The ratio x:y is 1:3
Which of the following statements are correct?
A. x is 1/3 of y
B. y is 2 of (x + y)
C x is 1/4 of y
D. y is 3/4 of x​

Answer:

SD = 2x

UD = x[tex]\sqrt{3}[/tex]

Step-by-step explanation:

The hypotenuse of a 30-60-90 triangle is 2 times the length of the shorter leg.

SU is the shorter leg = x

So, SD = 2x

The longer leg of a 30-60-90 triangle is [tex]\sqrt{3}[/tex] times the shorter leg.

So, UD = x[tex]\sqrt{3}[/tex]

Answer:

Below in bold.

Step-by-step explanation:

In  a 30-60-90 triangle the sides are in the ratio 1:√3:2 so if the shortest side SU = x then the long leg = √3x and the hypotenuse = 2x.

Answer:

The Answer is 8.

Its the only Number that Multiplies itself three times to give 512.

So the Cube root of 512... Should be 8.

Answer:

8.

Step-by-step explanation:

512 = 64* 8

∛512 = ∛64 * ∛8

= 4 * 2

= 8.

Answer:

A because it uses all of domains

Step-by-step explanation:

Answer:

-1

Step-by-step explanation:

Answer:

The longest length is 30 cm

Step-by-step explanation:

Mathematically, the perimeter of a triangle is simply the sum of the lengths of its three sides

So, what we have to do here is divide the perimeter in the given ratio to get the side lengths

since 5 is the biggest of the numbers in the ratio, it represents the largest length value

so we have this as;

(3 + 4 + 5) = 12

So that would be;

5/12 * 72

= 5 * 6 = 30

Answer:

130

Step-by-step explanation:

total apple juice= 1560

if 12 children share juice equally

they get

=1560/12

= 130

Answer:

A triangle is dilated by scale factor of 1/5

Step-by-step explanation:

A triangle has three sides. All the corresponding angles of triangle must be congruent. When the triangle is dilated it is rotated 90 degrees clockwise about its origin. The shape of the triangle will not change due to rotation of dilation.

Answer: Use the app photo math, you just take a picture and it gives you the answer and shows you the steps:)

1) x> 5

2) x< 2

3) x<-6

4) x< 2

5) x> 2

6) x> - 7/2

Step-by-step explanation:

See the images below for the work:)  The images will be in order with the number the first problem will be the answer to the first.

Answer:

[tex]\sf 1)\:4x - 2 > 2x + 8[/tex]

Add 2 from both sides:

[tex]\sf 4x-2+2>2x+8+2[/tex]

[tex]\sf 4x>2x+10[/tex]

Subtract 2x from both sides:

[tex]\sf 4x-2x>2x+10-2x[/tex]

[tex]\sf 2x>10[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{10}{2}[/tex]

[tex]\boxed{\sf x>5}[/tex]

_______________________________

[tex]\sf 2)\: -3x - 6 > 4x - 20[/tex]

Add 6 from both sides:

[tex]\sf -3x-6+6>4x-20+6[/tex]

[tex]\sf -3x>4x-14[/tex]

Subtract 4x from both sides:

[tex]\sf -3x-4x>4x-14-4x[/tex]

[tex]\sf -7x>-14[/tex]

Multiply both sides by -1:

[tex]\sf\left(-7x\right)\left(-1\right)<\left(-14\right)\left(-1\right)[/tex]

[tex]\sf 7x<14[/tex]

Divide both sides by 7:

[tex]\sf \cfrac{7x}{7}<\cfrac{14}{7}[/tex]

[tex]\boxed{\sf x<2}[/tex]

_______________________________

[tex]\sf 3)\: 4(x + 1) < 3x - 2[/tex]

Apply distributive property:

[tex]\sf 4x+4<3x-2[/tex]

Subtract 4 from both sides:

[tex]\sf 4x+4-4<3x-2-4[/tex]

[tex]\sf 4x<3x-6[/tex]

Subtract 3x from both sides:

[tex]\sf 4x-3x<3x-6-3x[/tex]

