to build the pyramids in egypt, it is believed that giant's causeways were constructed to transport the building materials to the site. one such causeway is said to have been 3000 ft long, with a slope of about 2.3 degrees. how much force would be required to hold a 60-ton monolith on this causeway?

Answers

Answer 1

The force required to hold a 60-ton monolith on a 3000 ft long causeway with a slope of 2.3 degrees is approximately 267,077 N.


force = mass x acceleration

First, we need to convert the slope angle to radians:

2.3 degrees = 0.04 radians

Next, we need to calculate the acceleration due to gravity:

acceleration = 9.81 m/s^2

We will assume that the causeway is made of stone and has a coefficient of friction of 0.5. This means that the force required to hold the monolith in place would be equal to the force of friction:

force = frictional force = coefficient of friction x normal force

The normal force is equal to the weight of the monolith, which is:

mass = 60 tons = 54,431 kg

weight = mass x acceleration due to gravity = 534,154 N

Therefore, the normal force is 534,154 N.

Now we can calculate the force of friction:

frictional force = 0.5 x 534,154 N = 267,077 N


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Related Questions

If scientists are interested in studying the composition of the early solar system, the best objects to study are:______

Answers

If scientists are interested in studying the composition of the early solar system, the best objects to study are meteorites and comets.

These celestial bodies are considered remnants from the formation of the solar system and can provide valuable insights into its composition and history.

Comets, on the other hand, are icy bodies that originate from the outer solar system and periodically pass through the inner solar system. They are composed of frozen water, gases, and dust and can provide information about the conditions present in the outer solar system at the time of their formation.

When comets pass near the Sun, they release gas and dust, forming a visible coma and tail that can be observed from Earth. Scientists can study the composition of comets by analyzing the gases and dust that are released, which can provide insights into the conditions that existed in the early solar system.

Both meteorites and comets are important sources of information about the early solar system and can help scientists better understand the processes that led to the formation of our solar system and the planets within it.

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jerome plays middle linebacker for south's varsity football team. in a game against cross-town rival north, he delivered a hit to north's 82-kg running back, changing his eastward velocity of 5.6 m/s into a westward velocity of 2.5 m/s.
(a) determine the initial momentum of the running back.
(b) determine the final momentum of the running back.
(c) determine the momentum change of the running back.
(d) determine the impulse delivered to the running back.

Answers

(a) The initial momentum of the running back  p= 459.2 kg m/s.

(b)The final momentum of the running back p= -205 kg m/s.

(c) The momentum change of the running back is momentum = -664.2 kg m/s.

(d)The impulse delivered to the running back is the momentum change

(a) The initial momentum of the running back can be calculated using the formula p = mv, where p is momentum, m is mass, and v is velocity. So, the initial momentum of the running back is

p = 82 kg * 5.6 m/s

p= 459.2 kg m/s.
(b) The final momentum of the running back is p = mv, where m is still 82 kg but v is now -2.5 m/s (since the direction has changed). So, the final momentum of the running back is

p = 82 kg * (-2.5 m/s)

p= -205 kg m/s.
(c) The momentum change of the running back is the final momentum minus the initial momentum, or p_final - p_initial. So, the momentum change of the running back is

momentum=-205 kg m/s - 459.2 kg m/s

momentum = -664.2 kg m/s.
(d) The impulse delivered to the running back can be calculated using the formula J = FΔt, where J is impulse, F is force, and Δt is the time during which the force is applied. We don't know the force or time, but we can use the fact that impulse is also equal to the change in momentum, or J = Δp. So, the impulse delivered to the running back is the momentum change calculated in part (c), which is -664.2 kg m/s.

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What is the momentum of a 50-kg carton that slides at 4 m/s across an icy surface?

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Momentum is the product of an object's mass and velocity. To find the momentum of a 50-kg carton that slides at 4 m/s across an icy surface.

We can use the formula p = mv, where p is momentum, m is mass, and v is velocity.

