Answer:
True.
Explanation:
The three-point suspension system can be found on all industrial trucks and this is what promotes stability to the truck. This system forms a triangle with imaginary lines, which represents the zone of stability as shown in the question above. This is because the truck's steering axle stabilizes on a pivot pin that is placed in the center of the axle, this being the first point of the suspension system. This point is projected through imaginary lines to two diagonal points, forming the center of stability.
a) The initial moisture content of a food product is 77% (wet basis), and the critical moisture content is 30% (wet basis). If the constant drying rate in a fluidized bed dryer is 0.1 kg water removed/m2-s, determine the time required for the product to begin the falling-rate drying period. The product has a cube shape with 5-cm sides; the initial product density is 950 kg/m3.
Answer:
≈ 53 seconds
Explanation:
calculate Time required for the product to begin the falling-rate drying period
Initial moisture content = 0.77 kg water /kg of product
= 3.35 kg water /kg solids
Critical moisture content = 0.3 kg water / kg product
= 0.43 kg water / kg solids
∴ amount of water to be removed = 3.35 - 0.43 = 2.95kg water /kg solids
next: calculate surface are a of product during drying
= (0.05 * 0.05 ) * 6
= 0.015 m^3
Drying rate = 0.1 kg water m^2.s^-1 * 0.015 m^3 = 1.5 * 10^-3 kg water s^-1
applying product density
initial product mass = 0.11875 * 0.23 = 0.0273kg solid
hence total amount of water to removed = 2.92 * 0.0273 = 0.07972 kg
therefore : Time required for the product to begin the falling-rate drying period
= 0.07972 / 1.5 * 10^-3
= 53 seconds
Explain the process of energy conversion by describing how energy was converted from the windmill design brief. Discuss the different forms of energy and what technology was used to convert the energy from one form to another.
Answer:
Wind energy is converted to Mechanical energy which is then converted in to electrical energy
Explanation:
In a wind mill the following energy conversions take place
a) Wind energy is converted into Mechanical energy (rotation of rotor blades)
b) Mechanical energy is converted into electrical energy (by using electric motor)
This electrical energy is then used for transmission through electric lines.
which statement best describes the velocity of a bus traveling along its route
Answer:
Option A is the correct answer. The bus traveled at 50 mph for 20 minutes
Explanation:
The complete question is
Which of the following choices best describes velocity of a bus traveling along its route? A. The bus traveled at 50 mph for 20 minutes. B. The airplane traveled southwest at 280 mph. C. The car went from 35 mph to 45 mph. D. The train made several stops, with an average rate of 57 mph.
Solution
In option A the bus is travelling at a speed of 50 miles per hour. This describes the velocity of bus along its route.
The other options are about the velocity of airplane, car and train
Question 5
Not yet answered
Marked out of 1.00
P Flag question
Which one of the following torque is produced by the spring in PMMC instrument?
O a. Damping
O b. Forcing
OC. Deflection
O d. Controlling
Answer:
A
Explanation:
Actually I don't know anything about American history, I chose it because South Africa is not in the least
Let S = { p q |p, q are prime numbers greater than 0} and E = {0, −2, 2, −4, 4, −6, 6, · · · } be the set of even integers. . Prove that |S| = |E| by constructing a bijection from S to E.
Answer:
prove that | S | = | E | ; every element of S there is an Image on E , while not every element on E has an image on S
Explanation:
Given that S = { p q |p, q are prime numbers greater than 0}
E = {0, −2, 2, −4, 4, −6, 6, · · · }
To prove by constructing a bijection from S to E
detailed solution attached below
After the bijection :
prove that | S | = | E | : every element of S there is an Image on E , while not every element on E has an image on S
∴ we can say sets E and S are infinite sets
During peak systole, the heart delivers to the aorta a blood flow that has a velocity of 100cm/sec at a pressure of 120mmHg. The aortic root has a mean diameter of 25mm. Determine the force (Rz)acting on the aortic arch if the conditions at the outlet are a pressure of 110mmHg and a diameter of 21mm. The density of blood is 1050 kg/m3. Assume that aorta is rigid non-deformable and blood is incompressible and steady state. Ignore the weight of blood vessel and the weight of blood inside the blood vessel (i.e. body force is zero).
