Answer:
The answer is A on edge 2020
Step-by-step explanation:
Answer: A
Step-by-step explanation:
(0, 3) and (-2, -1)
Write an equation in slope intercept from of the line that passes through the given points.
Answer:
y = 2x + 3
Step-by-step explanation:
Slope Formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Slope-Intercept Form: y = mx + b
Step 1: Find slope m
m = (-1 - 3)/(-2 - 0)
m = -4/-2
m = 2
y = 2x + b
Step 2: Rewrite equation
y = 2x + 3
*You are given y-intercept (0, 3), so simply add it to your equation.
F (X) = x² - 2x and 6(x) = 3x+1
A) Find F(g(-4))
B) Find F(g(x)) simply
C) find g^-1 (x)
Part A
g(x) = 3x+1
g(-4) = 3(-4)+1 ... every x replaced with -4
g(-4) = -12+1
g(-4) = -11
Plug this into the f(x) function
f(x) = x^2 - 2x
f( g(-4) ) = (g(-4))^2 - 2( g(-4) )
f( g(-4) ) = (-11)^2 - 2(-11)
f( g(-4) ) = 121 + 22
f( g(-4) ) = 143 is the answer====================================================
Part B
Plug the g(x) function into the f(x) function
f(x) = x^2 - 2x
f( g(x) ) = ( g(x) )^2 - 2( g(x) ) ... replace every x with g(x)
f( g(x) ) = (3x+1)^2 - 2(3x+1)
f( g(x) ) = (9x^2+6x+1) + (-6x-2)
f( g(x) ) = 9x^2+6x+1-6x-2
f( g(x) ) = 9x^2-1 is the answerNote that we can plug x = -4 into this result and we would get
f( g(x) ) = 9x^2-1
f( g(-4) ) = 9(-4)^2-1
f( g(-4) ) = 9(16)-1
f( g(-4) ) = 144-1
f( g(-4) ) = 143 which was the result from part A
====================================================
Part C
Replace g(x) with y. Then swap x and y. Afterward, solve for y to get the inverse.
[tex]g(x) = 3x+1\\\\y = 3x+1\\\\x = 3y+1\\\\3y+1 = x\\\\3y = x-1\\\\y = \frac{1}{3}(x-1)\\\\y = \frac{1}{3}x-\frac{1}{3}\\\\g^{-1}(x) = \frac{1}{3}x-\frac{1}{3}\\\\[/tex]
Find the slope and y-intercept: 4x-y+6=0
Answer:
The slope is 4, and the y-intercept is 6.
Step-by-step explanation:
The equation of the line is generally written as y = mx + b.
Where m is the slope, and b is the y-intercept.
4x - y + 6 = 0
Solve for y.
- y = 0 - 4x - 6
y = -1(-4x - 6)
y = 4x + 6
The slope of the line is 4, and the y-intercept of the line is 6.
Answer:
Y-intercept is (0,6). The slope is 4
Step-by-step explanation:
Determine if the matrix below is invertible. Use as few calculations as possible. Justify your answer. 3 0 -4 2 0 6 -3 0 8
a. The matrix is invertible. The columns of the given matrix span R^3.
b. The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.
c. The matrix is invertible. The given matrix has 2 pivot positions.
d. The matrix is not invertible. If the given matrix is A, the equation Ax = 0 has only the trivial solution.
Answer:
b. The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.
Step-by-step explanation:
A square matrix is said to be invertible if the product of the matrix and its inverse result into an identity matrix.
3 0 -4
2 0 6
-3 0 8
Since the second column elements are all zero, the determinant of the matrix is zero ad this implies that the inverse of the matrix does not exist(i.e it is not invertible )
A square matrix is said to be invertible if it has an inverse.
The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.
The matrix is given as:
[tex]\left[\begin{array}{ccc}3&0&-4\\2&0&6\\-3&0&8\end{array}\right][/tex]
Calculate the determinant
The determinant of the matrix calculate as:
[tex]|A| = 3 \times(0 \times 8- 6 \times 0) - 0(2 \times 8 - 6 \times -3) -4(2 \times 0 - 0 \times -3)[/tex]
[tex]|A| = 3 \times(0) - 0(34) -4(0)[/tex]
[tex]|A| = 0 - 0 -0[/tex]
[tex]|A| = 0[/tex]
When a matrix has its determinant to be 0, then
It is not invertibleIt does not form a linear independent set.Hence, the correct option is (b)
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If the 2412 leaves are not a random sample, but the researchers treated the 2412 leaves as a random sample, this most likely made the data more:_____________.1. accurate, but not precise2. precise, but not accurate3. neither4. both accurate and precise
Answer:
2. Precise but not accurate
Step-by-step explanation:
In a high precision, low accuracy case study, the measurements are all close to each other (high agreement between the measurements) but not near/or close to the center of the distribution (how close a measurement is to the correct value for that measurement)
Work out the surface area of this sphere.
