The probability distribution for a
random variable x is given in the table.

The Probability Distribution For Arandom Variable X Is Given In The Table.

Answers

Answer 1

Answer: 79% probability

Step-by-step explanation:

.17 + .13 + .33 + .16 = .79

.79 x 100 = 79%

Answer 2

Answer:

.79

Step-by-step explanation:


Related Questions

Which of the following points is NOT a solution of the inequality y ≥ Ixl + 3?

A. (-3, 0)

B. (-3, 6)

C. (0, 4)​

Answers

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

In an aquarium, there are 7 large fish and 6 small fish. Half of the small fish are red.
One fish is selected at random. Find the probability that it is a small, red fish.
Write your answer as a fraction in simplest form.

Answers

Answer:

3/13

Step-by-step explanation:

There are a total of 13 fish (6+ 7 = 13). There are 3 small, red fish. (1/2 · 6 = 3). Put the number of small, red fish over the total number of fish because the small, red fish is being selected from the entire tank of fish. 3/13 cannot be simplified any further.

A triangle on a coordinate plane is translated according to the rule T-3,5(x, y). Which is another way to write this rule?
(x, y) - (x - 3, y + 5)
(x, y) - (x-3, y-5)
(x,y) - (x + 3, y-5)
(x, y) = (x + 3, y + 5)

Answers

Answer: Choice A. [tex](x,y) \to (x-3, y+5)[/tex]

Explanation:

The notation [tex]T_{-3,5}(x,y)[/tex]  or means to move any point (x,y) along the vector <-3,5>. Put another way, it says to shift (x,y) three units to the left and five units up. The x portion deals with left or right shifting, the y portion deals with up or down shifting. Since the x portion is negative, we go in the negative direction on the x axis. Y being positive means we move up rather than down.

This all means we end up with the translation rule [tex](x,y) \to (x-3,y+5)[/tex]

PLEASE HELP SOLVE THIS!!!!!

Answers

Answer:

20) -43

21) 25

22)-9

Step-by-step explanation:

20) -6 (-6 + 49)/6 = -43

21) 10 - (-10 - (-1 + 6)) = 25

22) 1 - 10/2 - 5 = -9

Step-by-step explanation:

22

Let's calculate the expression khowing that m= 1 and n = 5

m-[tex]\frac{m+m}{2}[/tex] -nm- [tex]\frac{2m}{2}[/tex]-n m-m-n0-n0-5-5

20

Let's calculate the expression khowing that n= -7 and p= - 6

[tex]\frac{p(p+n^{2}) }{6}[/tex] [tex]\frac{-6(-6+(-7)^{2}) }{6}[/tex][tex]\frac{-6(-6+49)}{2}[/tex] [tex]\frac{-6*43}{6}[/tex] -1*43-43

21

Let's calculate the expression khowing that n = -6 and m = -1 and p = -10

mp-(p-(m-n))mp-(p-m+n)mp-p+m-n(-1)*(-10)-(-10)+(-1)-(-6)10+10-1+620-1+619+625

As an example, 15,000 Men 18-34 watched program X at 7-8 pm on Monday night. 32,000 Men 18-34 had their TV on during the same time period. There are 200,000 Men 18-34 in the television households in the market. What would be the rating for Men 18-34 for program X? Group of answer choices 47 rating points 7.5 rating points 16 rating points 23.5 rating points

Answers

Answer:

7.5 rating points

Step-by-step explanation:

The computation of the rating for Men 18-34 for program X is shown below:

Given that

Number of men 18 -34 watched a program X = 15,000 = X

Number of men 18 - 34 watched in a same time = 32,000

And, the total households in the market = 200,000 = Y

So, the rating for men 18-34 for program x is

[tex]= \frac{X}{Y}[/tex]

[tex]= \frac{15,000}{200,000}[/tex]

= 7.5 rating points

We simply applied the above formula

Identify the correct HYPOTHESIS used in a hypothesis test of the following claim and sample data: Claim: "The average annual household income in Warren County is $47,500." A random sample of 86 households from this county is obtained, and they have an average annual income of $48,061 with a standard deviation of $2,351. Test the claim at the 0.02 significance level.

Answers

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

Use the function below to find f(4).
f(x)=1/3x4^x


A. 8/3
B.256/3
C.64/3
D.16/3

Answers

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Simply replace X with 4

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

i need this fast plz

Answers

Answer:

180-130 = 50 degrees because its same side angle

m<2 = 50

Step-by-step explanation:

the second one m<1 is 105 for the same reason

Question 3 of 10
2 Points
If h(x) =(fºg)(x) and h(x) = 3(x + 2), find one possibility for f (x) and g(x).

