The ratio of the speed of light in a medium to the speed of light in a vacuum
is called its:
A. angle of incidence
B. Snell's Law
C. angle of refraction
D. refractive index

Answers

Answer 1

Answer:D.Refractive Indez

Explanation:

It is usually expressed the other way: the ratio of the speed of light in a vacuum to the speed of light in a medium. In that case, it is called the "index of refraction".

Answer 2

You're going for "refractive index", but you've got the ratio flipped over.


Related Questions

Define centre of mass.​

Answers

Answer:

The center of mass is a position defined relative to an object or system of object

someone pls answer! i will give u brainliest

Answers

Answer:

Liquid

Explanation:

Before anything evaporates, it is in a liquid state.

I think it’s liquid.

After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?

a) 35m/s north
b) 35m/s south
c) 81 m/s north
d) 81 m/s south

Answers

I’m almost 100 percent sure it’s the first one


Two train cars with the same mass (30,000 kg) are traveling in the same direction when they collide.
Train Car A has a velocity of 10 m/s and Train Car B has a velocity of 5 m/s. What is their total
momentum after the collision? Make sure to show all your work and include proper units.

Answers

Answer:

25

Explanation:

I just did this

michael's house is 5.0 km away from his school. How long would it take him to go ti school, riding a bus, if its velocity is 25 km/h?

Pleaseee answer correctly
I mark brainliest who answer this​

Answers

Answer:

12 mins

Explanation:

The distance covered is 5 km, divide this by 25 to get the fraction of an hour it takes. Doing this you get .2, times this by 60 min (1 hour) to get how many mins it takes

When you use a microwave, what is the main way that heat is transferred?
1. radiation
2. convection
3.conduction

Answers

Answer:

the correct answer is 1. radiation

radiacion ! so that would be answer number 1.

HELP ASAP Which statement describes the water particles when condensation takes place?

A. The particles gain heat energy and move closer to each other
B. The particles lose heat energy and move closer to each other
C. The particles gain heat energy and move away from each other
D. The particles lose heat energy and move away from each other

Answers

The answer is going to be B

How much heat does it take to raise 0.0438 kg of aluminum from room temperature (20.0°C) to its melting point (660°C)?

HELP​

Answers

Answer:

2.5x10^4 J (scientific notation)

25,000 (Acellus)

Equation:

Q=mcΔT

where:

Q=heat

m = mass

c = specific heat

ΔT=change in temperature

Any rearranging?

Let's see.

No, we need heat.

So no rearranging.

Plug in the numbers and solve

It takes approximately 28,224 joules of heat to raise 0.0438 kg of aluminum from room temperature to its melting point.

To calculate the heat required to raise the temperature of aluminum from room temperature to its melting point, we need to use the specific heat capacity formula: Q = m × c × ΔT

where:

Q = heat (in joules)

m = mass of aluminum (in kilograms)

c = specific heat capacity of aluminum (in joules per kilogram per degree Celsius)

ΔT = change in temperature (in degrees Celsius)

Given:

Mass of aluminum (m) = 0.0438 kg

Specific heat capacity of aluminum (c) = 900 J/kg°C (approximate value for aluminum)

Change in temperature (ΔT) = melting point (660°C) - room temperature (20°C) = 640°C

Now, let's calculate the heat (Q):

Q = 0.0438 kg × 900 J/kg°C × 640°C

Q = 28,224 J (joules)

So, it takes approximately 28,224 joules of heat to raise 0.0438 kg of aluminum from room temperature to its melting point.

To know more about temperature

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Find the electric field a distance z above the midpoint between equal and opposite charges,a distance d apart

Answers

Answer:

Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex] ,  E_z =0

Explanation:

To find the electric field of each charge, let's use

          E = k q / r²

where the field for a positive charge is outgoing and for a negative charge it is incoming.

