The warning tag on a lawn mower states that it produces noise at a level of 91.0 dB. What is the intensity of this sound in watts per meter squared

The pictorial diagram with a rocket launched straight upward, showing the first three positions of the rocket with equal spacing between them, best illustrates projectile motion. In this case, the rocket is projected upward into the air, and its path follows a parabolic trajectory due to the influence of gravity.

Projectile motion refers to the motion of an object that is thrown, launched or otherwise projected into the air and then moves under the influence of gravity alone. In this type of motion, the object moves along a curved path, called a parabola, due to the combined effect of its initial velocity and the force of gravity acting on it.

When a rocket is launched straight upward, it experiences a projectile motion. The rocket's initial velocity is upwards, but gravity causes it to decelerate until it eventually stops at the highest point of its trajectory. The rocket then starts to fall back down, accelerating due to gravity until it reaches the ground. If we take three equal intervals of time, we can show the rocket's positions at those times. Initially, the rocket will be moving upwards with a decreasing velocity, then it will reach its maximum height before falling back down with an increasing velocity.

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Answer: I believe it should be the final answer,

A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground

Explanation:

Answer:

Explanation:

The point P is influenced by two electric fields, that are from Q1 and Q2. Because Q1 is a positive point charge, the E-fields is going to the right and the E-fields from Q2 is going to the left because of negative point charge. So:

[tex]E_{1}=\frac{kQ_{1}}{R_{1}^{2}}[/tex]

[tex]E_{2}=\frac{kQ_{2}}{R_{2}^{2}}[/tex]

Where R1 = 2 + 3 = 5 m, and R2 = 3 m. With k = [tex]k=9\times 10^{9}[/tex] in [tex]Nm^{2}/C^{2}[/tex], we can obtain:

[tex]E_{1}=(9\times 10^{9})\frac{500\times10^{-6}}{25}=180\times 10^{3}[/tex] N/C (+)

[tex]E_{2}=(9\times 10^{9})\frac{100\times 10^{-6}}{9}=100\times 10^{3}[/tex] N/C (-)

So: the Electric Field at P : [tex]E_{P}=E_{1}-E_{2}=(180-100)\times 10^{3}=8\times 10^{4}[/tex] N/C in magnitude

Answer:

Explanation:

You can use [tex]Q = mc\Delta T=(550)(4.184)(28.8-12.7)=37049.32[/tex] joule.

Answer:

0.52     8.9  

Explanation:

calc.

The tension in the rope just before the student releases it is 576 N.

Tension is defined in physics as the pulling force transmitted axially by a string, rope, chain, or similar object.

Just before the student releases the rope, his velocity is zero. At this point, all of his kinetic energy has been converted into potential energy. Therefore, we can write:

1/2 m [tex]v^2[/tex] = mgh

h = [tex]v^2[/tex] / (2g) = [tex](6.2 m/s)^2[/tex] / (2 x 9.8 [tex]m/s^2[/tex]) ≈ 1.95 m

m g = 56 kg x 9.8 [tex]m/s^2[/tex] ≈ 549 N

The tension required to keep the rope taut is equal to the horizontal component of the force due to the weight of the student, which is:

T = m g / cos(θ)

tan(θ) = h / L

tan(θ) = 1.95 m / 10.0 m ≈ 0.195

θ ≈ 10.9°

So, T = m g / cos(θ) ≈ 576 N

To find the maximum tension in the rope during the swing, we can use conservation of angular momentum.

L = I ω

I = (1/3) m [tex]L^2[/tex]

I = (1/3) x 10.0 kg x [tex](10.0 m)^2[/tex] ≈ 3333.3 kg[tex]m^2[/tex]

The angular velocity of the rope just after the student releases it is:

ω = v / L

ω = 6.2 m/s / 10.0 m ≈ 0.62 rad/s

L = I ω ≈ 2070 N m s

Thus, the angular momentum of the system just after the student releases the rope is 2070 N m s.

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Answer: I would buy the thermometer with the most features because they all cost the same price so why not you getting more than what you are paying for than buying something the same but with less feature and things it can do for the same price.

Hope this helps :) If so brainliest would mean alot thanks!

Explanation:

Answer:

787.5m/s

Explanation:

Speed = wavelength x frequency

speed = 2.25m x 350 Hz

= 787.5m/s

number of protons

the atomic number of an atom is equal to the number of protons

According to a periodic table, Krypton was created during the fission of Uranium.

Atomic number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.

Thus, the fission of uranium is led by two elements with atomic numbers 56 and 36. According to a periodic table, those atomic numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.

