The solubility of sodium acetate is 46 g per 100 g H₂O at
20°C and 170 g per 100 g H₂O at 100°C. A solution is
prepared by adding 112 g of sodium acetate to 100g of water at
25°C, heating the solution to 100°C and cooling back to 20°C.
How much will recrystallize when a seed crystal is added?

Answers

Answer 1

The solution contains 66 g of sodium acetate, which is less than the maximum amount that can remain in the solution, no recrystallization occurs when a seed crystal is added.

Calculate the amount of sodium acetate that dissolves in 100 g of water at 25°C:

46 g NaC₂H₃O₂ / 100 g H₂O = x / 100 g H₂O

x = 46 g

Therefore, at 25°C, the solution is already supersaturated and contains 112 g - 46 g = 66 g of undissolved sodium acetate.

When the solution is heated to 100°C, all the sodium acetate dissolves, since the solubility at this temperature is 170 g per 100 g H₂O. The total mass of the solution is now 100 g + 112 g = 212 g.

When the solution is cooled back to 20°C, the solubility of sodium acetate decreases to 46 g per 100 g H₂O. The maximum amount of sodium acetate that can remain in solution at this temperature is:

46 g NaC₂H₃O₂ / 100 g H₂O x 212 g H₂O = 97.52 g NaC₂H₃O₂

All the sodium acetate remains dissolved in the solution.

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Related Questions

Need help answering this question in the picture

Answers

The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to find out the concentration of a binary solution. Here the molarity is 0.67 M. The correct option is D.

The molarity of a solution is defined as the number of moles of the solute dissolved per liter of the solution. It is represented by the letter 'M' and it is expressed in the unit mol / L.

Molarity = Number of moles of solute  / Volume of solution in liters

M = 0.500 / 0.75 = 0.66 mol / L ≈ 0.67 M

Thus the correct option is D.

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Burning Dorito chips releases 12,357 J of thermal energy. Assuming all the heat is absorbed by a 234.2g sample of water with initial temp of 22C, what would be the temperature of the water

Answers

Answer:

22°C + 14.82°C = 36.82°C

Explanation:

We can use the formula:

q = mCΔT

where q is the heat absorbed by the water, m is the mass of the water, C is the specific heat of water, and ΔT is the temperature change of the water.

We are given q = 12,357 J, m = 234.2 g, and an initial temperature of 22C. The specific heat of water is 4.184 J/(g·°C).

Plugging in the numbers, we get:

12,357 J = (234.2 g)(4.184 J/(g·°C))(ΔT)

Solving for ΔT, we get:

ΔT = 14.82°C

Therefore, the final temperature of the water would be:

22°C + 14.82°C = 36.82°C

under what circumstances do you think credit cards should NOT be used ?

Answers

It's never a good idea to use your credit card when experiencing strong emotions, especially if you tend to steer toward 'retail therapy.

If a dilute solution of hydrochloric acid is electrolysed, what gas will be produced at the anode? Answer in words not symbols.​

Answers

If a dilute solution of hydrochloric acid (HCl) is electrolyzed, the gas produced at the anode (positive electrode) will be chlorine gas (Cl₂). When a dilute solution of hydrochloric acid (HCl) is electrolyzed, it undergoes a process called electrolysis.

In the case of hydrochloric acid, it dissociates into hydrogen ions (H+) and chloride ions (Cl-). The positive hydrogen ions (H+) are attracted to the cathode (negative electrode) and are involved in the reduction reaction. At the cathode, hydrogen gas (H₂) is produced as a result of the reduction of H+ ions. At the anode (positive electrode), the chloride ions (Cl-) are attracted. Here, the chloride ions undergo oxidation, losing electrons and forming chlorine gas (Cl₂). The chlorine gas is released as a product of the reaction at the anode.

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Copper has a specific heat capacity of 0,385 J/g °C. A 105g sample is exposed to 15.2 kJ in an
insulated container. How many degrees will the temperature of the copper sample increase?

