This is a parallelogram. 5 mi. 6 mi. 9 mi.What is the area of the parallelogram?
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We have the following parallelogram.:
We have that the height of the paralellogram is 5 cm and the base is 9cm, then the area is:
[tex]\begin{gathered} A=b\cdot h \\ \Rightarrow A=9\cdot5=45 \\ A=45\operatorname{cm}^2 \end{gathered}[/tex]therefore, the area of the parallellogram is 45 cm²
Related Questions
Solve for x143x = 46
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You have the following equation:
14 - 3x = 46 - x
In order to solvet the previous equation for x, you proceed as follow:
14 - 3x = 46 - x subtract 14 and sum x both sides
-3x + x = 46 - 14 simplify similar terms
-2x = 32 divide by -2 both sides
x = 32/(-2) = -16
x = -16
Hence, the solution of the given equation is x = -16
Solve for x:1/2(2-4x)+2x=13
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Answer:
Explanation:
Given the equation:
[tex]\frac{1}{2}\mleft(2-4x\mright)+2x=13[/tex]First, we open the bracket:
[tex]\frac{1}{2}(2)-\frac{1}{2}(4x)+2x=13[/tex]Can someone help me with these geometry questions it’s a three parter?The options for A are cone,cylinder,rectangular prism, and sphere
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Part A.
In the picture, we can see that it has a circular base and from it it goes right with the same shape for each section, so this is a prism. Since its base is a circle, this is close to a cylinder.
Part B.
The diameter of the base and the length is shown, so we just need to draw a cylinder and put these measures:
The net of a cylinder has the two circles of the base and the middle part is unfolded to form a rectangle:
Part C.
The amount of plastic they will need corresponds to the surface area of the cylinder, and the net draw unfold the shape into a 2 dimensional draw, so we can use it to determine the surface area of the cylinder, which will lead us to the amount of plastic needed.
Find y' if y=2x^6-5x^5+3/x^4
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Given the function:
[tex]y=\frac{2x^6-5x^5+3}{x^4}[/tex]We can write the given function as follows:
[tex]\begin{gathered} y=(2x^6-5x^5+3)\cdot x^{-4} \\ y=2x^2-5x+3x^{-4} \end{gathered}[/tex]So, y' will be as follows:
[tex]\begin{gathered} y^{\prime}=2\cdot2x-5\cdot1+3\cdot(-4x^{-5}) \\ \\ y^{\prime}=4x-5-\frac{12}{x^5} \end{gathered}[/tex]So, the answer will be: y' = 4x - 5 -12/x^5
i hate doin algebra homework i’m too smart i know it all
Answers
Answer
[tex]\begin{gathered} Given\text{ }\frac{x}{3}+x^2-2\text{ }when\text{ }x=9 \\ \frac{9}{3}+9^2-2=3+81-2=82 \end{gathered}[/tex]Therefore the answer is 82.
What is 0 if 0degrees is less than or equal to 0 less than 360 degrees
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Solution
On a unit circle,
Since it's a unit circle, the radius is 1.
[tex]\begin{gathered} \sin\theta=\frac{\sqrt{2}}{2} \\ \\ \Rightarrow\theta=\arcsin(\frac{\sqrt{2}}{2})=45^0 \end{gathered}[/tex]Hence, the correct option is C. 45
Andy rode his bike 2 4/5 miles on monday. tuesday 1 3/10 miles. how many total miles did andy ride on the 2 days?
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The problem is asking us to add two mixed numbers in order to calculate the number of miles ridden.
So in order to be able to add them, we need to convert them in fraction form and afterwards find a common denominator to add them.
The mixed number: 2 4/5 is the same as 10/5 + 4/5 = 14/5
The mixed number 1 3/10 = 10/10 + 3/10 = 13/10
Noe, we need to add them:
14/5 + 13/10, and we notice that the Least Common Denominator for these two fractions is: "10". So we write the first one with denominator 10 by multiplying numerator and denominator by "2":
14/5 + 13/10 = 28/10 + 13/10 = 41/10
Now, we write this improper fraction in mixed number form:
41/10 = 40/10 + 1/10 = 4 1/10
So the person rode a total of 4 1/10 miles
Use the tables to name the zeros,their multiplicity,and the effect of the multiplicity on the graph. (In the effect boxes it should be either bounces or intersects) SPELL PROPERLY
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We have
[tex]x^2(x-1)^4(x+5)[/tex]First we will find the zeros,
for the term x^2
[tex]x^2=0[/tex][tex]x=0[/tex]for the term (x-1)^4
[tex](x-1)^4=0[/tex][tex]x-1=0[/tex][tex]x=1[/tex]for the terms (x+5)
[tex]x+5=0[/tex][tex]x=-5[/tex]zeros
x=-5
x=0
x=1
Then with the multiplicity
Because we have a power of 1 in (x+5), x=-5 has a multiplicity of 1
Because we have a power of two in x^2, x=0 has multiplicity 2
Because we have a power of 4 in (x-1)^4, x=1 has a multiplicity of 4
For the effect
x+5 has an odd power the effect will be crosses
x^2 has an even power the effect will be bounces
(x-1)^4 has an even power the effect will be bounces
, x
Can u please help me. I'll send the other options to u as well
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Explanation
We are told to fi
Simplify each of the fractions. If there is no answer, enter "undefined."A. 4/12
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Answer:
undefined
Step-by-step explanation:
Describe all numbers x that are at a distance of 14 from the number −5. Express this using absolute value notation.