Give your answer to 1 decimal place.
Answer:
452.4
Step-by-step equation:
surface area of a sphere formula= 4πr²
plug 6 in for r
4π(6)² =452.389 rounded to 452.4
Assume that the profit generated by a product is given by where x is the number of units sold. If the profit keeps changing at a rate of per month, then how fast are the sales changing when the number of units sold is 1900
Answer:
21794.495 units/month
Step-by-step explanation:
Some data are missing which i can assume as per requirement of the Question.
Let us consider that profit generated by a product is given by
p(x) =4√x
Also, consider that the profit keeps changing at a rate of $1000 per month.
Now, Using the chain rule we can write
dp/dx=(dp/dt)÷(dx/dt).
So, we can calculate
dp/dx=2x^(-1/2)=2/√x.
As per question we have to find out dx/dt
Since, dx/dt= (dp/dt)/(dp/dx),
so plugging x=1900 we get 1000√1900/2=21794.495 units/month increase in sales.
please i need this answer right now !!!! Dx
Answer: the answer is d sin30degrees equal 5/x because sin is opposite over hyponuese
Find the product of all positive integer values of $c$ such that $3x^2+7x+c=0$ has two real roots. I will award a lot of points
Answer: 24
Step-by-step explanation:
Let's find one solution:
3x² + 7x + c = 0
a=3 b=7 c=c
First, let's find c so that it has REAL ROOTS.
⇒ Discriminant (b² - 4ac) ≥ 0
7² - 4(3)c ≥ 0
49 - 12c ≥ 0
-12c ≥ -49
[tex]c\leq\dfrac{-49}{-12}\quad \rightarrow c\leq \dfrac{49}{12}[/tex]
Since c must be a positive integer, 1 ≤ c ≤ 4
Example: c = 4
3x² + 7x + 4 = 0
(3x + 4)(x + 1) = 0
x = -4/3, x = -1 Real Roots!
You need to use Quadratic Formula to solve for c = {1, 2, 3}
Valid solutions for c are: {1, 2, 3, 4)
Their product is: 1 x 2 x 3 x 4 = 24
Answer:
$3x^2+7x+c=0$
comparing above equation with ax²+bx+c
a=3
b=7
c=1
using quadratic equation formula
[tex]x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{ 2a} [/tex]
x=(-7+-√(7²-4×3×1))/(2×3)
x=(-7+-√13)/6
taking positive
x=(-7+√13)/6=
taking negative
x=(-7-√13)/6=
A new landowner has a triangular piece of flat land she wishes to fence. Starting at the first corner, she measures the first side to be 5.7 m long and is directed 0.3 radians north of east. From the second corner, the second side is 9 m long and is directed 0.9 radians west of north. What is the length of the third side of the fence?
Answer:
The length of the third side of fence is 11.4 m
Step-by-step explanation:
Solution:-
- We are to mow a triangular piece of land. We are given the description of motion and the orientation of land-mower while fencing.
- From one corner of the triangular land, the land-mower travels H1 = 5.7 m at θ1 = 0.3 radians north of east. We will use trigonometric ratios to determine the amount traveled ( B1 ) in the east direction.
[tex]cos ( theta_1 ) = \frac{B_1}{H_1}[/tex]
Where,
B1: Is the base length of the right angle triangle
H1: Hypotenuse of the right angle triangle
Therefore,
[tex]B_1 = H_1*cos ( theta_1 )\\\\B_1 = 5.7*cos ( 0.3 )\\\\B_1 = 5.44541 m[/tex]
- Similarly, from the other corner of the triangular land. The land-mower moves a lateral distance of H2 = 9m and directed θ2 = 0.9 radians north of west. We will use trigonometric ratios to determine the amount traveled ( B2 ) in the west direction.
[tex]cos ( theta_2 ) = \frac{B_2}{H_2} \\[/tex]
Where,
B2: Is the base length of the right angle triangle
H2: Hypotenuse of the right angle triangle
Therefore,
[tex]B_2 = H_2*cos ( theta_2 )\\\\B_2 = 9*cos(0.9)\\\\B_2 = 5.59448 m[/tex]
- The total length of the third side of the fence would be the sum of bases of the two right angles formed by the land-mower motion at each corner.
