To measure the internal diameter of a beaker one would reliably use______.​

Answers

Answer 1

Answer:

Vernier calipers is used to measure the internal diameter of a beaker


Related Questions

Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.

Answers

It's the one that has a concave line running upward.

Answer:

its the middle one

Explanation:

i did it on edge 2021

9.
A 2.85-cm diameter coin is placed a distance of 31.4 cm from a diverging lens that has a focal length
of-11.6 cm. Determine the image distance and the diameter of the image.

Answers

Answer:

image distance = -8.47 cm

diameter of the image = 0.769 cm

When measuring volume, your final
result must be in
A. linear units.
B. single units.
C. squared units.
D. cubed units.

Answers

D cubed units


(often represented with a 3)

Explain what happens to the path of light as it hits a piece of black paper, a glass mirror, and a glass
of water. Explain why the light behaves the way it does as it hits each object.

1. Light is _________ by the black paper.

2. Light is _________ by the mirror.

3. Light is _________ by the glass of water.​

Answers

1: absorbed
2: reflected
3: i forgot the last one

Question number 11 how did we found the answer ?

Answers

Answer:

Option A. 57.14 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 100 Ω

Resistor 2 (R₂) = 400 Ω

Resistor 3 (R₃) = 200 Ω

Equivalent Resistor (Rₚ) =?

The equivalent resistor in the above circuit can be obtained as follow:

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₚ = 1/100 + 1/400 + 1/200

Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown

1/Rₚ = (4 + 1 + 2)/400

1/Rₚ = 7/400

Invert

Rₚ = 400/7

Rₚ = 57.14 Ω


A boy weighs 50 kg and is running with 225 J of energy, what is his velocity?

Answers

0.22 Is the answer. Have a great day!

a stone on the ground has zero energy why​

Answers

Explanation:

it has no energy when considered with respect to earth ,as it has neither height (i e potential energy) nor velocity (i.e kinetic energy).

As amplitude of a wave increases, the
_____ of the wave also increases.

frequency

wave speed

wavelength

energy

Answers

i think so it is frequency

What would be the mass of an atom with 2 protons and 3 neutrons?​

Answers

Answer:

5

Explanation:

From the question given above, the following data were obtained:

Proton number = 2

Neutron number = 3

Mass number =.?

The mass number of a given atom is simply the sum of the protons and neutrons in the nucleus of the atom. Mathematically, it is expressed as:

Mass number = proton + neutron

With the above formula, we can obtain the mass number of the atom as follow:

Proton number = 2

Neutron number = 3

Mass number =.?

Mass number = proton + neutron

Mass number = 2 + 3

Mass number = 5

Thus, the mass number the atom is 5.

A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity?

Answers

We have that for the Question " constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110." it can be said that

the final velocity vf is

[tex]vf=3.83m/s[/tex]

and the applied force Fnew is

[tex]F_{new}=3.43N[/tex]

From the question we are told

A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force F new would give the box the same final velocity?

Generally the equation for the Force  is mathematically given as

F_p-\mu mg=ma

Therefore

11-0.110*7*9.8=7*a

a=0.49m/s^2

Using Newtons equation

v^2=u^2+2as

v^2=0+2*0.49*15

v=3.83m/s

Therefore

F=ma

F=0.49*7

F_{new}=3.43N

Therefore

the final velocity vf is

[tex]vf=3.83m/s[/tex]

and the applied force Fnew is

[tex]F_{new}=3.43N[/tex]

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what are the materials that you have illustrated?​

Answers

Answer:

An illustration is a decoration, interpretation or visual explanation of a text, concept ... such as posters, flyers, magazines, books, teaching materials, animations, video games and films.

Explanation:

The head scale of a screw gauge contains 100 divisions and it's pitch is 1mm. what is the least count of the screw gauge​

Answers

Answer:

0.01 mm

Explanation:

The least count of the screw gauge = pitch/number of divisions on circular scale

Pitch = 1 mm and number of divisions = 100

Substituting the values of the variables into the equation, we have

least count of the screw gauge = pitch/number of divisions on circular scale =  1 mm/100 = 0.01 mm

A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.

Answers

Answer:

The speed of the knife after passing through the target is 9.33 m/s.

Explanation:

We can find the speed of the knife after the impact by conservation of linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]

Where:

[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg

[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg

[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s

[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s

[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?

