The Student Council advisor surveyed a total of 36 students by asking every tenth student in the lunch line how they preferred to be contacted with school news.

The results are shown in the table below:

Is the sample method valid?




b) If yes, name the type of sample it is:



c) If there are 684 students at the school, how many can be expected to prefer E-mail based on the data given from sample?

Karan plans to construct an obtuse angled triangle ΔXYZ, and Riya plans to construct a right angled triangle ΔLMN.

The given information:

Karan plans to construct an obtuse angled triangle ΔXYZ with ∠Y = 85° and ∠Z = 115°.

Riya plans to construct a right angled triangle ΔLMN with ∠L = 60° and ∠M = 90°.

We can make the following observations:

The sum of angles in a triangle is always 180°.

The measure of the third angle in each triangle as follows:

ΔXYZ:

∠X = 180° - ∠Y - ∠Z

= 180° - 85° - 115°

= 40°

ΔLMN:

∠N = 180° - ∠L - ∠M

= 180° - 60° - 90°

= 30°

In an obtuse angled triangle one angle is greater than 90°.

In ΔXYZ, ∠Z = 115° is greater than 90° so it is indeed an obtuse angled triangle.

In a right angled triangle one angle is exactly 90°.

In ΔLMN, ∠M = 90° is the right angle so it is indeed a right angled triangle.

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The required scientific notation is written as the weight of cans = 2.07837 x 10⁹ g.

The weight of one empty can is 0.03417 grams. The number of cans recycled in 2011 was 6.1 x 10¹⁰. To find the total weight of the cans recycled in 2011, we need to multiply these two numbers together.

Weight of cans = number of cans * weight of one can

Weight of cans = 6.1 x 10¹⁰* 0.03417

Weight of cans = 2.07837 x 10⁹ grams

The weight of the cans recycled in 2011 is 2.07837 x 10⁹ grams. In scientific notation, this is written as the weight of cans = 2.07837 x 10⁹ g.

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Answer: B.

Step-by-step explanation:

D. C. B.

100%

The quadratic function for this problem is given as follows:

The roots of the quadratic function in the context of this problem are given as follows:

Hence the linear factors of the function are given as follows:

Hence the function is:

y = a(x + 1)(x + 8).

When x = 0, y = 4, hence the leading coefficient a is obtained as follows:

8a = 4

a = 0.5.

Hence the factored form of the function is of:

y = 0.5(x + 1)(x + 8).

The standard form of the function is given as follows:

y = 0.5(x² + 9x + 8)

y = 0.5x² + 4.5x + 4.

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The range of the function f(x) for the given domain is {-12, 0, 3}.

We have,

To find the range of the function f(x) = -x² + 4x with the given domain

{-2, 0, 1}, we can evaluate the function at each value in the domain and determine the corresponding range values.

For x = -2:

f(-2) = -(-2)² + 4(-2) = -4 + (-8) = -12

For x = 0:

f(0) = -(0)² + 4(0) = 0 + 0 = 0

For x = 1:

f(1) = -(1)² + 4(1) = -1 + 4 = 3

Therefore,

The range of the function f(x) for the given domain is {-12, 0, 3}.

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The distance from the bottom of the slide to the bottom of the ladder is approximately 160.9 feet.

We can use the Pythagorean theorem to find the distance from the bottom of the slide to the bottom of the ladder. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is the distance we want to find, and the other two sides are the length of the slide (150 feet) and the height of the ladder (58 feet). Therefore, we have:

Distance² = 150² + 58²

Distance²= 22,500 + 3,364

Distance² = 25,864

Taking the square root of both sides, we get:

Distance = 160.9 feet (rounded to the nearest tenth)

Therefore, the distance from the bottom of the slide to the bottom of the ladder is approximately 160.9 feet.

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The conditions to allow skewed variables are: they are naturally occurring phenomenon that can't be controlled, it serves as control variable, and if it has significant impact on the outcome variable, it may be necessary to include.