[tex]L = B_1 + B_2\\\\L = 5.44541 + 5.59448\\\\L = 11.4 m[/tex]
What number must you add to complete the square?
X^2 + 8x= 11
A. 12
B. 16
c. 8
D. 4
Answer:
16
Step-by-step explanation:
X^2 + 8x= 11
Take the coefficient of x
8
Divide by 2
8/2 =4
Square it
4^2 = 16
Add 16 to each side
Please answer this correctly
Answer:
The second question
Step-by-step explanation:
The orca starts at -25 meters. She goes up 25 meters.
up 25 = +25
-25+25=0
Answer:
Option 2
Step-by-step explanation:
The orca swims at the elevation of -25 meters. The orca swims up 25 meters higher than before.
-25 + 25 = 0
Two vehicles begin traveling at the same time. Vehicle A travels at 45
miles per hour (MPH) for two hours. Vehicle B travels at 80 MPH for
one hour. Which vehicle travels the farthest, and how much farther
does it travel?
Answer:
The answer is A because 45x2= 90 miles and 80×1 = 80 miles and 90-80= 10 so Vehicle A travels 10 miled farther than Vehicle B. Hope that helps!
Vehicle which travels the farthest is vehicle A and the distance it travels farther is 10 miles.
What is Speed?Speed is the unit rate in terms of distance travelled by an object and the time taken to travel the distance.
Speed is a scalar quantity as it only has magnitude and no direction.
Given that,
Speed of vehicle A = 45 miles per hour
Speed of vehicle B = 80 miles per hour
Vehicle A travels for 2 hours.
Total distance travelled = Speed × Time = 45 × 2 = 90 miles
Vehicle B travels for 1 hour.
Distance travelled = 80 miles
Vehicle A travels farthest since the distance is greater for A.
Difference in the distance = 90 - 80 = 10 miles
Hence the vehicle A travels 10 miles farther.
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Four students are working on a Math problem to find the soulution to 2x-3=11. Each student got a different answer. The four answers were 5,6,7 and 8. Which of these numbers make the equation true?
Answer:
7
Step-by-step explanation:
2x-3=11
Move the -3 to the right side by adding 3 to both sides of the equation
2x=14
Divide both sides by 2 to get x by itself
x=7
Answer:
7
Step-by-step explanation:
2x -3 = 11
2x = 14 . . . . add 3
x = 7 . . . . . . divide by 2
The number 7 makes the equation true when substituted for x.
Need help with this as soon as possible.
Answer:
after 9 weeks it would become 9*1+10=19 inches
and after w weeks it will be w*1+10 inches tall
hope this helps
Step-by-step explanation:
Answer:
a) 19 inches
b) 10+w inches
Step-by-step explanation:
The equation for this problem is 10 + w. In the first part, w = 9, so the plant is 19 inches tall.
I don't know what to do.
Answer:
104.93 in
Step-by-step explanation:
When we draw out a picture of our triangle, we should see that we need to use sin∅ to solve:
sin23° = 41/x
xsin23° = 41
x = 41/sin23°
x = 104.931
Suppose that the scores of bowlers in particular league follow a normal distribution such that the standard deviation of the population is 6. Find the 95% confidence interval of the mean score for all bowlers in this league, using the accompanying data set of 10 random scores. Round your answers to two decimal places and use ascending order. Score 86 86 93 88 98 107 93 75 89
Answer:
A 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].
Step-by-step explanation:
Since in the question only 9 random scores are given, so I am performing the calculation using 9 random scores.
We are given that the scores of bowlers in particular league follow a normal distribution such that the standard deviation of the population is 6.
The accompanying data set of 9 random scores in ascending order is given as; 75, 86, 86, 88, 89, 93, 93, 98, 107
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\bar X[/tex] = sample mean score = [tex]\frac{\sum X}{n}[/tex] = [tex]\frac{815}{9}[/tex] = 90.56
[tex]\sigma[/tex] = population standard deviation = 6
n = sample of random scores = 9
[tex]\mu[/tex] = population mean score for all bowlers
Here for constructing a 95% confidence interval we have used a One-sample z-test statistics because we know about population standard deviation.