In this case, the mass of the carton is 50 kg and the velocity is 4 m/s. So, the momentum of the carton can be calculated as follows:

p = mv
p = 50 kg x 4 m/s
p = 200 kg m/s

Therefore, the momentum of the 50-kg carton that slides at 4 m/s across an icy surface is 200 kg m/s. This means that the carton has a significant amount of momentum, which can be difficult to stop or change direction.

It is important to take precautions and use proper safety measures when handling or transporting heavy objects with high momentum to avoid accidents or injuries.

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The frequency of the first harmonic in a pipe is measured. An adjustment [1 mark] is then made which causes the speed of sound in the pipe to increase. What is true for the frequency and the wavelength of the first harmonic when the speed of sound has increased? Frequency Wavelength А increase unchanged B unchanged increase C increase increase D unchanged unchanged

Answers

When the speed of sound in the pipe increases, the frequency and wavelength of the first harmonic will both increase. Therefore, the correct answer is C (increase, increase).

When an adjustment is made which causes the speed of sound in the pipe to increase, the frequency of the first harmonic also increases while the wavelength remains unchanged. This is because the frequency of a wave is directly proportional to its speed, and the wavelength is inversely proportional to its speed. Thus, when the speed of sound increases, the frequency of the first harmonic increases while the wavelength remains constant.

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with the use of a phase shift, the positing of an object may be modeled as a cosine or sine function. if given the option, which function would you choose? assuming that the phase shift is zero, what are the initial conditions of the function; that is, the initial position, velocity, and acceleration, when using a sine function? how about when a cosine function is used?

Answers

The  answer  is that the choice between a cosine or sine function for modeling the position of an object with a phase shift depends on the initial conditions of the object's motion.


If the object starts from its equilibrium position (i.e., its initial position, velocity, and acceleration are zero), then both the sine and cosine functions can be used interchangeably, as they will produce the same results. However, if the object starts from a non-equilibrium position, then the choice between the two functions will depend on the specific initial conditions.

When using a sine function with a phase shift of zero, the initial position will be the amplitude of the function (i.e., the maximum displacement from the equilibrium position). The initial velocity will be zero, as the function crosses the equilibrium position at that moment. The initial acceleration will be negative, as the function is concave downward at that moment.

On the other hand, when using a cosine function with a phase shift of zero, the initial position will also be the amplitude of the function. However, the initial velocity will be positive, as the function reaches its maximum displacement from the equilibrium position at that moment. The initial acceleration will be zero, as the function changes from concave upward to concave downward at that moment.

Therefore, the choice between a sine or cosine function for modeling an object's motion depends on the initial conditions of the object's position, velocity, and acceleration.

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how does the azimuth of sunrise change from the first day of winter to the first day of spring?

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The azimuth of sunrise changes from the first day of winter to the first day of spring due to the tilt of the Earth's axis.

On the first day of winter, the Earth's tilt causes the sun to rise at its southernmost point on the horizon, resulting in a lower azimuth angle.

As the Earth continues its orbit around the sun, the tilt of the axis causes the sunrise position to gradually move northward, resulting in a higher azimuth angle on the first day of spring.

Hence, the azimuth of sunrise changes from winter to spring due to the tilt of the Earth's axis, causing the position of the sunrise to gradually move northward.

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Why has the supermassive black hole in our galaxy (or any galaxies in general) not gobbled up our whole galaxy yet? How can one trigger it to, or is it even possible to?

Answers

Black holes are among the oddest and most intriguing celestial bodies. Even light cannot escape their gravitational pull due to their immense density and strength.

Yes, a blackhole might theoretically continue to consume everything in the universe if the matter entered its event horizon.

Nevertheless, as galaxies move apart, space is expanding. And because a portion of the universe will always have escaped, this circumstance will never arise as long as one galaxy is growing away from another galaxy.

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T/F isaac newton favored a wave theory of light, just like huygens.

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False, Isaac Newton favoured a particle theory of light, known as the "corpuscular theory," while Huygens supported the wave theory of light.

They had different views on the nature of light.