Yes, there are certain conditions in which it may be acceptable to allow skewed variables into a research study. One such condition is when the variable is a naturally occurring phenomenon and cannot be manipulated or controlled. In such cases, it may be necessary to include the variable in the study despite its skewed nature.

Another condition is when the skewed variable is not the primary focus of the research, but rather serves as a control variable or confounding variable. In such cases, the focus of the study may be on other variables, and the skewed variable may be included simply to control for its effects on the outcome variable.

Additionally, if the skewed variable is expected to have a significant impact on the outcome variable, it may be necessary to include it in the study despite its skewed nature. In such cases, researchers may use statistical techniques to account for the skewedness and ensure that the results are still valid and reliable.

Overall, while skewed variables can present challenges in research studies, there may be certain conditions in which their inclusion is necessary or acceptable. Researchers should carefully consider these conditions and use appropriate techniques to address any issues related to skewed variables in their studies.

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The probability of event A or event B occurring is 0.51 if events A and B are independent.

If events A and B are independent, then the probability of both events occurring is given by:

P(A and B) = P(A) * P(B)

Since the events A and B are independent, the probability of either event occurring is given by the sum of their individual probabilities minus their joint probability:

P(A or B) = P(A) + P(B) - P(A and B)

Substituting the given probabilities of P(A) = 0.28 and P(B) = 0.32, we have:

P(A or B) = 0.28 + 0.32 - (0.28 * 0.32)

= 0.6 - 0.0896

= 0.51

Therefore, the probability of event A or event B occurring is 0.51 if events A and B are independent.

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a. The distribution of X is normal with mean 9.7 ppm and standard deviation 1.5 ppm: X ~ N(9.7, 1.5)

b. The distribution of the sample mean is also normal with mean μ = 9.7 ppm and standard deviation σ/√n = 1.5/√36 = 0.25 ppm: ~ N(9.7, 0.25)

c. We need to find P(X > 9.4).Looking up the standard normal distribution table, we find P(Z > -0.2) = 0.5793. Therefore, the probability that one randomly selected city's waterway will have more than 9.4 ppm pollutants is 0.5793.

d.  Therefore, the probability that the average amount of pollutants is more than 9.4 ppm is 0.8849.

e. Yes, the assumption that the distribution is normal is necessary because we are using the central limit theorem to approximate the distribution of the sample mean. The central limit theorem applies only when the sample size is sufficiently large (n ≥ 30) and the population distribution is approximately normal.

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The unique solution to the system X' = AX with initial condition X(0) = [1, 0] is:X(t) = (1/2 + i/2) * e^((2+i)*t) * [1, -i] + (1/2 - i/2)

Given a system of differential equations, X' = AX, and an initial condition, X(0), the unique solution can be obtained by solving for the eigenvalues and eigenvectors of the matrix A.

Given a system of differential equations, X' = AX, where X and A are matrices, we can find the unique solution by solving for the eigenvalues and eigenvectors of the matrix A. An eigenvector v of A is a nonzero vector such that Av = lambda * v, where lambda is a scalar called the eigenvalue corresponding to v. The eigenvalues and eigenvectors can be found by solving the characteristic equation det(A - lambda*I) = 0, where I is the identity matrix.

Once the eigenvalues and eigenvectors are found, the solution is given by X(t) = c1 * e^(lambda1 * t) * v1 + c2 * e^(lambda2 * t) * v2 + ... + cn * e^(lambdan * t) * vn, where lambda1, lambda2, ..., lambdan are the eigenvalues and v1, v2, ..., vn are the corresponding eigenvectors. The constants c1, c2, ..., cn can be found by using the initial condition X(0).

For example, suppose we have the system of differential equations:

x1' = 2x1 + x2

x2' = -x1 + 2x2

The matrix A is given by:

A = [2 1]

   [-1 2]

To find the eigenvalues and eigenvectors, we solve the characteristic equation:

det(A - lambda*I) = 0

(2 - lambda)*(2 - lambda) - (-1)*1 = 0

lambda^2 - 4lambda + 5 = 0

This has solutions lambda = 2 + i and lambda = 2 - i, which are complex conjugates. The corresponding eigenvectors are v1 = [1, -i] and v2 = [1, i], respectively.

