Answer:
Proofing and language.
Explanation:
Write a program that prompts the user to enter a Social Security number in the format ddd-dd-dddd, where d is a digit. The program displays Valid SSN for a correct Social Security number or Invalid SSN otherwise.
ssn = input("Enter a valid Social Security number: ")
dashes = 0
nums = 0
message = "Invalid SSN"
if len(ssn) == 11:
for x in ssn:
if x.isdigit():
nums += 1
elif x == "-":
dashes += 1
if nums == 9 and dashes == 2:
message = "Valid SSN"
print(message)
I wrote my code in python 3.8. I hope this helps!
The program that prompts the user to enter a Social Security number in the format ddd-dd-dddd, where d is a digit can be implemented in Python using regular expressions. The regular expression pattern for the SSN format can be used to validate the input.
Pythons code:
```python
import re
ssn_pattern = re.compile(r'^\d{3}-\d{2}-\d{4}$')
ssn = input("Enter your Social Security Number (format: ddd-dd-dddd): ")
if ssn_pattern.match(ssn):
print("Valid SSN")
else:
print("Invalid SSN")
```
In the above code, we first import the `re` module to work with regular expressions.
We then define the regular expression pattern for the SSN format as `^\d{3}-\d{2}-\d{4}$`. This pattern matches any string that starts with three digits, followed by a hyphen, then two digits, another hyphen, and finally, four digits.
We then prompt the user to enter their SSN using the `input()` function. We then check if the entered SSN matches the pattern using the `match()` function of the regular expression object `ssn_pattern`.
If the SSN matches the pattern, we print "Valid SSN". Otherwise, we print "Invalid SSN".
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