Newton's corpuscular theory proposed that light is composed of tiny particles that travel in straight lines and interact with matter to produce the phenomena of reflection, refraction, and diffraction. In contrast, Huygens' wave theory proposed that light is a wave that propagates through a medium and undergoes interference and diffraction. The debate between the particle theory and the wave theory of light was eventually resolved in the 19th century, with the wave theory being supported by experiments like the double-slit experiment.

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Which of the following statements are true?Check all that applyFor the gas to do positive work, the cycle must be traversed in a clockwise manner.Positive heat is added to the gas as it proceeds from state C to state D.The net work done by the gas is proportional to the area inside the closed curve.The heat transferred as the gas proceeds from state B to state C is greater than the heat transferred as the gas proceeds from state D to state A.

Answers

Out of the given statements, the true statements  are that positive work occurs when the cycle is traversed in a clockwise manner, and the net work done by the gas is proportional to the area inside the closed curve.

1. For the gas to do positive work, the cycle must be traversed in a clockwise manner.
2. The net work done by the gas is proportional to the area inside the closed curve.

In a thermodynamic cycle, positive work is done when the cycle proceeds in a clockwise manner.

Additionally, the net work done by the gas in a cycle is proportional to the area enclosed by the cycle on a pressure-volume diagram.

Hence, Out of the given statements, the true ones are that positive work occurs when the cycle is traversed in a clockwise manner, and the net work done by the gas is proportional to the area inside the closed curve.

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What is the default storage mechanism for Core Data?A. XMLB. SQLiteC. Binary dataD. UserDefaults

Answers

The default storage mechanism for Core Data is B) SQLite.

Core Data is a framework provided by Apple that allows developers to manage the model layer objects in an application. It supports several different storage mechanisms, including XML, Binary data, and SQLite. However, SQLite is the default storage mechanism used by Core Data.

SQLite is a lightweight and fast database engine that is commonly used in mobile and desktop applications. It provides a reliable and scalable way to store and query data in an application.

Developers can customize the storage mechanism used by Core Data by specifying a different type of persistent store, but for most applications, B) SQLite provides a good balance of performance and functionality.

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Can you think of a case where a roller skate and a truck would have the same momentum?

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Yes, it is possible for a roller skate and a truck to have the same momentum if the roller skate is moving at a high velocity and the truck is moving at a much lower velocity.

Momentum is calculated by multiplying an object's mass by its velocity, so if the roller skate has a very small mass but is moving very quickly, its momentum could be equal to a truck with a much larger mass but a slower velocity. However, it is important to note that this scenario is unlikely in real-life situations and would require specific conditions to occur. A roller skate and a truck can have the same momentum in a situation where the product of the mass and velocity for each is equal. Momentum (p) is calculated using the formula p = mv, where m is mass and v is velocity.

For example, if a roller skate with a mass of 1 kg moves at a velocity of 10,000 m/s, its momentum would be 10,000 kg·m/s. If a truck with a mass of 5,000 kg moves at a velocity of 2 m/s, its momentum would also be 10,000 kg·m/s. In this scenario, both the roller skate and the truck have the same momentum.

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during the collision of the railroad cars of the previous problem, what is the magnitude of the impulse on one of the cars?

Answers

The magnitude of the impulse on one of the cars during the collision can be calculated using the formula:

This explanation provides a brief overview of the process for calculating the magnitude of the impulse. For a more detailed and long answer, additional information such as the masses and velocities of the cars would be necessary to provide a specific numerical answer.


Impulse = Change in momentum
To find the change in momentum, we can use the equation
Δp = mΔv
where Δp is the change in momentum, m is the mass of the car, and Δv is the change in velocity.
In order to calculate Δv, we need to know the initial and final velocities of the car. This information should be provided in the problem statement.
Once we have calculated Δp, we can then find the magnitude of the impulse by taking the absolute value of Δp.

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how far must a 2.0-cm-diameter piston be pushed down into one cylinder of a hydraulic lift to raise an 7-cm-diameter piston by 35 cm?