The solution to the system is then:

X(t) = c1 * e^((2+i)*t) * [1, -i] + c2 * e^((2-i)*t) * [1, i]

Using the initial condition X(0) = [1, 0], we can solve for the constants c1 and c2:

X(0) = c1 * [1, -i] + c2 * [1, i]

[1, 0] = c1 * [1, -i] + c2 * [1, i]

Solving this system of equations, we get c1 = 1/2 + i/2 and c2 = 1/2 - i/2.

Therefore, the unique solution to the system X' = AX with initial condition X(0) = [1, 0] is:

X(t) = (1/2 + i/2) * e^((2+i)*t) * [1, -i] + (1/2 - i/2)

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The value of c such that f(c) is the average value of the function f(x) = 4x on the interval [0, 2] is c = 1. Option A

The average value of a function on an interval [a, b] is given by the formula:

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx

In this case, the interval is [0, 2] and the function is f(x) = 4x.

Average value = (1 / (2 - 0)) * ∫[0, 2] 4x dx

Simplifying the integral:

Average value = (1 / 2) * [[tex]2x^2][/tex] evaluated from x = 0 to x = 2

Average value =[tex](1 / 2) * (2(2)^2 - 2(0)^2)[/tex]

Average value = (1 / 2) * (2 * 4 - 0)

Average value = (1 / 2) * 8

Average value = 4

Now, we want to find the value of c such that f(c) is equal to the average value, which is 4.

f(c) = 4

Substituting the function f(x) = 4x:

4x = 4

Dividing both sides by 4:

x = 1

Therefore, the value of c such that f(c) is the average value of the function f(x) = 4x on the interval [0, 2] is c = 1.

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Answer:116

angles in a triangle is 180.

Answer:

1=116

2=32

Thank You

The component that is the reason why AE (Aggregate Expenditure) may be different from GDP (Gross Domestic Product) is unplanned inventory investment.

Unplanned inventory investment occurs when actual sales differ from expected sales, leading to unplanned changes in inventory levels. When firms produce more output than what consumers are willing to buy, the unsold goods accumulate as inventory. On the other hand, when the demand for goods exceeds the production levels, firms may run out of inventory.

The difference between actual inventory levels and planned inventory levels can lead to unplanned changes in inventory investment, which affects GDP. If actual inventory levels are greater than planned inventory levels, this indicates that firms have produced more than what consumers are willing to buy. Therefore, firms will reduce production in the future, leading to a decrease in GDP. Conversely, if actual inventory levels are lower than planned inventory levels, this indicates that firms have produced less than what consumers are willing to buy. Therefore, firms will increase production in the future, leading to an increase in GDP. Thus, unplanned inventory investment plays a significant role in the difference between AE and GDP

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The F-test should only be used to test the joint significance of multiple variables or restrictions, and should not be used to reject all the hypotheses.

When testing joint hypothesis, you should use the F-statistics and reject at least one of the hypothesis if the statistic exceeds the critical value.

This is because the F-test is designed to test the joint significance of multiple variables or restrictions. In other words, it tests whether the combination of the hypotheses is statistically significant.

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Answer:

-----------------

Use slope formula and solve for y:

The value of y is 4.

To calculate the overall probability, we multiply the individual probabilities together:

(3/11) * (1/10) * (7/9) = 21/990 ≈ 0.0212

Therefore, the closest option is 0.02.

Therefore, the exact length of the polar curve r = 3 sin(θ), where 0 ≤ θ ≤ π/3, is π units.