Solution :
Given :
Velocity, [tex]$V_1 =100$[/tex] cm/sec
Pressure, [tex]$P_1 = 120 $[/tex] mm Hg
Then, [tex]$P_1 = \rho_1 g h$[/tex]
[tex]$P_1 = 0.120 \times 13.6 \times 1000 \times 9.81$[/tex]
= 16.0092 kPa
[tex]$P_2 = 110 $[/tex] mm Hg
[tex]$P_2 = \rho_2 g h$[/tex]
[tex]$= 0.110 \times 13.6 \times 1000 \times 9.81$[/tex]
= 14.675 kPa
Then blood is incompressible,
[tex]$A_1v_1=A_2v_2$[/tex]
[tex]$\frac{\pi}{4}(25)^2\times 100=\frac{\pi}{4}(21)^2\times v_2$[/tex]
[tex]$v_2=141.72 \ cm/s$[/tex]
Then the linear momentum conservation fluid :
(Blood ) in y - direction
[tex]$P_1A_1+ P_2A_2-F_g = m_2v_2-m_1v_1$[/tex]
[tex]$m_1=m_2=P_1A_1v_1$[/tex]
[tex]$=1.50 \times \frac{\pi}{4}\times (0.025)^2 \times 1.00$[/tex]
= 0.515 kg/ sec
Then the linear conservation of momentum of blood in y direction.
[tex]$P_1A_1+ P_2A_2-F_g = m_2v_2-m_1v_1$[/tex]
[tex]$16.0092 \times 1000 \times \frac{\pi}{4} \times (0.025)^2+14.675 \times 1000\times \frac{\pi}{4}\times (0.021)^2$[/tex]
[tex]$-F_y=0.515(-1.4172-1)$[/tex]
7.858+5.0828- Fy = 0.515(-2.4172)
Fy = 14.1856 N
A hypothetical metal alloy has a grain diameter of 1.7 102 mm. After a heat treatment at 450C for 250 min, the grain diameter has increased to 4.5 102 mm. Compute the time required for a specimen of this same material (i.e., d 0 1.7 102 mm) to achieve a grain diameter of 8.7 102 mm while being heated at 450C. Assume the n grain diameter exponent has a value of 2.1.
Answer:
the required time for the specimen is 1109.4 min
Explanation:
Given that;
diameter of metal alloy d₀ = 1.7 × 10² mm
Temperature of heat treatment T = 450°C = 450 + 273 = 723 K
Time period of heat treatment t = 250 min
Increased grain diameter 4.5 × 10² mm
grain diameter exponent n = 2.1
First we calculate the time independent constant K
dⁿ - d₀ⁿ = Kt
K = (dⁿ - d₀ⁿ) / t
we substitute
K = (( 4.5 × 10² )²'¹ - ( 1.7 × 10² )²'¹) / 250
K = (373032.163378 - 48299.511117) / 250
K = 1298.9306 mm²/min
Now, we calculate the time required for the specimen to achieve the given grain diameter ( 8.7 × 10² mm )
dⁿ - d₀ⁿ = Kt
t = (dⁿ - d₀ⁿ) / K
t = (( 8.7 × 10² )²'¹ - ( 1.7 × 10² )²'¹) / 1298.9306
t = ( 1489328.26061158 - 48299.511117) / 1298.9306
t = 1441028.74949458 / 1298.9306
t = 1109.4 min
Therefore, the required time for the specimen is 1109.4 min
A pump draws water from a reservoir through a 150 mm diameter suction pipe and delivers it to a 75 mm diameter discharge pipe.
a. The end of the pipe is 2 m below the free surface of the reservoir.
b. The pressure gage on the discharge pipe (located 2 m above the reservoir surface) reads 170 kPa.
c. The average velocity in the discharge pipe is 3 m/s.
Assume no head loss in the suction or discharge pipe. Determine the power added to the fluid by the pump.
