the polynomial p(x)=x^3-7x-6 has a known factor of (x+1). rewrite p(x) as a product of linear factors

Answer:

5,000 passengers

Step-by-step explanation:

1. Find out how many trains leave each hour.

6 min – 60/6 = 10 x 200 passengers = 2000

10 min – 60/10 = 6 x 200 passengers = 1200

12 min – 60/12 = 5 x 200 passengers = 1000

15 min – 60/15 = 4 x 200 passengers = 800

2. Add it all up.

2000 + 1200 + 1000 + 800 = 5000 passengers

Answer:

5000

Step-by-step explanation:

6 minute train leaves 10 times

10 x 200 = 2000 passengers

10 minute train leaves 6 times

6x200 = 1200

12 minute train leaves 5 times

5x200 =1000

15 minute train leaves 4 times

4x200 =800

2000+1200+1000+800=5000

assuming more than 1 train can be at the station at once

Answer:

You are m + 1 years old.

Step-by-step explanation:

Let's say that you are x years old, and Mack is m years old.

x = 1/2( two plus twice m)

x = 1/2(2 + 2m)

x = 1 + m

x = m + 1

Hope this helps!

Answer:

6c1;   [tex]Area = 81.12m^2[/tex]

6cii:  See Explanation

Step-by-step explanation:

Given

[tex]A = 3p^2[/tex]

[tex]0 \leq p \leq 6[/tex]

Where A represents Area and P represents Width

Required

Solve 6c

Please note that because you only need 6c, I'll solve using calculations;

Solving 6ci:

Area of the cage, when width is 5.2m

Substitute 5.2m for p in[tex]A = 3p^2[/tex]

[tex]A = 3 * 5.2m^2[/tex]

[tex]A = 3 * 27.04m^2[/tex]

[tex]A = 81.12m^2[/tex]

Hence, the area of the cage is 81.12m²

Solving 6cii:

Area of the cage, when width is 40m

From the range of value of p:   [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p

However, if the range is extended; the value of Area is as follows;

Substitute 40m for p

[tex]A = 3 * 40m^2[/tex]

[tex]A = 3 * 1600m^2[/tex]

[tex]A = 4,800m^2[/tex]

Greetings from Brasil...

Here we don't have much to go

∛Y = A.(C + 1/X)

∛Y = (AC + A/X)

raising both members to the cube.....

(∛Y)³ = (AC + A/X)³

from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³

Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³

Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]

Answer:

$2,500 was invested in the first account while $7,500 was invested in the second account

Step-by-step explanation:

Here in this question, we want to find the amount which was invested in each of the accounts, given their individual interest rates and the total amount that was accorded as interest from the two investments

Now, since we do not know the amount invested , we shall be representing them with variables.

Let the amount invested in the first account be $x and the amount invested in the second account be $y

Since the total amount invested is $10,000, this means that the summation of both gives $10,000

Mathematically;

x + y = 10,000 ••••••(i)

now for the $x, we have an interest rate of 5%

This mathematically translates to an interest value of 5/100 * x = 5x/100

For the $y, we have an interest rate of 6% and this mathematically translates to a value of 6/100 * y= 6y/100

The addition of both interests, gives 575

Thus mathematically;

5x/100 + 6y/100 = 575

Multiplying through by 100, we have

5x + 6y = 57500 •••••••••(ii)

From 1, we can have x = 10,000-y

let’s substitute this into equation ii

5(10,000-y) + 6y = 57500

50,000-5y + 6y = 57500

50,000 + y = 57500

y = 57500-50,000

y = 7,500

Recall;

x = 10,000-y

so we have;

x = 10,000-7500 = 2,500

Answer:

9.48*

Step-by-step explanation:

This is a right triangle. The formula for solving the Hypotenuse, or the longest side of the right triangle is A^2 + B^2 = C^2. If we put the numbers from the problem into the formula this is what we get :

3^2 + 9^2 = C^2

9 + 81 = C^2

90 = C^2

9.48 = C

* This is rounded, the exact number is closer to 9.486832980505138. Your class should tell you what to round to.

