The total distance in miles that a delivery van travels varies directly with the gallons of tule that the van uses.The van used 12 gallons of the fuel when it traveled 204 miles. How many miles will the van traveled when it has used 18 gallons of fuel?

The Total Distance In Miles That A Delivery Van Travels Varies Directly With The Gallons Of Tule That

Answers

Answer 1

It is said that the distance varies directly with the gallons of fuel. This is:

[tex]d=\frac{204\text{miles}}{12\text{gallons}}\times18gallons[/tex][tex]d=306mi[/tex]


Related Questions

if measure of arc JI= (3x+2), measure of arc HLK= (15x+36), and measure of angle HMK=(8x-1), find the measure of arc HLK.

Answers

Step 1: Problem

If the measure of arc JI= (3x+2), a measure of arc HLK= (15x+36), and a measure of angle HMK=(8x-1), find the measure of arc HLK.​

Step 2: Concept

Apply secant theorem

[tex]\text{HMK = }\frac{1}{2}(\text{ }JI\text{ + HLK )}[/tex]

Step 3: Method

Given data

[tex]\begin{gathered} 8x\text{ - 1 = }\frac{1}{2}\text{ ( 3x + 2 + 15x - 36 )} \\ (8x\text{ - 1 ) }\times\text{ 2 = 18x - 34} \\ 16x\text{ - 2 = 18x - 34} \\ 34\text{ - 2 = 18x - 16x } \\ 32\text{ = 2x} \\ x\text{ = 32/2} \\ x\text{ = 16} \end{gathered}[/tex]

The measure of arc HLK = 15x - 36

= 15(16) - 36

= 240 - 36

= 204

Step 4: Final answer

arc HLK = 204

how to solve? |b+1|=5

Answers

Answer:

b = 4 and -6

Explanation:

Given the equation:

|b + 1| = 5

|b + 1| represents the absolute value of (b + 1)

This equation gives rise to two equations

b + 1 = 5 ......................................(1)

b + 1 = -5 .......................................(2)

Solve equation (1)

b + 1 = 5

Subtract 1 from both sides of the equation

b + 1 - 1 = 5 - 1

b = 4

Solve equation (2)

b + 1 = -5

Subtract 1 from both sides of the equation

b + 1 - 1 = -5 -1

b = -6

Therefore, the values for b are 4 and -6

Mary has been getting up extra early on school days so far she has woken up 6 out of 80 school days what percent of the days has she get been getting up early

Answers

Let's begin by identifying key information given to us:

Number of times she woke early (e) = 6

Total number of days (t) = 80 days

The percentage of days she's been getting up early ​is given by:

[tex]\begin{gathered} \text{\%}n\text{=}\frac{e}{t}\cdot100\text{\%} \\ \text{\%}n=\frac{6}{80}\cdot100\text{\%} \\ \text{\%}n=7.5\text{\%} \end{gathered}[/tex]

Mary has gotten up early 7.5% of the days

1.1. Which statement explains why the two systems of equations below have thesame solution?A6x + 8y = -102x - 5y = 12B8x + 3y = 212x + 16y = -20

Answers

Let:

[tex]\begin{gathered} 6x+8y=-10_{\text{ }}(1) \\ 2x-5y=12_{\text{ }}(2) \\ 8x+3y=2_{\text{ }}(3) \\ 12x+16y=-20_{\text{ }}(4) \end{gathered}[/tex][tex]\begin{gathered} (4)=2(1) \\ so\colon \\ 2(6x+8y)=2(-10)\equiv12x+16y=-20 \\ 12x+16y=-20\equiv12x+16y=-20 \end{gathered}[/tex]

Therefore, (4) is a Scalar Multiple of (1).

[tex]\begin{gathered} (1)+(2) \\ 6x+2x+8y-5y=-10+12 \\ 8x+3y=2\equiv(3) \\ so\colon_{} \\ (1)+(2)\equiv(3) \end{gathered}[/tex]

Therefore, (3) is a linear combination of (1) and (2)

A recipe calls for 4 parts chocolate chips for every 6 parts of nuts. calling makes the recipe for a party and uses 18 tablespoon of nuts how many tablespoons of chocolate chips did he use

Answers

To answer this question, we need to have into account the ratio between the chocolate and the nuts. This ratio is:

[tex]\frac{4}{6}=\frac{2}{3}[/tex]

That is, simplifying the ratio, we have 2 parts of chocolate and 3 parts of nuts. This ratio must be the same for the tablespoon. Then, if we have 18 tablespoons of nuts, then we can pose the situation as follows:

[tex]\frac{4}{6}=\frac{2}{3}=\frac{x}{18}\Rightarrow x=\frac{2\cdot18}{3}\Rightarrow x=\frac{36}{3}\Rightarrow x=12[/tex]

Therefore, we need 12 tablespoons of chocolate to follow the recipe for the party.