Answers

Answer:

12 degrees

Explanation:

A sample of neon gas at 50c and a volume of 2.5 liters is cooled to 25c. What is the new volume

Answers

Answer: 2.31 L

Explanation:

charles law  v2= V1 x T2/T1

temperature must be in Kelvin

V2=2.5 X 298.15 / 323.15 =2.31 L

Im confused as to how to know whether a element is a atom or Ion

Answers

The element with atom or ion can be filled as

B        neutral atom          5 proton             5 electron

[tex]Mg^{2+}[/tex]       cation                12 proton                10 electron

[tex]Ge^-[/tex]           anion                32 proton               33 electron

Because they have an equal amount of protons and electrons, atoms are neutral particles. Ions are electrically charged particles that may be created by either taking electrons away from neutral atoms to form positive ions or adding electrons to neutral atoms to produce negative ions. The quantity of protons remains constant during the formation of an ion. By taking out one or more electrons, neutral atoms can be transformed into positively charged ions.

B        neutral atom          5 proton             5 electron

[tex]Mg^{2+}[/tex]       cation               12 proton                10 electron

[tex]Ge^-[/tex]           anion                32 proton               33 electron

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What volume of O2 at 760. mmHg and 27 ∘C is required to synthesize 11.0 mol of NO?

Answers

To determine the volume of O2 required to synthesize 11.0 mol of NO, we need to use the ideal gas law equation:

PV = nRT

Where:

P = Pressure (in this case, 760. mmHg)

V = Volume

n = Number of moles (11.0 mol of NO)

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature (27 ∘C = 27 + 273 = 300 K)

Rearranging the equation to solve for V:

V = (nRT) / P

Substituting the given values:

V = (11.0 mol) * (0.0821 L·atm/(mol·K)) * (300 K) / (760. mmHg)

Note that we need to convert the pressure from mmHg to atm:

1 atm = 760 mmHg

V = (11.0 mol) * (0.0821 L·atm/(mol·K)) * (300 K) / (760/760)

Simplifying the equation:

V = 3.44 L

Therefore, the volume of O2 required to synthesize 11.0 mol of NO at 760. mmHg and 27 ∘C is 3.44 L.

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Conclusion
Discuss accuracy and precision of your experiment by comparing your value of the heat of reaction
to the textbook/table value. As part of your accuracy discussion, calculate the percent error. What
sources of error could account for your percent error? Be very specific and mention at least three.
For each error, tell if it would cause the heat of each specific reaction to he too high or too low
[Mg HCI, MgO+ HCI), Next, tell how each error would affect the heat of the overall reaction.
Use the errors in the conclusions section of the previous experiment as a guide to the errors that
should be discussed.

Answers

The degree of proximity between a measured value and the actual value can be defined as Accuracy.

Precision is one that is used to know the level of uniformity present in a group of measurements that are repeated multiple times.

The Possible sources of error in the above experiment can be :

Instrumental errorsProcedural errorsEnvironmental errors

What is the errors about?

By conducting an experiment and comparing the outcome of the heat of reaction with the accepted value presented in a textbook or table, it is possible to compute the percentage of deviation. The percentage deviation can either be positive or negative and represents whether the experimentally obtained value is higher or lower than the accepted value, respectively.

Each mistake has the potential to result in an excessive or inadequate level of heat for the individual reaction. The  Insufficient execution of the procedure can impact the individual reaction's thermal energy.

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Of the following, which atom has the smallest atomic radius:
Sb
As
Rb
Ba
OK

Answers

Answer:

Rubidium (Rb)

Explanation:

Sb: 206pm

As: 185pm

Rb: 303pm

Ba: 268pm

How many moles of water are represented by 7.43 x 1018 molecules of water

Answers

Answer:

approx 7.41 sextillion

Explanation:

One mole of any substance contains 6.022 x 10^23 particles (Avogadro's Number). Therefore, 1 mole of water contains 6.022 x 10^23 water molecules.

To find how many moles are represented by 7.43 x 10^18 molecules of water, we can divide 7.43 x 10^18 by Avogadro's Number:

7.43 x 10^18 / 6.022 x 10^23 = 0.0123 moles of water

Now, we can use this to find the number of water molecules:

0.0123 moles x 6.022 x 10^23 molecules/mole = 7.41 x 10^21 molecules of water

Therefore, 7.43 x 10^18 molecules of water represent 7.41 x 10^21 molecules or approximately 7.41 sextillion (7,410,000,000,000,000,000) molecules of water.

How much solute is needed to make a 50.0mL of a 0.100 M solution of each reactant when using copper (ll) sulfate + sodium Hydroxide

Answers

We need 0.798 g of copper (ll) sulfate and 0.400 g of sodium hydroxide to make a 50.0 mL of a 0.100 M solution of each reactant.

