this is a test a b c d e f g h i j k l m n o p

Answer:

heat and power

Explanation:

is the simultaneous production of electricity and heat both of which are used

Answer:

A

Explanation:

Explanation:

A weather front is a boundary separating air masses of several characteristics eg. Air density, wind and humidity. Disturbed weather often arises from these differences

Answer: suppressed; chemotherapy

Explanation:

Chemotherapy is typically a drug treatment whereby powerful chemicals are used to kill the fast growing cells in ones body. Chemotherapy is usually used in the treatments of cancer.

Research revealed that patients who received chemotherapy in a hospital setting subsequently experienced

a (suppressed) immune response when they again visited the hospital. In this example, the (chemotherapy) would be classified as the US.

Answer:

The answer to this is C) 100N

When borosilicate glass is undergoing change in temperature, heat is transferred.  The specific heat of borosilicate glass is 837.4 J/kg. °C

The specific heat is the amount of heat stored per kilogram of substance by 1 degree rise in temperature.

Given is the mass of borosilicate glass m =100 g =0.1 kg, heat transferred Q = 309J, temperature change ΔT = 3.69°C

Q = m x Cp x  ΔT

309 = 0.1 x Cp x 3.69

Cp = 837.4 J/kg. °C

Thus, the specific heat of borosilicate glass is 837.4 J/kg. °C

Learn more about specific heat.

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Answer:

The angle of incidence is the angle formed by the incident ray and the perpendicular to the surface. Together, the angle of incidence and the angle the incident ray makes with the surface form a right angle (90 degrees). The angle of incidence is therefore given by the following expression:

Angle of incidence = 90 degrees - angle ray makes with the surface

In your example

Angle of incidence = 90 degrees - 40 degrees = 50 degrees

The law of reflection states that the angle of incidence equals the angle of reflection, which is also measured with respect to the perpendicular to the surface, so

Angle of reflection = Angle of incidence = 50 degrees.

Answer:

2. 294 j

3. 37500 J

Explanation:

Answer:

2)294 3)15

Explanation:

2)E=mv^2/2

E=3×14^2/2

E=3×196/2

E=3×98

E=294 J

3)E=mv^2/2

m=2E/v^2

m=2×750/10^2

m=2×750/100

m=750/50

m=15

Answer:

(C) HBr is an acid .......

Answer:

d: 870 Hz

Explanation:

Answer:

100 g

Explanation:

Let the mass of density 1.2 g/cm³ be x gram and let the mass of density 1.8 g/cm³ be y gram

Applying

Density (D) = mass(m)/Volume (V)

Volume (V) = mass(m)/Density(D)

V = m/D........................... Equation 1

From the question,

x+y = 400...................... Equation 1

Volume of the liquidis

V = 400/1.6 = 250 cm³

(x/1.2)+(y/1.8) = 250

(1.8x/1.2)+y = 450............... Equation 1

Solving both equation simultaneously,

Subtract equation 1 from equation 2

x-(1.8x/1.2)+(y-y) = 400-450

x-1.5x = -50

-0.5x = -50

x = -50/-0.5

x = 100 g.

Hence the mass of the liquid of density 1.2 g/cm³ is 100 g

Answer:

Amplitude

Explanation:

The lower the amplitude, the lower the frequency.

Answer:

5 N

Explanation:

Given that,

A large bar magnet of mass 0.4 kg exerts a 5 N force on a small bar magnet (mass of 0.1 kg) located 20 cm away.

We need to find the force exerted by the small bar magnet on the large one.

We know that, every action has an equal and opposite reaction. Both action and reaction occur in pairs. The force acting on one object to another is same and in opposite direction on the other object.

Hence, the force exerted by the small bar magnet on the large one is also 5 N.

Answer:

see explanation

Explanation:

sound travels faster in liquid than in gases because the molecules are packed closer together!

hope this helped! xoxo raina

Respuesta:

a) 12.3 m/s²

b) 153.75 m

c) 36.9 m/s

Explicación:

Paso 1: Información provista

Paso 2: Calcular la aceleración (a) del cochecito

Usaremos la segunda ley del movimiento de Newton.

F = m × a

a = F/m = 8 N / 0.650 kg = 12.3 m/s²

Paso 3: Calcular el espacio recorrido (x) en 5 segundos (t).

