Answer:
[tex]Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}[/tex]
Explanation:
Hello,
In this case, weak acids are characterized by the fact they do not dissociate completely, it means they do not divide into the conjugated base and acid at all, a percent only, which is quantified via equilibrium. In such a way, the chemical equation representing such incomplete dissociation is said to be:
[tex]C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+[/tex]
Thus, we can write the law of mass action, which consider the equilibrium concentrations of all the involved species, which is also known as the acid dissociation constant which accounts for the capacity the acid has to yield hydronium ions:
[tex]K=Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}[/tex]
Best regards.
The compound barium nitrate is a strong electrolyte. Write the transformation that occurs when solid barium nitrate dissolves in water.
Answer:
Ba(NO₃)₂(s) → Ba²⁺ + 2NO₃⁻
Explanation:
A strong electrolyte is a salt (A compound that has an anion and a cation and are neutral) that, in water, dissociates completely in its ions.
In Barium nitrate, Ba(NO₃)₂, the cation is Ba²⁺ (Alkaline earth metal), and the anion is the nitrate ion, NO₃⁻.
Thus, when Ba(NO₃)₂ (s) is dissolved in water, its transformation is:
Ba(NO₃)₂(s) → Ba²⁺ + 2NO₃⁻When solid barium nitrate (Ba(NO₃)₂) dissolves in water, it undergoes a dissociation process where the compound breaks apart into its constituent ions.
Dissociation refers to the process in which a compound breaks apart into its constituent ions when dissolved in a solvent, typically water. In this process, the chemical bonds within the compound are disrupted, resulting in the separation of positive and negative ions.
The dissociation occurs due to the interaction between the solute particles and the solvent molecules, leading to the formation of hydrated ions.
The transformation can be represented as follows:
Ba(NO₃)₂(s) → Ba²⁺(aq) + 2NO₃⁻(aq)
In this process, the barium nitrate compound dissociates into barium ions (Ba²⁺) and nitrate ions (NO₃⁻) in the aqueous solution. The resulting ions are free to move and conduct electricity, indicating that barium nitrate is a strong electrolyte when dissolved in water.
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A constant volume and mass of helium gas at 77°C is heated so that the pressure of the gas doubles. What is the new temperature of the gas in Celsius degrees?
Answer:
427°C .
Explanation:
Step 1:
Data obtained from the question. This include the following:
Initial temperature (T1) = 77°C
Initial pressure (P1) = P
Final pressure (P2) = 2P
Final temperature (T2) =?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This is illustrated below:
T(K) = T (°C) + 273
Initial temperature (T1) = 77°C
Initial temperature (T1) = 77°C+ 273 = 350K
Step 3:
Determination of the new temperature. The new temperature can be obtained as follow:
P1/T1 = P2/T2
P/350 = 2P/T2
Cross multiply
P x T2 = 350 x 2P
Divide both side by P
T2 = (350 x 2P ) / P
T2 = 700K
Step 4:
Conversion of Kelvin temperature to celsius temperature.
This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 700K
T(°C) = 700 – 273
T(°C) = 427°C
Therefore, the new temperature of the gas is 427°C
Calculate the mass of a body
Whose volume is
Is 2cm3 and
density is 520cm3
Answer:
The answer is
1040gExplanation:
Density = mass / volume
mass = density × volume
volume = 2cm³
density = 520g/cm³
mass = 2 × 520
= 1040g
Hope this helps you
1. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n):_______.
