OKKKKK I NEEEDDDDD HELLPPPPP WITHHHHHHH MATTTTTTTTTTTHHHHHHHHH
Hi i have this class work of my cousing
but i need some help beacause i forgot this
the first question is 5_8
Answer:
5 < 8
-4 < 0
0 < 4
-5 < 5
-9 > -19
-5 > -8
Step-by-step explanation:
Remember, the "Alligator" or better known as the "Packman" symbol ( > < )
It will always want to "eat" the bigger number. so, 8 is bigger than five, so the "Packman" will want to go after the bigger number. 5 < 8
which one should I choose
Answer:
The radius is 8.5
Step-by-step explanation:
Mathematically, the radius of a circle is the distance from the center of the circle to its circumference
Thus, as we have here;
The two marked lengths are radii of the inner inscribed circle and this means that they are equal in length
thus;
x + 6 = 5x-4
5x - x = 6 + 4
4x = 10
x = 10/4
x = 2.5
Now, to get the radius length, substitute the value of x in any of the lengths
from x + 6
2.5 + 6 = 8.5
D) 9. What is the solution to this equation?
2x + 10 = 28
Answer:
X=9
Step-by-step explanation:
I know this because you can find the answer by doing 28 - 10 which equals 18 and 2 times 9 gets you 18 and would make the equation
( 2 times 9) + 10= 28
18 + 10=28
1. What is the greatest common factor of
6x2 – 3x + 18?
a. 3
b. 3x
C. 6x
d. There is no GCF
Answer:
a. 3
Step-by-step explanation:
[tex]6 {x}^{2} - 3x + 18 \\ \\ = 3(2 {x}^{2} - x + 6) \\ \\ GCF = 3[/tex]
the greatest common factor of 6x2 – 3x + 18 is 3.
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life
Here, given that,
6x2 – 3x + 18
=3×(2x2-x+6)
Hence, the greatest common factor of 6x2 – 3x + 18 is 3.
To learn more on multiplication click:
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help me plz: In a race Ram covers 5 km in 20 min. how Much distance will he cover in 100 min? 25 km , 26 km ,35km ,or 40km plz help me
5km :20min
? km :100min
here you do cross multiplication.
SOLUTION:
5×100=500
500÷20=25KM
DONE!!!!
Step-by-step explanation:
This is called direct propotion where you do cross multiplication!!
keep that in mind
Another word one! Please help only if you know, thank you!
Answer:
Step-by-step explanation:
if C is the right angle,
AB is the hypotenuse
AB^2=AC^2+BC^2
AC^2=13^2-5^2
AC^2=169-25=144
AC=[tex]\sqrt{144}[/tex]=12
AC=12
In the diagram below, AB = BD = BC, and mZA = 24°. Find
mZC.
Answer:
m∠C = 66°
Step-by-step explanation:
Since AB = BD, it means this triangle is an Isosceles triangle and as such;
∠BAD = ∠BDA = 24°
Thus, since sum of angles in a triangle is 180,then;
∠ABD = 180 - (24 + 24)
∠ABD = 180 - 48
∠ABD = 132°
We are told that BC = BD.
Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC
Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.
Thus;
132 = ∠BCD + ∠BDC
Since ∠BCD = ∠BDC, then
∠BCD = ∠BDC = 132/2
∠BCD = ∠BDC = 66°
if 24 golf balls weigh 2 1/4 pounds, how much would 60 golf balls weigh
Answer:
5.625 pounds or 5 5/8 pounds
Step-by-step explanation:
(2 1/4)/24 = weight of one golf ball = 0.09375
0.09375 x 60 = 5.625 pounds or 5 5/8 pounds
Answer:
5.625 pounds or 5 5/8 pounds as a fraction
Step-by-step explanation:
Answer choices 192m to the 2nd power, 25m to the 2nd power 177 ft to the 2nd power 242 inches to the second power 61 ft to the 2nd power 40 inches to the 2nd powe
40m to the 2nd power when doing the math its 40m to the 2nd power and then you get ur answer :)
Answer:
i got 61 ft2
Step-by-step explanation:
rectangle: 10 x 4=40
triangle: 7 x 6=42 x 1/2= 21
40+21=61
also its says ft in each measurement
61 ft to the second power (61 ft2)
-kenma #3
(hopefully im right this time)
XYZ is a triangle in which XY = 11 centimeters and YZ = 15 centimeters. The length of XZ is in whole centimeters and is greater than 20 centimeters. What are the possible lengths of XZ?