To find the exact length of the polar curve r = 3 sin(θ), where 0 ≤ θ ≤ π/3, we can use the arc length formula for polar curves:

Length = ∫[θ1 to θ2] √(r^2 + (dr/dθ)^2) dθ

In this case, we have:

r = 3 sin(θ)

dr/dθ = 3 cos(θ)

Substituting these values into the arc length formula, we get:

Length = ∫[0 to π/3] √((3 sin(θ))^2 + (3 cos(θ))^2) dθ

Simplifying, we have:

Length = ∫[0 to π/3] √(9 sin^2(θ) + 9 cos^2(θ)) dθ

Length = ∫[0 to π/3] √(9 (sin^2(θ) + cos^2(θ))) dθ

Length = ∫[0 to π/3] √(9) dθ

Length = ∫[0 to π/3] 3 dθ

Length = 3θ |[0 to π/3]

Length = 3(π/3 - 0)

Length = π

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The flux of the vector field F = xy i + yz j + zx k out of a sphere of radius 5 centered at the origin is [?]. To find the flux of a vector field through a surface, we need to evaluate the surface integral of the dot product between the vector field and the outward normal vector of the surface.

In this case, the vector field F = xy i + yz j + zx k and the surface is a sphere of radius 5 centered at the origin.

To calculate the flux, we need to compute the dot product of the vector field F and the outward normal vector of the sphere at each point on the surface. The outward normal vector is given by the unit radial vector pointing away from the origin.

The flux integral can be expressed as:

Flux = ∬ F · dA

where dA is the vector differential area on the surface of the sphere.

To evaluate this integral over the entire surface of the sphere, we can use spherical coordinates. However, since the surface of the sphere is symmetric, the flux through one hemisphere will be equal to the flux through the other hemisphere. Therefore, we can calculate the flux through one hemisphere and multiply it by 2 to get the total flux.

The detailed calculation involves setting up the integral in spherical coordinates, determining the limits of integration, and evaluating the dot product. The resulting flux will depend on the specific limits and calculations performed.

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The ratio of the critical load using the arrangement (a) to the critical load using the arrangement (b) is 16:9.

The critical load of a column depends on its effective length and its moment of inertia. The moment of inertia of the column in arrangement (a) is 2I, where I is the moment of inertia of each individual plank. The moment of inertia of the column in arrangement (b) is I. Therefore, the critical load of the column in arrangement (a) is 16 times that of the critical load of the column in arrangement (b), because the critical load varies as the moment of inertia. Hence, the ratio of the critical load using the arrangement (a) to the critical load using the arrangement (b) is 16:9.

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The area of the region outside r=8sin(θ) and inside r=24sin(θ) is 160π/3 square units.

To find the area, we first need to find the limits of integration for θ. The two curves intersect at θ=π/6 and θ=11π/6. Thus, we integrate from θ=π/6 to θ=11π/6. Next, we use the formula for the area of a polar region, which is given by: A = ∫[a,b] 1/2[r(θ)]^2 dθ

where r(θ) is the distance from the origin to the curve as a function of θ. In this case, we have:

A = ∫[π/6,11π/6] 1/2[(24sin(θ))^2 - (8sin(θ))^2] dθ

Simplifying the expression and evaluating the integral, we get:

A = (160π)/3

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The first two approximations are y(0.2) ≈ 2.4 and y(0.4) ≈ 1.92.

Euler's method is a numerical method used to approximate the solutions of ordinary differential equations (ODEs) with a given initial value.

The method involves breaking down the solution into smaller intervals and approximating the solution at each interval using the derivative at the current point. Specifically, for the initial value problem y'(t) = f(t,y(t)), y(t0) = y0, with a time step size of delta t, Euler's method proceeds as follows:

y1 = y0 + delta t * f(t0, y0)

In the given problem, the ODE to be solved is y'(t) = -y and the initial value is y(0) = 3. Therefore, we have f(t,y) = -y and y0 = 3. The time step size is given as delta t = 0.2, which means we need to compute the values of y at t = 0.2 and t = 0.4 using Euler's method.

Applying the formula for the first approximation, we get:

y1 = y0 + delta t * f(t0, y0) = 3 + 0.2 * (-3) = 2.4

So, the first approximation of y at t = 0.2 is y1 = 2.4.

For the second approximation, we need to use y1 as the initial value and compute y2 as follows:

y2 = y1 + delta t * f(t1, y1) = 2.4 + 0.2 * (-2.4) = 1.92

Therefore, the second approximation of y at t = 0.4 is y2 = 1.92.