2. Glyceraldehyde is an example of a(n):_____, because it has three carbon atoms.
3. A monosaccharide is a(n):_______ if the carbonyl group is on the end of the carbon chain.
4. Any carbohydrate with the carbonyl group on the second carbon is a(n):_______.
5. The most common carbohydrate, , has six carbon atoms.
6. With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n):_________.
Answer:
Following are the answer to this question:
Explanation:
The answer are:
1) ketopentose
2) Triose
3) Aldose
4) Ketose
5) Glucose
6) Aldohexose
The pentose has 2-position contain a personal ketone group. The triose is a monosaccharide or simple sugar that contains three atoms of carbon. The Aldose and ketose are simple carbohydrates, both also called monosaccharides. In aldose, it has a functional group of aldehydes within its structure. The ketose sugars have workable ketone groups. Stereoisomerism has been found in aldose sugars that contain more than three carbon atoms. Glucose is also one of the main molecules which function as plant and animal energy sources. It's also derived from plant sap and seems to be present in the bloodstream of humans, that's why it is called "blood sugar." The aldohexose is a hexose is a group of aldehydes on one end, it has a total of 16 possible aldohexose stereoisomers in four chiral centers.What is the shape of a molecule that has 4 atoms bonded to a central atom
and no lone pairs of electrons?
A. Octahedral
B. Cubic
C. Tetrahedral
D. Trigonal-pyramidal
Answer:
C. Tetrahedral
Explanation:
Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which means it has tetra (which translates to four) domains hence tetrahedral.
Tetrahedral is the shape of a molecule that has 4 atoms bonded to a central atom and no lone pairs of electrons. Hence, option C is correct.
What is an atom?An atom consists of a central nucleus that is usually surrounded by one or more electrons.
Tetrahedral would be the correct choice because the central atom has 4 domains (1 bond counts as 1 domain so 4 bonds =4) and no lone pairs which mean it has tetra (which translates to four) domains hence tetrahedral.
Hence, option C is correct.
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What is the electron geometry and molecular geometry of:
A. H2O
B. CH2CL2
C. OPCL3
D. CO3^2-
E. ALCL6^3-
F. SO2
G. PCL5
Answer:
H2O
Electron geometry-tetrahedral
Molecular geometry bent
CH2Cl2
Electron geometry- tetrahedral
Molecular geometry-tetrahedral
OPCL3
Electron geometry- tetrahedral
Molecular geometry- tetrahedral
CO3^2-
Electron geometry- trigonal planar
Molecular geometry- trigonal planar
ALCL6^3-
Electron geometry-octahedral
Molecular geometry- octahedral
SO2
Electron geometry-tetrahedral
Molecular geometry-bent
PCL5
Electron geometry-trigonal bipyramidal
Molecular geometry- trigonal bipyramidal
Explanation:
Water contains four electron domains this corresponds to a tetrahedral electron geometry. How ever, there are two lone pairs in the molecule hence it is bent.
CH2Cl2 is shows a tetrahedral molecular geometry and a tetrahedral electron geometry. This can only be observed from the structure of the compound.
OPCL3 is bonded to four groups making it a tetrahedral molecule. There are non lone pairs on phosphorus so the molecule is not bent.
CO3^2- is bonded to three groups which leads to a trigonal planar geometry.
ALCL6^3- contains six bonding groups which arrange themselves at the corners of a regular octahedron at a bond angle of 90°.
SO2 has four electron domains leading to a tetrahedral electron domain geometry according to valence shell electron pair repulsion theory. However, the lone pairs on the central atom in the molecule leads to a bent molecular geometry.
PCL5 has five electron domains without lone pairs of electrons on its central atom. Hence the molecule possess a trigonal bipyramidal geometry.
The electron geometry and molecular geometry of the molecule are as follows:
A. H₂O: The electron geometry is tetrahedral because it has four electron domains (two bonding pairs and two lone pairs). However, due to the presence of two lone pairs, the molecular geometry is bent or V-shaped.
B. CH2Cl₂: The electron geometry is tetrahedral. However, the molecular geometry is trigonal planar because two of the electron domains are occupied by chlorine atoms, resulting in a bent shape.
C. OPCl₃: The electron geometry is tetrahedral. However, the molecular geometry is trigonal pyramidal because one of the electron domains is occupied by a lone pair on phosphorus.
D. CO3⁻²: The electron geometry is trigonal planar because it has three electron domains (three single bonds). The molecular geometry is also trigonal planar.
E. AlCl6⁻³: The electron geometry is octahedral because it has six electron domains. The molecular geometry is also octahedral.