Answer:
3.42 kW
Explanation:
calculate the mass flow rate of the water = density * velocity * area
= 13.3 kg/s
where Area of pipe = π/4 * d^2 = π/4 * 0.075^2 m = 0.0044 m^2
given that : 1 Kg = 1 N s^2 / m, 1 Watt = 1 N m /s
calculate : power produced by discharge pipe
Discharge Pressure x Volume flow =
Pressure * Area * velocity
P * 0.0044 * 3 = 2253 N m /s
calculate: power due the mass of water
mass of water * 2 = 258 N m/s
where: mass of water = density * volume
Calculate power produced due the velocity of exiting water
= m * V2/2 = 59.4 N m/s
hence The power added to fluid = 2253 watts
power added to the fluid by pump = 2253 / 0.75 = 3.42 kW
2. The following segment of carotid artery has an inlet velocity of 50 cm/s (diameter of 15 mm). The outlet has a diameter of 11mm. The pressure at inlet is 110 mm of Hg and pressure at outlet is 95 mm of Hg. Determine the forces required to keep the artery in place (consider steady state, ignore the mass of blood in the vessel and the mass of blood vessel; blood density is 1050 kg/m3)
This question is incomplete, the missing diagram is uploaded along this answer below.
Answer:
the forces required to keep the artery in place is 1.65 N
Explanation:
Given the data in the question;
Inlet velocity V₁ = 50 cm/s = 0.5 m/s
diameter d₁ = 15 mm = 0.015 m
radius r₁ = 0.0075 m
diameter d₂ = 11 mm = 0.011 m
radius r₂ = 0.0055 m
A₁ = πr² = 3.14( 0.0075 )² = 1.76625 × 10⁻⁴ m²
A₂ = πr² = 3.14( 0.0055 )² = 9.4985 × 10⁻⁵ m²
pressure at inlet P₁ = 110 mm of Hg = 14665.5 pascal
pressure at outlet P₂ = 95 mm of Hg = 12665.6 pascal
Inlet volumetric flowrate = A₁V₁ = 1.76625 × 10⁻⁴ × 0.5 = 8.83125 × 10⁻⁵ m³/s
given that; blood density is 1050 kg/m³
mass going in m' = 8.83125 × 10⁻⁵ m³/s × 1050 kg/m³ = 0.092728 kg/s
Now, using continuity equation
A₁V₁ = A₂V₂
V₂ = A₁V₁ / A₂ = (d₁/d₂)² × V₁
we substitute
V₂ = (0.015 / 0.011 )² × 0.5
V₂ = 0.92975 m/s
from the diagram, force balance in x-direction;
0 - P₂A₂ × cos(60°) + Rₓ = m'( V₂cos(60°) - 0 )
so we substitute in our values
0 - (12665.6 × 9.4985 × 10⁻⁵) × cos(60°) + Rₓ = 0.092728( 0.92975 cos(60°) - 0 )
0 - 0.6014925 + Rₓ = 0.043106929 - 0
Rₓ = 0.043106929 + 0.6014925
Rₓ = 0.6446 N
Also, we do the same force balance in y-direction;
P₁A₁ - P₂A₂ × sin(60°) + R[tex]_y[/tex] = m'( V₂sin(60°) - 0.5 )
we substitute
⇒ (14665.5 × 1.76625 × 10⁻⁴) - (12665.6 × 9.4985 × 10⁻⁵) × sin(60°) + R[tex]_y[/tex] = 0.092728( 0.92975sin(60°) - 0.5 )
⇒ 1.5484 + R[tex]_y[/tex] = 0.092728( 0.305187 )
⇒ 1.5484 + R[tex]_y[/tex] = 0.028299
R[tex]_y[/tex] = 0.028299 - 1.5484
R[tex]_y[/tex] = -1.52 N
Hence reaction force required will be;
R = √( Rₓ² + R[tex]_y[/tex]² )
we substitute
R = √( (0.6446)² + (-1.52)² )
R = √( 0.41550916 + 2.3104 )
R = √( 2.72590916 )
R = 1.65 N
Therefore, the forces required to keep the artery in place is 1.65 N
Diseña un mecanismo multiplicador con un engranaje motriz cuya relación de transmisión sea de 0.5 y que transmita el movimiento entre ejes distantes. Inserta una captura de pantalla indicando la relación entre los diámetros y la velocidad de giro del engranaje motriz.
20 points!!!! In this unit, we learned that, ideally, the reductionist and holistic approaches to engineering work together to ensure an optimal manufacturing process. We also discussed how problems may arise without a systems engineer to oversee the process. What if the tables were turned, however? What might happen if a systems engineer overlooked a detail that may have been discovered by a manufacturing engineer? Explain using an example.
