Answer:
The depth of the object below the surface of the liquid is 0.510 meters.
Explanation:
The hydrostatic pressure ([tex]P[/tex]), measured in pascals, experimented by the object is directly proportional to density of the fluid ([tex]\rho[/tex]), measured in kilograms per cubic meter, gravitational acceleration ([tex]g[/tex]), measured in meters per square second, and depth of the object ([tex]h[/tex]), measured in meters. That is:
[tex]P = \rho\cdot g \cdot h[/tex] (1)
If we know that [tex]P = 4500\,Pa[/tex], [tex]\rho = 900\,\frac{kg}{m^{3}}[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the depth of the object is:
[tex]h = \frac{P}{\rho\cdot g}[/tex]
[tex]h = \frac{4500\,Pa}{\left(900\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]
[tex]h = 0.510\,m[/tex]
The depth of the object below the surface of the liquid is 0.510 meters.
The depth of the object below the liquid's surface will be
"0.510 m".
Pressure and DensityAccording to the question,
Object immersed, P = 4500 Pa
Density of liquid, ρ = 900 kg/m³
Acceleration due to gravity, g = 9.8 m/s²
We know the relation,
→ Hydrostatic pressure (P) = ρ.g.h
or,
Depth will be:
→ h = [tex]\frac{P}{\rho .g}[/tex]
By substituting the values,
= [tex]\frac{4500}{900\times 9.8}[/tex]
= [tex]\frac{4500}{8820}[/tex]
= 0.510 m
Thus the above answer is appropriate.
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The speed of a 1200 kg car increases from 5 to 29 m/s in 12 s.
What force accelerated the car?
Answer:I think I’m not sure But I think that the force that would be accurated the car would be friction or something like that and to solve the equation you would do f/m
Explanation:
It just makes sense
1. What is the velocity of an 250-kg that has 6,250 J of energy?
Please help
Explanation:
KE = 1/2mv^2
6,250 J =1/2(250kg) v ^2
6250 J = 125kgv^2
125kg. 125kg
v =
[tex] \sqrt{50} [/tex]
which of these is NOT a metamorphic rock?
Basalt
Slate
Marble
Explanation:
Basalt is not a metamorphic rocks
1. If you were the organizer of this dance event, are you favor in moving the date on May? Why
or why not?
Answer:
I am in favor of the dance event being in may. Because it is nice weather outside, more people will decide to come and spend their time there. It is also light in the evening in may, meaning that you could have the dance event at any time, and younger people will still feel safe at night, meaning their parents will be more open to lwtting kids go.
The body weighing 8kg moves in a straight line uniformly accelerated with an acceleration of 3m / s? on a horizontal surface, under the action of force 60N.Find a) What is the friction force acting on the body) The coefficient of friction between the body and the surface where it moves
Answer:
the friction force f=36
and the coefficient of friction =0.45
4. A substance is cut into several piece and compared to the density of the
original sample. The density of each piece will be:-
areater
bl the same
Answer:
The density pf each piece will be the same, since density is defined as a mass per unit volume, so even when you cut an object it will not change
PLS HELP WITH THIS DENSITY QUESTIONS AND WHEN SHOWING STEPS PLS USE GRASS
Calculate the density of aluminum if you have a piece of aluminum that has a volume of 48.9 cm³.When the piece is measured it is found to have a mass of 132 g.
A small amount of copper is found to have a mass of 27 g. Calculate the density of copper if the volume of the sample is 3.0 cm³.
The volume of a piece of iron is 65 cm³. If the piece of iron has a mass of 512 g. Calculate the density of the sample of iron.
A stick of cedar wood has a mass of 1.2 kg. It has a volume of 3243 cm³ . What is the density of cedar wood?
Zinc has a density of 7.14 g/cm³. If you are given 50 g of zinc calculate the volume of the sample.
A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density?
Mercury metal is poured into a graduated cylinder that holds exactly 22.5 mL. The mercury used to fill the cylinder weighs 306.0 g. From this Information, calculate the density of mercury.
What volume of silver metal will weigh exactly 2500.0 g. The density of silver is 10.5 g/cm³
Answer:
Explanation:
Density = mass/volume
132g/(48.9 cm³) = 2.7 g/cm³
(27 g)/(3 cm³) = 9 g/cm³
512 g/(65 cm³) = 7.9 g/cm³
1.2 kg/(3243 cm³) cm³ = 1200 g/(3243 cm³) = 0.37 g/cm³
An electric iron is connected to the mains power supply of 220 V. When the electric iron is
adjusted at 'minimum heating' it consumes a power of 360 W but at 'maximum heating' it takes a
power of 840 W. Calculate the current and resistance in each case.