F. SO₂: The electron geometry is trigonal planar because it has three electron domains (two single bonds and one lone pair). The molecular geometry is bent or V-shaped due to the presence of a lone pair on sulfur.
G. PCl₅: The electron geometry is trigonal bipyramidal because it has five electron domains. The molecular geometry is also trigonal bipyramidal.
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What is the atomic mass of OsO4
Answer:
254.23 g/mol
Explanation:
Atomic mass for Osmium tetroxide would be 254.23 g/ml
Answer:254.2276
Explanation:
Which physical method can be used for obtaining a sample of salt from a small beaker of salt water?
boiling
freezing
chromatography
sorting
Answer:
a. boiling
Explanation:
Write a balanced half-reaction for the reduction of aqueous arsenic acid H3AsO4 to gaseous arsine AsH3 in basic aqueous solution. Be sure to add physical state symbols where appropriate.
Answer:
H₃AsO₄(aq) + 4 H₂O(l) + 8 e⁻ ⇒ AsH₃(g) + 8 OH⁻(aq)
Explanation:
Let's consider the half-reaction for the reduction of aqueous arsenic acid to gaseous arsine in a basic aqueous solution.
H₃AsO₄(aq) ⇒ AsH₃(g)
We see that there is an excess of 4 oxygen atoms on the left side. So, we add 4 molecules of water to the left side and 8 hydroxyl ions to the right side.
H₃AsO₄(aq) + 4 H₂O(l) ⇒ AsH₃(g) + 8 OH⁻(aq)
We need to add 8 electrons to the left side to balance the reaction electrically.
H₃AsO₄(aq) + 4 H₂O(l) + 8 e⁻ ⇒ AsH₃(g) + 8 OH⁻(aq)
Answer:
[tex]H_3AsO_4(aq)+8H^+(aq)+8e^-=AsH_3(g)+4H_2O(l)[/tex]
Explanation:
Chemistry question. Image attached.
Answer:
The balanced equation is given below: C2H6O + 3O2 —> 2CO2 + 3H2O
The coefficients are: 1, 3, 2, 3
Explanation:
C2H6O + O2 —> CO2 + H2O
The above equation can be balance as follow:
There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C2H6O + O2 —> 2CO2 + H2O
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C2H6O + O2 —> 2CO2 + 3H2O
There are a total of 3 atoms of O on the left side and a total of 7 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:
C2H6O + 3O2 —> 2CO2 + 3H2O
Now the equation is balanced.
The coefficients are: 1, 3, 2, 3.
Answer:
The balanced equation is given below: C2H6O + 3O2 —> 2CO2 + 3H2O
The coefficients are: 1, 3, 2, 3
Explanation:
C2H6O + O2 —> CO2 + H2O
The above equation can be balance as follow:
There are 2 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 2 in front of CO2 as shown below:
C2H6O + O2 —> 2CO2 + H2O
There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:
C2H6O + O2 —> 2CO2 + 3H2O
There are a total of 3 atoms of O on the left side and a total of 7 atoms on the right side. It can be balance by putting 3 in front of O2 as shown below:
C2H6O + 3O2 —> 2CO2 + 3H2O
Now the equation is balanced.
The coefficients are: 1, 3, 2, 3.
Explanation:
If 20.0 mL of a 0.0800 M HNO3, 35.0 mL of a 0.0800 M KSCN, and 40.0 mL of a 0.0800 M Fe(NO3)3 are combined, what is the initial concentration of SCN- in the mixture
Answer:
0.0295M
Explanation:
As you can see, in the mixture you have KSCN and other compounds. The KSCN in solution is dissolved in K⁺ ions and SCN⁻ ions. That means initial concentration of SCN⁻ ions is the same of KSCN, 0.0800M.
You are adding 35.0mL of this solution and the total volume of the mixture is 20.0mL + 35.0mL + 40.0mL = 95.0mL.
That means you are diluting your solution 95.0mL / 35.0mL = 2.714 times.