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Therefore, we can write the expression g(x) as g(x) = f(h(x)), where h(x) is the inside function. In this expression, h(x) represents the input to f(x), and f(x) represents the outer function that is being applied to the input.

In order to identify the "inside function" h(x) in the expression g(x) = f h(x), we need to understand what a composition functions means.

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Answer:

-7+7=2x

Step-by-step explanation:

0=2x

0/2=2x/2

0/2=x

Answer:

Step-by-step explanation:

Given rectangle RSTU with diagonals SU = 4x+2 and RT= 5x-7 that meet at point V with angle VTS = 39°, you want the measures of RV and angle VSR.

The diagonals of a rectangle bisect each other and are congruent:

  SU = RT

  4x +2 = 5x -7

  9 = x

And RV = RT/2:

  RV = (5x -7)/2 = (5·9 -7)/2

  RV = 19

The base angles in each of the isosceles triangles are congruent. That means ∠VST = ∠VTS = 39°. The angle of interest, ∠VSR is the complement of angle VST, so is ...

  ∠VSR = 90° -39°

  ∠VSR = 51°

The maximum and minimum value of the function f(x)=2x/x² is infinity and does not exists.

To find the maximum and minimum values of a function, we need to analyze its behavior over its entire domain. In this case, the function f(x) = 2x / x² is defined for all real numbers except x = 0.

First, let's consider the behavior of the function as x approaches positive infinity. We can do this by taking the limit as x approaches infinity:

lim(x→∞) 2x / x²

To simplify the expression, we can divide both the numerator and denominator by x:

lim(x→∞) 2 / x

As x approaches infinity, the value of 2 / x approaches 0. Therefore, the function approaches 0 as x tends to positive infinity.

Now, let's consider the behavior of the function as x approaches negative infinity. We can take the limit as x approaches negative infinity:

lim(x→-∞) 2x / x²

Again, dividing both the numerator and denominator by x:

lim(x→-∞) 2 / x

As x approaches negative infinity, the value of 2 / x approaches 0. However, notice that the function has a negative sign in the numerator, which means it approaches negative infinity as x tends to negative infinity.

To find the minimum value, we can examine the function around its critical points. A critical point occurs where the derivative of the function is equal to zero or is undefined. Let's find the derivative of f(x) and set it equal to zero:

f(x) = 2x / x²

To find the derivative, we can use the quotient rule:

f'(x) = (2 * x² - 2x * 2x) / (x²)² = (2x² - 4x²) / x⁴ = -2x² / x⁴ = -2 / x²

Setting f'(x) = 0:

-2 / x² = 0

Since the numerator is a constant, the equation is only satisfied when the denominator, x², equals zero. However, x² cannot be zero, so there are no critical points for this function.

Therefore, we can conclude that the minimum value of the function f(x) = 2x / x² does not exist. The function approaches negative infinity as x approaches negative infinity but does not have a specific minimum value.

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A) Flowchart provides a visual representation of patterns that an algorithm comprises.

A flowchart is a diagrammatic representation of an algorithm using various symbols and arrows to depict the sequence of steps and decisions involved in solving a problem. It provides a visual representation of the flow of control and data in the algorithm, making it easier to understand and analyze the logic of the algorithm. Flowcharts are used by programmers, software developers, and system analysts to plan, develop, and document complex algorithms and programs.

Pseudocode and source code are not visual representations, but rather written forms of the algorithm in a format that can be executed by a computer. Pseudocode is a high-level, informal language that describes the steps of the algorithm in a way that is easily understood by humans. Source code, on the other hand, is the actual code written in a programming language that can be compiled and executed by a computer.

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The sample space of this experiment is {1,1}, {1,2}, {1,3}, {1,4}, {2,1}, {2,2}, {2,3}, {2,4}, {3,1}, {3,2}, {3,3}, {3,4}, {4,1}, {4,2}, {4,3}, {4,4}.

