the starting sales price of a new car on monticello car lot is normally distributed with a mean of $40,000 and a standard deviation of $5,000. what is the probability that a randomly selected individual will buy a car that costs at least $30,000?

The only exponential growth equation is the third one:

y = 2*(4)^x

A general exponential equation is:

y = A*(b)^x

if 0 < b < 1, then it is a decay.

if 1 < b, then it is a growth.

So any equation where the base, b, is larger than 1, represents a growth.

Then the correct option is the third one:

y = 2*(4)^x

All the other options are decays.

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Answer: i dont know if this is right but i put a^4+b^4=c^4

Step-by-step explanation:

I have no idea tho

Answer: Sarah bought 5 first class tickets and (13-5) = 8 coach tickets.

Step-by-step explanation: The taken a toll of one to begin with lesson ticket is $1200 and the fetched of one coach ticket is $380.

So, the full taken a toll of first class tickets would be 1200x and the entire cost of coach tickets would be 380(13-x) = 4940 - 380x.

The overall fetched of the tickets is given as $9040, so we will set up the taking after condition:

1200x + 4940 - 380x = 9040

Streamlining and tackling for x, we get:

820x = 4100

x = 5

The logical assumption used is: An arithmetic sequence is a set of discrete values, whereas a line is a continuous set of values.

An arithmetic sequence is a set of numbers where, with the exception of the first term, each term is obtained by adding a fixed constant to the term before it. Every pair of following terms in the sequence has the same fixed constant, which is known as the common difference. A1 stands for the first term in an arithmetic sequence, while an is used to represent the nth term.

A solid line symbolises continuous numbers, whereas the classmate's logical presumption is that an arithmetic series comprises of discrete values. This presumption is untrue, though, as a line can effectively represent an arithmetic series.

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The value of g(x) = x^2 + 4x depends on the value of x.

If, for example, x = 2, then:

g(2) = 2^2 + 4(2) = 4 + 8 = 12

If x = -3, then:

g(-3) = (-3)^2 + 4(-3) = 9 - 12 = -3

In general, we can evaluate g(x) for any value of x by substituting that value into the expression x^2 + 4x.

Equation that represents the total number of minutes y Emily studied for the math exam is y = 40 +x.

We can represent the total number of minutes Emily studied for the math exam using the equation,

y = 40 + x

Here, 'y' represents the total number of minutes Emily studied for the math exam, '40' represents the number of minutes she studied in the morning, and 'x' represents the number of minutes she studied later that evening.

By adding the number of minutes studied in the morning to the number of minutes studied later that evening, we can calculate the total number of minutes Emily studied for the math exam.

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If rosanne makes 112 liters of strawberry lemonade, she pours 14 of a liter of lemonade into a thermos to take to the park, rosanne's brother drink 25 liters of lemonade

To solve this problem, we can start by subtracting the 14 liters of lemonade that Rosanne poured into the thermos from the total 112 liters to get the amount of lemonade that remained:

112 - 14 = 98 liters

Next, we need to subtract the amount of lemonade that Rosanne's brother drank, which is 25 liters, from the remaining amount:

98 - 25 = 73 liters

Therefore, Rosanne's brother drank 25 liters of lemonade.

To check our answer, we can add the amount of lemonade in the thermos, the amount that Rosanne's brother drank, and the remaining amount to see if it adds up to the original 112 liters:

14 + 25 + 73 = 112

Since the sum is indeed equal to 112, we can be confident that our answer of 25 liters for the amount of lemonade that Rosanne's brother drank is correct.

In summary, to find the amount of lemonade that Rosanne's brother drank, we subtracted the amount that Rosanne poured into the thermos and the amount that her brother drank from the total amount of lemonade that Rosanne made. The answer is 25 liters.

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The only possible elements that can appear in all the sets are 4 and 5. Since both 4 and 5 appear in each set, they must be in the intersection.

Based on the given set definition, we have:

A₁ = {4, 5}

A₂ = {4, 5, 6}

A₃ = {4, 5, 6, 7}

A₄ = {4, 5, 6, 7, 8}

and so on.