Answers

Answer:

[tex]\boxed{\sf \ \ \ \text{one possibility is } f(x)=3x \ and \ g(x)=x+2 \ \ \ }[/tex]

Step-by-step explanation:

hello

h(x)=f(g(x))=3(x+2)

if we have f(x)=3x and g(x)=x+2 then

f(g(x))=f(x+2)=3(x+2)

hope this helps

The manufacturer of a certain brand of hot dogs claims that the mean fat content per hot dog is 20 grams. Suppose the standard deviation of the population of these hot dogs is 1.9 grams. A sample of these hot dogs is tested, and the mean fat content per hot dog of this sample is found to be 20.5 grams. Find the probability that the sample mean is at least 20.5 when the sample size is 35.

Answers

Answer:

[tex]z=\frac{20.5-20}{\frac{1.9}{\sqrt{35}}}= 1.557[/tex]

And using the normal standard distribution and the complement rule we got:

[tex]P(z>1.557) =1-P(z<1.557) = 1-0.940 = 0.06[/tex]

Step-by-step explanation:

For this case we define our random variable X as "fat content per hot dog" and we know the following parameters:

[tex]\mu = 20, \sigma =1.9[/tex]

We select a sample of n=35 and we want to find the following probability:

[tex] P(\bar X>20.5)[/tex]

For this case since the sample size is >30 we can use the central limit theorem and we use the z score formula given by:

[tex]z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

Replacing we got:

[tex]z=\frac{20.5-20}{\frac{1.9}{\sqrt{35}}}= 1.557[/tex]

And using the normal standard distribution and the complement rule we got:

[tex]P(z>1.557) =1-P(z<1.557) = 1-0.940 = 0.06[/tex]

Pls help see the picture posted

Answers

I hope this helps you

Simplify. Remove all perfect squares from inside the square root. \sqrt{30b^5}= 30b 5 ​

Answers

Answer:

The answer is b=0 or b=9.085603

The equation is solved and the perfect squares are removed from the square root and A = b²√( 30b )

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = √( 30b⁵ )

On simplifying the equation , we get

We can simplify the given expression by breaking down the number inside the square root into its prime factors:

30b⁵ = 2 x 3 x 5 x b⁵

Since we are looking to remove all perfect squares, we can remove the factors of 2 and 3, which are the only perfect squares present in the prime factorization of 30. This leaves us with:

30b⁵ = 2 x 3 x 5 x b⁵

= 2 x 3 x 5 x b⁴ x b

= 30b⁴ x b

Therefore, we can simplify the original expression as:

√(30b⁵) = √(30b⁴ x b) = √(30b⁴) x √b

A = b²√30 x √b

Hence , the expression √(30b⁵) simplifies to A = b²√30 x √b

To learn more about equations click :

https://brainly.com/question/19297665

#SPJ2

Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1 to catch rainwater off his roof.he has a full 2 liters tin of paint in his store and decides to paint the tank (not the base) If he uses 25ml to cover 1m^2 will he have enough paint to cover the tank with one layer of paint

Answers

Answer:

  yes

Step-by-step explanation:

The lateral area of a cylinder is ...

  LA = πdh

Putting in the given numbers, we find the area to be ...

  LA = π(1.1 m)(1.4 m) ≈ 4.838 m²

At 25 mL per m², the amount of paint Tublu needs is ...

  (4.838 m²)(25 mL/m²) = 120.95 mL

2 liters is 2000 mL, so Tublu easily has enough paint for one layer.

___

The amount he has is enough for more than 16 coats of paint, so he could paint inside and out with the paint he has.

Answer:

he should.

Step-by-step explanation:

If we express $2x^2 + 6x + 11$ in the form $a(x - h)^2 + k$, then what is $h$? (ignore the $)

Answers

Answer:

h = - [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 6x + 11 ( factor out 2 from the first 2 terms )

   = 2(x² + 3x) + 11

Using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 3x

y = 2(x² + 2([tex]\frac{3}{2}[/tex] )x + [tex]\frac{9}{4}[/tex] - [tex]\frac{9}{4}[/tex] ) + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² - [tex]\frac{9}{2}[/tex] + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² + [tex]\frac{13}{2}[/tex] ← in vertex form

with h = - [tex]\frac{3}{2}[/tex]

Simplfy the following expressions:

Answers

Answer:

1st one =  d y^27

2nd one = b 2x^9

Step-by-step explanation:

1st one: since the power is being raised to the power of 3 you multiply the numbers

2nd one: the powers aren't being raised so you add the powers together.

12x^13y^10/6X^4y^10

then dividing for exponents is subtracting them so

2x^9 since y gets canceled out

Please answer this correctly

Answers

Answer:

Question 2 is the right answer.