[tex]\boxed{\sf x<-6}[/tex]

_______________________________

[tex]\sf 4)\: 2x + 3 + x < -2x + 1 + 12[/tex]

Combine like terms:

[tex]\sf (2x+x)= 3x[/tex]

[tex]\sf( 1+12)=13[/tex]

[tex]\sf 3x+3<-2x+13[/tex]

Subtract 3 from both sides:

[tex]\sf 3x+3-3<-2x+13-3[/tex]

[tex]\sf 3x<-2x+10[/tex]

Add 2x from both sides:

[tex]\sf 3x+2x<-2x+10+2x[/tex]

[tex]\sf 5x<10[/tex]

Divide both sides by 5:

[tex]\sf \cfrac{5x}{5}<\cfrac{10}{5}[/tex]

[tex]\boxed{\sf x<2}[/tex]

________________________________

[tex]\sf 5)\: 2(x - 1) > 4x + 4 - 5x[/tex]

Combine like terms:

[tex]\sf (4x-5x)=-x[/tex]

[tex]\sf 2\left(x-1\right)>-x+4[/tex]

Apply distributive property:

[tex]\sf 2x-2>-x+4[/tex]

Add 2 from both sides:

[tex]\sf 2x-2+2>-x+4+2[/tex]

[tex]\sf 2x>-x+6[/tex]

Add x from both sides:

[tex]\sf 2x+x>-x+6+x[/tex]

[tex]\sf 3x>6[/tex]

Divide both sides by 3:

[tex]\sf \cfrac{3x}{3}>\cfrac{6}{3}[/tex]

[tex]\boxed{\sf x>2}[/tex]

_______________________________

[tex]\sf 6)\: 2 + 4x -7 < 8x + 2 - 2x[/tex]

Subtract 2 from both sides:

[tex]\sf 2+4x-7-2<8x+2-2x-2[/tex]

[tex]\sf 4x-7<8x-2x[/tex]

Combine like terms:

[tex]\sf (8x-2x)=6x[/tex]

[tex]\sf 4x-7<6x[/tex]

Add 7 from both sides:

[tex]\sf 4x-7+7<6x+7[/tex]

[tex]\sf 4x<6x+7[/tex]

Subtract 6x from both sides:

[tex]\sf 4x-6x<6x+7-6x[/tex]

[tex]\sf -2x<7[/tex]

Multiply both sides by -1:

[tex]\sf \left(-2x\right)\left(-1\right)>7\left(-1\right)[/tex]

[tex]\sf 2x>-7[/tex]

Divide both sides by 2:

[tex]\sf \cfrac{2x}{2}>\cfrac{-7}{2}[/tex]

[tex]\boxed{\sf x>-\frac{7}{2}}[/tex]

_______________________________________

Answer:its C because the base is the bottom of the figure and C goes to the middle point at the bottom of the figure

Step-by-step explanation:

Answer:

[tex]x=-1[/tex]

Step-by-step explanation:

[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]

Step 1: Simplify both sides of the equation.

[tex]\frac{7}{2}x+\frac{1}{2}x=\frac{1}{2}+\frac{9}{2}x[/tex]

[tex](\frac{7}{2}x+\frac{1}{2}x)=\frac{9}{2}x+\frac{1}{2}[/tex]  (Combine Like Terms)

[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]

[tex]4x=\frac{9}{2}x+\frac{1}{2}[/tex]

Step 2: Subtract [tex]\frac{9}{2}x[/tex] from both sides.

[tex]4x-\frac{9}{2}x=\frac{9}{2}x+\frac{1}{2}-\frac{9}{2}x[/tex]

[tex]\frac{-1}{2}x=\frac{1}{2}[/tex]

Step 3: Multiply both sides by [tex](\frac{2}{-1})[/tex].

[tex](\frac{2}{-1})*(\frac{-1}{2}x)=(\frac{2}{-1})*(\frac{1}{2})[/tex]

[tex]x=-1[/tex]

Therefore, [tex]x=-1[/tex] will be your final answer.

Sorry this took very long. I had to calculate all of this.