According to a periodic table, Krypton was created during the fission of Uranium. [tex]\blacksquare[/tex]

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Answer:

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

Explanation:

Given:

Force between pair of charges= 900 newtons

The distance between the charges = 0.01 meters

Strength of Charge first q1 = 2e-10 Coulomb

To find:

Strength of Charge second q2 = ____ Coulomb?

Solution:

We know that,

Force between two charges separate by distance r is given by the equation,

[tex]|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb[/tex]

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

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Answer:

a water is heating up

Explanation:

the water's temperature is inceasing

Answer:

Explanation:

Answer: Sonic Boom.

When the object reaches the speed of sound, air cannot readily move out of the way and a shock wave is formed. When the object is moving faster than sound, the resulting sounds travel behind the object, creating a sonic boom.

Answer:

This is because the force of gravity is much less on the moon than on the earth, therefore the person wont be pulled down much and will jump higher

Answer: This is because the force of gravity is much less on the moon than on the earth, therefore the person won't be pulled down much and will jump higher.

Answer:

No

Explanation:

It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.

It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.

Answer:

Mass

Explanation:

In the core of the red giant, helium fuses into carbon. All stars evolve the same way up to the red giant phase. The amount of mass a star has determines which of the following life cycle paths it will take from there. The life cycle of a low mass star (left oval) and a high mass star (right oval).May 7, 2015

Based on research by Abraham Maslow, the meta-needs which are fulfilled by "making more money" are none of the meta-needs.

According to Abraham Maslow, meta-needs are human needs that relate to beauty, knowledge and creativity.

All of these can be met without having to make more money so it stands to reason that there are no meta-needs that can be met by making more money.

The main need that is met by making more money according to Maslow is Security and it is not a meta-need.

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Hi there!

A)

At this point, the pilot is experiencing a DOWNWARD NET centripetal force (ALWAYS points towards the center of the circle) as well as a downward force due to gravity. Additionally, we can say that the normal force exerted by the seat on the pilot is its apparent weight.

[tex]\Sigma F = F_g + F_N[/tex]

**The net force is the centripetal force.

We can assign both to be positive since they work in the same direction. (Assigning down as positive in THIS situation will make things easier).

We know that:
[tex]F_c = \frac{mv^2}{r}[/tex]

Fc = Centripetal force (N)
m = mass (kg)
v = velocity (m/s)

r = radius (m)

[tex]F_g = mg[/tex]

Fg = Force due to gravity (N)
m = mass (kg)
g = acceleration due to gravity (9.81 m/s²)

Solve for mass. (Given weight)

[tex]m = \frac{F_g}{g}\\\\m = \frac{719}{9.8} = 73.367 kg[/tex]
Now, we have everything we need to solve.

[tex]\frac{mv^2}{r} = F_g + F_N \\\\\frac{mv^2}{r} - F_g = F_N\\\\F_N = \frac{(73.367)(225^2)}{3110} - 719 = \boxed{475.278 N}[/tex]

B)
Weightlessness is achieved when the pilot is in free fall. In this instance, FN (Normal force by the seat) = 0 N.

We can use the same setup as above.

[tex]\frac{mv^2}{r} = F_g + 0 (F_N)[/tex]

[tex]\frac{mv^2}{r} = mg[/tex]

Solve for 'v'.

[tex]\frac{v^2}{r} = g\\\\v = \sqrt{gr} = \sqrt{(9.81)(3110)} = \boxed{174.669 \frac{m}{s}}[/tex]

C)
At the BOTTOM, we have the force of gravity working DOWNWARD (Negative in this instance), while the centripetal force (NET FORCE) and normal force are upward (Positive). Do another summation of forces:
[tex]\Sigma F = F_N - F_g\\\\\\frac{mv^2}{r} + F_g = F_N \\\\F_N = \frac{(73.367)(225^2)}{3110} + 719 = \boxed{1913.278 N}[/tex]

Answer:

it allows electric charges to travel through freely

a. The net force from t = 1 to t = 6 s is 112 N

b. The net force from t = 7 to t = 12 s is 0 N

Force is that thing which causes a change in motion of an object. The net force is given mathematically as F = ma where

This is the resultant sum of all the forces acting on an object. It is also given by F = ma where

The net force from t = 1 to t = 6 s is 112 N

From the table from time t = 1 to t = 6 s, the acceleration a = 1.4 m/s². Since m = 80 kg,