To find the union of all the sets, we need to find all the distinct elements that appear in at least one of the sets. We can do this by listing the elements in each set and removing duplicates:

⋃[infinity] =1 Aᵢ = {4, 5, 6, 7, 8, ...}

We can see that the union includes all the natural numbers greater than or equal to 4. We can prove this by showing that any natural number n greater than or equal to 4 is included in at least one of the sets. Indeed, for any such n, we can choose i = n - 3, which is a natural number since n is at least 4, and then we have n in Aᵢ.

To find the intersection of all the sets, we need to find the elements that appear in all the sets. We can do this by listing the elements in each set and finding the common elements:

⋂[infinity] =1 Aᵢ = {4, 5}

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There are 23 quarters and 29 dimes in the bag.

Let's denote the number of quarters as "q" and the number of dimes as "d".

We can set up a system of two equations based on the given information:

The total number of coins is 52:

q + d = 52

The total value of the coins is $8.35, where each quarter is worth $0.25 and each dime is worth $0.10:

0.25q + 0.10d = 8.35

To solve this system of equations, we can use substitution, elimination, or any other appropriate method.

Let's use elimination to solve this system of equations.

0.10(q + d) = 0.10(52)

25q + 10d = 835

25q + 10d = 835

0.25q + 0.10d = 8.35 (multiply by 100)

Now, let's multiply both sides of the first equation by 2 and the second equation by 8 to make the coefficients of "q" the same:

50q + 20d = 1670

200q + 80d = 6680

Now, let's subtract the first equation from the second equation to eliminate "q":

200q + 80d - (50q + 20d) = 6680 - 1670

150q + 60d = 5010

Now, let's divide both sides of the resulting equation by 30 to solve for "q":

150q/30 + 60d/30 = 5010/30

5q + 2d = 167

After trying different values, we find that when "q" = 23 and "d" = 29, the equation is satisfied and the condition "q + d = 52" is also satisfied. Therefore, there are 23 quarters and 29 dimes in the bag.

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Every day, the number of views of the video increases by 80% of the previous day's views.

Every day, the number of views of the video increases by a certain percentage. To find the daily percent change in the views, we can use the formula for percent change, which is given by:

percent change = ((new value - old value) / old value) * 100

In this case, the old value is the number of views at the start, which is 500, and the new value is the number of views after one day, which is given by:

V(1) = 500*(1.8)^1 = 900

Substituting these values into the formula, we get:

percent change = ((900 - 500) / 500) * 100 = 80%

In other words, for every day that passes, the number of views of the video is multiplied by a factor of 1.8.

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For a normal distribution ,a positive value of z simply means that the observation or sample mean is above the population mean this implies

none of the options provided is completely accurate.

All the observations must have had positive values,

It is not necessarily true for a positive value of z.

The value of z indicates how many standard deviations away from the mean a particular observation or sample mean is.

A positive value of z simply means that the observation or sample mean is above the population mean.

The area corresponding to the z is either positive or negative,

It is also not accurate.

The area under the normal curve corresponds to probabilities, not positive or negative values.

The area to the right of the mean corresponds to positive z-values, and the area to the left of the mean corresponds to negative z-values.

The sample mean is smaller than the population mean,

It is a possibility when the z-value is negative, indicating that the sample mean is below the population mean.

The sample mean is larger than the population mean,

It is a possibility when the z-value is positive, indicating that the sample mean is above the population mean.

Therefore, the sample mean can be either larger or smaller than the population mean depending on the direction of the z-value.

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Answer:

The answer is 7x(5-2y)

Step-by-step explanation:

35x-14xy

7x(5-2y)

the error made is the x in the bracket

Answer:

2x-13

Step-by-step explanation:

First flip the operation to be (-10x^2+2x-10) + (10x^2-3).

Then you simplify it. The 10x^2 would get canceled out. You would then get 2x-13.

The surface area of the cylinder is approximately 94.2 ft².