And the concentration of SCN⁻ is:
0.0800M / 2.714 =
0.0295MWhich of the following atoms would have the longest de Broglie wavelength, if all have the same velocity?
A) Li
B) Na
C) Fe
D) Pb
E) Not possible to tell with given information
Answer:
Li
Explanation:
The phenomenon of wave particle duality was well established by Louis deBroglie. The wavelength associated with matter waves was related to its mass and velocity as shown below;
λ= h/mv
Where;
λ= wavelength of matter waves
m= mass of the particle
v= velocity of the particle
This implies that if the velocities of all particles are the same, the wavelength of matter waves will now depend on the mass of the particle. Hence; the wavelength of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The longest wavelength will then be obtained from the smallest mass of matter. Hence lithium which has the smallest mass will exhibit the longest DeBroglie wavelength
The atom that have the longest de Broglie wavelength is ; ( A ) Li
Wave particle duality is a phenomenon by de Broglie. that shows that The wavelength associated with matter waves is related to its mass and velocity .
Wave particle duality is represented as ; λ = h / mv
λ= wavelength of matter waves
m= mass of the particle
v= velocity of the particle
Given that the elements have the same velocity the atom that would have the longest de Broglie wavelength is Li
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How does the carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere?
Answer:
The calculator add the CO2 released from the use of electricity, released from driving and the CO2 from the waste that we disposed.
Explanation:
The carbon dioxide, CO2 is what the human body does not need, therefore, we breathe it out, hence taking in oxygen(respiration process). The plants need oxygen for the production of their own food.
The carbon calculator estimate the amount of CO2 that each individual releases into the atmosphere through the consideration of several factors such as the kind of food that we eat.
Therefore, if we are to use the carbon calculator to determine the amount of CO2 that each individual releases into the atmosphere we will have:
The amount of CO2 that each individual releases into the atmosphere =( CO2 released from the use of electricity) + (CO2 released from driving) + (the CO2 from the waste that we disposed).
Calculate experimental error using the following data: the measured value equals 1.4 cm; the accepted value equals 1.2 cm.
a) -14.3%
b) 4.3%
c) -16.7%
d) 16.7%
Answer:
b) 14.3%
Explanation:
Hello,
In this case, the experimental error is computed as:
[tex]error=\frac{exp-theo}{exp} *100\%[/tex]
Whereas exp accounts for the measured value, in this case 1.4 cm, and theo the theoretical value, in this case 1.2 cm. Therefore, the result is:
[tex]error=\frac{1.4-1.2}{1.4} *100\%\\\\error=14.3\%[/tex]
Thereby, answer should be b) 14.3% (corrected).
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What is the name and molecular formula of the gas formed when baking soda was combined with vinegar, which you identified using flaming and glowing splints
What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?
[Afus H° = 6.01 kJ/mol H2O(s)]
Answer:
[tex]m=33.9g[/tex]
Explanation:
Hello,
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
[tex]Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J[/tex]
Afterwards, the mass of ice that can be melted is computed by:
[tex]Q=n \Delta _{fus}H[/tex]
So we solve for moles with the proper units handling:
[tex]n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol[/tex]
Finally, with the molar mass of water we compute the mass:
[tex]m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g[/tex]
Best regards.
mass=33.9g
Given:
n= 3.00 mol
Δfus H° = 6.01 kJ/mol H₂O(s)
Enthalpy of fusion is the change in its enthalpy resulting from providing energy, typically heat, to a specific quantity of the substance to change its state from a solid to a liquid, at constant pressure.
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
[tex]Q=nC_P[/tex]ΔT
[tex]Q=3.00\text{mol}*75.38\frac{J}{mol^oC} *50.0^oC\\\\Q=11307J[/tex]
Now, the mass of ice that can be melted is given by:
Q=nΔfus H°
So we solve for moles with the proper units handling:
n= Q/ Δfus H°
[tex]n=\frac{11307 J}{6010\frac{J}{mol} } =1.88 mol[/tex]
On substituting the moles with the molar mass of water we get:
[tex]m=1.88 mol*\frac{18 g}{1mol}\\\\m=33.9g[/tex]
The mass of ice is 33.9g.