To explain further, the experiment involves selecting two parts from a box containing four identical parts numbered 1, 2, 3, and 4. The selection is done with replacement, meaning that after each part is selected, it is put back into the box before the next selection. Also, the order of the parts matters, so selecting part 1 first and part 2 second is different from selecting part 2 first and part 1 second.

The sample space of an experiment refers to the set of all possible outcomes. In this case, there are 16 possible outcomes, as shown above. Each outcome is equally likely to occur, assuming that the parts are truly identical and the selection process is random.

Knowing the sample space is important in probability theory because it allows us to calculate the probability of each possible outcome and make predictions about the likelihood of certain events occurring. For example, we can calculate the probability of selecting two parts with a sum greater than 6 or the probability of selecting two identical parts.

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To find the average value of a function on an interval, we need to integrate the function over that interval and divide the result by the length of the interval. So, to find the average value of the function y=x^2(x^3+1)^(1/2) on the interval [0,2], we need to evaluate the definite integral:

(1/2) * ∫[0,2] x^2(x^3+1)^(1/2) dx

We can use a substitution u = x^3+1 and du = 3x^2 dx to simplify the integral:

(1/6) * ∫[1,9] (u-1)^(1/2) du

Now, we can use the power rule to integrate:

(1/6) * (2/3)*(u-1)^(3/2) |_1^9

= (1/9) * [(9-1)^(3/2) - (1-1)^(3/2)]

= (1/9) * [8^(3/2) - 0]

= 8/9 * sqrt(2)

So, the average value of the function on the interval [0,2] is:

(1/2) * [8/9 * sqrt(2)] / (2-0)

= 4/9 * sqrt(2)

Therefore, the average value of the function y=x^2(x^3+1)^(1/2) on the interval [0,2] is 4/9 * sqrt(2).

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Therefore, the integral (0,5) 3/2 x-6 can be interpreted as the area of the upper triangle minus the area of the lower triangle, which is (-3.75) - (-15) = 11.25.

The integral (0,5) 3/2 x-6 represents the area under the curve of the function 3/2 x-6 from x=0 to x=5. This area can be split into two triangles, one above the x-axis and one below it. The area of the lower triangle is given by 1/2 base x height, where the base is 5-0=5 and the height is the value of the function at x=0, which is -6. So the area of the lower triangle is 1/2 (5)(-6) = -15.

The area of the upper triangle is given by the same formula, where the base is still 5 but the height is now the value of the function at x=5, which is -3/2. So the area of the upper triangle is 1/2 (5)(-3/2) = -3.75.

Therefore, the integral (0,5) 3/2 x-6 can be interpreted as the area of the upper triangle minus the area of the lower triangle, which is (-3.75) - (-15) = 11.25.

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The correct journal entry for the transaction is: Debit Repair and Maintenance Expense account: Rs 10,000, Credit Building account: Rs 10,000.

(a) Correction:  Furniture purchased for Rs. 10,000 should be debited to the Furniture account instead of the Purchase account.

(b) Correction: The purchase of machinery on credit from Raman for Rs. 20,000 should be recorded in the Machinery account, not the Purchase account.

(c)Correction: Repairs on machinery amounting to Rs. 1,400 should be debited to the Repairs Expense account instead of the Machinery account.

(d) Correction: The repairs on overhauling of the second-hand machinery purchased for Rs. 2,000 should be debited to the Machinery account not the Repair account.

(e) Correction: The sales of old machinery at the book value of Rs. 3,000 should be credited to the Machinery Sales account instead of the Sales account.

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The complete question is:

Rectify the following errors:

(i) Repairs made on Building for Rs 1,00,000 were debited to Building a/c.

(ii) Rent paid Rs 12,000 to Landlord was debited to Landlord a/c.

(iii) Wages paid for installation of Machinery of Rs 7,000 was debited to Wages a/c.

(iv) Salary paid to Accountant (Mr. Ram) on Rs 15,000 was debited to Ram a/c.

(v) Rs 32,000 paid for purchase of Computer was charged to Office Expenses a/c.

(vi) Amount of Rs 7,500 withdrawn by proprietor for personal use was debited to Miscellaneous Expenses a/c.