Surface area refers to the total area of the external or outer part of an object. It is the sum of the areas of all the individual surfaces or faces of the object. Surface area is typically measured in square units, such as square inches (in²), square feet (ft²), or square meters (m²), depending on the unit of measurement used.

According to the given information:

The surface area of a cylinder is the sum of the lateral surface area (the curved surface) and the area of the two circular bases.

The formula for the lateral surface area of a cylinder is given:

Lateral Surface Area = 2πrh

where r is the radius of the cylinder and h is the height of the cylinder.

Plugging in the given values for the radius (r = 3 ft) and height (h = 2 ft), we can calculate the lateral surface area:

Lateral Surface Area = 2π * 3 * 2 = 12π ft²

The formula for the area of a circle (which represents the bases of the cylinder) is given:

Circle Area = πr²

Plugging in the given value for the radius (r = 3 ft), we can calculate the area of each circular base:

Circle Area = π * 3² = 9π ft²

Since there are two bases in a cylinder, we multiply this by 2 to account for both bases:

2 * Circle Area = 2 * 9π = 18π ft²

Now, we can add the lateral surface area and the area of the two bases to find the total surface area of the cylinder:

Total Surface Area = Lateral Surface Area + 2 * Circle Area

= 12π + 18π

= 30π ft²

As a decimal rounded to the nearest tenth, the surface area of the cylinder is approximately 94.2 ft²

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Answer:

Jaxon made 11 free throws over the season.

Step-by-step explanation:

If he made 5% of his free throws, we know that he will make 5% of the total number of free throws he took, which is 220:

We multiply 220 by 0.05, or 5% to find out how many free throws he made:

220*0.05 = 11

After that, we now know that Jaxon made 11 of his free throws out of 220 over the course of the season, or 5%.

If y is proportional to the square root of x and y = 60 when x = 36, then the value of x when y = 80 is 64

We are given that y is proportional to the square root of x, or y ∝ √x.

Using the constant of proportionality k, we can write this relationship as:

y = k√x

To solve for k, we can use the values given in the problem

y = 60, x = 36

60 = k√36

60 = k × 6

k = 60 / 6

Divide the numbers

k = 10

Now that we know k, we can use the same equation to find x when y = 80

80 = 10√x

Squaring both sides, we get

6400 = 100x

x = 64

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The given question is incomplete, the complete question is:

y ∝ √x If y = 60 when x = 36, find x when y = 80​.

Donna Mosier should use an Individuals control chart to set control limits for the data entry process.

An Individuals control chart is a type of process control chart used to monitor the process when the sample size is one. In this case, Mosier is examining 100 records entered by each of the 20 clerks, making the sample size one.

To set control limits that include 99.73% of the random variation in the data entry process, Mosier can use the following steps:

By using an Individuals control chart, Mosier can set control limits to monitor the data entry process and detect any issues before they become major problems.

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Answer:

see the images and explanation

Step-by-step explanation:

for the graph:

the domain 0 < x < 5

the range for each functions:

g(x) = 2x + 1

g(x) = y  ,   1 < y < 11

h(x) = 2x + 2 ,  2 < y < 12

The length of the given line AB is 6 units and the polygon ABCDEF has been created.

A graph is a mathematical structure made up of a collection of points called VERTICES and a set of lines connecting some pair of VERTICES that may or may not be empty.

There is a chance that the edges will be directed, or orientated.

If the lines are directed or undirected, respectively, they are referred to as ARCS or EDGES.

Make a sequence of bars on graph paper as an example of a graph.

So, in the given situation the polygon ABCDEF has been created:

(Refer to the graph attached below)

Now, the length of the side AB:

Count the units as follows which comes to 6 units.

Therefore, the length of the given line AB is 6 units and the polygon ABCDEF has been created.

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Correct question:

Help Here is your graph of the points on the previous screen.

Connect the points in order to create polygon `ABCDEF`.

1.2 Enter the length of the segment between A and B.

Answer:150°

Step-by-step explanation:

approximately 3.6 milliliters of medication would be needed for this prescription.