Answer:

The answer would be A. 3√10 blocks

Step-by-step explanation:

I have had this question and its 3√10 blocks.
Hope this helps you other people :))

Answer:

Step-by-step explanation:

[tex]x^2+\frac bax+\frac ca=0\\\\ ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\qquad\quad x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\\\x_1+x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}+\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{-2b}{2a}=\dfrac{-b}a\\\\\\x_1\cdot x_2=\dfrac{-b-\sqrt{b^2-4ac}}{2a}\cdot\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\\\\{}\ \ =\dfrac{b^2-b\sqrt{b^2-4ac}+b\sqrt{b^2-4ac}-(\sqrt{b^2-4ac})^2}{2a}=\dfrac{b^2-(b^2-4ac)}{4a^2}=\\\\{}\ \ =\dfrac{b^2-b^2+4ac}{4a^2}=\dfrac{4ac}{4a^2}=\dfrac{c}{a}[/tex]

[tex]x_1-x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}-\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-2\sqrt{b^2-4ac}}{2a}=\frac{-\sqrt{b^2-4ac}}{a}\\\\\\x_1\div x_2=\frac{-b-\sqrt{b^2-4ac}}{2a}\div\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-b-\sqrt{b^2-4ac}}{2a}\,\cdot\,\frac{2a}{-b+\sqrt{b^2-4ac}}=\\\\=\frac{-b-\sqrt{b^2-4ac}}{-b+\sqrt{b^2-4ac}}=\frac{b+\sqrt{b^2-4ac}}{b-\sqrt{b^2-4ac}}=\frac{b^2+2\sqrt{b^2-4ac}+b^2-4ac}{b^2-b^2+4ac}=\frac{2b^2+2\sqrt{b^2-4ac}-4ac}{4ac}=[/tex]

[tex]=\frac{b^2+\sqrt{b^2-4ac}-2ac}{2ac}[/tex]

Work Shown:

sin(angle) = opposite/hypotenuse

sin(35) = 10/x

x*sin(35) = 10

x = 10/sin(35)

x = 17.434467956211 make sure your calculator is in degree mode

x = 17.4

Answer:

[tex]\boxed{17.4}[/tex]

Step-by-step explanation:

sin [tex]\theta[/tex] = [tex]\frac{opposite}{hypotenuse}[/tex]

sin (35) = [tex]\frac{10}{x}[/tex]

x = [tex]\frac{10}{sin(35)}[/tex]

x = 17.4344679562...

x ≈ 17.4

Answer:

There is no relationship, except they do intersect at the point (1, -1). Hope this helps :)

Brainliest?

Both given lines are going to intersect at ( 1,-1 ) that's it.

A line section that can connect two places is referred to as a segment.

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

In other words, a line segment is just part of a big line that is straight and going unlimited in both directions.

Given that

Line 1 ; 5x +y = 4

Line 2 ;  20 + 4y = 16 ⇒ y = -1

At  y = -1  the first line is

5x  - 1  =  4 ⇒ x = 1

So,

It is clear that line 1 has a point ( 1 .-1 ) and line 2 also passes

through it hence there will an intersection.

For more about line segment

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Answer: It represents that 2 will be divided into 3 equal parts.

Step-by-step explanation:

The given fraction : [tex]\dfrac{2}{3}[/tex]

here, Numerator = 2

Denominator = 3

It represents that 2 will be divided into 3 equal parts.

Answer:

D. 4z^3

Step-by-step explanation:

First, you see what cubed is 64, which is 4, so you know it is either A or D, but it can not be A because it is not z to the power 5 but x to the power of 3

Hope this helps, if you want me to explain more, feel free to ask questions.

Have a good day! :)

Answer:

4 z^3

Step-by-step explanation:

( 64 z^9) ^ 1/3

Rewriting 64 as 4^3

( 4^3 z^9) ^ 1/3

We know that ( ab) ^c = a^c  * b^c

4^3 ^ 1/3 z^9  ^ 1/3

We know that a^ b^c = a^ ( b*c)

4^(3 * 1/3) z^ (9  * 1/3)

4 ^ ( 1)  z^ ( 3)

4 z^3

Answer:

144 codes are possible

Step-by-step explanation:

Okay for the first digit, we shall be selecting one out of 3,4,5,6.

