Complete Question
A 6.00-µc charge is moving with a speed of 7.50x10^4 m/s parallel to a very long, straight wire. the wire is 5.20 cm from the charge and carries a current of 68.5 A in a direction opposite to that of the moving charge. Calculate the magnitude of the force on the charge.
Answer:
The value is [tex]F =1.20 *10^{-4} \ N[/tex]
Explanation:
From the question we are told that
The magnitude of the charge is [tex]Q = 6.00\muC = 6.00 *10^{-6} \ C[/tex]
The speed is [tex]v = 7.50 *10^{4} \ m/s[/tex]
The distance of the wire from the charge is [tex]d = 5.20 \ cm = 0.0520 \ m[/tex]
The current flowing through the wire in the opposite direction to the charge is [tex]I _2 = 68.5 \ A[/tex]
Gnerally the magnitude of force on that charge is mathematically represented as
[tex]F = qvB[/tex]
Here B is magnetic field which is mathematically represented as
[tex]B = \frac{\mu_o * I}{2\pi d}[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
So
[tex]F = qv[\frac{\mu_o * I}{2\pi d}][/tex]
=> [tex]F = 6.0*10^{-6} * (7.50 *10^{4})[\frac{4\pi * 10^{-7} * 68.5 }{2* 3.142 * 0.0520 }][/tex]
=> [tex]F =1.20 *10^{-4} \ N[/tex]
Two cars are traveling on a desert road between three consecutive poles, as shown in the
figure. After 5.1 s, they are side by side at the
next telephone pole. The distance between
the poles is 72.7 m.
1-Find the displacement of Car A after 5.1 s.(answer in units of m.)
2-Find the average velocity of Car A during 5.1
s. (answer in units of m/s.)
Answer:
SUGGGA
Explanation:
A race car driver travelling at 15m*s^-1 accelerates at a constant value for 10.0s. She is now driving at a speed of 35 m*s^-1 What was her acceleration? Give your answer in m*s^-2 to one significant figure . Do not include units with your answer.
The driver speeds up with acceleration a so that
35 m/s = 15 m/s + a (10.0 s)
Solve for a :
20 m/s = a (10.0 s)
a = (20 m/s) / (10.0 s)
a = 2 m/s²
If I kick a ball off the top of a mountain cliff, will it take longer to hit the ground than if I just drop it? Explain your answer. Your answer:
Answer:
they will drop at the same time
Explanation:
projectile motion consists of two components, horizontal and vertical, which are independent of one another. That means that if you drop a ball and kick another one straight out, they will both hit the ground at the same time so long as they have the same initial drop height .
Perception of color is determined by the wavelength of light that an object reflects
Please select the best answer from the choices provided
T
Or
F
Answer:
True
Explanation:
hope I could help :)
Answer:
true
Explanation:
i know my stuff
4. State in words how acceleration is calculated.
Acceleration can be calculated by dividing the change in velocity by the change in time. If we have a mass and force that makes the acceleration, the divide the force by mass to get the acceleration.
What is acceleration ?Acceleration is a physical quantity which describes the rate of change in velocity. Like velocity, acceleration is a vector quantity having both magnitude and direction.
If both speed and direction are changing and if we want to know the acceleration at any particular moment in time, calculating acceleration can be challenging.
However, since just speed is changing, it is quite simple to determine average acceleration over time. After then, acceleration is equal to the time change divided by the velocity change.
a = ΔV/Δt
Similarly if have the force which accelerates a body of mass m, then the acceleration is the ratio of that force to the mass.
a = F/m
Find more on acceleration:
http://brainly.com/question/2303856
#SPJ2
After a wave passes through a medium, particles in the medium
are permanently displaced in a direction opposite to the direction of the wave
remain in the new location
are moved along with the wave
return to the original position
Answer:
D. Return to the original position
Explanation:
I took the test
When there are equal forces from opposite directions acting on an object, the forces are said to be which of the following? (4 points)
A.Positive
B.Negative
C.Balanced
D.Gravitational
Answer: C. Balanced
Explanation:
I took the test and got it right.