Step-by-step explanation:

Answer:

Question 2

Step-by-step explanation:

Temperature in the morning =  2°F  above normal temperature = + 2

Temperature at dinner time = 2° F lower than the morning = -2

+2 - 2 = 0° F

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
a. Calculate a 95% two-sided confidence interval on the death rate from lung cancer.
b. Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03?
c. How large must the sample be if you wish to be at least 95% confident that the error in estimating p is less than 0.03, regardless of the true value of p?

Answers

Answer:

a) [tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

b) [tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

c) [tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

[tex]\hat p=\frac{823}{1000}=0.823[/tex]

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96[/tex]

The confidence interval for the mean is given by the following formula:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

If we replace the values obtained we got:

[tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

And on this case we have that [tex]ME =\pm 0.03[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

Part c

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Suppose that we don't have a formula for g(x) but we know that g(3) = −1 and g'(x) = x2 + 7 for all x.
(a) Use a linear approximation to estimate g(2.95) and g(3.05).
g(2.95) =
g(3.05) =
(b) Are your estimates in part (a) too large or too small? Explain.
A) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie below the curve. Thus, the estimates are too small.
B) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie below the curve. Thus, the estimates are too small.
C) The slopes of the tangent lines are positive and the tangents are getting steeper, so the tangent lines lie above the curve. Thus, the estimates are too large.
D) The slopes of the tangent lines are positive but the tangents are becoming less steep, so the tangent lines lie above the curve. Thus, the estimates are too large.

Answers

Answer:

g(2.95) ≈ -1.8; g(3.05) ≈ -0.2A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.

Step-by-step explanation:

(a) The linear approximation of g(x) at x=b will be ...

  g(x) ≈ g'(b)(x -b) +g(b)

Using the given relations, this is ...

  g'(3) = 3² +7 = 16

  g(x) ≈ 16(x -3) -1

Then the points of interest are ...

  g(2.95) ≈ 16(2.95 -3) -1 = -1.8

  g(3.05) ≈ 16(3.05 -3) -1 = -0.2

__

(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)

The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that he must stop at the first signal is 0.36, the analogous probability for the second signal is 0.51, and the probability that he must stop at least one of the two signals is 0.67.What is theprobability that he must stop.
a) At both signals?
b) At the first signal but not at the second one?
c) At exactly on signal?

Answers

Answer:

a) P(X∩Y) = 0.2

b) [tex]P_1[/tex] = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability [tex]P_1[/tex] that he must stop at the first signal but not at the second one can be calculated as:

[tex]P_1[/tex] = P(X) - P(X∩Y)

[tex]P_1[/tex] = 0.36 - 0.2 = 0.16

At the same way, the probability [tex]P_2[/tex] that he must stop at the second signal but not at the first one can be calculated as:

[tex]P_2[/tex] = P(Y) - P(X∩Y)

[tex]P_2[/tex] = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

[tex]P = P_1+P_2\\P=0.16+0.31\\P=0.47[/tex]

Brainliest to whoever gets this correct This word problem has too much information. Which fact is not needed to solve the problem? Tanisha tried to sell all her old CDs at a garage sale. She priced them at $2 each. She put 80 CDs in the garage sale, but she sold only 35 of them. How many did she have left? A. All of the information is needed. B. Tanisha sold the CDs for $2 each. C. Tanisha put 80 CDs in the sale. D. Tanisha sold 35 of the CDs.

Answers

B. tanisha sold the cds for $2 each

Answer:

B. Tanisha sold the CDs for $2 each.

Step-by-step explanation:

Hurry!! Determine the intervals for which the function shown below is decreasing.

Answers

Answer:

everywhere except between 2 and 5

(between -inf and 2 and between 5 and inf)

Step-by-step explanation:

Use the standard normal table to find P(z ≥ 1.06). Round to the nearest percent.

Answers

Answer:

14%

Step-by-step explanation:

On edge 2020

Select the expression that is equivalent to (x - 1)2.
O A. x2 - 2x + 2
O B. x2 - x + 2
O C. x2 - x + 1
O D. x2 – 2x + 1

Answers

Answer:

x^2 -2x+1

Step-by-step explanation:

(x - 1)^2

(x-1) * (x-1)

FOIL

first: x^2

outer: -1x

inner: -1x

last: 1

Add together

x^2 -1x-1x+1

Combine like terms

x^2 -2x+1

Answer:

[tex] \boxed{\sf D. \ {x}^{2} - 2x + 1} [/tex]

Step-by-step explanation:

[tex] \sf Expand \: the \: following: \\ \sf \implies {(x - 1)}^{2} \\ \\ \sf \implies (x - 1)(x - 1) \\ \\ \sf \implies x(x - 1) - 1(x - 1) \\ \\ \sf \implies (x)(x) - (1)(x) - (1)(x) - (1)( - 1) \\ \\ \sf \implies {x}^{2} - x - x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x - ( - 1) \\ \\ \sf \implies {x}^{2} - 2x + 1[/tex]

Binomial factor of 25x2 + 40xy + 16y2 ?