Usaremos la siguiente fórmula cinemática para un movimiento rectilineo uniformemente acelerado.

x = 1/2 × a × t²

x = 1/2 × 12.3 m/s² × (5s)² = 153.75 m

Paso 4: Calcular la velocidad (v) a los 3 segundos si parte del reposo

Usaremos la siguiente fórmula cinemática para un movimiento rectilineo uniformemente acelerado.

v = a × t

v = 12.3 m/s² × 3 s = 36.9 m/s

Los cálculos dados serían los siguientes:

a). Aceleración = 12,3 m / s ^ 2

B). Distancia recorrida en 5 segundos = 153,75 m

C). Velocidad en 3 segundos = 36,9 m / s

Dado que,

Fuerza aplicada = 8N

Peso de la silla de paseo en gramos = 650g

a). To find the aceleración,

[tex]F = m[/tex] × [tex]a[/tex]

[tex]a = F/m[/tex]

[tex]= 8 N/0.650 kg[/tex]

[tex]= 12.3 m/s^2[/tex]

Now,

b). :-espacio recorrido en 5 segundos y

Using the Kinematic formula:

[tex]x = 1/2[/tex] × [tex]a[/tex] × [tex]t^2[/tex]

[tex]x = 1/2[/tex] × [tex]12.3 m/s^2[/tex] × [tex](5s)^2[/tex]

= 153.75 m

c). Using the same formula,

velocidad a los 3 segundos si parte

[tex]v = a[/tex] × [tex]t[/tex]

[tex]v = 12.3 m/s^2[/tex] × [tex]3 s[/tex]

= 36.9 m/s

Learn more about "Acceleration" here:

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Answer:

light can bounce off the material, which is called reflection. The reflection of a wave is simply a process by which a wave, whether light, sound, infrared, or radio waves, hits an object and bounces off it.

Explanation:

Answer:

It is reflection because the light will instead of passing through will bounce off a material and be reflected to another surface or material

Answer:

2519.63 kg

Explanation:

mass(m)=momentum (p)/velocity

=77000/30.56

=2519.63kg

Answer:

A) 1.3013476 × 10²⁸ N·m

b) 2.8618128 × 10²⁹ J

c) 4.73183333 × 10²³ W

Explanation:

The mass of the Earth, M = 5.972 × 10²⁴ kg

The radius of the Earth, R = 6,371 km

The angular speed of the Earth, ω = 2·π/(24 hr) = 7.27220522 × 10⁻⁵ rad/s

The shape of the Earth ≈ Spherical

The moment of inertia of a sphere, I = (2/5)·M·R²

The angular acceleration of the Earth in 7 days from rest its present angular speed, ω, is given as follows;

 α = 7.27220522 × 10⁻⁵ rad/s/((7 × 24 × 60 × 60) s) = 1.2024149 × 10⁻¹⁰ rad/s²  

Torque, τ = I × α

∴ τ = (2/5) × 5.972 × 10²⁴ × 6,731,000² × 1.2024149 × 10⁻¹⁰ = 1.3013476 × 10²⁸

The torque required, τ = 1.3013476 × 10²⁸ N·m

b) The energy required, [tex]K.E. _{(Rotational)}[/tex] = 1/2 × I × ω²

∴  [tex]K.E. _{(Rotational)}[/tex] = (1/2) × (2/5) × 5.972 × 10²⁴ × 6,731,000² × (7.27220522 × 10⁻⁵ rad/s)²

The energy required, [tex]K.E. _{(Rotational)}[/tex] = 2.8618128 × 10²⁹ J

c) Power = Energy/Time

Therefore, the average power required, P = [tex]K.E. _{(Rotational)}[/tex]/Time

∴ P = 2.8618128 × 10²⁹ J/(7 × 24 × 60 × 60) s) = 4.73183333 × 10²³ Watts

The average power required, P = 4.73183333 × 10²³ Watts.

Answer:

The force of the ball on the bat is same as the force of the bat on the ball.  

Explanation:

A bat hits the ball and the ball moves to the out filed.

According to the Newton's third law, for every action there is an equal and opposite reaction.

The action and the reaction forces acts on the two different bodies but the magnitude of the force is same.  

As the ball is hitted by the bat, the bat exerts the force on the ball and the same force is exerted on the bat by the ball according to the Newton's third law.

So, the force of the ball on the bat is same as the force of the bat on the ball but the direction of force is opposite.  

Answer:

7. 5 pa

8. 5 pa

9. 5 pa

10. 75 pa

11. 25 N

Explanation:

7.

P = F/ A

= 15 / 3

= 5 pa

8.

P = F/ A

= 35 / 7

= 5 pa

9.

area of floor = l × b

= 1 × 4

= 4m^ 2

P = F / A

= 20 / 4

=5 pa

10.

area in m^2 = 400/100 = 4m^2

P = F/A

= 300 / 4

= 75 pa

11.

F = P×A

= 25×1

= 25 N

Answer: large reflector located in orbit above the Earth's atmosphere

Explanation:

Since the student wants to see the big weather patterns in the upper atmosphere of the planet, and she will therefore need to have excellent resolution, the type of telescope that is ideal for her to use is a large reflector located in orbit above the Earth's atmosphere.

It should be noted that the refractor or a radio telescope isn't ideal in this situation as they will not capture the bug weather pattern and doesn't have an excellent resolution like the large reflector.