Answer:
Given: V = 220V, Pmin = 360W, Pmax = 840W
For minimum heating case:
We know that
Pmin = VI
360 = 220 X I
I = 1.63 amp
R = V/I
R = 220/1.63
R = 134.96ohms
For maximum heating case:
We know that
Pmax = VI
840 = 220 X I
I = 3.81 amp
R = V/I
R = 220/3.81
R = 57.74 ohms
Displacement a combination of
Answer:
Displacement a combination of distance
Explanation:
I'm not sure eh
HELP please!!!!!!!!!!!!!!!
Between steel and iron which is more suitable for making permanent magnets electromagnet and magnetic screen give reason for your answer
Answer:
steel is suitable for making permanent magnet
as still has hi factor coercity.
iron is for electromagnet and magnetic screen as iron loses its magnetism as soon as the switch is open and a current is switched off.
Steel is better suitable for making permanent magnets than soft iron since it has higher retentivity and lower coercivity. Compared to soft iron, steel has a lower retentivity and higher coercivity. Compared to soft iron, steel is more resilient and coercive.
What is retentivity and coercivity ?Retentivity : The ability to retain the generated magnetization in a magnetic material when the magnetizing force is removedCoercivity : A measure of the ability of a material to withstand an external magnetic field without becoming demagnetized.What is Permanent magnet and Electromagnet?Permanent magnet : To be suitable for permanent magnet, material should retain its magnetism for longer time, since steel have high retentivity and coercivity . Electromagnet : To be suitable for electromagnet , material should have magnetization and demagnetizing property .
Since , steels have high remanence which means it will remain magnetized even after magnetic field is removed which is not suitable for electromagnetic . iron has high permeability so magnetization is larger and have low retentivity so that material will not retain the magnetic properties . Magnetic screen , Iron has high permeability hence it can shield better than steel
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1 watt is the same as the transfer of ____
joules per second. What number completes the sentence?
Answer:
1 watt is the same as the transfer of 1 joules per second.
1 watt is the same as the transfer of energy at a rate of 1 joule per second.
A watt is a unit of power, representing the amount of energy transferred or converted per unit of time. Specifically, 1 watt is equivalent to 1 joule of energy being transferred every second. It is a common metric used to measure the rate of energy flow or work done in various systems. For example, a 100-watt light bulb converts electrical energy into light and heat at a rate of 100 joules per second. Understanding power in terms of watts helps us quantify and compare the efficiency and performance of different devices and processes.
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The final velocity of a car is 30m/s. The car is accelerating at a rate of 2.5m/s2
over an 2.8m/s2
8 second period of time. What is the initial velocity of the car?
Answer:
10m/s
Explanation:
Vf=v0+at
30m/s=v0+2.5m/s^2*8s
Solve for v0=10m/s
Sorry for the vague explanation I'm on my phone right now. Hope this still helps!
Initial velocity of the car where final velocity of a car is 30m/s and it is accelerating at a rate of 2.5 [tex]m/s^{2}[/tex] over an 2.8 [tex]m/s^{2}[/tex] 8 second period of time is 10 m/s.
To find the initial velocity of the car, we can use the kinematic equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t)).
Given the final velocity (v) as 30 m/s, acceleration (a) as 2.5 [tex]m/s^{2}[/tex], and time (t) as 8 seconds, we can plug these values into the equation:
30 m/s = u + (2.5 [tex]m/s^{2}[/tex] * 8 s).
Now, solve for the initial velocity (u):
30 m/s = u + 20 m/s.
Subtract 20 m/s from both sides:
u = 30 m/s - 20 m/s = 10 m/s.
Therefore, the initial velocity of the car is 10 m/s.
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Whatb19 ÷117= some help me with this
Answer:
0.16239316239316239316239
Explanation:
ang haba nang solve ko dito hehe
. A boy wishes to throw a ball through a house via two small openings, one in the front and the other in
the back window, the second window being directly behind the first. If the boy stands at a distance of 5m
in front of the house and the house is 6m deep and if the opening in the front window is 5m above him
and that in the back window 2m higher, calculate the velocity and the angle of projection of the ball that
will enable him to accomplish his desire.