To calculate the total milliliters of medication needed for this prescription, we will use the formula dosage × frequency × day supply.

In this case, the dosage is 2 drops per ear, the frequency is twice a day, and the day supply is 9 days.

First, let's find out how many drops are needed per day:
2 drops/ear × 2 ears = 4 drops
Since the frequency is twice a day, multiply this number by 2:
4 drops × 2 = 8 drops per day

Now, multiply the number of drops per day by the day supply (9 days):
8 drops/day × 9 days = 72 drops

Typically, 1 drop is approximately 0.05 millilitres. To find out how many millilitres of medication are needed, multiply the total number of drops by the volume of one drop:

72 drops × 0.05 mL/drop = 3.6 mL

So, approximately 3.6 millilitres of medication would be needed for this prescription.

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Approximately 1.8 milliliters of medication would be needed for this prescription.

To calculate how many milliliters of medication would be needed for this prescription, we need to use the following formula:

dosage × frequency × day supply.
The dosage is 2 drops, the frequency is twice a day, and the day supply is 9 days.
First, we need to convert drops to milliliters.

One drop is equal to approximately 0.05 milliliters.

2 drops would be equal to 0.1 milliliters.
Next, we can plug in the values into the formula:
[tex]0.1 milliliters/drop \times 2 drops/twice a day \times 9 days = 1.8 milliliters. [/tex]

The patient will be using exactly 2 drops in each ear for each dose, and that there will be no waste or spillage of the medication.

To determine how many milliliters of medicine would be required for this prescription:

dose frequency day supply.

The recommended dosage is 2 drops, twice day, with a 9-day supply.

We must first convert droplets to milliliters.

A drop is around 0.05 milliliters in volume. As a result, 2 drops are equivalent to 0.1 milliliters.

The values may then be entered into the formula as follows:

0.1 milliliters each drop times twice daily for nine days equals 1.8 milliliters.

As a result, this prescription would require about 1.8 milliliters of medicine.

It's crucial to note that this estimate is predicated on the patient applying precisely 2 drops to each ear for each dose.

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Answer:

Perimeter:

[tex]2( \frac{2}{3} + \frac{1}{2} ) = 2( \frac{4}{6} + \frac{3}{6} ) = 2( \frac{7}{6} ) = \frac{7}{3} = 2 \frac{1}{3} [/tex]

The perimeter is 2 1/3 inches.

Area:

[tex] \frac{2}{3} \times \frac{1}{2} = \frac{1}{3} [/tex]

The area is 1/3 of a square inch.

There are 16 possible move sequences for the frog.

The possible moves that the frog can make.

The frog can move to either the closest point with a greater integer coordinate that is a multiple of 3, or to the closest point with a greater integer coordinate that is a multiple of 13.
Let's consider the first type of move, where the frog moves to the closest point with a greater integer coordinate that is a multiple of 3.

If the frog is at the point [tex]$n$[/tex], then the closest point with a greater integer coordinate that is a multiple of 3 is either [tex]$n+3$ or $n+6$[/tex].

Similarly, if the frog is at the point [tex]$n$[/tex] and wants to move to a multiple of 13, then the closest point with a greater integer coordinate that is a multiple of 13 is either[tex]$n+13$[/tex] or [tex]$n+26$[/tex].
Constructing move sequences.

The sequence starts with 0 and ends with 39.

The frog has two choices for its first move: either move to 3 or move to 13.

Let's assume that the frog moves to 3.

From there, the frog has two choices again:

move to 6 or move to 13. If the frog moves to 6, then it has two choices again: move to 9 or move to 13.

If it moves to 13, then it has two choices: move to 26 or move to 16.

We can continue this process until we reach 39.
We can create a tree diagram to help us keep track of the possible move sequences:
                            0
                             |
                        3 or 13
                      /            \
                6 or 13       13 or 26
                  /       \       /        \
             9        13     16         26
            / \        / \    / \           / \
          ... ...     ... ... ... ...         ... ...
Each branch represents a different move sequence.

We can see that there are 16 possible move sequences in total.