So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 < [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < 1.96) = 0.95
P( [tex]-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\bar X-\mu}[/tex] < [tex]1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95
P( [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95
95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] , [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ]
= [ [tex]90.56-1.96 \times {\frac{6}{\sqrt{9} } }[/tex] , [tex]90.56+1.96 \times {\frac{6}{\sqrt{9} } }[/tex] ]
= [86.64 , 94.48]
Therefore, a 95% confidence interval for the population mean score for all bowlers in this league is [86.64, 94.48].
I don't know what to do.
Answer:
13 Compute using the 2 right angles, we know that m<FIG=90* and
Your bank balance is $102.35 and you've just made purchases for $20, $33.33, and $52.80. You then make deposits of $25 and $24.75. What's your new balance?
A. 565.77
B. 54102
C. $45.97
D. 551.22
Answer:
C
Step-by-step explanation:
102.35-20-33.33-52.80+25+24.75
45.97
Arrange the functions for which the result is a non-infinite value and the limit exists in ascending order of their limit values as x tends to infinity. Please see picture attached.
Answer:
see attached
Step-by-step explanation:
The limit as x gets large is the ratio of the highest-degree terms. In most cases, the limit can be found by evaluating that ratio. Where an absolute value is involved, the absolute value of the highest-degree term is used.
If the ratio gives x to a positive power, the limit does not exist. If the ratio gives x to a negative power, the limit is zero.
The arrangement of functions according to the given condition
[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]
[tex]h(x)=\frac{x^{3} -x^{2} +4}{1-3x^{2} }[/tex]
[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]
[tex]i(x)=\frac{x-1}{|1-4x| }[/tex]
[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]
[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]
[tex]f(x)=\frac{x^{2} -1000}{x-5}[/tex]
[tex]j(x)=\frac{x^{2}-1 }{|7x-1|}[/tex]
What is limit?A limit is the value that a function approaches as the input approaches some value.
According to the given question
[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]
⇒[tex]\lim_{nx\to \infty} \frac{5x^{2} -1}{x^{2} +1}[/tex]
⇒[tex]\lim_{x \to \infty} \frac{x^{2} }{x^{2} } \frac{5-\frac{1}{x^{2} } }{1+\frac{1}{x^{2} } }[/tex]
= 5 ([tex]\frac{1}{x^{2} } = 0[/tex] ,as x tends to infinity [tex]\frac{1}{x^{2} }[/tex] tends to 0)
[tex]i(x)=\frac{x-1}{|1-4x|}[/tex]
⇒[tex]\lim_{x \to \infty} \frac{x-1}{|1-4x|}[/tex] = [tex]\lim_{x \to \infty} \frac{x}{x} \frac{1-\frac{1}{x} }{|\frac{-1}{4}+\frac{1}{x} | }[/tex] =[tex]\frac{1}{\frac{1}{4} }[/tex] =[tex]\frac{1}{4}[/tex]
As x tends to infinity 1/x tends to 0, and |[tex]\frac{-1}{4}[/tex]| gives 1/4
[tex]f(x)= \frac{x^{2} -1000}{x--5}[/tex]
⇒[tex]\lim_{x \to \infty} \frac{x^{2} -1000}{x-5}[/tex]= [tex]\lim_{x \to \infty} \frac{x^{2} }{x} \frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex]= [tex]\lim_{x \to \infty} x\frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex] ⇒ limit doesn't exist.
[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]
⇒[tex]\lim_{x\to \infty} \frac{4x^{2} -6}{1-4x^{2} }[/tex]=[tex]\lim_{x\to \infty} \frac{x^{2} }{x^{2} } \frac{4-\frac{6}{x^{2} } }{\frac{1}{x^{2} } -4}[/tex] [tex]= \lim_{n \to \infty} \frac{4}{-4}[/tex] = -1
As x tends to infinity [tex]\frac{1}{x^{2} }[/tex] tends to 0.