The relative frequency polygon shows pulse rates or women and men.

Answers

Given:

A relative frequency polygon that shows pulse rates of women and men.

To determine the midpoints of the class with the most pulse rates for women and men, we first note that based on the given graph, the most pulse rates for women is 74.5 with more than 30% of relative frequency. While the most pulse rates for men is 64.5 with more than 40% of relative frequency.

Therefore, the midpoints of the class with the most pulse rates for women and men respectively is:

74.5, 64.5

Hi!! I have a homework problem i am not sure how to do.. I have missed some school due to health related issues so i’m a little behind. Thank you so much. I also have an example of the answer i have to give i can send to you

Answers

We need to find a quadratic model from the news or social media.

We can model the number of people watching a story after t time of posting it.

When you post it, there are no people watching it, it starts at y=0. Throughout the day more people are watching, but when time passes, the number of people starts to decrease.

The situation can be modeled by the quadratic function:

[tex]y=-0.5x^2+10x[/tex]

Where x is the time in hours after posting the story, and y is the number of new people who watched the story in the past hour.

If we graph the function it looks like this:

As can be seen, at the beginning the number of people watching the story starts to increase, but after some time the number of people you reach out to with your story starts to decrease until no one will watch it.

The quadratic term of the function is:

[tex]-0.5x^2[/tex]

The coefficient of the quadratic term determines how wide or narrow the graphs are, and whether the graph turns upward or downward. As we have a negative coefficient, then the parabola opens down.

The linear term is 10x, and it determines the position of the vertex.

There is a maximum value and it occurs at t=10 when you reach out to 50 people: (10,50).

The domain of the function is the set of possible x-values, as can be seen in the graph, it is [0,20], which means after 20 hours no one will watch your story.

The range is the set of y-values the function takes. It is [0,50]. It means you start with 0 people and the maximum number of people you reach out to in one hour is 50.

I need help with a question for my math practice but I will have to see the picture to show you

Answers

The dependent variable is Y because the value depends on the number of people(x) who buy tickets

and y is the total cost of the tickets

Then the right option is D

Find the equation of a line perpendicular to y = - 1/4 x + 9 that passes through the point (4, - 8) .

Answers

perpendicularWe were given the following information:

The equation of a line is given by: y = - 1/4 x + 9

We want to obtain the equation for a line perpendicular to this line & that passes through the point (4, -8). This is shown below:

The general equation of a straight line is given by:

[tex]\begin{gathered} y=mx+b \\ where\colon \\ m=slope \\ b=y-intercept \end{gathered}[/tex]

The equation of the line given us is:

[tex]\begin{gathered} y=-\frac{1}{4}x+9 \\ \text{Comparing this with the general equation, we will deduce that:} \\ mx=-\frac{1}{4}x \\ m=-\frac{1}{4} \\ \text{Thus, the slope of this line is: }-\frac{1}{4} \end{gathered}[/tex]

The relationship between the slope of a line and the slope of a line perpendicular to it is given by the statement "the product of the slopes of two lines perpendicular to one another is negative one"

This is expressed below:

[tex]\begin{gathered} m\times m_{perpendicular}=-1 \\ m_{perpendicular}=-\frac{1}{m} \\ m=-\frac{1}{4} \\ m_{perpendicular}=\frac{-1}{-(\frac{1}{4})} \\ m_{perpendicular}=4 \\ \\ \therefore m_{perpendicular}=4 \end{gathered}[/tex]

Therefore, the slope of the perpendicular line is: 4

We were told that the perpendicular line passes through the point (4, -8). We will obtain the equation of the perpendicular line using the Point-Slope equation. This is shown below:

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ (x_1,y_1)=(4,-8) \\ m\Rightarrow m_{perpendicular}=4_{} \\ \text{Substitute the values of the variables into the initial equation above, we have:} \\ y-\mleft(-8\mright)=4(x-4) \\ y+8=4(x-4) \\ y+8=4x-16 \\ \text{Subtract ''8'' from both sides, we have:} \\ y=4x-16-8 \\ y=4x-24 \\ \\ \therefore y=4x-24 \end{gathered}[/tex]

The graphical representation of this is given below:

What is the process between the second and third step? I don’t get how step 3 has 10^2 power.

Answers

ANSWER

Base raised to logarithm rule

EXPLANATION

Between the second and third steps, a property of logarithms was applied, the base raised to logarithm rule. This property states that when the base of the logarithm is raised to the logarithmic expression, the result is the argument,

[tex]a^{\log_a(x)}=x[/tex]

In this case, we can see that it only says "log", so we can assume that the base of this logarithm is 10. To get from step 2 to step 3, we have to raise the base (10) to each side of the equation,

[tex]10^{\log(\frac{x+2}{x+1})}=10^2[/tex]

And then, by the property stated above, we have the third line of this solution,

[tex]\frac{x+2}{x+1}=10^2[/tex]

In the picture, the equation is inverted, but since there is an equal sign it is equivalent.

If AB=18cm,AC=14cm,BC=8cm and XY=4cm how do i find AX and AY?

Answers

To answer this question, we can see that:

Then, we have that both triangles are similar triangles since the side CB and XY are parallel and then the interior angles are congruent. Then, we can write the next proportions:

[tex]\frac{CB}{XY}=\frac{AC}{AX}=\frac{AB}{AY}[/tex]

We have that the ratio between CB and XY is:

[tex]\frac{CB}{XY}=\frac{8}{4}\Rightarrow\frac{CB}{XY}=2[/tex]

In other words, we can say that the side CB is twice the measure of side XY or:

[tex]\frac{CB}{XY}=\frac{AC}{AX}=\frac{AB}{AY}=2[/tex]

And we can also say that:

[tex]\frac{XY}{CB}=\frac{AX}{AC}=\frac{AY}{AB}=\frac{1}{2}[/tex]

Using these proportions is easy to find the values of AX and AY as follows:

Finding the value of AX

We have that AC = 14cm, then:

[tex]\frac{AX}{AC}=\frac{1}{2}\Rightarrow AX=\frac{1}{2}\cdot AC\Rightarrow AX=\frac{1}{2}\cdot14\operatorname{cm}\Rightarrow AX=7\operatorname{cm}[/tex]Finding the value of AY

We have that AB = 18cm, then we have:

[tex]\frac{AY}{AB}=\frac{1}{2}\Rightarrow AY=\frac{1}{2}\cdot AB\Rightarrow AY=\frac{1}{2}\cdot18\operatorname{cm}\Rightarrow AY=9\operatorname{cm}[/tex]

In summary, therefore, the value for AX = 7cm, and the value for AY = 9cm.

If ai6 and an=3an-1 + n then find the value of az.Answer:

Answers

Answer

a₃ = 63

Explanation

We are told to find the 3rd term of this sequence.

Then, we are given that

first term = a₁ = 6

nth term = aₙ = 3aₙ₋₁ + n

To find the third term, we need to find the second term first

second term = a₂ = 3a₁ + 2 = 3 (6) + 2 = 18 + 2 = 20

Third term = a₃ = 3a₂ + 3 = 3 (20) + 3 = 60 + 3 = 63

Hope this Helps!!!

ActivityPlane A is descending toward the local airport, and plane B is ascending from the same airport. Plane A is descending at a rate of 2,500 feet perminute. Plane B is ascending at a rate of 4,000 feet per minute. If plane A is currently at an altitude of 14,000 feet and plane B is at an altitude of1,000 feet, how long will it take them to be at the same altitude? Represent time in minutes as the x-variable and altitude in thousands of feet asthe y-variable.

Answers

Let:

y1 = altitude of the plane A

y2 = altitude of the plane B

Let's find the equation for plane A:

[tex]\begin{gathered} m1=-2500 \\ y1=-2500x+b \\ for \\ 14000=-2500(0)+b \\ b=14000 \\ y1=-2500x+14000 \end{gathered}[/tex]

And for plane B:

[tex]\begin{gathered} m2=4000 \\ y2=4000x+b \\ for \\ 1000=4000(0)+b \\ b=1000 \\ y2=4000x+1000 \end{gathered}[/tex]

So:

[tex]\begin{gathered} y1=y2 \\ -2500x+14000=4000x+1000 \\ solve_{\text{ }}for_{\text{ }}x\colon_{} \\ 6500x=13000 \\ x=\frac{13000}{6500} \\ x=2 \end{gathered}[/tex]

Answer:

2 minutes

what is the distance from the origin to point P graphed on the complex plane below?√7√29729

Answers

SOLUTION:

Step 1:

In this question, we are given the following:

Step 2:

From the graph, we can see that:

Using the Pythagoras' theorem,

[tex]\begin{gathered} p^2=2^{2\text{ }}+5^2 \\ p^2=\text{ 4+ 25} \\ p^2=\text{ 29} \\ \text{square}-\text{root both sides, we have that:} \\ p\text{ =}\sqrt[]{29} \end{gathered}[/tex]

CONCLUSION:

The final answer is:

[tex]\sqrt[]{29}[/tex]

1. Lines m and n are perpendicular. If the slope of line m is zero, then what is the slope of line n? If you were to sketchlines m and n, what type of lines would you sketch?2. On a graph, create your own set of perpendicular lines similar to lines m and n. Choose two points on each line andprove through the slope formula, that the lines are perpendicular to each other.

Answers

when lines are perpendicular to each other, they make 90 degrees to each other

whenever you have a slope of 0, it means the y-axis remains constant while the x-axis increases

since m has a slope of zero, that's why it's in that position while n increases

slope = y2 - y1 / x2 - x1

After a translation, the image of P(-3,5) is P(-4,3). Find the translation rule. Write your answer in the form (x+a, y+b).

Answers

P(-3,5)

Image: (-4,3)

x coordinate:

-3+a = -4

Solve for a

a=-4+3

a= -1

y coordinate:

5+b =3

b =3-5

b= -2

So:

(x-1, y-2)

Please help meif you can't read it it says -138=-6(6b-7)

Answers

We have the following:

[tex]\begin{gathered} -138\ge-6\cdot(6b-7) \\ \end{gathered}[/tex]

solving for b:

[tex]\begin{gathered} -6\cdot(6b-7)\le-138 \\ -\frac{6}{6}\cdot(6b-7)\le-\frac{138}{6} \\ -(6b-7)\le-23 \\ (6b-7)\ge23 \\ 6b-7+7\ge23+7 \\ 6b\ge30 \\ b\ge\frac{30}{6} \\ b\ge5 \end{gathered}[/tex]

Therefore, the interval is:

[tex]\lbrack5,\infty)[/tex]

Rewrite the rational expression as an equivalent rational expression with the given denominator

Answers

Let z be the required expression.

The given is

[tex]\frac{3}{14x+98}=\frac{z}{14y(x+7)}[/tex]

Using the cross product method, we get

[tex]3\times14y(x+7)=z(14x+98)[/tex]

[tex]42y(x+7)=z(14x+98)[/tex]

Dividing both sides by 14x+98, we get

[tex]\frac{42y\mleft(x+7\mright)}{14x+98}=\frac{z\mleft(14x+98\mright)}{14x+98}[/tex]

[tex]\frac{42y\mleft(x+7\mright)}{14(x+7)}=z[/tex]

[tex]\frac{42y}{14}=z[/tex]

[tex]3y=z[/tex]

Hence the answer is

[tex]\frac{3}{14x+98}=\frac{3y}{14y(x+7)}[/tex]

What is the volume of this cone? Use 73.14. Round your answer to thenearest whole cubic centimeter, if needed.14cm10cmANSWER CHOICES ARE 1539615470140

Answers

[tex]\begin{gathered} V=3.14\cdot7^2\cdot10 \\ V=1538.6\operatorname{cm}^3 \\ V\approx1539\operatorname{cm}^3 \end{gathered}[/tex]

given the inequality 6x - 10y ≥ 9, select all possible solutionsA. (-1, 1)B. (-3, 4)C. (2, 1)D. (4, -2)E. (2, 8)F. (5, 2)

Answers

[tex]6x-10y\ge9[/tex]

we simplify the expression to work easier

[tex]\begin{gathered} 6x\ge9+10y \\ 6x-9\ge10y \\ \frac{6x-9}{10}\ge y \end{gathered}[/tex]

now we check each point replacing the coordinates and checking the inequality

A.

[tex]\begin{gathered} \frac{6(-1)-9}{10}\ge(1) \\ \\ \frac{-6-9}{10}\ge1 \\ \\ -\frac{15}{10}\ge1 \\ \\ -1.5\ge1 \end{gathered}[/tex]

A is wrong because -1.5 isnt greater than 1 , so the inequality is wrong

B.

[tex]\begin{gathered} \frac{6(-3)-9}{10}\ge(4) \\ \\ \frac{-18-9}{10}\ge4 \\ \\ \frac{-27}{10}\ge4 \\ \\ -2.7\ge4 \end{gathered}[/tex]

B is wrong because -2.7 isnt greater than 4

C.

[tex]\begin{gathered} \frac{6(2)-9}{10}\ge(1) \\ \\ \frac{12-9}{10}\ge1 \\ \\ \frac{3}{10}\ge1 \\ \\ 0.3\ge1 \end{gathered}[/tex]

C is wrong because 0.3 isnt greater than 1

D.

[tex]\begin{gathered} \frac{6(4)-9}{10}\ge(-2) \\ \\ \frac{24-9}{10}\ge-2 \\ \\ \frac{15}{10}\ge-2 \\ \\ 1.5\ge-2 \end{gathered}[/tex]

D is right because 1.5 is grreater than -2

E.

[tex]\begin{gathered} \frac{6(2)-9}{10}\ge(8) \\ \\ \frac{12-9}{10}\ge8 \\ \\ \frac{3}{10}\ge8 \\ \\ 0.3\ge8 \end{gathered}[/tex]

E is wrong because 0.3 isnt greater than 8

F.

[tex]\begin{gathered} \frac{6(5)-9}{10}\ge(2) \\ \\ \frac{30-9}{10}\ge2 \\ \\ \frac{21}{10}\ge2 \\ \\ 2.1\ge2 \end{gathered}[/tex]

F is Right because 2.1 is greater than 2

In the United States, 1000 residents aged 15 or older were surveyed and 870 replied that they were satisfied with the water quality. The 90% confidence interval estimate of all U.S residents satisfied with their water quality is _________.

Answers

Given:

Here In the United States, 1000 residents aged 15 or older were surveyed and 870 replied that they were satisfied with the water quality is given.

Required:

Interval of 90% confidence level.

Explanation:

The formula to find the interval of confidence level is as below

[tex]=(p^{\prime}-z*\sqrt[]{\frac{p^{\prime}(1-p^{\prime})}{n}},\text{p' }+z*\sqrt[]{\frac{p^{\prime}(1-p^{\prime})}{n}})[/tex]

Now we have to find the value of all

z=1.64485

p'=870/1000=0.87

n=1000

Now put the all values

[tex](0.87-1.64485*\sqrt[]{\frac{0.87(1-0.87)}{1000}},0.87+1.64485*\sqrt[]{\frac{0.87(1-0.87)}{1000}})[/tex][tex](0.87-0.0175,0.87+0.0175)[/tex][tex](0.8525,0.8875)[/tex]

Final answer:

Confidence interval is (0.8525,0.8875)

how to solve 5x+5=2x+20

Answers

To do this you can subtract 5 from both sides of the equation

[tex]\begin{gathered} 5x+5=2x+20 \\ 5x+5-5=2x+20-5 \\ 5x=2x+15 \end{gathered}[/tex]

Now you can subtract 2x from both sides of the equation

[tex]\begin{gathered} 5x=2x+15 \\ 5x-2x=2x+15-2x \\ 3x=15 \end{gathered}[/tex]

Finally, you can divide by 3 both sides of the equation

[tex]\begin{gathered} \frac{3x}{3}=\frac{15}{3} \\ x=5 \end{gathered}[/tex]

On the other hand, to check you replace the value of x found in the original expression

[tex]\begin{gathered} 5x+5=2x+20 \\ 5(5)+5=2(5)+20 \\ 25+5=10+20 \\ 30=30 \end{gathered}[/tex]

Since a true equality is obtained, then it is true that the value of x is 5.

Question 3 of 10Which of the following are exterior angles? Check all that apply.

Answers

The possible angles are exterior angles:

[tex]\measuredangle2,\text{ }\measuredangle4\text{ and }\measuredangle6[/tex]

The inner angles of the triangle are:

[tex]\measuredangle5\text{ and }\measuredangle1[/tex]

We also can see that:

[tex]\measuredangle1\text{ }\cong\measuredangle3\text{ and }\measuredangle2\text{ }\cong\measuredangle4[/tex]

Since

[tex]\measuredangle1\text{ and }\measuredangle3\text{ }[/tex]

They are vertical angles formed by two intersecting lines, and 1 is congruent to 3. So, 3 is a

4Which expression is equivalent to 3*25?--45+34 1 1+3x+4³03x-y-4 5+3+3X-3x - 1 - 1 - 3 x -1 13X-43 152+3544YyIN1|2