Answers

Answer:

The distance the 2.0-cm-diameter piston must be pushed down to raise 9 cm diameter is 607.5 cm.

Explanation:

Distance the piston must be pushed down.

a mechanic turns a wrench using a force of 25 n at a distance of 16 cm from the rotation axis. the force is perpendicular to the wrench handle. what magnitude torque does she apply to the wrench?

Answers

The torque applied to an object is given by the equation:

τ = F × r × sin(θ)

where τ is the torque, F is the force applied, r is the distance from the rotation axis, and θ is the angle between the force vector and the vector pointing from the rotation axis to the point where the force is applied.

In this case, the force is perpendicular to the wrench handle, so θ = 90 degrees and sin(θ) = 1. Also, the distance r is given in centimeters, so we need to convert it to meters:

r = 16 cm = 0.16 m

Substituting the values into the equation, we get:

τ = 25 N × 0.16 m × sin(90°) = 4 N·m

Therefore, the mechanic applies a torque of 4 N·m to the wrench..

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if the net external torque on a figure skater is zero and her rotational inertia about some vertical axis increases by 25%, then what would happen to her angular speed, measured about the same axis?

Answers

If the net external torque on a figure skater is zero and her rotational inertia about some vertical axis increases by 25%, her angular speed, measured about the same axis, would decrease. This is due to the conservation of angular momentum, which states that the angular momentum of an object remains constant in the absence of external torques.

As the skater's rotational inertia increases, her angular momentum must remain constant, so her angular speed must decrease to compensate for the increase in inertia.

Net external torque refers to the sum of all external torques acting on an object or a system. Torque is a measure of the twisting force that causes rotation, and it is a vector quantity that has both magnitude and direction.

In order to calculate the net external torque acting on an object, you must first identify all the external forces that are causing torque. This can include forces such as gravity, friction, air resistance, and any other forces that are not generated by the object itself.

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Answer:

Decrease by 20%

Explanation:

on a cold day you inhale of air at , and its temperature is raised to . assume that the pressure of the air remains a constant during this process. what is the total change (in joules) in thermal energy of the air you inhaled?

Answers

The total change in thermal energy of the air you inhaled is approximately 158872.5 joules.

To calculate the total change in thermal energy of the air you inhaled, we can use the specific heat capacity equation:

Q = m * c * deltaT

where Q is the total change in thermal energy, m is the mass of the air, c is the specific heat capacity of air, and deltaT is the change in temperature.

We can assume that the pressure of the air remains constant, so we can use the equation for constant pressure processes:

Q = m * Cp * deltaT

where Cp is the specific heat capacity at constant pressure.

The mass of air inhaled is not given, but we can assume it is approximately equal to the volume of air inhaled, which is typically around 0.5 liters or 0.5 kg.

The specific heat capacity of air at constant pressure, Cp, is approximately 1005 J/kg*K.

The change in temperature, deltaT, is (32 - (-10)) = 42 degrees Celsius, which is equivalent to 42 + 273.15 = 315.15 Kelvin.

Plugging in the values, we get:

Q = 0.5 kg * 1005 J/kg*K * 315.15 K = 158872.5 J

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a 9.0-cm -long spring is attached to the ceiling. when a 2.5 kg mass is hung from it, the spring stretches to a length of 14 cm

Answers

The spring has a spring constant of 55 N/m.

When a mass of 2.5 kg is hung from the spring, it stretches by 14 cm, which is 0.14 m. Using the formula for the spring constant, k = F/x, where F is the force applied to the spring and x is the displacement of the spring from its equilibrium position, we can calculate the spring constant as k = (mg)/x = (2.5 kg x 9.8 m/s^2)/0.14 m = 171.4 N/m. However, this is the spring constant when the spring is stretched to a length of 14 cm. To calculate the spring constant when the spring is at its natural length of 9.0 cm, we need to use Hooke's Law, which states that the force exerted by a spring is proportional to its displacement from its equilibrium position. Thus, we can write F = kx, where F is the force exerted by the spring, x is the displacement of the spring from its equilibrium position, and k is the spring constant. Solving for k, we get k = F/x = (mg)/x = (2.5 kg x 9.8 m/s^2)/(0.14 m - 0.09 m) = 55 N/m.

