrite each expression below using the Distributive Property :
a. 5 (2x + 1)
b. 34 (x - 1)
c. 9 (x + 3)
For what value of x does 3^4x=27^x-3?
0 -9
O-3
O 3
O 9
Answer:
the answer to the value of X is 0-3
Find the distance between the points 4,7 and -5,7
Answer:
9
Step-by-step explanation:
Horizontal line from 4 to -5.
Distance formula is: [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
[tex](x_{1},y_{1}) = (4,7)\\(x_{2},y_{2}) = (-5,7)[/tex]
Thus let us plug in all the know values and solve:
[tex]\sqrt{(-5-4)^2+(7-7)^2} =\sqrt{(-9)^2} =\sqrt{81} = 9[/tex]
Thus the distance is 9
Hope that helps!
What is the sum of all integers between square root of 8 and square root 113?
Answer: The sum is____
The integers between square root of 8 and square root 113 are the numbers without decimal points
The sum is 52
How to detemine the sum?The square root of 8 is 2.82
The square root of 113 is 10.63
The integers between 2.82 and 10.63 are:
3, 4, 5, 6, 7, 8, 9 and 10
The sum of these integers is represented as:
Sum = 3 + 4+ 5+ 6+ 7+ 8+ 9 + 10
Evaluate the sum
Sum = 52
Hence, the sum is 52
Read more about integer sum at:
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Shane found a website that gives the daily weather report from mars. for 4 days, shane recorded the daily high and low temperatures on mars.use the dropdowns to complete each statement. table of daily high and low temperatures in degrees celsius. on day 1, the low was negative eighty-two; the high was negative twenty-four. on day 2, the low was negative eighty-three; the high was negative twenty-six. on day 3, the low was negative eighty-four; the high was negative twenty-seven. on day 4, the low was negative eighty-four; the high was negative twenty-eight.a. the average temperature on day 2 was blank.b. the difference of the average high temperature and the average low temperature for all four days is blank.c. the day with the greatest average temperature was blank.
The average temperature on day 2 was -54.5.
What is Average?This is usually calculated with the sum of the numbers divided by how many numbers are present.
The average temperature on day 2 = -83-26 /2 = -54.5The difference of the average high temperature and the average low temperature for all four days include the following:Day one = -82-(-24) = -58
Day two = -83-(-26) = -57
Day three = -84-(-27) = -57
Day four = -84-(-28) = -56
The day with the greatest average temperature was Day one = -82-24/2 = -53.
Read more about Average here https://brainly.com/question/20118982
Answer:
Step-by-step explanation:
How much does it cost to buy 3 watering cans if each watering can costs $7.48?
Answer:
$22.44
Step-by-step explanation:
We can multiply the total number of watering cans being bought by the total cost of one watering can.
3 * 7.48 = 22.44
It will cost $22.44 to buy three watering cans.
Find the missing coordinate.
x = cos t
y = sin t
(-1, [?])
Ashton is solving the equation
3x + 7 = 16.
Which shows a step Ashton can
use to solve the equation?
a. 3x + 7 = 16 - 7
b. 3x + 7 - 7 = 16 - 7
c. 3x + 7 = 16 + 7
d. 3x + 7 + 7 = 16 + 7
PLEASE HELP
Answer:
B: 3x + 7 - 7 = 16 - 7
Step-by-step explanation:
B: 3x + 7 - 7 = 16 - 7
Answer:
[tex]\boxed{\sf{B. \quad3x + 7 - 7 = 16 - 7}}[/tex]
[tex]\boxed{\sf{x=3}}[/tex]
Step-by-step explanation:
Isolate the term of x from one side of the equation.
3x+7=16First, subtract by 7 from both sides.
⇒ 3x+7-7=16-7
Solve.
⇒ 16-7=9
Rewrite the problem down.
⇒ 3x=9
Divide by 3 from both sides.
⇒ 3x/3=9/3
Solve.
Divide the numbers from left to right.
⇒ 9/3=3
⇒ x=3
Therefore, the solution is x=3, which is our answer.So, the correct answer is B. 3x+7-7=16-7 (second option).I hope this helps you! Let me know if my answer is wrong or not.
Sketch the graph of the function y=3 sin(2x)-1
Function: y = 3sin(2x) - 1
Find y-intercept:
y = 3sin(2x) - 1y = 3sin(2(0)) - 1y = -1Formula for minimum: m = A ‐ |B|
Minimum:
-1 - |3|-4=========
When y = -4
3sin(2x) - 1 = -43sin(2x) = -3sin(2x) = -12x = sin⁻¹(-1)2x =-450°, -90°, 270°, 630°x = -225°, -45°, 135°, 315°Formula for maximum: M = A + |B|
Maximum:
-1 + |3|2=========
When y = 2
3sin(2x) - 1 = 2sin(2x) = 12x = sin⁻¹(1)2x = -630°, -270°, 90°, 450°x = -315°, -135°, 45°, 225°Now we can plot the graph for the equation in range of -360° < x < 360°
For more graphing problems: brainly.com/question/27117441
Answer:
[tex]y=A\sin(B(x+C))+D[/tex]
Amplitude = A
The height from the center line to the peak (or trough).
Period = (2π)/B
The horizontal distance from one peak to the next.
Phase shift = C
How far the function is shifted horizontally from its usual position.
(positive is to the left, negative is to the right).
Vertical shift = D
How far the function is shifted vertically from its usual position.