Since the electric field is a vector magnitude, let's add its components at the point z

X axis

       Eₓ = E₁ₓ + E₂ₓ

       Eₓ = 2 E₁ₓ

Z axis

       E_z = E_{1z} -E_{2z}

       E_z= 0

Let's find the expression for the electric field

the distance from the charge to the test point, using the Pythagorean theorem is

      r² = (x-0) ² + (0-z) ²

      E = [tex]k \frac{q}{x^2 + z^2}[/tex]

with trigonometry we can find its components

      cos θ = E₁ₓ / E

      E₁ₓ = E cos θ

we substitute

     Eₓ = 2 E cos θ

where the cosine

    cos θ = x / r

     Ex = [tex]2 k \frac{q}{x^2 + z^2} \ \frac{x}{\sqrt{x^2 + z^2} }[/tex]

     Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex]

     E_z = 0

Expresa en notación científica los siguientes números en notación científica estándar: a) 9367421= b) 7241= c) 0.0005519= d) 0.02=

Answers

Answer:

so yeah it is Respuesta

Determine both the mass and the charge of a block of material consisting of 3 x 10^27 protons, 3 x 10^37 neutrons, and 3.1 x 10^27 electrons.

Answers

Answer:

The mass of the block of material is 3 x 10³⁷ g/mol

The charge of the material is  4.8 x 10⁸ C

Explanation:

Given;

number of protons of the material, P = 3 x 10²⁷

number of neutrons in the material, N = 3 x 10³⁷

number of electrons in the material, E =  3 x 10²⁷

The mass of the block of material is calculated as follows;

M = P + N

M =  3 x 10²⁷ +  3 x 10³⁷

M =  3 x 10³⁷ g/mol

The charge of the material is calculated as follows;

charge of 1 electron = 1.6 x 10⁻¹⁹ C

charge of  3 x 10²⁷ electrons =  3 x 10²⁷ electrons   x   1.6 x 10⁻¹⁹ C

                                                = 4.8 x 10⁸ C


A toy train moves round a circular track of radius 0.50 m.
How many radians has the trained turned through in moving 1.4 m along a track?

Answers

Answer:

2.8 radians

Explanation:

[tex]s = r \beta \\ 1.4 = 0.50 \beta \\ \beta = 2.8 \: rad[/tex]

A plastic rod is rubbed with a cloth and becomes positively charged. After charging, the rod is held close to the suspended table-tennis ball shown in Fig. 9.1. The table-tennis ball is covered with metal paint and is uncharged.


Describe what happens to the charges on the metal-painted table-tennis ball as the positively-charged rod is brought close to the ball.

Answers

Charges on the metal painted table-tennis ball gain charges from the positively charged rod and becomes positively charged

Waldo needs to know how much force to apply in order to move a 4000-kg object at 2 m/S2. Which law should he refer to

Answers

Answer:

Newton's second law of motion?

Light waves travel at 3 × 10 8 m/s. If the light wave has a particular wavelength of 400 nm (400 × 10 –9 m), calculate its frequency.

Answers

Answer:

[tex]f=7.5\times 10^{14}\ Hz[/tex]

Explanation:

Given that,

The wavelength of light, [tex]\lambda=400\ nm=400\times 10^{-9}\ m[/tex]

The speed of light, [tex]c=3\times 10^8\ m/s[/tex]

We need to find the frequency of light. We know that,

[tex]c=f\lambda[/tex]

Where

f is the frequency

So,

[tex]f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{400\times 10^{-9}}\\\\f=7.5\times 10^{14}\ Hz[/tex]

So, the frequency of light is [tex]7.5\times 10^{14}\ Hz[/tex].

work done in taking charge from one point of a conductor to is another point is called ​

Answers

Answer:

Explanation:

electric potential

I think so

How much acceleration does a car need if it is to go a distance of 620 ft. In a time of 20 sec while it is speeding up

Answers

31ft/second . 620/20

A force of 20 N acts upon a 5000g block. Calculate the acceleration of the object

Answers

Answer:

a = 4 m/s²

Explanation:

Given: 5000 g, 20N  

To find: Acceleration (a)  

Solution: Firstly, convert 5000g to kilograms

1000g = 1kg

∴ 5000g = 5kg if divided by 1000

A = F ÷ m

=  20 ÷  5  

= 4 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

Which of the following organs are found in the
lower gastrointestinal tract? Check all that apply.


answers are above

Answers

Answer:

small intestine, tongue and large intestine

Explanation:

The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.

how much does the angle of refraction change from 380nm to 700nm when the incident angle is 80?