Answers

Answer:

  (5x +4y)^2

Step-by-step explanation:

The first and last terms are both perfect squares, and the middle term is twice the product of their roots. That means the trinomial is the perfect square trinomial ...

  25x^2 +40xy +16y^2 = (5x +4y)^2

_____

It matches the pattern ...

  a^2 +2ab +b^2 = (a +b)^2

Answer:

(5x +4y)^2

Step-by-step explanation:

11- In
how many ways 3 mathematics books, 4 history books ,3
chemisidy books and a biology books can be arranged
on an Shelf so thet all books of the same subjects are
together!​

Answers

Answer:    20,736

Step-by-step explanation:

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

How many meters are in 18,200 milliliter

Answers

Answer:

18.2 :)

Have a great day!!!

PLZZZ I NEED HELP I’ll give 20 POINTS
What is the median of the following data set?
(6,3, 9, 1,7)
03
06
08
09

Answers

Answer:

6

Step-by-step explanation:

Arrange the data from smallest to largest

1,3,6,7,9

The median is the middle number

1,3   ,6,   7, 9

The middle number is 6

Classify the following triangle. Check all that apply.
A. Isosceles
B. Right
C. Obtuse
D. Equilateral
E. Scalene
F. Acute

Answers

Answer:

Equilateral

Acute

Step-by-step explanation:

The sides are all equal as indicated by the lines on each side - Equilateral

The angles are all equal by the angle marks  180/3 = 60 which is less than 90 degrees.  This makes the angles acute

Use a proportion to solve the problem. Round to the nearest tenth as needed.
Triangle in a triangle Find the height of the building. Assume that the height of the person is 5 ft.
104 ft
building
13 ft
5 ft

Answers

Answer:

Height of the building is 40 feet

Step-by-step explanation:

From the figure attached,

Height of the person DE = 5 feet

Let height of the building BC = h feet

Since, ΔABC ~ ΔADE,

Their corresponding sides will be proportional,

[tex]\frac{DE}{BC}=\frac{AD}{AB}[/tex]

[tex]\frac{5}{h}=\frac{13}{104}[/tex]

h = [tex]\frac{104\times 5}{13}[/tex]

h = 40 feet

Therefore, height of the building is 40 feet.

A production facility employs 20 workers on the day shift, 15 workers on the swing shift, and 10 workers on the graveyard shift. A quality control consultant is to select 7 of these workers for in-depth interviews. Suppose the selection is made in such a way that any particular group of 7 workers has the same chance of being selected as does any other group (drawing 7 slips without replacement from among 45).
1. How many selections result in all 7 workers coming from the day shift?
2. What is the probability that all 7 selected workers will be from the day shift?
3. What is the probability that all 7 selected workers will be from the same shift?
4. What is the probability that at least two different shifts will be represented among the selected workers?
5. What is the probability that at least one of the shifts will be un-represented in that sample of workers?

Answers

Answer:

1. 77520

2. [tex]P_1[/tex] = 0.0017

3. [tex]P_2[/tex] = 0.0019

4. [tex]P_3[/tex] = 0.9981

5. [tex]P_4[/tex] = 0.2036

Step-by-step explanation:

The number of ways or combinations in which we can select x elements from a group of n can be calculated as:

[tex]nCx = \frac{n!}{x!(n-x)!}[/tex]

So, there are 77520 selections that result in all 7 workers coming from the day shift. It is calculated as:

[tex]20C7 = \frac{20!}{7!(20-7)!}=77520[/tex]

At the same way, the total number of selections of 7 workers from the 45 is 45C7, so the probability that all 7 selected workers will be from the day shift is:

[tex]P_1=\frac{20C7}{45C7} =0.0017[/tex]

The probability that all 7 selected workers will be from the same shift is calculated as:

[tex]P_2=\frac{20C7+15C7+10C7}{45C7} =0.0019[/tex]

Because the consultant can select all workers from the day shift (20C7) or can select all workers from the swing shift (15C7) or can select all workers from the graveyard shift (10C7).

On the other hand, the probability that at least two different shifts will be represented among the selected workers is the complement of the probability that all 7 selected workers will be from the same shift. So it is calculated as:

[tex]P_3 = 1- P_2=1 - 0.0019 = 0.9981[/tex]

Finally, the probability that at least one of the shifts will be un-represented in that sample of workers is:

[tex]P_4=\frac{25C7+30C7+35C7}{45C7} =0.2036[/tex]

Where 25C7 is the number of ways to select all 7 workers from swing or graveyard shift, 30C7 is the number of ways to select all 7 workers from day or graveyard shift and 35C7 is the number of ways to selects all 7 workers from day shift and swing shift.

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