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The distance (d) between two numbers a and b equals the absolute value of their difference:
[tex]d=|a-b|[/tex]If a number x is at a distance of 1/4 from the number -5, then:
[tex]|x-(-5)|=\frac{1}{4}[/tex]Solve for x. Remember that when an equation involves a variable inside an absolute value, two cases must be considered: If the expression inside the absolute value is positive or if it is negative.
Case 1: x-(-5) is positive.
Then:
[tex]|x-(-5)|=x-(-5)[/tex]Solve for x:
[tex]\begin{gathered} |x-(-5)|=\frac{1}{4} \\ \Rightarrow x-(-5)=\frac{1}{4} \\ \Rightarrow x+5=\frac{1}{4} \\ \Rightarrow x=\frac{1}{4}-5 \\ \therefore x=-\frac{19}{4} \end{gathered}[/tex]Case 2: x-(-5) is negative.
Then:
[tex]|x-(-5)|=-(x-(-5))[/tex]Solve for x:
[tex]\begin{gathered} |x-(-5)|=\frac{1}{4} \\ \Rightarrow-(x-(-5))=\frac{1}{4} \\ \Rightarrow-(x+5)=\frac{1}{4} \\ \Rightarrow x+5=-\frac{1}{4} \\ \Rightarrow x=-\frac{1}{4}-5 \\ \therefore x=-\frac{21}{4} \end{gathered}[/tex]Therefore, all the numbers that are at a distance of 1/4 from the number -5 are -21/4 and 19/4. They can be described by the equation:
[tex]|x-(-5)|=\frac{1}{4}[/tex]
I need to convert the following equation Demonstrating the identity Property of Multiplication
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The identity property of multiplication simply states that a number equals itself when multiplied by 1.
So:
[tex]7y\cdot1=7y[/tex]15x + 21 ≥ 120 what's the inequality
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Given the inequality:
[tex]\text{ 15x + 21 }\ge\text{ 120}[/tex]Let's determine the solution to the inequality.
This graph shows two line segments whose endpoints are pairs of complex numbers. What are these two pairs? What complex number is common to both lines?
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Problem Statement
The question gives us a graph of two lines and we are told that the lines have endpoints thta represent complex numbers. We are asked to find:
1. The pairs of complex numbers.
2. The complex number common to both lines.
Method
- To solve the question, we must first understand what the graph describes. The graph is NOT an ordinary real-line graph but rather a complex number graph showing the imaginary part on the y-axis and the real part on the x-axis.
- This means that the coordinate of the points on the graph is a coordinate of real and imaginary part. For example:
[tex]undefined[/tex]What is the equation of a line that passes through the point (1, -10) and is perpendicular to the equation y
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The equation of a line in the slope intercept form is expressed as
y = mx + c
Where
m represents slope
c represents y intercept
The given equation is expressed as
y = - x/3 + 5
By comparing with the slope intercept equation,
slope, m = - 1/3
If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line. The negative reciprocal of - 1/3 is 3. Thus, the slope of the line passing through the point, (1, - 10) is 3
We would determine the y intercept, c by substituting x = 1, y = - 10 and m = 3 into the slope intercept equation. It becomes
- 10 = 3 * 1 + c
- 10 = 3 + c
c = - 10 - 3
c = - 13
We would substitute m = 3 and c = - 13 into the slope intercept equation. Thus, the equation of the line is
y = 3x - 13
Option D is correct
during one day in a hardware store, 37 people came in and made a purchase, and 13 people looked around but didnt purchase anything. Express the following ratios
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In the day the number of purchasers was 37 and the number of nonpurcharses is 13
To determine the purchasers/nonpurchasers you have to divide the number of people that purchased something by the number of people that only browsed the store
[tex]\frac{37}{13}[/tex]The nonpurchasers to purcharsers ratio follows the same logic, divide the number of people that didn't buy something by the number of people that made purchases
[tex]\frac{13}{37}[/tex]The total customers of the store is
[tex]37+13=50[/tex]The ratio purchasers to total customers ratio is
[tex]\frac{37}{50}[/tex]In how many ways can 6 photos be arrangedon a wall?