Meaning we are selecting one out of four choices

The number of ways this can be done is 4C1 ways = 4 ways

For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways

And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices

So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes

Answer:

rectangular prism

Step-by-step explanation:

check by rotating the shape in images

Answer:

The total bill was $84

Step-by-step explanation:

Ok so we know a few things, we know that the total cost of the bill is divisible by both 6 and 4, and we know that if we call the total cost of the bill x and the amount each person would pay if it was divided for 6 people y we can write these equations:

[tex]\frac{x}{6}=y[/tex]

[tex]\frac{x}{4}=y+7[/tex]

Now we can substitute the first equation into the second and solve for x

[tex]\frac{x}{4}=\frac{x}{6}+7\\\frac{x}{4}-\frac{x}{6}=7\\\frac{x}{12}=7\\x=7*12=84[/tex]

Therefore, the total bill was $84

Answer:

Both have the same period which is 2π

Step-by-step explanation:

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

a) For x < 2:

[tex]z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08[/tex]

From normal distribution table,  P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

[tex]z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08[/tex]

For x = 11:

[tex]z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67[/tex]

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

[tex]z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67[/tex]

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

[tex]z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08[/tex]

For x = 5:

[tex]z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83[/tex]

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

[tex]z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83[/tex]

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

Answer:

It takes Carrie and James an hour and a half to finish the job.

Step-by-step explanation:

assuming they have to inspect ONE case of watches.

Carrie can inspect 1/5 case in one hour.

James can inspect 1/3 case in one hour.

Carrie worked alone for 1 hour, so she finished 1/5 of a case.

She leaves 4/5 case to finish.

She had lunch.

After that, Carrie and James worked together for x hours to finish the job.

When they work together, the finish 1/5+1/3 = 8/15 case per hour.

So time to finisher the remaining case

Time = 4/5 / (8/15)

= 4/5 * 15/8

= 3/2 hours

= an hour and a half.

Answer: x ≥  -5

Step-by-step explanation:

First, let's see how the function f(x) = IxI works:

if x ≥ 0, IxI = x

if x ≤ 0, IxI = -x

Notice that for 0, I0I = 0.

Ok, we want that:

|x+5| = x+5

Notice that this is equivalent to:

IxI = x

This means that  |x+5| = x+5 is only true when:

(x + 5) ≥ 0

from this we can find the possible values of x:

we can subtract 5 to both sides and get:

(x + 5) -5 ≥ 0 - 5

x ≥  -5

So the graph in the number line will be a black dot in x = -5, and all the right region shaded.

something like:

-7__-6__-5__-4__-3__-2__-1__0__1__2__3__4__ ...

Answer:

Step-by-step explanation:

f(x) = 3x + 2

To find f(5) substitute 5 into f(x)

That's

f(5) = 3(5) + 2

= 15 + 2

= 17

Hope this helps you

Answer:

17

Step-by-step explanation:

You just plug 5 into the equation

f(5)= 3(5)+2

=15+2

=17

Hope this helped! :)

Answer:

Step-by-step explanation:

The values ​​of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.

Answer: it is =4176000000000000

Step-by-step explanation:

(2.9)(100000)(7.2)(10^2)

5(10^−8)

=

(290000)(7.2)(10^2)

5(10^−8)

=

2088000(10^2)

5(10^−8)

=

(2088000)(100)

5(10^−8)

=

208800000

5(10^−8)

=

208800000

5(1/100000000)=

208800000/1

20000000

=4176000000000000

hope i helped

-lvr

Answer:

Step-by-step explanation:

Discount =$7000-$4900

Discount% =

[tex] \frac{2100}{7000} \times 100 \\ = \frac{210000}{7000 } \\ = \frac{210}{7} = 30[/tex]

Answer:

C. Same is not an orange belt and Kate is not a red belt.

Step-by-step explanation:

The negation for the statement is Sam is not an orange belt or Kate is not a red belt.