Explanation:
When a problem is discovered in the system design or manufacturing process, it generally gets reported to all concerned (if the company has an appropriate culture). Depending on the nature of the problem, a "quick fix" may be found by the discoverer, or by someone to whom the discovery is reported. In some situations, what seems a simple problem requires a rethinking of the entire manufacturing process, possible product recalls, possible plant retrofits, and even larger ramifications. This can happen regardless of where along the line the problem is discovered.
__
Hypothetical example:
A test technician determines that a lithium battery charger sometimes gets confused and doesn't shut down properly--continuing to charge the battery when it should not. If the proximate cause is a wire harness routing or a component improperly installed, a manufacturing engineer may be called in to address the issue. The manufacturing engineer's investigation may determine that a number of battery chargers have been delivered with the problem. Further investigation may reveal a potential for fire in situations where injury or loss of life are possible outcomes.
Assessment of the design by manufacturing, process, and design engineers may reveal more than one potential cause of the shutdown/fire-hazard issue, and that the location and nature of any fire may release toxins or cause damage to systems and equipment beyond those in the immediate vicinity of the defective battery and/or charger.
Such ramifications may require the attention of one or more systems engineers and/or a rethinking of system failure modes and effects, including fire detection and suppression, throughout the product. The product may be effectively "grounded" (taken out of service), with possible customer revenue implications, until such time as the issues can be satisfactorily resolved.
(Note: 787 Dreamliner battery problems were caused by the physics of the battery construction, not the charger. The rest of the scenario above is not a bad match.)
Fracture Mechanics: A specimen of a 4340 steel alloy having a plane strain fracture toughness of 45 MPa m ( ) is exposed to a stress of 1000 MPa (145,000 psi). Assume that the parameter Y has a value of 1.0. a) Calculate the critical stress for brittle fracture of this specimen if it is known that the largest surface crack is 0.75 mm (0.03 in.) long. b) Will this specimen experience fracture
Answer:
a) 927 MPa
b)The specimen will experience fracture
Explanation:
a) Calculate critical stress for brittle fracture
σ = fracture toughness / (y √ π * surface crack)
= 45 / ( 1 [tex]\sqrt{\pi * ( 0.75*10^-3)}[/tex] )
= 927 MPa
b) since critical stress( 927 MPa) < 1000 MPa
hence : The fracture will occur
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Garth is a recruitment executive in a firm and knows the eight stages of recruitment. What activity or incident should Garth carry out or
expect to occur at each stage of the process?
place an advertisement in a job portal
vacancyWhat activity should Garth
Here are the eight stages of the recruitment process and what Garth might expect to occur or carry out at each stage in the explanation part.
What is recruitment?The process of identifying, attracting, and selecting qualified candidates for a job opening in an organisation is known as recruitment.
Here are the eight stages of the recruitment process, as well as what Garth might expect to happen or do at each stage:
Identifying the Need for the Position: Garth should review the company's staffing needs and determine if a position needs to be filled. Once a decision has been made, he should create a job description and identify the position's requirements.Garth should create a recruitment plan that includes a timeline for the recruitment process, a list of recruitment sources, and an advertising strategy.Garth should actively seek qualified candidates through various recruitment channels such as job boards, social media, referrals, and recruiting events.Screening Candidates: Garth should go over resumes, cover letters, and other application materials to see if candidates meet the job requirements. Garth should conduct interviews with the most qualified candidates to assess their skills, experience, and fit for the position. Garth should review all of the information gathered during the recruitment process and choose the best candidate for the position. Garth should ensure that the new hire has all of the necessary information and resources to succeed in their new role.Evaluating the Recruitment Process: Garth should go over the recruitment process to see where he can improve.Thus, these are the stages of recruitment.