Parent function:
[tex]y=\sin(x)[/tex]
Therefore:
Amplitude = 1Period = 2πPhase shift = noneVertical shift = noneGiven function:
[tex]y=3\sin(2x)-1[/tex]
[tex]y=3\sin(2(x+0))-1[/tex]
Therefore:
Amplitude = 3Period = πPhase shift = noneVertical shift = -1**See attached images for how the parent function is transformed to the final function**
I need help please help me
Method 1 :
replace x and y by their value 1 and 3
3 = 4(1) - 1 = 4-1 = 3
2(1) + 3 = 2 + 3 = 5
correct
Method 2 :
y = 4x - 1
2x + y = 5
y = 4x - 1
y = -2x + 5
y - y = 4x - 1 - ( -2x + 5 )
0 = 4x - 1 + 2x - 5
6x - 6 = 0
6x = 6
x = 6/6 = 1
y = 4x - 1
y = 4(1) - 1
y = 3
correct
Answer:
Yes the points (1,3) is the solution for the systems of equations that are shown
Step-by-step explanation:
y = 4x - 1
plug in the numbers
3 = 4(1) - 1
3 = 4 - 1
3 = 3 so this is correct
2x + y = 5
plug in the numbers
2(1) + 3 = 5
2 + 3 = 5
5 = 5
so that means the points are also a solution for BOTH
4. Find the volume of the pyramid
Answer:
58 1/3 in³
Step-by-step explanation:
Volume of a square pyramid:
V = (1/3)a^2h (don't need the lateral lenght)
hello evryone. please help if you know the answer. donr help if u dont know the answer. ill give brailest to the first person that answers
a WHOLE is always simplified to "1", namely 100/100 = 1, 57/57 = 1 and so on. Well, in this case we have a total of 21 students, so 21/21 is all of them, their "whole", but we also know that 6 of them read about animals and the rest about plants, so
[tex]\stackrel{whole}{\cfrac{21}{21}}\qquad \qquad \cfrac{\stackrel{animals}{6}~~ + ~~\stackrel{plants}{15}}{21}\implies \cfrac{6}{21}~~ + ~~\stackrel{plants}{\cfrac{15}{21}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{15}{21}\implies \cfrac{3\cdot 5}{3\cdot 7}\implies \cfrac{3}{3}\cdot \cfrac{5}{7}\implies 1\cdot \cfrac{5}{7}\implies \boxed{\cfrac{5}{7}}[/tex]
Answer:
I think its 5 over 7
Step-by-step explanation:
because 6-21 equals 15 so 15 is how many read about plants out of the total students at the library which is 21.if you divide 15 over 21 by 3 you get 5 over 7
Can someone explain to me how to use square root? How do I solve it? How do I use it? I'm not sure the right way to use square root and I have testing soon, so I wanted to know how to use it beforehand.
Answer: a square root of a number x is a number y such that y² = x; in other words, a number y whose square is x. For example, 4 and −4 are square roots of 16, because 4² = ² = 16
The square of any number is always a positive number, so every number has two square roots, one of a positive value, and one of a negative value. For example, both 2 and -2 are square roots of 4.
What is the x to help me
Answer:
116 degrees
Step-by-step explanation:
the shape is 360 degrees in total
64+64 = 128
360-128 = 232
232/2 = 116
Based on the lengths of the segments in the hyperbola below, how long is the dashed line? Show your work.
Check the picture below.
keeping in mind that the difference of the distances of d1 and d2 is always a consistent constant value, as you can see in the left-hand-side of the picture, if we keep on sliding on the hyperbolic line shrinking d2 from being slanted to be horizontal, once we put d1 and d2 on a horizontal line, as you see on the right-hand-side, if we subtract the pink line from the orange line, what's leftover is, yeap, you guessed it.
Suppose that 25 inches of wire costs 75 cents.
At the same rate, how much (in cents) will 21 inches of wire cost?
Answer:
73 cents
Step-by-step explanation:
first multiply 75×21 and you will get 1575 then divide 1575 by 25 and you get 73 which is 73 cents
Type your answer into the box. Butter and flour are mixed in the ratio 2:3. Chris has 640 grams of butter and 880 grams of flour. How much more flour does he need?
Answer:
80 grams
Step-by-step explanation:
since butter & flour are in the ratio 2:3
2/5 = 640
then 3/5 = flour(?)
eliminate 5 since it is common so that
2= 640
3= x
cross multiply
x= 3 /2× 640
= 960
640 grams of butter needs to mix with 960grams of flour so that they can be in the ratio of 2:3
960-880 = 80
hence 80 more grams of flour are needed.
Abby is buying flower bulbs for her garden. She wants to buy the same number of tulips and daffodils. If tulip bulbs come in packs of 8 and daffodil bulbs come in packs of 4, what is the least number of each type of bulb Abby will need to buy?
16
lcm : 4= 4, 8, 12 , 16
8= 8 , 16
if log7=a and log…
help me solve ths math problem on picture
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: log_{4}(39.2) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{4}( {2}^{3} \times {7}^{2} \times 10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{4}( {2}^{3} ) + log_{4}( {7}^{2} ) + log_{4}(10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{ {2}^{2} }( {2}^{3} ) + log_{ {2}^{2} }( {7}^{2} ) + log_{ {2}^{2} }(10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: \frac{3}{2} log_{2}(2) + \frac{2}{2} log_{2}(7) - \frac{1}{2} log_{2}(10) [/tex]
[tex]\qquad \sf \dashrightarrow \: \frac{3}{2} + a - \frac{b}{2} [/tex]
That's the required result ~
also you can take it's LCM and write it as :
[tex]\qquad \sf \dashrightarrow \: \dfrac{2a - b + 3}{2} [/tex]