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If a neutral acid donates a proton, the conjugate base will have a charge of _______. - Type both an integer and a sign for your answer.
Answer:
-1
Explanation:
If you donate a proton (positive charge) then the result will leave a negative charge. (a negative and positive charge result In a neutral charge)
The answer is -1
Now if i have an acid such as H2SO4. Recall that the neutral acid is dibasic as you cam see from the formula of the acid, the acid can give out a proton as follows;
[tex]H2SO4 ------> H^+ + HSO4^-[/tex]
We can see that the conjugate base (HSO4-) has a charge of -1 as written in the answer.
The same also happens for a monobasic acid and so on.
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In your discussion consider a SN2 reaction mechanism concept. Propose a modification of experimental procedure that would improve reaction yield. Give an example of another method of ether synthesis. Illustrate it with drawn reaction scheme; describe it in few sentences.
Answer:
Here's what I get
Explanation:
You may have done a Williamson synthesis of guaifenesin by reacting guaiacol with 3-chloropropane-1,2-diol.
A. Mechanism
Step 1
NaOH converts guaiacol into a phenoxide ion.
Step 2
The phenoxide acts as the nucleophile in an SN2 reaction to displace the Cl from the alkyl halide.
B. Improve the yield
You probably carried out the reaction in ethanol solution — a polar protic solvent.
You might try doing the reaction in a polar aprotic solvent— perhaps DMSO.
A polar aprotic solvent does not hydrogen bond to nucleophiles, so they become stronger.
C. Another method of ether synthesis —dehydration of alcohols
Sulfuric acid catalyzes the conversion of primary alcohols to ethers.
This is also a nucleophilic displacement reaction.
Protonation of the OH converts it into a better leaving group.
Attack by a second molecule of alcohol forms the protonated ether.
A molecule of water then removes the proton.
: Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050-L flask at 668 K, how many moles of Cl2(g) will be present at equilibrium
Answer:
The number of moles of Cl₂ present at equilibrium is 3.94x10⁻⁴ moles.
Explanation:
The reaction is:
CO(g) + Cl₂(g) ⇄ COCl₂(g)
The equilibrium constant of the above reaction is:
K = 1.2x10³
To find the moles of Cl₂ present at equilibrium, let's evaluate the reverse reaction:
COCl₂(g) ⇄ CO(g) + Cl₂(g)
The equilibrium constant for the reverse reaction is:
[tex] K_{r} = \frac{1}{1.2 \cdot 10^{3}} = 8.3 \cdot 10^{-4} [/tex]
Now, we need to calculate the concentration of CO and COCl₂:
[tex] C_{CO} = \frac{\eta_{CO}}{V} = \frac{0.3500 moles}{3.050 L} = 0.115 M [/tex]
[tex] C_{COCl_{2}} = \frac{\eta_{COCl_{2}}}{V} = \frac{0.05500 moles}{3.050 L} = 0.018 M [/tex]
Now, from the reaction we have:
COCl₂(g) ⇄ CO(g) + Cl₂(g)
0.018 - x 0.115+x x
The concentration of Cl₂ is:
[tex] K_{r} = \frac{[CO][Cl_{2}]}{[COCl_{2}]} [/tex]
[tex] 8.3 \cdot 10^{-4} = \frac{(0.115 + x)(x)}{0.018 - x} [/tex]
[tex] 8.3 \cdot 10^{-4}*(0.018 - x) - (0.115 + x)(x) = 0 [/tex]
By solving the above equation for x we have:
x = 1.29x10⁻⁴ M = [Cl₂]
Finally, the number of moles of Cl₂ present at equilibrium is:
[tex] \eta_{Cl_{2}} = C_{Cl_{2}}*V = 1.29 \cdot 10^{-4} mol/L*3.050 L = 3.94 \cdot 10^{-4} moles [/tex]
Therefore, the number of moles of Cl₂ present at equilibrium is 3.94x10⁻⁴ moles.