Answer:
1) The angle of projection of the ball is approximately 52.496° above the horizontal
2) The velocity with which the boy throws the ball to enable him accomplish his desire is approximately 14.769 m/s
Explanation:
In the projectile motion of the ball, the parameters are;
The distance the boy stands from the front of the house = 5 m
The depth of the house, front to back = 6 m
The height of the opening of the front window above him = 5 m
The height of the back window = 2 m higher than the front window
Therefore, the height of the back window = 5 m + 2 m = 7 m
1) The general formula for the vertical height of a parabolic projectile motion is given as follows;
y = a·x² + b·x + c
At y = 0, x = 0, therefore, c = 0
At y = 5, x = 5, we have;
5 = a·5² + b·5
∴ 5 = 25·a + 5·b...(1)
At y = 7, x = 11, we have;
7 = a·11² + b·11
7 = 121·a + 11·b...(2)
Making 'a' the subject of equation (1) and (2) and equating both values of 'a' gives;
For equation (1);
a = (5 - 5·b)/25 = 1/5 - b/5
a = 1/5 - b/5
For equation (2);
a = (7 - 11·b)/121 = 7/121 - b/11
a = 7/121 - b/11
∴ 1/5 - b/5 = 7/121 - b/11
1/5 - 7/121 = b/5 - b/11
86/605 = 6·b/55
b = (86/605) × (55/6) = 43/33
b = 43/33
a = 1/5 - b/5 = 1/5 - (43/33)/5 = -2/33
∴ y = (-2/33)·x² + (43/33)·x
The slope of the curve = dy/dx = d((-2/33)·x² + (43/33)·x)/dx = -4/33·x + 43/33
The slope of the curve at any point on the projectile = -4/33·x + 43/33
The slope at the origin is given by plugging x = 0 as follows
The slope at the origin = -4/33 × 0 + 43/33 = 43/33
The slope at the origin = tan(θ) = 43/33
Where;
θ = The angle of projection of the ball
∴ θ = arctan(43/33) ≈ 52.496°
The angle of projection of the ball, θ ≈ 52.496° above the horizontal
2) At the back widow, the equation for the vertical height, 'h', is given as follows;
[tex]h = (tan \angle \theta) \cdot x - \left(\dfrac{g}{2 \cdot v_1^2 \cdot cos^2 \angle \theta } \right )\cdot x^2[/tex]
Where;
h = The vertical height of the back window = 7 m
tan∠θ = 43/33
x = The horizontal distance of the back window from the boy = 5 m + 6 m = 11 m
g = The acceleration due to gravity = 9.8 m/s²
v₁ = The velocity with which the boy throws the ball
cos²∠θ = cos²(arctan(43/33)) = 1089/2938
Plugging in the values gives;
[tex]7 = \left (\dfrac{43}{33} \right) \times 11 - \left(\dfrac{9.8}{2 \cdot v_1^2 \cdot \dfrac{1089}{2938} } \right )\cdot 11^2[/tex]
[tex]\therefore v_1^2 = \dfrac{71981}{330}[/tex]
[tex]\therefore v_1 = \sqrt{\dfrac{71981}{330}} \approx \pm14.769[/tex]
The velocity with which the boy throws the ball to enable him accomplish his desire, v₁ ≈ 14.769 m/s.
Brad has three beakers of water. Each beaker contains 500 mL of water. The temperature of the water in the first beaker is 40°C. The water in the second beaker is at 100°C, and the water in the third beaker is at 60°C. As part of a lab experiment he will carefully combine the water in all three beakers. He predicts that the combined water will have a final temperature of 50°C.
Evaluate Brad’s claim and clearly state whether he is correct or not. Explain your answer to support your evaluation.
Explanation:
uasjwwbwjwbwia GJ wkwkjwnwnwjwjjwjwd7beba s
Which of the following determines the identity of an atom?
A. atomic mass
B. mass number
C. atomic number
D. charge
Explain why gaps are left between railway lines
Answer:
to prevent the derailing of the train due to thermal expansion.
Answer:
Iron are good conductors of heat and electricity. Being a good conductor it expands as well as contracts with the change of temperature.When heat is applied,they expands because molecules inside the element gets excited and number of molecules inside it increases in tremendous amount,so it leads to expansion of iron. So when the temperature is lowered it comes in its normal state.
The term for this is called as thermal expansion or contraction.The gap in the joint between 2 rails is to prevent from the expansion of the iron. It is necessary ,if not there will be change in structure,it may buckle and chance of derailed is increased.
Explanation:
The gap in the joint between to rails is to compensate for the expansion of the material of rail during summer.
The metals expand or contract with the changes in temperature. The expansion or contraction depends on the coefficient of thermal expansion of the material. Based on this property of the metal, the gap in the joint of two rails is provided.
4. Premature wrinkling due to overexposure to the Sun, what am I?
Premature Aging
Mark as brainlist
why do you think people translate sound waves from compression waves to transverse waves ?
Answer:
Sound waves are translated into transverse waves to know the frequency, amplitude, wavelength etc of the waves.
Explanation:
They translate the sound waves to know the depth about that specific waves and translating it to transverse waves makes it easier.
Hope it helps :D
A human cannonball act uses springy bungee cords instead of gunpowder to launch a person through a long cylindrical tube into the air. If a cannon is capable of launching a 55 kg test dummy 11 m into the air when launched straight up, how much energy is stored in the bungee cords? *
A. 539J
B. 605 J
C. 2965J
D. 5929 J
Answer:
Energy stored, E = 5929 J
Explanation:
Given that,
The mass of a test dummy, m = 55 kg
It is launched 11 m into the air.