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what principle is responsible for the fact that certain sunglasses can reduce glare from reflected surfaces?

Answers

Polarization is the principle responsible for reducing glare from reflected surfaces. When light is reflected from a shiny surface, it vibrates in all directions, creating intense glare.

Some additional points to consider:

The filter in polarized sunglasses is typically made of a material such as polaroid or polycarbonate, which only allows light waves vibrating in a specific direction to pass through.The vertical orientation of light waves is less likely to cause glare, while horizontally oriented light waves are more likely to be scattered and cause glare.Polarized sunglasses are especially useful for activities like driving or water sports, where glare from reflective surfaces can be dangerous and/or impair vision.

Polarized sunglasses have a special filter that blocks this scattered light, allowing only the vertically oriented light waves to pass through.

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Two charged conducting spheres are connected by a metallic wire attached to each sphere. Sphere A is larger than sphere B. In electrostatic equilibrium, the magnitude of the electric potential at the surface of sphere A:

Answers

The magnitude of the electric potential at the surface of sphere A is equal to the magnitude of the electric potential at the surface of sphere B. This is because, in electrostatic equilibrium, the charges on the conducting spheres distribute themselves evenly, and the electric potential is constant throughout the surface of each sphere.

When the two spheres are connected by a metallic wire, the charges on the spheres can flow through the wire until the potentials on each sphere are equal. This process continues until the charges are distributed evenly across both spheres, and the potential is the same everywhere on the surface of each sphere.
The electric potential at the surface of sphere A is the same as the electric potential at the surface of sphere B when the two spheres are connected by a metallic wire in electrostatic equilibrium. This is due to the equal distribution of charges on both spheres, resulting in a constant electric potential throughout their surfaces.

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In cylinders, what will cause wall tension to increase?

Answers

Wall tension in cylinders will increase due to higher internal pressure, thinner walls, and larger diameter.

The pressure exerted on the walls of the cylinder causes the molecules of the material to move closer together, resulting in an increase in tension or stress on the walls. This increase in tension can cause the cylinder to deform or even rupture if the pressure becomes too great. It's important to note that the thickness and material of the cylinder wall also play a significant role in determining the amount of tension it can withstand.

In addition, other factors such as temperature, friction, and external forces can also contribute to an increase in wall tension. Overall, understanding the factors that affect wall tension in cylinders is essential for ensuring their safe and effective use in various applications.

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if these spheres are released from rest at precisely the same time, how fast, in meters per second, will they be moving when they are infinitely far away from each other?

Answers

Two spheres that are gravitationally attracted to each other, we can use the formula for escape velocity to determine how fast they will be moving when they are infinitely far away from each other. The escape velocity is the minimum velocity required for an object to escape the gravitational attraction of another object. It is given by the formula:

v = sqrt(2GM/r)

where v is the escape velocity, G is the gravitational constant, M is the mass of the object creating the gravitational field, and r is the distance between the centers of the two objects.

If we assume that the two spheres have the same mass and are a distance r apart when they are released, we can simplify the formula to:

v = sqrt(GM/r)

If we plug in the values for G, M, and r, we get:

v = sqrt(6.67 x 10^-11 m^3/kg s^2 * 2M/r)

Simplifying further, we get:

v = sqrt(13.34M/r) m/s

Therefore, if the two spheres are released from rest at precisely the same time, they will be moving at a speed of sqrt(13.34M/r) meters per second when they are infinitely far away from each other.

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Final answer:

When the spheres are infinitely far apart, their potential energy becomes zero, and all their initial mechanical energy is converted into kinetic energy.