For more details regarding recruitment, visit:
https://brainly.com/question/30086296
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What disadvantages can a resort come across
Answer:
the disadvantages can be people's thoughts about them and also a rival resort nearby which looks more posh pls mark brainliest i need 5 more for next rank thank you
Explanation:
A wind turbine designer is considering installing a horizontal axis wind turbine at a location in Michigan. To increase the power extracted from wind, the designer is debating between increasing the blade radius by 10% versus increasing the height from 40 m to 60 m, which would increase the average wind speed from 6 mph to 6.5 mph. Considering the only the impact on power extraction, the designer should go with the height increase.
a. True
b. False
Answer:
False ( B )
Explanation:
considering that the wind turbine is a horizontal axis turbine
Power generated/extracted by the turbine can be calculated as
P = n * 1/2 * p *Av^3
where: n = turbine efficiency
p = air density
A = πd^2 / 4
v = speed
From the above equation it can seen that increasing the Blade radius by 10% will increase the Blade Area which will in turn increase the value of the power extracted by the wind turbine
The voltage supplied by a wall socket varies with time, reversing its polarity with a constant frequency, as shown in the graph. (Figure 1)
What is the rms value Vrms of the voltage plotted in the graph?
Answer:
What is the rms value Vrms of the voltage plotted in the graph?
Express your answer in volts.
Vrms = ? V
2.
When a lamp is connected to a wall plug, theresulting circuit can be represented by a simplified AC circuit, asshown in the figure. (Part B figure) Here the lamp has been replaced by a resistor with an equivalentresistance Part B figure) Here the lamp has been replaced bya resistor with an equivalent resistance R = 120 . What is the rms value Irms of the current flowing through the circuit?
Express your answer in amperes.
Irms = ? A
3.
What is the average power Pavg dissipated in the resistor?
Express your answer in watts.
Pavg = ? W
14. The flow water in a 10-in Schedule 40 pipe is to be metered. The temperature of the water is
100oF, and the static pressure upstream of the meter is 20 psig, The density of the water is 62
Ibm/ft3
, Assume the flow meter is a square-edged orifice with a diameter ratio of 0.5 . When the
flow rate is 1,200 gpm and the flow coefficient is 0.5. the pressure drop across the orifice
(ibf/in2
) is Pipe ID = 10.002 in.
Answer:
I don't know plead hrdffffdddffff
Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of 30 m3/min and exits at 12 bar, 400 K. Heat transfer occurs at a rate of 5 kW from the compressor to its surroundings. Assuming the ideal gas model for air and neglecting kinetic and potential energy effects, determine the power input, in kW.
Answer:
power input = -66.2798 kW
Explanation:
Steady state pressure ( Cp ) = 1.05 bar,
Temperature ( T1 ) = 300 K
Volumetric flow rate = 30 m^3/min
exit pressure = 12 bar
exit temperature ( T2 ) = 400 K
Heat transfer rate ( Q ) = 5 kW
Calculate the power input in kW
p1v1 = m RT
m = p1v1 / RT1
= (1.05 * 10^2 * ( 30/60 )) / ( 0.287 * 300 )
= 0.60975 m^3/sec
also
h1 + Q = h2 + w
∴ w = m ( h1 - h2 ) + Q
= mCp ( t1 - t2 ) + Q ----- ( 1 )
where : ( Q ) = 5 kW , Cp = 1.05 bar, t1 = 300 K, t2 = 400 k ( input values into equation 1 )
w = -66.2798 kW
A 3-ft-diameter duct is used to carry ventilating air ( , ) into a vehicular tunnel at a rate of 11000 ft3/min. Tests show that the pressure drop is 1.2 in. of water per 1500 ft of duct. What is (a) the value of the friction factor for this duct and (b) the approximate size of the equivalent roughness of the surface of the duct
Answer:
a) Friction factor for this duct = 0.0239
b) ε = 0.006 ft
Explanation:
Given data :
Flow rate = 11000 ft^3 /min
Pressure drop = 1.2 in per 1500 ft of duct
a) Determine the value of the friction factor for this duct
Friction factor for this duct = 0.0239
b) Determine the approximate size of the equivalent roughness of the surface of the duct
ε = 0.006 ft
attached below is the detailed solution to the given problem
Q5) Write C++ program to find the summation of sines of the even values that can be divided by 7 between -170 and -137.