Answer:
Possible lengths of [tex]XZ[/tex] are [tex]21\,\,cm,22\,\,cm,23\,\,cm,24\,\,cm,25\,\,cm[/tex]
Step-by-step explanation:
According to triangle inequality theorem,
length of one side is less than the sum of remaining two sides.
Also,
[tex]XY=11\,\,cm\\YZ=15\,\,cm\\XZ>20\,\,cm[/tex]
Therefore,
[tex]20<XZ<15+11\\20<XZ<26[/tex]
The length of [tex]XZ[/tex] is in whole centimeters.
Therefore, possible lengths of [tex]XZ[/tex] are [tex]21\,\,cm,22\,\,cm,23\,\,cm,24\,\,cm,25\,\,cm[/tex]
You deposit $1200 in an account. The account earns $120 simple
interest in 8 months. What is the annual interest rate? PLS HELP WILL GIVE BRAINLIEST AND ITS DUE SOON
We have to find the unit rate, so we have to divide what you earned in interest by the amount of months.
120/8=15
So you earn $15 per month
---
sorry if this doesn't help
WILL GIVE BRAINLIEST
Answer:
Answer:
4 m
Step-by-step explanation:
I took the test
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The volume of a cone (V) is calculated as
V = [tex]\frac{1}{3}[/tex] πr²h ( r is the radius and h the height )
Here V = 151 and r = diameter ÷ 2 = 12 ÷ 2 = 6 , then
[tex]\frac{1}{3}[/tex] πr²h = 151 ( multiply both sides by 3 to clear the fraction )
πr²h = 453 , that is
3.14 × 6² × h = 453
3.14 × 36h = 453
113.04h = 453 ( divide both sides by 113.04 )
h ≈ 4 m ( to the nearest metre ) → B
A rectangle’s length is three times its width, w. Its area is 243 square units. Which equation can be used to find the width of the rectangle?
w2 = 3(243)
3w2 = 243
4w2 = 243
3w2 = 3(243)
Answer:
3w² = 243
Step-by-step explanation:
Width = w
Length = 3w
Area = 243 square units
length *width = 243
3w * w = 243
3w² = 243
The equation that you can used to determine the width of the rectangle with the given area is: 3w² = 243
What is the Area of a Rectangle?Area = (length)(width)
The given dimensions are:
Width = w unitsLength = 3w unitsArea of rectangle = 343 sq. unitsThe equation to se in finding the width (w) of the rectangle will be:
3w(w) = 243
3w² = 243
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2. For a school project, Terence is taking a survey of students' favorite type
of shoe. Which sampling method would likely provide the representative
sample of the students? *
O Survey 10 students in a math class.
O
Survey only the students wearing sandals.
Survey 20 students who play basketball
Survey every 4th student who walks into the cafeteria.
Survey every 4th student who walks into the cafeteria.
At any time t ≥ 0, in hours, the rate of growth of a population of bacteria is given by dy/dt = 0.5y. Initially, there are 200 bacteria.
(a) Solve for y, the number of bacteria present, at any time t ≥ 0.
(b) Write and evaluate an expression to find the average number of bacteria in the population for 0 ≤ t ≤ 10.
(c) Write an expression that gives the average rate of bacteria growth over the first 10 hours of growth. Indicate units of measure.
