The quantity of matter in an object. More specifically, it is the measure of the inertia that an object exhibits in response to any effort made to start it, stop it, or change in any way its state of motion

Answer:

5400

Explanation:

i calculated it

Big  brain

Sulfur trioxide/Formula

SO3

this is what i looked up and got

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 30 \times {15}^{2} \\ = 15 \times {15}^{2} \\ = {15}^{3} \: \: \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer: 5N

Explanation:

Horizontal component is the force that is applied as a result of the diagonal application of force.

here in this case,

given diagonal force =10N.

angle= 30°

horizontal component is found using trigonometry..

so,

A vector of magnitude 10 N is provided.

It is at an angle of 30° to the + x axis.

To find:

The components along the x and y axis.

Calculation:

Along x axis:

F(x) = F cos(θ)

=> F(x) = 10 × cos(30)

=> F(x) = 10 (√3/2) = 5√3N

Along y axis:

F(y) = F sin(θ)

=> F(y) = 10 sin(30°)

=> F(y) = 10 × ½

=> F(y) = 5 N.

Additional information:

1. A vector is a quantity that can be defined with both magnitude and direction.

2. Since force is a vector, we are able to break it down into components along chosen axis.

Answer :

556.59 m/s.

Explanation:

Given that,

An airplane is traveling at an altitude of 15,490 meters.

A  box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.

The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :

[tex]v^2-u^2=2as[/tex]

Put u = 0 and a = g

[tex]v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s[/tex]

So, when it hits the ground its velocity is 556.59 m/s.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.2 × 3.1

We have the final answer as

Hope this helps you

Answer:

9.92

Hope I helped

Answer:

[sə′plī ‚vōl·tij] (electricity) The voltage obtained from a power source for operation of a circuit or device.

Explanation:

hope this helps :)

Answer:

credits to the real owner of the answer I just found it here

Answer: it's wind

Explanation:

Answer:

1mph

Explanation:

Answer:

Explanation:

The answer is radiation.

Answer: The pressure exerted on a surface by an object increases as the surface area of contact decreases.

Explanation:

Pressure measures the amount of force exerted per a given area of an object. From this definition, the surface area of the object and force applied, affects the pressure applied.

As Benny presses his finger against a map, nothing happens to the map because the force applied is affected by the increased surface area of his finger. However as he presses a thumbtack into the map using the same force the tack will probably poke a hole in the map because the small( decreased) surface area of the sharp point of the thumbtack produces a much larger pressure on the map than the area of Benny finger. I hope this helps, thanks!

sorry

Explanation:

Sorry

Answer:

3N

Explanation:

Answer:

W = 1526.43 J

Explanation:

Given that,

Force acting on a heavy crate, F = 325 N

The rope will make 29.0° angle with the horizontal

The distance covered by the crate, d = 5.37 m

We need to find the work done by the crate. The work done by an object is given by :

[tex]W=Fd\cos\theta\\\\=325 \times 5.37\times \cos29\\\\=1526.43\ J[/tex]

So, the required work done is 1526.43 J.

Explanation:

Its organism are one cell I think

Answer:

yo so if nobody helps ill gladly take the brainliest

Explanation:

Answer:

[tex]m1v1 + m2v2 = m1v3 + m2v4[/tex]

[tex](0.2 x 5) + (0.3 x 2) = (0.2 x 0) + (0.3 x v4)[/tex]

[tex]1.0 + 0.6 = 0 + 0.3v4,  0.3v4 = 1.6[/tex]

[tex]v4 = 1.6/0.3 = 5.3 m/s (2 sf)[/tex]

Answer:

a) The centripetal acceleration of the car is 0.68 m/s²

b) The force that maintains circular motion is 940.03 N.

c) The minimum coefficient of static friction between the tires and the road is 0.069.

Explanation:

a) The centripetal acceleration of the car can be found using the following equation:

[tex] a_{c} = \frac{v^{2}}{r} [/tex]

Where:

v: is the velocity of the car = 51.1 km/h

r: is the radius = 2.95x10² m

[tex] a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2} [/tex]

Hence, the centripetal acceleration of the car is 0.68 m/s².

b) The force that maintains circular motion is the centripetal force:

[tex] F_{c} = ma_{c} [/tex]

Where:

m: is the mass of the car

The mass is given by:

[tex] P = m*g [/tex]

Where P is the weight of the car = 13561 N

[tex] m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg [/tex]

Now, the centripetal force is:

[tex] F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N [/tex]

Then, the force that maintains circular motion is 940.03 N.

c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:

[tex] F_{c} = F_{\mu} [/tex]

[tex] F_{c} = \mu N = \mu P [/tex]

[tex] \mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069 [/tex]

Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.

I hope it helps you!                

Answer:

v = 14.7m/s

Explanation:

When the rock was at the top of cliff it had only Potential Energy and no Kinetic Energy but soon as the rock hit the ground all the Potential Energy converted into Kinetic Energy so by the Law of Conservation of Energy

[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]

because all of that potential energy got converted into kinetic energy so we use the following formula as we need to calculate the velocity (v)

[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]

here we know  [tex]g = 9.8m/s^2[/tex] because the rock was under free fall motion so it had acceleration of 9.8 but we do not the height which is h but we do know the formula:

[tex]Velocity=\frac{Displacement}{Time}[/tex]

the height h is the displacement so we replace height with the following:

[tex]Velocity=\frac{Displacement}{Time}\\\\Displacement=Velocity*Time\\h=vt[/tex]

now, insert h = vt in the above equation

[tex]v^2=2gh\\\\v^2=2g(vt)\\v^2=2vgt\\\\\frac{v^2}{v} =2gt\\\\v=2gt\\v=2(9.8)(0.75)\\v=14.7m/s[/tex]

Answer:

When a body is in uniform circular motion, its speed remains constant but its velocity, angular acceleration, angular velocity changes due to change in its direction.

Answer:

Sexual reproduction

Explanation:

Its what its called hope it helps

Answer:

i think its called allogamy

Explanation:

Answer:

Hydrothermal vents

Explanation:

A hydrothermal vent is found along with areas of volcanic activity in the ocean floor which discharges geothermally heated water. Tectonic plates in such areas move apart at spreading centers and hotspots to form hydrothermal vent.

A hydrothermal vent ejects hot and often toxic, fluids and gases into the surrounding seawater when seawater meets magma.

Hence, the correct answer is "Hydrothermal vents".

Answer:

v₀ = 16.55 m/s

Explanation:

This motion of the ball can be modeled as a projectile motion with following data:

R = Range of Projectile = 27.5 m

θ = Launch Angle = 50°

g = acceleration due to gravity = 9.81 m/s²

v₀ = Initial Speed of Ball = ?

Therefore, using formula for range of projectile, we have:

[tex]R = \frac{v_{0}^2\ Sin2\theta}{g}\\\\v_{0}^2 = \frac{Rg}{Sin2\theta}\\\\v_{0}^2 = \frac{(27.5\ m)(9.81\ m/s^2)}{Sin100^o}\\\\v_{0} = \sqrt{273.93\ m^2/s^2}[/tex]

v₀ = 16.55 m/s

Answer:

Difference is given below.

Explanation:

The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.

Explanation:

The velocity of an object can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex] v = \frac{10}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

I'll try and find the answer for you:)

Explanation:

I can't promise you I will though