F = ma

= 80 kg × 1.4 m/s²

= 112 kgm/s²

= 112 N

So, the net force from t = 1 to t = 6 s is 112 N

The net force from t = 7 to t = 12 s is 0 N

From the table from t = 7 to t = 12 s, the acceleration a = 0 m/s²

Since m = 80 kg,

F = ma

= 80 kg × 0 m/s²

= 0 kgm/s²

= 0 N

So, the net force from t = 7 to t = 12 s is 0 N

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Answer:

150   kg-m/s

Explanation:

momentum = m * v

50 * 3 = 150

Answer:

(B)

Explanation:

Time = change of velocity ÷ acceleration

= (6-0) ÷ 5

= 1.2

1.2 s it take for an object accelerating at a constant rate of 5 m/s to change its velocity from 0 to 6 m/s.

Hence, the correct option is D.

To calculate the time it takes for an object to change its velocity from 0 to 6 m/s, we can use the formula:

time = change in velocity / acceleration

Given that the change in velocity (Δv) is 6 m/s and the acceleration (a) is 5 m/s², we can plug these values into the formula:

time = 6 m/s / 5 m/s²

time = 1.2 seconds

Therefore, 1.2 s it take for an object accelerating at a constant rate of 5 m/s to change its velocity from 0 to 6 m/s.

Hence, the correct option is D.

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Answer:

They eat Himalayan blue sheep, boar, deers, wild mountain goats, pikas etc.

Explanation:

The conscious mind contains all of the thoughts, memories, feelings, and wishes of which we are aware at any given moment. This is the aspect of our mental processing that we can think and talk about rationally. This also includes our memory, which is not always part of consciousness but can be retrieved easily and brought into awareness.

hope it helps...!!!

According to Sigmund Freud, memories that easily surface into everyday thought are a conscious part of the mind.

At any given time, the conscious mind contains all of our thoughts, memories, feelings, and wants.

This is the element of our brain functioning that we can reasonably think about and discuss. This includes our memories, which are not always conscious but can be readily recovered and brought into awareness.

Memories that easily emerge into everyday consciousness, according to Sigmund Freud, are a conscious element of the mind.

Hence, memories that easily surface into everyday thought are a conscious part of the mind.

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(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

ΔK.E = ΔP.E

¹/₂m(v²- u²) = mg(hi - hf)

¹/₂(v²- u²) = g(0 - hf)

v² - u² = -2ghf

v² = u² - 2ghf

where;

when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

v² = u² - 2ghf

where;

Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

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Answer:

125J

Explanation:

[tex]work \: = force \: \times distance \\ = 25 \times 5 \\ = 125joules[/tex]

If steam in a cylinder expands against a piston, exerting 10 atm of external pressure, the change in energy of the steam is mathematically given as

dE= -3010 kJ

Generally, the equation for the workdone  is mathematically given as

Work = - (pressure * Volume)

Therefore

w= - (10 x 10)

w= -100 L atm

In conclusion

dEnergy = q + work

dE = -3000 + -10.13

dE= -3010 kJ

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Answer:

when it has a fewer amount of electrons than protons

(1.a) The surface area being vibrated by the time the sound reaches the listener is 5,026.55 m².

(1.b) The intensity of the sound wave as it reaches the person listening is 0.02 W/m².

(1.c) The relative intensity of the sound as heard by the listener is 103 dB.

(2.a) The speed of sound if the air temperature is 15⁰C is 340.3 m/s.

(2.b) The frequency of the sound heard by the suspect is 614.3 Hz.

The surface area being vibrated by the time the sound reaches the listener is calculated as follows;

A = 4πr²

A = 4π x (20)²

A = 5,026.55 m²

The intensity of the sound is calculated as follows;

I = P/A

I = (100) / (5,026.55)

I = 0.02 W/m²

[tex]B = 10log(\frac{I}{I_0} )\\\\B = 10 \times log(\frac{0.02}{10^{-12}} )\\\\B = 103 \ dB[/tex]

[tex]v= 331.3\sqrt{1 + \frac{T}{273} } \\\\v = 331.3\sqrt{1 + \frac{15}{273} } \\\\v = 340.3 \ m/s[/tex]

The frequency of the sound heard is determined by applying Doppler effect.

[tex]f_o = f_s(\frac{v \pm v_0}{v \pm v_s} )[/tex]

where;

[tex]f_0 = f_s(\frac{v-v_0}{v- v_s} )[/tex]

[tex]f_0 = 512(\frac{340.3 - 10}{340.3 - 65} )\\\\f_0 = 614.3 \ Hz[/tex]

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