Answer:
(a) The equation for the number of bacteria at time t ≥ 0 is [tex]y = 200\cdot e^{0.5 \cdot t }[/tex]
(b) The average population in the bacteria for 0 ≤ t ≤ 10 is 29,482 bacteria
(c) The growth rate of the bacteria in the first 10 hours is 14,841 Bacteria/hour
Step-by-step explanation:
(a) The given rate of growth of the bacteria population is;
[tex]\dfrac{dy}{dt} = 0.5 \cdot y[/tex]
The initial amount of bacteria = 200
At time, t ≥ 0, we have;
[tex]\dfrac{dy}{y} = 0.5 \cdot dt[/tex]
[tex]\int\limits {\dfrac{dy}{y} } = \int\limits {0.5} \, dt[/tex]
ln(y) = 0.5·t + C
[tex]y = e^{0.5 \cdot t + C}[/tex]
[tex]y = C_1 \cdot e^{0.5 \cdot t }[/tex]
When, t = 0, y = 200, we have;
[tex]200 = C_1 \cdot e^{0.5 \times 0 } = C_1[/tex]
C₁ = 200
The equation for the number of bacteria at time t ≥ 0 is therefore given as follows;
[tex]y = 200\cdot e^{0.5 \cdot t }[/tex]
(b) The expression for the average number of bacteria in the population for 0 ≤ t ≤ 10 is given as follows;
[tex]y = \int\limits^t_0 {0.5 \cdot y} \, dt[/tex]
[tex]y = \int\limits^{10}_0 {0.5 \cdot 200\cdot e^{0.5 \cdot t }} \, dt = \left[200\cdot e^{0.5 \cdot t }\right]^{10}_0 \approx 2,9682.6 - 200 = 29,482.6[/tex]
The average population in the bacteria for 0 ≤ t ≤ 10 is therefore, y = 29,482
(c) The average rate of growth after 10 hours of growth is given as follows;
[tex]\dfrac{dy}{dt} = 0.5 \cdot y[/tex]
[tex]\dfrac{dy}{dt} = 0.5 \cdot 200\cdot e^{0.5 \cdot 10 } = 14,841.32 \ Bacteria/hour[/tex]
The growth rate of the bacteria in the first 10 hours is 14,841 Bacteria/hour
Population functions can either represent growth or decays.
The given parameter is:
[tex]\frac{dy}{dt}= 0.5y[/tex]
(a) Solve for y
We have:
[tex]\frac{dy}{dt}= 0.5y[/tex]
Integrate both sides
[tex]\int \frac{dy}{dt}= \int 0.5y[/tex]
Divide both sides by y, and multiply both sides by dt
[tex]\int \frac{dy}{y}= \int 0.5\ dt[/tex]
Integrate both sides of the equation
[tex]\ln(y) = 0.5t +c[/tex]
Take the exponent of both sides
[tex]y = e^{0.5t +c}[/tex]
This gives
[tex]y = ce^{0.5t}[/tex]
When t = 0, and y = 200.
So, we have:
[tex]200 = ce^{0.5 \times 0}[/tex]
[tex]200 = ce^{0}[/tex]
Evaluate the exponent
[tex]200 = c[/tex]
Rewrite as:
[tex]c = 200[/tex]
Substitute 200 for c in [tex]y = ce^{0.5t}[/tex]
[tex]y = 200e^{0.5t}[/tex]
Hence, the equation for y is [tex]y = 200e^{0.5t}[/tex]
(b) The average number of bacterial for 0 ≤ t ≤ 10.
The average value of the function is calculated as:
[tex]y' = y(10) - y(0)[/tex]
Calculate y(0) and y(10)
[tex]y = 200e^{0.5t}[/tex]
[tex]y(0) = 200e^{0.5(0)}= 200[/tex]
[tex]y(10) = 200e^{0.5\times 10} =29682.6318205[/tex]
So, we have
[tex]y' = y(10) - y(0)[/tex]
[tex]y' = 29682.6318205 - 200[/tex]
[tex]y' = 29482.6318205}[/tex]
[tex]y' = 29483[/tex]
Hence, The average number of bacterial for 0 ≤ t ≤ 10 is 29483
(c) The average rate over the first 10 hours of growth
We have:
[tex]\frac{dy}{dt}= 0.5y[/tex]
Substitute [tex]y = 200e^{0.5t}[/tex]
[tex]\frac{dy}{dt}= 0.5 \times 200e^{0.5t}[/tex]
[tex]\frac{dy}{dt}= 100e^{0.5t}[/tex]
When t = 10, we have:
[tex]\frac{dy}{dt}= 100e^{0.5 \times 10}[/tex]
[tex]\frac{dy}{dt}= 100e^{5}[/tex]
[tex]\frac{dy}{dt}= 14841[/tex]
Hence, the average rate over the first 10 hours of growth is 14841
Read more about population growth functions at:
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Evaluate the algebraic expression 3f + g,when f = 6, g = 8, h = 12 and j = 2. A. 30 B. 26 C. 17 D. 13
Answer: A.26
Step-by-step explanation:
= 3f+g
= 3 (6)+8
=26
negative 7 over 3, the whole multiplied by x minus 3 equals negative 52
Answer:
21
Step-by-step explanation:
Which values from the set -6, -4, -3, -1, 0, 2 satisfy this inequality?