Explanation:

To determine how fast the spheres will be moving when they are infinitely far away from each other, we can apply the law of conservation of energy. Since the spheres are released from rest, their initial total mechanical energy is equal to zero. As the spheres move away from each other, their gravitational potential energy decreases and their kinetic energy increases. When the spheres are infinitely far apart, their potential energy becomes zero, and all their initial mechanical energy is converted into kinetic energy. Therefore, the spheres will be moving at a speed equal to the square root of 2 times the initial speed when they were released.

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Pure water and pure salt are poor conductors of electricity. When salt is dissolved in water, the resulting solution conducts electricity well. a. true
b. false

Answers

a. True.

When salt is dissolved in water, it dissociates into its constituent ions, which can carry an electric current through the solution.

The positively charged sodium ions (Na+) and negatively charged chloride ions (Cl-) are attracted to the electrodes of an electric circuit, and when a potential difference is applied, they move towards their respective electrodes, carrying electric charge with them.

In contrast, pure water does not conduct electricity because it contains no free ions or electrons that can carry an electric current.

Pure salt (NaCl) is also a poor conductor of electricity because its constituent ions are held together by strong electrostatic forces and are not free to move.

Thus, the statement "When salt is dissolved in water, the resulting solution conducts electricity well" is true.

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(a) calculate the magnitude of the centripetal acceleration at the tip of a 4.00 m long helicopter blade that rotates at 300 rev/min.

Answers

The magnitude of the centripetal acceleration at the tip of a 4.00 m long helicopter blade rotating at 300 rev/min is 1,962.96 m/s².

To calculate the centripetal acceleration, follow these steps:
1. Convert the angular velocity from rev/min to rad/s: (300 rev/min) * (2π rad/rev) * (1 min/60 s) = 31.42 rad/s.
2. Apply the centripetal acceleration formula: a_c = rω², where a_c is the centripetal acceleration, r is the radius (blade length), and ω is the angular velocity.
3. Substitute the values: a_c = (4.00 m) * (31.42 rad/s)² = 1,962.96 m/s².

The centripetal acceleration at the tip of the helicopter blade is found using the given blade length and rotation speed, along with the appropriate conversion factors and formula.

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two musical strings have the same length and tension, but string a has one fourth the mass of string b. the speed of a wave on string a is

Answers

Two musical strings have the same length and tension, but string A has one fourth the mass of string B. We need to determine the speed of a wave on string A.

The speed of a wave on a string can be calculated using the formula:
v = √(T/μ)

where v is the wave speed, T is the tension, and μ is the linear mass density (mass per unit length).

Since the tension is the same for both strings, we'll focus on the linear mass density. Let μ_A and μ_B represent the linear mass densities of strings A and B, respectively. Given that string A has one fourth the mass of string B, we can write:
μ_ A = (1/4)μ_ B

Now we can find the ratio of the wave speeds on the two strings:
v_ A / v_ B = √(T/μ _A) / √(T/μ _B)

Since the tensions are the same, they cancel out:
v_ A / v_ B = √(1/μ_ A) / √(1/μ_ B)

Now, substitute the relationship between μ_A and μ_B:

v_ A / v_ B = √(1/[(1/4)μ_B]) / √(1/μ_B)
v_ A / v_ B = √(4/μ_B) / √(1/μ_B)

Taking the ratio, we get:

v_ A / v_ B = √4
v_ A = 2v _B

The speed of a wave on string A is twice the speed of a wave on string B.

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Assume that a 120โฆ resistor and ammeter are in series. A voltmeter is in parallel with both of them. The meters are not ideal, but have internal resistances of ๐๐=10.0๐โฆ and ๐๐ด=2.00โฆ. If the voltmeter reads 8.25 volts, what is the actual voltage across the resistor? b) Note: The circuit in this problem is wired differently from the circuit in problem a. Assume that a 470kโฆ resistor is in parallel with the voltmeter from problem a. If the ammeter from problem 3 is in series with this parallel combination, what is the actual current through the resistor if the ammeter reads 2.00 ๐๐ด?

Answers

The current through the resistor is 0.0625 A, under the condition that the ammeter reads 2.00 ohm.

The voltage across the resistor can be evaluated by Ohm's law which states that V = IR
Here
V = voltage,
I = current
R = resistance.
The internal resistance of the voltmeter and ammeter are given as 10 ohms and 2 ohms.
Let us consider that the current flowing through the circuit is I.
The voltage across the resistor can be calculated as follows:
V = IR
The current flowing through the circuit can be evaluated using Kirchhoff's current law which states that the sum of currents entering a node should be  equal to the sum of currents leaving a node.
I = I1 + I2
Here
I1 = current flowing through the resistor
I2 = current flowing through the voltmeter.
The current flowing through the voltmeter can be evaluated by
I2 = V/R2
Here
R2 = internal resistance of the voltmeter.
The current flowing through the resistor can also br evaluated as
I1 = V/R1
Here
R1 = resistance of the resistor.

Staging these values in Kirchhoff's current law
I = V/R1 + V/R2
The voltage across the resistor can be found out by staging this value in Ohm's law equation
V = IR1
Staging values we get
V = (V/R1 + V/R2)R1
Solving for V we get
V = (R1/(R1+R2)) × 8.25 volts
V = (120/(120+10)) × 8.25 volts
V = 7.5 volts
Then, actual voltage across resistor is 7.5 volts.

For part b), we have a parallel combination of a voltmeter and a 470k ohm resistor in series with an ammeter and a 120 ohm resistor. The total resistance of this combination can be calculated as follows:

Rt = (Rv × R3)/(Rv + R3) + R4

where Rv is internal resistance of voltmeter, R3 is resistance of 470k ohm resistor, and R4 is resistance of 120 ohm resistor.

Substituting values we get:

Rt = (10 × 470000)/(10 + 470000) + 120

Rt = 120.025 ohms

The actual current through resistor can be calculated using Ohm's law as follows:

I = V/Rt

where V is voltage across resistor which we have already calculated in part a) as 7.5 volts.

Substituting values we get:

I = 7.5/120.025

I = 0.0625 A

Therefore, actual current through resistor if ammeter reads 2.00 ohms is 0.0625 A.

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why should the mass of an object never be determined when the object's temperature is above room temperature?

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The mass of an object should never be determined when the object's temperature is above room temperature because the object's expansion due to heat will cause inaccuracies in the measurement.

When an object is heated, its molecules move faster and take up more space, causing the object to expand. This expansion can lead to an increase in the object's apparent mass, making it difficult to accurately determine its true mass. Therefore, it is important to ensure that the object has cooled down to room temperature before attempting to measure its mass.

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A bullet of mass m is fired with muzzle speed v0 horizontally and due north from a position at colatitude θ. Find the direction and magnitude of theCoriolis force in terms of m, v0, θ, and the Earth's angular velocity Ω.

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The Coriolis force is about 60% of the weight of the bullet in this case.

The Coriolis force is given by F = -2mΩ * v, where m is the mass of the bullet, v is its velocity vector, and Ω is the angular velocity of the Earth. In this case, the velocity vector is horizontal and due north, so it can be expressed as v = v0(cosθ)i + v0(sinθ)j, where i and j are unit vectors in the eastward and northward directions, respectively.
Taking the cross product of Ω and v, we get:
Ω x v = (Ωz)(cosθ)i - (Ωz)(sinθ)j
where Ωz is the z-component of Ω (which is pointing upward). Therefore, the Coriolis force is:
F = -2m(Ωz)(cosθ)i + 2m(Ωz)(sinθ)j
The magnitude of this force is given by:
|F| = 2mΩv0sinθ
This shows that the Coriolis force is proportional to the mass of the bullet, the speed of the bullet, the sine of the colatitude angle θ, and the angular velocity of the Earth.
Comparing the Coriolis force to the weight of the bullet, we need to know the mass of the bullet. Assuming it is a standard 7.62 mm bullet with a mass of 0.01 kg, and using v0 = 1000 m/s and θ = 40°, we get:
|F| = 2(0.01 kg)(7.29 * 10^{-5} rad/s)(1000 m/s)(sin40°) ≈ 0.058 N
The weight of the bullet is:
mg = (0.01 kg)(9.81 m/s^2) ≈ 0.098 N

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complete question:

A bullet of mass m is fired with muzzle speed v_o horizontally and due north from a position at colatitude theta. Find the direction and magnitude of the Coriolis force in terms of m, v_o, theta, and the earth's angular velocity Ohm. How does the Coriolis force compare with the bullet's weight if v_o = 1000 m/s and theta = 40 deg?