Answers

Answer:

35 degrees

Explanation:

The incident angle, an 80-degree angle, and as the angle of incidence increases, the amount of refraction also increases. So, we can expect a significant change in the angle of refraction from blue to red light at an 80-degree angle of incidence.

What is refraction?

Refraction refers to the bending of light when it passes from different mediums.The amount of refraction that occurs at an interface between two materials depends on the wavelength of light, the angle of incidence, and the properties of the materials. The relationship between these factors is described by Snell's law:

n1 sinθ1 = n2 sinθ2

where n1 and n2 are the refractive indices of the two materials, θ1 is the angle of incidence, and θ2 is the angle of refraction.

For a given angle of incidence, the amount of refraction that occurs is greater for shorter wavelengths (i.e., blue light) than for longer wavelengths (i.e., red light). This effect is known as dispersion, and it is why we see rainbows when sunlight is refracted through water droplets.

In the absence of any information about the properties of the materials involved, we can assume that the amount of refraction will increase as the wavelength decreases.

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Work done depends on
A. Force
B. Displacement
C. Both force and displacement
D. Neither force nor displacement

Answers

Answer:

C. Both force and displacement

Explanation:

Hope this helps

6CO2 + 6H20 → C6H12O6 + 602
What type of model is shown?
a
b
computer model
conceptual model
physical model
C
mathematical model

Answers

Answer:

C. physical model

Explanation:

Sana nakatulong

An eighth-grade class is studying the motion of objects. They have learned the following concepts about motion.

Motion occurs when there is a change in the position of an object with respect to a reference point.

While the speed of the object may change at various times during a trip the average speed for the trip is found by dividing the total distance by the total time.

The motion of the object can be changed by varying the amount of net force acting on the object or by varying the mass of the object.

The teacher asked students to design investigations to determine how changing the forces acting on an object or the mass of the object would change its motion.

The materials for the investigation included:

1 - toy cart

3 - 10N weights

1 - pulley

2 - meters of string

One group of students decided to design an investigation to determine how different amounts of mass on the toy cart would affect the speed of the toy cart. They set up their investigation as shown below:



The students performed several trials using different masses in the toy cart (M1). They hung a mass shown as (M2) to pull the toy cart as it dropped.

Below is a table they made to record their results.





Which of the following would be a way to test the effect changing the amount of force acting on the object has on the average speed of the object?
Move the cart at various speeds and determine the force at M1
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
Move the cart at various speeds and determine the force exerted by M2

Answers

Add varying numbers of weights to M1 and measure the speed of the car.

Add varying numbers of weights to M2 and measure the speed of the cart.

How to test the effect of weight on the speed of object?

In order to test the changing amount of force that is acting on the object has effect on the average speed of the object we have to change the amount of weight on the object and allows it to move to a certain point in this way we can check the effect of changing amount of weight on the speed of the object.

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A jet plane travels east for
661.8 meters in 6 seconds.
What is the velocity of the plane?
velocity = distance = time

Answers

3,970.8

Explanation:

v=661.8×6

3,970.8

El diámetro del embolo de una jeringa para inyección mide 1.5 cm. Una enfermera ejerce una fuerza de 2N cuando inyecta a su paciente. Calcule la presión que ejerce el fluido inyectado sobre las venas.

