The shaded portion of the bar model in Part A shows 38. What percent is equivalent to 38? Enter the correct answer in the box.

Answers

Answer 1

Question:

The shaded portion of the bar model in Part A shows 3/8. What percent is equivalent to 3/8? Enter the correct answer in the box.

Answer:

The equivalent is 37.5%

Step-by-step explanation:

Given

[tex]\frac{3}{8}[/tex]

Required

The equivalent

The model is not shown, but the question can still be solved.

We have:

[tex]\frac{3}{8}[/tex]

Multiply by 100%

[tex]\frac{3}{8} = \frac{3}{8} * 100\%[/tex]

[tex]\frac{3}{8} = 0.375 * 100\%[/tex]

[tex]\frac{3}{8} = 37.5\%[/tex]


Related Questions

A local frame shop charges $5 per foot for the wood to make a frame. You want to have an 8 inch by 10 inch picture frame. How much will it cost?

Answers

Answer:15$

Step-by-step explanation:

i'll pay someone to do my math <3

Answers

I would like to be paid, then xD

Write the y-intercept of the graph of -6x + y = 8.

Answers

Answer:

0,8

Step-by-step explanation:

help pls ok fast pls

Answers

Answer:

I would say the last one. If its wrong then its definitely option 9y/3

Sorry if its wrong :(

juan drove 126 miles in 3 hours. If he continued at the same rate, how long would it take to travel 336 miles? ​

Answers

Answer:

8 hours

Step-by-step explanation:

First you divide 126 by 3 to get the Miles Per Hour, you should get 42 Miles Per Hour, then, just divide 336 by 42 to get the numbers of hours he will have to drive, (which is 8)

Answer:

8 hours

Step-by-step explanation:

126 miles - 3 hours

336 miles - x hours

Cross multiply

126x = 336 x 3

126x = 1008

Divide both sides by 126

x = 1008/126

x = 8

Let f be differentiable such that f(-2)=3,f(3)=5, f'(-2)=4 and f'(3)=6. Let g be differentiable functions such that g(x)=f^-1 (x) for all x. What is the value of g'(3)

Answers

Answer:

[tex]g'(3)=\frac{1}{4}[/tex]

Step-by-step explanation:

There is a rule in calculus that tells us that:

[tex]g'[f(x)]=\frac{1}{f'(x)}[/tex]

In this case, we know that f(-2)=3, therefore:

g'(3)=g'(f(-2))

So, if we used the rule, we would get that:

[tex]g'[f(-2)]=\frac{1}{f'(-2)}[/tex]

we know that f'(-2)=4, so:

[tex]g'[f(-2)]=\frac{1}{4}[/tex]

or:

[tex]g'[3]=\frac{1}{4}[/tex]

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