The second H-shaped polygon is a scaled copy of the first. The height of the original H is 5 units. The width is 10. The center bar is 4 across. The height of the copy is about 1.25 units. The width is about 2.5. The center bar is 1 across. Show one pair of corresponding points and two pairs of corresponding sides in the original polygon and its copy. Consider using colored pencils to highlight corresponding parts or labeling some of the vertices. What scale factor takes the original polygon to its smaller copy? Explain or show your reasoning.

Answer:

128

Step-by-step explanation:

sorry if no correct

Answer:

with what

Step-by-step explanation:

Answer:

1. C. Rotation

-The rectangle rotated clockwise

2. A. Translation

-The shape moved  but it didn't change its appearance in any other way, which concludes to your answer "translation"

Answer:

1) C

2) B

Step-by-step explanation:

1) they rotated the rectangle

2) you see the reflection

162 cow-days

Since the initial grass and the grass accumulated over 4 days is equal to 144 cow-days, the initial grass is equal to (144 − 36) or 108 cow-days. Now, to find the answer to the question: in 18 days, the grass accumulation is equal to 18 ∗ 9 or 162 cow-days.

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Using the principle of proportional relationship, it will take 20 cows 7.2 days.

Setting up the relationship thus :

36 cows = 4 days

Hence, if they eact at the same rate ;

1 cow = 36 × 4 = 144 days

Hence, for 20 cows, it will take;

144 days ÷ 20

= 7.2 days

Hence, 20 cows will feed on the grass for 7.2 days

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Answer:

y=-2x-1

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than [tex]A(t)=A_{0}e^{kt}[/tex]. for example, if an initial population P₀ requires n units of time to triple, then the function [tex]P(t)=P_{0}(3)^{\frac{t}{n} }[/tex] models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form [tex]P(t)=P_{0}(3)^{\frac{t}{n} }[/tex] that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form [tex]A(t)=A_{0}e^{kt}[/tex].

Answer: a) [tex]P(t)=50(3)^{\frac{t}{30} }[/tex]

              b) P(t) = 280 insects

              c) t = 74 days

             d) [tex]A(t)=50e^{0.037t}[/tex]

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

[tex]P(t)=50(3)^{\frac{t}{30} }[/tex]

b) In t = 47 days:

[tex]P(t)=50(3)^{\frac{t}{30} }[/tex]

[tex]P(47)=50(3)^{\frac{47}{30} }[/tex]

[tex]P(47)=50(3)^{1.567}[/tex]

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

[tex]750=50(3)^{\frac{t}{30} }[/tex]

[tex]\frac{750}{50}=(3)^{\frac{t}{30} }[/tex]

[tex](3)^{\frac{t}{n} }=15[/tex]

Using the property Power Rule of logarithm:

[tex]log(3)^{\frac{t}{30} }=log15[/tex]

[tex]\frac{t}{30}log(3)=log15[/tex]

[tex]t=\frac{log15}{log3} .30[/tex]

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

[tex]A(t)=A_{0}e^{kt}[/tex]

[tex]3A_{0}=A_{0}e^{30k}[/tex]

[tex]3=e^{30k}[/tex]

Use Power Rule again:

[tex]ln3=ln(e^{30k})[/tex]

[tex]ln3=30k[/tex]

[tex]k=\frac{ln3}{30}[/tex]

k = 0.037

Equation for exponential growth will be:

[tex]A(t)=50e^{0.037t}[/tex]

Answer:

Step-by-step explanation:

X+y=8

X=2y-8

Answer:

8 lions 15 tigers

Step-by-step explanation:

Answer:

4, -19

Step-by-step explanation:

Answer:

4 and -19

Step-by-step explanation:

Answers on edge 2021

Answer:

remote interior angle

Step-by-step explanation:

Answer:

option C

Step-by-step explanation:

got it right on edge 2020

The expression Z₁ -Z₂ is 4 - (4√3 -16)i.

Subtraction is mathematic operation. Which is used to remove terms or objects in expression.

The given expression Z₁ = 4 - 4√3i.

And Z₂ = -16i

Subtract Z₂ to Z₁:

Z₁ -Z₂

=  4 - 4√3i - (-16i)

=  4 - (4√3 -16)i.

Therefore,  Z₁ -Z₂ is 4 - (4√3 -16)i.

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Answer: 80

10/16=0.625

0.625x80=50

Answer:c=2m+1.50

Step-by-step explanation:

If you plug in each mile for M that’s how you get the answer .

Answer:

14, 1352, 36.8, 50.8, 50.8

Step-by-step explanation:

Hope this helped!

Answer:

213 acres

Step-by-step explanation:

Answer:

5,2

Step-by-step explanation:

Clockwise rotations for 90 is

The preimage of (x,y), or for this problem, (-2,5) into (y,-x).

So, a clockwise rotation is from x,y into y,-x

So we do -2,5 into 5,2

We flipped the x and y, and the 2 became positive because two negatives equal a positive

When a point is rotated, it must be rotated through a point.

The image of P is: (5,2)

The point is given as:

[tex]\mathbf{P = (-2,5)}[/tex]

The rule of 90 degrees clockwise rotation is:

[tex]\mathbf{(x, y) \to (y, -x)}[/tex]

So, we have:

[tex]\mathbf{(-2, 5) \to (5, 2)}[/tex]

This gives:

[tex]\mathbf{P' = (5, 2)}[/tex]

Hence, the image of P is: (5,2)

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Answer: 12. X = 14

Step-by-step explanation:

10x + 17 = 87 + 5x

10x = 70 + 5x

5x = 70

X = 14

Answer:

86

Step-by-step explanation:

Answer: the answer is 86

Step-by-step explanation:

Answer:

3750

Step-by-step explanation:

Simple interest (I) is calculated as

I = [tex]\frac{PRT}{100}[/tex] ( P is the principal, R is rate of interest and T time in years )

Here P = 25000, R = 5 and T = 3 , thus

I = [tex]\frac{25000(5)(3)}{100}[/tex]

  = [tex]\frac{375000}{100}[/tex]

  = 3750

Answer:

Albert is 24. Albert's father is 48

Step-by-step explanation:

Answer:

4.500

Step-by-step explanation:

Answer:

Step-by-step explanation:  for 8 thirds use the long lines to count back from 5 to 0 then once u get 0 use the little lines to get to 8 thirds towards 5 and do the same for -11 thirds but towrds -5

Answer:

The answer is $14.6 for the plain paper and $14.12

Step-by-step explanation:

I think i'm probably wrong but 6+9= 15 so 219 divided by 15 is 14.6 so thats answer 1 and 12+13=25 and 353 divided by 25 is 14.12

:p sorry if im incorrect

Answer: The first answer for 6 of wrapping paper and 9 wrapping paper is $7.30. The second answer for 12 wrapping paper and 13 rolls of SHINY wrapping paper is $4.38.

Step-by-step explanation:

Answer: -3/8

Step-by-step explanation:

Answer:

the area would be "4x2+9+12x"

sorry if this doesn't help :(

Step-by-step explanation:

Answer:

Answer given in the photo

Complete question is;

Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall. Decide whether each of the crate sizes described below has the same volume as Justin’s crate.

a. 9 feet long, 1 foot wide, 4 feet tall

b. 8 feet long, 2 feet wide, 2 feet tall

c. 4 feet long, 4 feet wide, 3 feet tall

d. 8 feet long, 3 feet wide, 3 feet tall

e. 6 feet long, 2 feet wide, 4 feet tall Answer:

Options C & E have the same volume as Justin's crate.

Step-by-step explanation:

We are told Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall.

Thus, original volume is;

V_o = 8 × 2 × 3 = 48 ft³

A) For a dimension of 9 feet long, 1 foot wide, 4 feet tall , volume is;

V_a = 9 × 1 × 4 = 36 ft³

B) For a dimension of 8 feet long, 2 feet wide, 2 feet tall, volume is;

V_b = 8 × 2 × 2 = 32 ft³

C) For a dimension of 4 feet long, 4 feet wide, 3 feet tall, volume is;

V_c = 4 × 4 × 3 = 48 ft³

D) For a dimension of 8 feet long, 3 feet wide, 3 feet tall, volume is;

V_d = 8 × 3 × 3 = 72 ft³

E) For a dimension of 6 feet long, 2 feet wide, 4 feet tall, volume is;

V_e = 6 × 2 × 4 = 48 ft³

Looking at all the options, the only ones that given a volume equal to Justin's original volume are options C & E.

Answer:

The greatest common factor of 128 and 192 is 64, because 64 is the highest number that is divisible by both numbers.

The greatest common factor of 128 and 192 is 64 because 64 is the highest number that is divisible by both numbers.

The greatest common factor is the largest positive number which can be divided into given numbers evenly.

In mathematics, the largest positive integer that divides each of the integers is known as the greatest common divisor of two or more integers that are not all equal to zero. The greatest common divisor of two integers is x and y.

Given that the two numbers are 128 and 192. The greatest common factor is the largest number which is divided into both numbers.

128 = 2 x 2 x 2 x 2 x 2 x 2 x 2

192 = 2 x 2 x 2 x 2 x 2 x 2 x 3

The greatest common factor is,

GCF =  2 x 2 x 2 x 2 x 2 x 2

GCF = 64

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Answer:

first use your brain

Step-by-step explanation:

step by step you have to learn first

Answer:

30

Step-by-step explanation:

15 x 2 = 30

he was q5 feet ahead so in another hour he will be 30 feet