−12x + 3≥ 5
-6, -4 , -3 , and - 1 only
-6 and -4 only
- 1 , 0, and 2 only
-4, -3, -1, 0, and 2 only
I REALLY NEED HELP THIS IS A TEST
Answer:
-6, -4 , -3 , and - 1 only.
Step-by-step explanation:
−12x + 3 ≥ 5
-12x ≥ 5 - 3
-12x ≥ 2
Divide both sides by -12:
x ≤ -1/6 (Note the inequality sign flips because we are dividing by a negative value).
So considering the given set, all the values except 0 and 2 fit this inequality.
if p is the smallest of four consecutive even integers what is their sum interms of p.
Answer:
4p + 12
Step-by-step explanation:
p + p+2 + p+4 + p+6 = 4p + 12
Of 20 test scores, four are less than or equal to 85. What is the percentile rank of a test score of 85
Answer:
Bottom 20% percentile
Step-by-step explanation:
4/20= .2
Here is an inequality: -2x>10.
List some values for x that would make this inequality true.
How are the solutions to the inequality -2x10 different from the solutions to -2x>10? Explain your reasoning.
Answer:
The difference is -2x10 is basically-2 times x times 10.
Step-by-step explanation:
Cuz i said so
The x values that makes the given inequality true are -10, -9, -8, -7 and -6.
What are inequalities?Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
The given inequality is -2x>10.
Divide -2 on both the sides of an inequality, we get
x<-5
So, the solution is {.......-10, -9, -8, -7, -6}
Hence, the x values that makes the given inequality true are -10, -9, -8, -7 and -6.
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I need help with these questions (see image). Please show workings.
Answer:
Inscribed angle is half of the intercepted arc.Central angle is the same size as the intercepted arc.As per above two statements we have:
y = 2*58° = 116°and
z = 90°/2 = 45°Answer:
y=58×2=116 central angle of the cyclic quadrilateral is double if inscribed angle
z=90/2=45
inscribed angle is half of central angle of the cyclic quadrilateral
Solve the following system of equations by substitution
2x – 3y = -1
y = x - 1
Answer:
(4, 3)
Step-by-step explanation:
Plug in x - 1 where y is. The equation will turn in 2x - 3(x - 1) = -1. Distribute, and you'll have 2x -3x + 3 = -1. Combine like terms (2x and -3x) and you'll have -x + 3 = -1. Subtract 3 from both sides, and you'll have -x = -4. Divide by -x (or -1) on both sides, and you'll have x = 4. Since y = x - 1, y = 3, since 4 - 1 = 3. Sorry if this sounds repetitive btw. Good luck :D
the mean of a group of students in 60 . if their marks 85 ,65,36 ,48 , X ,75 ,39,72 then find the value of x
Answer: 60
Step-by-step explanation:
Find the total number of students.
In this case, there are 8 total students. Multiply 60 * 8 = 480
Add all the numbers up.
85 + 65 + 36 + 48 + 75 + 39 + 72 = 420
480 - 420 = 60
x = 60
find the area of the figure
Answer:
area = 92 yd²
Step-by-step explanation:
13x8 = 104
3x8x0.5 = 12
104 - 12 = 92 yd²
Answer:
Step-by-step explanation:
PLZZZZ HELP ME WITH THIS QUESTION WITH AN EXPLANATION
Answer :
Given : A and B are complementary angles. B and C are complementary angles.
Prove : A C
I have attached a picture of me doing it. Hope this helps, thank you :) !!
help please i rlly need it
What is the answer this question is hard answer fast plz
Answer:
Step-by-step explanation:
I believe it is b
SOMEONE ANYONE PLEASE HELP ME WITH A SCIENCE ENGINEERING LAB ITS NOT HARD
Answer:
Sure, where is the activity
Answer:
where is it?
Step-by-step explanation: