Tin(II) fluoride is added to some dental products to help
prevent cavities. Tin(II) fluoride is prepared according
to the following equation:
Sn(s) + 2HF(aq) → SnF2(aq) + H2(g)
How many grams of tin(II) fluoride can be produced
from 55.0 g of hydrogen fluoride if there is plenty of tin
available to react?

Answers

Answer 1
Solution:

Step 1: Calculate the molar mass of HF and SnF₂.

For HF

molar mass = (1.008 g/mol × 1) + (19.00 g/mol × 1)

molar mass = 20.008 g/mol

For SnF₂

molar mass = (118.7 g/mol × 1) + (19.00 g/mol × 2)

molar mass = 156.7 g/mol

Step 2: Determine the mole ratio needed.

mole ratio = 2 mol HF : 1 mol SnF₂

Step 3: Calculate the mass of SnF₂ produced by using the mole ratio.

[tex]\text{mass of SnF₂ = 55.0 g HF} × \frac{\text{1 mol HF}}{\text{20.008 g HF}} × \frac{\text{1 mol SnF₂}}{\text{2 mol HF}} × \frac{\text{156.7 g SnF₂}}{\text{1 mol SnF₂}}[/tex]

[tex]\boxed{\text{mass of SnF₂ = 215.4 g}}[/tex]


Related Questions

What is the IUPAC name for the compound shown?

Answers

2-methyl-1,4-dibutal. That could be wrong but it looks right to me. Sorry if it isn’t righ

When the temperature is 23C, a bottle of gas has a pressure of 5.5atm.Assuming that the volume of the balloon remains constant, what will the
pressure be if the temperature is decreased to 18C?

Answers

Answer:

use the formula pressure 1 ÷ temperature 1 = pressure 2 ÷ temp 2

so your equation would look like this,

p2= p1(T2)÷ T1

so p2 =5.5(18)÷23

so it would be 4.304347826

round as you must

Which material is likely to slow the flow of electric charges the most? Explain.

Answers

Answer:

copper hiiiiiiiiiiiii

If there is sufficient water in the reaction system, how many grams of KOH can be produced from 22.2 g of K?

Answers

Answer: 31.9 g of KOH can be produced from 22.2 g of KOH

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} K=\frac{22.2g}{39g/mol}=0.57moles[/tex]  

[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]  

According to stoichiometry :

2 moles of [tex]K[/tex] produce = 2 moles of [tex]KOH[/tex]

Thus 0.57 moles of [tex]K[/tex] will produce=[tex]\frac{2}{2}\times 0.57=0.57moles[/tex]  of [tex]KOH[/tex]

Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.57moles\times 56g/mol=31.9g[/tex]

Thus 31.9 g of KOH can be produced from 22.2 g of KOH

bromine pentachloride formula

Answers

Answer:

Bromine pentafluoride, BrF5

bromine pentafluoride is an interhalogen compound and a fluoride of bromine. It is a strong fluorination reagent. BrF5 finds use in oxygen isotope analysis.

The chemical formula of a compound is obtained from the symbols of the elements that compose the compound. The formula of bromine pentachloride is BrCl5.

In chemistry, compounds are represented using shorthand symbols called chemical formula.

The chemical formula is composed of the symbols of the respective elements that compose the compound as well as the number of atoms of each element that compose the compound.

For the compound bromine pentachloride, there is one bromine atom and five chlorine atoms giving the formula BrCl5.

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Biological membranes are selectively permeable, allowing certain molecules to cross the membrane, but not others. Classify the molecules or ions depending on how they cross a biological membrane. Note that some of these examples may also utilize active transport to traverse a membrane. However, this question is limited to passive transport processes only. Match the followings with each others

a. Simple Diffusion
b. Facilitated Diffusion

1. steroid hormones
2. K+
3. N2
4. Glucose

Answers

Answer:

Following are the solution to these question:

Explanation:

Simple diffusion implies which molecules can move across a cell membrane instead of using the incorporated protein structure channels. Its flow of molecules across these canals is enabled by diffusion. It has steroid hormones and N2.

Facilitated diffusion of molecules via cell membranes, or active transportation, which would be the random mass transit process of molecules or ions via unique cellular membranes from the transmembrane. It has K+ and Glucose.

Help for number 9 Please!

Answers

Answer:

A..............................

11 D. Organism 4 When Charles Darwin observed finches on the Galapagos Islands, he noted differences in the shapes of birds' beaks. redeater bexl, Leal, and fruit estet Ceci este Soalanxei celer A 0 If there is a two-year drought that kills off many seed and fruit plants, which finch species have traits that could make them more successful? A. A and B B. A and C C. B and C D. C and D​

Answers

It is A. A and B. Your welcome BRAINLIEST?

2-methyl-2-butene + hydrogen chloride

Answers

This is an electrophilic addition of a hydrogen halide to an alkene.

The pi bond is attacked by the electrophilic H⁺ from the H⁺Cl⁻, resulting in the loss of the double bond and the formation of a tertiary carbocation on C2. A less stable carbocation intermediate with the positive charge on C3 is also formed.

The nucleophilic Cl⁻ then attacks the carbocations, forming the haloalkane products. The major product will be 2-chloro-2-methybutane, where the Cl is bonded to the most substituted C (Markovnikov's rule). The minor product, if you have to worry about it, will be 2-chloro-3-methylbutane. The major product has no stereoisomers to worry about as it's achiral.

The attached image shows the scheme of this reaction. Only the major product is shown.  

What is the density at STP of the gas sulfur hexafluoride, SF6?
O 3.93 x 1024 g/L
O 0.153 g/L
O 6.52 g/L
O 3270 g/L

Answers

Answer:

Explanation:

There is a formula for this:

M = DRT/P where M = molar mass. This just derived from PV = nRT where you say n = grams/molar mass. However, just with this formula, we can get D which is density at STP (1 atm and 273K). We find that D = 6.52g/L.

the third one... 6.52 g/L

Two gases helium and x are released from one end of an evacuated long cylinder at the same time if it takes helium atoms 3 times faster than gas X to effuse from one end. What is gas X?

Answers

Answer:

Hypoflorous acid, HOF

Explanation:

From the question, we're told that the helium atoms effuses 3 times than the said gas X.

We can determine the rate of effusion by using the formula

r is inversely proportional to 1/√M, where M is the molecular mass of the gas.

And also,

r is inversely proportional to 1/t, where t is the time taken for effusion.

From both formulas I listed, we can conclude that t is directly proportional to √M. And thus we proceed.

The molecular mass of Helium is 4.

tHe = tX/3, where tx is the time taken for the unknown gas X

As of yet, we don't know the molecular mass of X. Next, we say that

tX/tHe =√Mx/MHe

3 = √Mx/4

If we square both the sides, to remove the square root, we have

9 = Mx/4

Mx = 36

The molecular mass of the unknown gas X is 36.

what is acid by Lewis in science​

Answers

A Lewis acid is a substance that accepts a pair of electrons to form a covalent bond. A Lewis base is a substance that donates a pair of electrons to form a covalent bond. So, a Lewis acid-base reaction is represented by the transfer of a pair of electrons from a base to an acid.

How many moles are in 4.28 x 1023 atoms of carbon?

Answers

Answer:

0.711 moles C

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 4.28 × 10²³ atoms C

[Solve] moles C

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up:                                                                                                     [tex]\displaystyle 4.28 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})[/tex][DA] Divide [Cancel out units]:                                                                        [tex]\displaystyle 0.710727 \ moles \ C[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.710727 moles C ≈ 0.711 moles C

Our most recent mass extension happened about 65million years ago. Describe the effects of this event.

Answers

Answer:

To explain what caused this mass extinction, scientists have focused on events that would have altered our planet's climate in dramatic, powerful ways. The leading theory is that a huge asteroid or comet slammed into Earth 65 million years ago, blocking sunlight, changing the climate and setting off global wildfires.

Identify the reactants and products in the following chemical equation: Zn +2HCl --> ZnCl2 + H2 *
20 points
A: Reactants: Zn & HCl Products: ZnCl2 & H2
B: Reactants: ZnCl2 & H2 Products: Zn & HCl
C: Reactants: Zn & H2 Products: ZnCl2 & HCl

Answers

Answer:

A.

Explanation:

zinc and hydrochloric acid reacts to form zinc chloride and hydrogen.

hope it helps. :)

Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3

Answers

Answer:  4.22 grams of solute is there in 278 ml of 0.038 M [tex]Fe_2(SO_4)_3[/tex]

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in L

Now put all the given values in the formula of molality, we get

[tex]0.038M=\frac{n}{0.278L}[/tex]

[tex]n=0.0105mol[/tex]  

mass of  [tex]Fe_2(SO_4)_3[/tex] = [tex]moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g[/tex]

Thus 4.22 grams of solute is there in 278 ml of 0.038 M [tex]Fe_2(SO_4)_3[/tex]

What is total distance traveled?
What is the displacement (change in positions) ​

Answers

Answer:

Exercise 1

a)  140 m

b)  100 m

c)  180 m

d) 140 m

Exercise 2

a) 20 yards

b) 30 yards

c) 20 yards

d) 55 yards

Exercise 3

a)  11 Kilometers

b) 7 Kilometers

Explanation:

Exercise 1

Distance from B to C = 140 m

Distance from  to D = 100 m

Total distance = 100+40+40 = 180 m

Total displacement i.e. distance between A and D is 140 m

Exercise 2

a) Distance from B to C = 35 -15 = 20 yards

b) Distance from C to D  = 5 + 35  = 30 yards

c) Distance from B to D = 5 + 15 = 20 yards

d) Displacement = 5 + 50 = 55 yards

Exercise 3

a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers

b) Displacement = 5-2 + 4 = 7 Kilometers

Calculate the pH of a solution prepared by dissolving 1.60 g of sodium acetate, CH3COONa, in 50.0 mL of 0.10 M acetic acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1.75 x 10^-5.

Answers

Answer:

pH = 5.35

Explanation:

Given 1.60 grams sodium acetate (NaOAc(aq))*** added to 50ml of 0.10M acetic acid (HOAc(aq)) solution.

Applying common ion effect keeping in mind that the addition of NaOAc provides the common-ion (OAc⁻).

      HOAc(aq) ⇄          H⁺(aq)            +                 OAc⁻(aq)

 I      0.10m          1.32 x 10⁻³M ≈ ∅M*     (1.6g/82.03g/mol) / 0.050L = 0.39M

 C       -x                         +x                                0.39M + x ≈ 0.39M**

 E    0.10M - x                  x                                    0.39M

       ≈ 0.10M

Ka = [H⁺][OAC⁻]/[HOAC] => [H⁺] = Ka·[HOAc] / [OAc⁻]

[H⁺] = (1.75 X 10⁻⁵)(0.10) / (0.39) = 4.5 x 10⁻⁶M

∴ pH = -log[H⁺] = -log(4.5 x 10⁻⁶) = -(-5.35) = 5.35

_______________________________________________

* [H⁺] before adding NaOAc = SqrRt(Ka · [HOAc]) = SqrRt(1.75 x 10⁻⁵· 0.10) = 1.32 x 10⁻³M. Since this concentration value is so small, the initial [H⁺] is assumed to be zero molar (∅M).

** The added [H⁺] is negligible and dropped in the ICE table. That is, adding ~[H⁺] in the order of 10⁻³M does not change the H⁺ ion concentration sufficiently to affect problem outcome and is therefore dropped in the ICE table.

*** Acetic Acid and Sodium Acetate are frequently written HOAc and NaOAc where the OAc⁻ anion is the acetate ion (CH₃COO⁻) for brevity.

The pH of the solution measures the acid of the liquid throughout the molar concentration of hydrogen ions in a solution.

[tex]\bold{CH_3COONa \ mass = 1.60\ g}\\\\[/tex]

Solution Volume (V) [tex]=50.0\ mL =0.05\ L\\\\[/tex]

[tex]\bold{CH3COONa \ molarity =0.10\ M }[/tex]

[tex]\bold{\text{Calculating the CH3COONa moles} =\frac{mass}{molar\ mass}}[/tex]

                                                       [tex]= \frac{1.60\ g}{82.03\frac{g}{mol}} \\\\=0.0195\ mol\\\\[/tex]

[tex]\bold{M = \frac{ \text{amount of solute moles} } { \text{solution volume in L} }}[/tex]

     [tex]= \frac{0.0195\ mol}{0.05\ L}\\\\ =0.39\ M[/tex]

Using Henderson Hasselbach equation:

[tex]\bold{pH = -\log K_{a} + \log{[salt]}{[acid]}}\\\\[/tex]

     [tex]=\bold{ -\log (1.75\times 10^{-5}) + \log ( \frac{0.39}{0.10}) }\\\\=\bold{ 4.757 + \log (3.9)}\\\\=\bold{ 4.757 + 0.5910}\\\\=\bold{ 5.348}\\\\=\bold{ 5.35}\\[/tex]

So, the final answer is "5.35".

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water from a town is suspected to contain chloride ions but not sulphate ions . describe how the presence of the chloride ions in the water can be shown​

Answers

Answer:

See Explanation

Explanation:

We can establish that there are chloride ions present in water if we add dilute trioxonitrate V acid to a sample of the water in drops followed by aqueous silver trioxonitrate V.

If a white precipitate is observed and the precipitate is found to be soluble in excess aqueous ammonia solution, then we can confirm the presence of chloride ion in the water.

Which substance has the highest ph?

A. Tomato
B. Unpolluted rainwater
C. Ammonium hydroxide
D. Orange juice

Answers

Answer:

c ammonium hydroxide nh4oh has higher ph value and its a base

plz mark me branliest

Answer:

c) ammonium hydroxide

Explanation:

ammonium hydroxide nh4oh has higher ph value, and it is an alkaline

ection
9)
A compound consists of 25.9% nitrogen and 74.1% oxygen by mass. What is the empirical
formula of the compound?
A)
NOZ
B)
NO
C)
N₂Os
D)
0
1
N20
2
3
4
5
6
7
8
9
0
21
2

Answers

Answer:

69

Explanation:

5. Element X exists as diatomic molecules.
In which group of the Periodic
Table is X placed?
A. Group O
B.
Group I
C.
Group II
D.
Group VII​

Answers

Element X Exists as diatomic molecules . In which group of the Periodic Table is X placed ?

Group VII

Group VII - elements are Fluorine , Chlorine , Bromine and Iodine .

They exist in diatomic molecules as F2 , Cl2 , Br2 and I2 .

When a thermometer is heated, the red liquid inside the thermometer moves up. This is mainly because:
A. The red liquid is thin.
B. The molecules of the liquid move faster and get a little further apart.
C. Hot liquid is lighter.
D. The glass of the thermometer gets hot.

Answers

C. Hot liquid is lighter.

The thermometers with red liquid usually depicts a kerosene based column with red dye. It is more safe than mercury thermometer. The red liquid inside the thermometer moves up due to the molecules of the liquid move faster and get a little further apart. The correct option is B.

What is thermometer?

The device which is used to measure the temperature is defined as the thermometer. It can measure the temperature of a solid such as food, a liquid like water and a gas like air.

The thermometers which are developed for clinical purposes are called clinical thermometers. It can also measure the temperature of human body. It is a long narrow glass tube which contain a bulb and consists of mercury at the end.

When a thermometer is heated, the molecules present in the liquid inside the thermometer get a little further apart. Because the liquid takes up more space. So the red line moves up in the tube.

Thus the correct option is B.

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What is the empirical formula for a compound that is 7.70 % carbon and 92.3 % chlorine?

Answers

Answer:

Imole/C=129 Directions Show All Of Your Work For Each Of The Following Problems. 1.

Explanation:

How many grams of iron contain 4.06X10^24 atoms of iron?

Answers

4.06x20^24/6.02x10^23 = 6.744 moles x 55.845 g/mole = 376.61868grams

We have that the grams of iron contained 4.06X10^24 atoms of iron is

g= 376.6g

From the question we are told

How many grams of iron contain 4.06X10^24 atoms of iron?

Generally the equation for the Moles of Iron   is mathematically given as

[tex]M=\frac{4.06x10^24}{6.02x10^23} \\\\M=6.744moles[/tex]

Therefore

Where Molar mass of Iron =55.845

Generally the equation for the mass   is mathematically given as

g= 6.744  x 55.85

g= 376.6g

Therefore

the grams of iron contained 4.06X10^24 atoms of iron is

g= 376.6g

 

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what are the two changes of state occurs during distillation​

Answers

Answer:

The changes of state occur during distillation are boiling followed by condensation. The liquid is converted into its vapor phase at its boiling point and the vapor is then condensed back to liquid on cooling.

Explanation:

Heart me pls

The body system responsible for breaking down food and absorbing nutrients is the ____

a
circulatory system
b
respiratory system
c
excretory system
d
digestive system

Answers

Answer:

d

digestive system

Explanation

It’s the digestive system

Hhheppppp fffaaast
Mixture of water and LEAD SULPHATE is an example of Homogeneous mixture Select one : True O False​

Answers

Answer:

False

Explanation:

Lead sulfate is insoluble in water and sinks in water

(sorry if it's wrong)

how can two rocks made by the same process be so different in color

Answers

Answer: Although the rocks of the produced by similar processes but their chemical composition may vary dependent upon the type of mineral present in these rocks so the color of the rock also varies depending upon the mineral composition.

Explanation:

The rocks are made by basic steps like disintegration of parent rock material, erosion, crystallization, metamorphism, and sedimentation. These basic steps are common in same kind of rocks but their color may vary because of the mineral composition in them for example, Rhyolite is of light colored because of the presence of quartz mineral present in it.

In a titration of nitrous acid with NaOH, the pH of the solution is 3.14 when the moles of HNO2 and the moles of NO2-- are equal. What is the Ka of nitrous acid?

Answers

Answer:

[tex]Ka=3.98x10^{-4}[/tex]

Explanation:

Hello there!

In this case, since the modelling of titration problems can be approached via the Henderson-Hasselbach equation to set up a relationship between pH, pKa and the concentration of the acid and its conjugate base, we can write:

[tex]pH=pKa+log(\frac{[NO_2^-]}{[HNO_2]} )[/tex]

Whereas the pH is given as 3.14 and the concentrations are the same, that is why the pH would be equal to the pKa as the logarithm gets 0 (log(1)=0); thus, we can calculate the Ka via:

[tex]Ka=10^{-pKa}=10^{-3.14}\\\\Ka=3.98x10^{-4}[/tex]

Best regards!

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