Answer:
In C++:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double total = 0;
for(int i = -170; i<=-130;i++){
if(i%2 == 0 && i%7==0){
double angle = i*3.14159/180;
total+=sin(angle); } }
cout<<"Total: "<<total;
return 0; }
Explanation:
This initializes the total to 0
double total = 0;
This iterates from -170 to - 130
for(int i = -170; i<=-130;i++){
This checks if the current number is even and is divided by 7
if(i%2 == 0 && i%7==0){
This converts the number from degrees to radians
double angle = i*3.14159/180;
This adds the sine of the number
total+=sin(angle); } }
This prints the calculated total
cout<<"Total: "<<total;
A 03-series cylindrical roller bearing with inner ring rotating is required for an application in which the life requirement is 40 kh at 520 rev/min. The application factor is 1.4. The radial load is 2600 lbf. The reliability goal is 0.90.
Required:
Determine the C10 value in kN for this application and design factor.
Answer:
[tex]\mathbf{C_{10} = 137.611 \ kN}[/tex]
Explanation:
From the information given:
Life requirement = 40 kh = 40 [tex]40 \times 10^{3} \ h[/tex]
Speed (N) = 520 rev/min
Reliability goal [tex](R_D)[/tex] = 0.9
Radial load [tex](F_D)[/tex] = 2600 lbf
To find C10 value by using the formula:
[tex]C_{10}=F_D\times \pmatrix \dfrac{x_D}{x_o +(\theta-x_o) \bigg(In(\dfrac{1}{R_o}) \bigg)^{\dfrac{1}{b}}} \end {pmatrix} ^{^{^{\dfrac{1}{a}}[/tex]
where;
[tex]x_D = \text{bearing life in million revolution} \\ \\ x_D = \dfrac{60 \times L_h \times N}{10^6} \\ \\ x_D = \dfrac{60 \times 40 \times 10^3 \times 520}{10^6}\\ \\ x_D = 1248 \text{ million revolutions}[/tex]
[tex]\text{The cyclindrical roller bearing (a)}= \dfrac{10}{3}[/tex]
The Weibull parameters include:
[tex]x_o = 0.02[/tex]
[tex](\theta - x_o) = 4.439[/tex]
[tex]b= 1.483[/tex]
∴
Using the above formula:
[tex]C_{10}=1.4\times 2600 \times \pmatrix \dfrac{1248}{0.02+(4.439) \bigg(In(\dfrac{1}{0.9}) \bigg)^{\dfrac{1}{1.483}}} \end {pmatrix} ^{^{^{\dfrac{1}{\dfrac{10}{3}}}[/tex]
[tex]C_{10}=3640 \times \pmatrix \dfrac{1248}{0.02+(4.439) \bigg(In(\dfrac{1}{0.9}) \bigg)^{\dfrac{1}{1.483}}} \end {pmatrix} ^{^{^{\dfrac{3}{10}}[/tex]
[tex]C_{10} = 3640 \times \bigg[\dfrac{1248}{0.9933481582}\bigg]^{\dfrac{3}{10}}[/tex]
[tex]C_{10} = 30962.449 \ lbf[/tex]
Recall that:
1 kN = 225 lbf
∴
[tex]C_{10} = \dfrac{30962.449}{225}[/tex]
[tex]\mathbf{C_{10} = 137.611 \ kN}[/tex]
Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 20oC and exits at 3.0 bar. The refrigerant undergoes a throttling process. Determine the temperature, in oC, and the quality of the refrigerant at the exit of the expansion valve. Step 1 Determine the temperature of the refrigerant at the exit, in oC.
Answer:
[tex]T_{2}[/tex] = -9.24 °C
x = 0.1057
Explanation:
The tables used in this answer and explanation come from Fundamentals of Engineering Thermodynamics 9th Edition.
Using Table A-14: Properties of Saturated Ammonia (Liquid-Vapor): Pressure Table and the given [tex]P_{2}[/tex], [tex]T_{2}[/tex] can be determined by finding the temperature that corresponds with [tex]P_{2}[/tex] on the table. In this case, [tex]T_{2}[/tex] = -9.24 °C.
The quality of the refrigerant can be determined by using data from the same table and [tex]h_{2} =274.26[/tex] kJ/kg.
Necessary data (P=3bar):
[tex]h_{f}=137.42[/tex] kJ/kg
[tex]h_{g}=1431.47[/tex] kJ/kg
The formula to calculate quality is [tex]h_{2} =h_{f}+x(h_{g}-h_{f})[/tex].