Q: List, in order the steps you would follow in order to charge an electroscope by induction.

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To charge an electroscope by induction, the steps to be followed are Grounding, Approach, Charge Separation, Ground Connection, Charge Neutralization, Ground Disconnection, and Charge Retention.

1. Grounding: First, ensure that the electroscope is placed on a stable, non-conductive surface to prevent any unwanted charge transfer.

2. Approach: Bring a charged object (e.g., a charged rod) near, but not touching, the electroscope's metal plate or sphere. This creates an electric field that influences the electroscope.

3. Charge Separation: Due to the electric field, the free electrons in the electroscope redistribute themselves. If the charged object is negatively charged, electrons in the electroscope will be repelled to the furthest point, leaving the metal plate or sphere with a positive charge.

4. Ground Connection: Temporarily connect the electroscope to a ground, such as the Earth, using a conductor (e.g., a metal wire). This provides a path for excess charges to move between the electroscope and the ground.

5. Charge Neutralization: With the ground connection in place, the excess electrons in the electroscope move to the ground, neutralizing the negative charge on the furthest point.

6. Ground Disconnection: Remove the ground connection while the charged object is still near the electroscope. This traps the remaining positive charge on the metal plate or sphere.

7. Charge Retention: Finally, move the charged object away from the electroscope. The electroscope remains positively charged, demonstrating that it has been charged by induction.

By following these steps, you can successfully charge an electroscope using the induction method. This process demonstrates the principles of charge separation, grounding, and charge conservation.

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radius of the earth is 6.4*10^3 km and the value of acceleration due to gravity on it surface is 9.8m/s^2.find the value of acceleration due to gravity produced on a meteor at the distance of 9850m from the earth surface.


Help meee​

Answers

The acceleration due to gravity produced by a celestial body depends on its mass and the distance between the object and the center of the celestial body. The formula to calculate the acceleration due to gravity is g = (G * M) / r^2, where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the celestial body, and r is the distance between the object and the center of the celestial body.

To solve the problem, we need to find the mass of the Earth, which is 5.97 x 10^24 kg. Using the formula, we can find the acceleration due to gravity on the surface of the Earth, which is 9.8 m/s^2. To find the acceleration due to gravity produced on a meteor at a distance of 9850 m from the Earth's surface, we can use the same formula, where r is the distance between the meteor and the center of the Earth. The acceleration due to gravity produced on the meteor is 9.67 m/s^2.

At what distance from a 1.0-C charge is the electric potential equal to 12 V?A) 8.3 Ã 107 mB) 7.5 Ã 108 mC) 9.0 Ã 108 mD) 1.1 Ã 109 mE) 3.0 Ã 109 m

Answers

The distance from the charge at which the electric potential equals 12 V is about 7.5 108 m. Therefore the correct option is option B.

The electric potential owing to a point charge can be calculated as follows:

V = k * Q / r

where V represents the electric potential, k represents the Coulomb constant (9 109 Nm2/C2), Q represents the charge, and r represents the distance from the charge.

We are given a 12 V electric potential and a charge of 1.0 C. When we enter these values into the formula, we get:

[tex]12 = (9 × 10^9 N·m^2/C^2) * (1.0 C) / r[/tex]

When we solve for r, we get:

[tex]r = (9 × 10^9 N·m^2/C^2) * (1.0 C) / 12[/tex]

[tex]r = 7.5 × 10^8 m[/tex]

As a result, the distance from the charge at which the electric potential equals 12 V is about 7.5 108 m, which is similar to option (B) 7.5 108 m.

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