[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]
⇒[tex]\lim_{x\to \infty} \frac{|4x-1|}{x-4}[/tex] = [tex]\lim_{x \to \infty} \frac{|x|}{x} \frac{4-\frac{1}{x} }{1 -\frac{4}{x} } }[/tex] = 4
as x tends to infinity 1/x tends to 0
and |x|=x ⇒[tex]\frac{|x|}{x}=1[/tex]
[tex]h(x)=\frac{x^{3}-x^{2} +4 }{1-3x^{3} }[/tex][tex]\lim_{x \to \infty} \frac{x^{3} -x^{2} +4}{1-3x^{3} }[/tex][tex]= \lim_{x \to \infty} \frac{x^{3} }{x^{3} } \frac{1-\frac{1}{x}+\frac{4}{x^{3} } }{\frac{1}{x^{3} -3} }[/tex] = [tex]\frac{1}{-3}[/tex] =[tex]-\frac{1}{3}[/tex]
[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]
[tex]\lim_{x \to \infty} \frac{5x+1000}{x^{2} }[/tex] = [tex]\lim_{x \to \infty} \frac{x}{x} \frac{5+\frac{1000}{x} }{x}[/tex] =0
As x tends to infinity 1/x tends to 0
[tex]j(x)= \frac{x^{2}-1 }{|7x-1|}[/tex]
[tex]\lim_{x \to \infty} \frac{x^{2}-1 }{|7x-1|}[/tex] = [tex]\lim_{x \to \infty} \frac{x}{|x|}\frac{x-\frac{1}{x} }{|7-\frac{1}{x}| }[/tex] = [tex]\lim_{x \to \infty} 7x[/tex] = limit doesn't exist.
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Forty-two divided by seven plus the quantity three divided by six 1. Write the numerical expression. 2. Evaluate within parentheses. 3. There are no exponents to evaluate. 4. Multiply and divide from left to right. 5. Add and subtract from left to righ
Answer:
6.5Step-by-step explanation:
Given Forty-two divided by seven plus the quantity three divided by six, the equivalent numerical expression will be;
[tex]\frac{42}{7} + \frac{3}{6}[/tex]
To evaluate the numerical expression, we will find the LCM of the denominator
[tex]\frac{42}{7} + \frac{3}{6} = \frac{6(42)+7(3)}{42}\\ = \frac{252+21}{42}\\= \frac{273}{42}\\= 6.5[/tex]
The value of the expression 6.5
Answer:
Write and simplify this numerical expression.
Forty-two divided by seven plus the quantity three divided by six
1. Write the numerical expression.
✔ 42 ÷ 7 + (3 ÷ 6)
2. Evaluate within parentheses.
✔ 42 ÷ 7 + 0.5
3. There are no exponents to evaluate.
4. Multiply and divide from left to right.
✔ 6 + 0.5
5. Add and subtract from left to right.
✔ 6.5
Step-by-step explanation:
hope this helps! :)
Simplify (7+1) - (11+39) 4.
ОА17
ов 59
ос -3
D - 13
Answer:
-41
Step-by-step explanation:
(7 + 1) - (11 + 39) =
= 8 - 50
= -41
Answer:
Step-by-step explanation:
Do the work inside parentheses first. We get:
(8) - (50)(4), or
8 - 200 = -192
Here are summary statistics for randomly selected weights of newborn girls: nequals153, x overbarequals31.5 hg, sequals7.1 hg. Construct a confidence interval estimate of the mean. Use a 90% confidence level. Are these results very different from the confidence interval 30.4 hgless thanmuless than32.8 hg with only 15 sample values, x overbarequals31.6 hg, and sequals2.7 hg?
Answer:
yes it is little different from the confidence interval (30.4 ≤μ≤ 32.8) changes statistics
90% confidence interval estimate of the mean is
(30.1048 , 33.0952)
Step-by-step explanation:
Step(I):-
Given sample size 'n' = 153
Given mean of the sample x⁻ = 31.5
Sample standard deviation 'S' = 7.1 h g
90% confidence interval estimate of the mean is determined by
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
Degrees of freedom
ν = n-1 = 153-1 =152
t₀.₀₅ =1.9757
Step(ii)
90% confidence interval estimate of the mean is
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
[tex](31.5 - 1.9757 } \frac{7.1}{\sqrt{153} } , 31.5 + 1.9757 \frac{7.1}{\sqrt{153} } )[/tex]
( 31.5 - 1.1340 , 31.5 + 1.1340)
(30.366 , 32.634)
90% confidence interval estimate of the mean is
(30.4 , 32.6)
b)
Given sample size 'n' = 15
Given mean of the sample x⁻ = 31.6
Sample standard deviation 'S' = 2.7 h g
90% confidence interval estimate of the mean is determined by
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
Degrees of freedom
ν = n-1 = 15-1 =14
t₀.₀₅ =2.1448
90% confidence interval estimate of the mean is
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
[tex](31.6 - 2.1448 } \frac{2.7}{\sqrt{15} } , 31.6 + 2.1448 \frac{2.7}{\sqrt{15} } )[/tex]
( 31.6 - 1.4952 , 31.6 + 1.4952)
(30.1048 , 33.0952)
Conclusion:-
yes it is little different from the confidence interval (30.4 ≤μ≤32.8)
Solve the system of equations for the variables: x+2y-z=3 x+y-2z= -1
Answer:
z=0
x= -5
y=4
Step-by-step explanation:
Check the attachment please
Hope this helps :)
Step-by-step explanation:
x + 2y − z = 3
x + y − 2z = -1
There are three variables but only two equations, so this system of equations is undefined. We cannot solve for the variables, but we can eliminate one of them and reduce this to a single equation.