I hope it helps you!
A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent composition of fluorine
Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:
[tex]percent composition element A=\frac{total mass of element A}{mass of compound} *100[/tex]
In this case, the percent composition of fluorine is:
[tex]percent composition of fluorine=\frac{39.6 g}{60.3 g} *100[/tex]
percent composition of fluorine= 65.67%
The percent composition of fluorine is 65.67%
Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:
In this case, the percent composition of fluorine is:
percent composition of fluorine= 65.67%
The percent composition of fluorine is 65.67%
Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønsted-Lowery Theory.
Use the internet or your textbook as a reference to name the following and indicate if they are an acid or a base:
a. HCI
b. KOH
c. HNO
d. Mg(OH),
Answer and Explanation:
1. Arrhenius Theory which describes the concept protonic. The substance that gives H+ ions when diluted in water is called as an acid (e.g. HCl) and the substance that dissociates OH-ions whenever it is diluted in water is called as the base (e.g. NaOH)
on the other hand
Bronsted Lowery Theory describes the concept of a proton donor-acceptor. The proton-donating species is an acid and the proton-accepting species is known as a base.
2. The Chemical name and nature of acid is shown below:-
Nature Chemical Name
a. HCl Acidic Hydrochloric Acid
b. KOH Basic Potassium hydroxide
c. HNO Acidic Nitric Acid
d. Mg(OH)2 Basic Magnesium hydroxide
Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without re-arrangement give 2-butanol as the major product.
Answer:
See explanation
Explanation:
Hydration of alkenes is a common reaction in organic chemistry. Hydration is simply the addition of water to an alkene. This is an acid catalysed reaction as we can see from the mechanism attached.
Recall that our task is to carry out the synthesis of 2-butanol using an alkene starting material in which there will be no rearrangement of the intermediate carbocation. If we start with the compound shown in the image (but-2-ene), the first step is the formation of the secondary carbocation. This is followed by the addition of water. Subsequently, the added water is deprotonated by another water molecule to yield 2-butanol and the acid catalyst. All these steps have been clearly outlined in the image attached.
Which substance is the oxidizing agent in the following reaction? 2H2 + O2 -> 2H2O
Answer:
O₂
Explanation:
When we create H₂O, the electrons tend to be shared by oxygen. The hydrogen bonds with the oxygen covalently, but the electrons tend to stay with the oxygen longer rather than near the hydrogens.
Calculate the weight of solid NaOH required to prepare (a) 5 liters of a 2 M solution, (b) 2 liters of a solution of pH 11.5?
i need full solution not just result please
Answer:
A. 400g of NaOH.
B. 0.253g of NaOH.
Explanation:
A. The following data were obtained from the question:
Volume = 5 L
Molarity = 2 M
Mass =..?
Next, we shall determine the number of mole of NaOH. This can be obtain as follow:
Molarity = mole /Volume
2 = mole/5
Cross multiply
Mole = 2 x 5
Mole of NaOH = 10 moles
Finally, we shall convert 10 moles of NaOH to grams. This is illustrated below:
Mole of NaOH = 10 moles
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH =?
Mole = mass /molar mass
10 = mass of NaOH /40
Cross multiply
Mass of NaOH = 10 x 40
Mass of NaOH = 400g
Therefore, 400g of NaOH is needed to prepare the solution.
B. The following data were obtained from the question:
pH = 11.5
Volume = 2 L
Next, we shall determine the pOH of the solution. This can be obtain as shown below:
pH + pOH = 14
pH = 11.5
11.5 + pOH = 14
Collect like terms
pOH = 14 – 11.5
pOH = 2.5
Next, we shall determine the concentration of the hydroxide ion, [OH-] in the solution.