The negation of a conjunction is equivalent to the disjunction of the negation of the statements making up the conjunction. To negate an “and” statement, negate each part and change the “and” to “or”.

Given statement:

Sam is an orange belt and Kate is a red belt.

Now, to make the negation we have to consider the rule "To negate an “and” statement, negate each part and change the “and” to “or”."

So, the negation statement would be

Sam is not an orange belt or Kate is not a red belt.

Learn more about  De Morgan's laws here:

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Answer:

Options B:  and C:

Step-by-step explanation:

Remember that 30% in fraction form is

The amount of health points (H) restored would depend on the amount of the current H so it means it would add 30% of the current which we can write as:

And since it would add that to the current total we can right the current total as:

So our equation would be:

For option B:

We can factor out the H and you will be left with:

Combine or add the fractions inside the parenthesis and you will have:

For option C:

We can simplify the fractions which will result in:

Then factor out the H and you will have:

Options B:  and C:

Step-by-step explanation:

Remember that 30% in fraction form is

The amount of health points (H) restored would depend on the amount of the current H so it means it would add 30% of the current which we can write as:

And since it would add that to the current total we can right the current total as:

So our equation would be:

For option B:

We can factor out the H and you will be left with:

Combine or add the fractions inside the parenthesis and you will have:

For option C:

We can simplify the fractions which will result in:

Then factor out the H and you will have:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

             ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                            PEACE!

Answer:

[tex] (0, 8\sqrt{3}) [/tex]  and  [tex] (0, -8\sqrt{3}) [/tex] are both 14 units from points (-2, 0) and (2, 0).

Step-by-step explanation:

distance formula

[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

We want the distance, d, from points (-2, 0) and (2, 0) to be 14.

Point (-2, 0):

[tex] 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} [/tex]

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

Point (2, 0):

[tex] 14 = \sqrt{(x - 2)^2 + (y - 0)^2} [/tex]

[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]

We have a system of equations:

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]

Since the right sides of both equations are equal, we set the left sides equal.

[tex] \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} [/tex]

Square both sides:

[tex] (x + 2)^2 + y^2 = (x - 2)^2 + y^2 [/tex]

Square the binomials and combine like terms.

[tex] x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 [/tex]

[tex] 4x = -4x [/tex]

[tex] 8x = 0 [/tex]

[tex] x = 0 [/tex]

Now we substitute x = 0 in the first equation of the system of equations:

[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{(0 + 2)^2 + y^2} = 14 [/tex]

[tex] \sqrt{4 + y^2} = 14 [/tex]

Square both sides.

[tex] y^2 + 4 = 196 [/tex]

[tex] y^2 = 192 [/tex]

[tex] y = \pm \sqrt{192} [/tex]

[tex] y = \pm \sqrt{64 \times 3} [/tex]

[tex] y = \pm 8\sqrt{3} [/tex]

The points are:

[tex] (0, 8\sqrt{3}) [/tex]  and  [tex] (0, -8\sqrt{3}) [/tex]

Answer:

28

Step-by-step explanation:

We divide the shape covenientely, like this, and area 1 is 4*4=16

area 2=4*4/2=8

area 3= 2*4/2=4

Area total = Area 1 + Area 2 + Area 3=16+8+4=28

Answer:

15

Step-by-step explanation:

Answer:

21.213

Step-by-step explanation:

Answer:

paid vacation

paid medical

401k

Answer:

Step-by-step explanation:

Vertex of f is (-1, -4) so its range is limited to y≥-4

|x+1| is always ≥0 therefore -|x+1| is always ≤0 {4 is insignificant to this - slope doesn't mean in range} so its range is limited to y≤0

Answer:

D

Step-by-step explanation:

i just took the test

Answer:

V = 15 pi m^3

Step-by-step explanation:

The volume of a cone is

V = 1/3 pi r^2 h

The radius is 3 and the height is 5

V = 1/3 pi ( 3)^2 *5

V = 15 pi m^3

Answer:

15 pi m3

Step-by-step explanation: