The triangle shown below has an area of 22 units, 4 Find the missing length. = units​

The Triangle Shown Below Has An Area Of 22 Units, 4 Find The Missing Length. = Units

Answers

Answer 1

Answer:

11

Step-by-step explanation:

The formula for the area of a triangle is bh(1/2).

We can model an equation with:

22=4x(1/2)

multiply both sides by 2

44=4x

x=11


Related Questions

A.
B.
C.
D.
Please help

Answers

Answer:

I Think the answer is B I'm sorry if I'm wrong

Financial Literacy Paul earns $25 for grooming a dog plus $18.50
per day for boarding the same dog.
e. Write an equation to find the amount of money Paul earned m
for grooming a dog once and boarding it for any number of days d.
f. Make a table to find his earnings for 5, 6, 7, or 8 days. Then graph
the ordered pairs.

Answers

Answer:

e): m=18.50d + 25

Step-by-step explanation:

If a chain is on 24 tooth front gear and 8 tooth rear gear determine whether this combination will result in high speed than a 2 to 1 gear ratio, assuming the speed you are pedalling is the same

Answers

24/8 = 3


the 24 to 8 gear = 3:1 ratio which is greater than 2:1

PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPP


Consider this dilation.



(a) Is the image of the dilation a reduction or an enlargement of the original figure? Explain.
(b) What is the scale factor? Explain and show your work.

ANSWER BOTH PARTS YOU MAY GET EXTRA POINTS!

Answers

Answer:

reductionscale factor 1/2

Step-by-step explanation:

The usual English meanings of the words "reduction" and "enlargement" apply to geometrical figures.

(a)

Figure A'B'C'D' is smaller than figure ABCD, so represents a reduction.

__

(b)

Every coordinate of every image point is half as far from the origin in A'B'C'D' as in the original figure ABCD. For example, the x-coordinate of C' is 2, and the x-coordinae of C is 4. The dilation factor is the ratio of these values:

  k = Cx'/Cx = 2/4 = 1/2

The scale factor is 1/2.

1\6 + 1\6 + 1\6= pl help answers 3\6, 6\3, 3/18, 1\18

Answers

Answer: 3/6
1+1+1=3 and the bottom isn’t changed

6 math questions, answer all please for all points

Answers

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Recall that the projection of a vector [tex]u[/tex] onto [tex]v[/tex] is [tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v[/tex].

Identify the vectors:

[tex]u=\langle-10,-7\rangle[/tex]

[tex]v=\langle-8,4\rangle[/tex]

Compute the dot product:

[tex]u\cdot v=(-10*-8)+(-7*4)=80+(-28)=52[/tex]

Find the square of the magnitude of vector v:

[tex]||v||^2=\sqrt{(-8)^2+(4)^2}^2=64+16=80[/tex]

Find the projection of vector u onto v:

[tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\\\\proj_vu=\biggr(\frac{52}{80}\biggr)\langle-8,4\rangle\\\\proj_vu=\biggr\langle\frac{-416}{80} ,\frac{208}{80}\biggr\rangle\\\\proj_vu=\biggr\langle\frac{-26}{5} ,\frac{13}{5}\biggr\rangle\\\\proj_vu=\langle-5.2,2.6\rangle[/tex]

Thus, B is the correct answer

Problem 2

Treat the football and wind as vectors:

Football: [tex]u=\langle42\cos172^\circ,42\sin172^\circ\rangle[/tex]

Wind: [tex]v=\langle13\cos345^\circ,13\sin345^\circ\rangle[/tex]

Add the vectors: [tex]u+v=\langle42\cos172^\circ+13\cos345^\circ,42\sin172^\circ+13\sin345^\circ\rangle\approx\langle-29.034,2.481\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{(-29.034)^2+(2.481)^2}\approx29.14[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{2.841}{-29.034}\biggr)\approx -5^\circ[/tex]

Because our resultant vector is in Quadrant II, the true direction angle is 6° clockwise from the negative axis. This means that our true direction angle is [tex]180^\circ-5^\circ=175^\circ[/tex]

Thus, C is the correct answer

Problem 3

We identify the initial point to be [tex]R(-2,12)[/tex] and the terminal point to be [tex]S(-7,6)[/tex]. The vector in component form can be found by subtracting the initial point from the terminal point:

[tex]v=\langle-7-(-2),6-12\rangle=\langle-7+2,-6\rangle=\langle-5,-6\rangle[/tex]

Next, we find the magnitude of the vector:

[tex]||v||=\sqrt{(-5)^2+(-6)^2}=\sqrt{25+36}=\sqrt{61}\approx7.81[/tex]

And finally, we find the direction of the vector:

[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{6}{5}\biggr)\approx50.194^\circ[/tex]

Keep in mind that since our vector is in Quadrant III, our direction angle also needs to be in Quadrant III, so the true direction angle is [tex]180^\circ+50.194^\circ=230.194^\circ[/tex].

Thus, A is the correct answer

Problem 4

Add the vectors:

[tex]v_1+v_2=\langle-60,3\rangle+\langle4,14\rangle=\langle-60+4,3+14\rangle=\langle-56,17\rangle[/tex]

Determine the magnitude of the vector:

[tex]||v_1+v_2||=\sqrt{(-56)^2+(17)^2}=\sqrt{3136+289}=\sqrt{3425}\approx58.524[/tex]

Find the direction of the vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{17}{-56} \biggr)\approx-17^\circ[/tex]

Because our vector is in Quadrant II, then the direction angle we found is a reference angle, telling us the true direction angle is 17° clockwise from the negative x-axis, so the true direction angle is [tex]180^\circ-17^\circ=163^\circ[/tex]

Thus, A is the correct answer

Problem 5

A vector in trigonometric form is represented as [tex]w=||w||(\cos\theta i+\sin\theta i)[/tex] where [tex]||w||[/tex] is the magnitude of vector [tex]w[/tex] and [tex]\theta[/tex] is the direction of vector [tex]w[/tex].

Magnitude: [tex]||w||=\sqrt{(-16)^2+(-63)^2}=\sqrt{256+3969}=\sqrt{4225}=65[/tex]

Direction: [tex]\displaystyle \theta=tan^{-1}\biggr(\frac{-63}{-16}\biggr)\approx75.75^\circ[/tex]

As our vector is in Quadrant III, our true direction angle will be 75.75° counterclockwise from the negative x-axis, so our true direction angle will be [tex]180^\circ+75.75^\circ=255.75^\circ[/tex].

This means that our vector in trigonometric form is [tex]w=65(\cos255.75^\circ i+\sin255.75^\circ j)[/tex]

Thus, C is the correct answer

Problem 6

Write the vectors in trigonometric form:

[tex]u=\langle40\cos30^\circ,40\sin30^\circ\rangle\\v=\langle50\cos140^\circ,50\sin140^\circ\rangle[/tex]

Add the vectors:

[tex]u+v=\langle40\cos30^\circ+50\cos140^\circ,40\sin30^\circ+50\sin140^\circ\rangle\approx\langle-3.661,52.139\rangle[/tex]

Find the magnitude of the resultant vector:

[tex]||u+v||=\sqrt{3.661^2+52.139^2}\approx52.268[/tex]

Find the direction of the resultant vector:

[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{52.139}{-3.661} \biggr)\approx-86^\circ[/tex]

Because our resultant vector is in Quadrant II, then our true direction angle will be 86° clockwise from the negative x-axis. So, our true direction angle is [tex]180^\circ-86^\circ=94^\circ[/tex].

Thus, B is the correct answer

someone help me with my homework

Answers

Answer:

Cite evidence from the text to explain Her as role in Greek mythology

What is the simplest form of the quotient? Simplify by rationalizing the denominator.

[tex]\frac{\sqrt{3x^{12} y^{10}}}{\sqrt{5x^{6} y^{3}}}[/tex]

A. [tex]5x^{3} y^3 \sqrt{15y}[/tex]
B. [tex]\frac{x^3 y^3 \sqrt{15y} }{5}[/tex]
C. [tex]\frac{\sqrt{15x^{18} y^{13}}}{5x^6 y^3}[/tex]
D. none of these

Answers

Answer:

[tex]5x^{3} y^3 \sqrt{15y}[/tex] is the right answer and other are wrong

Please help fast!!!!
How many solutions does the equation y + 12 = y + 10 + 2 have?
O Zero
One
O Two
O Infinitely many

Answers

Answer:

Infinitely many

Step-by-step explanation:

Given:

[tex]y + 12 = y + 10 + 2[/tex]

Solve:

Subtract y from  both sides

[tex]y+12-y=y+10+2-y[/tex]

Simplify

[tex]12=10+2[/tex]

Now add : 10 + 2

[tex]12=12[/tex]

Both side are equal

Since both sides are equal then answer = Infinitely many

[RevyBreeze]

Find the sum of 3.0478 and 4.92 using the correct number of significant digits.

A. 7.967
B. 7.97
C. 7.9
D. 8

Answers

Answer:

Since the least number of digits in the number is 2 decimal places

Round 3.0478 to 2 dp

3.05+4.92=7.97

B is the answer

Step-by-step explanation:

Give brainliest please

Answer:

B

Step-by-step explanation:

The growth of plants in one week are recorded for 6 plants with a sample standard deviation of 4inches and sample mean of 11 inches.
t* at the 0.05 significance level=__
Margin of error = ___
Confidence interval = _____

Answers

Answer:

from my side it's blurry

Margin of error = 0.8226401

Confidence interval = (9.17736,10.82264)

We have given data for one week recorded for 6 plants.

With a sample standard deviation of 1 inch and a sample mean of 10 inches.

For this sample, it is given that,

Sample size = n = 6

Sample SD = s = 1

Sample mean = x = 10

At a 0.10 significance level, the critical point is with t-distribution (n-1)df=5 df,

t*  =2.015048

Margin of error = E=2.015048*s/ √n = 0.8226401

Confidence interval

= (9.17736,10.82264)

Learn more about Margin of error here: https://brainly.com/question/10218601

#SPJ4

How do I use Brainly math for solving stuff like this and how do I show my evidence on paper?

Answers

Answer:

a) 3

b) 1/3

Step-by-step explanation:

I've never used Brainly math before, but I can help you out with the work for these problems.

Part A

3(x + 1) - x = 15

3x + 3 - x = 15

4x + 3 = 15

4x = 12

x = 3

Part B

5(x + 2) - 2x = 11

5x + 10 - 2x = 11

3x + 10 = 11

3x = 1

x = 1/3

Hope this helps!

The following can be deposited in a savings account: (check all that apply)
1. Jewels
2. Cash
3. Paycheck
4. Coin
5. Checks

Answers

Jewels is the answer

Answer:  cash, paychecks, checks

Step-by-step explanation:

(: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (:

A rectangle has an area of 20 cm^2. What will the area be if the rectangle tripled in size?

Answers

Answer:

  180 cm^2

Step-by-step explanation:

For similar figures the ratio of areas is the square of the ratio of linear dimensions.

We take "tripled in size" to mean that the linear dimensions of the larger rectangle are 3 times those of the smaller rectangle. That means the area of the larger rectangle will be 3² = 9 times the area of the smaller one.

  Area = (3²)(20 cm²) = 180 cm² . . . . area after tripled in size

What are the coordinates of a point on the unit circle if the angle formed by the positive x-axis and the radius is 45? (WHO WANTS BRAINLIEST?!)

Answers

Answer:

the 45 degree angle is in the first quadrant, the coordinates are (√2/2, √2/2) (square root of 2 on the top, 2 on the bottom)

26 rooms on 2 floors = ____ rooms on 4 floors

Answers

Answer:

There would be 104 rooms on 4 floors in total.

Step-by-step explanation:

If there were 26 rooms on 2 floors, then you multiply 26 x 4, the result would be 104 rooms on 4 floors in total.

Answer:

52 rooms

Step-by-step explanation:

you could set up a proportion to solve this

26 rooms/ 2 floors = ?/4 floors

to find the answer for the question mark you can divide the amount of rooms by floors and get 13.

With the 13 you can multiply that by 4 to get 52 rooms. You basically used the 13 as the amount of increase

i hope this helped

if you have anymore questions feel free to ask again:3

Find the exact value, without a
calculator.
30°
sin 15° sin
tan 15º =
2
cos 15° 30°
2
COS
II
[ ? ] - [
] + [
Enter

Answers

[tex]sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}} \qquad cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1-cos(30^o)}{2}}\implies \sqrt{\cfrac{1-\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2-\sqrt{3}}{2}~~}{2}}[/tex]

[tex]\sqrt{\cfrac{2-\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2-\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2-\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1+cos(30^o)}{2}}\implies \sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2+\sqrt{3}}{2}~~}{2}} \\\\\\ \sqrt{\cfrac{2+\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2+\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{~~ sin\left( \frac{30^o}{2} \right)~~}{cos\left( \frac{30^o}{2} \right)}\implies \cfrac{~~\frac{\sqrt{2-\sqrt{3}}}{2} ~~}{\frac{\sqrt{2+\sqrt{3}}}{2}}\implies \cfrac{\sqrt{2-\sqrt{3}}}{2}\cdot \cfrac{2}{\sqrt{2+\sqrt{3}}} \\\\\\ \cfrac{\sqrt{2-\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \blacktriangleright \sqrt{\cfrac{2-\sqrt{3}}{2+\sqrt{3}}} \blacktriangleleft[/tex]

Pattern A follows the rule "add 5" and Pattern B follows the rule "subtract 2." Pattern A 5 10 15 20 25 Pattern B 20 18 16 14 12 Which ordered pairs are formed from combining a term in Pattern A with its corresponding term in Pattern B? Select all correct answers.

Answers

Answer:

(10,  20)

(25,  12)

(15,  20)

Step-by-step explanation:

Hopes this helps! :)

Answer:

the correct answers are,

(15, 16)

(25, 12)

(5, 20)

The probability distribution for a random variable x is given in the table.

(see image)

Find the probability that x<-3

Answers

Answer:

30%

Step-by-step explanation:

The sign means that x can be equal to or LESS than -3. The only ones are -3 and -5. 0.17+0.13=0.30

If the data for the heights of players on a basketball team is skewed right, which statistical measure represents the spread of the data best?

A. Interquartile Range
B. Mean
C. Median
D. Range

Answers

Answer:

Median

Step-by-step explanation:

I know that you can't do Range, since it's skewed right.

The mean can't be it since it's also not representative when it's skewed right.

I'd say Median, or IQR at first glance but if you look at a graph, the IQR might follow with the skewed and move over a bit.

That leaves Median.

The correct statistical measure which represents the spread of the data best is, Median.

Given that;

The data for the heights of players on a basketball team is skewed right.

Since, We know that;

For the data for the heights of players on a basketball team is skewed right,

We can use Median for the spread of the data best.

Hence, The correct statistical measure which represents the spread of the data best is, Median.

Learn more about the median visit:

https://brainly.com/question/26177250

#SPJ2

A question to upload the GeoGebra downloaded file : Graph the quadratic function of your choice and find the vertex and axis of symmetry .​

Answers

Answer:I drew a quadratic function with a vertex and axis of symmetry, hope this helps

After your training program is completed, what should you do?
A. Evaluate progress
B. None apply
C. Start the program again
D. Add on more time

Answers

Answer:

A. evaluate progress

Step-by-step explanation:

common sense

Find any in the sequence -3, 6, -12, 24

Answers

Answer: 3

Step-by-step explanation:

go in evenly

Find the measures of angles 1 through 6.

Answers

Answer:

<1 = 88° , <2 = 129°, <3 = 82°, <4 = 147°, <5 = 94°, <6 = 86°

Step-by-step explanation:

<1 + 92° = 180°

<1 = 88°

<2 + 51° = 180°

<2 = 129°

<3 + 98° = 180°

<3 = 82°

<4 + 33° = 180°

<4 = 147°

<1 + <2 + <3 + <4 + <5 = 540°

88° + 129° + 82° + 147 + <5 = 540°

<5 = 94°

<5 + <6 = 180°

94° + <6 =180°

<6 = 86°

How many symmetrical sides does a star have?​

Answers

Answer:

Depends on how many points the star has. For example, a 5 pointed star will have 5 lines of symmetry. Knowing this, you should be able to count using a diagram or drawing of the star

The sum of the three interior angles of a triangle is 180. Suppose one angle is 74 and the remaining two angles are the same measure. Reason numerically to find the measures of the remaining angles.

Answers

Answer:

53

Step-by-step explanation:

[tex]sum \: of \: angles = 180 \\ 180 = 74 + 2x \: where \: x \: is \: the \: measure \: of \: the \: other \: angles \\ 180 - 74 = 2x \\ 106 = 2x \\ x = \frac{106}{2} \\ x = 53[/tex]

Always welcome

Let
[tex]Let \\ \displaystyle\sf S = \sum_{k=1}^n \dfrac{n}{n^2+kn + k^2} [/tex] and ,
[tex]\displaystyle \sf T_n =\sum_{k=0}^{n-1}\dfrac{n}{n^2+kn+k^2}[/tex] ,
[/tex]
where n = 1,2,3,4..... Then ,
[tex]A)\quad S_n < \dfrac{\pi}{3\sqrt3} \qquad \qquad B)\quad S_n >\dfrac{\pi}{3\sqrt3}\\\\ C)\quad T_n >\dfrac{\pi}{3\sqrt3}\qquad\qquad D)\quad T_n < \dfrac{\pi}{3\sqrt3}[/tex]

Answers

Answer:

  A, D

Step-by-step explanation:

You want to know the bound for the values of Sn and Tn, given their definitions as ...

  [tex]\displaystyle S_n=\sum_{k=1}^n{\dfrac{n}{n^2+kn+k^2}}\\\\T_n=\sum_{k=1}^{n-1}{\dfrac{n}{n^2+kn+k^2}}[/tex]

Values

All we need to do to determine the correct answer choices is evaluate the sums for some value of n.

For n=2, the value of S2 is ...

  S2 = 2/(4+2+1) +2/(4+4+4) = 2/7 +2/12 = 19/42 ≈ 0.4524

For n=2, the value of T2 is ...

  T2 = 2/(4+2+1) = 2/7 ≈ 0.2857 . . . . . 1/(3n) less than the value of Sn

Both of these values are less than π/(3√3) ≈ 0.6046.

The correct answer choices are ...

  A) Sn < π/(3√3)

  D) Tn < π/(3√3)

__

Additional comment

For the purpose here, it is not necessary to determine the limiting value of either Sn or Tn. It is only necessary to demonstrate which side of the given value the terms of either sequence lie.

<95141404393>

which statement about the transformation is true? A. the unshaded octagon is a reflection because it is a flip over a diagonal line B. the unshaded octagon is a dilation because it is smaller than the shaded octagon C. the unshaded octagon is a horizontal translation because it is directly to the left of the shaded octagon D. the unshaded octagon is a vertical translation because it is directly under the shaded octagon

Answers

A)

If you draw a diagonal line going down and crossing the origin, you can see that the figure reflects over that line. It’s like a mirror.
It is not the case for horizontal reflection because then it had to be reflected to the left of y-axis and it is not vertical reflection because then it would reflect below the x-axis

ANSWER THE FOLLOWING:​

Answers

Step-by-step explanation:

2. since there are 15 shirt

the probability of her wearing a blue shirt is 5/15

the probability of her wearing a blue shirt is 4/15

using wqdevdsqxcsqsd

Answers

What is your question here bro !!
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