We need to find the energy stored in the bungee cords. It can be calculated as follows :
[tex]E=mgh\\\\E=55\times 9.8\times 11\\\\E=5929\ J[/tex]
So, 5929 J of energy is stored in the bungee cords.
1.) A projectile is launched at 32.1 m/s and 52.6 º above the horizontal. Determine the:
a.) Maximum height of the projectile.
b.) The time it takes to reach the maximum height
c.) Time of flight
d.) Range
Answer:
a.) Maximum height of the projectile. =32.5m
b.) The time it takes to reach the maximum height=2.6s
c.) Time of flight=2.6s
d.) Range=99.5m
Explanation:
Which has more potential energy: a baseball held 1 m above the ground or a baseball held 2 m above the ground?
The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.
The potential energy can be calculated with the following equation:
[tex] E_{p} = mgh [/tex]
Where:
m: is the mass of the baseball
g: is the acceleration due to gravity
h: is the height
We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:
Potential energy above 1 m[tex] E_{p_{1}} = mg*1 = mg [/tex] (1)
Potential energy above 2 m[tex] E_{p_{2}} = mg*2 = 2mg [/tex] (2)
By entering equation (1) into 2 we have:
[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]
Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.
Therefore, the baseball held 2 m above the ground has more potential energy.
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1/2 means that the voltage (or charge) of the system will increase to half more of what is left in a time equal to t1/2 seconds. Therefore if a system is already at half charge (t1/2 seconds after starting) then after t1/2 more seconds the system will be charged to 50% plus half of 50%. That is 25% more, or 75% of the entire charge. Let's say that four t1/2's have gone by. That means that the charge (or voltage) is at (50% + 1/2*50% + 1/2*1/2*50% + 1/2*1/2*1/2*50%) = 93.75% of maximum charge. Yikes! Now look in your manual for a more simple mathematical derivation of this concept. Given t1/2 to be 0.4406 seconds, how long should it take to reach 75% of maximum charge? answer in seconds.
Answer:
The answer is "0.047".
Explanation:
Given value:
[tex]\to t_{\frac{1}{2}}= 0.4406\\\\\to V=0.9375 V_{max}[/tex]
Calculating the capacitance:
[tex]\to V=V_{max} (1-e^{\frac{-t}{Rc}})[/tex]
In this, the t = time, which is taken to calculates its maximum voltage.
[tex]\to 0.9375 V_{max} = V_{max}(1-e^{- \frac{t}{103\times(165.279\times10^{-6})}})\\\\\to e^{- \frac{t}{103\times(165.279\times10^{-6})}}= 0.0625\\\\\to - \frac{t}{103\times(165.279\times10^{-6})} = \ln(0.0625)\\\\\to -t= 0.01702\times(-2.77258) \\\\ \to -t = -0.04719 \\\\ \to t= 0.04719 \approx 0.047 \ s[/tex]
If an object is placed between a convex lens and its focal point, which type of image will be produced?
A.
real, inverted, and magnified
B.
real, upright, and smaller
C.
virtual, inverted, and magnified
D.
virtual, upright, and magnified
E.
real, inverted, and smaller
Answer:
A
Explanation:
Beacuse it has 2 angles
Answer:
b I do believe sorry if I'm wrong
what is the shape of the path traversed by the earth around the sun?
Answer:
The shape of the path transverse by the Earth around the sun is called an ellipse
Explanation:
:)
So if any of ya got like, screenshots of all the answers for Edge, 2020. Lab-Kinetic Energy-student guide, That would be really helpful. If you could help me, then I will mark you brainliest. And for you trollers out there who just want the points, could you not steal them for this one? Anyways, thanks ya'll!
Answer:
has any one finished the lab yet?????
Explanation:
in a nuclear plant, 1 * 10 ^27 J of energy is available from mass conversion How much mass was lost ?
Answer:
[tex]1.2\times 10^{10}\ kg[/tex]
Explanation:
Given that,
The energy of the nuclear plant, [tex]E=10^{27}\ J[/tex]
We need to find how much mass wast lost.
The relation between energy and mass is given by :
[tex]E=mc^2[/tex]
Where
c is speed of light
[tex]m=\dfrac{E}{c^2}\\\\m=\dfrac{10^{27}}{(3\times 10^8)^2}\\\\m=1.2\times 10^{10}\ kg[/tex]
So, [tex]1.2\times 10^{10}\ kg[/tex] of mass was lost.
Anyone able to help with these questions, will give brainliest to first correct anwser
Answer:
b
Explanation:
I did this question earlier
Which graph shows a vehicle traveling at a constant speed?
(look at the attached photo)