To determine the amount of solute needed to make a 50.0 mL of a 0.100 M solution of each reactant when using copper (ll) sulfate and sodium hydroxide, we need to use the formula:

Molarity (M) = moles of solute ÷ volume of solution (in liters)

First, we need to calculate the number of moles of solute needed. Since the molar ratio of copper (ll) sulfate to sodium hydroxide is 1:2, we will need twice as many moles of sodium hydroxide as copper (ll) sulfate.

Let's start with copper (ll) sulfate:

Molarity (CuSO4) = 0.100 M

Volume (V) = 50.0 mL = 0.0500 L

Using the formula, we can rearrange it to solve for moles of solute:

moles of CuSO4 = Molarity × Volume

moles of CuSO4 = 0.100 M × 0.0500 L

moles of CuSO4 = 0.00500 mol

Next, we can calculate the number of moles of sodium hydroxide needed:

moles of NaOH = 2 × moles of CuSO4

moles of NaOH = 2 × 0.00500 mol

moles of NaOH = 0.0100 mol

Now that we know the number of moles of each solute needed, we can calculate the mass of each solute needed using their respective molar masses:

mass of CuSO4 = moles of CuSO4 × molar mass of CuSO4

mass of CuSO4 = 0.00500 mol × 159.61 g/mol

mass of CuSO4 = 0.798 g

mass of NaOH = moles of NaOH × molar mass of NaOH

mass of NaOH = 0.0100 mol × 40.00 g/mol

mass of NaOH = 0.400 g

Therefore, we need 0.798 g of copper (ll) sulfate and 0.400 g of sodium hydroxide to make a 50.0 mL of a 0.100 M solution of each reactant.

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Mole questions Chemistry Copper is a product of the reaction that occurs when dry ammonia is passed over a sample of heated copper (II) oxide. The equation for the reaction is given below: 1. 2NH3 + 3CuO → 3Cu + 3H₂O + N₂. Calculate the mass of copper produced if 0.12 dm³ of nitrogen is produced a room temperature and pressure rtp), [Relative atomic mass of Cu = 64; One mole of gas occupies 24dm³ at rtp.] (4 marks)​

Answers

The mass of copper produced is 0.48 g.

From the balanced equation, we can see that 2 moles of NH3 produce 1 mole of N2. Therefore, the number of moles of N2 produced from 0.12 dm³ (120 cm³) of N2 gas at RTP can be calculated as:

n(N2) = (volume of gas at RTP) / (molar volume at RTP)

n(N2) = (120 cm³) / (24 dm³/mol)

n(N2) = 0.005 mol

According to the balanced equation, 3 moles of Cu is produced for every 2 moles of NH3. Therefore, the number of moles of Cu produced can be calculated as:

n(Cu) = (3/2) * n(N2)

n(Cu) = (3/2) * 0.005 mol

n(Cu) = 0.0075 mol

The molar mass of Cu is 64 g/mol. Therefore, the mass of copper produced can be calculated as:

mass(Cu) = n(Cu) * M(Cu)

mass(Cu) = 0.0075 mol * 64 g/mol

mass(Cu) = 0.48 g

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A hermit lives in a mountain cabin 50 miles outside of town. The hermit received a letter that their cabin is outside of the electric company’s range and they will no longer be able to access the power grid. The hermit is worried because the mountain region experiences several months with below-freezing temperatures each year. With no electrical energy available, which method would most likely provide enough thermal energy to heat the hermit’s cabin?

Answers

With no electrical energy available, conduction would most likely provide enough thermal energy to heat the hermit’s cabin.

Thermal energy is defined as a type of energy which is contained within a system which is responsible for temperature rise.Heat is a type of thermal energy.It is concerned with the first law of thermodynamics.

Thermal energy arises from friction and drag.It includes the internal energy or enthalpy of a body of matter and radiation.It is related to internal energy and heat .It arises when a substance whose molecules or atoms are vibrating faster.

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Draw out the skeletal structure of cis-2-methylcyclohexano

Answers

The chemical structure of the compound is shown in the image attached.

How do you draw a chemical structure?

Ascertain the molecule's atomic composition and the types of bonds (covalent, ionic, etc.) that each atom forms.

The skeletal structure, which is a straightforward illustration of the molecule's framework, should be drawn first. To do this, a series of lines are drawn to symbolize the atoms' bonds.

By positioning the atoms at the ends of the bond lines, you may complete the skeleton framework.

