Three biologically important diatomic species, either because they promote or inhibit life, are
(a) CO,
(b) NO3 and
(c) CN-.
The first binds to hemoglobin, the second is a chemical messenger, and the third interrupts the respiratory electron transfer chain. Their biochemical action is a reflection of their orbital structure. Deduce their ground state electron configurations.

Answers

Answer 1

Answer:

See Explanation

Explanation:

We can write the molecular orbital configuration of molecules in the same way as we write the orbital electron configuration of atoms. The valence electrons in the molecule are filled into molecular orbitals of appropriate energy in accordance to the Aufbau principle.

For CO;

σ2s2, σ*2s2, Π2py2, Π2pz2, σ2px2

For NO;

σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2, Π*2px1

For CN-;

σ2s2, σ*2s2, Π2px2, Π2py2, σ2pz2

These are the ground state electron configurations of these molecules.


Related Questions

How long will it take a 500-W heater to raise the temperature of 400 g of water from 15.0 °C to 98.0
°C?

Answers

Explanation:

E=(98-15)×400×4.2

E=139440J

t=E/P

E=139440/500=278.88s

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how to solve x² in differential​

Answers

Answer:

x² = mutiphy by them self

Explanation:

Balanced equation: K2S(aq) + BaCl2(aq) =

Answers

Answer:

K2S(aq) + BaCl2(aq) = 2KCl(aq) + BaS(s)

In the image attached, it is explained how the solution is balanced.

The number of atoms of any element in the given chemical formula is the number that is written on the foot of the symbol of that element. The   balanced equation is

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)

What is Balanced equation?

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side.

The unbalanced equation is

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]KCl(aq) + BaS(s)

The number of atoms of K on reactant side is 2 while on product side it is 1, so to balance K we need to multiply KCl by 2

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq) [tex]\rightarrow[/tex]2KCl(aq) + BaS(s)

The atoms of sulfur on reactant and product side is 1, so it is balanced.

The atoms of Ba on reactant and product side is 1, so it is balanced.

The atoms of Cl on reactant and product side is 2, so it is balanced.

Therefore the balanced equation is

K[tex]_2[/tex]S(aq) + BaCl[tex]_2[/tex](aq)[tex]\rightarrow[/tex]2KCl(aq) + BaS(s)

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The chemical equation below is unbalanced.
NaOH + H3PO4 -> Na3PO4 + H2O
When the equation is correctly balanced, what will be the coefficient of H2O?

Answers

Answer:

3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)

Explanation:

This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.

When the equation is balanced, and the coefficient of H₂O is 3.

To balance the chemical equation:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + H₂O

The number of atoms of each element is the same on both sides of the equation.

Balance the hydrogen atoms. There are three hydrogen atoms on the left side and two hydrogen atoms on the right side. To balance the hydrogen atoms, multiply H₂O by a coefficient of 3:

NaOH + H₃PO₄ ⇒ Na₃PO₄ + 3H₂O

If the oxygen (O) atoms are balanced. There are four oxygen atoms on the right side, but only two oxygen atoms on the left side. To balance the oxygen atoms, we need to multiply NaOH by a coefficient of 2.

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Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
(a) SO3
(b) N2O (N is central)
(c) CH2C12

Answers

Solution :

a). [tex]$SO_3$[/tex]

  This compound is known as sulfur trioxide.

  The molecular shape of sulfur trioxide is trigonal planer.

   And the bond angle is 120°.

b). [tex]$N_2O$[/tex]

   This compound is known as Nitrous oxide. Here, nitrogen is in the center.     There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.

 It is linear in shape.

  The bond angle between them is 180°.

c). [tex]$CH_2Cl_{2}$[/tex]

  This compound is known as the Dichloromethane.

   The molecular shape of the compound is tetrahedral.

   The bond angles is 120°

   

Please help
Apply your knowledge and understanding of equilibrium constant in solving the following problems:

The equilibrium constant Kc for the reaction below is 170 at 500 K.

Determine whether the reaction mixture is at equilibrium when the concentrations of the components at this temperature are as follows:
[N2]=1.50
[H2]=1.00
[NH3]=8.00

If it is not at equilibrium, state and explain in which direction the reaction will proceed.Multi Line Text.
2()+32() ⇄ 23()

Answers

Answer:

The reaction will proceed to the right to attain the equilibrium.

Explanation:

Step 1: Write the balanced equation

2 N₂(g) + 3 H₂(g) = 2 NH₃(g)

Step 2: Calculate the reaction quotient

The reaction quotient (Qc) is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.

Qc = [NH₃]² / [N₂]² × [H₂]³

Qc = 8.00² / 1.50² × 1.00³ = 28.4

Since Qc ≠ Kc, the reaction is not at equilibrium.

Since Qc < Kc, the reaction will proceed to the right to attain the equilibrium.

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