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Solution
We can use the multiplication principle and we have:
6!= 6*5*4*3*2*!= 720 ways
Luigi uses 39 cups of flour for every 6 pizzas he makes. Complete the table using equivalent ratios. Flour (cups) Pizzas 39 6 I Mla 13
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Given:
39 cups of floor = 6 pizzas
Let's find the number of cups of floor for 1 pizza:
[tex]\frac{39}{6}=6.5\text{ cups}[/tex]Therefore, to make 1 pizza, 6.5 cups of floor is needed.
From the table, we have:
4 pizzas = 6.5 x 4 = 26 cups of floor
13 cups of floor =
[tex]\frac{13}{6.5}=2[/tex]ANSWER:
Floor(cups) Pizzas
39 6
26 4
13 2
the cost C in dollars sign of producing X items in the equation C equals x over 7 plus 1 which of the following choices will find the cost C if x is 35
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Writing the equation described, we have:
[tex]C=\frac{x}{7}+1[/tex]Now, calculating the value of the cost C for x equal to 35, we have:
[tex]\begin{gathered} C=\frac{35}{7}+1 \\ C=5+1 \\ C=6 \end{gathered}[/tex]So the cost C for 35 products is $6.
what is the volume in cubic inches of a cylinder with a height of 20 inches and a base radius of 2in to the nearest tenths place
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1) We've been told that this is a cylinder. So we can find out its volume by making use of this formula below:
[tex]V_{\text{cylinder}}=\pi\cdot r^2\cdot h[/tex]2) So let's plug into that the given information:
[tex]\begin{gathered} V_{\text{cylinder}}=\pi\cdot r^2\cdot h \\ V_{\text{cylinder}}=\pi\cdot(2)^2\cdot20 \\ V_{\text{cylinder}}=80\pi in^3 \\ V_{\text{cylinder}}\approx251.3in^3 \end{gathered}[/tex]3) Hence, the volume of that cylinder rounded off to the nearest tenth is 251.3 in³
May I please get help with this. I have tried multiple times but still could not get the correct answers. I would appreciate it so much if I could get help
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To answer this question we need to remember some properties for any parallelogram:
• Two pairs of opposite sides are equal in length.
,• Two pairs of opposite angles are equal in measure.
,• The diagonals bisect each other.
We notice that in the figure QSRP opposite sides are equal in length then we conclude that this is a parallelogram.
In figure RSUT we notice that the diagonals bisect each otherm then we conclude that this is a parallelogram.
In figure KLNM we notice that none of the properties stated before are fullfill, then this is not necesarrily a parallelogram.
In figure BDCA we notice that alternate interior angles are equal, this means that segments BD and CA are parallel, we also notice that the other segments are parallel; therefore this is a parallelogram.
Which table shows a constant rate of change of $3.25? *Which table shows a constant rate of change of $3.25?Cost of Ham Sandwiches13 5 73.25 10.50 16 22.25Cost of Ham Sandwiches1 3 5 73.25 9.75 16.25 22.75HhСhСF3GCost of Ham Sandwiches1 3 S 73.25 9.50 16.25 22.50Cost of Ham Sandwiches1 3 5 73.25 9.75 15.25 21.75hсhc С
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The costant rate of change can be expressed as,
[tex]R=\frac{\Delta C}{\Delta h}[/tex]Consider table H.
The constant rate of change can be calculated as,
[tex]\begin{gathered} R=\frac{\Delta C}{\Delta h}=\frac{9.75-3.25}{3-1}=3.25 \\ R=\frac{\Delta C}{\Delta h}=\frac{16.25-9.75}{5-3}=3.25 \\ R=\frac{\Delta C}{\Delta h}=\frac{22.75-16.25}{7-5}=3.25 \end{gathered}[/tex]Therefore, table H shows a constant rate of change of $3.25.
just so you know you can use half numbers for example 46.5 or 24.5 etc.
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Given:
[tex]61,63,63,64,67,67,69,72,73,74,75,79,81,85,86,87,89,92[/tex]To draw:
The box and whisker plot.
Explanation:
According to the given data,
The minimum of the data is 61.
The maximum of the data is 92.
Since the total number of data is n = 18 which is even.
So, the median formula is given by,
[tex]\begin{gathered} Q_2=\frac{(\frac{n}{2})^{th}term+(\frac{n}{2}+1)^{th}term}{2} \\ =\frac{(\frac{18}{2}){^{th}term+(\frac{18}{2}+1)^{th}term}}{2} \\ =\frac{9^{th}term+10^{th}term}{2} \\ =\frac{73+74}{2} \\ =\frac{147}{2} \\ Q_2=73.5 \end{gathered}[/tex]Therefore, the median is 73.5.