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A chemical equation is given
below. How would you classify
this reaction?
Na₂CO3 → Na₂O + CO₂
A.single replacement
B. Synthesis
C. Combustion
D. Decomposition

Answers

ANSWER:

D (because because it results in two compounds from one substance)

A compound is found to be 30.45% N and 69.55 % O by mass. If 1.63 g of this compound occupies 389 mL at 0.00° C and 775 mmHg, what is the molecular formula of the compound?

Answers

The molecular formula mass ratio is approximately 1.48, the molecular formula of the compound is approximately N₁O₂.

To determine the molecular formula of the compound, we need to follow a series of steps. First, we calculate the moles of nitrogen (N) and oxygen (O) in the given mass percentage composition.

Assuming we have 100 g of the compound, we would have:

30.45 g of N

69.55 g of O

Next, we calculate the number of moles of each element using their respective molar masses:

Moles of N = 30.45 g / 14.01 g/mol ≈ 2.18 mol

Moles of O = 69.55 g / 16.00 g/mol ≈ 4.35 mol

We then divide the number of moles by the smallest number of moles (in this case, N) to obtain a simple ratio:

N ≈ 2.18 mol / 2.18 mol = 1

O ≈ 4.35 mol / 2.18 mol ≈ 2

This gives us the empirical formula, which is N₁O₂.

Finally, to determine the molecular formula, we need to find the ratio of the empirical formula's molar mass to the experimental molar mass provided. We calculate:

Empirical formula mass of N₁O₂ = 14.01 g/mol + (2 × 16.00 g/mol) = 46.01 g/mol

Experimental molar mass = 1.63 g / (389 mL × 0.00°C / 22.4 L/mol × 0.775) = 68.34 g/mol

Dividing the experimental molar mass by the empirical formula mass:

Molecular formula mass ratio = 68.34 g/mol / 46.01 g/mol ≈ 1.48

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on and
1 of 1
What is the final volume in milliliters when 0.694 L of a 36.2 % (m/v) solution is diluted to
20.3 % (m/v)?
Express your answer with the appropriate units.

Answers

The final volume when 0.694 L of a 36.2% (m/v) solution is diluted to 20.3% (m/v) is approximately 1236 mL.

To calculate the final volume in milliliters when a solution is diluted, we can use the formula:

(V1)(C1) = (V2)(C2),

where V1 is the initial volume, C1 is the initial concentration, V2 is the final volume, and C2 is the final concentration.

In this case, we have:

V1 = 0.694 L (initial volume)

C1 = 36.2% (m/v) (initial concentration)

C2 = 20.3% (m/v) (final concentration)

We need to solve for V2, the final volume.

Using the formula, we can rearrange it to solve for V2:

V2 = (V1)(C1) / C2

Substituting the given values:

V2 = (0.694 L)(36.2% (m/v)) / 20.3% (m/v)

Calculating this expression, we find:

V2 = (0.694 L)(0.362) / 0.203

V2 = 1.23628 L

Since the question asks for the final volume in milliliters, we convert the result to milliliters by multiplying by 1000:

V2 = 1.23628 L × 1000 mL/L

V2 ≈ 1236 mL

Therefore, the final volume when 0.694 L of a 36.2% (m/v) solution is diluted to 20.3% (m/v) is approximately 1236 mL.

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A 3.43 mol sample of helium is in a 27.17 L container. What is the
pressure of this gas in atmospheres at 219 °C?
A) 2.21 atm
B) 5.10 atm
C) 6.50 atm
D) 7.92 atm

Answers

:Response: 2.21 atm The ideal gas law says that the pressure of a gas is equal to the quantity of the gas times the universal gas constant (R) times the temperature (T) times the volume (V) divided by the number of moles in the gas.

Consequently, we may apply the following equation to this issue: P = (n*R*T)/V. We may get the pressure of the gas in atmospheres by using the following formula, where n is the number of moles, V is the volume, T is the temperature, and R is the universal gas constant.

P is equal to 2.21 atm or (3.43 mol*0.0821 L*atm/mol*K*492.15 K)/27.17 L. As a result, choice A) 2.21 atm is the right one.

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4. Show your calculation for the concentration (mg/mL) of ascorbic acid in the initial vitamin C tablet/capsule solution
that you prepared?