Answers

Explanation

If we look at the given options we can see that

[tex]\begin{gathered} \frac{1}{3}x-\frac{1}{4}y-\frac{4}{5}+\frac{1}{3}x-\frac{1}{4}y \\ rearrange\text{ terms} \\ =\frac{1}{3}x+\frac{1}{3}x-\frac{1}{4}y-\frac{1}{4}y-\frac{4}{5} \\ =\frac{x+x}{3}-\frac{y+y}{4}-\frac{4}{5} \\ =\frac{2x}{3}-\frac{2y}{4}-\frac{4}{5} \\ =\frac{2x}{3}-\frac{1}{2}y-\frac{4}{5} \end{gathered}[/tex]

Answer: Option 2

I need help checking my answers to simplifying expressions. -2n-(9-10n)

Answers

We are given the following expression

[tex]-2n-(9-10n)[/tex]

We are asked to simplify the above expression.

First of all, expand the parenthesis.

[tex]\Rightarrow-2n-9+10n[/tex]

Now, combine the like terms together and simplify

[tex]\begin{gathered} \Rightarrow10n-2n-9 \\ \Rightarrow8n-9 \end{gathered}[/tex]

Therefore, the simplified expression is

[tex]8n-9[/tex]

Fill in the blank __(x+6)+8(x+6) =4x+24

Answers

We want to fill in the blank in the equation;

let's represent the blank with a.

[tex]_{}a(x+6)+8(x+6)=4x+24[/tex]

Let's factorize the right side of the equation.

[tex]\begin{gathered} a(x+6)+8(x+6)=4x+24 \\ a(x+6)+8(x+6)=4(x+6) \end{gathered}[/tex]

and also the left side;

[tex]\begin{gathered} a(x+6)+8(x+6)=4(x+6) \\ (a+8)(x+6)=4(x+6) \end{gathered}[/tex]

Then let's divide both sides by (x+6);

[tex]\begin{gathered} (a+8)(x+6)=4(x+6) \\ \frac{(a+8)(x+6)}{(x+6)}=\frac{4(x+6)}{(x+6)} \\ (a+8)=4 \end{gathered}[/tex]

Then we can solve for a in the resulting equation.

subtract 8 from both sides.

[tex]\begin{gathered} a+8=4 \\ a+8-8=4-8 \\ a=-4 \end{gathered}[/tex]

Therefore, the value to fill into the blank is -4

[tex]-4(x+6)+8(x+6)=4x+24[/tex]

Sara runs along a circular track. The diameter of the track is 75 yards. She will jog 2 laps around the track. Which is the closest to the amount of yards Sara will run?

Answers

Answer:

Sara will run 8836 square yards

Explanation:

Given that the diameter of the track Sara runs is 75 yards.

The radius is half the diameter, and so, 37.5

Sara will jog 2 laps around the track, therefore, the amount of yards Sara will run is obtained by finding twice the area of the circle she is going to cover.

Area of a circle is:

[tex]A=\pi r^2[/tex]

Where r is the radius

Using r = 37.5

[tex]\begin{gathered} A=\pi(37.5)^2 \\ =1406.25\pi \\ =4417.9 \end{gathered}[/tex]

Since she is jogging 2 laps, we have the yards she will cover to be:

2(4417.9)

= 8835.8

Approximately 8836 square yards

Which graph shows a polynomial function that does not have a negative interval?

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

Graph

Step 02:

We must analyze the graphs to find the solution.

Positive Interval (above x-axis)

That is the full solution.

Which of the graphs is represented by the following table:X-2 -1 0 1 2y1 2 3 4 5Click the button BELOW the correct graph.2+23442++22++2-3+432++2Show

Answers

Let us prepare the table from the deduced information as shown below:

We can use a graphing calculator to plot the points.

The graph is shown below:

x = 23 is a solution for the equation x/2 = 10 true or false

Answers

False

Here, we want to check if x = 23 is a solution for the equation

Firstly, we need to understand that what we have is a linear equation, an equation in which the highest power of the variable is 1. For this type of equations, what we expect is a single solution.

Thus;

[tex]\begin{gathered} \frac{x}{2}\text{ = 10} \\ \\ x\text{ = 2 }\times\text{ 10} \\ \\ x\text{ = 20} \end{gathered}[/tex]

Since x = 20 is the only possible solution, then x = 23 as a solution must be incorrect and false

Other Questions
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