[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)

Taking as a positive direction the direction of the knife movement, we have:

[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]  

[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]

Therefore, the speed of the knife after passing through the target is 9.33 m/s.

I hope it helps you!              

Which conversion can take place in a transformer
A. An electric current into a magnetic field
B. Electric energy into mechanical energy
C. Mechanical energy into electric energy
D. A lower voltage into a higher voltage

Answers

Answer:

D. A lower Voltage into a higher

two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of​

Answers

Answer:

2 possible answers:

1# 2.5 Ω (when the resistors are in parallel)

2# 10 Ω (when the resistors are in series)

Explanation:

there are two possible answers for this:

1# if the resistors are in parallel in the circuit

then:

1/R-equivalent=1/5+1/5

1/R-equivalent=2/5

R-equivalent=5/2=2.5 Ω

2# if the resistors are in series in the circuit

then:

R-equivalent=5+5

R-equivalent=10 Ω

Two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of​

If connected in series :

R = R1 + R2

R = 5 + 5

R = 10 ohms

If connected in parallel :

R = 1/R1 + 1/R2

R = 1/ 5 + 1/5

  = 2 / 5

  = 2.5 ohms

What is equivalent resistance ?

"The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated." Essentially, the circuit is designed either in Series or Parallel. Electrical resistance shows how much energy one needs when you move the charges/current through your devices.

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A small car is traveling at a speed of 60 mph on the highway. In the next lane, a large passenger bus is traveling at the same speed.

Answers

Answer:

A. The bus has more kinetic energy than the car.

Explanation:

As we know that

Kinetic energy is the amount of energy possessed by the body at the time when it is in motion.  

Also,

Kinetic energy = 1 ÷ 2mv²

Here m denotes the mass of the body

and v denotes the velocity of the body.

So it would be based on the mass & velocity of the body

As if the passenger bus contains more kinetic energy as compared to the car because of the big mass

Hence, the first option is correct

Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.00R from the disk. Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.00 . Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what percentage will you decrease the electric field magnitude at P?

Answers

Answer:

The electric field will be decreased by 29%

Explanation:

The distance between point P from the distance z = 2.0 R

Inner radius = R/2

Outer raidus = R

Thus;

The electrical field due to disk is:

[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])

[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]

Similarly;

[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]

However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]

[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]

[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]


Which wave type could move in the empty space between the Sun and the Earth

Answers

Answer:

Electromagnetic waves

A train is travelong at 22 m/s when the condutor gets a radio call about a car stalled on the tracks. He hits the emergancy brake and the train comes to a halt in 135 sevonds several meters before the car. What was the train's accleration during the emergency?

Answers

Answer:

final velocity = 0

because the train stoped

so,

acceleration = (v - u) ÷ tacceleration = (0 - 22) ÷ 135acceleration = -22 ÷ 135

acceleration = -0.162 m/s²

A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work did do after he speeds up?

Answers

Answer: 50.7 J

Explanation:

Given

mass of lion is  [tex]m=2.6\ kg[/tex]

The initial speed of the lion is [tex]v_1=5\ m/s[/tex]

increased speed of lion is [tex]v_2=8\ m/s[/tex]

Initially, its kinetic energy is [tex]K_1=\frac{1}{2}mv_1^2[/tex]

Final kinetic energy [tex]k_2=\frac{1}{2}mv_2^2[/tex]

work did by lion after speed up is [tex]k_2-k_1[/tex]

[tex]\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J[/tex]

if up is up and down is down isn't downside up , upside down

Answers

Answer:

No they arent because they are opposite to each other.

Which two criteria are least important for engineers to consider when developing a process to produce an important chemical?
A. The process should be located in a major city.
B. The process should use local, organic reactants.
C. The process should produce a significant amount of the product.
D. The process should be cost-effective.​

Answers

Answer:

two least important criteria are A and B.

Explanation:

In an industrial production process there are criteria on the location of the production plants. Among the most important criteria we have that a good quantity is produced from the producer and that the process is cost-beneficial - cats to increase the profit of the company.

There are other desirable but minor criteria

A) The size of the city is of minor importance

b) Finding raw material locally is interesting, but its importance is less, the raw material can be sent from other locations.

Consequently the two least important criteria are A and B.