A planned high-speed train between Houston and Dallas will travel a distance of 386 kilometers in 5.40 × 103 seconds. What is the average speed of this train?
Type of tissue that helps with movement.Immersive Reader
a. Epithelial
b.Muscle
c.Connective
d.Nervous
Consider two current-carrying circular loops. Both are made from one strand of wire and both carry the same current, but one has twice the radius of the other. If the magnetic field strength at the center of the smaller loop is B, what is the magnetic field strength at the center of the larger loop
Explanation:
The magnetic field at the center of a current-carrying circular loop is given by :
[tex]B=\dfrac{\mu_o I}{2r}[/tex]
Where, I is current and r is radius of loop
We have, two current-carrying circular loops. Both are made from one strand of wire and both carry the same current, but one has twice the radius of the other.
For smaller loop, the magnetic field is B (with radius r)
For larger loop, let the magnetic field be B' (with radius r', r'=2r). So,
[tex]B'=\dfrac{\mu_o I}{2r'}\\\\B'=\dfrac{\mu_o I}{2(2r)}\\\\B'=\dfrac{1}{2}\times \dfrac{\mu_o I}{2r}\\\\B'=\dfrac{1}{2}B[/tex]
Hence, the magnetic field strength at the center of the larger loop is half of the magnetic field strength at the center of the smaller loop.
A force of 50n is applied to an object at an angle of 50 degrees measured relative to the horizontal. Determine the horizontal and vertical components of the applied force?
Answer:
Fx = 32.14 [N]
Fy = 38.3 [N]
Explanation:
To solve this problem we must decompose the force vector, for this we will use the angle of 50 degrees measured from the horizontal component.
F = 50 [N]
Fx = 50*cos(50) = 32.14 [N]
Fy = 50*sin(50) = 38.3 [N]
We can verify this result using the Pythagorean theorem.
[tex]F = \sqrt{(32.14)^{2}+ (38.3)^{2}} \\F = 50 [N][/tex]
I will give you branilest!
Answer:
easy thats
13
Explanation:
A cows mass is 401 kg and a trucks mass is 832 kg. What is the difference between their weights . Answer please!!!
Answer:
403 kg is the diffrence
Please help me if you know physics
Answer:
19. down
20. True
Explanation:
The examples I saw were projectiles launched at different angles and speeds. In each case, the only acceleration was ...
19: down
20: due to gravity (true)
The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2. 4 6 8 10 Column 2 5 10 15 20 25 30 O Column 1 should be titled "Time," and Column 2 should be titled "Velocity." O Column 1 should be titled "Velocity," and Column 2 should be titled "Time." O Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."
Answer:
Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”
Explanation:
Organ system that is responsible for breaking down food
a.Digestive
b.Respiratory
c.Circulatory
d.Nervous
Answer:
A. Digestive
Explanation:
Answer:
digestive system
Explanation:
since the digestive system secretes enzymes like amylase,lipase etc. required by the body for the proper breakdown of food.
10. The electron dot diagram for the element Ne would have
Answer:
2,8
Explanation:
The first electron shell would have 2 electrons, the second shell would have 8 electrons. This is because Neon has a relative charge of 10.
If a pair of shoes weighs 0.3 N on Pluto what is the strength of gravity on Pluto
Answer:
0.6 m/s 2
Explanation:
please answer please please
Physics
Answer:
about -1.26 m/s²
Explanation:
The acceleration can be found from the formula ...
a = (v2² -v1²)/(2d)
Here, we have the initial velocity v1=23 m/s, the final velocity v2=0, and teh distance d=210 m. Using the formula, we find the acceleration to be ...
a = (0 -23²)/2(210) ≈ -1.2595 . . . m/s²
Helpppp guys plsss help !
Answer:
with what? I can help but with what
Answer:
2
Explanation:
Select the correct answer from each drop-down menu.
Rocky metallic objects found between the orbits of Mars and Jupiter are(drop down). The largest known of these is(drop down).