This is illustrated below:
pOH = - Log [OH-]
pOH = 2.5
2.5 = - Log [OH-]
-2.5 = Log [OH-]
Take the antilog of both side
[OH-] = antilog (-2.5)
[OH-] = 3.16×10¯³ M
Next, we shall determine the concentration of NaOH. This is illustrated below:
NaOH —> Na+ + OH-
From the balanced equation above,
1 mole of NaOH produced 1 mole of OH-.
Therefore, 3.16×10¯³ M NaOH will also produce 3.16×10¯³ M OH-.
Therefore, the concentration of NaOH is 3.16×10¯³ M
Next, we shall determine the number of mole of NaOH in the solution. This can be obtain as follow:
Molarity = 3.16×10¯³ M
Volume = 2 L
Mole of NaOH =?
Molarity = mole /Volume
3.16×10¯³ = mole of NaOH / 2
Cross multiply
Mole of NaOH = 3.16×10¯³ x 2
Mole of NaOH = 6.32×10¯³ mole
Finally, we shall convert 6.32×10¯³ mole of NaOH to grams
Mole of NaOH = 6.32×10¯³ mole
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH =?
Mole = mass /molar mass
6.32×10¯³ = mass of NaOH /40
Cross multiply
Mass of NaOH = 6.32×10¯³ x 40
Mass of NaOH =0.253 g
Therefore, 0.253g of NaOH is needed to prepare the solution.
Calculate the number of moles of C2H6 in 3.97×1023 molecules of C2H6.
3.97×1023 molecules C2H6 1 mol C2H6
------------------------------------------ x ------------------------------------ = 0.66 mol C2H6
6.022 x 1023 molec. C2H6
Sulfamic acid, HSO3NH2 (molar mass = 97.1 g/mol), is a strong monoprotic acid that can be used to standardize a strong base: A 0.179-g sample of HSO3NH2 required 19.4 mL of an aqueous solution of KOH for a complete reaction. What is the molarity of the KOH solution?
Answer: The molarity of KOH solution is 0.093 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
moles of [tex]HSO_3NH_2[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.179g}{97.1g/mol}=0.0018mol[/tex]
Now the balanced chemical equation will be :
[tex]HSO_3NH_2+KOH\rightarrow KSO_3NH_2+H_2O[/tex]
As 1 mole of [tex]HSO_3NH_2[/tex] requires 1 mole of KOH
Thus 0.0018 moles of [tex]HSO_3NH_2[/tex] requires =[tex]\frac{1}{1}\times 0.0018=0.0018[/tex] moles of KOH
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{0.0018\times 1000}{19.4ml}[/tex]
[tex]Molarity=0.093M[/tex]
Therefore, the molarity of KOH solution is 0.093 M
The molarity of the KOH solution is 0.093 M
We'll begin by calculating the number of mole of HSO₃NH₂.
Mass of HSO₃NH₂ = 0.179 gMolar mass of HSO₃NH₂ = 97.1 g/mol Mole of HSO₃NH₂ =?Mole = mass / molar mass
Mole of HSO₃NH₂ = 0.179 / 97.1
Mole of HSO₃NH₂ = 0.0018 mole
Next, we shall determine the number of mole of KOH required to react with 0.0018 mole of HSO₃NH₂.
HSO₃NH₂ + KOH —> KSO₃NH₂ + H₂O
From the balanced equation,
1 mole of HSO₃NH₂ reacted with 1 mole of KOH.
Therefore,
0.0018 mole of HSO₃NH₂ will also react with 0.0018 mole of KOH.
Finally, we shall determine the molarity of the KOH solution.
Mole of KOH = 0.0018 moleVolume = 19.4 mL = 19.4 / 1000 = 0.0194 LMolarity of KOH =?Molarity = mole / Volume
Molarity of KOH = 0.0018 / 0.0194
Molarity of KOH = 0.093 M
Thus, the molarity of the KOH solution is 0.093 M.