Answer:

A. The process should be located in a major city.

B. The process should use local, organic reactants.

Explanation:

ap.ex

Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration would be small, but it could continue for months or years in the vacuum of space. Consider a 1200 kg uncrewed space probe powered by a 15 MW laser. After one year, how far will it have traveled and how fast will it be going

Answers

Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy )  ---- ( 1 )

where :

work done = p * t

                  = 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2   given ; m = 1200 kg  and initial V = 0

back to equation 1

473040000 * 10^6  = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

i) Determine how fast the rocket is ( acceleration of the rocket )

a = Vf / t

  = 887918.92 / ( 1 year )

  = 0.0282 m/s^2

ii) determine distance travelled by rocket

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) =  Vf^2 / ( 2a )

                     = ( 887918.92 )^2 / ( 2 * 0.0282 )

                    = 13.98 * 10^12 m

What do all clouds contain the some amount of

Answers

Answer:

A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.

Explanation:

For a satellite to orbit Earth at a constant distance, its centrifugal acceleration
must be equal and opposite Earth's gravitational acceleration. If a satellite is
to orbit at a constant distance from Earth at a circular radius of 8,300,000 m,
what is the required velocity of the satellite? (Assume the acceleration due to
Earth's gravity is 5.6 m/s2 at this altitude.)
A. 7043 m/s
B. 8239 m/s
C. 7576 m/s
D. 6818 m/s

Answers

If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,300,000, the required velocity of the satellite is 8239m/s.

What is a satellite?

Most spacecraft, with the exception of passive satellites, contain a means of generating electricity for the technology they carry, such as solar panels or radioisotope thermoelectric generators (RTGs). The majority of satellites also feature transponders, which are a type of ground station communication system. The most common satellites, small CubeSats, use a standardised bus to reduce costs and labour. Satellites of a similar type can cooperate with one another to form constellations.

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Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?

Answers

Answer:

a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]

b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]

c) the magnitude of the net momentum is 54102.5 kgm/s

Explanation:

Given the data in the question;

a) x-component of the net momentum of this system.

the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up

so;

Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]

Px = 44200 kgm/s [tex](-x)[/tex]

Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]

b) y-component of the net momentum of this system

Also, momentum along y-axis is entirely provided by the sedan

Py = 1300 kg × 24.0 m/s [tex](y)[/tex]

Py = 31200 kgm/s [tex](y)[/tex]

Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]

c) magnitude of the net momentum?

magnitude of the net momentum P = √( Px² + Py² )

so we substitute  

P = √( (44200)² + (31200)² )

P = √( 2927080000 )

P = 54102.5 kgm/s

Therefore, the magnitude of the net momentum is 54102.5 kgm/s

write short note : power​

Answers

Answer:

In physics, power is the amount of energy transferred or converted per unit time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

SI unit: watt (W)

Derivations from other quantities: P = E/t; P = F·v; P = V·I; P = τ·ω

In SI base units: kg⋅m2⋅s−3

Answer:

As a student, what are your insights about this lesson? Write an essay on your

toughts about the types of drugs/subtance of abuse, discussing its description and

effects

The statement "if I raise the temperature of
a cup of water, then an increased amount of
sugar will be dissolved" is an example of
A. an observation
B. a hypothesis.
C. a theory

Answers

B is the answer for this here question

1. A temperature of 162 °F is equivalent to what temperature in kelvins?
(a) 373 K
(b) 288 K
(C) 345 K
(d) 201 K (e) 308 K

Answers

345k

Because the formula for our Fahrenheit is Kevin = 5 * (°Fahrenheit + 459.67)

9.

A 16 lb weight stretches a spring 6 inches in equilibrium. It is attached to a damping mechanism with constant c. Find all values of c such that the free vibration of the weight has infinitely many oscillations.

Answers

Answer:

[tex]-8<c<8[/tex]

Explanation:

Given data:

Weight W = 16 lb

length l = 6/12 = 0.5 ft

hence, spring constant  k = W/l = 16/0.5 = 32 lb/ft

The equation of motion of spring is

[tex]mx''+cx+kx=0\\0.5x''+cx'+32x=0[/tex]

the auxiliary equation can be written as

[tex]0.5r^2+cr+32=0\\r^2+2cr+64=0[/tex]

The discriminate of equation is

[tex]D =(2c)^2+-4(1)(64)\\=4(c^2-64)[/tex]

To get the value of the damping constant,

[tex]D<0\\4(c^2-64)<0\\c>-8, c<8\\-8<c<8[/tex]

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