Explanation:

[tex]from \: newton \: first \: equation \\ V = U + at \\ 0 = U + ( - 6 \times 2) \\ U = 12 \: m {s}^{ - 1} \\ from \: newtons \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {12}^{2} + (2 \times - 12 \times \: S ) \\ 144 = 24S \\S = 6 \: m [/tex]

Answer:

Su Donarken Neden Genleşir?

Çevremizdeki maddelerin neredeyse tamamı sıcaklıkları arttığı zaman genleşir ve hacimleri artar. Bu durumu maddelerin sıcaklıklarıyla birlikte enerjilerinin de artmasıyla açıklayabiliriz.

Katı ya da sıvı haldeki bir maddenin taneciklerini bir arada tutan ana kuvvet elektromanyetik etkileşimdir. Maddelerin yoğun fazlar (katı, sıvı) oluşturmalarından da anlaşılabileceği gibi, tanecikler arasındaki çekme kuvvetleri itme kuvvetlerine baskın gelir. Isıtma sırasında maddeye verilen enerji, taneciklerin maddeyi bir arada tutan kuvvetleri kısmen de olsa yenmesini ve taneciklerin birbirinden uzaklaşmasını sağlar. Bu nedenle, genel olarak sıcaklığı artan maddelerin hacimleri de artar.

Su ise yukarıda anlatılan duruma bir istisna oluşturur. Soğutulan sıvı suyun hacmi 4ºC’ye kadar beklendiği gibi azalırken, 4ºC’den sonra artmaya başar. Hacimde soğumayla beraber yaşanan bu artış donma sırasında da devam eder. Bu olguyu açıklayabilmek için su moleküllerinin katı haldeki kristal yapısına bakmak gerekir. Sudaki hidrojen ve oksijen atomları arasında oluşan hidrojen bağları, su katı haldeyken hidrojen atomlarının farklı iki su molekülünün oksijen atomlarını birleştiren doğrusal çizgiye yakın bir nokta etrafında konumlanmasını sağlar. Oluşan bu hidrojen bağları katı halde hayli boşluklu bir yapı oluşmasına neden olur. Sıcaklık artışıyla moleküllerin enerjisi arttığı zaman ise, hidrojen bağları sebebiyle oluşan boşluklu yapı bozulur ve hacim azalır.

Answer:

a. Increases

b. Two objects that have opposite charges

Explanation:

a. As the amount of charge on two objects increases, the strength of the electrical force between the objects increases. decreases. varies. remains the same.

According to Coulomb's law, the electrical force, F between two charges q and Q is directly proportional to the product of the charges.

So, F ∝ qQ

So, if q and Q increase, their product increases and thus, the strength of the electrical force between them increases.

So, if the amount of charge of two objects increases, the strength of the electrical force between the objects increases.

b. For which pair of objects would adding the same amount of electrons to each object result in a decrease in the electric force? two positively charged objects two negatively charged objects two objects that have no charge two objects that have opposite charges

Since according to Coulomb's law, the electrical force, F between two charges q and Q is directly proportional to the product of the charges.

So, F ∝ qQ

If the same amount of electrons are added to both charges and the charges are opposite in sign, the magnitude of one charge  increases while that of the other charge decreases. so the product qQ decreases and thus F decreases.

So, the electric force decreases when the same amount of electrons is added to two objects that have opposite charges.

Answer:

A increases

Explanation:

Answer:

All minerals have a definite chemical makeup. ... For example, the mineral hematite has two iron atoms for every three oxygen atoms. The mineral magnetite has three iron atoms for every four oxygen atoms. Many minerals have very complex chemical formulas that include several elements.

Explanation:

Destructive interference occurs when the maxima of two waves are 180 degrees out of phase: a positive displacement of one wave is cancelled exactly by a negative displacement of the other wave.

Answer:

The crest of one wave overlaps the trough of another.

Answer:

The crest of one wave overlaps with the trough of another.

Answer:

Sound is a vibration, or wave, that travels through the air. Sound waves are invisible to our eyes; unless we find a way to make the sound waves move something that we can see. In this activity, your child will use different noise-making objects to cause sound waves and make sand visibly move.

Sound wave can be described by five characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed. The minimum distance in which a sound wave repeats itself is called its wavelength.

Explanation:

When the vibrating air hits your eardrum, it causes your eardrum to vibrate, just as the balloon did. These vibrations are transferred through the tiny bones in your ear to the inner ear. These vibrations are detected by nerves, which send impulses that your brain "hears" as sound.

Answer:

vibrates, and they carry energy from one place to another. Look at the sound wave and the water wave. vibrating electric charges and can travel through space where matter is not present. to particle, electromagnetic waves travel by transferring energy between vibrating electric and magnetic fields.