Double the first equation:
2x + 4y − 2z = 6
Subtract the second equation.
(2x + 4y − 2z) − (x + y − 2z) = (6) − (-1)
2x + 4y − 2z − x − y + 2z = 7
x + 3y = 7
Determine whether the given value is from a discrete or continuous data set. When a car is randomly selected, it is found to have 8 windows. Choose the correct answer below. A. A discrete data set because there are a finite number of possible values. B. A continuous data set because there are infinitely many possible values and those values cannot be counted. C. A continuous data set because there are infinitely many possible values and those values can be counted. D. The data set is neither continuous nor discrete.
Answer:
A discrete data set because there are a finite number of possible values.
Step-by-step explanation:
We are given the following data set below;
When a car is randomly selected, it is found to have 8 windows.
Firstly, as we know that the discrete data is that data that have countable or finite values, and also we can observe at a point value.
On the other hand, the continuous data is that data in which there is a range of values and we can't count or observe each and every value.
So, in our question; as we can observe that we can count all the windows and it is also a finite number which means that the given data set is a discrete data set because there are a finite number of possible values.
are the two triangles below similar
Answer:
Hey!
Your answer is YES!
AKA the Last Option on your screen!
Step-by-step explanation:
It is this because...
They both have the angles 105 in it...
And looking at the other angle on the smaller one (25)
50 + 25 = 75 ... 180 - 75 = 105
WE HAVE 105 as an angle on the larger triangle...which makes them SIMILAR but congruent Angles!
It cant be the "corresponding sides" as we do not have the notations (lines intersecting the sides) that let us know that the lines are the same.
Hope this helps!
PLS HELP ASAP!!!!........
Answer:
aaaaha pues
Step-by-step explanation:
Answer:
what happened
Step-by-step explanation:
Graph the solution set for this inequality:
4x - 2y > 8
Answer:
x-intercept: 2 y-intercept= -4
Step-by-step explanation:
First, change the given equation 4x-2y>8 to slope-intercept form, which is y=mx+b. We do this by solving for y.
4x-2y>8. Subtract 4x from each side
-2y> -4x+8. Divide by -2. Don't forget to switch the sign!
y< 2x-4 is our equation in slope-intercept form.
Now, we can graph it. We know the slope (m)= 2 and the y-intercept= -4. Start at -4 and move up two, over one, making points until you can form a line. We can see from the graph that when x=0, (0, -4) y= -4. When y=0, (2, 0), x=2. These are our intercepts of the graph!
Hope this helps!
The graph of inequality 2x - y > 4 is shown in image.
We have to given that,
The inequality is,
⇒ 4x - 2y > 8
Since, A relation by which we can compare two or more mathematical expression is called an inequality.
Now, We can simplify it as,
⇒ 4x - 2y > 8
Take 2 as common,
⇒ 2 (2x - y) > 8
⇒ 2x - y > 4
So, The graph of inequality 2x - y > 4 is shown in image.
Learn more about the inequality visit:
https://brainly.com/question/25944814
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Which of the following (x,y) pairs is the solution for the system of equations x+2y=4 and -2x+y=7
Answer:
(-2 ,3)
Step-by-step explanation:
Step 1: Rewrite first equation
x = 4 - 2y
-2x + y = 7
Step 2: Substitution
-2(4 - 2y) + y = 7
Step 3: Solve y
-8 + 4y + y = 7
-8 + 5y = 7
5y = 15
y = 3
Step 3: Plug in y to find x
x + 2(3) = 4
x + 6 = 4
x = -2
In the North Area Mall, 18 of the 90 stores sell shoes. If that same ratio holds true for the University Mall and 9 stores there sell shoes, how many stores are at University Mall?
Answer:
18/90=9/x and to find x use proportion so first 90*9=18x and 810=18x and x-45
Step-by-step explanation:
Answer:
45 stores are at University Mall
Step-by-step explanation:
The ratio of malls that sell shoes at North Area mall are 18 out of 90, which simplifies to one fifth of stores. Since the same ratio holds for the University Mall, and 9 is half of 18, the amount of stores at University Mall is 45 because 45 is half of 90.