Answer:
Blank 1 (asteroids)
Blank 2 (Ceres)
Explanation:
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
What are asteroids?Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]
A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
The correct option from the drop-down menu is asteroids and ceres.
To learn more about the asteroids refer to the link;
https://brainly.com/question/19161842
One statement of the first law of thermodynamics is that:___________.
a. the amount of work done on a system is dependent of pathway.
b. the total work done on a system must equal the heat absorbed by the system.
c. the heat flow in or out of a system is independent of pathway.
d. the total energy flow in or out of a system is equal to the sum of the heat transferred to or from the system and the work done by or on the system.
e. in any chemical process the heat flow must equal the change in enthalpy.
Answer:
a. the amount of work done on a system is dependent of pathway
Explanation:
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.
ΔU = Q - W
Where;
Q, the net heat transfer into the system depends on the pathway
W, the net work done by the system also depends on the pathway
But, ΔU, the change in internal energy is independent of pathway
Therefore, the correct option is "A"
a. the amount of work done on a system is dependent of pathway
A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen when the spectacles hit the ground? Neglect the air resistance.
Answer:
[tex]h_p = 30.46\ m[/tex]
Explanation:
Free Fall Motion
A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.
The speed vf of the object when a time t has passed is given by:
[tex]v_f=g\cdot t[/tex]
Where [tex]g = 9.8 m/s^2[/tex]
Similarly, the distance y the object has traveled is calculated as follows:
[tex]\displaystyle y=\frac{g\cdot t^2}{2}[/tex]
If we know the height h from which the object was dropped, we can solve the above equation for t:
[tex]\displaystyle t=\sqrt{\frac{2\cdot y}{g}}[/tex]
The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:
[tex]\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec[/tex]
The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:
[tex]t_2=2.56 - 2 = 0.56\ sec[/tex]
Therefore, it has traveled down a distance:
[tex]\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m[/tex]
Thus, the height of the pen is:
[tex]h_p = 32 - 1.54\Rightarrow h_p=30.46\ m[/tex]
The pen is 30.52 m above the ground.
Given that the height of the stadium is h = 32m
The initial velocity of the glasses will be 0.
[tex]h=\frac{1}{2}gt^{2} \\t=\sqrt{\frac{2h}{g} } \\t=\sqrt{\frac{2*32}{9.8} }\\t=2.55s[/tex]is the time taken for the glasses to hit the ground.
Now the pen is released 2 seconds later. So by the time the glasses hit the ground the pen has spent:
[tex]t^{'}=2.55-2\\t^{'}=0.55s[/tex]in the air
distance traveled by the pen:
[tex]d=\frac{1}{2}gt^{2}\\\\d=\frac{1}{2}*9.8*0.55*0.55\\\\d=1.48m[/tex]
So the pen is [tex]h-d=32-1.48=30.52m[/tex] above the ground.
Learn More:
https://brainly.com/question/24018491
Question 5 of 10
Two hockey pucks, each with a mass of 0.15 kg, slide across the ice and
collide. Before the collision, puck 1 is moving 14 m/s to the west and puck 2
is moving 10 m/s to the east. After the collision, puck 1 is moving at 10 m/s
to the east. What is the velocity of puck 2?
A. 14 m/s east
B. 10 m/s west
C. 10 m/s east
D. 14 m/s west
Answer: D. 14 m/s west
Explanation:
I just did it on A p e x
electromagnetic waves and sound waves can have the same frequency. what is the wavelength of a 1.00kHz electromagnetic wave
Consider the following debate between two students about their answer to the above question.
Student 1: I thought that whenever one object exerts a force on a second object, the second object also exerts a force that is equal in strength, but in the other direction. So even though Earth is bigger and more massive than the Moon, they still pull on each other with a gravitational force of the same strength, just in different directions.
Student 2: I disagree. I said that Earth exerts the stronger force because it is way bigger than the Moon. Because its mass is bigger, the gravitational force Earth exerts has to be bigger too. I think you are confusing Newton's third law with the law of gravity. Do you agree or disagree with either or both of the students?