We can also see that some sequences are longer than others.

The longest sequence has 7 moves, while the shortest sequence has only 2 moves.

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The probability is approximately 0.446 or 44.6%.

Waiting time is exponentially distributed, we can use the cumulative distribution function (CDF) of the exponential distribution to solve this problem.

Let X be the waiting time in minutes.

X is exponentially distributed with a mean of 8 minutes.

The rate parameter λ is equal to 1/8.

The CDF of the exponential distribution is given by:

[tex]F(x) = 1 - e^(-\lambda x)[/tex]

The probability that a patient will see the doctor within eleven minutes of the scheduled time.

The value of F(11) - F(0).

[tex]F(11) = 1 - e^(-\lambda \times 11) = 1 - e^(-11/8)[/tex] ≈ 0.554

[tex]F(0) = 1 - e^(-\lambda \times 0) = 1 - e^0 = 1[/tex]

Therefore, the probability that a randomly selected patient will see the doctor within eleven minutes of the scheduled time is:

F(11) - F(0) ≈ 0.554 - 1 ≈ 0.446

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Answer:

B

Step-by-step explanation:

The value of 0.6 is greater than the value of 0.39 because 0.6 represents a larger proportion or fraction of a whole than 0.39 does.

To compare these two values, we can think of them as parts of a whole. For example, we can consider 0.6 as 60% of a whole and 0.39 as 39% of the same whole. When we compare 60% and 39%, it is clear that 60% is greater than 39%.

Another way to compare these two values is to convert them to fractions. 0.6 can be written as 6/10 or 3/5, while 0.39 can be written as 39/100.

When we compare 6/10 and 39/100, we can see that 6/10 is greater than 39/100 because 6/10 represents 6 parts out of 10, while 39/100 represents 39 parts out of 100.

Therefore, we can conclude that the value of 0.6 is greater than the value of 0.39 because it represents a larger proportion or fraction of a whole.

The H. C. F of 80,215,245 and 720 using long division method is 5.

The long division method to find the Highest Common Factor (H.C.F.) of 80, 215, 245, and 720.

Divide the largest number by the smallest number.

720 ÷ 80 = 9 with a remainder of 0

Divide the smallest number by the remainder from the previous step.

80 ÷ 40 = 2 with a remainder of 0

Divide the remainder from the previous step by the next smallest number.

40 ÷ 5 = 8 with a remainder of 0

Divide the remainder from the previous step by the next smallest number.

5 ÷ 5 = 1 with a remainder of 0

We have reached a remainder of 0, which means that 5 is the H.C.F. of the given numbers.

Therefore, the H.C.F. of 80, 215, 245, and 720 is 5.

We can also verify this by listing the factors of each number and finding the common factors:

80: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

215: 1, 5, 43, 215

245: 1, 5, 7, 35, 49, 245

720: 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 30, 36, 40, 45, 48, 60, 72, 80, 90, 120, 144, 180, 240, 360, 720

The common factors are 1, 5, and 40.

The largest common factor is 5, which is the same as what we obtained using the long division method.

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The value of both domain and range of this exponential function is (−∞,∞).

y = 2x-9

The domain of the function can be defined as all real numbers except the ones where the expression is undefined. In the case of 2x-9, there is no real number for which this expression is undefined. Therefore, a domain of this exponential function is (−∞,∞).

The range of the function is defined as the set of all valid y values. In this case, all real numbers are valid values of y. Therefore, the range of this exponential function is (−∞,∞).

Therefore, domain of y = 2x-9 is (−∞,∞) and range is also (−∞,∞).

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Lee needs to score a total of 26 points in the next game to increase his mean score to 13 points.

Given that

Scores = 12,14,14,15,8,10,3,15

To increase his mean score to 13 points,

Lee needs to have a total of 13 x 9 = 117 points after the next game.

He has already scored a total of 12+14+14+15+8+10+3+15 = 91 points in the first 8 games.

Therefore, Lee needs to score a total of 117 - 91 = 26 points in the next game to increase his mean score to 13 points.

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