Rearranging for x:
[tex]x=\frac{h_{2}-h_{f} }{h_{g}-h_{f} }= \frac{274.26-137.42}{1431.47-137.42}=0.1057[/tex]
me that both a triaxial shear test and a direct shear test were performed on a sample of dry sand. When the triaxial test is performed, the specimen was observed to fail when the major and minor principal stresses were 100 lb/in2 and 20 lb/in2, respectively. When the direct shear test is performed, what shear strength can be expected if the normal stress is 3000 lb/ft2
Answer:
shear strength = 2682.31 Ib/ft^2
Explanation:
major principal stress = 100 Ib / in2
minor principal stress = 20 Ib/in2
Normal stress = 3000 Ib/ft2
Determine the shear strength when direct shear test is performed
To resolve this we will apply the coulomb failure criteria relationship between major and minor principal stress a
for direct shear test
use Mohr Coulomb criteria relation between normal stress and shear stress
Shear strength when normal strength is 3000 Ib/ft = 2682.31 Ib/ft^2
attached below is the detailed solution
Consider a mixing tank with a volume of 4 m3. Glycerinflows into a mixing tank through pipe A with an average velocity of 6 m/s, and oil flow into the tank through pipe B at 3 m/s. Determine the average density of the mixture that flows out through the pipe at C. Assumeuniform mixing of the fluids occurs within the 4 m3 tank.
This question is incomplete, the complete question as well as the missing diagram is uploaded below;
Consider a mixing tank with a volume of 4 m³. Glycerin flows into a mixing tank through pipe A with an average velocity of 6 m/s, and oil flow into the tank through pipe B at 3 m/s. Determine the average density of the mixture that flows out through the pipe at C. Assume uniform mixing of the fluids occurs within the 4 m³ tank.
Take [tex]p_o[/tex] = 880 kg/m³ and [tex]p_{glycerol[/tex] = 1260 kg/m³
Answer:
the average density of the mixture that flows out through the pipe at C is 1167.8 kg/m³
Explanation:
Given that;
Inlet velocity of Glycerin, [tex]V_A[/tex] = 6 m/s
Inlet velocity of oil, [tex]V_B[/tex] = 3 m/s
Density velocity of glycerin, [tex]p_{glycerol[/tex] = 1260 kg/m³
Density velocity of glycerin, Take [tex]p_o[/tex] = 880 kg/m³
Volume of tank V = 4 m
from the diagram;
Diameter of glycerin pipe, [tex]d_A[/tex] = 100 mm = 0.1 m
Diameter of oil pipe, [tex]d_B[/tex] = 80 mm = 0.08 m
Diameter of outlet pipe [tex]d_C[/tex] = 120 mm = 0.12 m
Now, Appling the discharge flow equation;
[tex]Q_A + Q_B = Q_C[/tex]
[tex]A_Av_A + A_Bv_B = A_Cv_C[/tex]
π/4 × ([tex]d_A[/tex])²[tex]v_A[/tex] + π/4 × ([tex]d_B[/tex] )²[tex]v_B[/tex] = π/4 × ([tex]d_C[/tex])²[tex]v_C[/tex]
we substitute
π/4 × (0.1 )² × 6 + π/4 × (0.08 )² × 3 = π/4 × (0.12)²[tex]v_C[/tex]
0.04712 + 0.0150796 = 0.0113097[tex]v_C[/tex]
0.0621996 = 0.0113097[tex]v_C[/tex]
[tex]v_C[/tex] = 0.0621996 / 0.0113097
[tex]v_C[/tex] = 5.5 m/s
Now we apply the mass flow rate condition
[tex]m_A + m_B = m_C[/tex]
[tex]p_{glycerin}A_Av_A + p_0A_Bv_B = pA_Cv_C[/tex]
so we substitute
1260 × π/4 × (0.1 )² × 6 + 880 × π/4 × (0.08 )² × 3 = p × π/4 × (0.12)² × 5.5
1260 × 0.04712 + 880 × 0.0150796 = p × 0.06220335
59.3712 + 13.27 = 0.06220335p
72.6412 = 0.06220335p
p = 72.6412 / 0.06220335
p = 1167.8 kg/m³
Therefore, the average density of the mixture that flows out through the pipe at C is 1167.8 kg/m³
When framing a wall, temporary bracing is
used to support, plumb, and straighten the wall.
used to support, level, and straighten the wall.
used to square the wall before it is erected.
removed before the next level is constructed.