Answer:
I agree with student 1
Explanation:
This is because, the magnitude of the gravitational force on both Earth and Moon depends on the product of their masses. Also, both Earth and Moon exert the same force but in opposite directions.
Student 2 is wrong because the gravitational force is the only force acting between the Earth and Moon, and from Newton's third law, it follows an action-reaction pair. But, student 2 got it wrong in the sense that the magnitude of the action and reaction forces are the same and are equal to the gravitational force.
So, the gravitational force acting on each object is the same and doesn't vary for each mass.
We should agree with the student 1.
Gravitational force:
This is to be done due to the magnitude of the force since earth and moon should be based on the masses' product. Moreover, the earth and moon exert a similar force but that should be in inverse directions. Here student 2 should be wrong because the gravitational force is that force that acted between the earth and moon. Based on this, we can say that it should be acted on each object when it is the same also it should not be changed for every mass.
Learn more about newton here: https://brainly.com/question/14379797
Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands, two seconds after being kicked, about 20 m away to the north. Assume that air resistance is negligible, and plot the horizontal and vertical components of the ball's velocity as a function of time. Consider only the time that the ball is in the air, after being kicked but before landing. Take "north" and "up" as the positive x ‑ and y ‑directions, respectively, and use g≈10 m/s2 for the downward acceleration due to gravity.
Answer:
v_y = 10 - 10t
v_x = 10 m/s
Explanation:
This is a projectile launch where the x axis and y axis will be treated independently.
Now, towards the north on the x-axis, there will be no acceleration and so the speed is constant
So, vₓ = v₀ₓ
Whereas, on the vertical y - axis, the acceleration due to gravity with be negative since it's in a downward direction.
Thus, the equation is;
v_y = v_oy - gt
Now, the initial velocity component will be;
cos 45 = v₀ₓ/v₀
And sin 45 = v_₀y/v₀
Thus, we have;
v₀ₓ = v₀(cos 45)
Also, v_oy = v₀(sin 45)
Now, the initial velocity would be gotten from the equation of range which is;
R = (v₀² × sin 2θ)/g
Making v₀ the subject, we have;
v₀ = √(Rg/sin 2θ)
We are given;
R = 20 m
g = 10 m/s²
θ = 45°
Thus;
v₀ = √[20 × 10/(sin (2 × 45))]
v₀ = √200
v₀ = 14.14 m/s
Thus;
v₀ₓ = 14.14(cos 45) = 10 m/s
v_oy = 14.14(sin 45) = 10 m/s
Earlier we saw that;
v_y = v_oy - gt
Thus;
v_y = 10 - 10t
Also,we saw that;
vₓ = v₀ₓ
Thus;
v_x = 10 m/s
For the graph, we will use times of t = 0, 0.2, 0.4, 0.6, 0.8, 1.0, 1.2
Thus, for each of those values of t, we will have the following values of v_oy
t (s) v_oy (m / s)
0 10
0.2 8
0.4 6
0.6 4
0.8 2
1.0 0
1.2 -2
Graph is attached
A boy and a girl are pulling a heavy crate at the same time with 7 units of firce each. What is the net force acts on the ibject? Is the object balanced or unbalanced?
Answer:
Net force= 14 units
The object is unbalanced
Explanation:
The net force refers to the sum of all forces applied to an object. However, the direction of force applied determine the net force. In this question, a boy and girl is pulling a heavy crate at the same time.
This means that the force is in the same direction, hence, the net force will be:
F(N) = 7 + 7 = 14 unit
However, since the pull is occuring at the same direction. This means that the object has a net force, therefore, will move in a particular direction. This means that the OBJECT IS UNBALANCED
The Newton unit obtained from
A)Kg.m/s2
B) Kg. m
C) kg/m
D) kg ml
Answer:
Explanation:
The Newtons unit is kg. m/s2
Option A is the correct answer
MULTIPLE CHOICE QUESTION
What is the acceleration of the object?
(Remember a = Fnet/m and acceleration needs a
direction)
8 m/s/s
0.125 m/s/s to the right
8 m/s/s to the left
8 m/s/s to the right
Which object? More information is needed to answer this question