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If the reaction starts with a mixture of PCl5, PCl3 and Cl2 at pressures of 0.820 atm, 1.322 atm and 0.911 atm respectively, is the reaction at equilibrium
Answer:
The reaction is not in equilibrium
Explanation:
For the reaction:
PCl₅ ⇄ PCl₃ + Cl₂
Equilibrium constant, Kp, is defined as:
[tex]Kp = \frac{P_{PCl_3}P_{Cl_2}}{P_{PCl_5}} = 0.497[/tex]
When this ratio is = 0.497, the reaction is in equilibrium. Replacing the pressures of the problem, reaction quotient, Q, is:
[tex]Q =\frac{1.322atm*0.911atm}{0.820atm} = 1.469[/tex]
As Q ≠ Kp, the reaction is not in equilibrium
To reach the equilibrium, the reaction will shift to the left producing more reactant and decreasing amount of products.
Give me example of rancidity
Answer:
An example of rancidity is when a chips pack is exposed to atmospheric air which results in a change in taste and odor.
Explanation:
Rancidity is a condition in which the substance with oil and fats get oxidized when they are exposed to air. A substance is said to be rancid when there is a change in smell, taste, and colour.Oil becomes rancid due to decomposition of fats it contains or sometimes milk becomes rancid due to not heating it in humid atmosphere, etc.
Answer:
Change in the taste and smell of food is the answer.
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Read the following passage and find the two errors. Then, choose the answer that corrects the errors.
pH is a measure of the concentration of OH ions in a solution of an acid or base. The pH scale plots the concentration of solutions in a range from 0-16.
O pH is a measure of the concentration of Hions in a solution of an acid or base. The pH plots the concentration of solutions in a range from 0-14.
O pH is a measure of the concentration of H* ions in a solution of an acid or base. The basic scale plots the concentration of solutions in a range from 0-16.
O pH is a measure of the concentration of OH" ions in a solution of water. The pH scale plots the concentration of solutions in a range from 0-12
O pH is a measure of the concentration of OH" ions in a solution of an acid or base. The acid scale plots the concentration of solutions in a range from 0-
16
Answer:
pH is a measure of the concentration of H+ ions in a solution of an acid or base. The pH plots the concentration of solutions in a range from 0–14.
Explanation:
The pH is a measure of the hydrogen ion(H^+) concentration in an acid or base. It can be obtained mathematically by the formula:
pH = —Log [H^+]
The pH scale ranges from 0 to 14
Answer:
it really is A
Explanation:
just got wrong answer because i put 16 and clearly b and c makes no sence : )
Addition of 12 M (concentrated) HCl to saturated NaCl results in precipitation of NaCl. Yet when 1 M HCl is added to the same NaCl solution, no precipitate forms. Explain.
Answer:
When we add 12M HCl, reaction quotient Qsp becomes greater than Ksp of NaCl leading to precipitation
Explanation:
When sodium chloride is dissolved in water, the equilibrium dissolution process known as Ksp is set up as typified by the equation;
NaCl(s)------> Na^+(aq) + Cl^-(aq)
According to Le Chatelier's principle, this system will remain in equilibrium after the addition of the 1M HCl. This explains why there will not be any change in the system after adding this solution.
However, addition of 12 M HCl will significantly distort the equilibrium position since there is now more Cl^- ion in the system. The system now seeks to relieve this stress by recrystallizing more sodium chloride leading to the formation of a precipitate. Succinctly put, when we add the 12M HCl, the reaction quotient Qsp becomes greater than Ksp of NaCl leading to precipitation of NaCl crystals.
When we add 12-M (concentrated) H-C-I, reaction quo-ti-ent becomes high that leading to pre-ci-pi-ta-tion.
L-e Cha-te-li-er's principle:
In the case when sodium chloride should be dissolved in water, the equilibrium diss-olu-tion process is developed as typified by the equation;
[tex]NaCl(s)\rightarrow Na^+(aq) + Cl^-(aq)[/tex]
Now as per the principle, this system will remain in equilibrium after the addition of the 1-M is done. But the addition of 12-M will significantly distort the equilibrium position since there is now more [tex]Cl^-[/tex] ion in the system.
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