Answers

Use the following formula to obtain the ascorbic acid content in milligrams of a vitamin C tablet:

Mass of ascorbic acid (mg) = Volume of NaOH (mL) x Concentration of NaOH (mol/L) x Molar mass of ascorbic acid (g/mol) x 1000 / 1

We must first determine the molar mass of ascorbic acid:

Molar mass of ascorbic acid = (6 x atomic mass of carbon) + (8 x atomic mass of hydrogen) + (6 x atomic mass of oxygen)

= (6 x 12.01) + (8 x 1.01) + (6 x 16.00)

= 176.12 g/mol

Now we can substitute the values ​​in the formula into:

Mass of ascorbic acid (mg) = 20.74 mL x 0.201 mol/L x 176.12 g/mol x 1000 / 1

= 739.1 mg

Therefore, the amount of ascorbic acid in the Vitamin C tablet is 739.1 mg.

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Your question is incomplete, most probably the complete question is:

A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NaOH solution. From the results of this titration, the mg of ascorbic acid in the tablet was calculated. Molecular formula of ascorbic acid: C6H8O6 Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 20.74 Concentration of NaOH in mol/L, 0.201 Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg).

Which is one way that spring tides are different from regular tides?

Answers

Answer:

high tides are a little higher and low tides are a little lower than average

Explanation:

A spring tide is the highest tide (when the greatest difference between the high and low tides). This happens during the new and full moon.

Answer: It's worth noting that low tides can sometimes be lower than usual, which is referred to as spring tides. Despite its name, this phenomenon isn't related to spring and has a different historical origin.

how may liters are in 0.8291moles of hexane (c6h14)?

Answers

In 0.8291 moles of hexane ([tex]C_6H_1_4[/tex]) there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

To determine the number of liters in 0.8291 moles of hexane (C6H14), we need to use the ideal gas law equation:

PV = nRT

where:

P = pressure (atm)

V = volume (L)

n = moles of gas

R = gas constant (0.0821 L*atm/mol*K)

T = temperature (K)

We need to rearrange this equation to solve for V:

V = nRT/P

First, we need to calculate the number of moles of hexane:

n = mass/molar mass

The molar mass of hexane (C6H14) is:

6(12.01 g/mol) + 14(1.01 g/mol) = 86.18 g/mol

n = 0.8291 moles

Next, we need to convert the temperature to Kelvin. Assuming room temperature (25°C or 298 K):

T = 298 K

Finally, we need to assume a pressure value. Let's assume atmospheric pressure (1 atm).

P = 1 atm

Now we can plug in the values and solve for V:

V = (0.8291 mol)(0.0821 L*atm/mol*K)(298 K)/(1 atm)

V = 20.8 L

Therefore, there are 20.8 liters in 0.8291 moles of hexane at room temperature and atmospheric pressure.

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The VSEPR Theory is used to

A). Predict Molecular Structure
B). Predict Crystal Structures
C). Predict Lewis Structures
D). Determine the partial charge o on each atom

Answers

Answer:

Explanation:

VSEPr Gives you the structures of molecules

A

write and equation for ache of each antacid with hydrochloric acid
magnesium hydroxide
calcium carbonate
aluminum hydroxide

Answers


1. Magnesium hydroxide:

Mg(OH)2(s) + 2HCl(aq) → MgCl2(aq) + 2H2O(l)

2. Calcium carbonate:

CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)

3. Aluminum hydroxide:

Al(OH)3(s) + 3HCl(aq) → AlCl3(aq) + 3H2O(l)

Hope this helps!

how many calories are in a snack with 175 kj of energy

Answers

Answer:

41826.05 Calories

Explanation:

1 J = 0.239006 Calories

175 KJ

= 175 x 1000 J

= 175000 J

175000 J to Calories

= 175000 x 0.239006

= 41826.05 Calories

Answer: 41.8

Explanation:

Acellus verified ✅

PLEASE HELP!!!
2C₂H6 (g) + 702 (g) —> 4CO2 (g) + 6H₂O(g)

If 10.0 liters of ethane gas are used, how many liters of oxygen gas will be
needed for the above reaction at STP?
A: 35.0 liters
B: 2.85 liters
C: 70.0 liters
D: 1.4 liters

Answers

The volume (in liters) of oxygen gas, O₂ that will be needed for the above reaction at STP is 35 liters (option A)

How do i determine the volume of oxygen gas needed?