Two technicians are explaining what exhaust gas emissions tell you about engine operation. Technician A says that the higher the level of CO2 in the exhaust stream, the more efficiently the engine is operating. Technician B says that CO2 levels of 20 to 25 percent are considered acceptable. Who is correct?
A. Both Technicians A and B
B. Neither Technicians A and B
C. Technician A
D. Technician B
Technicians A is correct in the given scenario. The correct option is C.
What is exhaust gas?Exhaust gas is a byproduct of combustion that exits the tailpipe of an internal combustion engine.
It consists of a gas mixture that includes carbon dioxide (CO2), carbon monoxide (CO), nitrogen oxides (NOx), hydrocarbons (HC), and particulate matter (PM).
Technician B is mistaken. CO2 levels in the exhaust should be less than 15%, preferably between 13% and 14.5% for petrol engines and 11% to 13% for diesel engines.
High CO2 levels can actually indicate inefficient engine operation, as it means that not all of the fuel in the engine is being burned and is being wasted as exhaust.
Thus, C is the correct answer. A technician is correct.
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A wastewater treatment plant discharges 1 m3/s of effluent with an ultimate BOD of 40 mg/L into a stream flowing at 10 m3/s. Just upstream of the discharge point, the stream has an ultimate BOD of 3 mg/L. The deoxygenation constant (kd) is estimated to be 0.22 1/d. (a) Assuming complete and instantaneous mixing, find the ultimate BOD of the mixture of the waste and the river just downstream of the outfall. (b) Assuming a constant cross-sectional area for the stream equal to 55 m2, what ultimate BOD would you expect to find at a point 10,000 m downstream
Answer:
(a) 6.36 mg/L
(b) 5.60 mg/L
Explanation:
(a)
Using the formula below to find the required ultimate BOD of the mixture.
[tex]L_o = \dfrac{Q_wL_w+ Q_rL_r}{Q_W+Q_r}[/tex]
where;
Q_w = volumetric flow rate wastewater
Q_r = volumetric flow rate of the river just upstream of the discharge point
L_w = ultimate BOD of wastewater
Replacing the given values:
[tex]L_o = \dfrac{(1 \ m^3/L ) (40 \ mg/L) + (10 \ m^3/L) (3 \mg/L)}{(1m^3/L) +(10 \ m^3/L)} \\ \\ L_o = 6.36 \ mg/L[/tex]
(b)
The Ultimate BOD is estimated as follows:
Recall that:
[tex]time(t) = \dfrac{distance }{speed}[/tex]
replacing;
distance with 10000 m and speed with [tex]\dfrac{11 \ m^3/s}{55 \ m^2}[/tex]
[tex]time =\dfrac{10000 \ m}{\Bigg(\dfrac{11 \ m^3/s}{55 \ m^2}\Bigg)}\Bigg(\dfrac{1 \ hr}{3600 \ s}\Bigg) \Bigg(\dfrac{1 \ day}{24 hr}\Bigg)[/tex]
time (t) = 0.578 days
Finally; [tex]L_t = L_oe^{-kt}[/tex]
here;
k = rate of coefficient reaction
[tex]L_ t= (6.36) \times e^{-(0.22/day)(0.5758 \ days)}\\ \\ \mathbf{L_t =5.60 \ mg/L}[/tex]
Thus, the ultimate BOD = 5.60 mg/L
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Answer:
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Explanation:
6) A deep underground cavern Contains 980 cuft
of methane gas (CH4) at a pressure of 230
psia and temperature of 150°F. How many
(omllbmol of methane does this gas
deposit contain?
Answer:
15625 moles of methane is present in this gas deposit
Explanation:
As we know,
PV = nRT
P = Pressure = 230 psia = 1585.79 kPA
V = Volume = 980 cuft = 27750.5 Liters
n = number of moles
R = ideal gas constant = 8.315
T = Temperature = 150°F = 338.706 Kelvin
Substituting the given values, we get -
1585.79 kPA * 27750.5 Liters = n * 8.315 * 338.706 Kelvin
n = (1585.79*27750.5)/(8.315 * 338.706) = 15625
An interest rate of norminal 12% per year , compounded weekly is
Answer: It is a nominal rate per year