Then, the lower quartile is the median of the lower half of the data.
The lower half data are,
[tex]\begin{equation*} 61,63,63,64,67,67,69,72,73 \end{equation*}[/tex]The middle term is 67.
Therefore, the lower quartile is 67.
The upper quartile is the median of the upper half of the data.
The upper half data are,
[tex]\begin{equation*} 74,75,79,81,85,86,87,89,92 \end{equation*}[/tex]The middle term is 85.
Therefore, the upper quartile is 85.
So, the box and whisker plot is,
Consinder this set of expressions.3 -4. -2 + -3. -5 - 4part a: Simplfy each expression.A: 3 =B: -4 =C: -2 + -3 =D: -5 - -4=part b: graph each value on the number line. label the points.
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The absolute value of a negative number is the positive of that same number. Therefore,
Part A
[tex]\lvert3\rvert=3[/tex][tex]-\lvert4\rvert=-4[/tex][tex]\lvert-2\rvert+\lvert-3\rvert=2+3=5[/tex][tex]\lvert-5\rvert-\lvert4\rvert=5-4=1[/tex]part B
Compare: 0.008 O 0.08A.>B.
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We have the next two numbers
[tex]0.008\text{ and }0.08[/tex]To compare two decimal numbers we need to know that the smaller number will be
1. The one with the smallest integer
2. If the numbers have the same integer part, the one with the smallest decimal part.
In this case, the numbers have the same integer part, so we must compare their decimal parts.
To compare the decimal parts we need to take the numbers after the decimal point
[tex]008\text{ and }08[/tex]Then, We must add 0 to the right of the number with the least amount of digits until the 2 numbers have the same amount
So, we would have
[tex]008\text{ and }080[/tex]Now, we can see that 8 < 80. Then,
[tex]0.008<0.08[/tex]ANSWER:
B) <
Find the value of the variable,3m + 5 4m - 10A )-5B) - 3/4C)0D)15
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A to B is same distance as B to C
We can thus say:
AB = BC
AB is 3m + 5
BC is 4m - 10
So,
AB = BC
3m + 5 = 4m - 10
Now, we simply do algebra and solve this equation for m. Shown below:
[tex]undefined[/tex]which equation represents a circle with a center located at ( -2, 2) and a circumference of 16 pi?
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Explanation:
The equation of a circle with center located at (x1, y1) and radius r is:
[tex](x-x_1)^2+(y-y_1)^2=r^2[/tex]We have the point but we need to find r. For that we can use the equation of the circumference:
[tex]C=2\pi r[/tex]We have C = 16pi:
[tex]\begin{gathered} 16\pi=2\pi r \\ \frac{16\pi}{2\pi}=r \\ r=8 \end{gathered}[/tex]Now we have r = 8, therefore r²=64. The answers could be either option 1 or option 3. To find out which one is it we have to check the point.
If the point is (-2, -2) then the part with x is (x - (-2))² = (x+2)² and the part with y is (y - 2)²
Answer:
The correct equation is option 3:
[tex](x+2)^2+(y-2)^2=64[/tex]hi can you help please, I have to turn this in soon
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The sum of the interior angles of a triangle is 180. Besides, the angle that is missing is suplementary (sums 180) to 153. So we have the next equation
[tex]\begin{gathered} (x-4)+(2x+10)+(180-153)=180 \\ x+2x=180+4-10-180+153 \\ 3x=147 \\ x=49 \end{gathered}[/tex]A pie recipe calls for 2/3 Cup of sugar to make a pie. How many cups will be needed to make five pies? Round your answer to the nearest hundredth.
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To find the number of cups of sugar which will make five pies, we proceed as follows:
[tex]\begin{gathered} \sin ce\colon \\ \frac{2}{3}\text{cups}\Rightarrow\text{ 1 pie} \\ m\text{ ultiply both sides of the equivalence by 5, since we want to make 5 pies} \\ 5\times\frac{2}{3}cups=\text{>5}\times1p\text{ie} \\ \frac{10}{3}\text{cups}\Rightarrow5p\text{ies} \\ 3.33\text{cups}=>5p\text{ies} \end{gathered}[/tex]Therefore, to the nearest hundredth, we will be needing 3.33 cups of sugar in order to make 5 pies.
Which of the following statements says that a number is between -3 and 3?Olx = 3Olx <3Olx > 3
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If |x|=3, then x can either be 3 or -3.
If |x| < 3, then x < 3 or -x < 3. Multiplying -1 on both sides of the second inequality, we have the following.
[tex]\begin{gathered} x<3 \\ \\ x>-3 \end{gathered}[/tex]This mea