Answers

Answer:

Presión = 11111,11 N/m

Explanation:

Dados los siguientes datos;

Diámetro = 1,5 cm a metros = 1,5 / 100 = 0,015 m

Fuerza = 2N

Para encontrar la presión;

En primer lugar, determinaríamos el área del círculo usando la fórmula;

Área del círculo = πr²

Radio = diámetro/2 = 0.015/2 = 0.0075 m

Área de la jeringa = 3.142 * 0.0075²

Área de la jeringa = 3.142 * 0.00005625

Área de la jeringa = 0.00018 metros

Ahora, podemos encontrar la presión usando la fórmula;

Presión = fuerza/área

Presión = 2/0.00018

Presión = 11111,11 N/m

If the car goes exits a freeway and goes from 65
mph to 35 mph is it accelerating?

Answers

Answer:

No, the car is decelerating  

Explanation:

No the car is decelerating if it exits a freeway and goes from 65

mph to 35 mph since the change in velocity is negative.

change in velocity = final - initial

change in velocity  = 35 - 65

change in velocity = -30mph

Since the change in velocity is negative, hence the car is decelerating. Deceleration is a negative acceleration

A spring has an unstretched length of
12.0 cm. Its stiffness k is 8 N/cm. What load is
needed to stretch the spring to a length of 15.0 cm?

Answers

Answer:

24 N

Explanation:

Given,

Unstretched length or original length , x1 = 12cm

Stiffness constant, k = 8 N/cm

Load required to take spring to a length , x2 of 15cm

Recall the relation :

F = Ke

Where, e = extension

e = x2 - x1

e = (15 - 12) = 3

F = ke

F = 8 N/cm * 3cm

F = 24 N/cm*cm

F = 24 N

Hence, required load = 24 N

PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
I am soooooooooooo desperate.

Answers

Answer:

the answers the correct one is C

Explanation:

In radioactive decay processes, a very important concept is the half-life time, which is the time it takes for the parent nuclei to decompose into child nuclei.

expressed this mathematically is

              N = N₀ [tex]e^{- \lambda t}[/tex]

for the average life time

              N₀ / 2 = N₀  [tex]e^{- \lambda T_{1/2}[/tex]

               T =[tex]\frac{ln 2x}{ \lambda}[/tex]

Analyzing this expression, the nuclei that decay are the so-called parents and the new nuclei called children appear.

when checking the answers the correct one is C

Need help pls. It is for acellus

Answers

Answer:

The height of the water column = 1.62405[tex]\overline{30}[/tex] × 10⁻¹ m

Explanation:

The air cavity in the Coke bottle = 0.220 m deep

The fundamental (frequency) it plays when water is added to shorten the column and it is blown across the top, f = 528 Hz

The given speed of sound in air, v = 343 m/s

We note that the air cavity in the coke bottle is equivalent to a tube closed at one end

The fundamental frequency for a tube closed at one end, 'f', is given as follows;

f = v/(4·L) = v/λ

Where;

L = The height of the water column

λ = The wavelength of the wave

∴ 4·L = v/f = (343 m/s)/(528 Hz) = 0.6496[tex]\overline{21}[/tex] m

∴ L = 0.6496[tex]\overline{21}[/tex] m/4 = 0.162405[tex]\overline{30}[/tex] m

The height of the water column = 1.62405[tex]\overline{30}[/tex] × 10⁻¹ m.

Answer:

0.058

Explanation:

got it right on acellus

A spherical conducting shell has charge -5 C. A particle with charge -8 C is placed at the center of the cavity. The charges (in C) on the inner surface and on the outer surface of the shell, respectively, are:

Answers

Answer:

Explanation:

The charge of - 5C will be spread  on the outer surface of the shell . The presence of - 8C charge at the Centre will create + 8C charge on the inner surface and - 8C charge on the outer surface . The result is that the total charge on the outer surface of the shell will be - 5C + - 8C = - 13C and the inner surface will have charge of + 8C . + 8C charge will be locked to centrally situated - 8C charge and will not be neutralized by negative charge of outer surface .

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