The volume of oxygen gas needed for the reaction can be obtain as shown below:

Balanced equation:

2C₂H₆(g) + 7O₂(g) —> 4CO₂(g) + 6H₂O(g)

From the question given above, we were told that the reaction occur at standard temperature and pressure, STP. Thus we can obtain the volume of oxygen needed as follow::

2 liters of C₂H₂ reacted with 7 liters of O₂

Therefore

10 liters of C₂H₂ will react = (10 liters × 7 liters) / 2 liters = 35 liters of O₂

Thus, we can conclude that the volume of oxygen gas needed for the reaction is 35 liters (option A)

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Distinguish between the order and the molecularity of a reaction ​

Answers

The order of a reaction is determined experimentally and describes the relationship between the rate of a reaction and the concentration of reactants, whereas the molecularity of a reaction is a theoretical concept that describes the number of molecules that participate in the rate-determining step of a reaction.

The order of a reaction is the mathematical representation of the relationship between the rate of a reaction and the concentration of reactants. It describes how the rate of a reaction changes with respect to the change in concentration of reactants.

The order of a reaction is determined experimentally by observing how the rate of a reaction changes as the concentration of reactants is varied while keeping the concentration of other reactants and conditions constant. The order of a reaction can be 0, 1, 2, or even a fraction.

The molecularity of a reaction ​is the number of reactant molecules that collide in a single step to form the product. The molecularity of a reaction can be unimolecular (1), bimolecular (2), or termolecular (3). It is important to note that not all reactions have a molecularity, as some reactions have multiple steps and multiple reactants involved.

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Find the concentration of the missing substance
11) A + B = C
K=20,
IAl=2,
[B=5
[C] =
12) A(s) + B(ag) = C(g)
K = 10
B=

Answers

11. The concentration of C is 200

12. The concentration of B is 0.4

How do i determine the equilibrium concentrations?

Equilibrium constant, K is defined as follow:

nReactant ⇌ mProduct

Equilibrium constant, K = [Product]ᵐ / [Reactant]ⁿ

With the above formula, we can obtain the equilibrium concentration of the missing substance as follow:

11. For concentration of C

A + B ⇌ CEquilibrium constant (K) = 20Concentration of A, [A] = 2Concentration of B, [B] = 5Concentration of C, [C] =?

K = [C] / [A][B]

20 = [C] / (2 × 5)

20 = [C] / 10

Cross multiply

[C] = 20 × 10

Concentration of C, [C] = 200

12. For concentration of B

A(s) + B(aq) ⇌ C(g)Equilibrium constant (K) = 10Concentration of C, [C] = 4Concentration of B, [B] = ?

K = [C] / [B]

10 = 4/ [B]

Cross multiply

10 × [B] = 4

Divide both sides by 10

[B] = 4 / 10

Concentration of B, [B] = 0.4

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Complete question:

Find the concentration of the missing substance

11) A + B = C

K = 20

[A] = 2

[B] = 5

[C] =?

12) A(s) + B(ag) = C(g)

K = 10

[C] = 4

[B] = ?

2)
If I have an unknown quantity of gas at a pressure of 121.6 mmHg, a volume of
45L, and a temperature of 87 °C, how many moles of gas do I have?

Answers

If one has an unknown quantity of gas at a pressure of 121.6 mmHg, a volume of 45 L, and a temperature of 87 °C, then that person has approximately 1.93 moles of gas.

To find the number of moles of gas

PV = nRT

where: P = pressure V = volume, n = number of moles R = the gas constant T = temperature.

One needs to rearrange this equation to solve for n:

n = PV/RT

where R is the gas constant, which has a value of 0.08206 L•atm/mol•K.

121.6 mmHg = 0.160 atm

87 °C = 360 K

n = (0.160 atm)(45 L) / (0.08206 L•atm/mol•K)(360 K)

n = 1.93 mol

Therefore, one has approximately 1.93 moles of gas.

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Gene copies that are different versions of a trait are called

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Gene copies that are different versions of a trait are called alleles. Understanding alleles and their inheritance patterns is crucial in genetics and is the foundation of the principles of Mendelian inheritance.

An allele is a specific form of a gene that is responsible for a particular trait or characteristic. For example, the gene for eye color may have different alleles such as brown, blue, green, or gray. Each allele controls the expression of the eye color trait differently, resulting in different eye colors in individuals.

Alleles can be dominant or recessive, with dominant alleles expressing their trait even if only one copy is present, while recessive alleles require two copies to express the trait. In addition, individuals can have different combinations of alleles, which can result in variations in traits within a population.

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